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  • Ensure a new session every time the user connects to a Servlet

    - by Daziplqa
    Hi, I've a JSP/Servlet Web App that consist of more than one servlet (and some JSPs) I need to create an new HttpSession whenever the users access servlet A, knowing that, servlet A is the home page (i.e. he access it as the first servlet/page in the application) so far so good, I can write the following code at the start of the servlet A: HttpSession session = request.getSession(false); if (session == null) { logger.debug("starting new session..."); session = request.getSession(); // other staff here } But the problem is, if the user didn't close his browser (even if he closes the tab - in firefox for instance - the session will still be open), so when he try to open my site again, the last session will be re-used (in the rage of session timeout ofcourse), and this I don't need. I need whenever he access Servlet A, he got created a brand new HttpSession. but unfortunately, he may access this servlet twice per session based on some scenario!! Please help.

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  • Getting message in android app: Binary XML file line #2: You must supply a layout_width attribute.

    - by opike
    I'm trying to use a ListView inside of a RelativeLayout but when I run my app I get a runtimeexception with the message: Binary XML file line #2: You must supply a layout_width attribute. I tried putting layout_width attributes in every conceivable place in the xml resource files but so far no luck. I attempt to populate the listview with this line of code: setListAdapter(new ArrayAdapter(this, R.layout.tablerow3, R.id.label, items)); Here's the tablerow3.xml contents: <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"> android:layout_width="20dp" android:layout_height="5dp" android:id="@+id/tablerow01"> <Label android:id="@+id/label01" android:layout_width="5dp" android:layout_height="5dp" android:textColor="@color/solid_white" android:singleLine="true"/> <Label android:id="@+id/label02" android:layout_width="5dp" android:layout_height="5dp" android:textColor="@color/solid_white" android:singleLine="true"/> </LinearLayout> Here's the xml that contains the RelativeLayout(forex2.xml): <?xml version="1.0" encoding="utf-8"?> <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="fill_parent"> <Button android:text="Static Button" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_alignParentLeft="true" android:layout_alignParentTop="true" android:id="@+id/button_id"> </Button> <Spinner android:id="@+id/spinner1" android:layout_width="match_parent" android:layout_toRightOf="@id/button_id" android:layout_alignParentTop="true" android:layout_height="wrap_content" android:drawSelectorOnTop="true" /> <ListView android:id="@android:id/list" android:layout_width="5dp" android:layout_height="5dp" android:layout_alignParentBottom="true" /> <!-- android:layout_width="wrap_content" android:layout_height="wrap_content" --> </RelativeLayout>

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  • Better to build or buy a compute grid platform?

    - by James B
    I am looking to do some quite processor-intensive brute force processing for string matching. I have run my prototype in a multi-threaded environment and compared the performance to an implementation using Gridgain with a couple of nodes (also multithreaded). The performance I observed was that my Gridgain implementation performed slower to my multithreaded implementation. It could be the case that there was a flaw in my gridgain implementation, but it was only a prototype, and I thought the results were indicative. So my question is this: What are the advantages of having to learn and then build an implementation for a particular grid platform (hadoop, gridgain, or EC2 if going hosted - other suggestions welcome), when one could fairly easily put together a lightweight compute grid platform with a much shallower learning curve?...i.e. what do we get for free with these cloud/grid platforms that are worth having/tricky to implement? (Please note, I don't have any need for a data grid) Cheers, -James (p.s. Happy to make this community wiki if needbe)

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  • Android application transparency and window sizing at root level

    - by ajoburg
    Is it possible to create an application with a transparent background on the root task such that you can see the task running beneath it when it is part of a separate stack? Alternatively, is it possible to run an application so the window of the root task is only a portion of the screen instead of the whole screen? I understand how the transparency and window sizing is done with activities that are not the root task and this works fine. However, the root task of an activity seems to always fill the whole screen and be black even when a transparent theme is applied to the application object in the manifest file. ApplicationManifest.xml: <application android:icon="@drawable/icon" android:label="@string/app_name" android:debuggable="true" android:theme="@style/Theme.Transparent"> Styles.xml <resources> <style name="Theme.Transparent"> <item name="android:windowIsTranslucent">true</item> <item name="android:windowNoTitle">true</item> <item name="android:windowBackground">@drawable/ transparent_background</item> <item name="android:windowAnimationStyle">@android:style/ Animation.Translucent</item> <item name="android:colorForeground">#fff</item> <item name="android:windowIsFloating">true</item> <item name="android:gravity">bottom</item> </style> </resources> Colors.xml <resources> <drawable name="transparent_background">#00000000</drawable> </resources>

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  • Calling web services from your JSF code

    - by Abel Morelos
    Let's say that you have a presentation tier in JSF, and that your business tier is accessed using web services. How would you call your web services from JSF? I was considering to have my backing beans to call the web services, but I just though I could use Ajax with JSF in order to connect to the web services. What would you choose and why? Any other choice you could recommend? Thanks.

