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  • ACL architechture for a Software As a service in Sprgin 3.0

    - by geoaxis
    I am making a software as a service using Spring 3.0 (Spring MVC, Spring Security, Spring Roo, Hibernate) I have to come up with a flexible access control list mechanism.I have three different kinds of users System (who can do any thing to the system, includes admin and internal daemons) Operations (who can add and delete users, organizations, and do maintenance work on behalf of users and organizations) End Users (they belong to one or more organization, for each organization, the user can have one or more roles, like being organization admin, or organization read-only member) (role like orgadmin can also add users for that organization) Now my question is, how should i model the entity of User? If I just take the End User, it can belong to one or more organizations, so each user can contain a set of references to its organizations. But how do we model the users role for each organization, So for example User UX belongs to organizations og1, og2 and og3, and for og1 he is both orgadmin, and org-read-only-user, where as for og2 he is only orgadmin and for og3 he is only org-read-only-user I have the possibility of making each user belong to one organization alone, but that's making the system bounded and I don't like that idea (although i would still satisfy the requirement) If you have a better extensible ACL architecture, please suggest it. Since its a software as a service, one would expect that alot of different organizations would be part if the same system. I had one concern that it is not a good idea to keep og1 and og2 data on the same DB (if og1 decides to spawn a 100 reports on the system, og2 should not suffer) But that is some thing advanced for now and is not directly related to ACL but to the physical distribution of data and setup of services based on those ACLs This is a community Wiki question, please correct any thing which you wish to do so. Thanks

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  • Spring validation @AssertTrue

    - by Eqbal
    How do I display on a view jsp validation error message that occurs as a result of @AssertTrue annotation? It isn't tied to a specific field, but I am using it to validate a combination of fields. If I use <form:errors path="*"/> that will display all the errors for that form?

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  • Spring Security RememberMe Services with Session Cookie

    - by Jarrod
    I am using Spring Security's RememberMe Services to keep a user authenticated. I would like to find a simple way to have the RememberMe cookie set as a session cookie rather than with a fixed expiration time. For my application, the cookie should persist until the user closes the browser. Any suggestions on how to best implement this? Any concerns on this being a potential security problem? The primary reason for doing so is that with a cookie-based token, any of the servers behind our load balancer can service a protected request without relying on the user's Authentication to be stored in an HttpSession. In fact, I have explicitly told Spring Security to never create sessions using the namespace. Further, we are using Amazon's Elastic Load Balancing, and so sticky sessions are not supported. NB: Although I am aware that as of Apr. 08, Amazon now supports sticky sessions, I still do not want to use them for a handful of other reasons. Namely that the untimely demise of one server would still cause the loss of sessions for all users associated with it. http://aws.amazon.com/about-aws/whats-new/2010/04/08/support-for-session-stickiness-in-elastic-load-balancing/

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  • Creating a session scoped bean in Google App Engine using Spring 2.5

    - by zfranciscus
    Hi, I am trying to create a session bean in spring mvc. I am having the following error message when I run my google app engine server in my local box: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'siteController' defined in ServletContext resource [/WEB-INF/springapp-servlet.xml]: Cannot resolve reference to bean 'oAuth' while setting bean property 'oAuth'; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'oAuth' defined in BeanDefinition defined in ServletContext resource [/WEB-INF/springapp-servlet.xml]: Initialization of bean failed; nested exception is org.springframework.aop.framework.AopConfigException: **Cannot proxy target class because CGLIB2 is not available. Add CGLIB to the class path or specify proxy interfaces.** This is my spring mvc configuration: <bean name="oAuth" class="org.locate.server.FoursquareMgr" scope="session"> <aop:scoped-proxy/> </bean> <bean name="siteController" class="org.locate.server.SiteController" > <property name="oAuth" ref="oAuth"></property> </bean> I have enabled session in my google app engine appengine-web.xml file <sessions-enabled>true</sessions-enabled> I have included CGLIB2: cglib-2.1_3.jar and cglib-nodep-2.1_3.jar in my eclipse project build path. Has any one encountered this problem before ?

