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  • Posting XML via curl (command-line) without using key/value pairs

    - by Mathias Bynens
    Consider a PHP script that outputs all POST data, as follows: <?php var_dump($_POST); ?> The script is located at http://example.com/foo.php. Now, I want to post XML data to it (without using key/value pairs) using command line curl. I have tried many variations of the following: curl -H "Content-type: text/xml; charset=utf-8" --data-urlencode "<foo><bar>bazinga</foo></bar>" http://example.com/foo.php Yet none of them seem to actually post anything — according to the PHP script, $_POST is just an empty array. What am I doing wrong here?

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  • JPA 2.0, hiberante 3.5, jars & persistence.xml location

    - by phmr
    I'm building a desktop application using hibernate 3.5 & JPA 2.0. I have 2 jars, the lib, which defines every entity and DAO, packages looks like this : org.my.package.models org.my.package.models.dao org.my.package.models.utils In org.my.package.utils I defined my hibernate utility class for getting EM & EMF instances, which means the lib is bound to a Persistence Unit name but that's not a problem for now (anyway you can recommend me a better way to manage that) the second jars is built as follow: org.my.package.app META-INF is defined on the root of the project which means in my jar I can find this directories directly in the root: META-INF/ META-INF/persistence.xml org/ org/my/ ... org/my/package/app/Main.class META-INF/ When I run the app, hibernate doesn't managed to find persistence.xml it throws an exception something like "package or class for PersistenceUnitName not found". I googled a bit about the problem but I can't get the source code organisation right. Any help ?

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  • Customizing Rails XML rendering to include extra properties

    - by Isaac Cambron
    Let's say I have a model like this: create_table :ninjas do |t| t.string name end And the Ninja class with an extra property: class Ninja < ActiveRecord::Base def honorific "#{name}san" end end And in my controller I just want to render it to XML: def show render :xml => Ninja.find(params[:id]) end The honorific part isn't rendered. That makes sense, since it's just a method, but is there a way of tricking it? I'm totally up for answers to the effect of, "You're doing this totally wrong." I'll just add that I really do want to calculate the honorific on the fly, and not, like, store it in the database or something.

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  • Updating Xml attributes with new values in a SQL Server 2008 table

    - by SMD
    I have a table in SQL Server 2008 that it has some columns. One of these columns is in Xml format and I want to update some attributes. For example my Xml column's name is XmlText and it's value in 5 first rows is such as: <Identification Name="John" Family="Brown" Age="30" /> <Identification Name="Smith" Family="Johnson" Age="35" /> <Identification Name="Jessy" Family="Albert" Age="60" /> <Identification Name="Mike" Family="Brown" Age="23" /> <Identification Name="Sarah" Family="Johnson" Age="30" /> and I want to change all Age attributes that are 30 to 40 such as below: <Identification Name="John" Family="Brown" Age="40" /> <Identification Name="Smith" Family="Johnson" Age="35" /> <Identification Name="Jessy" Family="Albert" Age="60" /> <Identification Name="Mike" Family="Brown" Age="23" /> <Identification Name="Sarah" Family="Johnson" Age="40" />

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  • Parsing Wiki XML Dumps ver0.4 just got tough

    - by syed
    Hello, I am trying to parse Wikipedia XML Dump using "Parse-MediaWikiDump-1.0.4" along with "Wikiprep.pl" script. I guess this script works fine with ver0.3 Wiki XML Dumps but not with the latest ver0.4 Dumps. I get the following error. Can't locate object method "page" via package "Parse::MediaWikiDump::Pages" at wikiprep.pl line 390. Also, under the "Parse-MediaWikiDump-1.0.4" documentation @ http://search.cpan.org/~triddle/Parse-MediaWikiDump-1.0.4/lib/Parse/MediaWikiDump/Pages.pm, I read "LIMITATIONS Version 0.4 This class was updated to support version 0.4 dump files from a MediaWiki instance but it does not currently support any of the new information available in those files." Any work arounds would help me get to the next level. Note: one may wonder why cannot we directly use SAX or STAX parser instead, wikipedia dump is a 25GB plus single file, stack/memory issues are obvious. Hence, the above perl script resolves this issue but currently I am stuck with this version problem.

