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  • Declare Locally or Globally in Delphi?

    - by lkessler
    I have a procedure my program calls tens of thousands of times that uses a generic structure like this: procedure PrintIndiEntry(JumpID: string); type TPeopleIncluded = record IndiPtr: pointer; Relationship: string; end; var PeopleIncluded: TList<TPeopleIncluded>; PI: TPeopleIncluded; begin { PrintIndiEntry } PeopleIncluded := TList<TPeopleIncluded>.Create; { A loop here that determines a small number (up to 100) people to process } while ... do begin PI.IndiPtr := ...; PI.Relationship := ...; PeopleIncluded.Add(PI); end; DoSomeProcess(PeopleIncluded); PeopleIncluded.Clear; PeopleIncluded.Free; end { PrintIndiEntry } Alternatively, I can declare PeopleIncluded globally rather than locally as follows: unit process; interface type TPeopleIncluded = record IndiPtr: pointer; Relationship: string; end; var PeopleIncluded: TList<TPeopleIncluded>; PI: TPeopleIncluded; procedure PrintIndiEntry(JumpID: string); begin { PrintIndiEntry } { A loop here that determines a small number (up to 100) people to process } while ... do begin PI.IndiPtr := ...; PI.Relationship := ...; PeopleIncluded.Add(PI); end; DoSomeProcess(PeopleIncluded); PeopleIncluded.Clear; end { PrintIndiEntry } procedure InitializeProcessing; begin PeopleIncluded := TList<TPeopleIncluded>.Create; end; procedure FinalizeProcessing; begin PeopleIncluded.Free; end; My question is whether in this situation it is better to declare PeopleIncluded globally rather than locally. I know the theory is to define locally whenever possible, but I would like to know if there are any issues to worry about with regards to doing tens of thousands of of "create"s and "free"s? Making them global will do only one create and one free. What is the recommended method to use in this case? If the recommended method is to still define it locally, then I'm wondering if there are any situations where it is better to define globally when defining locally is still an option.

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  • Weird behavior of substitution in Mathematica.

    - by Ilya
    My question is: why doesn't the following work, and how do I fix it? Plot[f[t], {t, 0, 2*Pi}] /. {{f -> Sin}, {f -> Cos}} The result is two blank graphs. By comparison, DummyFunction[f[t], {t, 0, 2*Pi}] /. {{f -> Sin}, {f -> Cos}} gives {DummyFunction[Sin[t], {t, 0, 2 *Pi}], DummyFunction[Cos[t], {t, 0, 2 * Pi}]} as desired. This is a simplified version of what I was actually doing. I was very annoyed that, even after figuring out the annoying "right way" of putting the curly brackets nothing works. In the end, I did the following, which works: p[f_] := Plot[f[t], {t, 0, 2*Pi}] p[Sin] p[Cos]

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  • Start Default Browser - Windows

    - by dbasnett
    When starting the default browser like this: Dim trgt1 As String = "http://www.vbforums.com/showthread.php?t=612471" pi.FileName = trgt1 System.Diagnostics.Process.Start(pi) It takes about 40 seconds to open the page. If I do it like this, though this isn't the default browser Dim trgt1 As String = "http://www.vbforums.com/showthread.php?t=612471" pi.Arguments = trgt1 pi.FileName = "iexplore.exe" 'or firefox.exe System.Diagnostics.Process.Start(pi) it opens immediately. Is this a bug or a feature? I have tried this with both IE and FireFox set to be the default browser.

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  • How can I further optimize this color difference function?

