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• MySQL - complete server migration (Ubuntu) [closed]

  - by Mr A

  Possible Duplicate: How to copy and move mysql database Dump all databases with SSH access I'm setting up a new dev machine, and I have the old one sitting right next to me. I'd like to do an exact copy of all MySQL structures and data from the old machine to the new. Nothing fancy needs to happen (it's a dev machine). No replication. I don't care about "downtimes" etc. Is there a super simple way to do this? For example, I have SSH on the old server, can I just use Nautilus, do a connect to server, and then transfer a folder over, replacing another folder with it and be done? It's the same version of MySQL on both sides. Same version of Ubuntu. Same in most respects.

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• Why doesn't phpMyAdmin connect to MySQL server?

  - by Grafica

  I'm running xampp on Windows 7, and when I type localhost/phpmyadmin, there is an error: phpMyAdmin tried to connect to the MySQL server, and the server rejected the connection. You should check the host, username and password in your configuration and make sure that they correspond to the information given by the administrator of the MySQL server. Here's what I did, but I'm still not able to connect: In config.inc.php, changed from true to false: $cfg['Servers'[$i]['AllowNoPassword'] = false; Changed password here: localhost/security/xamppsecurity.php In resetroot.bat, typed new password where it says 'password': echo REPLACE INTO user VALUES ('localhost', 'pma', 'password', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', '', '', '', '', 0, 0, 0, 0, '', ''); >>resetroot.sql Restarted apache and mySQL I still get the same error message. Thanks in advance!

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• Binding MySQL to run from the public or private LAN IP address - which one is faster

  - by Lamin Barrow

  So we have 2 servers all running at the same web host. We have bind MySQL to listen on the public ip-address of the database server and the web server connects to it from the public ip. Both servers run on the same private network. Currently, the DB connect method from our php script takes about 3ms to connect to the MySQL database server host. My question is, would MySql data interaction from the web server be faster if we bind it to listen on the private lan address on the database server instead of the public IP? or is it the same regardless and it wont make a different.

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• mysql does not start properly

  - by Erik Svenson

  Hi I am using XAMPP on Windows XP. Since I changed the version from 1.73 to 1.77 MySQL does not start properly. That means that the status says, it is started, but the safety check says it is not . Because of that I cannot set any password, which is unacceptable. Any idea? That's mysql_error.log: 111007 9:42:56 [Note] Plugin 'FEDERATED' is disabled. 111007 9:42:56 InnoDB: The InnoDB memory heap is disabled 111007 9:42:56 InnoDB: Mutexes and rw_locks use Windows interlocked functions 111007 9:42:56 InnoDB: Compressed tables use zlib 1.2.3 111007 9:42:56 InnoDB: Initializing buffer pool, size = 16.0M 111007 9:42:56 InnoDB: Completed initialization of buffer pool 111007 9:42:57 InnoDB: highest supported file format is Barracuda. 111007 9:42:57 InnoDB: Waiting for the background threads to start 111007 9:42:58 InnoDB: 1.1.8 started; log sequence number 1595675 111007 9:42:58 [Note] Event Scheduler: Loaded 0 events 111007 9:42:58 [Note] mysql\bin\mysqld.exe: ready for connections. Version: '5.5.16' socket: '' port: 3306 MySQL Community Server (GPL)

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• MySQL keeps crashing due to bug

  - by mike

  So about a week ago, I finally figured out what was causing my server to continually crash. After reviewing my mysqld.log I keep seeing this same error, 101210 5:04:32 [Warning] option 'max_join_size': unsigned value 18446744073709551615 adjusted to 4294967295 Here is a link to the bug report, http://bugs.mysql.com/bug.php?id=35346 someone recommend that you set the max_join_size vaule in my.cnf to 4M, and I did. I assumed this fixed the issue, and it was working for about a week with no issues until today... I checked MySQL and the same error is now back, 101216 06:35:25 mysqld restarted 101216 6:38:15 [Warning] option 'max_join_size': unsigned value 18446744073709551615 adjusted to 4294967295 101216 6:38:15 [Warning] option 'max_join_size': unsigned value 18446744073709551615 adjusted to 4294967295 101216 06:40:42 mysqld ended Anyone know how I can really fix this issue? I can't keep having mysql crash like this. EDIT: I forgot to mention every time this happens I get an email from linode staying I have a high disk io rate Your Linode, has exceeded the notification threshold (1000) for disk io rate by averaging 2483.68 for the last 2 hours.

