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  • Odd log entries when starting up PotgreSQL

    - by Shadow
    When restarting pgSQL, I get the following log entries: 2010-02-10 16:08:05 EST LOG: received smart shutdown request 2010-02-10 16:08:05 EST LOG: autovacuum launcher shutting down 2010-02-10 16:08:05 EST LOG: shutting down 2010-02-10 16:08:05 EST LOG: database system is shut down 2010-02-10 16:08:07 EST LOG: database system was shut down at 2010-02-10 16:08:05 EST 2010-02-10 16:08:07 EST LOG: autovacuum launcher started 2010-02-10 16:08:07 EST LOG: database system is ready to accept connections 2010-02-10 16:08:07 EST LOG: connection received: host=[local] 2010-02-10 16:08:07 EST LOG: incomplete startup packet 2010-02-10 16:08:07 EST LOG: connection received: host=[local] 2010-02-10 16:08:07 EST FATAL: password authentication failed for user "postgres" 2010-02-10 16:08:08 EST LOG: connection received: host=[local] 2010-02-10 16:08:08 EST FATAL: password authentication failed for user "postgres" 2010-02-10 16:08:08 EST LOG: connection received: host=[local] 2010-02-10 16:08:08 EST FATAL: password authentication failed for user "postgres" 2010-02-10 16:08:09 EST LOG: connection received: host=[local] 2010-02-10 16:08:09 EST FATAL: password authentication failed for user "postgres" 2010-02-10 16:08:09 EST LOG: connection received: host=[local] 2010-02-10 16:08:09 EST FATAL: password authentication failed for user "postgres" 2010-02-10 16:08:10 EST LOG: connection received: host=[local] 2010-02-10 16:08:10 EST FATAL: password authentication failed for user "postgres" 2010-02-10 16:08:10 EST LOG: connection received: host=[local] 2010-02-10 16:08:10 EST FATAL: password authentication failed for user "postgres" 2010-02-10 16:08:11 EST LOG: connection received: host=[local] 2010-02-10 16:08:11 EST FATAL: password authentication failed for user "postgres" 2010-02-10 16:08:11 EST LOG: connection received: host=[local] 2010-02-10 16:08:11 EST FATAL: password authentication failed for user "postgres" 2010-02-10 16:08:12 EST LOG: connection received: host=[local] 2010-02-10 16:08:12 EST FATAL: password authentication failed for user "postgres" 2010-02-10 16:08:12 EST LOG: connection received: host=[local] 2010-02-10 16:08:12 EST FATAL: password authentication failed for user "postgres" 2010-02-10 16:08:12 EST LOG: connection received: host=[local] 2010-02-10 16:08:12 EST LOG: incomplete startup packet My question regarding a potential consequence of this is posted here: http://stackoverflow.com/questions/2238954/mdb2-says-connection-failed-db-logs-say-otherwise , but I didn't realize this was happening when I asked that question, and I figured this [part of the] problem is for SF. Edit: I can connect to the database and manipulate things normally with the psql CLI and the postgres user.

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  • Recieving a 500 Internal Server error after login success?

    - by Jeremy Quick
    I created my first member login form which takes the typical username and password and then sends it to the code below: checklogin.php: mysql_connect($db_host, $db_username, $db_password) or die(mysql_error()); mysql_select_db($db_database) or die(mysql_error()); $username=$_POST['username']; $password=$_POST['password']; $username = stripslashes($username); $password = stripslashes($password); $username = mysql_real_escape_string($username); $password = mysql_real_escape_string($password); $sql="SELECT * FROM users WHERE username='$username' and password='$password'"; $result=mysql_query($sql); $count=mysql_num_rows($result); if($count == 1) //ERROR APPEARS TO TAKE PLACE HERE { session_start(); $_SESSION['username'] = $username; $_SESSION['password'] = $password; header('login_success.php'); } else { header("location:login_fail.php"); } If I type in the wrong information everything works properly so I know the error appears to be taking effect in the marked if statement. I have been searching the internet now looking for solutions but none seem to match mine or I am overlooking them. I've made a few changes which brought me to this point, before I was receiving deprecation warnings. Also, I have checked the logs and they are empty of errors relating to this.