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  • Spring - SessionAttribute problem

    - by Max
    Hello, I want to implement something like this: @Controller @SessionAttributes("promotion") class PromotionController { @RequestMapping("showPromo") void showPromotionInfo( @RequestParam("promId") String promotionId, @ModelAttribute Promotion promotion, Errors errors ) { promotion = Promotions.get(promotionId); if (promotion == null || promotion.validates() == false) { errors.reject("promotion.invalid"); } return "prom"; } } The code is invalid, wont work and has some bad errors, but I don't know how to write it better. When user comes to an URL "showPromo?promId=15", controller should validate if the promotion is valid (outdated/non-existent/etc.). If it is valid - it should show it's information and save the promotion to model and session. If it's not - it should show some error about promotion being invalid. Problem is, I need to save the promotion in the session (for several requests) and don't want to use direct session management. Is it currently possible with Spring? Or am I doing something wrong? Could you please provide the optimal solution to my problem using Spring 3? Thanks in advance.

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  • Accessing Spring beans from a Tiles view (JSP)

    - by Sinuhe
    In Spring MVC I can access my beans in JSP using JstlView's exposedContextBeanNames (or exposeContextBeansAsAttributes). For example, then, in my JSP I can write (${properties.myProperty). But when the same JSP is a part of a tiles view, these properties aren't accessible. Is possible to configure Tiles properly or access these properties in another way? I'm using Spring MVC 3.0.2 and Tiles 2.2.1. Here's a bit of my configuration: <bean id="tilesViewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver"> <property name="order" value="1"/> <property name="viewClass" value="org.springframework.web.servlet.view.tiles2.TilesView" /> </bean> <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"/> <property name="order" value="2"/> <property name="prefix" value="/WEB-INF/views/"/> <property name="suffix" value=".jsp"/> <property name="exposedContextBeanNames"> <list><value>properties</value></list> </property> </bean>

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  • Doubt about instance creation by using Spring framework ???

    - by Arthur Ronald F D Garcia
    Here goes a command object which needs to be populated from a Spring form public class Person { private String name; private Integer age; /** * on-demand initialized */ private Address address; // getter's and setter's } And Address public class Address { private String street; // getter's and setter's } Now suppose the following MultiActionController @Component public class PersonController extends MultiActionController { @Autowired @Qualifier("personRepository") private Repository<Person, Integer> personRepository; /** * mapped To /person/add */ public ModelAndView add(HttpServletRequest request, HttpServletResponse response, Person person) throws Exception { personRepository.add(person); return new ModelAndView("redirect:/home.htm"); } } Because Address attribute of Person needs to be initialized on-demand, i need to override newCommandObject to create an instance of Person to initiaze address property. Otherwise, i will get NullPointerException @Component public class PersonController extends MultiActionController { /** * code as shown above */ @Override public Object newCommandObject(Class clazz) thorws Exception { if(clazz.isAssignableFrom(Person.class)) { Person person = new Person(); person.setAddress(new Address()); return person; } } } Ok, Expert Spring MVC and Web Flow says Options for alternate object creation include pulling an instance from a BeanFactory or using method injection to transparently return a new instance. First option pulling an instance from a BeanFactory can be written as @Override public Object newCommandObject(Class clazz) thorws Exception { /** * Will retrieve a prototype instance from ApplicationContext whose name matchs its clazz.getSimpleName() */ getApplicationContext().getBean(clazz.getSimpleName()); } But what does he want to say by using method injection to transparently return a new instance ??? Can you show how i implement what he said ??? ATT: I know this funcionality can be filled by a SimpleFormController instead of MultiActionController. But it is shown just as an example, nothing else

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  • Spring: Bean fails to read off values from external Properties file when using @Value annotation