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• why installing mysql-server wants to remove sysvinit

  - by E-rich

  I want to install mysql-server-5.5 in a new Debian Squeeze installation, but when I start to install it I get a warning that I don't see as being a requirement: WARNING: The following essential packages will be removed. This should NOT be done unless you know exactly what you are doing! sysvinit It looks like the upstart package will be installed to replace sysvinit. Will proceeding with the install cause damage? Can you help me understand why sysvinit needs to be removed for mysql-server to be installed? Is there a way to install mysql-server without removing sysvinit?

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• [SOLVED]Can't enable mysql and mysqli extension in PHP [closed]

  - by Sydcul

  I used to had my website hosted at a hosting company. But i decided to start my own webserver and in order to get phpBB, MediaWiki, etc. working i need PHP and MySQL. So after a bit of screwing around i could get those working but the MySQL and MySQLi extensions do not seem to work. When i use phpMyAdmin, phpBB, whatever it would say it is not installed correctly. I uncommented it in php.ini, i put my PHP folder in path, still not working. Please note i am not a PHP developer at all. Using: Windows Server 2003 Small Buisiness (too lazy to install Linux) Apache2 (not sure what version) PHP 5.2 (threaded, manually installed) MySQL 5.5.28 Thanks in advance, -Sydcul EDIT: Solved. Don't know how, just used the installer and it worked.

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• Spring security and MySQL under CentOS

  - by user223268

  i'm trying to connect to MySQL using spring security, spring should access the database and check the user and pass using direct sql. the problem is when i use localhost to access my local database nothing happen no exceptions no any thing but login fails. if i changed the host of the server to one of my team machine IP address the program login successfully. the only deference is that i'm using CentOS 6.5 and my team is using Windows. how can i make sure i'm configuring MySQL correctly and what privileges should i grand to my users to be able to finish this. note: i'm a newcomer to linux and MySQL server administration.

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• Upgrading Apache, PHP and MySQL

  - by Javacadabra

  I'm looking to upgrade my current version of Apache, PHP and mySQL. I remember when I installed them it was a very intricate and somewhat delicate process and I am sort of afraid to upgrade in case everything just stops working! Currently I am running Apache 2.2.21 and PHP 5.3.5. MySQL is 5.6.4 Does anyone have any ideas how you upgrade these things? I think the current versions are Apache 2.4.3, PHP 5.4.7 and MySQL 5.6. Thanks in advance!

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• How to Create MySQL Query to Find Related Posts from Multiple Tables?

  - by Robert Samuel White

  This is a complicated situation (for me) that I'm hopeful someone on here can help me with. I've done plenty of searching for a solution and have not been able to locate one. This is essentially my situation... (I've trimmed it down because if someone can help me to create this query I can take it from there.) TABLE articles (article_id, article_title) TABLE articles_tags (row_id, article_id, tag_id) TABLE article_categories (row_id, article_id, category_id) All of the tables have article_id in common. I know what all of the tag_id and category_id rows are. What I want to do is return a list of all the articles that article_tags and article_categories MAY have in common, ordered by the number of common entries. For example: article1 - tags: tag1, tag2, tag3 - categories: cat1, cat2 article2 - tags: tag2 - categories: cat1, cat2 article3 - tags: tag1, tag3 - categories: cat1 So if my article had "tag1" and "cat1 and cat2" it should return the articles in this order: article1 (tag1, cat1 and cat2 in common) article3 (tag1, cat1 in common) article2 (cat1 in common) Any help would genuinely be appreciated! Thank you!

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• MySQL calling in Username to show instead of ID!