    - by aLfa
    I have made this function to calculate color differences in the CIE Lab colorspace, but it lacks speed. Since I'm not a Java expert, I wonder if any Java guru around has some tips that can improve the speed here. The code is based on the matlab function mentioned in the comment block. /** * Compute the CIEDE2000 color-difference between the sample color with * CIELab coordinates 'sample' and a standard color with CIELab coordinates * 'std' * * Based on the article: * "The CIEDE2000 Color-Difference Formula: Implementation Notes, * Supplementary Test Data, and Mathematical Observations,", G. Sharma, * W. Wu, E. N. Dalal, submitted to Color Research and Application, * January 2004. * available at http://www.ece.rochester.edu/~gsharma/ciede2000/ */ public static double deltaE2000(double[] lab1, double[] lab2) { double L1 = lab1[0]; double a1 = lab1[1]; double b1 = lab1[2]; double L2 = lab2[0]; double a2 = lab2[1]; double b2 = lab2[2]; // Cab = sqrt(a^2 + b^2) double Cab1 = Math.sqrt(a1 * a1 + b1 * b1); double Cab2 = Math.sqrt(a2 * a2 + b2 * b2); // CabAvg = (Cab1 + Cab2) / 2 double CabAvg = (Cab1 + Cab2) / 2; // G = 1 + (1 - sqrt((CabAvg^7) / (CabAvg^7 + 25^7))) / 2 double CabAvg7 = Math.pow(CabAvg, 7); double G = 1 + (1 - Math.sqrt(CabAvg7 / (CabAvg7 + 6103515625.0))) / 2; // ap = G * a double ap1 = G * a1; double ap2 = G * a2; // Cp = sqrt(ap^2 + b^2) double Cp1 = Math.sqrt(ap1 * ap1 + b1 * b1); double Cp2 = Math.sqrt(ap2 * ap2 + b2 * b2); // CpProd = (Cp1 * Cp2) double CpProd = Cp1 * Cp2; // hp1 = atan2(b1, ap1) double hp1 = Math.atan2(b1, ap1); // ensure hue is between 0 and 2pi if (hp1 < 0) { // hp1 = hp1 + 2pi hp1 += 6.283185307179586476925286766559; } // hp2 = atan2(b2, ap2) double hp2 = Math.atan2(b2, ap2); // ensure hue is between 0 and 2pi if (hp2 < 0) { // hp2 = hp2 + 2pi hp2 += 6.283185307179586476925286766559; } // dL = L2 - L1 double dL = L2 - L1; // dC = Cp2 - Cp1 double dC = Cp2 - Cp1; // computation of hue difference double dhp = 0.0; // set hue difference to zero if the product of chromas is zero if (CpProd != 0) { // dhp = hp2 - hp1 dhp = hp2 - hp1; if (dhp > Math.PI) { // dhp = dhp - 2pi dhp -= 6.283185307179586476925286766559; } else if (dhp < -Math.PI) { // dhp = dhp + 2pi dhp += 6.283185307179586476925286766559; } } // dH = 2 * sqrt(CpProd) * sin(dhp / 2) double dH = 2 * Math.sqrt(CpProd) * Math.sin(dhp / 2); // weighting functions // Lp = (L1 + L2) / 2 - 50 double Lp = (L1 + L2) / 2 - 50; // Cp = (Cp1 + Cp2) / 2 double Cp = (Cp1 + Cp2) / 2; // average hue computation // hp = (hp1 + hp2) / 2 double hp = (hp1 + hp2) / 2; // identify positions for which abs hue diff exceeds 180 degrees if (Math.abs(hp1 - hp2) > Math.PI) { // hp = hp - pi hp -= Math.PI; } // ensure hue is between 0 and 2pi if (hp < 0) { // hp = hp + 2pi hp += 6.283185307179586476925286766559; } // LpSqr = Lp^2 double LpSqr = Lp * Lp; // Sl = 1 + 0.015 * LpSqr / sqrt(20 + LpSqr) double Sl = 1 + 0.015 * LpSqr / Math.sqrt(20 + LpSqr); // Sc = 1 + 0.045 * Cp double Sc = 1 + 0.045 * Cp; // T = 1 - 0.17 * cos(hp - pi / 6) + // + 0.24 * cos(2 * hp) + // + 0.32 * cos(3 * hp + pi / 30) - // - 0.20 * cos(4 * hp - 63 * pi / 180) double hphp = hp + hp; double T = 1 - 0.17 * Math.cos(hp - 0.52359877559829887307710723054658) + 0.24 * Math.cos(hphp) + 0.32 * Math.cos(hphp + hp + 0.10471975511965977461542144610932) - 0.20 * Math.cos(hphp + hphp - 1.0995574287564276334619251841478); // Sh = 1 + 0.015 * Cp * T double Sh = 1 + 0.015 * Cp * T; // deltaThetaRad = (pi / 3) * e^-(36 / (5 * pi) * hp - 11)^2 double powerBase = hp - 4.799655442984406; double deltaThetaRad = 1.0471975511965977461542144610932 * Math.exp(-5.25249016001879 * powerBase * powerBase); // Rc = 2 * sqrt((Cp^7) / (Cp^7 + 25^7)) double Cp7 = Math.pow(Cp, 7); double Rc = 2 * Math.sqrt(Cp7 / (Cp7 + 6103515625.0)); // RT = -sin(delthetarad) * Rc double RT = -Math.sin(deltaThetaRad) * Rc; // de00 = sqrt((dL / Sl)^2 + (dC / Sc)^2 + (dH / Sh)^2 + RT * (dC / Sc) * (dH / Sh)) double dLSl = dL / Sl; double dCSc = dC / Sc; double dHSh = dH / Sh; return Math.sqrt(dLSl * dLSl + dCSc * dCSc + dHSh * dHSh + RT * dCSc * dHSh); }

