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  • Using Sendkeys in python to press {F12} results in other keys pressed?

    - by ThantiK
    import time from ctypes import * import win32gui import win32com.client as comclt X = 119 Y = 53 def PILColorToRGB(pil_color): """ convert a PIL-compatible integer into an (r, g, b) tuple """ hexstr = '%06x' % pil_color # reverse byte order r, g, b = hexstr[4:], hexstr[2:4], hexstr[:2] r, g, b = [int(n, 16) for n in (r, g, b)] return (r, g, b) wsh = comclt.Dispatch("WScript.Shell") w = win32gui user = windll.LoadLibrary("c:\\windows\\system32\\user32.dll") h = user.GetDC(0) gdi = windll.LoadLibrary("c:\\windows\\system32\\gdi32.dll") while True: FG = w.GetWindowText(w.GetForegroundWindow()) #FG = Foreground window title. if FG == "World of Warcraft": rgb = (PILColorToRGB(gdi.GetPixel(h,X,Y))) #X, Y time.sleep(0.333) #don't check too often. if (rgb[0] >= 130): #While Pixel (X, Y) is Red... #print "%d %d %d" % (rgb[0], rgb[1], rgb[2]) #Debug wsh.SendKeys("{F12}") #Send a key. time.sleep(0.7) #Add some extra down-time if we send the key. else: time.sleep(5) Basically all this code does is read a pixel on the screen, and send a key (F12) if the pixel is red. But when using this code I regularly get some phantom key-code being pressed. The application I'm using this on is obviously world of warcraft, and I have checked that all keybinds are standard keybinds. However randomly it seems I get either an up arrow, or a w pressed, which moves my character forward whenever this code executes (F12 is bound to a macro, unbound from any movement. If I press f12 with a hardware event, it does not exhibit this behavior. What in the world could be going on here?

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  • Django foreign keys cascade deleting and "related_name" parameter (bug?)

    - by Wiseman
    In this topic I found a good way to prevent cascade deleting of relating objects, when it's not neccessary. class Factures(models.Model): idFacture = models.IntegerField(primary_key=True) idLettrage = models.ForeignKey('Lettrage', db_column='idLettrage', null=True, blank=True) class Paiements(models.Model): idPaiement = models.IntegerField(primary_key=True) idLettrage = models.ForeignKey('Lettrage', db_column='idLettrage', null=True, blank=True) class Lettrage(models.Model): idLettrage = models.IntegerField(primary_key=True) def delete(self): """Dettaches factures and paiements from current lettre before deleting""" self.factures_set.clear() self.paiements_set.clear() super(Lettrage, self).delete() But this method seems to fail when we are using ForeignKey field with "related_name" parameter. As it seems to me, "clear()" method works fine and saves the instance of "deassociated" object. But then, while deleting, django uses another memorized copy of this very object and since it's still associated with object we are trying to delete - whooooosh! ...bye-bye to relatives :) Database was arcitectured before me, and in somewhat odd way, so I can't escape these "related_names" in reasonable amount of time. Anybody heard about workaround for such a trouble?

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  • C#...... associating keys to buttons...

    - by user300484
    Hello everyone! I have to write a method on C# that associates a certain key ( from the keyboard) to a specific button.For example.... if I press "a"....... the button that I created on a form application should appear like if it is being pressed. I dont really know how to do that and I would appreciate your help! :)

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  • How do I specify a keys password with MSBuild for the purpose of using Hudson?

    - by Brett Ryan
    We have just setup our hudson server to build .NET projects which seems to be working fine, however for projects that require a password when signing the assemblies I can not figure out how to tell hudson what the password is? For us the password is asked the first time a developer checks out the source code and they open with visual studio, how is this stored? Can we just place a secret file somewhere on the server?

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  • How do I order by foreign attribute for belongs_to refernece where there are 2 keys to foreign table

    - by Will
    I have a Model which has a belongs_to association with another Model as follows class Article belongs_to :author, :class_name => "User" end If I wanted to find all articles for a particular genre ordered by author I would do something like the following articles = Article.all(:includes => [:author], :order => "users.name") However if Article happens to have two references to User how can I sort on :author? class Article belongs_to :editor, :class_name => "User" belongs_to :author, :class_name => "User" end I have tried articles = Article.all(:includes => [:author], :order => "users.name") #=> incorrect results articles = Article.all(:includes => [:author], :order => "authors.name") #=> Exception Thrown

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  • How do I delete a [sub]hash based off of the keys/values of another hash?

