Search Results

Search found 59353 results on 2375 pages for 'class instance variables'.

Page 73/2375 | < Previous Page | 69 70 71 72 73 74 75 76 77 78 79 80  | Next Page >

  • SQL Server instance shuts down

    - by user42119
    I'm currently developing a new ASP.NET project hosted on a Windows Server 2008 RC2 with an SQL Server 2008 Express database. I have three SQL Server instances (for different purposes) running which currently all contain a single database. For apparently no reason, these instances tend to shut down after some days. There might be low or no traffic to these instances, because there might be some days in a row, where I can't develop. It now occurred several times, that one or two of these three instances just shut down, so that I can't access the database, without manually starting the instance. I can't seem to find a event log entry for the shutdown, which is most likely because I just enabled logging (why is the default setting off?). So the questions are: * Why does an SQL Server instance shut down? (Is there such a thing as a "Shut down instance after 3 days of inactivity"? * How can I achieve that the instances are running 24/7? Edit: I solved this problem by writing my own application that checks for the status of the SQL Server services. My program will start via a batch file, that gets called by the Windows Task Scheduler every 5 minutes.

    Read the article

  • Installing sqlite gem fails on AWS Linux instance with sqlite-devel libraries installed

    - by Scott
    Hi, I'm running an instance built off ami-595a0a1c. I am trying to install the sqlite3 (or sqlite) gem and it's failing with the below error: $ sudo gem install sqlite3 Building native extensions. This could take a while... ERROR: Error installing sqlite3: ERROR: Failed to build gem native extension. /usr/bin/ruby extconf.rb checking for sqlite3.h... no sqlite3.h is missing. Try 'port install sqlite3 +universal' or 'yum install sqlite3-devel' and check your shared library search path (the location where your sqlite3 shared library is located). extconf.rb failed * Could not create Makefile due to some reason, probably lack of necessary libraries and/or headers. Check the mkmf.log file for more details. You may need configuration options. Provided configuration options: --with-opt-dir --without-opt-dir --with-opt-include --without-opt-include=${opt-dir}/include --with-opt-lib --without-opt-lib=${opt-dir}/lib --with-make-prog --without-make-prog --srcdir=. --curdir --ruby=/usr/bin/ruby --with-sqlite3-dir --without-sqlite3-dir --with-sqlite3-include --without-sqlite3-include=${sqlite3-dir}/include --with-sqlite3-lib --without-sqlite3-lib=${sqlite3-dir}/lib Gem files will remain installed in /usr/lib64/ruby/gems/1.8/gems/sqlite3-1.3.3 for inspection. Results logged to /usr/lib64/ruby/gems/1.8/gems/sqlite3-1.3.3/ext/sqlite3/gem_make.out Typically, this just means you need to install the development libraries and everything is cool. However, I have installed the sqlite-devel packages and still no dice. Since this is the Amazon Linux instance, I'd rather not add more repositories than the ones Amazon provides if possible. What can i do to get this thing to compile? Thanks for any insight! From a brand new instance, here's what I've done: $ sudo yum install rubygems ruby-devel $ sudo gem update --system $ sudo gem install rails $ rails new app $ cd app $ rails server Could not find gem 'sqlite3 (= 0)' in any of the gem sources listed in your Gemfile. $ sudo yum install sqlite-devel $ sudo gem install sqlite (or sqlite3 -- same result) See breakage above

    Read the article

  • Where are config files for class libraries physically located?

    - by BadNinja
    My guess is that this question will fall under the category of "duh", but, nevertheless, I'm confused. When using config files in, for example, a Windows Forms Application, the config file can be found in C:\Program files\CompanyName\ProductName\Application.exe.config. However, with the class library I'm developing I do not see a "ClassLibrary.dll.config" file in the install folder after installing it (in tandem with another project) from Visual Studio. Even though I do not see the file anywhere, retrieving data from it works correctly. Plus, running the following code from a method within the class library returns the path you would expect: C:\Program files\CompanyName\ProductName\ClassLibrary.dll.config. If someone could shed some light on what I'm missing here, that would be really awesome. public static string MyMethod() { Assembly assem = Assembly.GetExecutingAssembly(); Configuration config = ConfigurationManager.OpenExeConfiguration(assem.Location); return "The assembly location was: " + assem.Location + Environment.NewLine + "The config file path was: " + config.FilePath; // Gives me "C:\Program files\CompanyName\ProductName\ClassLibrary.dll.config" }