    - by daydreamer
    XML Configuration <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:util="http://www.springframework.org/schema/util" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util.xsd"> <util:properties id="mongoProperties" location="file:///storage/local.properties" /> <bean id="mongoService" class="com.business.persist.MongoService"></bean> </beans> and MongoService looks like @Service public class MongoService { @Value("#{mongoProperties[host]}") private String host; @Value("#{mongoProperties[port]}") private int port; @Value("#{mongoProperties[database]}") private String database; private Mongo mongo; private static final Logger LOGGER = LoggerFactory.getLogger(MongoService.class); public MongoService() throws UnknownHostException { LOGGER.info("host=" + host + ", port=" + port + ", database=" + database); mongo = new Mongo(host, port); } public void putDocument(@Nonnull final DBObject document) { LOGGER.info("inserting document - " + document.toString()); mongo.getDB(database).getCollection(getCollectionName(document)).insert(document, WriteConcern.SAFE); } I write my MongoServiceTest as public class MongoServiceTest { @Autowired private MongoService mongoService; public MongoServiceTest() throws UnknownHostException { mongoRule = new MongoRule(); } @Test public void testMongoService() { final DBObject document = DBContract.getUniqueQuery("001"); document.put(DBContract.RVARIABLES, "values"); document.put(DBContract.PVARIABLES, "values"); mongoService.putDocument(document); } and I see failures in tests as 12:37:25.224 [main] INFO c.s.business.persist.MongoService - host=null, port=0, database=null java.lang.NullPointerException at com.business.persist.MongoServiceTest.testMongoService(MongoServiceTest.java:40) Which means bean was not able to read the values from local.properties local.properties ### === MongoDB interaction === ### host="127.0.0.1" port=27017 database=contract How do I fix this? update It doesn't seem to read off the values even after creating setters/getters for the fields. I am really clueless now. How can I even debug this issue? Thanks much!

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  • Spring MessageSource not being used during validation

    - by Jeremy
    I can't get my messages in messages.properties to be used during Spring validation of my form backing objects. app-config.xml: <bean id="messageSource" class="org.springframework.context.support.ResourceBundleMessageSource"> <property name="basename" value="messages" /> </bean> WEB-INF/classes/messages.properties: NotEmpty=This field should not be empty. Form Backing Object: ... @NotEmpty @Size(min=6, max=25) private String password; ... When I loop through all errors in the BindingResult and output the ObjectError's toString I get this: Field error in object 'settingsForm' on field 'password': rejected value []; codes [NotEmpty.settingsForm.password,NotEmpty.password,NotEmpty.java.lang.String,NotEmpty]; arguments [org.springframework.context.support.DefaultMessageSourceResolvable: codes [settingsForm.password,password]; arguments []; default message [password]]; default message [may not be empty] As you can see the default message is "may not be empty" instead of my message "This field should not be empty". I do get my correct message if I inject the messageSource into a controller and output this: messageSource.getMessage("NotEmpty", new Object [] {"password"}, "default empty message", null); So why isn't the validation using my messages.properties? I'm running Spring 3.1.1. Thanks!

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  • Spring Data Neo4J @Indexed(unique = true) not working

    - by Markus Lamm
    I'm new to Neo4J and I have, probably an easy question. There're NodeEntitys in my application, a property (name) is annotated with @Indexed(unique = true) to achieve the uniqueness like I do in JPA with @Column(unique = true). My problem is, that when I persist an entity with a name that already exists in my graph, it works fine anyway. But I expected some kind of exception here...?! Here' s an overview over basic my code: @NodeEntity public abstract class BaseEntity implements Identifiable { @GraphId private Long entityId; ... } public class Role extends BaseEntity { @Indexed(unique = true) private String name; ... } public interface RoleRepository extends GraphRepository<Role> { Role findByName(String name); } @Service public class RoleServiceImpl extends BaseEntityServiceImpl<Role> implements { private RoleRepository repository; @Override @Transactional public T save(final T entity) { return getRepository().save(entity); } } And this is my test: @Test public void testNameUniqueIndex() { final List<Role> roles = Lists.newLinkedList(service.findAll()); final String existingName = roles.get(0).getName(); Role newRole = new Role.Builder(existingName).build(); newRole = service.save(newRole); } That's the point where I expect something to go wrong! How can I ensure the uniqueness of a property, without checking it for myself?? THANKS IN ADVANCE FOR ANY IDEAS!! P.S.: I'm using neo4j 1.8.M07, spring-data-neo4j 2.1.0.BUILD-SNAPSHOT and Spring 3.1.2.RELEASE.

