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  • how to submit a form without losing values already selected at the same form

    - by kawtousse
    Hi everyone, I am using jstl with dropdown lists. When i click submit button i success the specification but values int dropdownlists are reinitialized. So I want to submit form without loosing the values already selected in the form because I need to stay always at the same level in the form.To be more clear, user choose a value from ddl and click edit button to show other options and fill them at the same form without loosing what he has selected. I have tried to deal like that... <form action="myjsp.jsp" method="post"> <input type="Submit" value="Edit"> ...but it doesn't work. Thank you for your help.

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  • Saving a modified InfoPath form to its form library

    - by Nathan Lykken
    Within our corporate SharePoint 2007 site, there is a particular form library that contains 10 separate files. 9 of these are either Excel, Word, or PowerPoint files and one of these is an InfoPath 2007 form that serves as a report. After noticing an error within this InfoPath form, I saved this InfoPath form to my local directory and then, within the design mode of InfoPath, I modified this InfoPath form. What is the proper way to save this modified InfoPath form to its form library? Everything that I have tried results in nobody except myself having access to this modified InfoPath form. I can open this InfoPath form without error but when my coworkers try to open this InfoPath form on their machines, they receive this error: “The form cannot be opened because it requires the domain permission level and it currently has restricted permission. To fix this problem, open the form from the location it was published to."

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  • Spring boot JAR as windows service

    - by roblovelock
    I am trying to wrap a spring boot "uber JAR" with procrun. Running the following works as expected: java -jar my.jar I need my spring boot jar to automatically start on windows boot. The nicest solution for this would be to run the jar as a service (same as a standalone tomcat). When I try to run this I am getting "Commons Daemon procrun failed with exit value: 3" Looking at the spring-boot source it looks as if it uses a custom classloader: https://github.com/spring-projects/spring-boot/blob/master/spring-boot-tools/spring-boot-loader/src/main/java/org/springframework/boot/loader/JarLauncher.java I also get a "ClassNotFoundException" when trying to run my main method directly. java -cp my.jar my.MainClass Is there a method I can use to run my main method in a spring boot jar (not via JarLauncher)? Has anyone successfully integrated spring-boot with procrun? I am aware of http://wrapper.tanukisoftware.com/. However due to their licence I can't use it. UPDATE I have now managed to start the service using procrun. set SERVICE_NAME=MyService set BASE_DIR=C:\MyService\Path set PR_INSTALL=%BASE_DIR%prunsrv.exe REM Service log configuration set PR_LOGPREFIX=%SERVICE_NAME% set PR_LOGPATH=%BASE_DIR% set PR_STDOUTPUT=%BASE_DIR%stdout.txt set PR_STDERROR=%BASE_DIR%stderr.txt set PR_LOGLEVEL=Error REM Path to java installation set PR_JVM=auto set PR_CLASSPATH=%BASE_DIR%%SERVICE_NAME%.jar REM Startup configuration set PR_STARTUP=auto set PR_STARTIMAGE=c:\Program Files\Java\jre7\bin\java.exe set PR_STARTMODE=exe set PR_STARTPARAMS=-jar#%PR_CLASSPATH% REM Shutdown configuration set PR_STOPMODE=java set PR_STOPCLASS=TODO set PR_STOPMETHOD=stop REM JVM configuration set PR_JVMMS=64 set PR_JVMMX=256 REM Install service %PR_INSTALL% //IS//%SERVICE_NAME% I now just need to workout how to stop the service. I am thinking of doing someting with the spring-boot actuator shutdown JMX Bean. What happens when I stop the service at the moment is; windows fails to stop the service (but marks it as stopped), the service is still running (I can browse to localhost), There is no mention of the process in task manager (Not very good! unless I am being blind).

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  • Table Decorators on Zend Framework Form

    - by ulduz114
    hello i created a form that it decorates as table form its my code for decorates $this->setElementDecorators(array( 'ViewHelper', 'Errors' array(array('data'=>'HtmlTag'), array('tag'=>'td','class'=>'element')), array('Label',array('tag'=>'td')), array(array('row'=>'HtmlTag'),array('tag'=>'tr')), )); $this->setDecorators(array( 'FormElements', array('HtmlTag',array('tag'=>'table')), 'Form' )); it works correctly, now i wana errors message decorates too what do i change my code?