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  • XML: Process large data

    - by Atmocreations
    Hello What XML-parser do you recommend for the following purpose: The XML-file (formatted, containing whitespaces) is around 800 MB. It mostly contains three types of tag (let's call them n, w and r). They have an attribute called id which i'd have to search for, as fast as possible. Removing attributes I don't need could save around 30%, maybe a bit more. First part for optimizing the second part: Is there any good tool (command line linux and windows if possible) to easily remove unused attributes in certain tags? I know that XSLT could be used. Or are there any easy alternatives? Also, I could split it into three files, one for each tag to gain speed for later parsing... Speed is not too important for this preparation of the data, of course it would be nice when it took rather minutes than hours. Second part: Once I have the data prepared, be it shortened or not, I should be able to search for the ID-attribute I was mentioning, this being time-critical. Estimations using wc -l tell me that there are around 3M N-tags and around 418K W-tags. The latter ones can contain up to approximately 20 subtags each. W-Tags also contain some, but they would be stripped away. "All I have to do" is navigating between tags containing certain id-attributes. Some tags have references to other id's, therefore giving me a tree, maybe even a graph. The original data is big (as mentioned), but the resultset shouldn't be too big as I only have to pick out certain elements. Now the question: What XML parsing library should I use for this kind of processing? I would use Java 6 in a first instance, with having in mind to be porting it to BlackBerry. Might it be useful to just create a flat file indexing the id's and pointing to an offset in the file? Is it even necessary to do the optimizations mentioned in the upper part? Or are there parser known to be quite as fast with the original data? Little note: To test, I took the id being on the very last line on the file and searching for the id using grep. This took around a minute on a Core 2 Duo. What happens if the file grows even bigger, let's say 5 GB? I appreciate any notice or recommendation. Thank you all very much in advance and regards

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  • Caching the xml response from a HttpHandler

    - by Blankman
    My HttpHandler looks like: public void ProcessRequest(HttpContext context) { context.Response.ContentType = "text/xml"; XmlWriter writer = new XmlTextWriter(context.Response.OutputStream, Encoding.UTF8); writer.WriteStartDocument(); writer.WriteStartElement("ProductFeed"); DataTable dt = GetStuff(); for(...) { } writer.WriteEndElement(); writer.WriteEndDocument(); writer.Flush(); writer.Close(); } How can I cache the entire xml document that I am generating? Or do I only have the option of caching the DataTable object?

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  • phantom error "error parsing XML: unbound prefix"

    - by Brad Hein
    The error "error parsing XML: unbound prefix" shows up on my main layout: main.xml when I first open Eclipse. To make the error go away, all I have to do is make a modification to the file, then undo it, then hit save (have to make a change in order to be able to save file and thus trigger the new syntax check). My environment is: Fedora Eclipse Platform Version: 3.4.2 Based on build id: 20090211-1700 My target is Android API level 5. The first time I saw the error I spent a long time trying to track down "the problem" but later realized there isn't really a problem, it's just a phantom error. Screenshot: http://i50.tinypic.com/2i89iee.jpg Who should I report this to?

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  • Getting an XML node using LINQ

    - by MarceloRamires
    Somehow, using linq I can't test it with this CUF field in the beginning: <NFe> <infNFe versao="1.0" Id="NFe0000000000"> <ide> <cUF>35</cUF> <!--...--> </ide> </NFe> With the following code: XDocument document = XDocument.Load(@"c:\nota.xml"); var query = from NFe in document.Descendants("NFe") select new { cuf = NFe.Element("infNFe").Element("ide").Element("cUF").Value }; The whole XML loads into document (checked) but NFe.cuf gives me nothing. I guess the parameters inside the nodes are messing it up.. How do I get this "cuf" with linq? What if I wanted the Id parameter in infNFe ?

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  • Legally use CDATA in XML

    - by idazuwaika
    Hi, I have an XML file which XML parser choke on. A part of it is : <closedDeal><customer><![CDATA[ABC ]]></customer></closedDeal> The error I got is The literal string ']]>' is not allowed in element content. Error processing resource What is the correct way of using CDATA? I need CDATA because the data is read from Excel, and could contain illegal character such as ALT+ENTER whitespace. Please help. Thanks.