    - by Zack
    Lets assume I have two hashes. One of them contains a set of data that only needs to keep things that show up in the other hash. e.g. my %hash1 = ( test1 => { inner1 => { more => "alpha", evenmore => "beta" } }, test2 => { inner2 => { more => "charlie", somethingelse => "delta" } }, test3 => { inner9999 => { ohlookmore => "golf", somethingelse => "foxtrot" } } ); my %hash2 = ( major=> { test2 => "inner2", test3 => "inner3" } ); What I would like to do, is to delete the whole subhash in hash1 if it does not exist as a key/value in hash2{major}, preferably without modules. The information contained in "innerX" does not matter, it merely must be left alone (unless the subhash is to be deleted then it can go away). In the example above after this operation is preformed hash1 would look like: my %hash1 = ( test2 => { inner2 => { more => "charlie", somethingelse => "delta" } }, ); It deletes hash1{test1} and hash1{test3} because they don't match anything in hash2. Here's what I've currently tried, but it doesn't work. Nor is it probably the safest thing to do since I'm looping over the hash while trying to delete from it. However I'm deleting at the each which should be okay? This was my attempt at doing this, however perl complains about: Can't use string ("inner1") as a HASH ref while "strict refs" in use at while(my ($test, $inner) = each %hash1) { if(exists $hash2{major}{$test}{$inner}) { print "$test($inner) is in exists.\n"; } else { print "Looks like $test($inner) does not exist, REMOVING.\n"; #not to sure if $inner is needed to remove the whole entry delete ($hash1{$test}{$inner}); } }

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  • Ruby: How can I have a Hash take multiple keys?

    - by zxcvbnm
    I'm taking 5 strings (protocol, source IP and port, destination IP and port) and using them to store some values in a hash. The problem is that if the IPs or ports are switched between source and destination, the key is supposed to be the same. If I was doing this in C#/Java/whatever I'd have to create a new class and overwrite the hashcode()/equals() methods, but that seems error prone from the little I've read about it and I was wondering if there would be a better alternative here.

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  • Send music control keys from my app in android.

    - by Hamid
    Is there a simple way to tell the default media player to change track back or forward? I want the ability to send commands to the system media player (Music) to change track back and forward from within my app. Is there a simple way? Code examples or descriptive explanation please, I have not developed for Android before.

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  • Convert Ruby array of tuples into a hash given an array of keys?

    - by Kit Ho
    I have an simple array array = ["apple", "orange", "lemon"] array2 = [["apple", "good taste", "red"], ["orange", "bad taste", "orange"], ["lemon" , "no taste", "yellow"]] how can i convert in to this hash whenever element in array match the first element of each element in array2? hash = {"apple" => ["apple" ,"good taste", "red"], "orange" => ["orange", "bad taste", "orange"], "lemon" => ["lemon" , "no taste", "yellow"] } I am quite new to ruby, and spend a lot to do this manipulation, but no luck, any help ?

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  • Any "trick" to use some keys to launch an application?

    - by Profete162
    Hello, I am currently developing an free application (TaskOS ) that allow users to have multitasking and switch easily between applications on their mobile ( like alt+tab in Windows ) That work pretty well and user can launch my application by a long press on the "search" button" by adding this line in the manifest: <action android:name="android.intent.action.SEARCH_LONG_PRESS" /> I also succeed to allow to the users to Use the camera button ( they can of course disable that in application settings) and the way to do that is slighlty different: <receiver android:name=".CameraPressed"> <intent-filter android:priority="10000"> <action android:name="android.intent.action.CAMERA_BUTTON"/> </intent-filter> I am now wondering if there are other ways to launch easily my task switcher? ( long press on Home key, long press on trackball, or any other idea.) Reading the Google documentation does not help me a lot. Any other idea/suggestion would be warmly welcome. Christophe

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  • Adding Data into tables iclueds Foreign Keys but Which New Row created Entity FrameWork ?