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  • Access VBA sub with form as parameter doesn't alter the form

    - by Ski
    I have a Microsoft Access 2003 file with various tables of data. Each table also has a duplicate of it, with the name '[original table name]_working'. Depending on the user's choices in the switchboard, the form the user choose to view must switch its recordsource table to the working table. I refactored the relevant code to do such a thing into the following function today: Public Sub SetFormToWorking(ByRef frm As Form) With frm .RecordSource = rst![Argument] & "_working" .Requery Dim itm As Variant For Each itm In .Controls If TypeOf itm Is subForm Then With Item Dim childFields As Variant, masterFields As Variant childFields = .LinkChildFields masterFields = .LinkMasterFields .Form.RecordSource = .Form.RecordSource & "_working" .LinkChildFields = childFields .LinkMasterFields = masterFields .Form.Requery End With End If Next End With End Sub The lines of code that call the function look like this: SetFormToWorking Forms(rst![Argument]) and SetFormToWorking Forms(cmbTblList) For some reason, the above function doesn't change the recordsource for the form. I added the 'ByRef' keyword to the parameter just to be certain that it was passing by reference, but no dice. Hopefully someone here can tell me what I've done wrong?

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  • Submit Form Equivalent To WML

    - by Nathan Campos
    I'm playing a little bit with WML with PHP, then I want to know what is the equivalent of this on WML: <form action="upload_file.php" method="post"enctype="multipart/form-data"> <label for="file">File:</label><br /> <input type="file" name="file" id="file" /><br /> <input type="submit" name="submit" value="Submit" /> </form>

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  • how to check if the enddate is after the startdate in a zend form

    - by murze
    I have a zend form with a start- and an endate. $form = new Zend_Form(); $form->setName($this->formName) ->setMethod('post'); $feStartdate = new Zend_Form_Element_Text('startdate'); $feEnddate = new Zend_Form_Element_Text('enddate'); $form->addElement($feStartDate) ->addElement($feEndDate) ->addElement('submit', 'submit', array('label' => 'Save')); I assume I must write a custom validator for to check this. How would this custom validator look like and how can I call it? I assume something like $feEnddate->addValidator('dateComesAfter', $feStartDate)

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  • Spring.NET & Immediacy CMS (or how to inject to server side controls without using PageHandlerFactor

    - by Simon Rice
    Is there any way to inject dependencies into an Immediacy CMS control using Spring.NET, ideally without having to use to ContextRegistry when initialising the control? Update, with my own answer The issue here is that Immediacy already has a handler defined in web.config that deals with all aspx pages, & so it's not possible add an entry for Spring.NET's PageHandlerFactory in web.config as per a normal webforms app. That rules out making the control implement ISupportsWebDependencyInjection. Furthermore, most of Immediacy's generated pages are aspx pages that don't physically exist on the drive. I have changed the title of the question to reflect this. What I have done to get Dependency Injection working is: Add the usual entries to web.config for Spring.NET as outlined in the documentation, except for the adding the entry to the <httpHandlers> section. In this case I've got my object definitions in Spring.config. Create the following abstract base class that will deal with all of the Dependency Injection work: DIControl.cs public abstract class DIControl : ImmediacyControl { protected virtual string DIName { get { return this.GetType().Name; } } protected override void OnInit(EventArgs e) { if (ContextRegistry.GetContext().GetObject(DIName, this.GetType()) != null) ContextRegistry.GetContext().ConfigureObject(this, DIName); base.OnInit(e); } } For non-immediacy controls, you can make this server side control inherit from Control or whatever subclass of that you like. For any control with which you wish to use with Spring.NET's Inversion of Control container, define it to inherit from DIControl & add the relelvant entry to Spring.config, for example: SampleControl.cs public class SampleControl : DIControl, INamingContainer { public string Text { get; set; } protected string InjectedText { get; set; } public SampleControl() : base() { Text = "Hello world"; } protected override void RenderContents(HtmlTextWriter output) { output.Write(string.Format("{0} {1}", Text, InjectedText)); } } Spring.config <objects xmlns="http://www.springframework.net"> <object id="SampleControl" type="MyProject.SampleControl, MyAssembly"> <property name="InjectedText" value="from Spring.NET" /> </object> </objects> You can optionally override DIName if you wish to name your entry in Spring.config differently from the name of your class. Provided everything's done correctly, you will have the control writing out "Hello world from Spring.NET!" when used in a page. This solution uses Spring.NET's ContextRegistry from within the control, but I would be surprised if there's no way around that for Immediacy at least since the page objects themselves aren't accessible. However, can this be improved at all from a Spring.NET perspective? Is there maybe an Immediacy plugin that already does this that I'm completely unaware of? Or is there an approach that does this in a more elegant way? I'm open to suggestions.