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  • How to parse org.w3c.dom.Element RPX XML response

    - by Kenshin
    I am using rpxnow in Java, how do I use org.w3c.dom API to get the field identifier in this XML reponse for example? <?xml version='1.0' encoding='UTF-8'?> <rsp stat='ok'> <profile> <displayName> brian </displayName> <identifier> http://brian.myopenid.com/ </identifier> <preferredUsername> brian </preferredUsername> <providerName> Other </providerName> <url> http://brian.myopenid.com/ </url> </profile> </rsp>

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  • Del.icio.us get xml of all posts

    - by Marvin
    Im trying to get all of my posts in a delicious account to an MySql DB. Since delicious exports xml I think it wont be too complicated, but being new to it I cant really make sense of the api... I believe I have to query it as so: https://api.del.icio.us/v1/posts/all? But one catch is that im using an yahoo id for that account which I need to do it as follows: "To access data from accounts created using a Yahoo! ID, use the same API's as below, but change the path to /v2, and make HTTP requests using OAuth as provided by the Yahoo! Developer Network." I cant understand how to do it, can someone please help. Thanks. EDIT Although I still have the same doubt I figured out I can export the whole thing from the settings in my account, now I just need to get the html export in a xml file :) Also the yahoo method for accessing data, really is no good.

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  • Java .split() Method To Split XML Parameters

    - by Buzz Lightyear
    I have this line from an XML document: <?xml version="1.0" encoding="UTF-8"?> <svg xmlns:xlink="http://www.w3.org/1999/xlink" xmlns="http://www.w3.org/2000/svg" contentScriptType="text/ecmascript" width="1024" zoomAndPan="magnify" contentStyleType="text/css" viewBox="0 0 1024 768" height="768" preserveAspectRatio="xMidYMid meet" version="1.0"> I want to be able to split it up, using the split method. For example i want to save each parameter into a String array. So i'd like: contentScriptType="text/ecmascript" width="1024" zoomAndPan="magnify" contentStyleType="text/css" viewBox="0 0 1024 768" height="768" etc etc to be saved into a string array, is there anyway to do this using the split method, or can anybody suggest an easier, more efficient way to do this?

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  • Linq to SQL Web Service XML

    - by Bryan
    I built a .NET web service connecting to an MSSQL database. There is a web service call GetAllQuestions() that will not change. I saved the result of GetAllQuestions to GetAllQuestions.xml in the local application folder and set it to content. Normally I would get the result of the web service like this: var myService = new SATService(); var serviceQuestions = myService.GetAllQuestions(); I want to try something like: var serviceQuestions = File.Open("GetAllQuestions.xml"); Any suggestions are much appreciated!

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  • Automating scraping of table data to XML

    - by thewinchester
    Problem I have a YQL query result that I'm trying to get converted and sort into a clean XML file. Background Being the pains that they are, information from the World Cup isn't freely available in an easy to reuse format. So, after a bit of finessing with YQL I have managed to liberate the required table rows which contain the data I'm after. The YQL query can be viewed at: http://query.yahooapis.com/v1/public/yql/ravingbeefsteak/worldcup2010groupliberator?diagnostics=true I'd like to now convert this information into XML, and being an absolute n00b I don't know where to start or what to look for. I'm also needing to do a find and replace on the data to get the URL's working as they should without manual changes, and hopefully an initial sorting of the data. If anyone can point me in the right direction of what I need to be doing to make my needs a reality it would be greatly appreciated.

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  • Creating an XML sitemap with PHP