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  • Exception:Cannot Start your application.The Workgroup information file is missing or opened exclusiv

    - by Jeev
    We were getting this error when trying   to connect  to a password protected access file. This is what the connection string looked likestring conString =@"Provider=Microsoft.Jet.OLEDB.4.0;Data Source="Path to your access file";User Id=;Password=password";To fix the issue this is what we didstring conString =@"Provider=Microsoft.Jet.OLEDB.4.0;Data Source="Path to your access file";Jet OLEDB:Database Password=password";  We removed the User id and changed the password to Jet OLEDB:Database Password Hope this helps someone   

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  • pass username and password to get-credential or run sql query without using invoke-sqlcmd in Powersh

    - by Emo
    I am trying to connect to a remote sql database and simply run the "select @@servername" query in Powershell. I'm trying to do this without using integrated security. I've been struggling with "get-credential" and "invoke-sqlcmd", only to find (I think), that you can't pass the password from "get-credential" to another Powershell cmdlets. Here's the code I'm using: add-pssnapin sqlserverprovidersnapin100 add-pssnapin sqlservercmdletsnapin100 load assemblies [Reflection.Assembly]::Load("Microsoft.SqlServer.Smo, Version=9.0.242.0, Culture=neutral, PublicKeyToken=89845dcd8080cc91") [Reflection.Assembly]::Load("Microsoft.SqlServer.SqlEnum, Version=9.0.242.0, Culture=neutral, PublicKeyToken=89845dcd8080cc91") [Reflection.Assembly]::Load("Microsoft.SqlServer.SmoEnum, Version=9.0.242.0, Culture=neutral, PublicKeyToken=89845dcd8080cc91") [Reflection.Assembly]::Load("Microsoft.SqlServer.ConnectionInfo, Version=9.0.242.0, Culture=neutral,PublicKeyToken=89845dcd8080cc91") connect to SQL Server $serverName = "HLSQLSRV03" $server = New-Object -typeName Microsoft.SqlServer.Management.Smo.Server -argumentList $serverName login using SQL authentication $server.ConnectionContext.LoginSecure=$false; $credential = Get-Credential $userName = $credential.UserName -replace("\","") $pass = $credential.Password $server.ConnectionContext.set_Login($userName) $server.ConnectionContext.set_SecurePassword($credential.Password) $DB = "Master" invoke-sqlcmd -query "select @@Servername" -database $DB -serverinstance $servername -username $username -password $pass If if just hardcode the password in at the end of the "invoke-sqlcmd" line, it works. Is this because you can't use "get-credential" with "invoke-sqlcmd"? If so...what are my alternatives? Thanks so much for you help Emo

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  • Create a view in database to fetch username and password of all users having a particular roie (Form

    - by naveen
    Hi Guys, Background ========== I am using ASP.NET Forms Authentication for my application. I have made my Password Format "Clear", so no problems with the password encryption. Requirement =========== I need to create a view(in SQL server) to display all Administrators in my System. ie aspnet_Roles.LoweredRoleName='administrator' The fields needed are UserName and Password Can you guys give point out the most optimal way to do so? Regards, Naveen Jose

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  • java script is not working

    - by Piyush
    i am comparing password and confirm password through java script.my code- function validate_form(thisform) { with (thisform) { if (validate_required(password,"<b>Error: </b>Password must be filled out!")==false) {password.focus();return false;} else if (validate_required(cnfpassword,"<b>Error: </b>Confirm Password must be filled out!")==false) {cnfpassword.focus();return false;} else if (document.getElementById('password').value != document.getElementById('cnfpassword').value) {password.focus();Sexy.error("<b>Error: </b>Passwords entered are not same!"); password.value="";cnfpassword.value="";return false;} } validate_required() function is working fine, it is showing alert msg but password compare is not working. But the same code is working fine in some other page.I have written some php code to avoid page caching- <?php session_start(); session_cache_limiter('nocache'); header('Pragma: no-cache'); ?> what's the problem???