    Read the article

  • Problem posting multipart form data using Apache with mod_proxy to a mongrel instance

    - by Ryan E
    I am attempting to simulate my site's production environment as closely as I can on my local machine. This is a rails site that uses Apache w/ mod_proxy to forward requests to a mongrel cluster. On my Mac OSX Leopard machine, I have the default install of apache running and have configured a vhost to use mod_proxy to to forward requests to a local running mongrel instance on port 3000. <Proxy balancer://mongrel_cluster-development> BalancerMember http://127.0.0.1:3000 </Proxy> For the most part, this is working fine. I can browse my development site using the ServerName of the vhost I configured and can confirm that requests are being properly forwarded to the mongrel instance. However, there is a page on the site that has a multipart form that is used to upload an image to the server. When I post this form, there is a delay of about 5 minutes and the browser ultimately returns a Bad Request Your browser sent a request that this server could not understand. In the error log for my vhost: [Tue Sep 22 09:47:57 2009] [error] (70007)The timeout specified has expired: proxy: prefetch request body failed to 127.0.0.1:3000 (127.0.0.1) from ::1 () This same form works fine if I browse directly to the mongrel instance (http://127.0.0.1:3000). Anybody have any idea what the problem might be and how to fix it? If there is any important information that I neglected to include, post a comment, and I can add to this question. Note: Upon further investigation, this appears to be a problem specific to Safari. The form works fine in Firefox.

    Read the article

  • need to print 5 column list in alpha order, vertically

    - by Brad
    Have a webpage that will be viewed by mainly IE users, so CSS3 is out of the question. I want it to list like: A D G B E H C F I Here is the function that currently lists like: A B C D E F G H I function listPhoneExtensions($group,$group_title) { $adldap = new adLDAP(); $group_membership = $adldap->group_members(strtoupper($group),FALSE); sort($group_membership); print " <a name=\"".strtolower($group_title)."\"></a> <h2>".$group_title."</h2> <ul class=\"phone-extensions\">"; foreach ($group_membership as $i => $username) { $userinfo = $adldap->user_info($username, array("givenname","sn","telephonenumber")); $displayname = "<span class=\"name\">".substr($userinfo[0]["sn"][0],0,9).", ".substr($userinfo[0]["givenname"][0],0,9)."</span><span class=\"ext\">".$userinfo[0]["telephonenumber"][0]."</span>"; if($userinfo[0]["sn"][0] != "" && $userinfo[0]["givenname"][0] != "" && $userinfo[0]["telephonenumber"][0] != "") { print "<li>".$displayname."</li>"; } } print "</ul><p class=\"clear-both\"><a href=\"#top\" class=\"link-to-top\">&uarr; top</a></p>"; } Example rendered html: <ul class="phone-extensions"> <li><span class="name">Barry Bonds</span><span class="ext">8281</span></li> <li><span class="name">Gerald Clark</span><span class="ext">8211</span></li> <li><span class="name">Juan Dixon</span><span class="ext">8282</span></li> <li><span class="name">Omar Ebbs</span><span class="ext">8252</span></li> <li><span class="name">Freddie Flank</span><span class="ext">2281</span></li> <li><span class="name">Jerry Gilmore</span><span class="ext">4231</span></li> <li><span class="name">Kim Moore</span><span class="ext">5767</span></li> <li><span class="name">Barry Bonds</span><span class="ext">8281</span></li> <li><span class="name">Gerald Clark</span><span class="ext">8211</span></li> <li><span class="name">Juan Dixon</span><span class="ext">8282</span></li> <li><span class="name">Omar Ebbs</span><span class="ext">8252</span></li> <li><span class="name">Freddie Flank</span><span class="ext">2281</span></li> <li><span class="name">Jerry Gilmore</span><span class="ext">4231</span></li> <li><span class="name">Kim Moore</span><span class="ext">5767</span></li> <li><span class="name">Barry Bonds</span><span class="ext">8281</span></li> <li><span class="name">Gerald Clark</span><span class="ext">8211</span></li> <li><span class="name">Juan Dixon</span><span class="ext">8282</span></li> <li><span class="name">Omar Ebbs</span><span class="ext">8252</span></li> <li><span class="name">Freddie Flank</span><span class="ext">2281</span></li> <li><span class="name">Jerry Gilmore</span><span class="ext">4231</span></li> <li><span class="name">Kim Moore</span><span class="ext">5767</span></li> </ul> Any help is appreciated to getting it to list alpha vertically.