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  • using JMock to write unit test for a simple spring JDBC DAO

    - by Quincy
    I'm writing an unit test for spring jdbc dao. The method to test is: public long getALong() { return simpleJdbcTemplate.queryForObject("sql query here", new RowMapper<Long>() { public Long mapRow(ResultSet resultSet, int i) throws SQLException { return resultSet.getLong("a_long"); } }); } Here is what I have in the test: public void testGetALong() throws Exception { final Long result = 1000L; context.checking(new Expectations() {{ oneOf(simpleJdbcTemplate).queryForObject("sql_query", new RowMapper<Long>() { public Long mapRow(ResultSet resultSet, int i) throws SQLException { return resultSet.getLong("a_long"); } }); will(returnValue(result)); }}); Long seq = dao.getALong(); context.assertIsSatisfied(); assertEquals(seq, result); } Naturally, the test doesn't work (otherwise, I wouldn't be asking this question here). The problem is the rowmapper in the test is different from the rowmapper in the DAO. So the expectation is not met. I tried to put with around the sql query and with(any(RowMapper.class)) for the rowmapper. It wouldn't work either, complains about "not all parameters were given explicit matchers: either all parameters must be specified by matchers or all must be specified by values, you cannot mix matchers and values"

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  • How can I turn a string of text into a BigInteger representation for use in an El Gamal cryptosystem

    - by angstrom91
    I'm playing with the El Gamal cryptosystem, and my goal is to be able to encipher and decipher long sequences of text. I have come up with a method that works for short sequences, but does not work for long sequences, and I cannot figure out why. El Gamal requires the plaintext to be an integer. I have turned my string into a byte[] using the .getBytes() method for Strings, and then created a BigInteger out of the byte[]. After encryption/decryption, I turn the BigInteger into a byte[] using the .toByteArray() method for BigIntegers, and then create a new String object from the byte[]. This works perfectly when i call ElGamalEncipher with strings up to 129 characters. With 130 or more characters, the output produced is garbled. Can someone suggest how to solve this issue? Is this an issue with my method of turning the string into a BigInteger? If so, is there a better way to turn my string of text into a BigInteger and back? Below is my encipher/decipher code. public static BigInteger[] ElGamalEncipher(String plaintext, BigInteger p, BigInteger g, BigInteger r) { // returns a BigInteger[] cipherText // cipherText[0] is c // cipherText[1] is d BigInteger[] cipherText = new BigInteger[2]; BigInteger pText = new BigInteger(plaintext.getBytes()); // 1: select a random integer k such that 1 <= k <= p-2 BigInteger k = new BigInteger(p.bitLength() - 2, sr); // 2: Compute c = g^k(mod p) BigInteger c = g.modPow(k, p); // 3: Compute d= P*r^k = P(g^a)^k(mod p) BigInteger d = pText.multiply(r.modPow(k, p)).mod(p); // C =(c,d) is the ciphertext cipherText[0] = c; cipherText[1] = d; return cipherText; } public static String ElGamalDecipher(BigInteger c, BigInteger d, BigInteger a, BigInteger p) { //returns the plaintext enciphered as (c,d) // 1: use the private key a to compute the least non-negative residue // of an inverse of (c^a)' (mod p) BigInteger z = c.modPow(a, p).modInverse(p); BigInteger P = z.multiply(d).mod(p); byte[] plainTextArray = P.toByteArray(); String output = null; try { output = new String(plainTextArray, "UTF8"); } catch (Exception e) { } return output; }

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  • Spring - SessionAttribute problem

    - by Max
    Hello, I want to implement something like this: @Controller @SessionAttributes("promotion") class PromotionController { @RequestMapping("showPromo") void showPromotionInfo( @RequestParam("promId") String promotionId, @ModelAttribute Promotion promotion, Errors errors ) { promotion = Promotions.get(promotionId); if (promotion == null || promotion.validates() == false) { errors.reject("promotion.invalid"); } return "prom"; } } The code is invalid, wont work and has some bad errors, but I don't know how to write it better. When user comes to an URL "showPromo?promId=15", controller should validate if the promotion is valid (outdated/non-existent/etc.). If it is valid - it should show it's information and save the promotion to model and session. If it's not - it should show some error about promotion being invalid. Problem is, I need to save the promotion in the session (for several requests) and don't want to use direct session management. Is it currently possible with Spring? Or am I doing something wrong? Could you please provide the optimal solution to my problem using Spring 3? Thanks in advance.