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  • How to update the user profile through tokenid when a particular user logs in using his username and password

    - by Rani
    i have an application in which when the user enters his username and password in the login form , his username and password are submitted to the server database for validation and if he is a valid user a tokenid is generated for him through JSON response and he is allowed to log in.this is the JSON response that i get in the console when a valid user log in through the log in form : {"TokenID":"kaenn43otO","isError":false,"ErrorMessage":"","Result":[{"UserId":"164","FirstName":"Indu","LastName":"nair","Email":"[email protected]","ProfileImage":null,"ThumbnailImage":null,"DeviceInfoId":"22"}],"ErrorCode":900} 2011-06-24 11:56:57.639 Journey[5526:207] this is token id:kaenn43otO so when the same user wants to update his profile by clicking on the update tab using the tokenid So that if he want he can his firstname,lastname,password,email.etc.i i have done the following code to update the user profile using tokenid but it does not work.i get tokenid when the user log in and this tokenid i have to pass to other class: this is my code to update user profile: -(void)sendRequest { //this is the class in which i get the tokenid and i am passing it to this class apicontroller *apitest = [[apicontroller alloc]init]; NSString *tokentest = apitest.tokenapi; NSString *post = [NSString stringWithFormat:@"Token=%@&firstname=%@&lastname=%@&Username=%@&Password=%@&Email=%@",tokentest,txtfirstName.text,txtlast.text,txtUserName.text,txtPassword.text,txtEmail.text]; NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES]; NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]]; NSLog(@"%@",postLength); NSMutableURLRequest *request = [[[NSMutableURLRequest alloc] init] autorelease]; [request setURL:[NSURL URLWithString:@"http://192.168.0.1:96/JourneyMapperAPI?RequestType=Register&Command=SET"]]; [request setHTTPMethod:@"POST"]; [request setValue:postLength forHTTPHeaderField:@"Content-Length"]; [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"]; [request setHTTPBody:postData]; NSURLConnection *theConnection = [[NSURLConnection alloc] initWithRequest:request delegate:self]; if (theConnection) { webData = [[NSMutableData data] retain]; NSLog(@"%@",webData); [theConnection start]; } else { } } -(void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response { [webData setLength: 0]; } -(void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data { [webData appendData:data]; } -(void)connection:(NSURLConnection *)connection didFailWithError:(NSError *)error { [connection release]; [webData release]; } -(void)connectionDidFinishLoading:(NSURLConnection *)connection { NSString *loginStatus = [[NSString alloc] initWithBytes: [webData mutableBytes] length:[webData length] encoding:NSUTF8StringEncoding]; NSLog(@"%@",loginStatus); [loginStatus release]; [connection release]; [webData release]; } -(IBAction)click:(id)sender { [self sendRequest]; } this is my apicontroller.m file in which i am creating login form so that user login and in this page tokenid is generated -(void)sendRequest { UIDevice *device = [UIDevice currentDevice]; NSString *udid = [device uniqueIdentifier]; //NSString *sysname = [device systemName]; NSString *sysver = [device systemVersion]; NSString *model = [device model]; NSLog(@"idis:%@",[device uniqueIdentifier]); NSLog(@"system nameis :%@",[device systemName]); NSLog(@"System version is:%@",[device systemVersion]); NSLog(@"System model is:%@",[device model]); NSLog(@"device orientation is:%d",[device orientation]); NSString *post = [NSString stringWithFormat:@"Loginkey=%@&Password=%@&DeviceCode=%@&Firmware=%@&IMEI=%@",txtUserName.text,txtPassword.text,model,sysver,udid]; NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES]; NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]]; NSLog(@"%@",postLength); NSMutableURLRequest *request = [[[NSMutableURLRequest alloc] init] autorelease]; [request setURL:[NSURL URLWithString:@"http://192.168.0.1:96/JourneyMapperAPI?RequestType=Login"]]; [request setHTTPMethod:@"POST"]; [request setValue:postLength forHTTPHeaderField:@"Content-Length"]; [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"]; [request setHTTPBody:postData]; NSURLConnection *theConnection = [[NSURLConnection alloc] initWithRequest:request delegate:self]; if (theConnection) { webData = [[NSMutableData data] retain]; NSLog(@"%@",webData); } else { } } //to select username and password from database. -(void)check { //app.journeyList = [[NSMutableArray alloc]init]; [self createEditableCopyOfDatabaseIfNeeded]; NSString *filePath = [self getWritableDBPath]; sqlite3 *database; if(sqlite3_open([filePath UTF8String], &database) == SQLITE_OK) { const char *sqlStatement = "SELECT