    - by programmerist
    Addding Data into kartlar Table (RehberID,KampanyaID,BrimID) is ok. But Which Kart'ID created? i need to learn Which Id created after Adding Data (RehberID,KampanyaID,BrimID) into Kartlar? public static List<Kartlar> SaveKartlar(int RehberID, int KampanyaID, int BrimID, string Notlar) { using (GenSatisModuleEntities genSatisCtx = new GenSatisModuleEntities()) { Kartlar kartlar = new Kartlar(); kartlar.RehberReference.EntityKey = new System.Data.EntityKey("GenSatisModuleEntities.Rehber", "ID", RehberID); kartlar.KampanyaReference.EntityKey = new System.Data.EntityKey("GenSatisModuleEntities.Kampanya", "ID", KampanyaID); kartlar.BirimReference.EntityKey = new System.Data.EntityKey("GenSatisModuleEntities.Birim", "ID", BrimID); kartlar.Notlar = Notlar; genSatisCtx.AddToKartlar(kartlar); genSatisCtx.SaveChanges(); List<Kartlar> kartAddedPatient; kartAddedPatient = (from k in genSatisCtx.Kartlar where k.RehberReference.EntityKey == RehberID && k.KampanyaReference.EntityKey == KampanyaID && k.BirimReference.EntityKey == BrimID select k) return kartAddedPatient ; } } How can i do that? i want to get data from Kartlar which data i added?

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  • Insert into a generic dictionary with possibility of duplicate keys?

    - by Chris Clark
    Is there any reason to favor one of these approaches over the other when inserting into a generic dictionary with the possibility of a key conflict? I'm building an in-memory version of a static collection so in the case of a conflict it doesn't matter whether the old or new value is used. If Not mySettings.ContainsKey(key) Then mySettings.Add(key, Value) End If Versus mySettings(key) = Value And then of course there is this, which is obviously not the right approach: Try mySettings.Add(key, Value) Catch End Try Clearly the big difference here is that the first and second approaches actually do different things, but in my case it doesn't matter. It seems that the second approach is cleaner, but I'm curious if any of you .net gurus have any deeper insight. Thanks!

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  • Trying to import SQL file in a xampp server returns error

