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  • Noob filter: How do I refer to a string that is passed to my Ruby on Rails method from Flex as a HTT

    - by ben
    I have a HTTPService in my Flex 4 app that I call like this: getUserDetails.send(userLookup.text); In my Ruby on Rails method that this is linked to, how do I refer to the userLookup.text parameter? The method is as follows, with XXX as the placeholder: def getDetails @user = User.first (:conditions => "username = XXX") render :xml => @user end UPDATE: Is this way correct? I found it here. I'm still getting errors but it might be because of something else. def getDetails(lookupUsername) @user = User.first (:conditions => "username = '#{lookupUsername}") render :xml => @user end Thanks for reading!

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  • Where does Tomcat append / to directory paths?

    - by Anonymouse
    Suppose my Tomcat webapps directory looks like this: webapps/ webapps/fooapp/ webapps/fooapp/WEB-INF/ webapps/fooapp/WEB-INF/web.xml webapps/fooapp/bardir/ When I make a GET request for /fooapp/bardir, Tomcat sees that webapps/fooapp/bardir is a directory and sends back a 302 to /fooapp/bardir/ (with a slash at the end). Here is my question: Where in the Tomcat source code does this take place? (I'm looking at 6.0.x but a correct answer for any version would be a great starting point.) The only reference material I can find on this subject is in the Catalina Functional Specifications which states, regarding the Default Servlet: On each HTTP GET request processed by this servlet, the following processing shall be performed: [...] If the requested resource is a directory: If the request path does not end with "/", redirect to a corresponding path with "/" appended so that relative references in welcome files are resolved correctly. However, this functionality does not appear to be in org.apache.catalina.servlets.DefaultServlet; or at least, it's not there exclusively: if I replace the default servlet in web.xml with a servlet whose servlet-class does not exist, directory paths still come back 302 to add the slash, while every other request comes back with an error as expected.

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  • Spring @Autowired and WebApplicationContext in Tomcat

    - by EugeneP
    @Autowired works only once. What to do to make it wire the bean every time the Servlet is recreated? My web-app (Tomcat6 container) consists of 2 Servlets. Every servlet has private fields. Their setters are marked with @Autowired In the init method I use WebApplicationContextUtils ... autowireBean(this); It autowires the properties marked with @Autowired once - during the initialization of the Servlet. Any other session will see these fields values, they will not be rewired after the previous session is destroyed. What to do to make them rewire them each time a Servlet constructor is called? a) Put the autowiring into the constructor? Or better 2) get a web app context and extract a bean from there?

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  • What's the best way to view/analyse/filter huge traces/logfiles?

    - by oliver
    this seems to be a reoccurring issue: we receive a bug report for our software and with it tons of traces or logfiles. since finding errors is much easier when having a visualization of the log messages/events over time it is convenient to use a tool that can display the progression of events in a graph etc. (e.g. wireshark (http://www.wireshark.org) for analyzing network traffic) what tool do you use for such a purpose? the problem with most tools i used so far is that they mercilessly break down when you feed them huge data traces ( 1GB) so some criteria for such a tool would be: can deal with huge input files ( 1 GB) is really fast (so you don't have to get coffee while a file is loading) has some sort of filtering mechanism

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  • Can I filter a django model with a python list?

    - by Rhubarb
    Say I have a model object 'Person' defined, which has a field called 'Name'. And I have a list of people: l = ['Bob','Dave','Jane'] I would like to return a list of all Person records where the first name is not in the list of names defined in l. What is the most pythonic way of doing this?

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  • Character-encoding problem spring