Username,Password FROM UserInformation where Username=? and Password=?"; sqlite3_stmt *compiledStatement; if(sqlite3_prepare_v2(database, sqlStatement, -1, &compiledStatement, NULL) == SQLITE_OK) { sqlite3_bind_text(compiledStatement, 1, [txtUserName.text UTF8String], -1, SQLITE_TRANSIENT); sqlite3_bind_text(compiledStatement, 2, [txtPassword.text UTF8String], -1, SQLITE_TRANSIENT); //NSString *loginname= [NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement, 1)]; // NSString *loginPassword = [NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement, 2)]; } if(sqlite3_step(compiledStatement) != SQLITE_ROW ) { NSLog( @"Save Error: %s", sqlite3_errmsg(database) ); UIAlertView *alert = [[UIAlertView alloc]initWithTitle:@"UIAlertView" message:@"User is not valid" delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil]; [alert show]; [alert release]; alert = nil; } else { isUserValid = YES; if (isUserValid) { UIAlertView *alert = [[UIAlertView alloc]initWithTitle:@"UIAlertView" message:@"Valid User" delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil]; [alert show]; [alert release]; } } sqlite3_finalize(compiledStatement); } sqlite3_close(database); } -(void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response { [webData setLength: 0]; } -(void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data { [webData appendData:data]; } -(void)connection:(NSURLConnection *)connection didFailWithError:(NSError *)error { [connection release]; [webData release]; } -(void)connectionDidFinishLoading:(NSURLConnection *)connection { NSString *loginStatus = [[NSString alloc] initWithBytes: [webData mutableBytes] length:[webData length] encoding:NSUTF8StringEncoding]; NSLog(@"%@",loginStatus); //this is to perfrom insert opertion on the userinformation table NSString *json_string = [[NSString alloc] initWithData:webData encoding:NSUTF8StringEncoding]; NSDictionary *result = [json_string JSONValue]; //here i am storing the tokenid tokenapi = [result objectForKey:@"TokenID"]; NSLog(@"this is token id:%@",tokenapi); // BOOL errortest = [[result objectForKey:@"isError"] boolValue]; if(errortest == FALSE) { values = [result objectForKey:@"Result"]; NSLog(@"Valid User"); } else { NSLog(@"Invalid User"); } NSMutableArray *results = [[NSMutableArray alloc] init]; for (int index = 0; index<[values count]; index++) { NSMutableDictionary * value = [values objectAtIndex:index]; Result * result = [[Result alloc] init]; //through this i get the userid result.UserID = [value objectForKey:@"UserId"]; result.FirstName = [value objectForKey:@"FirstName"]; result.Username =[value objectForKey:@"Username"]; result.Email =[value objectForKey:@"Email"]; result.ProfileImage =[value objectForKey:@"ProfileImage"]; result.ThumbnailImage =[value objectForKey:@"ThumbnailImage"]; result.DeviceInfoId =[value objectForKey:@"DeviceInfoId"]; NSLog(@"%@",result.UserID); [results addObject:result]; [result release]; } for (int index = 0; index<[results count]; index++) { Result * result = [results objectAtIndex:index]; //save the object variables to database here [self createEditableCopyOfDatabaseIfNeeded]; NSString *filePath = [self getWritableDBPath]; sqlite3 *database; if(sqlite3_open([filePath UTF8String], &database) == SQLITE_OK) { const char *sqlStatement = "insert into UserInformation(UserID,DeviceId,Username,Password,FirstName,Email) VALUES (?,?,?,?,?,?)"; sqlite3_stmt *compiledStatement; if(sqlite3_prepare_v2(database, sqlStatement, -1, &compiledStatement, NULL) == SQLITE_OK) { //sqlite3_bind_text( compiledStatement, 1, [journeyid UTF8String],-1,SQLITE_TRANSIENT); sqlite3_bind_text( compiledStatement, 1, [result.UserID UTF8String],-1,SQLITE_TRANSIENT); sqlite3_bind_text(compiledStatement, 2, [result.DeviceInfoId UTF8String],-1,SQLITE_TRANSIENT); sqlite3_bind_text(compiledStatement, 3, [txtUserName.text UTF8String],-1,SQLITE_TRANSIENT); sqlite3_bind_text(compiledStatement, 4, [txtPassword.text UTF8String],-1,SQLITE_TRANSIENT); sqlite3_bind_text (compiledStatement, 5, [result.FirstName UTF8String],-1,SQLITE_TRANSIENT); sqlite3_bind_text (compiledStatement, 6, [result.Email UTF8String],-1,SQLITE_TRANSIENT); } if(sqlite3_step(compiledStatement) != SQLITE_DONE ) { NSLog( @"Save Error: %s", sqlite3_errmsg(database) ); } else { UIAlertView *alert = [[UIAlertView alloc]initWithTitle:@"UIAlertView" message:@"Record added" delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil]; [alert show]; [alert release]; alert = nil; } sqlite3_finalize(compiledStatement); } sqlite3_close(database); } [loginStatus release]; [connection release]; [webData release]; } -(IBAction)click:(id)sender { [self sendRequest]; //this is to select username and password from database. [self check]; } for a particular user who logs in only his profile must be update by using tokenid and userid.Please help me in solving this problem.Thanks