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  • Java Math.cos() Method Does Not Return 0 When Expected

    - by dimo414
    Using Java on a Windows 7 PC (not sure if that matters) and calling Math.cos() on values that should return 0 (like pi/2) instead returns small values, but small values that, unless I'm misunderstanding, are much greater than 1 ulp off from zero. Math.cos(Math.PI/2) = 6.123233995736766E-17 Math.ulp(Math.cos(Math.PI/2)) = 1.232595164407831E-32 Is this in fact within 1 ulp and I'm simply confused? And would this be an acceptable wrapper method to resolve this minor inaccuracy? public static double cos(double a){ double temp = Math.abs(a % Math.PI); if(temp == Math.PI/2) return 0; return Math.cos(a); }

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  • i'm trying to solve an equation using gfortran but i keep getting error

    - by sameon
    i'm using the below program but i keep getting error.What is wrong with my progam? real x complex y real m1,H0,Ms,P1,P2,P3,w0,wm,wh complex w1,w2,o1,o2 integer i,n real pi n=4000000000 pi=4*atan(1.0) m1=4*pi*1e-7 H0=39.79e3 Ms=1400e3 P1=0.7*0.12 P2=0.3*0.12 P3=P1-P2 w0=m1*(1.76e11)*H0 wm=m1*(1.76e11)*Ms wh=w0-P3*wm im=cmplx(0,1) w1=wm/2+wh-im*0.06*2*pi*x w2=wm/2-wh-im*0.06*2*pi*x o1=x**2-x*(2*wh-(P3*wm)/2)-w1*w2+(wm/2)*(P1*w2+P2*w1) o2=x**2+x*(2*wh-(P3*wm)/2)-w1*w2+(wm/2)*(P1*w2+P2*w1) do i=0,n x=i y=1+wm*(P1*w1*((w2)**2-x**2))/(o1*o2) & +wm*(P2*w2*((w1)**2-x**2))/(o1*o2) & -wm*((wm/2)*((P1*w2+P2*w1)**2)))/(o1*o2) & +wm*((wm/2)*((P3*x)**2))/(o1*o2) write(10,*)x,y enddo return end

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  • This codes in Actionscript-2, Can anyone help me translate it into AS-3 please ?.......a newby pulli

    - by Spux
    this.createEmptyMovieClip('mask_mc',0); bg_mc.setMask(mask_mc); var contor:Number=0; // function drawCircle draws a circle on mask_mc MovieClip of radius r and having center to mouse coordinates function drawCircle(mask_mc:MovieClip):Void{ var r:Number = 20; var xcenter:Number = _xmouse; var ycenter:Number = _ymouse; var A:Number = Math.tan(22.5 * Math.PI/180); var endx:Number; var endy:Number; var cx:Number; var cy:Number; mask_mc.beginFill(0x000000, 100); mask_mc.moveTo(xcenter+r, ycenter); for (var angle:Number = Math.PI/4; angle<=2*Math.PI; angle += Math.PI/4) { xend = r*Math.cos(angle); yend = r*Math.sin(angle); xbegin =xend + r* A *Math.cos((angle-Math.PI/2)); ybegin =yend + r* A *Math.sin((angle-Math.PI/2)); mask_mc.curveTo(xbegin+xcenter, ybegin+ycenter, xend+xcenter, yend+ycenter); } mask_mc.endFill(); } // contor variable is used to hold if the mouse is pressed (contor is 1) or not (contor is 0) this.onMouseDown=function(){ drawCircle(mask_mc); contor=1; } // if the mouse is hold and moved then we draw a circle on the mask_mc this.onMouseMove=this.onEnterFrame=function(){ if (contor==1){ drawCircle(mask_mc); } } this.onMouseUp=function(){ contor=0; }

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  • How can I work around the fact that in C++, sin(M_PI) is not 0?