  - by Jess

  I have a users table, books table and authors table. An author can have many books, while a user can also have many books. (This is how my DB is currently setup). As I'm pretty new to So far my setup is like bookview.php?book_id=23 from accessing authors page, then seeing all books for the author. The single book's details are all displayed on this new page...I can get the output to display the user ID associated with the book, but not the user name, and this also applies for the author's name, I can the author ID to display, but not the name, so somewhere in the query below I am not calling in the correct values: SELECT users.user_id, authors.author_id, books.book_id, books.bookname, books.bookprice, books.bookplot FROM books INNER JOIN authors on books.book_id = authors.book_id INNER JOIN users ON books.book_id = users.user_id WHERE books.book_id=" . $book_id; Could someone help me correct this so I can display the author name and user name both associated with the book! Thanks for the help :)

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• MySQL access classes in PHP

  - by Mike

  I have a connection class for MySQL that looks like this: class MySQLConnect { private $connection; private static $instances = 0; function __construct() { if(MySQLConnect::$instances == 0) { //Connect to MySQL server $this->connection = mysql_connect(MySQLConfig::HOST, MySQLConfig::USER, MySQLConfig::PASS) or die("Error: Unable to connect to the MySQL Server."); MySQLConnect::$instances = 1; } else { $msg = "Close the existing instance of the MySQLConnector class."; die($msg); } } public function singleQuery($query, $databasename) { mysql_select_db(MySQLConfig::DB, $this->connection) or die("Error: Could not select database " . MySQLConfig::DB . " from the server."); $result = mysql_query($query) or die('Query failed.'); return $result; } public function createResultSet($query, $databasename) { $rs = new MySQLResultSet($query, MySQLConfig::DB, $this->connection ) ; return $rs; } public function close() { MySQLConnect::$instances = 0; if(isset($this->connection) ) { mysql_close($this->connection) ; unset($this->connection) ; } } public function __destruct() { $this->close(); } } The MySQLResultSet class looks like this: class MySQLResultSet implements Iterator { private $query; private $databasename; private $connection; private $result; private $currentRow; private $key = 0; private $valid; public function __construct($query, $databasename, $connection) { $this->query = $query; //Select the database $selectedDatabase = mysql_select_db($databasename, $connection) or die("Error: Could not select database " . $this->dbname . " from the server."); $this->result = mysql_query($this->query) or die('Query failed.'); $this->rewind(); } public function getResult() { return $this->result; } // public function getRow() // { // return mysql_fetch_row($this->result); // } public function getNumberRows() { return mysql_num_rows($this->result); } //current() returns the current row public function current() { return $this->currentRow; } //key() returns the current index public function key() { return $this->key; } //next() moves forward one index public function next() { if($this->currentRow = mysql_fetch_array($this->result) ) { $this->valid = true; $this->key++; }else{ $this->valid = false; } } //rewind() moves to the starting index public function rewind() { $this->key = 0; if(mysql_num_rows($this->result) > 0) { if(mysql_data_seek($this->result, 0) ) { $this->valid = true; $this->key = 0; $this->currentRow = mysql_fetch_array($this->result); } } else { $this->valid = false; } } //valid returns 1 if the current position is a valid array index //and 0 if it is not valid public function valid() { return $this->valid; } } The following class is an example of how I am accessing the database: class ImageCount { public function getCount() { $mysqlConnector = new MySQLConnect(); $query = "SELECT * FROM images;"; $resultSet = $mysqlConnector->createResultSet($query, MySQLConfig::DB); $mysqlConnector->close(); return $resultSet->getNumberRows(); } } I use the ImageCount class like this: if(!ImageCount::getCount()) { //Do something } Question: Is this an okay way to access the database? Could anybody recommend an alternative method if it is bad? Thank-you.

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• How do I add a one-to-one relationship in MYSQL?

  - by alex

  +-------+-------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +-------+-------------+------+-----+---------+-------+ | pid | varchar(99) | YES | | NULL | | +-------+-------------+------+-----+---------+-------+ 1 row in set (0.00 sec) +-------+---------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +-------+---------------+------+-----+---------+-------+ | pid | varchar(2000) | YES | | NULL | | | recid | varchar(2000) | YES | | NULL | | +-------+---------------+------+-----+---------+-------+ 2 rows in set (0.00 sec) This is my table. pid is just the id of the user. "recid" is a recommended song for that user. I hope to have a list of pid's, and then recommended songs for each person. Of course, in my 2nd table, (pid, recid) would be unique key. How do I do a one-to-one query for this ?