    - by Victor_J_Martin
    I have done a ER diagram in Mysql Workbench, and I am trying load in my server with phpMyAdmin, but it returns me the next error: Error SQL Query: -- ----------------------------------------------------- -- Table `BDA`.`UG` -- ----------------------------------------------------- CREATE TABLE IF NOT EXISTS `BDA`.`UG` ( `numero_ug` INT NOT NULL, `nombre` VARCHAR(45) NOT NULL, `segunda_firma_autorizada` VARCHAR(45) NOT NULL, `fecha_creacion` DATE NOT NULL, `nombre_depto` VARCHAR(140) NOT NULL, `dni` INT NOT NULL, `anho_contable` INT NOT NULL, PRIMARY KEY (`numero_ug`), INDEX `nombre_depto_idx` (`nombre_depto` ASC), INDEX `dni_idx` (`dni` ASC), INDEX `anho_contable_idx` (`anho_contable` ASC), CONSTRAINT `nombre_depto` FOREIGN KEY (`nombre_depto`) REFERENCES `BDA`.`Departamento` (`nombre_depto`) ON DELETE NO ACTION ON UPDATE NO ACTION, CONSTRAINT `dni` FOREIGN KEY (`dni`) REFERENCES `BDA`.`Trabajador` (`dni`) ON DELETE NO ACTION ON UPDATE NO ACTION, CONSTRAINT `anho_contable` FOREIGN KEY (`anho_contable`) REFERENCES `BDA`.`Capitulo_Contable` (`anho_contable`) [...] MySQL said: Documentation #1022 - Can't write; duplicate key in table 'ug' I export the result of the diagram from Mysql Workbench to a SQL file, and this file is what I'm trying to upload. This is the file. I can not find the duplicate key. SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0; SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0; SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='TRADITIONAL,ALLOW_INVALID_DATES'; CREATE SCHEMA IF NOT EXISTS `BDA` DEFAULT CHARACTER SET utf8 COLLATE utf8_general_ci ; USE `BDA` ; -- ----------------------------------------------------- -- Table `BDA`.`Departamento` -- ----------------------------------------------------- CREATE TABLE IF NOT EXISTS `BDA`.`Departamento` ( `nombre_depto` VARCHAR(140) NOT NULL, `area_depto` VARCHAR(140) NOT NULL, PRIMARY KEY (`nombre_depto`)) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `BDA`.`Trabajador` -- ----------------------------------------------------- CREATE TABLE IF NOT EXISTS `BDA`.`Trabajador` ( `dni` INT NOT NULL, `direccion` VARCHAR(140) NOT NULL, `nombre` VARCHAR(45) NOT NULL, `apellidos` VARCHAR(140) NOT NULL, `fecha_nacimiento` DATE NOT NULL, `fecha_contrato` DATE NOT NULL, `titulacion` VARCHAR(140) NULL, `nombre_depto` VARCHAR(45) NOT NULL, PRIMARY KEY (`dni`), INDEX `nombre_depto_idx` (`nombre_depto` ASC), CONSTRAINT `nombre_depto` FOREIGN KEY (`nombre_depto`) REFERENCES `BDA`.`Departamento` (`nombre_depto`) ON DELETE NO ACTION ON UPDATE NO ACTION) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `BDA`.`Capitulo_Contable` -- ----------------------------------------------------- CREATE TABLE IF NOT EXISTS `BDA`.`Capitulo_Contable` ( `anho_contable` INT NOT NULL, `numero_ug` INT NOT NULL, `debe` DOUBLE NOT NULL, `haber` DOUBLE NOT NULL, PRIMARY KEY (`anho_contable`), INDEX `numero_ug_idx` (`numero_ug` ASC), CONSTRAINT `numero_ug` FOREIGN KEY (`numero_ug`) REFERENCES `BDA`.`UG` (`numero_ug`) ON DELETE NO ACTION ON UPDATE NO ACTION) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `BDA`.`UG` -- ----------------------------------------------------- CREATE TABLE IF NOT EXISTS `BDA`.`UG` ( `numero_ug` INT NOT NULL, `nombre` VARCHAR(45) NOT NULL, `segunda_firma_autorizada` VARCHAR(45) NOT NULL, `fecha_creacion` DATE NOT NULL, `nombre_depto` VARCHAR(140) NOT NULL, `dni` INT NOT NULL, `anho_contable` INT NOT NULL, PRIMARY KEY (`numero_ug`), INDEX `nombre_depto_idx` (`nombre_depto` ASC), INDEX `dni_idx` (`dni` ASC), INDEX `anho_contable_idx` (`anho_contable` ASC), CONSTRAINT `nombre_depto` FOREIGN KEY (`nombre_depto`) REFERENCES `BDA`.`Departamento` (`nombre_depto`) ON DELETE NO ACTION ON UPDATE NO ACTION, CONSTRAINT `dni` FOREIGN KEY (`dni`) REFERENCES `BDA`.`Trabajador` (`dni`) ON DELETE NO ACTION ON UPDATE NO ACTION, CONSTRAINT `anho_contable` FOREIGN KEY (`anho_contable`) REFERENCES `BDA`.`Capitulo_Contable` (`anho_contable`) ON DELETE NO ACTION ON UPDATE NO ACTION) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `BDA`.`Cliente` -- ----------------------------------------------------- CREATE TABLE IF NOT EXISTS `BDA`.`Cliente` ( `cif_cliente` INT NOT NULL, `nombre_cliente` VARCHAR(140) NOT NULL, PRIMARY KEY (`cif_cliente`)) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `BDA`.`Ingreso` -- ----------------------------------------------------- CREATE TABLE IF NOT EXISTS `BDA`.`Ingreso` ( `id` INT NOT NULL, `concepto` VARCHAR(45) NOT NULL, `importe` DOUBLE NOT NULL, `fecha` DATE NOT NULL, `cif_cliente` INT NOT NULL, `numero_ug` INT NOT NULL, PRIMARY KEY (`id`), INDEX `cif_cliente_idx` (`cif_cliente` ASC), INDEX `numero_ug_idx` (`numero_ug` ASC), CONSTRAINT `cif_cliente` FOREIGN KEY (`cif_cliente`) REFERENCES `BDA`.`Cliente` (`cif_cliente`) ON DELETE NO ACTION ON UPDATE NO ACTION, CONSTRAINT `numero_ug` FOREIGN KEY (`numero_ug`) REFERENCES `BDA`.`UG` (`numero_ug`) ON DELETE NO ACTION ON UPDATE NO ACTION) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `BDA`.`Proveedor` -- ----------------------------------------------------- CREATE TABLE IF NOT EXISTS `BDA`.`Proveedor` ( `cif_proveedor` INT NOT NULL, `nombre_proveedor` VARCHAR(140) NOT NULL, PRIMARY KEY (`cif_proveedor`)) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `BDA`.`Gasto` -- ----------------------------------------------------- CREATE TABLE IF NOT EXISTS `BDA`.`Gasto` ( `id` INT NOT NULL, `concepto` VARCHAR(45) NOT NULL, `importe` DOUBLE NOT NULL, `fecha` DATE NOT NULL, `factura` INT NOT NULL, `cif_proveedor` INT NOT NULL, `numero_ug` INT NOT NULL, PRIMARY KEY (`id`), INDEX `cif_proveedor_idx` (`cif_proveedor` ASC), INDEX `numero_ug_idx` (`numero_ug` ASC), CONSTRAINT `cif_proveedor` FOREIGN KEY (`cif_proveedor`) REFERENCES `BDA`.`Proveedor` (`cif_proveedor`) ON DELETE NO ACTION ON UPDATE NO ACTION, CONSTRAINT `numero_ug` FOREIGN KEY (`numero_ug`) REFERENCES `BDA`.`UG` (`numero_ug`) ON DELETE NO ACTION ON UPDATE NO ACTION) ENGINE = InnoDB; SET SQL_MODE=@OLD_SQL_MODE; SET FOREIGN_KEY_CHECKS=@OLD_FOREIGN_KEY_CHECKS; SET UNIQUE_CHECKS=@OLD_UNIQUE_CHECKS; Thanks for your advices.