    Read the article

  • CorePlot linker errors after upgrading iOS SDK

    - by JustinXXVII
    This seems like it's happened before but somehow ended up working itself out. It's happened again and I can't seem to get this fixed. I use the CorePlot Cocoa Touch framework. Everything was fine until I upgraded to the new 4.3 beta. Now my project won't compile, and is giving me linker errors for unknown symbols having to do with CorePlot. I've become a pro at adding the framework to my project, and I've checked and rechecked the instructions trying to do it again. Is there a button I can click or anything to just make this work again? I've used these instructions to try to re-add the framework, to no avail EDIT: By the way, this compiles just fine for simulator and runs graphs no problem. Compiling for the device gives me the linker errors, as follows: "_OBJC_CLASS_$_CPPlotRange", referenced from: objc-class-ref in GraphStatsWindow.o objc-class-ref in iPadGraphView.o objc-class-ref in GraphTrendView.o "_OBJC_CLASS_$_CPXYGraph", referenced from: objc-class-ref in GraphStatsWindow.o objc-class-ref in iPadGraphView.o objc-class-ref in GraphTrendView.o "_OBJC_CLASS_$_CPTextStyle", referenced from: objc-class-ref in GraphStatsWindow.o objc-class-ref in iPadGraphView.o objc-class-ref in GraphTrendView.o "_OBJC_CLASS_$_CPLineStyle", referenced from: objc-class-ref in GraphStatsWindow.o objc-class-ref in iPadGraphView.o objc-class-ref in GraphTrendView.o "_OBJC_CLASS_$_CPScatterPlot", referenced from: objc-class-ref in GraphStatsWindow.o objc-class-ref in iPadGraphView.o objc-class-ref in GraphTrendView.o "_OBJC_CLASS_$_CPAxisLabel", referenced from: objc-class-ref in GraphStatsWindow.o objc-class-ref in iPadGraphView.o objc-class-ref in GraphTrendView.o "_OBJC_CLASS_$_CPPlotSymbol", referenced from: objc-class-ref in GraphStatsWindow.o objc-class-ref in iPadGraphView.o objc-class-ref in GraphTrendView.o "_OBJC_CLASS_$_CPColor", referenced from: objc-class-ref in GraphStatsWindow.o objc-class-ref in iPadGraphView.o objc-class-ref in GraphTrendView.o "_OBJC_CLASS_$_CPFill", referenced from: objc-class-ref in GraphStatsWindow.o objc-class-ref in iPadGraphView.o objc-class-ref in GraphTrendView.o "_CPDecimalFromFloat", referenced from: -[GraphStatsWindow setNewGraph] in GraphStatsWindow.o -[iPadGraphView viewDidLoad] in iPadGraphView.o -[GraphTrendView setNewGraph] in GraphTrendView.o "_kCPPlainWhiteTheme", referenced from: -[GraphStatsWindow setNewGraph] in GraphStatsWindow.o -[iPadGraphView viewDidLoad] in iPadGraphView.o -[GraphTrendView setNewGraph] in GraphTrendView.o "_OBJC_CLASS_$_CPTheme", referenced from: objc-class-ref in GraphStatsWindow.o objc-class-ref in iPadGraphView.o objc-class-ref in GraphTrendView.o ld: symbol(s) not found for architecture armv7

    Read the article

  • Naming multi-instance performance counters in .NET

    - by Roger Lipscombe
    Most multiple instance performance counters in Windows seem to automatically(?) have a #n on the end if there's more than one instance with the same name. For example: if, in Perfmon, you look under the Process category, you'll see: ... dwm explorer explorer#1 ... I have two explorer.exe processes, so the second counter has #1 appended to its name. When I attempt to do this in a .NET application: I can create the category, and register the instance (using the PerformanceCounterCategory.Create that takes a CounterCreationDataCollection). I can open the counter for write and write to it. When I open the counter a second time, it opens the same counter. This means that I have two applications fighting over the counters. The documentation for PerformanceCounter.InstanceName states that # is not allowed in the name. So: how do I have multiple-instance performance counters that are actually multiple instance? And where the second (and subsequent) instances get #n appended to the name? That is: I know that I can put the process ID (e.g.) on the instance name. This works, but has the unfortunate side effect that restarting the process results in a new PID, and Perfmon continues monitoring the old counter.