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  • Exception while exposing a bean in webservice using spring mvc

    - by Ajay
    Hi, I am using Spring 3.0.5.Release MVC for exposing a webservice and below is my servlet.xml <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd"> <!-- To enable @RequestMapping process on type level and method level --> <context:component-scan base-package="com.pyramid.qls.progressReporter.service" /> <bean class="org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping" /> <bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter"> <property name="messageConverters"> <list> <ref bean="marshallingConverter" /> <ref bean="atomConverter" /> <ref bean="jsonConverter" /> </list> </property> </bean> <bean id="marshallingConverter" class="org.springframework.http.converter.xml.MarshallingHttpMessageConverter"> <constructor-arg ref="jaxbMarshaller" /> <property name="supportedMediaTypes" value="application/xml"/> </bean> <bean id="atomConverter" class="org.springframework.http.converter.feed.AtomFeedHttpMessageConverter"> <property name="supportedMediaTypes" value="application/atom+xml" /> </bean> <bean id="jsonConverter" class="org.springframework.http.converter.json.MappingJacksonHttpMessageConverter"> <property name="supportedMediaTypes" value="application/json" /> </bean> <!-- Client --> <bean id="restTemplate" class="org.springframework.web.client.RestTemplate"> <property name="messageConverters"> <list> <ref bean="marshallingConverter" /> <ref bean="atomConverter" /> <ref bean="jsonConverter" /> </list> </property> </bean> <bean id="jaxbMarshaller" class="org.springframework.oxm.jaxb.Jaxb2Marshaller"> <property name="classesToBeBound"> <list> <value>com.pyramid.qls.progressReporter.impl.BatchProgressMetricsImpl</value> <value>com.pyramid.qls.progressReporter.datatype.InstrumentStats</value> <value>com.pyramid.qls.progressReporter.datatype.InstrumentInfo</value> <value>com.pyramid.qls.progressReporter.datatype.LoadOnConsumer</value> <value>com.pyramid.qls.progressReporter.datatype.HighLevelTaskStats</value> <value>com.pyramid.qls.progressReporter.datatype.SessionStats</value> <value>com.pyramid.qls.progressReporter.datatype.TaskStats</value> <value>com.pyramid.qls.progressReporter.datatype.ComputeStats</value> <value>com.pyramid.qls.progressReporter.datatype.DetailedInstrumentStats</value> <value>com.pyramid.qls.progressReporter.datatype.ImntHistoricalStats</value> </list> </property> </bean> <bean id="QPRXmlView" class="org.springframework.web.servlet.view.xml.MarshallingView"> <constructor-arg ref="jaxbMarshaller" /> </bean> <bean class="org.springframework.web.servlet.view.ContentNegotiatingViewResolver"> <property name="mediaTypes"> <map> <entry key="xml" value="application/xml"/> <entry key="html" value="text/html"/> </map> </property> <property name="viewResolvers"> <list> <bean class="org.springframework.web.servlet.view.BeanNameViewResolver"/> <bean id="viewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"/> <property name="prefix" value="/WEB-INF/jsp/"/> <property name="suffix" value=".jsp"/> </bean> </list> </property> </bean> <bean id="QPRController" class="com.pyramid.qls.progressReporter.service.QPRController"> <property name="jaxb2Mashaller" ref="jaxbMarshaller" /> </bean> </beans> Following is what i am doing in controller (QPRController) @RequestMapping(value = "/clientMetrics/{clientId}", method = RequestMethod.GET) public ModelAndView getBatchProgressMetrics(@PathVariable String clientId) { List<BatchProgressMetrics> batchProgressMetricsList = null; batchProgressMetricsList = batchProgressReporter.getBatchProgressMetricsForClient(clientId); ModelAndView mav = new ModelAndView("QPRXmlView", BindingResult.MODEL_KEY_PREFIX + "batchProgressMetrics", batchProgressMetricsList); return mav; } And i get the following: SEVERE: Servlet.service() for servlet rest threw exception javax.servlet.ServletException: Unable to locate object to be marshalled in model: {org.springframework.validation.BindingResult.batchProgressMetrics= Note that BatchProgressMetrics is an interface so my MAV is returning list of BatchProgressMetrics objects and i have entry for its impl in classes to be bound in servlet.xml. Can you please help me as to what i am doing wrong. And yes if i send just batchProgressMetricsList.get(0) in MAV it just works fine.