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  • Howw to add new value with generic Repository if there are foreign keys (EF-4)?

    - by Phsika
    i try to write a kind of generic repository to add method. Everything is ok to add but I have table which is related with two tables with FOREIGN KEY.But Not working because of foreign key public class DomainRepository<TModel> : IDomainRepository<TModel> where TModel : class { #region IDomainRepository<T> Members private ObjectContext _context; private IObjectSet<TModel> _objectSet; public DomainRepository() { } public DomainRepository(ObjectContext context) { _context = context; _objectSet = _context.CreateObjectSet<TModel>(); } //do something..... public TModel Add<TModel>(TModel entity) where TModel : IEntityWithKey { EntityKey key; object originalItem; key = _context.CreateEntityKey(entity.GetType().Name, entity); _context.AddObject(key.EntitySetName, entity); _context.SaveChanges(); return entity; } //do something..... } Calling REPOSITORY: //insert-update-delete public partial class AddtoTables { public table3 Add(int TaskId, int RefAircraftsId) { using (DomainRepository<table3> repTask = new DomainRepository<table3>(new TaskEntities())) { return repTask.Add<table3>(new table3() { TaskId = TaskId, TaskRefAircraftsID = RefAircraftsId }); } } } How to add a new value if this table includes foreign key relation

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  • Why does cisco IOS require domain-name to be set before SSH keys can be generated?

    - by Daniel Papasian
    Is there a technical reason why IOS requires the device's domain-name to be set (via ip domain-name) before an SSH key can be generated? Is the domain-name used in any way in the generation of the key? Is there any way to force the generation of a key before the domain name is set? UPDATE: Myself (before I posted this question) and others in your answer seem to think it may be used as either a salt or a source of entropy for the key. Wouldn't the domain-name be very predictable? This doesn't seem like a suitable source of entropy.

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  • Find messages from certain key till certain key while being able to remove stale keys.