    Read the article

  • VS 2010 Class Diagram Error "The type cannot be edited..."

    - by Eric J.
    A few of the classes on a VS 2010 class diagram are displayed with a red title. The Class Details window shows all of the methods, properties, fields and correctly shows no events. However, there's an entry under each of methods, properties, fields and events that states where the name should be: "The type cannot be edited because the source code file contains an error." However, the source file builds with no errors or warnings. Anyone seen this? Any idea how to fix it?

    Read the article

  • Watir question regarding exist on a class for testing purposes.

    - by AJ
    I have a button on my page that changes depending on what radio button is clicked. The button has the same text on it with the same id, but different classes. How do I test if the two different buttons exist depending on the radio. <a id="submit" class="on" href="javascript:submit();">Submit</a> <a id="submit" class="off" href="javascript:submit();">Submit</a> How do i test if the second button appears instead of the first one. I used something like, browser.link(:text, 'Submit').exist? but this doesn't work cause it will return true no matter what. thanks

    Read the article

  • PDO using singleton stored as class properity

    - by Misiur
    Hi again. OOP drives me crazy. I can't move PDO to work. Here's my DB class: class DB extends PDO { public function &instance($dsn, $username = null, $password = null, $driver_options = array()) { static $instance = null; if($instance === null) { try { $instance = new self($dsn, $username, $password, $driver_options); } catch(PDOException $e) { throw new DBException($e->getMessage()); } } return $instance; } } It's okay when i do something like this: try { $db = new DB(DB_TYPE.':host='.DB_HOST.';dbname='.DB_NAME, DB_USER, DB_PASS); } catch(DBException $e) { echo $e->getMessage(); } But this: try { $db = DB::instance(DB_TYPE.':host='.DB_HOST.';dbname='.DB_NAME, DB_USER, DB_PASS); } catch(DBException $e) { echo $e->getMessage(); } Does nothing. I mean, even when I use wrong password/username, I don't get any exception. Second thing - I have class which is "heart" of my site: class Core { static private $instance; public $db; public function __construct() { if(!self::$instance) { $this->db = DB::instance(DB_TYPE.':hpost='.DB_HOST.';dbname='.DB_NAME, DB_USER, DB_PASS); } return self::$instance; } private function __clone() { } } I've tried to use "new DB" inside class, but this: $r = $core->db->query("SELECT * FROM me_config"); print_r($r->fetch()); Return nothing. $sql = "SELECT * FROM me_config"; print_r($core->db->query($sql)); I get: PDOStatement Object ( [queryString] => SELECT * FROM me_config ) I'm really confused, what am I doing wrong?

    Read the article

  • C++ method declaration, class definition problem

    - by John Fra.
    I have 2 classes: A and B. Some methods of class A need to use class B and the opposite(class B has methods that need to use class A). So I have: class A; class B { method1(A a) { } } class A { method1(B b) { } void foo() { } } and everything works fine. But when I try to call foo() of class A from B::method1 like this: class B { method1(A a) { a.foo(); } } I get as result compile errors of forward declaration and use of incomplete type. But why is this happening? (I have declared class A before using it?)

    Read the article

  • Howto write a class where a property can be accessed without naming it.

    - by SchlaWiener
    I have a (dump) question regarding VB/C# I often use third party classes where I can access a child object with only specifying the id or key. Example: Instead of writing: DataRow row = GetAPopulatedDataRowSomeWhere(); Object result = row.Items[1]; // DataRow has no Items property Object result = row.Items["colName"]; // Also not possible I use this code to access the members: DataRow row = GetAPopulatedDataRowSomeWhere(); Object result = row[1]; Object result = row["colName"]; Can someone tell me how a class has to look like to support this syntax? My own class has a Dictionary that I want to access this way. MyClass["key"]; // <- that's what I want MyClass.SubItems["key"]; // <- that's how I use it now