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  • spring-nullpointerexception- cant access autowired annotated service (or dao) in a no-annotations class

    - by user286806
    I have this problem that I cannot fix. From my @Controller, i can easily access my autowired @Service class and play with it no problem. But when I do that from a separate class without annotations, it gives me a NullPointerException. My Controller (works)- @Controller public class UserController { @Autowired UserService userService;... My separate Java class (not working)- public final class UsersManagementUtil { @Autowired UserService userService; or @Autowired UserDao userDao; userService or userDao are always null! Was just trying if any one of them works. My component scan setting has the root level package set for scanning so that should be OK. my servlet context - <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context" xmlns:tx="http://www.springframework.org/schema/tx" xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.0.xsd"> <!-- the application context definition for the springapp DispatcherServlet --> <!-- Enable annotation driven controllers, validation etc... --> <context:property-placeholder location="classpath:jdbc.properties" /> <context:component-scan base-package="x" /> <tx:annotation-driven transaction-manager="hibernateTransactionManager" /> <!-- package shortended --> <bean id="messageSource" class="o.s.c.s.ReloadableResourceBundleMessageSource"> <property name="basename" value="/WEB-INF/messages" /> </bean> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="${database.driver}" /> <property name="url" value="${database.url}" /> <property name="username" value="${database.user}" /> <property name="password" value="${database.password}" /> </bean> <!-- package shortened --> <bean id="viewResolver" class="o.s.w.s.v.InternalResourceViewResolver"> <property name="prefix"> <value>/</value> </property> <property name="suffix"> <value>.jsp</value> </property> <property name="order"> <value>0</value> </property> </bean> <!-- package shortened --> <bean id="sessionFactory" class="o.s.o.h3.a.AnnotationSessionFactoryBean"> <property name="dataSource" ref="dataSource" /> <property name="annotatedClasses"> <list> <value>orion.core.models.Question</value> <value>orion.core.models.User</value> <value>orion.core.models.Space</value> <value>orion.core.models.UserSkill</value> <value>orion.core.models.Question</value> <value>orion.core.models.Rating</value> </list> </property> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect">${hibernate.dialect}</prop> <prop key="hibernate.show_sql">${hibernate.show_sql}</prop> <prop key="hibernate.hbm2ddl.auto">${hibernate.hbm2ddl.auto}</prop> </props> </property> </bean> <bean id="hibernateTransactionManager" class="org.springframework.orm.hibernate3.HibernateTransactionManager"> <property name="sessionFactory" ref="sessionFactory" /> </bean> Any clue?

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  • How to manually set an authenticated user in Spring Security / SpringMVC

    - by David Parks
    After a new user submits a 'New account' form, I want to manually log that user in so they don't have to login on the subsequent page. The normal form login page going through the spring security interceptor works just fine. In the new-account-form controller I am creating a UsernamePasswordAuthenticationToken and setting it in the SecurityContext manually: SecurityContextHolder.getContext().setAuthentication(authentication); On that same page I later check that the user is logged in with: SecurityContextHolder.getContext().getAuthentication().getAuthorities(); This returns the authorities I set earlier in the authentication. All is well. But when this same code is called on the very next page I load, the authentication token is just UserAnonymous. I'm not clear why it did not keep the authentication I set on the previous request. Any thoughts? Could it have to do with session ID's not being set up correctly? Is there something that is possibly overwriting my authentication somehow? Perhaps I just need another step to save the authentication? Or is there something I need to do to declare the authentication across the whole session rather than a single request somehow? Just looking for some thoughts that might help me see what's happening here.

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  • Error 404 after change filter in web.xml