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  • Custom login in Django

    - by alpgs
    Django newbie here. I wrote simplified login form which takes email and password. It works great if both email and password are supplied, but if either is missing i get KeyError exception. According to django documentation this should never happen: By default, each Field class assumes the value is required, so if you pass an empty value -- either None or the empty string ("") -- then clean() will raise a ValidationError exception I tried to write my own validators for fields (clean_email and clean_password), but it doesn't work (ie I get KeyError exception). What am I doing wrong? class LoginForm(forms.Form): email = forms.EmailField(label=_(u'Your email')) password = forms.CharField(widget=forms.PasswordInput, label=_(u'Password')) def clean_email(self): data = self.cleaned_data['email'] if not data: raise forms.ValidationError(_("Please enter email")) return data def clean_password(self): data = self.cleaned_data['password'] if not data: raise forms.ValidationError(_("Please enter your password")) return data def clean(self): try: username = User.objects.get(email__iexact=self.cleaned_data['email']).username except User.DoesNotExist: raise forms.ValidationError(_("No such email registered")) password = self.cleaned_data['password'] self.user = auth.authenticate(username=username, password=password) if self.user is None or not self.user.is_active: raise forms.ValidationError(_("Email or password is incorrect")) return self.cleaned_data

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  • Why does tomcat-admin install require adding admin and manager to tomcat-users.xml manually?

    - by J G
    I installed tomcat6 on lucid using apt-get. All working. I installed tomcat-admin. Not working. I amended the /etc/tomcat6/tomcat-users.xml file to uncomment the users and roles (from the default) to be like the following: <role rolename="tomcat"/> <role rolename="role1"/> <user username="tomcat" password="password" roles="tomcat"/> <user username="both" password="password" roles="tomcat,role1"/> <user username="role1" password="password" roles="role1"/> This still didn't work. Then from the following page I added. <role rolename="manager"/> <user username="admin" password="secret" roles="manager"/> then it worked. Why doesn't this occur as part of the install? (Why isn't this in the Ubuntu Manual on Tomcat ?)

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  • Why acegi (Spring Security) converts password to uppercase before comparing ?

