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  • RightBarButtonItem in iphone

    - by venkat
    hello all. i am using navigation control with left and right bar buttons.my right side bar button contains length of 10 chars. And my title contains 12 chars. when i press the right bar button my title is moving.how can i stop moving the title when clicking button.

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  • How to create a web-based Email Client in .NET?

    - by Blankman
    I am creating a web based email client in .NET using a 3rd party component. I just want to make sure I have the right idea: I will first pull the emails in using POP I will then parse each individual message that I got from POP using the MIME component right? My choices for 3rd party are: Nsoftware, Quiksoft or Dart. I am looking at Nsoftware right now though.

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  • Extracting table rows with a particular attribute from an HTML File, using HTMLAgilityPack

    - by Soham
    Consider this html snippet: <tr> <td valign=top class="tim_new"><a href="/stocks/company_info/pricechart.php?sc_did=MI42" class="tim_new">3M India</a></td> <td class="tim_new" valign=top><a href='/stocks/marketstats/indcomp.php?optex=NSE&indcode=Diversified' class=tim>Diversified</a></td> <td class="tim_new" align=right valign=top>2,487.25</td> <td class="tim_new" align=right valign=top><font color=#16a903>187.25</font></td> <td class="tim_new" align=right valign=top><font color=#16a903>8.14</font></td> <td class="tim_new" align=right valign=top>2,801.90</td> <td class="tim_new" align=right valign=top>0.06</td> </tr> Realize these three things: The HTML file from which this snippet has been taken, contains multiple number of HTML tables. The table from which this snippet has been extracted doesnt contain only rows of the shown format, but also of other formats like this, for example: <tr><td colspan=7><img src="http://img1.moneycontrol.com/images/blank.gif"height="5"></td></tr>` This same table contains multiple rows of the format which I need to extract. So given this scenario, is it possible to run a code, which extracts, the link with the class name = "tim_new"? Help Appreciated, Soham

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  • Gradient a Parallelogram

    - by nuclearpenguin
    I'm working in JavaScript drawing on a canvas, and have four coordinates to draw a parallelogram, called A, B, C, and D starting from the top-left, top-right, bottom-left, and bottom right, respectively. An example of some coordinates might be: A: (3, 3) B: (4, 3) C: (1, 0) D: (2, 0) I can draw the parallelogram just fine, but I would like to fill it in with a gradient. I want the gradient to fill in from left to right, but matching the angle of the shape. The library I use (CAKE) requires a start and stop coordinate for the gradient. My stop and start would be somewhere half way between A and C, and end somewhere half way between B and D. Of course, it is not simply EXACTLY half way because the angles at A, B, C, and D are not right angles. So given this information (the coordinates), how to I find the point on the line A - C to start, and the point on the line B - D to stop? Remember, I'm doing this in JavaScript, so I have some good Math tools at my disposal for calculation.

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  • Most efficient way to combine two objects in C#

    - by Dested
    I have two objects that can be represented as an int, float, bool, or string. I need to perform an addition on these two objects with the results being the same thing c# would produce as a result. For instance 1+"Foo" would equal the string "1Foo", 2+2.5 would equal the float 5.5, and 3+3 would equal the int 6 . Currently I am using the code below but it seems like incredible overkill. Can anyone simplify or point me to some way to do this efficiently? private object Combine(object o, object o1) { float left = 0; float right = 0; bool isInt = false; string l = null; string r = null; if (o is int) { left = (int)o; isInt = true; } else if (o is float) { left = (float)o; } else if (o is bool) { l = o.ToString(); } else { l = (string)o; } if (o1 is int) { right = (int)o1; } else if (o is float) { right = (float)o1; isInt = false; } else if (o1 is bool) { r = o1.ToString(); isInt = false; } else { r = (string)o1; isInt = false; } object rr; if (l == null) { if (r == null) { rr = left + right; } else { rr = left + r; } } else { if (r == null) { rr = l + right; } else { rr = l + r; } } if (isInt) { return Convert.ToInt32(rr); } return rr; }

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  • Combo box in a scrollable panel causing problems

    - by Dennis
    I have a panel with AutoScroll set to true. In it, I am programmatically adding ComboBox controls. If I add enough controls to exceed the viewable size of the panel a scroll bar appears (so far so good). However, if I open one of the combo boxes near the bottom of the viewable area the combo list isn't properly displayed and the scrollable area seems to be expanded. This results in all of the controls being "pulled" to the new bottom of the panel with some new blank space at the top. If I continue to tap on the drop down at the bottom of the panel the scrollable area will continue to expand indefinitely. I'm anchoring the controls to the left, right and top so I don't think anchoring is involved. Is there something obvious that could be causing this? Update: It looks like the problem lies with anchoring the controls to the right. If I don't anchor to the right then I don't get the strange behavior. However, without right anchoring the control gets cut off by the scroll bar. Here's a simplified test case I built that shows the issue: public Form1() { InitializeComponent(); Panel panel = new Panel(); panel.Size = new Size(80, 200); panel.AutoScroll = true; for (int i = 0; i < 10; ++i) { ComboBox cb = new ComboBox(); cb.Anchor = AnchorStyles.Left | AnchorStyles.Right | AnchorStyles.Top; cb.Items.Add("Option 1"); cb.Items.Add("Option 2"); cb.Items.Add("Option 3"); cb.Items.Add("Option 4"); cb.Location = new Point(0, i * 24); panel.Controls.Add(cb); } Controls.Add(panel); } If you scroll the bottom of the panel and tap on the combo boxes near the bottom you'll notice the strange behavior.

