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  • How to add CSS classes to Zend_Form_Element_Select option

    - by Jah Selassie
    Hi, I'm trying to add a CSS class to a Zend_Form_Element_Select option, but I just can't find a way to do it. The desired output would be something like this: <select name="hey" id="hey"> <option value="value1" style="parent">label1</option> <option value="value2" style="sibling">sublabel1</option> <option value="value3" style="sibling">sublabel2</option> <option value="value4" style="parent">label2</option> <option value="value5" style="sibling">sublabel3</option> <option value="value6" style="sibling">sublabel4</option> </select> But I'm getting this: <select name="hey" id="hey"> <option value="value1">label1</option> <option value="value2">sublabel1</option> <option value="value3">sublabel2</option> <option value="value4">label2</option> <option value="value5">sublabel3</option> <option value="value6">sublabel4</option> </select> I can't seem to pass a CSS class attribute to any of the options in the select element although I can style the select element itselft. My code: $sel = new Zend_Form_Element_Select('hey'); $sel->setRequired(true)->setLabel('Select an Option:'); $sel->addMultiOption('value1', 'label1', array('class' => 'parent')) ->addMultiOption('value2', 'sublabel1', array('class' => 'sibling')) (etc...); After researching a bit I found out that Element_Select doesn't have a method for adding CSS styles to the options in the select box, only for the select itself. So, how can I add them? Should I extend the form_element_select? Or would a custom decorator suffice? Can anyone give me a hint? I'm baffled with this. Thanks in advance!

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  • multiple polls with email submit function

    - by Chris Mousdale
    I want to add a 4 sets of polls that each have around 4 radio buttons each for answers - then i would like to add an 'enter your email address' field below these polls. Finally I would like the submit button after the email field to 'submit' the data from the polls and the email address entered - so only one submit button. Just to make things even better, I would like some form of validation, that will not pass the form unless all 4 polls have a radio button pressed and a valid email. All this is then to go into a MySQL database. I have the email validation bit nailed - so thats fine.. it's the multiple polls bit thats getting me - I cannot get it to work?! Do i have to effectively add 5 forms? Any help would be greatly appreciated.

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  • how to obtain a stack trace when WAMP server crashes ?

    - by mithunmo
    Hello, Some times my WAMP server crashes . I get the following error. HTTP has encountered exception and needs to close. Unreferenced Memory. szAppName : httpd.exe szAppVer : 2.2.11.0 szModName : php5ts.dll szModVer : 5.3.0.0 offset : 0000c309 C:\DOCUME~1\blrcom\LOCALS~1\Temp\WERc677.dir00\httpd.exe.mdmp C:\DOCUME~1\blrcom\LOCALS~1\Temp\WERc677.dir00\appcompat.txt My question is how to obtain stack trace to debug this problem ? Should I use a windows debugger windows debugger or is there some setting in WAMP server configuration should i enable ?

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  • Facebook Connect and Hash Password Encryption

    - by JamesStrocel
    I'm trying to integrate a Zen Cart site with Facebook Connect. So far, I've been able to get Zen Cart to recognize that the user has a facebook account and is logged in, but that's it. True authentication into Zen Cart eludes me because I can't figure out where a password could be stored and how to get it to Zen Cart to be compared with the password hash. I know Facebook Connect has been implemented with webapps that have such passwords like wordpress, so I know there must be a way to do it. Is the password stored in a cookie? In the Facebook application itself? Any help would be appreciated, even if it's just a place to start searching.

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  • Why does my data not pass into my view correctly?

    - by dmanexe
    I have a model, view and controller not interacting correctly, and I do not know where the error lies. First, the controller. According to the Code Igniter documentation, I'm passing variables correctly here. function view() { $html_head = array( 'title' => 'Estimate Management' ); $estimates = $this->Estimatemodel->get_estimates(); $this->load->view('html_head', $html_head); $this->load->view('estimates/view', $estimates); $this->load->view('html_foot'); } The model (short and sweet): function get_estimates() { $query = $this->db->get('estimates')->result(); return $query; } And finally the view, just to print the data for initial development purposes: <? print_r($estimates); ?> Now it's undefined when I navigate to this page. However, I know that $query is defined, because it works when I run the model code directly in the view.