    Read the article

  • How to create an alias for a named SQL Server instance

    - by Svish
    On my developer computer I have an SQL Server instance named *developer_2005*. In the resource setting files of a C# application we are creating, the instance name is set to foobar (not really, but just as an example). So when I run the application (in debug or realease) it tries to connect to an SQL Server on localhost, named foobar. I am wondering if it is possible to create an alias or something like that, so that the application actually finds an SQL Server on localhost named foobar, but it is actually connecting to the instance named *developer_2005*. The connection string in the config file of the application is Data Source=localhost\foobar;Initial Catalog=barfoo;Integrated Security=True with provider name System.Data.SqlClient. If I change localhost\foobar to *localhost\developer_2005* then the application can connect like it should. How can I create an alias so that I won't have to change the string in the file? I tried, in SQL Server Management Studio, to create a Server Registration with registered server name "localhost\developer", but this didn't seem to do any good. Not even sure what that really did... But then I discovered SQL Server Configuration Manager\SQL Native Client COnfiguration\Aliases. And I kind of assume this is where the solution lies. But I can't quite figure out how to add a new one... When creating a new one, I have to provide Alias Name, Port No, Protocol and Server, and I don't really have a clue what to put in either of them.

    Read the article

  • Doubt about instance creation by using Spring framework ???

    - by Arthur Ronald F D Garcia
    Here goes a command object which needs to be populated from a Spring form public class Person { private String name; private Integer age; /** * on-demand initialized */ private Address address; // getter's and setter's } And Address public class Address { private String street; // getter's and setter's } Now suppose the following MultiActionController @Component public class PersonController extends MultiActionController { @Autowired @Qualifier("personRepository") private Repository<Person, Integer> personRepository; /** * mapped To /person/add */ public ModelAndView add(HttpServletRequest request, HttpServletResponse response, Person person) throws Exception { personRepository.add(person); return new ModelAndView("redirect:/home.htm"); } } Because Address attribute of Person needs to be initialized on-demand, i need to override newCommandObject to create an instance of Person to initiaze address property. Otherwise, i will get NullPointerException @Component public class PersonController extends MultiActionController { /** * code as shown above */ @Override public Object newCommandObject(Class clazz) thorws Exception { if(clazz.isAssignableFrom(Person.class)) { Person person = new Person(); person.setAddress(new Address()); return person; } } } Ok, Expert Spring MVC and Web Flow says Options for alternate object creation include pulling an instance from a BeanFactory or using method injection to transparently return a new instance. First option pulling an instance from a BeanFactory can be written as @Override public Object newCommandObject(Class clazz) thorws Exception { /** * Will retrieve a prototype instance from ApplicationContext whose name matchs its clazz.getSimpleName() */ getApplicationContext().getBean(clazz.getSimpleName()); } But what does he want to say by using method injection to transparently return a new instance ??? Can you show how i implement what he said ??? ATT: I know this funcionality can be filled by a SimpleFormController instead of MultiActionController. But it is shown just as an example, nothing else

    Read the article

  • Should I use Enumeration or Class stereotype in UML to represent a type directory table?

    - by Ivan
    Let's take 2 UML class model entities: One represents an actual Order and another represents an Orede Type. Any Order corresponds to one Type. A 2-way-naviglabe many Orders to one Type relation is meant. Order Type instances are, for example, "Request availability", "Request price", "Preorder", "Buy", "Cancel", "Request support", etc. Order Types are to be addable and editable in the resulting application. Should I model Order Type as Class or as Enumeration? From the data perspective I can't see the difference actually.

    Read the article

  • Trouble connecting to a local SQL server instance from the web

    - by dfarney
    We have a small network behind a firewall (WatchGuard XTM 2 series) and network switch. On our network we have multiple instances of SQL server, but 1 in specific that I would like to be able to access remotely from our website. We have a static IP address from our ISP and then all the machines on the network have a locally assigned dynamic IP address. When trying to connect to the database from outside our network how do I get the request to be directed to the proper machine / SQL instance? Is it a parameter in my connection string or something in my firewall? A few things to rule out: 1) The firewall is allowing access from the website to our network. I added the site's IP and opened up port 1433. Also, when trying to connect and monitoring the firewall no exceptions come up as they did before I added the proper IP address. 2) Remote connections on the SQL server has been setup and enabled. I've done a lot of reading up on remote connections and I am sure it has been setup properly. I am currently getting this error message on my site: A network-related or instance-specific error occurred while establishing a connection to SQL Server. The server was not found or was not accessible. Verify that the instance name is correct and that SQL Server is configured to allow remote connections. (provider: TCP Provider, error: 0 - A connection attempt failed because the connected party did not properly respond after a period of time, or established connection failed because connected host has failed to respond.)