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  • hibernate column uniqueness question

    - by Seth
    I'm still in the process of learning hibernate/hql and I have a question that's half best practices question/half sanity check. Let's say I have a class A: @Entity public class A { @Id @GeneratedValue(strategy=GenerationType.AUTO) private Long id; @Column(unique=true) private String name = ""; //getters, setters, etc. omitted for brevity } I want to enforce that every instance of A that gets saved has a unique name (hence the @Column annotation), but I also want to be able to handle the case where there's already an A instance saved that has that name. I see two ways of doing this: 1) I can catch the org.hibernate.exception.ConstraintViolationException that could be thrown during the session.saveOrUpdate() call and try to handle it. 2) I can query for existing instances of A that already have that name in the DAO before calling session.saveOrUpdate(). Right now I'm leaning towards approach 2, because in approach 1 I don't know how to programmatically figure out which constraint was violated (there are a couple of other unique members in A). Right now my DAO.save() code looks roughly like this: public void save(A a) throws DataAccessException, NonUniqueNameException { Session session = sessionFactory.getCurrentSession(); try { session.beginTransaction(); Query query = null; //if id isn't null, make sure we don't count this object as a duplicate if(obj.getId() == null) { query = session.createQuery("select count(a) from A a where a.name = :name").setParameter("name", obj.getName()); } else { query = session.createQuery("select count(a) from A a where a.name = :name " + "and a.id != :id").setParameter("name", obj.getName()).setParameter("name", obj.getName()); } Long numNameDuplicates = (Long)query.uniqueResult(); if(numNameDuplicates > 0) throw new NonUniqueNameException(); session.saveOrUpdate(a); session.getTransaction().commit(); } catch(RuntimeException e) { session.getTransaction().rollback(); throw new DataAccessException(e); //my own class } } Am I going about this in the right way? Can hibernate tell me programmatically (i.e. not as an error string) which value is violating the uniqueness constraint? By separating the query from the commit, am I inviting thread-safety errors, or am I safe? How is this usually done? Thanks!

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  • alternatedocroot

    - by ring bearer
    Using Sun Glassfish Enterprise server v2.1.1 I am using "alternatedocroot" via sun-web.xml for my web application to abstract out static content from actual deploy-able code (EAR/WAR) What I have is a cluster of two server instances distributed across two physical hosts - HOST1 and HOST2. "alternatedocroot" points to /data/static-content/ on both HOST1 and HOST2. Would DAS (Domain application server )take care of syncing /data/static-content between HOST1 and HOST2 if I use syncinstances=true option while starting up the cluster? Thanks!

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  • best way to pick a random subset from a collection?

    - by Tom
    I have a set of objects in a Vector from which I'd like to select a random subset (e.g. 100 items coming back; pick 5 randomly). In my first (very hasty) pass I did an extremely simple and perhaps overly clever solution: Vector itemsVector = getItems(); Collections.shuffle(itemsVector); itemsVector.setSize(5); While this has the advantage of being nice and simple, I suspect it's not going to scale very well, i.e. Collections.shuffle() must be O(n) at least. My less clever alternative is Vector itemsVector = getItems(); Random rand = new Random(System.currentTimeMillis()); // would make this static to the class List subsetList = new ArrayList(5); for (int i = 0; i < 5; i++) { // be sure to use Vector.remove() or you may get the same item twice subsetList.add(itemsVector.remove(rand.nextInt(itemsVector.size()))); } Any suggestions on better ways to draw out a random subset from a Collection?