    - by Adam Doyle
    In C++, const double Pi = 3.14159265; cout << sin(Pi); // displays: 3.58979e-009 it SHOULD display the number zero I understand this is because Pi is being approximated, but is there any way I can have a value of Pi hardcoded into my program that will return 0 for sin(Pi)? (a different constant maybe?) In case you're wondering what I'm trying to do: I'm converting polar to rectangular, and while there are some printf() tricks I can do to print it as "0.00", it still doesn't consistently return decent values (in some cases I get "-0.00") The lines that require sin and cosine are: x = r*sin(theta); y = r*cos(theta); BTW: My Rectangular - Polar is working fine... it's just the Polar - Rectangular Thanks! edit: I'm looking for a workaround so that I can print sin(some multiple of Pi) as a nice round number to the console (ideally without a thousand if-statements) edit: In case anyone's curious, this was what I landed on: double sin2(double theta) // in degrees { double s = sin(toRadians(theta)); if (fabs(s - (int)s) < 0.000001) { return floor(s + 0.5); } return s; } where toRadians() is a macro that converts to radians

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  • help understanding differences between #define, const and enum in C and C++ on assembly level.

    - by martin
    recently, i am looking into assembly codes for #define, const and enum: C codes(#define): 3 #define pi 3 4 int main(void) 5 { 6 int a,r=1; 7 a=2*pi*r; 8 return 0; 9 } assembly codes(for line 6 and 7 in c codes) generated by GCC: 6 mov $0x1, -0x4(%ebp) 7 mov -0x4(%ebp), %edx 7 mov %edx, %eax 7 add %eax, %eax 7 add %edx, %eax 7 add %eax, %eax 7 mov %eax, -0x8(%ebp) C codes(enum): 2 int main(void) 3 { 4 int a,r=1; 5 enum{pi=3}; 6 a=2*pi*r; 7 return 0; 8 } assembly codes(for line 4 and 6 in c codes) generated by GCC: 6 mov $0x1, -0x4(%ebp) 7 mov -0x4(%ebp), %edx 7 mov %edx, %eax 7 add %eax, %eax 7 add %edx, %eax 7 add %eax, %eax 7 mov %eax, -0x8(%ebp) C codes(const): 4 int main(void) 5 { 6 int a,r=1; 7 const int pi=3; 8 a=2*pi*r; 9 return 0; 10 } assembly codes(for line 7 and 8 in c codes) generated by GCC: 6 movl $0x3, -0x8(%ebp) 7 movl $0x3, -0x4(%ebp) 8 mov -0x4(%ebp), %eax 8 add %eax, %eax 8 imul -0x8(%ebp), %eax 8 mov %eax, 0xc(%ebp) i found that use #define and enum, the assembly codes are the same. The compiler use 3 add instructions to perform multiplication. However, when use const, imul instruction is used. Anyone knows the reason behind that?

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  • Running exe built in VC++ on XP and WIN7

    - by rajivpradeep
    sprintf_s(cmd, "%c:\index.exe", driver); STARTUPINFOA si; PROCESS_INFORMATION pi; ::SecureZeroMemory(&si, sizeof(STARTUPINFO)); ::SecureZeroMemory(&pi, sizeof(PROCESS_INFORMATION)); si.dwFlags = STARTF_USESHOWWINDOW | STARTF_USESTDHANDLES; si.wShowWindow = SW_SHOW; RES = ::CreateProcessA(NULL, cmd, NULL, NULL, NULL, NULL, NULL, NULL, &si, &pi); DWORD exitcode; DWORD err; do { Sleep(100); GetExitCodeProcess(pi.hProcess, &exitcode); } while (exitcode !=0); GetExitCodeThread(pi.hThread, &exitcode); RES = TerminateThread(pi.hThread, exitcode); if (RES == 0) err = GetLastError(); I am trying to run a flash file, the application is built in VS 2008 , on win 7. The application works well on WIN7 but fails in XP. Ie the application launches but doesn't complete the task. I see the application running in Task Manager