    - by aelshereay
    Hi All, I am stuck in a big problem with encoding in my website! I use spring 3, tomcat 6, and mysql db. I want to support German and Czech along with English in my website, I created all the JSPs as UTF-8 files, and in each jsp I include the following: <%@ page language="java" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8"%> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> I created messages.properties (the default which is Czech), messages_de.properties, and messages_en.properties. And all of them are saved as UTF-8 files. I added the following to web.xml: <filter> <filter-name>encodingFilter</filter-name> <filterclass> org.springframework.web.filter.CharacterEncodingFilter</filterclass> <init-param> <param-name>encoding</param-name> <param-value>UTF-8</param-value> </init-param> <init-param> <param-name>forceEncoding</param-name> <param-value>true</param-value> </init-param> </filter> <locale-encoding-mapping-list> <locale-encoding-mapping> <locale>en</locale> <encoding>UTF-8</encoding> </locale-encoding-mapping> <locale-encoding-mapping> <locale>cz</locale> <encoding>UTF-8</encoding> </locale-encoding-mapping> <locale-encoding-mapping> <locale>de</locale> <encoding>UTF-8</encoding> </locale-encoding-mapping> </locale-encoding-mapping-list> <filter-mapping> <filter-name>encodingFilter</filter-name> <url-pattern>/*</url-pattern> </filter-mapping> And add the following to my applicationContext.xml: <bean id="messageSource" class="org.springframework.context.support.ResourceBundleMessageSource" p:basenames="messages"/> <!-- Declare the Interceptor --> <mvc:interceptors> <bean class="org.springframework.web.servlet.i18n.LocaleChangeInterceptor" p:paramName="locale" /> </mvc:interceptors> <!-- Declare the Resolver --> <bean id="localeResolver" class="org.springframework.web.servlet.i18n.SessionLocaleResolver" /> I set the useBodyEncodingForURI attribute to true in the element of server.xml under: %CATALINA_HOME%/conf, also another time tried to add URIEncoding="UTF-8" instead. I created all the tables and fields with charset [utf8] and collection [utf8_general_ci] The encoding in my browser is UTF-8 (BTW, I have IE8 and Firefox 3.6.3) When I open the MYSQL Query browser and insert manually Czech or German data, it's being inserted correctly, and displayed correctly in my app as well. So, here's the list of problems I have: By default the messages.properties (Czech) should load, instead the messages_en.properties loads by default. In the web form, when I enter Czech data, then click submit, in the Controller I print out the data in the console before to save it to db, what's being printed is not correct having strange chars, and this is the exact data that saves to db. I don't know where's the mistake! Why can't I get it working although I did what people did and worked for them! don't know.. Please help me, I am stuck in this crappy problem since days, and it drives me crazy! Thank you in advance.

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  • How to develop JSP/Servlets Web App using MVC pattern?

    - by A.S al-shammari
    I'm developing a JSP/Servlets web app (no frameworks). I want to use MVC pattern. I designed my project like this : Controller :a servlet that reads a request, extracts the values,communicates with model objects and gives information to a JSP page. View : JSP Pages. Model : Java Classes / Java Beans .. etc . The problem : Index.jsp is the starting point (default page) in my web site. So, the Index.jsp becomes the controller to parse the request! .For example , the following request : index.jsp?section=article&id=10 parsed in index.jsp as following : <div class="midcol"> <!-- Which section? --> <%String fileName = request.getParameter("section"); if (fileName == null) { fileName = "WEB-INF/jspf/frontpage.jsp"; } else { fileName = "WEB-INF/jspf/" + fileName + ".jsp"; } %> <jsp:include page='<%= fileName%>' /> </div> Here, I can't force the servlet to be a controller .. because the index.jsp is the controller here since it's the starting point! Is there any solution to forward the request from index.jsp to the servlet and then go back to index.jsp ? Or any solution that achieves the MVC goal - the servlet should be the controller - ? I'm thinking of making a FrontPageController servlet as default page instead of index.jsp ! but I don't know if it's a perfect idea ?!

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  • What would the conditional statement be to filter these inputs?

    - by dmanexe
    I have a page with a form, and on the form are a bunch of input check boxes. In the following page, there's the following code to process the inputs from the page before (which are set as an ID). <? $field = $this->input->post('measure',true); $totals = array(); foreach($field as $value): $query = $this->db->get_where('items', array('id' => $value['input']))->row(); $totals[] = $query->price; ?> #HTML for displaying estimate output here <?php endforeach; ?> How would I have the loop run conditionally only if there was a check on the input on the page before?