    - by Falci
    I'm trying to add Spring Security to the project. After adding a block of code in web.xml, all url's give 404. What is wrong? It's a Maven project, Spring MVC, hibernate, postgres. (I do not know what information is relevant to describe the scenario) <?xml version="1.0" encoding="UTF-8"?> <web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> <!-- The definition of the Root Spring Container shared by all Servlets and Filters --> <context-param> <param-name>contextConfigLocation</param-name> <param-value>/WEB-INF/spring/root-context.xml</param-value> </context-param> <!-- Creates the Spring Container shared by all Servlets and Filters --> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> <!-- Processes application requests --> <servlet> <servlet-name>appServlet</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <init-param> <param-name>contextConfigLocation</param-name> <param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value> </init-param> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>appServlet</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> <filter> <filter-name>encodingFilter</filter-name> <filter-class>org.springframework.web.filter.CharacterEncodingFilter</filter-class> <init-param> <param-name>encoding</param-name> <param-value>UTF-8</param-value> </init-param> <init-param> <param-name>forceEncoding</param-name> <param-value>true</param-value> </init-param> </filter> <filter-mapping> <filter-name>encodingFilter</filter-name> <url-pattern>/*</url-pattern> </filter-mapping> <!-- After insert this block, all URL's return 404 error --> <filter> <filter-name>springSecurityFilterChain</filter-name> <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class> </filter> <filter-mapping> <filter-name>springSecurityFilterChain</filter-name> <url-pattern>/*</url-pattern> </filter-mapping> </web-app> UPDATE: Grave: Exception starting filter springSecurityFilterChain org.springframework.beans.factory.NoSuchBeanDefinitionException: No bean named 'springSecurityFilterChain' is defined at org.springframework.beans.factory.support.DefaultListableBeanFactory.getBeanDefinition(DefaultListableBeanFactory.java:529) at org.springframework.beans.factory.support.AbstractBeanFactory.getMergedLocalBeanDefinition(AbstractBeanFactory.java:1094) at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:276) at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:196) at org.springframework.context.support.AbstractApplicationContext.getBean(AbstractApplicationContext.java:1079) at org.springframework.web.filter.DelegatingFilterProxy.initDelegate(DelegatingFilterProxy.java:217) at org.springframework.web.filter.DelegatingFilterProxy.initFilterBean(DelegatingFilterProxy.java:145) at org.springframework.web.filter.GenericFilterBean.init(GenericFilterBean.java:179) at org.apache.catalina.core.ApplicationFilterConfig.initFilter(ApplicationFilterConfig.java:277) at org.apache.catalina.core.ApplicationFilterConfig.getFilter(ApplicationFilterConfig.java:258) at org.apache.catalina.core.ApplicationFilterConfig.setFilterDef(ApplicationFilterConfig.java:382) at org.apache.catalina.core.ApplicationFilterConfig.<init>(ApplicationFilterConfig.java:103) at org.apache.catalina.core.StandardContext.filterStart(StandardContext.java:4638) at org.apache.catalina.core.StandardContext.startInternal(StandardContext.java:5294) at org.apache.catalina.util.LifecycleBase.start(LifecycleBase.java:150) at org.apache.catalina.startup.HostConfig.checkResources(HostConfig.java:1366) at org.apache.catalina.startup.HostConfig.check(HostConfig.java:1454) at org.apache.catalina.startup.HostConfig.lifecycleEvent(HostConfig.java:295) at org.apache.catalina.util.LifecycleSupport.fireLifecycleEvent(LifecycleSupport.java:119) at org.apache.catalina.util.LifecycleBase.fireLifecycleEvent(LifecycleBase.java:90) at org.apache.catalina.core.ContainerBase.backgroundProcess(ContainerBase.java:1379) at org.apache.catalina.core.ContainerBase$ContainerBackgroundProcessor.processChildren(ContainerBase.java:1537) at org.apache.catalina.core.ContainerBase$ContainerBackgroundProcessor.processChildren(ContainerBase.java:1547) at org.apache.catalina.core.ContainerBase$ContainerBackgroundProcessor.run(ContainerBase.java:1526) at java.lang.Thread.run(Thread.java:722)

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  • Spring AOP advice order

    - by Chetter Hummin
    In Spring AOP, I can add an aspect at the following locations before a method executes (using MethodBeforeAdvice) after a method executes (using AfterReturningAdvice) around a method (both before and after a method executes) (using MethodInterceptor) If I have all three types of advice, is the order of execution always as follows? Around (before part) Before Method itself After Around (after part)

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  • Pivotal Announces JSR-352 Compliance for Spring Batch

    - by reza_rahman
    Pivotal, the company currently funding development of the popular Spring Framework, recently announced JSR 352 (aka Batch Applications for the Java Platform) compliance for the Spring Batch project. More specifically, Spring Batch targets JSR-352 Java SE runtime compatibility rather than Java EE runtime compatibility. If you are surprised that APIs included in Java EE can pass TCKs targeted for Java SE, you should not be. Many other Java EE APIs target compatibility in Java SE environments such as JMS and JPA. You can read about Spring Batch's support for JSR-352 here as well as the Spring configuration to get JSR-352 working in Spring (typically a very low level implementation concern intended to be completely transparent to most JSR-352 users). JSR 352 is one of the few very encouraging cases of major active contribution to the Java EE standard from the Spring development team (the other major effort being Rod Johnson's co-leadership of JSR 330 along with Bob Lee). While IBM's Christopher Vignola led the spec and contributed IBM's years of highly mission critical batch processing experience from products like WebSphere Compute Grid and z/OS batch, the Spring team provided major influences to the API in particular for the chunk processing, listeners, splits and operational interfaces. The GlassFish team's own Mahesh Kannan also contributed, in particular by implementing much of the Java EE integration work for the reference implementation. This was an excellent example of multilateral engineering collaboration through the standards process. For many complex reasons it is not too hard to find evidence of less than amicable interaction between the Spring ecosystem and the Java EE standard over the years if one cares to dig deep enough. In reality most developers see Spring and Java EE as two sides of the same server-side Java coin. At the core Spring and Java EE ecosystems have always shared deep undercurrents of common user bases, bi-directional flows of ideas and perhaps genuine if not begrudging mutual respect. We can all hope for continued strength for both ecosystems and graceful high notes of collaboration via efforts like JSR 352.