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  • @Secured not working

    - by user3640507
    I am new to spring and trying to implement Role based authorization with the help of @Secured annotation. I have a method which is specifically for ADMIN and I have written @Secured ("ROLE_ADMIN") to secure it. @Secured ("ROLE_ADMIN") public void HelloUser(String name) { System.out.println("Hello ADMIN"); } Now when I call this method by creating a class object it gets called eventhough user dont have ADMIN authority But when I dont create an object and use @autowired annotation instead then it works i.e User is not allowed to access this method. In my security.xml as well as servlet.xml I have added <global-method-security secured-annotations="enabled" /> Can some one please tell me where I am going wrong or is this the natural behaviour in spring ?

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  • Zend_Form : Adding fields in sub-forms on user's click

    - by anu iyer
    I'm having a zend form - comprised of a number of zend - sub forms, where the user is creating a new question (its a content management system). In one of the subforms, the user can click on a button to add more textfields, like this: [----------] [----------] [click to add more] which should give [----------] [----------] [----------] [click to add more] I'm trying to set a flag in the sub form in question - or set a count on how many times the button has been clicked, to add that many total fields to the subform - but its simply not working. I tried using a static count variable - but the value doesnt get incremented at all. Any thoughts on how to do this in a Zend-subform within a zend form? I'll definitely update if I hit a solution. Thanks!

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  • Spring Roo Database Reverse Engineer with Oracle

    - by kerry
    So you are trying to reverse engineer an Oracle database with roo? Unfortunately, due to licensing restrictions with the Oracle JDBC Drivers, this is a little difficult. There are a few blog posts and forum threads that address the problem but I figured I would post what worked for me here. First, you need to download the appropriate Oracle Drivers from Oracle. The required login, stringent password requirements, nosy registration form, and general system instability made this a pretty painful step for me. I’d also like to say that companies that have password requirements that don’t allow symbols (or any other non-standard requirement) have a special place in my heart. Having to recover my password every time I go to your site virtually guarantees I will only go there when I absolutely have to (not often). Anyways, once you have it downloaded you need to install is with maven: mvn install:install-file -Dfile=~/Downloads/ojdbc6.jar -DgroupId=com.oracle -DartifactId=ojdbc6 -Dversion=11.2.0.3 -Dpackaging=jar -DgeneratePom=true Here comes the fun part. You need to create an osgi wrapper for the driver to install it in roo. Otherwise, roo cannot see the driver. Create a new folder and put the contents of the oracle roo addon pom gist I created. Now build it with maven. You may want to change some of the artifact ids and dependencies for your particular situation. mvn package No open a roo shell and execute the following command: osgi install --url file:///Users/me/my-osgi-project/target/the-jar-it-built.jar Now run (in roo): jpa setup --provider HIBERNATE --database ORACLE dependency remove --groupId com.oracle --artifactId ojdbc14 --version 10.2.0.2 dependency add --groupId com.oracle --artifactId ojdbc6 --version 11.2.0.3 database properties set --key database.driverClassName --value oracle.jdbc.OracleDriver database properties set --key database.url --value jdbc:oracle:thin:@%YOUR_CONNECTION_INFO% database properties set --key database.username --value %YOUR_USERNAME% database properties set --key database.password --value %YOUR_PASSWORD% database reverse engineer --schema %YOUR_SCHEMA% --package ~.domain If you have any package loading exceptions when running the reverse engineer command you can uninstall the osgi bundle, set the package to optional in the osgi pom in the IncludedPackages tag (javax.some.package.*;resolution:=optional) rebuild, then reinstall in roo.