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  • Spring MVC: How to resolve the path to subdirectories of the root 'JSP' folder in a web application

    - by chrisjleu
    What is a simple way to resolve the path to a JSP file that is not located in the root JSP directory of a web application using SpringMVCs viewResolvers? For example, suppose we have the following web application structure: web-app |-WEB-INF |-jsp |-secure |-admin.jsp |-admin2.jsp index.jsp login.jsp I would like to use some out-of-the-box components to resolve the JSP files within the jsp root folder and the secure subdirectory. I have a *-servlet.xml file that defines: an out-of-the-box, InternalResourceViewResolver: <bean id="jspViewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"></property> <property name="prefix" value="/WEB-INF/jsp/"></property> <property name="suffix" value=".jsp"></property> </bean> a handler mapping: <bean id="handlerMapping" class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping"> <property name="mappings"> <props> <prop key="/index.htm">urlFilenameViewController</prop> <prop key="/login.htm">urlFilenameViewController</prop> <prop key="/secure/**">urlFilenameViewController</prop> </props> </property> </bean> an out-of-the-box UrlFilenameViewController controller: <bean id="urlFilenameViewController" class="org.springframework.web.servlet.mvc.UrlFilenameViewController"> </bean> The problem I have is that requests to the JSPs in the secure directory cannot be resolved, as the jspViewResolver only has a prefix defined as /jsp/ and not /jsp/secure/. Is there a way to handle subdirectories like this? I would prefer to keep this structure because I'm also trying to make use of Spring Security and having all secure pages in a subdirectory is a nice way to do this. There's probably a simple way to acheive this but I'm new to Spring and the Spring MVC framework so any pointers would be appreciated.

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  • How to call Twiter's Streaming/Filter Feed with urllib2/httplib?

    - by Simon
    Update: I switched this back from answered as I tried the solution posed in cogent Nick's answer and switched to Google's urlfetch: logging.debug("starting urlfetch for http://%s%s" % (self.host, self.url)) result = urlfetch.fetch("http://%s%s" % (self.host, self.url), payload=self.body, method="POST", headers=self.headers, allow_truncated=True, deadline=5) logging.debug("finished urlfetch") but unfortunately finished urlfetch is never printed - I see the timeout happen in the logs (it returns 200 after 5 seconds), but execution doesn't seem tor return. Hi All- I'm attempting to play around with Twitter's Streaming (aka firehose) API with Google App Engine (I'm aware this probably isn't a great long term play as you can't keep the connection perpetually open with GAE), but so far I haven't had any luck getting my program to actually parse the results returned by Twitter. Some code: logging.debug("firing up urllib2") req = urllib2.Request(url="http://%s%s" % (self.host, self.url), data=self.body, headers=self.headers) logging.debug("called urlopen for %s %s, about to call urlopen" % (self.host, self.url)) fobj = urllib2.urlopen(req) logging.debug("called urlopen") When this executes, unfortunately, my debug output never shows the called urlopen line printed. I suspect what's happening is that Twitter keeps the connection open and urllib2 doesn't return because the server doesn't terminate the connection. Wireshark shows the request being sent properly and a response returned with results. I tried adding Connection: close to my request header, but that didn't yield a successful result. Any ideas on how to get this to work? thanks -Simon

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  • how do I paste text to a line by line text filter like awk, without having stdin echo to the screen?

    - by Barton Chittenden
    I have a text in an email on a windows box that looks something like this: 100 some random text 101 some more random text 102 lots of random text, all different 103 lots of random text, all the same I want to extract the numbers, i.e. the first word on each line. I've got a terminal running bash open on my Linux box... If these were in a text file, I would do this: awk '{print $1}' mytextfile.txt I would like to paste these in, and get my numbers out, without creating a temp file. my naive first attempt looked like this: $ awk '{print $1}' 100 some random text 100 101 some more random text 101 102 lots of random text, all different 103 lots of random text, all the same 102 103 The buffering of stdin and stdout make a hash of this. I wouldn't mind if stdin all printed first, followed by all of stdout; this is what would happen if I were to paste into 'sort' for example, but awk and sed are a different story. a little more thought gave me this: open two terminals. Create a fifo file. Read from the fifo on one terminal, write to it on another. This does in fact work, but I'm lazy. I don't want to open a second terminal. Is there a way in the shell that I can hide the text echoed to the screen when I'm passing it in to a pipe, so that I paste this: 100 some random text 101 some more random text 102 lots of random text, all different 103 lots of random text, all the same but see this? $ awk '{print $1}' 100 101 102 103

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  • Asynchronous Processing in JBoss 6 ("Comet")