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  • Greasemonkey Submit Form

    - by magixx
    I'm trying to autosubmit a form with greasemonkey however I'm not sure how to do it with this button. The button seems to have the following properties a class="blue-button" href="javascript:void(0)" onclick="Form.submit(this);" and the only form I see above is <form xmlns="http://www.w3.org/1999/xhtml" xmlns:s="http://www.blizzard.com/ns/store" action="/account/management/add-game.xml" autocomplete="off" method="post"> The page is here you can use "[email protected]" and "a1a1a1a1" as a login.

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  • Could someone explain Spring Security BasePermission.Create?

    - by Matthew Sowders
    I am working on a project that involves Spring Security ACL and I came across the create permission BasePermission.CREATE. Would someone please explain how this is supposed to work or what it allows someone to do? It is my understanding that each object has an acl, and each acl has many ace's, and each ace has an sid and a permission. How can you grant permission on an object to create it, if it must be created in order to attach the acl to it?

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  • Spring, autowire @Value from a database

    - by Guido
    I am using a properties File to store some configuration properties, that are accessed this way: @Value("#{configuration.path_file}") private String pathFile; Is it possible (with Spring 3) to use the same @Value annotation, but loading the properties from a database instead of a file ?

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  • References between Spring beans when using a NameSpaceHandler

    - by teabot
    I'm trying to use a Spring context namespace to build some existing configuration objects in an application. I have defined a context and pretty much have if working satisfactorily - however, I'd like one bean defined by my namespace to implicitly reference another: Consider the class named 'Node': public Class Node { private String aField; private Node nextNode; public Node(String aField, Node nextNode) { ... } Now in my Spring context I have something like so: <myns:container> <myns:node aField="nodeOne"/> <myns:node aField="nodeTwo"/> </myns:container> Now I'd like nodeOne.getNode() == nodeTwo to be true. So that nodeOne.getNode() and nodeTwo refer to the same bean instance. These are pretty much the relevant parts I have in my AbstractBeanDefinitionParser: public AbstractBeanDefinition parseInternal(Element element, ParserContext parserContext) { ... BeanDefinitionBuilder containerFactory = BeanDefinitionBuilder.rootBeanDefinition(ContainerFactoryBean.class); List<BeanDefinition> containerNodes = Lists.newArrayList(); String previousNodeBeanName; // iterate backwards over the 'node' elements for (int i = nodeElements.size() - 1; i >= 0; --i) { BeanDefinitionBuilder node = BeanDefinitionBuilder.rootBeanDefinition(Node.class); node.setScope(BeanDefinition.SCOPE_SINGLETON); String nodeField = nodeElements.getAttribute("aField"); node.addConstructorArgValue(nodeField); if (previousNodeBeanName != null) { node.addConstructorArgValue(new RuntimeBeanReference(previousNodeBeanName)); } else { node.addConstructorArgValue(null); } BeanDefinition nodeDefinition = node.getBeanDefinition(); previousNodeBeanName = "inner-node-" + nodeField; parserContext.getRegistry().registerBeanDefinition(previousNodeBeanName, nodeDefinition); containerNodes.add(node); } containerFactory.addPropertyValue("nodes", containerNodes); } When the application context is created my Node instances are created and recognized as singletons. Furthermore, the nextNode property is populated with a Node instance with the previous nodes configuration - however, it isn't the same instance. If I output a log message in Node's constructor I see two instances created for each node bean definition. I can think of a few workarounds myself but I'm keen to use the existing model. So can anyone tell me how I can pass these runtime bean references so that I get the correct singleton behaviour for my Node instances?

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