    Read the article

  • PHP 5.3: Late static binding doesn't work for properties when defined in parent class while missing in child class

    - by DavidPesta
    Take a look at this example, and notice the outputs indicated. <?php class Mommy { protected static $_data = "Mommy Data"; public static function init( $data ) { static::$_data = $data; } public static function showData() { echo static::$_data . "<br>"; } } class Brother extends Mommy { } class Sister extends Mommy { } Brother::init( "Brother Data" ); Sister::init( "Sister Data" ); Brother::showData(); // Outputs: Sister Data Sister::showData(); // Outputs: Sister Data ?> My understanding was that using the static keyword would refer to the child class, but apparently it magically applies to the parent class whenever it is missing from the child class. (This is kind of a dangerous behavior for PHP, more on that explained below.) I have the following two things in mind for why I want to do this: I don't want the redundancy of defining all of the properties in all of the child classes. I want properties to be defined as defaults in the parent class and I want the child class definition to be able to override these properties wherever needed. The child class needs to exclude properties whenever the defaults are intended, which is why I don't define the properties in the child classes in the above example. However, if we are wanting to override a property at runtime (via the init method), it will override it for the parent class! From that point forward, child classes initialized earlier (as in the case of Brother) unexpectedly change on you. Apparently this is a result of child classes not having their own copy of the static property whenever it isn't explicitly defined inside of the child class--but instead of throwing an error it switches behavior of static to access the parent. Therefore, is there some way that the parent class could dynamically create a property that belongs to the child class without it appearing inside of the child class definition? That way the child class could have its own copy of the static property and the static keyword can refer to it properly, and it can be written to take into account parent property defaults. Or is there some other solution, good, bad, or ugly?

    Read the article

  • sql server 2005 instance unresponsive and all db's are 'in recovery'

    - by user44650
    we've got a sql server 2005 instance that one of our guys messed up, i believe they killed the sql server service and restarted the computer, and when it came back all of our databases are "in recovery" and it times out every time we try to connect to it. it's been 'in recovery'and unable to connect to 'msbd' (also in recovery) whenever we try to use SSMC, for the last 4 days now. i'm unsure how to use the DBCC CHECKDB command to check the db integrity. we have backups(which we can't recover from because it keeps timing out), and it's a testing server, so nothing in production is really lost. is there any way to get it out of recovery mode? we have another sqlserver instance running that's just fine, but this instance keeps timing out. the errors i keep seeing are database msdb is being recovered. wait until recovery is finished and an exception occurred while executing a transact-sql statement or batch Timeout expired. any thoughts? we don't really have a DBA here, or anyone with much sql experience.

    Read the article

  • What happens to a class in PHP once its been instantiated?

    - by Caylem
    Hi I'm just playing around with some PHP and was wondering what happens when an object from a class is created within another PHP script? I assume once its created and been processed their is no way of then going back and 'playing' around with it from another script? The idea is i'm trying to create a kind of deck of cards using a card class, each card has specific data that is added to each individual object to make it unique, suit, value etc. Once its created i need to be able to go back to specific cards to use them. In java i'd have an arraylist of card objects, i'm not sure how to approach the same area in PHP. Thanks.

    Read the article

  • In java can i have more than one class/object in a file?

    - by David
    So the way i've been told to do things is you have your file and the file name is Classname.java and then the code is something like this: class ClassName { SOME METHODS main {} } and then thats all. I'd like to have two objects defined and used within the same .java file. (i don't want to have to put the other class in a difernt file just because i'd like to send this to someone and i want to avoid hasstle of atatching multiple files to an email [the lazy do make good programers though if you think about it]) is it possible to do this? do i have to do anything special and if so what? what are some mistakes i'm likely to make or that you have made in the past when doing this?