    - by chris_l
    edit: Retagged as tomcat, since this is really a question about the Tomcat embedded inside JBoss 6, rather than JBoss itself I have an extremely simple servlet, which works on Glassfish v3. It uses Servlet 3.0 Asynchronous Processing. Here's a simplified version (which doesn't do much): @WebServlet(asyncSupported=true) public class SimpleServlet extends HttpServlet { @Override protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { final AsyncContext ac = request.startAsync(); ac.setTimeout(3000); } } On JBoss 6.0.0 (Milestone 2), I get the following Exception: java.lang.IllegalStateException: The servlet or filters that are being used by this request do not support async operation at org.apache.catalina.connector.Request.startAsync(Request.java:3096) at org.apache.catalina.connector.Request.startAsync(Request.java:3090) at org.apache.catalina.connector.RequestFacade.startAsync(RequestFacade.java:990) at playcomet.SimpleServlet.doGet(SimpleServlet.java:18) at javax.servlet.http.HttpServlet.service(HttpServlet.java:734) ... Do I have to do anything special to enable Asynchronous Processing in JBoss 6? Or do I need an additional deployment descriptor? ...

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  • Struts ActionError

    - by user287663
    Hi all. Anyone knows why the code below doesn't compile? The reason is that it could not find symbol for ActionError. Thanks in advance. package com.hbs; import javax.servlet.RequestDispatcher; import javax.servlet.ServletException; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpSession; import javax.servlet.http.HttpServletResponse; import org.apache.struts.action.Action; import org.apache.struts.action.ActionError; import org.apache.struts.action.ActionErrors; import org.apache.struts.action.ActionForm; import org.apache.struts.action.ActionMapping; import org.apache.struts.action.ActionForward; import org.apache.struts.util.MessageResources; import org.apache.commons.beanutils.PropertyUtils; public class FeedbackAction extends org.apache.struts.action.Action { private final static String SUCCESS = "success"; public ActionForward execute(ActionMapping mapping, ActionForm form, HttpServletRequest request, HttpServletResponse response) throws Exception { ActionErrors errors = new ActionErrors(); String fullName = (String)PropertyUtils.getSimpleProperty(form, "fullName"); String fullName1 = ""; if(fullName.equals(fullName1)) { errors.add("fullName", new ActionError("error.fullName", fullName)); saveErrors(request,errors); return (new ActionForward(mapping.getInput())); } return mapping.findForward(SUCCESS); } }

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  • How to get Alfresco login ticket without user password, but with impersonating user with user principal name (UPN)

    - by dok
    I'm writing a DLL that has function for getting Alfresco login ticket without using user password, using only a user principal name (UPN). I’m calling alfresco REST API service /wcservice. I use NTLM in Alfresco. I’m impersonating users using WindowsIdentity constructor as explained here http://msdn.microsoft.com/en-us/library/ms998351.aspx#paght000023_impersonatingbyusingwindowsidentity. I checked and user is properly impersonated (I checked WindowsIdentity.GetCurrent().Name property). After impersonating a user, I try to make HttpWebRequest and set its credentials with CredentialsCache.DefaultNetworkCredentials. I get the error: The remote server returned an error: (401) Unauthorized. at System.Net.HttpWebRequest.GetResponse() When I use new NetworkCredential("username", "P@ssw0rd") to set request credentials, I get Alfresco login ticket (HttpStatusCode.OK, 200). Is there any way that I can get Alfresco login ticket without user password? Here is the code that I'm using: private string GetTicket(string UPN) { WindowsIdentity identity = new WindowsIdentity(UPN); WindowsImpersonationContext context = null; try { context = identity.Impersonate(); MakeWebRequest(); } catch (Exception e) { return e.Message + Environment.NewLine + e.StackTrace; } finally { if (context != null) { context.Undo(); } } } private string MakeWebRequest() { string URI = "http://alfrescoserver/alfresco/wcservice/mg/util/login"; HttpWebRequest request = WebRequest.Create(URI) as HttpWebRequest; request.CookieContainer = new CookieContainer(1); //request.Credentials = new NetworkCredential("username", "p@ssw0rd"); // It works with this request.Credentials = CredentialCache.DefaultNetworkCredentials; // It doesn’t work with this //request.Credentials = CredentialCache.DefaultCredentials; // It doesn’t work with this either try { using (HttpWebResponse response = request.GetResponse() as HttpWebResponse) { StreamReader sr = new StreamReader(response.GetResponseStream()); return sr.ReadToEnd(); } } catch (Exception e) { return (e.Message + Environment.NewLine + e.StackTrace); } } Here are records from Alfresco stdout.log (if it helps in any way): 17:18:04,550 DEBUG [app.servlet.NTLMAuthenticationFilter] Processing request: /alfresco/wcservice/mg/util/login SID:7453F7BD4FD2E6A61AD40A31A37733A5 17:18:04,550 DEBUG [web.scripts.DeclarativeRegistry] Web Script index lookup for uri /mg/util/login took 0.526239ms 17:18:04,550 DEBUG [app.servlet.NTLMAuthenticationFilter] New NTLM auth request from 10.**.**.** (10.**.**.**:1229) 17:18:04,566 DEBUG [app.servlet.NTLMAuthenticationFilter] Processing request: /alfresco/wcservice/mg/util/login SID:7453F7BD4FD2E6A61AD40A31A37733A5 17:18:04,566 DEBUG [web.scripts.DeclarativeRegistry] Web Script index lookup for uri /mg/util/login took 0.400909ms 17:18:04,566 DEBUG [app.servlet.NTLMAuthenticationFilter] Received type1 [Type1:0xe20882b7,Domain:<NotSet>,Wks:<NotSet>] 17:18:04,566 DEBUG [app.servlet.NTLMAuthenticationFilter] Client domain null 17:18:04,675 DEBUG [app.servlet.NTLMAuthenticationFilter] Sending NTLM type2 to client - [Type2:0x80000283,Target:AlfrescoServerA,Ch:197e2631cc3f9e0a]