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• Drawing up a session value within SQL query? PHP and MySQL

  - by Derek

  Hi, on one of my web pages I want my manager user to view all activities assigned to them (personally). In order to do this, I need something like this: $sql = "SELECT * FROM activities WHERE manager = $_SESSION['SESS_FULLNAME']"; Now obviously this syntax is all wrong, but because I am new to this stuff, is there a way I can call up the full name from the user's session within a query? This is so that when I call up the database values to be displayed within the web page, only the activities for the manager who is logged in is displayed. For example, the activities table has a manager column of a full name entry. Any help is much appreciated. Thanks.

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• MYSQL - SQL query Getting single record for the similar records and populating other columns with which has more length

  - by Bujji

  Here is my case , I have a database table with below fields name place_code email phone address details estd others and example data if you look at the above example table First three records are talking about XYZ and place code 1020 . I want create a single record for these three records based on substring(name,1,4) place_code ( I am lucky here for all the similar records satisfies this condition and unique in the table .) For the other columns which record column length has max . For example again for the above 3 records email should be [email protected] , phone should be 657890 and details should be "testdetails" This should be done for all the table . (Some has single records and some has max 10 records ) Any help on query that helps me to get the desired result ? Thank You Regards Kiran

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• MySQL is there a Single Select to Query Various Unrelated Values from a database?

  - by zzapper

  I saw somewhere what seemed to be nested selects, one "master" select on the "outside" and a series of selects inside- is this possible? I'm not talking about joins as there is particular relation between the selects. I seem not to be explaining myself very well. I want to do a single query which will pull out a series of stats from various tables latest order, latest customer, largest order. Obviously I can do that with a series of selects. The example I saw was something like select ( select ... from tbl_1 where .., select ... from tbl_2 where .., select ... from tbl_3 where .., ... )

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• Please help me out in fetching the desired result from below given DB table structure of MySQL..

  - by OM The Eternity

  Hi All below are the table structures according to which I have to develop the desired output(given at the end) tbl_docatr docatr_id doc_id docatrtype_id docatr_float docatr_int docatr_date docatr_varchar docatr_blob 1 12 1 NULL NULL NULL testing [BLOB - NULL] 2 12 2 NULL NULL NULL Tesitng [BLOB - NULL] tbl_docatrtype docatrtype_id docatrtypegroup_id docatrtypetype_id docatrtype_name 1 1 4 Name 2 1 4 Company Name tbl_docatrtypetype docatrtypetype_id docatrtypetype_name 1 Float 2 Int 3 Date 4 String line Above are three tables from which I have to display the desired output as Name : testing Company Name : Tesitng such that at first step I have doc_id then I get docatrtype_id and then docatrtypetype_id acording to these values i have to fetch the result. Also the query must see the doactrtypetype_id from table tbl_docatrtypetype and fetch the result from tbl_docatr from respective column docatr_float, docatr_int, docatr_date, docatr_varchar, docatr_blob Please help!!!

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• Considering Embedding a Database? Choose MySQL!

  - by Bertrand Matthelié

  The M of the LAMP stack and the #1 database for Web-based applications, MySQL is also an extremely popular choice as embedded database. Normal 0 false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} Access our Resource Kit to discover the top reasons why:   3,000 ISVs and OEMs rely on MySQL as their embedded database 8 of the top 10 software vendors and hundreds of startups selected MySQL to power their cloud, on-premise and appliance-based offerings Leading mobile and SaaS providers ensure continuous service availability and scalability with lower cost and risk using MySQL Cluster. Learn how you can reduce costs and accelerate time to market while increasing performance and reliability. Access white papers, webinars, case studies and other resources in our Resource Kit.  