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  • Form Validation Options

    The steps involved in transmitting form data from the client to the Web server User loads web form. User enters data in to web form fields User clicks submit On submit page validates fields using JavaScript. If validation errors are found then the validation script stops the browser from canceling posting the data to the web server and displays error messages as needed. If the form passes the data validation process then the browser will URL encode the values of every field and post it to the server.  The server reads the posted data from the query string and then again validates the data just to ensure data consistency and to prevent any non-validated data because JavaScript was turned off on the clients browser from being inserted in to a database or passed on to other process. If the data passes the second validation check then the server side code will continue with the requested processes. In my opinion, it is mandatory to validate data using client side and server side validation as a fail over process. The client side validation allows users to correct any error before they are sent to the web server for processing, and this allows for an immediate response back to the user regarding data that is not correct or in the proper format that is desired. In addition, this prevents unnecessary interaction between the user and the web server and will free up the server over time compared to doing only server side validation. Server validation is the last line of defense when it comes to validation because you can check to ensure the user’s data is correct before it is used in a business process or stored to a database. Honestly, I cannot foresee a scenario where I would only want to use one form of validation over another especially with the current cost of creating and maintaining data. In my opinion, the redundant validation is well worth the overhead.

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  • Play audio file data - Spring MVC

    - by Vijay Veeraraghavan
    In my web-application, I have various audio clips uploaded by the users in the database stored in the BLOB column. The audio files are low bit rate WAV files. The clips are secured, one can see only those clips he has uploaded. Instead of user downloading the clip and playing it in his player, I need it be steamed online in the web page itself. In the jsp I use the <audio> tag with the source mapping to the controller mappping url. <td> <audio controls><source src="recfile/${au.id}" type="audio/mpeg" /></audio> </td> Where, the recfile is the request mapping and the au.id is the audio id. In the controller I process the request like below @RequestMapping(value = "/recfile/{id}", method = RequestMethod.GET, produces = { MediaType.APPLICATION_OCTET_STREAM_VALUE }) public HttpEntity<byte[]> downloadRecipientFile(@PathVariable("id") int id, ModelMap model, HttpServletResponse response) throws IOException, ServletException { LOGGER.debug("[GroupListController downloadRecipientFile]"); VoiceAudioLibrary dGroup = audioClipService.findAudioClip(id); if (dGroup == null || dGroup.getAudioData() == null || dGroup.getAudioData().length <= 0) { throw new ServletException("No clip found/clip has not data, id=" + id); } HttpHeaders header = new HttpHeaders(); I tried this too //header.setContentType(new MediaType("audio", "mp3")); header.setContentType(new MediaType("audio", "vnd.wave"); header.setContentLength(dGroup.getAudioData().length); return new HttpEntity<byte[]>(dGroup.getAudioData(), header); } When the jsp loads, the controller get the request, it serves back the audio data fetched from the database, the jsp too shows the player with the controls. But when I play it nothing happens. Why is it? Am I missing anything in the configuration? Am I doing it right?

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  • Spring 3.0 making JSON response using jackson message converter

    - by dupdup
    i configure my messageconverter as Jackson's then class Foo{int x; int y} and in controller @ResponseBody public Foo method(){ return new Foo(3,4) } from that i m expecting to return a JSON string {x:'3',y:'4'} from server without any other configuration. but getting 404 error response to my ajax request If the method is annotated with @ResponseBody, the return type is written to the response HTTP body. The return value will be converted to the declared method argument type using HttpMessageConverters. Am I wrong ? or should I convert my response Object to Json string myself using serializer and then returning that string as response.(I could make string responses correctly) or should I make some other configurations ? like adding annotations for class Foo here is my conf.xml <bean id="jacksonMessageConverter" class="org.springframework.http.converter.json.MappingJacksonHttpMessageConverter"> <bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter"> <property name="messageConverters"> <list> <ref bean="jacksonMessageConverter"/> </list> </property>

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  • using Spring JdbcTemplate for multiple database operations

    - by Joel Carranza
    I like the apparent simplicity of JdbcTemplate but am a little confused as to how it works. It appears that each operation (query() or update()) fetches a connection from a datasource and closes it. Beautiful, but how do you perform multiple SQL queries within the same connection? I might want to perform multiple operations in sequence (for example SELECT followed by an INSERT followed by a commit) or I might want to perform nested queries (SELECT and then perform a second SELECT based on result of each row). How do I do that with JdbcTemplate. Am I using the right class?