    - by Alfred
    My problem Let's say I add messages to some sort of datastructure: 1. "dude" 2. "where" 3. "is" 4. "my" 5. "car" Asking for messages from index[4,5] should return: "my","car". Next let's assume that after a while I would like to purge old messages because they aren't useful anymore and I want to save memory. Let's say at time x messages[1-3] became stale. I assume that it would be most efficient to just do the deletion once every x seconds. Next my datastructure should contain: 4. "my" 5. "car" My solution? I was thinking of using a concurrentskiplistset or concurrentskiplist map. Also I was thinking of deleting the old messages from inside a newSingleThreadScheduledExecutor. I would like to know how you would implement(efficiently/thread-safe) this or maybe use a library?

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  • How do I order by foreign attribute for belongs_to reference where there are 2 keys to foreign table

    - by Will
    I have a Model which has a belongs_to association with another Model as follows class Article belongs_to :author, :class_name => "User" end If I wanted to find all articles for a particular genre ordered by author I would do something like the following articles = Article.all(:includes => [:author], :order => "users.name") However if Article happens to have two references to User how can I sort on :author? class Article belongs_to :editor, :class_name => "User" belongs_to :author, :class_name => "User" end I have tried articles = Article.all(:includes => [:author], :order => "users.name") #=> incorrect results articles = Article.all(:includes => [:author], :order => "authors.name") #=> Exception Thrown

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  • Percentage difference between different values in the same keys of two different arrays.

    - by Paul
    Hey. I'm looking for a solution to this problem. I got 2 arrays, like this: array(2) { [20100526]=> array(1) { ["ga:pageviews"]=> string(5) "19088" } [20100527]=> array(1) { ["ga:pageviews"]=> string(5) "15566" } } array(2) { [20100526]=> array(1) { ["ga:pageviews"]=> string(5) "12043" } [20100527]=> array(1) { ["ga:pageviews"]=> string(5) "11953" } } Now I'd like to create a new array, with the % difference between the values per key. Would be something like this: array(2) { [20100526]=> array(1) { ["ga:pageviews"]=> string(5) "88,23" } [20100527]=> array(1) { ["ga:pageviews"]=> string(5) "74,54" } } Can anyone help me how to create that array?

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  • How to make MySQL utilize available system resources, or find "the real problem"?