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• Preventing iframe caching in browser

  - by Zarjay

  How do you prevent Firefox and Safari from caching iframe content? I have a simple webpage with an iframe to a page on a different site. Both the outer page and the inner page have HTTP response headers to prevent caching. When I click the "back" button in the browser, the outer page works properly, but no matter what, the browser always retrieves a cache of the iframed page. IE works just fine, but Firefox and Safari are giving me trouble. My webpage looks something like this: <html> <head><!-- stuff --></head> <body> <!-- stuff --> <iframe src="webpage2.html?var=xxx" /> <!-- stuff --> </body> </html> The var variable always changes. Despite the fact that the URL of the iframe has changed (and thus, the browser should be making a new request to that page), the browser just fetches the cached content. I've examined the HTTP requests and responses going back and forth, and I noticed that even if the outer page contains <iframe src="webpage2.html?var=222" />, the browser will still fetch webpage2.html?var=111. Here's what I've tried so far: Changing iframe URL with random var value Adding Expires, Cache-Control, and Pragma headers to outer webpage Adding Expires, Cache-Control, and Pragma headers to inner webpage I'm unable to do any JavaScript tricks because I'm blocked by the same-origin policy. I'm running out of ideas. Does anyone know how to stop the browser from caching the iframed content?

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• How to combine a Distance and Keyword SQL query?

  - by Jason

  Hi Folks, I have a tables in my database called "points" and "category". A user will input info into both a location input and a keyword input text box. Then I want to find points in my table where the keyword matches either the "title" field in the points table, or the "category" but are within a certain distance from the user's location. I want to order the results by distance. Here are the 2 queries which btoh work independently: $mysql = "SELECT *, ( 3959 * acos( cos( radians('$search_lat') ) * cos( radians( lat ) ) * cos( radians( longi ) - radians('$search_lng') ) + sin( radians('$search_lat') ) * sin( radians( lat ) ) ) ) AS distance FROM points HAVING distance < '$radius'"; $mysql2 = "SELECT * FROM `points` LEFT JOIN category USING ( category_id ) WHERE (point_title LIKE '%$esc_catsearch%' OR category.title LIKE '%$esc_catsearch%')"; Here is what I tried: $sql_search = sprintf("SELECT *,point_id FROM points WHERE point_title LIKE '%%%s%%' UNION SELECT *, ( 3959 * acos( cos( radians('%s') ) * cos( radians( lat ) ) * cos( radians( longi ) - radians('%s') ) + sin( radians('%s') ) * sin( radians( lat ) ) ) ) AS distance FROM points HAVING distance < '%s' ORDER BY distance LIMIT %d , %d", $esc_catsearch, mysql_real_escape_string($search_lat), mysql_real_escape_string($search_lng), mysql_real_escape_string($search_lat), mysql_real_escape_string($radius), $offset, $rowsPerPage); But it tells me there is no know column "distance". If I remove the "Order By" phrase then it works but I'm still not sure this is giving me the results I want. I also tried the query the other way around with the distance search first but that seems to ignore my keyword. Any thoughts would be much appreciated!

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• query structure - ignoring entries for the same event from multiple users?

  - by Andrew Heath

  One table in my MySQL database tracks game plays. It has the following structure: SCENARIO_VICTORIES [ID] [scenario_id] [game] [timestamp] [user_id] [winning_side] [play_date] ID is the autoincremented primary key. timestamp records the moment of submission for the record. winning_side has one of three possible values: 1, 2, or 0 (meaning a draw) One of the queries done on this table calculates the victory percentage for each scenario, when that scenario's page is viewed. The output is expressed as: Side 1 win % Side 2 win % Draw % and queried with: SELECT winning_side, COUNT(scenario_id) FROM scenario_victories WHERE scenario_id='$scenID' GROUP BY winning_side ORDER BY winning_side ASC and then processed into the percentages and such. Sorry for the long setup. My problem is this: several of my users play each other, and record their mutual results. So these battles are being doubly represented in the victory percentages and result counts. Though this happens infrequently, the userbase isn't large and the double entries do have a noticeable effect on the data. Given the table and query above - does anyone have any suggestions for how I can "collapse" records that have the same play_date & game & scenario_id & winning_side so that they're only counted once?