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  • java.bigDecimal divide in ruby environment

    - by Eyal
    I right script in Ruby that include java classes require 'java' include_class 'java.math.BigDecimal' include_class 'java.math.RoundingMode' during the script I need to divide 2 java.bigDecimal one = BigDecimal.new("1") number1 = BigDecimal.new("3") number1 = one.divide(number1,RoundingMode.new(HALF_EVEN)) since I don't have intellisense in this IDE I'm not sure the syntax is right and the runtime error is: uninitialized constant::HALF_EVEN do I combine java object in the ruby scrpit in the right way? how should I divide two java.bigDecimal object in ruby env?

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  • How to make an equation span the whole page / line in LaTeX?

    - by Reed Richards
    I have this equation and it's quite big (basically a FDM one) but it aligns with the text and then continues out on the right side to the nothingness. I've tried stuff like \begin{center} and \hspace*{-2.5cm} but to no avail. I want it to use the whole line not just from the left-margin and out to the right. How do I do it and do I need to install some special package for it? I use the \[ instead of the displaymath like this \[ Equation arrays here \] The code \[ \left( \begin{array}{cccccc} -(2\kappa+\frac{hV\rho}{2}) & (\frac{hV\rho}{2}-\kappa) & 0 & \cdots & 0 \\ -\kappa & -(2\kappa+\frac{hV\rho}{2}) & (\frac{hV\rho}{2}-\kappa) & 0 & \cdots \\ 0 & -\kappa & -(2\kappa+\frac{hV\rho}{2}) & (\frac{hV\rho}{2}-\kappa) & 0 & \cdots \\ \vdots & 0 & \ddots & \vdots \\ \vdots & \vdots & \vdots & -\kappa & -(2\kappa+\frac{hV\rho}{2}) & (\frac{hV\rho}{2}-\kappa) \\ 0 & \vdots & \vdots & 0 & \kappa - \frac{2h\kappa_{v}}{\kappa}(\frac{hv\rho}{2} - \kappa) & -2\kappa \\ \end{array} \right) \left( \begin{array}{c} T_{1} \\ T_{2} \\ \vdots \\ T_{n} \\ \end{array} \right) = \left( \begin{array}{c} Q(0) + \kappa T_{0} \\ Q(h) \\ Q(2h) \\ \vdots \\ Q((n-1)h) \\ 2\frac{\kappa_{v}}{\kappa_{v}}T_{out} \\ \end{array} \right) \]

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  • Prolog: Not executing code as expected.

    - by Louis
    Basically I am attempting to have an AI agent navigate a world based on given percepts. My issue is handling how the agent moves. Basically, I have created find_action/4 such that we pass in the percepts, action, current cell, and the direction the agent is facing. As it stands the entire code looks like: http://wesnoth.pastebin.com/kdNvzZ6Y My issue is mainly with lines 102 to 106. Basically, in it's current form the code does not work and the find_action is skipped even when the agent is in fact facing right (I have verified this). This broken code is as follows: % If we are headed right, take a left turn find_action([_, _, _, _, _], Action, _, right) :- retractall(facing(_)), assert(facing(up)), Action = turnleft . However, after some experimentation I have concluded that the following works: % If we are headed right, take a left turn find_action([_, _, _, _, _], Action, _, _) :- facing(right), retractall(facing(_)), assert(facing(up)), Action = turnleft . I am not entire sure why this is. I've attempted to create several identical find_action's as well, each checking a different direction using the facing(_) format, however swipl does not like this and throws an error. Any help would be greatly appreciated.

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  • BST insert operation. don't insert a node if a duplicate exists already