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  • Multi-threaded JOGL Problem

    - by moeabdol
    I'm writing a simple OpenGL application in Java that implements the Monte Carlo method for estimating the value of PI. The method is pretty easy. Simply, you draw a circle inside a unit square and then plot random points over the scene. Now, for each point that is inside the circle you increment the counter for in points. After determining for all the random points wither they are inside the circle or not you divide the number of in points over the total number of points you have plotted all multiplied by 4 to get an estimation of PI. It goes something like this PI = (inPoints / totalPoints) * 4. This is because mathematically the ratio of a circle's area to a square's area is PI/4, so when we multiply it by 4 we get PI. My problem doesn't lie in the algorithm itself; however, I'm having problems trying to plot the points as they are being generated instead of just plotting everything at once when the program finishes executing. I want to give the application a sense of real-time display where the user would see the points as they are being plotted. I'm a beginner at OpenGL and I'm pretty sure there is a multi-threading feature built into it. Non the less, I tried to manually create my own thread. Each worker thread plots one point at a time. Following is the psudo-code: /* this part of the code exists in display() method in MyCanvas.java which extends GLCanvas and implements GLEventListener */ // main loop for(int i = 0; i < number_of_points; i++){ RandomGenerator random = new RandomGenerator(); float x = random.nextFloat(); float y = random.nextFloat(); Thread pointThread = new Thread(new PointThread(x, y)); } gl.glFlush(); /* this part of the code exists in run() method in PointThread.java which implements Runnable */ void run(){ try{ gl.glPushMatrix(); gl.glBegin(GL2.GL_POINTS); if(pointIsIn) gl.glColor3f(1.0f, 0.0f, 0.0f); // red point else gl.glColor3f(0.0f, 0.0f, 1.0f); // blue point gl.glVertex3f(x, y, 0.0f); // coordinates gl.glEnd(); gl.glPopMatrix(); }catch(Exception e){ } } I'm not sure if my approach to solving this issue is correct. I hope you guys can help me out. Thanks.

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  • how to animate 2 surfaces in Matlab?

    - by Kate
    Hi everyone, I've written this code which makes an animation of 2 ellipsoids. Parameter k1 of these ellipsoids must depend on time (so they'd move asynchronously), but I need to animate them in one figure. Can I use loop for it or is it better to use timer & some kind of callback functions? The second problem - I need to move inner ellipsoid so they would have one common side. How can I do this? a=5; b=a; c=10; u = (0:0.05*pi:2*pi)'; v = [0:0.05*pi:2*pi]; X = a*sin(u)*cos(v); Y = a*sin(u)*sin(v); Z = c*cos(u)*ones(size(v)); Z(Z0)=0; % cut upper V1=4/3*pi*a*b*c; d=1/2; e=2^d; a2=a/e; b2=a/e; c2=c; V2=4/3*pi*a2*b2*c2; X2 = a2*sin(u)*cos(v);%-2.5; Y2 = b2*sin(u)*sin(v); Z2 = c2*cos(u)*ones(size(v));%+0.25; Z2(Z20)=0; % cut h=1/3; for j = 1:20 k1=(sin(pi*j/20)+0.5)^h; a=a*k1; c=c*k1; X = a*sin(u)*cos(v); Y = a*sin(u)*sin(v); Z = c*cos(u)*ones(size(v)); Z(Z0)=0; a2=a2*k1; b2=a2*k1; c2=c2*k1; X2 = a2*sin(u)*cos(v)+5;%-2.5; Y2 = b2*sin(u)*sin(v); Z2 = c2*cos(u)*ones(size(v));%+0.25; Z2(Z20)=0; hS1=surf(X,Y,Z); alpha(.11) hold on hS2=surf(X2,Y2,Z2); hold off axis([-20 20 -20 20 -20 20]); F(j) = getframe; end movie(F,4)

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  • Follow point of interest by applying torque