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  • Spring MVC Project's .war file not able to deploy using JRE in jetty server

    - by PDKumar
    IDE: STS(Eclipse) Server: Jetty-distribution-8.1.15.v20140411 I have created a SpringsMVC Project using Template available in STS tool(New-Springs Project- Springs MVC Project). I generated a war file(SpringsMVC.war) and placed it in /webapps folder of Jetty server. Now I started Jetty using JRE's 'java' , D:\jetty-distribution-8.1.15.v20140411"C:\Program Files (x86)\Java\jre7\bin\java" -jar start.jar Now when I tried to access my application in browser, it shows the below error; HTTP ERROR 500 Problem accessing /SpringMVCProject1/. Reason: Server Error Caused by: org.apache.jasper.JasperException: PWC6345: There is an error in invoking javac. A full JDK (not just JRE) is required at org.apache.jasper.compiler.DefaultErrorHandler.jspError(DefaultErrorHandler.java:92) at org.apache.jasper.compiler.ErrorDispatcher.dispatch(ErrorDispatcher.java:378) at org.apache.jasper.compiler.ErrorDispatcher.jspError(ErrorDispatcher.java:119) at org.apache.jasper.compiler.Jsr199JavaCompiler.compile(Jsr199JavaCompiler.java:208) at org.apache.jasper.compiler.Compiler.generateClass(Compiler.java:384) at org.apache.jasper.compiler.Compiler.compile(Compiler.java:453) at org.apache.jasper.JspCompilationContext.compile(JspCompilationContext.java:625) at org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:374) at org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:492) at org.apache.jasper.servlet.JspServlet.service(JspServlet.java:378) at javax.servlet.http.HttpServlet.service(HttpServlet.java:848) at org.eclipse.jetty.servlet.ServletHolder.handle(ServletHolder.java:684) at org.eclipse.jetty.servlet.ServletHandler.doHandle(ServletHandler.java:503) at org.eclipse.jetty.server.handler.ScopedHandler.handle(ScopedHandler.java:137) at org.eclipse.jetty.security.SecurityHandler.handle(SecurityHandler.java:575) at org.eclipse.jetty.server.session.SessionHandler.doHandle(SessionHandler.java:231) at org.eclipse.jetty.server.handler.ContextHandler.doHandle(ContextHandler.java:1086) at org.eclipse.jetty.servlet.ServletHandler.doScope(ServletHandler.java:429) at org.eclipse.jetty.server.session.SessionHandler.doScope(SessionHandler.java:193) at org.eclipse.jetty.server.handler.ContextHandler.doScope(ContextHandler.java:1020) at org.eclipse.jetty.server.handler.ScopedHandler.handle(ScopedHandler.java:135) at org.eclipse.jetty.server.Dispatcher.forward(Dispatcher.java:276) at org.eclipse.jetty.server.Dispatcher.forward(Dispatcher.java:103) at org.springframework.web.servlet.view.InternalResourceView.renderMergedOutputModel(InternalResourceView.java:238) at org.springframework.web.servlet.view.AbstractView.render(AbstractView.java:262) at