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  • Spring MVC; avoiding file extension in url?

    - by Ezombort
    I just started with Spring Web MVC. I'm trying to avoid file extenstions in the url. How can i do this? (I'm using Spring 2.5.x) Bean: <bean name="/hello.htm" class="springapp.web.HelloController"/> I want it to be: <bean name="/hello" class="springapp.web.HelloController"/> I cannot get it to work. Any ideas? Edit: Url-mapping <servlet-mapping> <servlet-name>springapp</servlet-name> <url-pattern>*.htm</url-pattern> </servlet-mapping> I have tried changing the url-pattern with no luck (* and /*).

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  • Can MYSQL filter by date if date is stored as text? ex "02/10/1984"

    - by Roeland
    Hello! I am trying to modify an app for a client which has already a database of over 1000 items. The dates are stored as text in the database with the format "02/10/1984". The system allows you to add and remove fields to the catalog dynamically and it also allows the advanced search to have specific fields be allowed. The problem is that it wasn't designed with dates in mind, so when I set a field as a date, and try to search by a range the query is trying to do a AND (cfv0.value = 01/02/2004 AND cfv0.value <= 05/03/2008) . I can make it so the date range passed is a numeric time value. Is there a way that when sending the query, it takes the text fields (with the date) and converts it to numeric time value so at that point I am basically just comparing numbers which would work fine. I do not have the option to change all the current date to numeric value due to the way the dynamic fields are set up. Thanks guys!

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  • ClassCastException happens when I use maven with tomcat plugin