    - by iMaster
    I'm trying to create a sitemap that will automatically update. I've done something similiar with my RSS feed, but this sitemap refuses to work. You can view it live at http://designdeluge.com/sitemap.xml I think the main problem is that its not recognizing the PHP code. Here's the full source: <?php header('Content-type: text/xml'); ?> <?xml version="1.0" encoding="UTF-8" ?> <urlset xmlns="http://www.google.com/schemas/sitemap/0.84" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.google.com/schemas/sitemap/0.84 http://www.google.com/schemas/sitemap/0.84/sitemap.xsd"> <url> <loc>http://www.designdeluge.com/</loc> <lastmod>2010-04-29</lastmod> <changefreq>daily</changefreq> <priority>1.00</priority> </url> <url> <loc>http://www.designdeluge.com/archives</loc> <lastmod>2010-04-29</lastmod> <changefreq>daily</changefreq> <priority>0.5</priority> </url> <url> <loc>http://www.designdeluge.com/about.php</loc> <lastmod>2010-04-29</lastmod> <changefreq>daily</changefreq> <priority>0.5</priority> </url> <?php include 'connection.php'; $entries = mysql_query("SELECT * FROM Entries ORDER BY timestamp DESC"); while($row = mysql_fetch_array($entries)) { $title = stripslashes($row['title']); $date = date("Y-m-d", strtotime($row['timestamp'])); ?> <url> <loc>http://www.designdeluge.com/<?php echo $row['title']; ?></loc> <lastmod><?php echo $date; ?></lastmod> <changefreq>none</changefreq> <priority>0.5</priority> </url> <?php } ?> </urlset> The problem is that the dynamic URL's (e.g. the ones pulled from the DB) aren't being generated and the sitemap won't validate. Thanks!

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  • Format XML with JAXB during unmarshal

    - by Tobiask
    Hi there, I want to format a XML document during unmarshal with JAXB. Unmarshal looks like: Unmarshaller u = createAndsetUpUnmarshaller(enableValidation, evtHandler, clazz); return u.unmarshal(new ByteArrayInputStream(stringSource.getBytes())); While marshaling one can format the code via: marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, Boolean.TRUE); But this isn´t possible for the unmarchal process... Any idea how I can format the XML string with JAXB during (or after) unmarshal process? BTW: I read some posts here about pretty print, but I want to do it with JAXB!

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  • Changing Element Value in Existing XML File Using DOM

    - by rylic38
    Hi All, I am trying to find examples of how to change an existing xml files Element Value. Using the following xml example: <book> <title>My Book</title> <author>John Smith</author> </book> If I wanted to replace the author element value 'John Smith' with 'Jim Johnson' in a Python script using DOM, how would I go about doing so? I've tried to look for examples on this, but have failed in doing so. Any help would be greatly appreciated. Regards, Rylic

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  • Error loading contents from a XML file into a dropdownlist

    - by Chaitanya
    private void BindCountry() { XmlDocument doc = new XmlDocument(); doc.Load(Server.MapPath("countries.xml")); foreach (XmlNode node in doc.SelectNodes("//country")) { usrlocationddl.Items.Add(new ListItem(node.InnerText, node.Attributes["codes"].InnerText)); //ddlCountry.Items.Add(new ListItem(node.InnerText, node.Attributes["code"].InnerText)); } } The above code am using for loading countries List from an xml file into a dropdown list. But while doing so am encountering a Null Reference error. Object reference not set to an instance of an object. Where in the code should I be changing, so that I can escape the error.

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  • Parsing XML feed into Ruby object using nokogiri?

    - by Galen King
    Hi all, I am pretty green with coding in Ruby but am trying to pull an XML feed into a Ruby object as follows (ignore the ugly code please): <% doc = Nokogiri::XML(open("http://api.workflowmax.com/job.api/current?apiKey=#{@feed.service.api_key}&accountKey=#{@feed.service.account_key}")) %> <% doc.xpath('//Jobs/Job').each do |node| %> <h2><%= node['name'].text %></h2> <p><%= node['description'].text %></p> <% end %> Basically I want to iterate through each Job and output the name, description etc. What am I missing? Many thanks, Galen