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  • httpClient proxy support in apache commons 3.1

    - by user1173339
    I am using apache commons 3.1 to implement httpClient with proxy support. I am trying to connect to a remote host through proxy. The proxy server is configured without any authentication, however the the remote host is configured with authentication. When I am passing the proxy parameters through properties file, it gives warning while execution: WARN - Required proxy credentials not available for BASIC @xx.xx.xx.xx WARN - Preemptive authentication requested but no default proxy credentials availble But the execution goes ahead. On the other hand when I am passing the proxy parameters through the JVM arguments then the again the same warning is given and the execution is stopped. Is there any specific reason for this behavior? Is there any difference in passing the proxy parameters through properties file and through JVM arg? Here is the code: if(System.getProperty("http.proxyHost") != null && System.getProperty("http.proxyPort") != null) { httpClient.getHostConfiguration().setProxy(System.getProperty("http.proxyHost"), Integer.parseInt(System.getProperty("http.proxyPort"))); } else if(AMXAdminTask.props.getProperty("http.proxyHost") != null && AMXAdminTask.props.getProperty("http.proxyPort") != null) { httpClient.getHostConfiguration().setProxy(Propfile.props.getProperty("http.proxyHost"), Integer.parseInt(Propfile.props.getProperty("http.proxyPort"))); }

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  • Android: Can not send http post

    - by jpartogi
    Hi all, I've been banging my head trying to figure out how to send a post method in Android. This is how my code look like: public class HomeActivity extends Activity implements OnClickListener { private TextView textView; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); textView = (TextView) findViewById(R.id.text); Button button = (Button)findViewById(R.id.button); button.setOnClickListener(this); } @Override public void onClick(View view) { HttpPost httpMethod = new HttpPost("http://www.example.com/"); httpMethod.addHeader("Accept", "text/html"); httpMethod.addHeader("Content-Type", "application/xml"); AndroidHttpClient client = AndroidHttpClient.newInstance("Android"); String result = null; try { HttpResponse response = client.execute(httpMethod); textView.setText(response.toString()); HttpEntity entity = response.getEntity(); Log.i(HomeActivity.class.toString(), result); textView.setText("Invoked webservice"); } catch (IOException e) { e.printStackTrace(); Log.e(HomeActivity.class.toString(), e.getMessage()); textView.setText("Something wrong:" + e.getMessage()); } } } What am I doing wrong here? Is there anything that I may need to configure from the Android emulator to get this working? Thank you for your help.

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  • Expandable listview Refreshing

    - by Sam97305421562
    Hi, I am using expandable listview i need to refresh as i am searching the list only for parent.I have searched for tutorial in which i can set visibility only for some parent but not all the expandable listview object . Thanks in advance.

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  • Socket server with multiple clients, sending messages to many clients without hurting liveliness

    - by Karl Johanson
    I have a small socket server, and I need to distribute various messages from client-to-client depending on different conditionals. However I think I have a small problem with livelyness in my current code, and is there anything wrong in my approach: public class CuClient extends Thread { Socket socket = null; ObjectOutputStream out; ObjectInputStream in; CuGroup group; public CuClient(Socket s, CuGroup g) { this.socket = s; this.group = g; out = new ObjectOutputStream(this.socket.getOutputStream()); out.flush(); in = new ObjectInputStream(this.socket.getInputStream()); } @Override public void run() { String cmd = ""; try { while (!cmd.equals("client shutdown")) { cmd = (String) in.readObject(); this.group.broadcastToGroup(this, cmd); } out.close(); in.close(); socket.close(); } catch (Exception e) { System.out.println(this.getName()); e.printStackTrace(); } } public void sendToClient(String msg) { try { this.out.writeObject(msg); this.out.flush(); } catch (IOException ex) { } } And my CuGroup: public class CuGroup { private Vector<CuClient> clients = new Vector<CuClient>(); public void addClient(CuClient c) { this.clients.add(c); } void broadcastToGroup(CuClient clientName, String cmd) { Iterator it = this.clients.iterator(); while (it.hasNext()) { CuClient cu = (CuClient)it.next(); cu.sendToClient(cmd); } } } And my main-class: public class SmallServer { public static final Vector<CuClient> clients = new Vector<CuClient>(10); public static boolean serverRunning = true; private ServerSocket serverSocket; private CuGroup group = new CuGroup(); public void body() { try { this.serverSocket = new ServerSocket(1337, 20); System.out.println("Waiting for clients\n"); do { Socket s = this.serverSocket.accept(); CuClient t = new CuClient(s,group); System.out.println("SERVER: " + s.getInetAddress() + " is connected!\n"); t.start(); } while (this.serverRunning); } catch (IOException ex) { ex.printStackTrace(); } } public static void main(String[] args) { System.out.println("Server"); SmallServer server = new SmallServer(); server.body(); } } Consider the example with many more groups, maybe a Collection of groups. If they all synchronize on a single Object, I don't think my server will be very fast. I there a pattern or something that can help my liveliness?