    - by anonymous coward
    This is a MySQL 5.0.26 server, running on SuSE Enterprise 10. This may be a Serverfault question. The web user interface that uses these particular queries (below) is showing sometimes 30+, even up to 120+ seconds at the worst, to generate the pages involved. On development, when the queries are run alone, they take up to 20 seconds on the first run (with no query cache enabled) but anywhere from 2 to 7 seconds after that - I assume because the tables and indexes involved have been placed into ram. From what I can tell, the longest load times are caused by Read/Update Locking. These are MyISAM tables. So it looks like a long update comes in, followed by a couple 7 second queries, and they're just adding up. And I'm fine with that explanation. What I'm not fine with is that MySQL doesn't appear to be utilizing the hardware it's on, and while the bottleneck seems to be the database, I can't understand why. I would say "throw more hardware at it", but we did and it doesn't appear to have changed the situation. Viewing a 'top' during the slowest times never shows much cpu or memory utilization by mysqld, as if the server is having no trouble at all - but then, why are the queries taking so long? How can I make MySQL use the crap out of this hardware, or find out what I'm doing wrong? Extra Details: On the "Memory Health" tab in the MySQL Administrator (for Windows), the Key Buffer is less than 1/8th used - so all the indexes should be in RAM. I can provide a screen shot of any graphs that might help. So desperate to fix this issue. Suffice it to say, there is legacy code "generating" these queries, and they're pretty much stuck the way they are. I have tried every combination of Indexes on the tables involved, but any suggestions are welcome. Here's the current Create Table statement from development (the 'experimental' key I have added, seems to help a little, for the example query only): CREATE TABLE `registration_task` ( `id` varchar(36) NOT NULL default '', `date_entered` datetime NOT NULL default '0000-00-00 00:00:00', `date_modified` datetime NOT NULL default '0000-00-00 00:00:00', `assigned_user_id` varchar(36) default NULL, `modified_user_id` varchar(36) default NULL, `created_by` varchar(36) default NULL, `name` varchar(80) NOT NULL default '', `status` varchar(255) default NULL, `date_due` date default NULL, `time_due` time default NULL, `date_start` date default NULL, `time_start` time default NULL, `parent_id` varchar(36) NOT NULL default '', `priority` varchar(255) NOT NULL default '9', `description` text, `order_number` int(11) default '1', `task_number` int(11) default NULL, `depends_on_id` varchar(36) default NULL, `milestone_flag` varchar(255) default NULL, `estimated_effort` int(11) default NULL, `actual_effort` int(11) default NULL, `utilization` int(11) default '100', `percent_complete` int(11) default '0', `deleted` tinyint(1) NOT NULL default '0', `wf_task_id` varchar(36) default '0', `reg_field` varchar(8) default '', `date_offset` int(11) default '0', `date_source` varchar(10) default '', `date_completed` date default '0000-00-00', `completed_id` varchar(36) default NULL, `original_name` varchar(80) default NULL, PRIMARY KEY (`id`), KEY `idx_reg_task_p` (`deleted`,`parent_id`), KEY `By_Assignee` (`assigned_user_id`,`deleted`), KEY `status_assignee` (`status`,`deleted`), KEY `experimental` (`deleted`,`status`,`assigned_user_id`,`parent_id`,`date_due`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 And one of the ridiculous queries in question: SELECT users.user_name assigned_user_name, registration.FIELD001 parent_name, registration_task.status status, registration_task.date_modified date_modified, registration_task.date_due date_due, registration.FIELD240 assigned_wf, if(LENGTH(registration_task.description)>0,1,0) has_description, registration_task.* FROM registration_task LEFT JOIN users ON registration_task.assigned_user_id=users.id LEFT JOIN registration ON registration_task.parent_id=registration.id where (registration_task.status != 'Completed' AND registration.FIELD001 LIKE '%' AND registration_task.name LIKE '%' AND registration.FIELD060 LIKE 'GN001472%') AND registration_task.deleted=0 ORDER BY date_due asc LIMIT 0,20; my.cnf - '[mysqld]' section. [mysqld] port = 3306 socket = /var/lib/mysql/mysql.sock skip-locking key_buffer = 384M max_allowed_packet = 100M table_cache = 2048 sort_buffer_size = 2M net_buffer_length = 100M read_buffer_size = 2M read_rnd_buffer_size = 160M myisam_sort_buffer_size = 128M query_cache_size = 16M query_cache_limit = 1M EXPLAIN above query, without additional index: +----+-------------+-------------------+--------+--------------------------------+----------------+---------+------------------------------------------------+---------+-----------------------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+-------------------+--------+--------------------------------+----------------+---------+------------------------------------------------+---------+-----------------------------+ | 1 | SIMPLE | registration_task | ref | idx_reg_task_p,status_assignee | idx_reg_task_p | 1 | const | 1067354 | Using where; Using filesort | | 1 | SIMPLE | registration | eq_ref | PRIMARY,gbl | PRIMARY | 8 | sugarcrm401.registration_task.parent_id | 1 | Using where | | 1 | SIMPLE | users | ref | PRIMARY | PRIMARY | 38 | sugarcrm401.registration_task.assigned_user_id | 1 | | +----+-------------+-------------------+--------+--------------------------------+----------------+---------+------------------------------------------------+---------+-----------------------------+ EXPLAIN above query, with 'experimental' index: +----+-------------+-------------------+--------+-----------------------------------------------------------+------------------+---------+------------------------------------------------+--------+-----------------------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+-------------------+--------+-----------------------------------------------------------+------------------+---------+------------------------------------------------+--------+-----------------------------+ | 1 | SIMPLE | registration_task | range | idx_reg_task_p,status_assignee,NewIndex1,tcg_experimental | tcg_experimental | 259 | NULL | 103345 | Using where; Using filesort | | 1 | SIMPLE | registration | eq_ref | PRIMARY,gbl | PRIMARY | 8 | sugarcrm401.registration_task.parent_id | 1 | Using where | | 1 | SIMPLE | users | ref | PRIMARY | PRIMARY | 38 | sugarcrm401.registration_task.assigned_user_id | 1 | | +----+-------------+-------------------+--------+-----------------------------------------------------------+------------------+---------+------------------------------------------------+--------+-----------------------------+

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