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  • XML Postback issue

    - by Mikey1980
    I have a script that is designed to parse XML postbacks from Ultracart, right now just dumps it into a MySQL table. The script works fine if I point it to a XML file on my localhost but using 'php://input' it doesn't seem to grabbing anything. My logs show apache returning 200 after the post so I have no idea what could be wrong or how to drill down the issue.. here's the code: $doc = new DOMDocument(); $doc->loadXML($page); $handle = fopen("test2/".time().".xml", "w+"); fwrite($handle,trim($page)); // it doesn't save this either :'( fclose(); require_once('includes/database.php'); $db = new Database('localhost', 'user', 'password', 'db_name'); $data = array(); $exports = $doc->getElementsByTagName("export"); foreach ($exports as $export) { $orders = $export->getElementsByTagName("order"); foreach($orders as $order) { $data['order_id'] = $order->getElementsByTagName("order_id")->item(0)->nodeValue; $data['payment_status'] = $order->getElementsByTagName("payment_status")->item(0)->nodeValue; $date_array = explode(" ",$order->getElementsByTagName("payment_date_time")->item(0)->nodeValue); if ($date_array[1] == 'JAN') { $date_array[1] = '01'; } if ($date_array[1] == 'FEB') { $date_array[1] = '02'; } if ($date_array[1] == 'MAR') { $date_array[1] = '03'; } if ($date_array[1] == 'APR') { $date_array[1] = '04'; } if ($date_array[1] == 'MAY') { $date_array[1] = '05'; } // converts Ultracart date to if ($date_array[1] == 'JUN') { $date_array[1] = '06'; } // MySQL date if ($date_array[1] == 'JUL') { $date_array[1] = '07'; } if ($date_array[1] == 'AUG') { $date_array[1] = '08'; } if ($date_array[1] == 'SEP') { $date_array[1] = '09'; } if ($date_array[1] == 'OCT') { $date_array[1] = '10'; } if ($date_array[1] == 'NOV') { $date_array[1] = '11'; } if ($date_array[1] == 'DEC') { $date_array[1] = '12'; } $data['payment_date'] = $date_array[2]."-".$date_array[1]."-".$date_array[0]; $data['payment_time'] = $date_array[3]; //... we'll skip this, there are 80 some elements $data['discount'] = $order->getElementsByTagName("discount")->item(0)->nodeValue; $data['distribution_center_code'] = $order->getElementsByTagName("distribution_center_code")->item(0)->nodeValue; } } } $db->insert('order_history',$data); } else die('ERROR: Token Check Failed!');

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  • How to simple parse xml in c#

    - by dzajdol
    I want parse a SOAP xml response in C# (but I can't use standard SOAP interface, because wsld is incorrect). When I parsing I want to have all elements with name (list element with name) and access to all its children. The overall appearance of the XML: <return> <item> <attr1>1</attr1> <attr2>X</attr2> </item> <item> <attr1>2</attr1> <attr2>Y</attr2> </item> ... </return> Regards

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  • Restructure XML nodes using XSLT

    - by Brian
    Looking to use XSLT to transform my XML. The sample XML is as follows: <root> <info> <firstname>Bob</firstname> <lastname>Joe</lastname> </info> <notes> <note>text1</note> <note>text2</note> </notes> <othernotes> <note>text3</note> <note>text4</note> </othernotes> I'm looking to extract all "note" elements, and have them under a parent node "notes". The result I'm looking for is as follows: <root> <info> <firstname>Bob</firstname> <lastname>Joe</lastname> </info> <notes> <note>text1</note> <note>text2</note> <note>text3</note> <note>text4</note> </notes> </root> The XSLT I attempted to use is allowing me to extract all my "note", however, I can't figure out how I can wrap them back within a "notes" node. Here's the XSLT I'm using: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output omit-xml-declaration="yes" indent="yes"/> <xsl:template match="notes|othernotes"> <xsl:apply-templates select="note"/> </xsl:template> <xsl:template match="*"> <xsl:copy><xsl:apply-templates/></xsl:copy> </xsl:template> </xsl:stylesheet> The result I'm getting with the above XSLT is: <root> <info> <firstname>Bob</firstname> <lastname>Joe</lastname> </info> <note>text1</note> <note>text2</note> <note>text3</note> <note>text4</note> </root> Thanks

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  • Displaying an XML DataSource

    - by Kubi
    Hi, I have an xml data file and I want to populate a listview in asp.net with this file. Can you show me how to generate an xslt and make a xml data file for this ? Thanks <Projects> <Project Name="" Category="" Subcategory=""> <Subheader></Subheader> <Thumbnail></Thumbnail> <CreateDate></CreateDate> <Explanation></Explanation> <PdfFile></PdfFile> <WordFile></WordFile> <Subheader></Subheader> <SlideShow> <Image></Image> <Image></Image> </SlideShow> </Project> </Projects>

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