    - by azymm
    Given a body with an orientation angle and a point of interest or targetAngle, is there an elegant solution for keeping the body oriented towards the point of interest by applying torque or impulses? I have a naive solution working below, but the effect is pretty 'wobbly', it'll overshoot each time, slowly getting closer to the target angle - undesirable effect in my case. I'd like to find a solution that is more intelligent - that can accelerate to near the target angle then decelerate and stop right at the target angle (or within a small range). If it helps, I'm using box2d and the body is a rectangle. def gameloop(dt): targetAngle = get_target_angle() bodyAngle = get_body_angle() deltaAngle = targetAngle - bodyAngle if deltaAngle > PI: deltaAngle = targetAngle - (bodyAngle + 2.0 * PI) if deltaAngle < -PI: deltaAngle = targetAngle - (bodyAngle - 2.0 * PI) # multiply by 2, for stronger reaction deltaAngle = deltaAngle * 2.0; body.apply_torque(deltaAngle); One other thing, when body has no linear velocity, the above solution works ok. But when the body has some linear velocity, the solution above causes really wonky movement. Not sure why, but would appreciate any hints as to why that might be.

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  • OpenGL texture on sphere

    - by Cilenco
    I want to create a rolling, textured ball in OpenGL ES 1.0 for Android. With this function I can create a sphere: public Ball(GL10 gl, float radius) { ByteBuffer bb = ByteBuffer.allocateDirect(40000); bb.order(ByteOrder.nativeOrder()); sphereVertex = bb.asFloatBuffer(); points = build(); } private int build() { double dTheta = STEP * Math.PI / 180; double dPhi = dTheta; int points = 0; for(double phi = -(Math.PI/2); phi <= Math.PI/2; phi+=dPhi) { for(double theta = 0.0; theta <= (Math.PI * 2); theta+=dTheta) { sphereVertex.put((float) (raduis * Math.sin(phi) * Math.cos(theta))); sphereVertex.put((float) (raduis * Math.sin(phi) * Math.sin(theta))); sphereVertex.put((float) (raduis * Math.cos(phi))); points++; } } sphereVertex.position(0); return points; } public void draw() { texture.bind(); gl.glEnableClientState(GL10.GL_VERTEX_ARRAY); gl.glVertexPointer(3, GL10.GL_FLOAT, 0, sphereVertex); gl.glDrawArrays(GL10.GL_TRIANGLE_FAN, 0, points); gl.glDisableClientState(GL10.GL_VERTEX_ARRAY); } My problem now is that I want to use this texture for the sphere but then only a black ball is created (of course because the top right corner s black). I use this texture coordinates because I want to use the whole texture: 0|0 0|1 1|1 1|0 That's what I learned from texturing a triangle. Is that incorrect if I want to use it with a sphere? What do I have to do to use the texture correctly?

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  • How to handle multiple effect files in XNA

    - by Adam 'Pi' Burch
    So I'm using ModelMesh and it's built in Effects parameter to draw a mesh with some shaders I'm playing with. I have a simple GUI that lets me change these parameters to my heart's desire. My question is, how do I handle shaders that have unique parameters? For example, I want a 'shiny' parameter that affects shaders with Phong-type specular components, but for an environment mapping shader such a parameter doesn't make a lot of sense. How I have it right now is that every time I call the ModelMesh's Draw() function, I set all the Effect parameters as so foreach (ModelMesh m in model.Meshes) { if (isDrawBunny == true)//Slightly change the way the world matrix is calculated if using the bunny object, since it is not quite centered in object space { world = boneTransforms[m.ParentBone.Index] * Matrix.CreateScale(scale) * rotation * Matrix.CreateTranslation(position + bunnyPositionTransform); } else //If not rendering the bunny, draw normally { world = boneTransforms[m.ParentBone.Index] * Matrix.CreateScale(scale) * rotation * Matrix.CreateTranslation(position); } foreach (Effect e in m.Effects) { Matrix ViewProjection = camera.ViewMatrix * camera.ProjectionMatrix; e.Parameters["ViewProjection"].SetValue(ViewProjection); e.Parameters["World"].SetValue(world); e.Parameters["diffuseLightPosition"].SetValue(lightPositionW); e.Parameters["CameraPosition"].SetValue(camera.Position); e.Parameters["LightColor"].SetValue(lightColor); e.Parameters["MaterialColor"].SetValue(materialColor); e.Parameters["shininess"].SetValue(shininess); //e.Parameters //e.Parameters["normal"] } m.Draw(); Note the prescience of the example! The solutions I've thought of involve preloading all the shaders, and updating the unique parameters as needed. So my question is, is there a best practice I'm missing here? Is there a way to pull the parameters a given Effect needs from that Effect? Thank you all for your time!