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• Refresh page in browser without resubmitting form

  - by Michael

  I'm an ASP.NET developer, and I usually find myself leaving the webpage that I'm working on open in my browser (Chrome is my browser of choice, but this question is relevant for any browser). My workflow typically goes like this: I write code, I rebuild my project in Visual Studio, and then I flip back to my browser with Alt-Tab and hit F5 to refresh the page. This is fine and dandy if a form hasn't been submitted since the page was opened. But if I've been clicking around on ASP.NET form controls, the page has posted form data a number of times, so hitting F5 causes the browser to (sensibly) pop up a confirmation message, e.g., "Confirm Form Resubmission: The page that you're looking for used information that you entered...". Sometimes I do want to resubmit the form, but more often than not, I just want to start over with the page (rather than resubmit form data). The way I usually get around this is to simply add some query string data to the URL so that the browser sees it as a fresh page request, e.g.: page.aspx becomes page.aspx? (or vice-versa). My question is: Is there a better way to quickly request a fresh version of a webpage (and not submit form data) in any of the major browsers? It seems like a no-brainer to me for web development, but maybe I'm missing something. What I'd love to see is something like the last item in this list: F5: refresh page Ctrl-F5: refresh page (and force cache refresh) Alt-F5: request fresh copy of the page without resubmitting the form

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• Default browser hangs

  - by Craig Hinrichs

  Intermittent hangs would occur when I would use Internet Explorer to open a new main page or new tab to a site I know would be up. The browser would open and say "Waiting for site example.com" and do nothing more. If I closed the window and reopened it it would immediately connect. Over time I would have to close and reopen the window to get to the page. This would happen to any page, including Google. Got sick of it and started using Chrome. I recently upgraded my anti-virus and am now experiencing the same issue with Chrome. I use AVG for my antivirus. Empirically it seems that if I don't make Chrome my default browser I don't experience the issue. I tested this theory for over two hours yesterday. Possible issues I have found this could be but not confirmed yet: MTU settings are not correct. I am infected but my antivirus has not caught it (unlikely but possible) ?? I would like to think this is related to my antivirus but I am unsure how to verify. I don't like the idea of killing my antivirus if #2 is a possibility. I am looking for tips on how I can troubleshoot possible issues.

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• What user information is exposed via a browser?

  - by ipso

  Is there a function or website that can collect and display ALL of the user information that can be obtained via a browser? Background: This of course does not account for the significant cross-reference abilities of large corporations to collate multiple sources and signals from users across various properties, but it's a first step. Ghostery is just a great idea; to show people all of the surreptitious scripts that run on any given website. But what information is available – what is the total set of values stored – that those scripts can collect from? If you login to a search engine and stay logged in but leave their tab, is that company still collecting your webpage viewing and activity from other tabs? Can past or future inputs to pages be captured – say comments on another website? What types of activities are stored as variables in the browser app that can be collected? This is surely a highly complex question, given to countless user scenarios – but my whole point is to be able to cut through all that – and just show the total set of data available at any given point in time. Then you can A/B test and see what is available with in a fresh session with one tab open vs. the same webpage but with 12 tabs open, and a full day of history to boot. (Latest Firefox & Chrome – on Win7, Win8 or Mint13 – although I'd like to think that won't make too much of a difference. Make assumptions. Simple is better.)

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• com.mysql.jdbc.exceptions.jdbc4.MySQLNonTransientConnectionException: Unknown command

  - by adisembiring

  Hi .. I'm trying to create datasource for connection pooling mysql database in Websphere Application Server. I've set the JDBC Provider, I set the Implementation class name : com.mysql.jdbc.jdbc2.optional.MysqlConnectionPoolDataSource my mysql driver 5.1.6. but I got this error while I try to connect the datasource: The test connection operation failed for data source btn_itb_ds on server server1 at node qnode with the following exception: com.mysql.jdbc.exceptions.jdbc4.MySQLNonTransientConnectionException: Unknown command. View JVM logs for further details. I have read this http://bugs.mysql.com/bug.php?id=38388 trouble shooting. But they just suggest to upgrade mysql driver version 5.1.X and I have do that. but I've got the same error.

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