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  • Using custom request and custom redirect with Contact Form 7

    - by Scott B
    I have several sites that I want to link back to the main site which hosts the contact form (using contact form 7). I would like to capture the request parameter "site-url" on incoming links to the contact form. Then when the user submits the form, I would like to redirect them back to the site specified in the site-url. Any ideas if this is possible with contact form 7? I would also like to add a special field in the contact form which would insert the site-url into the email that i get so that I know which site they were referred from.

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  • Efficient way to handle multiple HTMLPurifier configs.

    - by anomareh
    I'm using HTMLPurifier in a current project and I'm not sure about the most efficient way to go about handling multiple configs. For the most part the only major thing changing is the allowed tags. Currently I have a private method, in each class using HTMLPurifier, that gets called when a config is needed and it creates one from the default. I'm not really happy with this as if 2 classes are using the same config, that's duplicating code, and what if a class needs 2 configs? It just feels messy. The one upside to it, is it's lazy in the sense that it's not creating anything until it's needed. The various classes could be used and never have to purify anything. So I don't want to be creating a bunch of config objects that might not even be used. I just recently found out that you can create a new instance of HTMLPurifier and directly set config options like so: $purifier = new HTMLPurifier(); $purifier->config->set('HTML.Allowed', ''); I'm not sure if that's bad form at all or not, and if it isn't I'm not really sure of a good way to put it to use. My latest idea was to create a config handler class that would just return an HTMLPurifier config for use in subsequent purify calls. At some point it could probably be expanded to allow the setting of configs, but just from the start I figured they'd just be hardcoded and run a method parameter through a switch to grab the requested config. Perhaps I could just send the stored purifier instance as an argument and have the method directly set the config on it like shown above? This to me seems the best of the few ways I thought of, though I'm not sure if such a task warrants me creating a class to handle it, and if so, if I'm handling it in the best way. I'm not too familiar with the inner workings of HTMLPurifier so I'm not sure if there are any better mechanisms in place for handling multiple configs. Thanks for any insight anyone can offer.

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  • Duplicate entries on mysql on insert using doctrine

    - by Nikos Galis
    Hi all! I am facing a very weird problem with mysql and doctrine [with help of codeIgniter]. I am trying to make a simple migration script taking all records from one table and after a little process, saving them to another. However, on my laptop [running windows and wamp] I get double numbers of the original table records to have been copied to the destination table. In my colleagues' laptops, everything works fine! We are all using mysql 5.0.86 [plus windows plus wamp]. Here is the code : function buggy_function(){ $this->db(); //get db connection $q = Doctrine_Query::create()->from('Oldtable r'); $oldrecords = $q->fetchArray(); $count = 0; foreach ($oldrecords as $oldrecord){ $newrecord = new NewTableClass(); $newrecord->password = md5($oldrecord['password']); $newrecord->save(); echo $newrecord->id. ' Id -> saved.' } } Simple as that! I have 39 records on the Old table and I am getting 78 records in the new table, which are exactly the same records, except from the unique primary key. It seems as if the script runs twice. But the output of the script is the following : 1 Id -> saved. 2 Id -> saved. ... ... 39 Id -> saved. Do you have any idea why this is happening? Any known bug for mysql? Thank you in advanced!'