    - by Tony
    One of my colleague in QA team reported a bug to me, the bug said that can't change password to lowercase, otherwise login is rejected,using number or uppercase is all fine. The login system was implemented using acegi 1.0 (now called Spring Security). This was a very strange bug,changing password is done by encrypting the user input string into MD5 string, I implemented this without using anything related acegi, I don't if the is the origin cause of the problem. When the login is rejected, through debugging, I find that, the user input is converted into uppercase by acegi when passing to the acegi comparing logic. At first, I didn't believe this, when I checkout the acegi source and debugging with it, I find it does convert both username and password to uppercase (source code line 121), Can you tell me why it does this? This can cause password encoding mismatch!

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  • Is is possible to determine a password input string as plaintext or hashed?

    - by Godders
    I have a RESTful API containing a URI of /UserService/Register. /UserService/Register takes an XML request such as: <UserRegistrationRequest> <Password>password</Password> <Profile> <User> <UserName>username</UserName> </User> </Profile> </UserRegistrationRequest> I have the following questions given the above scenario: Is there a way (using C# and .Net 3.5+) of enforcing/validating that clients calling Register are passing a hashed password rather than plaintext? Is leaving the choice of hashing algorithm to be used to the client a good idea? We could provide a second URI of /UserService/ComputePasswordHash which the client would call before calling /UserService/Register. This has the benefit of ensuring that each password is hashed using the same algorithm. Is there a mechanism within REST to ensure that a client has called one URI before calling another? Hope I've explained myself ok. Many thanks in advance for any help.

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  • Using an empty keystore password used to be possible?

    - by TomTasche
    When signing an apk after a long break from Android development I was surprised that I'm no longer able to enter an empty keystore password to unlock it. Is it just me or has this been possible before? If so, when did that change and how can I manage to unlock the keystore anyway? Some background: maybe I'm just crazy and didn't use an empty password for the keystore before, but the one and only possible password that I could have been using instead doesn't work either (I swear, there's no chance I'd have used another password!).

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  • How does Lastpass recognize actual login?

    - by Pan.student
    We are currently working on simple school project using Codeigniter where we need login page. It would be very useful if Lastpass could recognise and save logins. We have several accounts with different roles and manual insert of login is pretty slow. So I was wondering what needs to be done and where in files (view, controller?) for Lastpass to work as it does on every website. For example this is our login form: <?php echo form_open('login'); ?> <input type="text" id="username" name="username"/> <input type="text" id="password" name="password"/> <input type="submit" value="Login"/> </form> Thanks for help. (could not create new tag "Lastpass" due to low reputation) [SOLVED] changed <input type="text" id="password" name="password"/> to <input type="password" id="password" name="password"/>

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  • MCrypt Module, Rijndael-256

    - by WernerCD
    An outside company is redoing our company Intranet. During some basic usage I disovered that the "User Edit" screens, with the "Password: *" boxes have the password in plain text, with the text box "type=password" to "hide" the password. The passwords are not store in the database as plain text, they are stored encrypted using "rijndael-256" cypher using the mcrypt module. I know that if I encrypt a password with SHA*, the password is "Unrecoverable" via one-way encryption. Is the same of MCrypt Rijndael-256 encryption? Shouldn't an encrypted password be un-recoverable? Are they blowing smoke up my rear or just using the wrong technology?

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  • How to recover Wordpress on GoDaddy hosting after reseting database password? [migrated]

    - by Tom Brito
    I did reset my database password, so I could enter the phpMyAdmin, but now my Wordpress installation can't connect to the database. I tried to access the "wp-config.php" (should be at http://mysite.com/wp-config.php right?) but, again, I get the "can't connect to database" message. Also, now when I try to access the file manager on the GoDaddy hosting, I get "The page isn't redirecting properly". I did e-mail the GoDaddy support, and I'm researching while they do not answer. Not sure if it's a GoDaddy or Wordpress issue. Is there any way to fix Wordpress, or I'll need to re-install it?

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  • How to pass username and password for authentication in URL?