org.springframework.web.servlet.DispatcherServlet.render(DispatcherServlet.java:1180) at org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:950) at org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:852) at org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:882) at org.springframework.web.servlet.FrameworkServlet.doGet(FrameworkServlet.java:778) at javax.servlet.http.HttpServlet.service(HttpServlet.java:735) at javax.servlet.http.HttpServlet.service(HttpServlet.java:848) at org.eclipse.jetty.servlet.ServletHolder.handle(ServletHolder.java:684) at org.eclipse.jetty.servlet.ServletHandler.doHandle(ServletHandler.java:503) at org.eclipse.jetty.server.handler.ScopedHandler.handle(ScopedHandler.java:137) at org.eclipse.jetty.security.SecurityHandler.handle(SecurityHandler.java:533) at org.eclipse.jetty.server.session.SessionHandler.doHandle(SessionHandler.java:231) at org.eclipse.jetty.server.handler.ContextHandler.doHandle(ContextHandler.java:1086) at org.eclipse.jetty.servlet.ServletHandler.doScope(ServletHandler.java:429) at org.eclipse.jetty.server.session.SessionHandler.doScope(SessionHandler.java:193) at org.eclipse.jetty.server.handler.ContextHandler.doScope(ContextHandler.java:1020) at org.eclipse.jetty.server.handler.ScopedHandler.handle(ScopedHandler.java:135) at org.eclipse.jetty.server.handler.ContextHandlerCollection.handle(ContextHandlerCollection.java:255) at org.eclipse.jetty.server.handler.HandlerCollection.handle(HandlerCollection.java:154) at org.eclipse.jetty.server.handler.HandlerWrapper.handle(HandlerWrapper.java:116) at org.eclipse.jetty.server.Server.handle(Server.java:370) at org.eclipse.jetty.server.AbstractHttpConnection.handleRequest(AbstractHttpConnection.java:494) at org.eclipse.jetty.server.AbstractHttpConnection.headerComplete(AbstractHttpConnection.java:971) at org.eclipse.jetty.server.AbstractHttpConnection$RequestHandler.headerComplete(AbstractHttpConnection.java:1033) at org.eclipse.jetty.http.HttpParser.parseNext(HttpParser.java:644) at org.eclipse.jetty.http.HttpParser.parseAvailable(HttpParser.java:235) at org.eclipse.jetty.server.AsyncHttpConnection.handle(AsyncHttpConnection.java:82) at org.eclipse.jetty.io.nio.SelectChannelEndPoint.handle(SelectChannelEndPoint.java:696) at org.eclipse.jetty.io.nio.SelectChannelEndPoint$1.run(SelectChannelEndPoint.java:53) at org.eclipse.jetty.util.thread.QueuedThreadPool.runJob(QueuedThreadPool.java:608) at org.eclipse.jetty.util.thread.QueuedThreadPool$3.run(QueuedThreadPool.java:543) at java.lang.Thread.run(Unknown Source) But if I use JDK's java, war file gets deployed and output displayed perfectly. D:\jetty-distribution-8.1.15.v20140411"C:\Program Files (x86)\Java\jdk1.7.0_55\bin\java" -jar start.jar Hello world! The time on the server is August 20, 2014 3:42:53 PM IST. Please tell is it not possible to use JRE to execute a "SpringsMVCProject"?