    - by zjffdu
    Hi all, I try to use maven with tomcat plugin to develop a simple web application. But When I invoke the servlet, ClassCastException happens, this is the error message: java.lang.ClassCastException: "com.snda.dw.moniter.LogQueryServlet cannot be to javax.servlet.Servlet" But I already make com.snda.dw.moniter.LogQueryServlet extends HttpServlet, it should can be cast to avax.servlet.Servlet. The following is my pom.xml http://maven.apache.org/maven-v4_0_0.xsd" 4.0.0 com.snda dw.moniter war 0.0.1-SNAPSHOT dw.moniter Maven Webapp http://maven.apache.org junit junit 3.8.1 test <dependency> <groupId>javax.servlet</groupId> <artifactId>servlet-api</artifactId> <version>2.4</version> <scope>provided</scope> </dependency> <dependency> <groupId>javax.servlet.jsp</groupId> <artifactId>jsp-api</artifactId> <version>2.0</version> <scope>provided</scope> </dependency> <dependency> <groupId>com.google.guava</groupId> <artifactId>guava</artifactId> <version>r07</version> <type>jar</type> <scope>compile</scope> </dependency> <dependency> <groupId>org.slf4j</groupId> <artifactId>slf4j-api</artifactId> <version>1.6.1</version> <type>jar</type> <scope>compile</scope> </dependency> <dependency> <groupId>org.slf4j</groupId> <artifactId>slf4j-simple</artifactId> <version>1.6.1</version> <type>jar</type> <scope>compile</scope> </dependency> <dependency> <groupId>org.apache.hadoop</groupId> <artifactId>hadoop-core</artifactId> <version>0.20.2</version> <type>jar</type> <scope>compile</scope> </dependency> <dependency> <groupId>com.snda</groupId> <artifactId>dw.common</artifactId> <version>1.0-SNAPSHOT</version> <type>jar</type> <scope>compile</scope> </dependency> <dependency> <groupId>net.sf.flexjson</groupId> <artifactId>flexjson</artifactId> <version>2.1</version> <type>jar</type> <scope>compile</scope> </dependency> </dependencies> <build> <finalName>dw.moniter</finalName> <pluginManagement> <plugins> <plugin> <artifactId>maven-compiler-plugin</artifactId> <configuration> <source>1.5</source> <target>1.5</target> </configuration> </plugin> <plugin> <groupId>org.codehaus.mojo</groupId> <artifactId>tomcat-maven-plugin</artifactId> <version>1.1</version> </plugin> <plugin> <groupId>org.mortbay.jetty</groupId> <artifactId>jetty-maven-plugin</artifactId> <version>8.0.0.M2</version> </plugin> </plugins> </pluginManagement> </build>

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  • Hibernate NoMethod Error in Java

    - by Noor
    I am getting an error in hibernate and failing to know its origin stack trace: java.lang.NoSuchMethodError: org.hibernate.cfg.AnnotationBinder.bindDefaults(Lorg/hibernate/cfg/Mappings;)V at org.hibernate.cfg.Configuration.secondPassCompile(Configuration.java:1360) at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1826) at com.BiddingSystem.server.ServiceImpl.<init>(ServiceImpl.java:60) at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method) at sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstructorAccessorImpl.java:39) at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingConstructorAccessorImpl.java:27) at java.lang.reflect.Constructor.newInstance(Constructor.java:513) at java.lang.Class.newInstance0(Class.java:355) at java.lang.Class.newInstance(Class.java:308) at org.mortbay.jetty.servlet.Holder.newInstance(Holder.java:153) at org.mortbay.jetty.servlet.ServletHolder.getServlet(ServletHolder.java:339) at org.mortbay.jetty.servlet.ServletHolder.handle(ServletHolder.java:463) at org.mortbay.jetty.servlet.ServletHandler.handle(ServletHandler.java:362) at org.mortbay.jetty.security.SecurityHandler.handle(SecurityHandler.java:216) at org.mortbay.jetty.servlet.SessionHandler.handle(SessionHandler.java:181) at org.mortbay.jetty.handler.ContextHandler.handle(ContextHandler.java:729) at org.mortbay.jetty.webapp.WebAppContext.handle(WebAppContext.java:405) at org.mortbay.jetty.handler.HandlerWrapper.handle(HandlerWrapper.java:152) at org.mortbay.jetty.handler.RequestLogHandler.handle(RequestLogHandler.java:49) at org.mortbay.jetty.handler.HandlerWrapper.handle(HandlerWrapper.java:152) at org.mortbay.jetty.Server.handle(Server.java:324) at org.mortbay.jetty.HttpConnection.handleRequest(HttpConnection.java:505) at org.mortbay.jetty.HttpConnection$RequestHandler.content(HttpConnection.java:843) at org.mortbay.jetty.HttpParser.parseNext(HttpParser.java:647) at org.mortbay.jetty.HttpParser.parseAvailable(HttpParser.java:211) at org.mortbay.jetty.HttpConnection.handle(HttpConnection.java:380) at org.mortbay.io.nio.SelectChannelEndPoint.run(SelectChannelEndPoint.java:395) at org.mortbay.thread.QueuedThreadPool$PoolThread.run(QueuedThreadPool.java:488)

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  • spring 3 mvc requestmapping dynamic param problem