    - by Maggie
    Hi there. I need to pass the user name and password in the URL for a REST web services call. I know that if I pass it this way in Firefox, it works: https://{UserName}:{Password}@api.opsourcecloud.net/oec/0.9/myaccount Is there a proper way to pass user name and password aside from the above example? It's a Spring Security Context?

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  • Understanding Nested If.. Else statements

    - by user1174762
    For some reason my PHP login script keeps returning "invalid email/password combination", yet i know I am entering the correct email and password. Does anyone see what I might be doing wrong? <?php $email= $_POST['email']; $password= $_POST['password']; if (!empty($email) && !empty($password)) { $connect= mysqli_connect("localhost", "root", "", "si") or die('error connecting with the database'); $query= "SELECT user_id, email, password FROM users WHERE email='$email' AND password='$password'"; $result= mysqli_query($connect, $query) or die('error with query'); if (mysqli_num_rows($result) == 1) { $row= mysqli_fetch_array($result); setcookie('user_id', $row['user_id']); echo "you are now logged in"; } else { echo "invalid username/password combination"; } } else { echo" you must fill out both username and password"; } ?>

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  • How can we store password other than plain text?

    - by Eric
    I've found numerous posts on stackoverflow on how to store user passwords. However, I need to know what is the best way to store a password that my application needs to communicate with another application via the web? Currently, our web app needs to transmit data to a remote website. To upload the data, our web app reads the password from a text file and creates the header with payloads and submits via https. This password in plain text on the file system is the issue. Is there any way to store the password more securely? Thanks!

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  • Best way to store a database password in a startup script / config file?

    - by Mark Harrison
    So our web server apps need to connect to the database, and some other apps have startup scripts that execute at boot time. What's the best way to store the name/password for these applications, in terms of security, e.g. perhaps we don't want sysadmins to know the database password maintainability, e.g. making the configuration easy to change when the password changes, etc. both windows and linux solutions appreciated!

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  • Mysql configuration errror : using password (NO) instead of YES.

    - by Tristan
    Hello, I try to connect mysql via PHPMYADMIN, using my password, but it can't stop telling me that (access denied, using password NO) but i'm using a password :O When i connect via the console with my password, it works but not on phpmyadmin. It's really weird. Do you have an idea to fix that ? edit: it worked couple of days ago, because i created 2 databases and 2 users via phpmyadmin... Thanks edit : When i'm using CHROME it's working unless FireFox ... any ideas ?

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  • Why can't I log into Lubuntu after the 13.04 update, even if I know the password?

    - by gudrun
    After the 13.04 update the login screen started to appear, even though I chose to automatically login in the Lubuntu install options one week ago. Even if my password and username is correct it won't login, it will just come back to the login screen. When I press ALT-CTRL-F1 at the login screen I am able to login perfectly, but I have no GUI and I'm kind of lost on that field. WHat is going?Is it just a bug? Can I downgrade?I tried several forums with different solutions but none of them worked.

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  • How can I authenticate Ubuntu Software Center with user password?

    - by user71852
    I would like to be able to use the password associated with this account to install packages with the GUI. Ideally, I would change the settings so that any user with sudo permissions could install packages. If that is not possible, I would like to be able to list all users that should be able to install. I know that this involves making changes to Policy Kit, and I have read a page with a similar question. However, I must need information specific to my own problem, because all my attempts so far have failed.

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  • Symfony 2 form repeated validation in Entity with annotation

    - by Sukhrob
    My question is "How can I do form repeated validation in Entity with annotation?". I have an Account entity with (email, password and confirmPassword) attributes. When a new user registers a new account, he/she has to fill in email, password and confirmPassword fields. Obviously, password and confirmPassword fields must match. I saw an example of this validation with pure php (form builder) in Stachoverflow like below. $builder->add('password', 'repeated', array( 'type' => 'password', 'first_name' => 'Password', 'second_name' => 'Password confirmation', 'invalid_message' => 'Passwords are not the same', )); But, this is not what I want. I want this functionality with annotation in my Account entity. Maybe * @Assert\Match( * matchField = "password", * message = "The password confirmation does not match password." * ) protected $confirmPassword;

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