    Read the article

  • Objective C instance variables - Newbie

    - by Dwayne King
    OK - so I'm sure my confusion here is just a result of being stuck in a "Java mindset" and not understanding how Obj C differs in this case. In Java, I can declare a variable in a class, like this, and each instance of that class will have it's own: MyClass { String myVar; MyClass() { // constructor } } In Obj C I tried to do the same thing by declaring a variable only in the .m file like this: #import "MyClass.h" @implementation MyClass NSString *testVar; @end My expectation here was that this variable has a scope limited to this class. So I created a second class (identical): #import "MySecondClass.h" @implementation MySecondClass NSString *testVar; @end What I'm seeing (and has me baffled) is that changing the variable in one class, affects the value seen in the other class. In fact, if I set a breakpoint, and then "Jump to Definition" of the variable, it takes me to th I've created an extremely small XCode project that demonstrates the problem here Nothing more humbling than moving to a new language :) Thanks in advance.

    Read the article

  • Best way to have common class shared by both C++ and Ruby?

    - by shuttle87
    I am currently working on a project where a team of us are designing a game, all of us are proficient in ruby and some (but not all) of us are proficient in c++. Initially we made the backend in ruby but we ported it to c++ for more speed. The c++ port of the backend has exactly the same features and algorithms as the original ruby code. However we still have a bunch of code in ruby that does useful things but we want it to now get the data from the c++ classes. Our first thought was that we could save some of the data structures in something like XML or redis and call that, but some of the developers don't like that idea. We don't need anything particularly complex data structures to be passed between the different parts of the code, just tuples, strings and ints. Is there any way of integrating the ruby code so that it can call the c++ stuff natively? Will we need to embed code? Will we have to make a ruby extension? If so are there any good resources/tutorials you could suggest? For example say we have this code in the c++ backend: class The_game{ private: bool printinfo; //print the player diagnostic info at the beginning if true int numplayers; std::vector<Player*> players; string current_action; int action_is_on; // the index of the player in the players array that the action is now on //more code here public: Table(std::vector<Player *> in_players, std::vector<Statistics *> player_stats ,const int in_numplayers); ~Table(); void play_game(); History actions_history; }; class History{ private: int action_sequence_number; std::vector<Action*> hand_actions; public: void print_history(); void add_action(Action* the_action_to_be_added); int get_action_sequence_number(){ return action_sequence_number;} bool history_actions_are_equal(); int last_action_size(int street,int number_of_actions_ago); History(); ~History(); }; Is there any way to natively call something in the actions_history via The_game object in ruby? (The objects in the original ruby code all had the same names and functionality) By this I mean: class MyRubyClass def method1(arg1) puts arg1 self.f() # ... but still available puts cpp_method.the_current_game.actions_history.get_action_sequence_number() end # Constructor: def initialize(arg) puts "In constructor with arg #{arg}" #get the c++ object here and call it cpp_method end end Is this possible? Any advice or suggestions are appreciated.

    Read the article

  • C# class code loaded in RAM ?

    - by Spi1988
    hi, I would like to know whether the actual code of a C# class gets loaded in RAM when you instantiate the class? So for example if I have 2 Classes CLASS A , CLASS B, where class A has 10000 lines of code but just 1 field, an int. And class B has 10 lines of code and also 1 field an int as well. If I instantiate Class A will it take more RAM than Class B due to its lines of code ? A supplementary question, If the lines of code are loaded in memory together with the class, will they be loaded for every instance of the class? or just once for all the instances? Thanks in advance.

    Read the article

  • ec2 spot instance for daily processing task

    - by chaft
    I don't have much experience as a sysadmin or with amazon aws, so I hope someone can explain in simple terms or refer me to a good guide on how to achieve the below. I have a system running on ec2 and amazon rds getting data in and saving it to the db. I need to run a script once a day (at the end of the day) to process all that data and prepare a daily report. This process will take approximately an hour to run. It needs to run on a high memory instance.. From what i've read so far, I guess the best way to do it is to have a high memory spot instance run every day, set it up to execute the script on startup and and shut down when done. Is that the right way to do it? If so, how to do it? how to tell the spot instance to run every day? through a cron job on the other server or is there a better way? How to set it up to run the script on startup? through cloudinit? Any help would be appreciated. One last thing, the job is not very time sensitive as long as it runs every day.. thanks

    Read the article

< Previous Page | 69 70 71 72 73 74 75 76 77 78 79 80  | Next Page >