    - by Faisal khan
    I have the following code which works fine with http://localhost:8080/HelloWorldSpring3/forms/helloworld but i want to have url have some thing like this http://localhost:8080/HelloWorldSpring3/forms/helloworld/locname_here/locid_here I found that adding this @RequestMapping("/helloworld/**") will work but when i try to access http://localhost:8080/HelloWorldSpring3/forms/helloworld/locname_here/locid_here it is not found. Web.xml entry as follows <servlet-mapping> <servlet-name>dispatcher</servlet-name> <url-pattern>/forms/*</url-pattern> </servlet-mapping> Mapping bean entry @RequestMapping("/helloworld/**") public ModelAndView helloWord(){ String message = "Hello World, Spring 3.0!"; return new ModelAndView("helloworld", "message",message); }

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  • How to filter and format email text and forward to customers?

    - by understack
    I get poorly formatted invoice related email from my payment gateway. I wan to automatically format these emails to make them more readbale. Mostly I want to remove few 'fixed' lines which are always present in email body. Do I need to run some sort of PHP process to do it? Is it possible to do it on email server itself? EDIT I have got cpanel access.

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  • REST/ROA Architecture - Send database search/querying/filter/sorting parameters in URL? (>, <, IN, e

    - by DutrowLLC
    I'm building a REST interface to my application using ROA (Resource Oriented Architecture) . I'd like to give the client the ability to specify search parameters in URL. So a client could say "Give me all people who's: "first_name" is equal to "BOB" "age" is greater than "30" sort by "last_name" I was thinking something like: GET /PEOPLE/{query_parameters}/{sort_parameters} ...or perhaps GET /PEOPLE?query=<query_string>&sort=<sort_string> ...but I'm unsure what syntax would be good for specifying in the COLUMN_NAME-OPERATOR-VALUE triplicates. I was thinking perhaps something like: column_name.operator.value So the client could say: GET /PEOPLE?query=first_name.EQUALS.bob&query=age.GREATER_THAN.30&sort=last_name.ASCENDING I really don't want to re-invent the wheel here, are there some accepted ways that this is done? I am using Restlets, I don't know if that makes a difference.

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  • ICEFACES : Multiple Parameters in link

    - by Carlos
    Hello ! i have a datatable with multiple rows , i want to put one link to redirect the values to one Servlet . the old call that i use is similar like this : a onclick=openWindow('./Servlet?param1=xx&param2=xxx') I m newbie in icefaces ... i want your help because i can put one parameter only like this : ice:outputLinktarget="mainFrame" value="./Servlet?param1=#{item.id} but when i put two parameters i ve errors in the code ... ice:outputLinktarget="mainFrame" value="./Servlet?param1=#{item.id}&param2=#{item.id} somebody knows to do it ? thank you very much ! Tommy

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  • Authentication with wget

    - by Llistes Sugra
    I am currently accepting the parameters login and password in my servlet, but logs are storing this info when using wget (as long as it is GET method, and apache is in the middle) Instead of this I want to enhance my servlet's authentication accepting: wget --http-user=login --http-password=password http://myhost/myServlet How can I read, in my servlet, the server side, the login and the password user is sending, in java code?

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  • Spring Security 3 - Login is not working

    - by newbie
    I use Spring Security with Spring Framework 3 and when I tyr to login from homepage I get following error: 2010-04-26 12:16:39,525 [tomcat-http--2] WARN org.springframework.web.servlet.PageNotFound - No mapping found for HTTP request with URI [/AppName/app/j_spring_security_check] in DispatcherServlet with name 'Spring MVC Dispatcher Servlet' Spring Security is initialized as loggings tell and there are no errors. So what could be reason for this error? I have understood that j_spring_security_check is default url for Spring Security login chekeing servlet.

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  • How can i filter a list of objects using lamda expression?

    - by Colour Blend
    I know i shouldn't have id's with the same value. This is just fictitious, so overlook that. I have: List<Car> carList = new List<Car>(); carList.Add(new Car() { id = 1, name = "Honda" }); carList.Add(new Car() { id = 2, name = "Toyota" }); carList.Add(new Car() { id = 1, name = "Nissan" }); I want to use Lamda Expression to retreive all cars that have an id of 1. Anticipated Result: -- Id: 1, Name: Honda -- Id: 1, Name: Nissan The problem is more filtering an object list based on a foriegn key. Please help me.

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