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  • Prepared statement help, Number of variables doesn't match number of parameters in prepared statement

    - by Sam Gabriel
    I'm getting this error : Number of variables doesn't match number of parameters in prepared statement every time I run this code: $dbh = new mysqli("localhost", "***", "***", "pics"); $stmt = $dbh->prepare("INSERT INTO comments (username, picture, comment) VALUES (?, ?, ?)"); $stmt->bind_Param('s', $username); $stmt->bind_Param('d', $picture); $stmt->bind_Param('s', $comment); $username=$_SESSION['username']; $picture=$_GET['id']; $comment=$_POST['comment']; $stmt->execute(); What's the problem?

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  • MVC: models interacts with the view?

    - by fayer
    i know that everything is going through the controller. but i often read articles that says something like this: user interacts with the view controller asks the model to change its state model notifies the view when its sate has changed i dont get the 3rd one. why saying that the model notifies the view, when it actually is notifying the controller and the controller is notifying the view?

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  • How to dump memcache contents to console in a telnet session

    - by morpheous
    I am having problems with memcached, and I need to find what is actually stored in the cache. I have telnet'ed into the daemon and am listening on the port, and can send the daemon commands via the CLI. I want to know if anyone is aware of a command I can use to dump the contents of the cache to the console. I know of commands like 'flush_all' and 'stats' but those are not quite sufficient for what I want to do.

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  • Should you do validation checks that go outside the possiblility of normal user activity?

    - by Scarface
    Hey guys I have been thinking about form security a lot lately. I have been told time and time again to check if form input is a number if you are expecting a number or escape it in case (unless you use proper mysqli formatting) to avoid injection. 1.After the safety checks are done, should I do additional logic checks? For example, if the user is sending a friend request to them-self for example even if my user interface will not show the form if the user is looking at their own page.

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  • Sql query problem

    - by LiveEn
    I have the below sql query that will update the the values from a form to the database $sql="update leads set category='$Category',type='$stype',contactName='$ContactName',email='$Email',phone='$Phone',altphone='$PhoneAlt',mobile='$Mobile',fax='$Fax',address='$Address',city='$City',country='$Country',DateEdited='$today',printed='$Printed',remarks='$Remarks' where id='$id'"; $result=mysql_query($sql) or die(mysql_error()); echo '<h1>Successfully Updated!!.</h1>'; when i submit I dont get any errors and the success message is displayed but the database isnt updated . When i echo the $sql, all the values are set properly. and when i ech the $result i get the value 1. can someone please tell me what am i doing wrong here??

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  • problems with infinite loop

    - by Tom
    function addAds($n) { for ($i=0;$i<=$n;$i++) { while($row=mysql_fetch_array(mysql_query("SELECT * FROM users"))) { $aut[]=$row['name']; } $author=$aut[rand(0,mysql_num_rows(mysql_query("SELECT * FROM users")))]; $name="pavadinimas".rand(0,3600); $rnd=rand(0,1); if($rnd==0) { $type="siulo"; } else { $type="iesko"; } $text="tekstas".md5("tekstas".rand(0,8000)); $time=time()-rand(3600,86400); $catid=rand(1,9); switch ($catid) { case 1: $subid=rand(1,8); break; case 2: $subid=rand(9,16); break; case 3: $subid=rand(17,24); break; case 4: $subid=rand(25,32); break; case 5: $subid=rand(33,41); break; case 6: $subid=rand(42,49); break; case 7: $subid=rand(50,56); break; case 8: $subid=rand(57,64); break; case 9: $subid=rand(65,70); break; } mysql_query("INSERT INTO advert(author,name,type,text,time,catid,subid) VALUES('$author','$name','$type','$text','$time','$catid','$subid')") or die(mysql_error()); } echo "$n adverts successfully added."; } The problem with this function, is that it never loads. As I noticed, my while loop causes it. If i comment it, everything is ok. It has to get random user from my db and set it to variable $author.

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  • How to generate Thumbnails with phpThumb and save it into a file?