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  • Finding the shorter turning direction towards a target

    - by A.B.
    I'm trying to implement a type of movement where the object gradually faces the target. The problem I've run into is figuring out which turning direction is faster. The following code works until the object's orientation crosses the -PI or PI threshold, at which point it will start turning into the opposite direction void moveToPoint(sf::Vector2f destination) { if (destination == position) return; auto distance = distanceBetweenPoints(position, destination); auto direction = angleBetweenPoints(position, destination); /// Decides whether incrementing or decrementing orientation is faster /// the next line is the problem if (atan2(sin(direction - rotation), cos(direction - rotation)) > 0 ) { /// Increment rotation rotation += rotation_speed; } else { /// Decrement rotation rotation -= rotation_speed; } if (distance < movement_speed) { position = destination; } else { position.x = position.x + movement_speed*cos(rotation); position.y = position.y + movement_speed*sin(rotation); } updateGraphics(); } 'rotation' and 'rotation_speed' are implemented as custom data type for radians which cannot have values lower than -PI and greater than PI. Any excess or deficit "wraps around". For example, -3.2 becomes ~3.08.

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  • Java SE 8 (with JavaFX) Developer Preview Release for ARM

    - by Roger Brinkley
    In an effort to get ARM developers testing Java SE 8 before the scheduled release later this year a Java SE 8 Developer Preview Release for ARM has been made available. This release has been tested on the Raspberry PI but should work on other ARM platforms. In addition to the new Java SE features, this release provides specific support of hard float GPU on the Raspberry PI. The support for hard float GPU has been anticipated by a number of developers. Additionally, this release includes support of an optimized JavaFX. Specific configurations of JDK 8 on ARM are defined below: Java FX is supported on ARM architecture v6/7 (hard float) Supported platforms without Java FX: ARM architecture v6/7 (hard float) ARM architecture v7 (VFP, little endian) ARM architecture v5 (soft float, little endian) Linux x86 The download page includes setup instructions for a Raspberry PI device as well as demos and samples. Developers are also encouraged to try their own applications as well and to share their stories via the JavaFX or Project Feedback Forums.  If you've got a Raspberry PI or other ARM devices it's time to get started with Java SE 8 Developer Preview release.

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  • SSH without portforward

    - by maigel
    I have a raspberry pi lying around in my dorm room. It's connected to campus internet which has all ports closed and I obviously don't have any access or permission to port forwarding. Now I want to ssh to the raspberry pi but this isn't possible since I can't port forward. I do however have a cheap vps doing nothing. Is there a way to make the pi connect to the vps and then use the vps as some sort of tunnel to ssh to the raspberry pi without having any port forwarding done?

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  • Mac OSX DHCP Stopped Working [on hold]

    - by Jesse James Richard
    Tethering a Raspberry PI to a MacBook (Mavericks) via ethernet is proving to be a real pain. This worked for about a day. My MacBook required a rare reboot and once it came back up the Pi won't get an address. I've confirmed it's not a problem with the Pi. It's a problem with the MacBook for sure. It's basically just stopped giving out IPs. I've read as much as I've found about how to fix this friggin' problem, but I've thus far come up blank. Internet sharing Wi-fi Ethernet enabled, and/or Edited /etc/bootpd.plist as described here (http://www.jacquesf.com/2011/04/mac-os-x-dhcp-server/ - this worked initially and now no longer does) Pi connected directly to the router has no problems. My MacBook DHCP server will no longer give out addresses. Any help would be much appreciated.