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  • Testing Spring MVC Output

    - by Sammy
    Hello, So I have an MVC project that exposes my services in JSON format. What would be the ideal method of (unit?) testing whether or not my methods return correct content (in terms of JSON syntax as well)? Thank you, Sammy

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  • Spring WS & Validator interceptor

    - by mada
    I have a endpoint mapping a webservice which is used to insert in the dabatabase some keywords: @Transactional(readOnly = false,isolation= Isolation.SERIALIZABLE) public Source saveKW(...). The input is a request. I would like to add an interceptor on the method in order to validate the parameters. this one will read some values from the DB. i would like that this interceptor is EMBED in the transaction declared for the endpoint (or this opposite). In other words, i want them to be in the same transaction. Ideally im looking for something like this with annotation: @Transactional(readOnly = false,isolation= Isolation.SERIALIZABLE) @validator("KeyWordValidaor.class") public Source saveKW(...) where KeyWordValidaor will be class validating the parameters. Have you any idea or short examples to implements this like this way or in a other real way?

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  • UndeclaredThrowableException due to SQLException in Spring + iBatis?

    - by jr
    Hello, I am getting the following exception when I typo the SQL driver name or the database server is offline, basically any SQLException. I can't determine where the UndeclaredThrowableException is coming from. Line 194 in SqlMapClientTemplate is this: logger.debug("Obtained JDBC Connection [" + springCon + "] for iBATIS operation"); Here is the trace: java.lang.reflect.UndeclaredThrowableException $Proxy59.toString(Unknown Source) java.lang.String.valueOf(Unknown Source) java.lang.StringBuffer.append(Unknown Source) org.springframework.orm.ibatis.SqlMapClientTemplate.execute(SqlMapClientTemplate.java:194) org.springframework.orm.ibatis.SqlMapClientTemplate.executeWithListResult(SqlMapClientTemplate.java:249) org.springframework.orm.ibatis.SqlMapClientTemplate.queryForList(SqlMapClientTemplate.java:296) org.springframework.orm.ibatis.SqlMapClientTemplate.queryForList(SqlMapClientTemplate.java:290) some of my reading points to some type of class loading problem? I can't figure out where the $Proxy is getting introduced?

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  • Bypass django form validation on new form instance

    - by Thomas Schultz
    Hello! I have a situation where we are trying to autofill some form data on the second page of a signup and I was wondering if there's a way to bypass the entire form validation when we pass in only a couple of fields? so we have something like form = NewForm(request.POST) Where request.POST only contains some of the fields in NewForm(). So the page loads and there is feedback about how some fields are not filled in yet. This all happens from the GET request of the second page. Is there a way to do something like... form = NewForm(request.POST, validate=False)

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  • Which view will be resolved, code from spring's docs

    - by Blankman
    So when you go to /appointments the get() action is called, so then would the view be get.jsp (assuming you are using .jsp, and assuming you are mapping action names to views)? And what about the getnewform? It seems to be returning an object? Is that basically passed into the view? @Controller @RequestMapping("/appointments") public class AppointmentsController { private final AppointmentBook appointmentBook; @Autowired public AppointmentsController(AppointmentBook appointmentBook) { this.appointmentBook = appointmentBook; } @RequestMapping(method = RequestMethod.GET) public Map<String, Appointment> get() { return appointmentBook.getAppointmentsForToday(); } @RequestMapping(value="/{day}", method = RequestMethod.GET) public Map<String, Appointment> getForDay(@PathVariable @DateTimeFormat(iso=ISO.DATE) Date day, Model model) { return appointmentBook.getAppointmentsForDay(day); } @RequestMapping(value="/new", method = RequestMethod.GET) public AppointmentForm getNewForm() { return new AppointmentForm(); } @RequestMapping(method = RequestMethod.POST) public String add(@Valid AppointmentForm appointment, BindingResult result) { if (result.hasErrors()) { return "appointments/new"; } appointmentBook.addAppointment(appointment); return "redirect:/appointments"; } } In the example, the @RequestMapping is used in a number of places. The first usage is on the type (class) level, which indicates that all handling methods on this controller are relative to the /appointments path. The get() method has a further @RequestMapping refinement: it only accepts GET requests, meaning that an HTTP GET for /appointments invokes this method. The post() has a similar refinement, and the getNewForm() combines the definition of HTTP method and path into one, so that GET requests for appointments/new are handled by that method.

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  • Spring properties (property-placeholder) autowiring

    - by peperg
    I have in my applicationContext.xml <context:property-placeholder location="classpath*:*.properties" /> <bean id="clientPreferencesManager" class="pl.bildpresse.bildchat2.business.ClientPreferencesManager" > <property name="clientApiUrl" value="${clientapi.url}" /> </bean> Is it possible to do the same by autowire ? Something like : @Autowired @Qualifier("${clientapi.url}") public void setClientApiUrl(String clientApiUrl) { this.clientApiUrl = clientApiUrl; }

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  • Spring Annotation trailing slash

    - by Eqbal
    I have a controller with @RequestMapping for root path "/". There are other controllers with say a @RequestMapping of "/test" etc. My application seems to be mapping correctly for paths like /appname/test, but if I add a trailing slash to the path, like so "/appname/test/ then it maps to the controller that has the @RequestMapping for root path "/". Any idea why?

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  • how to submit a form without loosing values already selected at the same form

    - by kawtousse
    Hi everyone, I am using jstl with dropdown lists. When i click submit button i success the specification but values int dropdownlists are reinitialized. So I want to submit form without loosing the values already selected in the form because I need to stay always at the same level in the form.To be more clear, user choose a value from ddl and click edit button to show other options and fill them at the same form without loosing what he has selected. I have tried to deal like that: but it doesn't work. think you for your help.

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