    - by CuSS
    Hi all, i wan't to know how to generate thumbnails with phpThumb Class, with an array with file paths already. And then Save the result of each image on other path but with the same name. Thank you all ;) EDIT: I have my code something like this: echo "A iniciar gerador de miniaturas para a área de cliente: \n"; include $wincli['files']['phpThumbClass']; $files = file_list($wincli['dirs']['logos']); $phpThumb = new phpThumb(); foreach( $files as $file ) { echo " # A converter o ficheiro '".basename($file)."' : "; if(is_file($file)){ $phpThumb->setSourceFilename($file); $phpThumb->setParameter('w', 880); $phpThumb->setParameter('h', 241); $phpThumb->setParameter('q', 90); $phpThumb->setParameter('zc', 1); $outputFilename = $wincli['dirs']['logosthumbs'].$file; if($phpThumb->GenerateThumbnail()){ if($phpThumb->RenderToFile($outputFilename)){ echo "OK \n"; }else{ echo "Falhou (Ao guardar no ficheiro)\n"; } }else{ echo "Falhou (Ao gerar miniatura)\n"; } }else{ echo "Falhou (Ficheiro inexistente)\n"; } }

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  • Is it dangerous to keep an admin page to administer your database?

    - by Scarface
    Hey guys I have an admin page that checks if you are admin before submitting any queries, and contains a header to the index page if you are not admin, but I am worried about protecting the page. I am concerned someone may be able to destroy my database with it. Does anyone have any recommendation into protecting a page like this, if not, should I just manually admin my database through phpmyadmin and delete the page all together?

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  • Storing class constants (for use as bitmask) in a database?

    - by fireeyedboy
    Let's say I have a class called Medium which can represent different types of media. For instance: uploaded video embedded video uploaded image embedded image I represent these types with contants, like this: class MediumAbstract { const UPLOAD = 0x0001; const EMBED = 0x0010; const VIDEO = 0x0100; const IMAGE = 0x1000; const VIDEO_UPLOAD = 0x0101; // for convenience const VIDEO_EMBED = 0x0110; // for convenience const IMAGE_UPLOAD = 0x1001; // for convenience const IMAGE_EMBED = 0x1010; // for convenience const ALL = 0x1111; // for convenience } Thus, it is easy for me to do a combined search on them on an (abstract) repository, with something like: { public function findAllByType( $type ) { ... } } $media = $repo->findAllByType( MediumAbstract::VIDEO | MediumAbstract::IMAGE_UPLOAD ); // or $media = $repo->findAllByType( MediumAbstract::ALL ); // etc.. How do you feel about using these constant values in a concrete repository like a database? Is it ok? Or should I substitute them with meaningful data in the database. Table medium: | id | type | location | etc.. ------------------------------------------------- | 1 | use constants here? | /some/path | etc.. (Of course I'll only be using the meaningful constants: VIDEO_UPLOAD, VIDEO_EMBED, IMAGE_UPLOAD and IMAGE_EMBED)