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  • Call methods in main method

    - by Niloo
    this is my main method that gets 3 integers from command line and I parse then in my validating method. However I have one operation method that calls 3 other methods, but i don't know what type of data and howmany I have to put in my operatinMethod() " cuase switch only gets one); AND also in my mainMethod() for calling the operationMehod(); itself? please let me know if i'm not clear? Thanx! main method: public class test { // Global Constants final static int MIN_NUMBER = 1; final static int MAX_PRIME = 10000; final static int MAX_FACTORIAL = 12; final static int MAX_LEAPYEAR = 4000; //Global Variables static int a,b,c; public static void main (String[] args) { for(int i =0; i< args.length; i++){} if(validateInput(args[0],args[1],args[2])){ performOperations(); } } //Validate User Input public static boolean validateInput(String num1,String num2,String num3){ boolean isValid = false; try{ try{ try{ a = Integer.parseInt(num1); if(!withinRange(a,MIN_NUMBER, MAX_PRIME)) { System.out.println("The entered value " + num1 +" is out of range [1 TO 10000]."); } isValid = true; } catch(Exception ex) { System.out.println("The entered value " + num1 + " is not a valid integer. Please try again."); } b = Integer.parseInt(num2); if(!withinRange(b,MIN_NUMBER, MAX_FACTORIAL)) { System.out.println("The entered value " + num2 +" is out of range [1 TO 12]."); } isValid = true; } catch(Exception ex) { System.out.println("The entered value " + num2 + " is not a valid integer. Please try again."); } c = Integer.parseInt(num3); if(!withinRange(c,MIN_NUMBER, MAX_LEAPYEAR)) { System.out.println("The entered value " + num3 +" is out of range [1 TO 4000]."); } isValid = true; } catch(Exception ex) { System.out.println("The entered value " + num3 + " is not a valid integer. Please try again."); } return isValid; } //Check the value within the specified range private static boolean withinRange(int userInput ,int min, int max){ boolean isInRange = true; if(userInput < min || userInput > max){ isInRange = false; } return isInRange; } //Perform operations private static void performOperations(int userInput) { switch(userInput) { case 1: // count Prime numbers countPrimes(a); break; case 2: // Calculate factorial getFactorial(b); break; case 3: // find Leap year isLeapYear(c); break; } } // Verify Prime Number private static boolean isPrime(int prime) { for(int i = 2; i <= Math.sqrt(prime) ; i++) { if ((prime % i) == 0) { return false; } } return true; } // Calculate Prime private static int countPrimes(int userInput){ int count =0; for(int i=userInput; i<=MAX_PRIME; i++) { if(isPrime(i)){ count++; } } System.out.println("Exactly "+ count + " prime numbers exist between "+ a + " and 10,000."); return count; } // Calculate the factorial value private static int getFactorial(int userInput){ int ans = userInput; if(userInput >1 ){ ans*= (getFactorial(userInput-1)); //System.out.println("The value of "+ b +"! is "+ getFactorial(userInput)); } return ans; } // Determine whether the integer represents a leap year private static boolean isLeapYear(int userInput){ if (userInput % 4 == 0 && userInput % 400 == 0 && userInput % 100 ==0){ System.out.println("The year "+ c +" is a leap year"); } else { System.out.println("The year "+ c +" is a not leap year"); } return false; } }

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  • Frame Showing Problem

    - by Nitz
    Hey Guys I have made one project which is showing the inventory of the stock of one store. In that inventory the software should store data of the products with their images. There is one problem... Bcz of the lots of stock, the screen on which is image is loading taking a lot of time. So, i thought i should give the frame in which there will be on label which will show the "Loading Software". But now when i am setting visible = true for that frame, but bcz of that images screen class loading problem my frame is not showing correctly. I have put screen shot, now my code. JFrame f; try{ f = new JFrame("This is a test"); f.setSize(300, 300); Container content = f.getContentPane(); content.setBackground(Color.white); content.setLayout(new FlowLayout()); JLabel jl = new JLabel(); jl.setText("Loading Please Wait...."); content.add(jl); f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); f.setVisible(true); }catch(Exception e){ e.printStackTrace(); } initComponents(); try { addInverntory = new AddInventoryScreen(); showstock = new showStock(); // this class will take big time. mf = new mainForm(); f.setVisible(false); }catch (Exception ex) { ex.printStackTrace(); } How Can show some message that, other class is loading or "Loading Software" kind of thing in this situation. Just For the know....this class is not screen on which the image will load.

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  • Paging of images in blackberry

    - by Maneesh
    How to display images in the form of pages where only one page is displayed at a time on blackberry screen. On scrolling down subsequent images will load at run time. So that loading of images do not consume time at startup.

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