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  • What You Said: What’s on Your Geeky Christmas List

    - by Jason Fitzpatrick
    Earlier this week we asked you to share what’s on your geeky Christmas list; you responded and we’re back to share your longed for tech goodies. The most requested item was this year’s hot introduction to the project board market: the Raspberry Pi. Dave writes: A Rapsberry Pi to tinker with, especially to see if I can get it up and running with OpenElec/Raspbmc and a torrent client for a low power media centre/htpc We just finished setting up a batch of new 512MB Raspberry Pi systems running the newest release of Rasbmbc and can’t recommend it enough–new refinements in Raspbmc and the extra 256MB of RAM really improve the media center experience. All John wants is a real keyboard so he can escape the torture of using a touch screen: How to Factory Reset Your Android Phone or Tablet When It Won’t Boot Our Geek Trivia App for Windows 8 is Now Available Everywhere How To Boot Your Android Phone or Tablet Into Safe Mode

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  • Apache2 and FTP

    - by Jo Colina
    I just set up an Apache web server on my Raspberry Pi, along with MySQL and PHP5, and to upload files i set up vsftpd. The thing is that the ftp connection sent me to my pi user home directory, instead of /var/www . So i changed Pi home directory to /var/www and changed it again to it's previous home. FTP now sends me to /var/www but whenever I upload files other rights are null. (Apache sends a 403 Forbidden every time unless I manually chmod the files inside /var/www uploaded via ftp) Does anyuone know how to fix this? Thanks!

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  • C++: Checking if an object faces a point (within a certain range)

    - by bojoradarial
    I have been working on a shooter game in C++, and am trying to add a feature whereby missiles shot must be within 90 degrees (PI/2 radians) of the direction the ship is facing. The missiles will be shot towards the mouse. My idea is that the ship's angle of rotation is compared with the angle between the ship and the mouse (std::atan2(mouseY - shipY, mouseX - shipX)), and if the difference is less than PI/4 (45 degrees) then the missile can be fired. However, I can't seem to get this to work. The ship's angle of rotation is increased and decreased with the A and D keys, so it is possible that it isn't between 0 and 2*PI, hence the use of fmod() below. Code: float userRotation = std::fmod(user->Angle(), 6.28318f); if (std::abs(userRotation - missileAngle) > 0.78f) return; Any help would be appreciated. Thanks!

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  • Having set up a DCHP server, what do I need to do for the rest of my network?

    - by fredley
    I've got a Raspberry Pi arriving any day now, and I intend to use it (amongst other things) as a DHCP server. Currently we have a few devices on our network to which we would like to assign static IPs, and a router, which is currently the DHCP server (the router can assign static IPs, but is buggy as hell, I've never got the config to stick for more than a few hours). Having connected the Pi to the network and configured dhcpl-3-server, what do I need to do on the rest of my network so that it works properly (clients get their IPs from the Pi, and use the Router as the default gateway)?

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  • RPi and Java Embedded: Hard-Float Support is Here!!!

    - by hinkmond
    You wanted Java Embedded with Hardware Floating Point support to install on a default Raspian environment for your Raspberry Pi? Well, you just got your wish. Merry Christmas! See: Developer JDK 8 for ARM w/Hard-Float Here's a quote: The Java SE 8 Developer Preview Release for ARM including JavaFX (JDK 8) on Linux has been made available at http://jdk8.java.net. The Developer Preview is provided to the community to get feedback on the ongoing progress of the project. Developers can start developing applications using this build of Java SE 8 on an ARM device, such as the a Raspberry Pi. It's a regular JDK (Java SE 8 preview) for your Raspberry Pi, so you should note this means there is a javac (and the other typical JDK tools) available to compile your Java apps right there on the device! Woot! I'll cover step-by-step instructions how to do that in a future blog post. Stay tuned... Hinkmond

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  • About my main Project

    - by user207365
    My project is to build a AI(Artificial Intelligence) system in which i am planning to have a raspberry pi or Intel i3/i5 processor. Raspberry pi is small and efficient but i don't know whether it can support 2 TB or more external hard disk. Where as in Intel i can have internal hard disk and at the same time external also and will be more faster with 2gb or 4gb RAM. Which is better Raspberry pi or Intel,is it possible to stimulate my ubuntu in Intel processor. the main reason using processor it to give the system decision making capability ,understanding and analyzing capabilities using different algorithm's .my processor should analyze the condition take proper steps in running the appropriate application

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