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  • pagination with css

    - by bsandrabr
    Hi I've tried every combination I can think of but I can't get this to work. Can you help? I'm trying to put some css onto my pagination and have read all the examples but they all contain so many backslashes and concatenation that I just dont know how to apply it Here is my pagination code (which works fine) along with my feeble attempt at styling it if ($st > 0) { $st3=$st; print "< Previous Page "; } $f=$st+3; for($i2=$st+1;$i2<=$f;$i2++) { $i3=$i2-3; if ($i3 0) { print "$i3 "; if($i2 % 3 == 0) { print ""; } } } $g=$st+3; for($i=$st+1;$i<=$g;$i++) { print "$i "; if($i % 3 == 0) { print ""; } } $st2=$st+2; print " Next Page "; Here is the css that I took from the website /* CSS Document */ body { background: #2D2D2D; font-family:Verdana, fantasy; font-size:13px; color: white; scrollbar-base-color: black; scrollbar-arrow-color: red; scrollbar-DarkShadow-Color: black; } a:visited,a:active,a:link { color: white;text-decoration: none; } a:hover { color: red;text-decoration: overline underline;background: none; } table,tr,td { font-family:Palatino Linotype; color: #FFFFFF;font-size: 12px; } .button { font-family:Verdana, fantasy; font-size:13; color:#FFFFFF; background-color: red; } input,textarea,dropdown{ font-family:Verdana, fantasy; font-size:13; color: #FFFFFF; background-color: #000000; border: 1px solid; } textarea,.submit input{ font-family:Verdana, fantasy; font-size:13; color:#ffffff; background-color: black; } .table { background-color:#000000; } .table3 { background-color:#000000; } .table td { color: #000000; background-color:#DEDEDE; height:22px; } .table3 td { background-color:#CCCCCC; } td .alt { background-color:#EEEEEE; height:22px; } td .h { background-image:url(tablehgrad.png); background-repeat:repeat-x; font-weight: bold; background-color: #D6D6D6; } .table th { background-image:url(tablehgrad.png); background-repeat:repeat-x; color: #000000; font-weight: bold; background-color: #D6D6D6; } .menu th { font-font-size: 12px; color: silver; background-image:url(th.png); background-repeat:repeat-x; font-weight: bold; background-color: #4B4B4B; } .stats td { font-font-size: 12px; color: white; font-weight: bold; } .menu td { font-size: 12px; text-align: center; color: white; background-image:url(tdover.png); background-repeat:repeat-x; font-weight: bold; background-color: #4B4B4B; } .menu td:hover{ color: white; background-image:url(td.png); div.pagination { padding: 3px; margin: 3px; } div.pagination a { padding: 2px 5px 2px 5px; margin: 2px; border: 1px solid #AAAADD; text-decoration: none; /* no underline */ color: #000099; } div.pagination a:hover, div.pagination a:active { border: 1px solid #000099; color: #000; } div.pagination span.current { padding: 2px 5px 2px 5px; margin: 2px; border: 1px solid #000099; font-weight: bold; background-color: #000099; color: #FFF; } div.pagination span.disabled { padding: 2px 5px 2px 5px; margin: 2px; border: 1px solid #EEE; color: #DDD; } thanks

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  • urlQuey and Security

    - by jasmine
    In url query with id I use is_numeric($_GET['id']) for security issues. But in query with for example category name, is urlencode() a right way for security? Thanks in advance.

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  • WordPress deactivate a plugin via database?

    - by Scott B
    I have a wordpress script, wp-supercache, that I need to disable (as its cached on a nasty error), however, the error is causing the wp-admin redirect to fail, which means I can't get into the site to disable the plugin. Any advice? I can access the database via cpanel.

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  • jQuery eval of ajax inline script not throwing errors

    - by Josh
    http://stackoverflow.com/questions/606794/debugging-ajax-code-with-firebug This question is quite similar, though old and without real answers. I'm currently putting together an app that has scripts that get loaded in with an ajax request. An example: var main = _main.get(); main.load( someurl ); Where someurl is a page that contains an inline script element: <script type="text/javascript"> $(document).ready( function(){ var activities = new activities(); activities.init(); }); </script> jQuery will do a line by line eval of js that lives in inline script tags. The problem is, I get no errors or any information whatsoever in firebug when something goes awry. Does anyone have a good solution for this? Or a better practice for loading pages which contain javascript functionality? Edit: A little progress... so at the top of the page that is being loaded in via ajax, I have another script that was being included like this: <script type="text/javascript" src="javascript/pages/activities.js"></script> When I moved the inline $(document).ready() code in the page to the end of this included file, instead, syntax errors were now properly getting thrown. As an aside, I threw a console.log() into the inline script tag, and it was being logged just fine. I also tried removing the $(document).ready() altogether, and also switching it out for a $(window).load() event. No difference. May have something to do with the inline scripts dependency on the included activities.js, I guess. :: shakes head :: javascript can be a nightmare.

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