    - by jeev
    the following code reads an input array, and constructs a BST from it. if the current arr[i] is a duplicate, of a node in the tree, then arr[i] is discarded. count in the struct node refers to the number of times a number appears in the array. fi refers to the first index of the element found in the array. after the insertion, i am doing a post-order traversal of the tree and printing the data, count and index (in this order). the output i am getting when i run this code is: 0 0 7 0 0 6 thank you for your help. Jeev struct node{ int data; struct node *left; struct node *right; int fi; int count; }; struct node* binSearchTree(int arr[], int size); int setdata(struct node**node, int data, int index); void insert(int data, struct node **root, int index); void sortOnCount(struct node* root); void main(){ int arr[] = {2,5,2,8,5,6,8,8}; int size = sizeof(arr)/sizeof(arr[0]); struct node* temp = binSearchTree(arr, size); sortOnCount(temp); } struct node* binSearchTree(int arr[], int size){ struct node* root = (struct node*)malloc(sizeof(struct node)); if(!setdata(&root, arr[0], 0)) fprintf(stderr, "root couldn't be initialized"); int i = 1; for(;i<size;i++){ insert(arr[i], &root, i); } return root; } int setdata(struct node** nod, int data, int index){ if(*nod!=NULL){ (*nod)->fi = index; (*nod)->left = NULL; (*nod)->right = NULL; return 1; } return 0; } void insert(int data, struct node **root, int index){ struct node* new = (struct node*)malloc(sizeof(struct node)); setdata(&new, data, index); struct node** temp = root; while(1){ if(data<=(*temp)->data){ if((*temp)->left!=NULL) *temp=(*temp)->left; else{ (*temp)->left = new; break; } } else if(data>(*temp)->data){ if((*temp)->right!=NULL) *temp=(*temp)->right; else{ (*temp)->right = new; break; } } else{ (*temp)->count++; free(new); break; } } } void sortOnCount(struct node* root){ if(root!=NULL){ sortOnCount(root->left); sortOnCount(root->right); printf("%d %d %d\n", (root)->data, (root)->count, (root)->fi); } }

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  • Rails CSS not Loading using Heroku

    - by eWizardII
    I have the following site set up here on Heroku - http://www.peerinstruction.net/users/sign_up the issue is that I have updated the css yet it is not being actively reflected on the site, it just shows a textbox, with some edited/custom fonts. I have attached the css file in the following gist - https://gist.github.com/f74b626c54ecbb60bbde The signup page controller: !!! Strict %html %head %title= yield(:title) || "Untitled" = stylesheet_link_tag 'application', 'web-app-theme/base', 'web-app-theme/themes/activo/style', 'web-app-theme/override' = javascript_include_tag :defaults = csrf_meta_tag = yield(:head) %body #container #header %h1 %a{:href => "/"} Peer Instruction Network #user-navigation %ul.wat-cf %li .content.login .flash - flash.each do |type, message| %div{ :class => "message #{type}" } %p= message = form_for(resource, :as => resource_name, :url => session_path(resource_name), :html => { :class => "form login" }) do |f| .group.wat-cf .left= f.label :email, :class => "label right" .right= f.text_field :email, :class => "text_field" .group.wat-cf .left= f.label :password, :class => "label right" .right= f.password_field :password, :class => "text_field" .group.wat-cf .right %button.button{ :type => "submit" } Login /= link_to "Sign In", destroy_user_session_path #box = yield The signup pages haml file: %h2 .block .content.login .flash - flash.each do |type, message| %div{ :class => "message #{type}" } %p= message = form_for(resource, :as => resource_name, :url => registration_path(resource_name)) do |f| = devise_error_messages! %div = f.label :firstname %br/ = f.text_field :firstname %div = f.label :middlename %br/ = f.text_field :middlename %div = f.label :lastname %br/ = f.text_field :lastname %div = f.label :email %br/ = f.email_field :email %div = f.label :password %br/ = f.password_field :password %div = f.label :academic %br/ = f.text_field :academic %div= f.submit "Continue" = render :partial => "devise/shared/links" I used web-app-theme to create an activo theme and then modify it.

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  • Div tags, how to create rows with them

    - by Daniel
    How to you define a row in div tags High level example in pseudo code: [DIV TAGS LEFT] [DIV TAGS CENTER] [DIV TAGS RIGHT] [WHAT GOES HERE?????] [DIV TAGS LEFT] [DIV TAGS CENTER] [DIV TAGS RIGHT] [WHAT GOES HERE?????] [DIV TAGS LEFT] [DIV TAGS CENTER] [DIV TAGS RIGHT]

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  • Windows store apps: ScrollViewer with dinamic content

    - by Alexandru Circus
    I have a scrollViewer with an ItemsControl (which holds rows with data) as content. The data from these rows is grabbed from the server so I want to display a ProgressRing with a text until the data arrives. Basically I want the content of the ScrollViewer to be a grid with progress ring and a text and after the data arrives the content to be changed with my ItemsControl. The problem is that the ScrollViewer does not accept more than 1 element as content. Please tell me how can I solve this problem. (I'm a C# beginner) <FlipView x:Name="OptionPagesFlipView" Grid.Row="1" TabNavigation="Cycle" SelectionChanged="OptionPagesFlipView_SelectionChanged" ItemsSource="{Binding OptionsPageItems}"> <FlipView.ItemTemplate> <DataTemplate x:Name="OptionMonthPageTemplate"> <ScrollViewer x:Name="OptionsScrollViewer" HorizontalScrollMode="Disabled" HorizontalAlignment="Stretch" VerticalScrollBarVisibility="Auto"> <ItemsControl x:Name="OptionItemsControl" ItemsSource="{Binding OptionItems, Mode=OneWay}" Visibility="Collapsed"> <ItemsControl.ItemTemplate> <DataTemplate x:Name="OptionsChainItemTemplate"> <Grid x:Name="OptionItemGrid" Background="#FF9DBDF7" HorizontalAlignment="Stretch"> <Grid.RowDefinitions> <RowDefinition Height="Auto"/> <RowDefinition Height="Auto"/> <RowDefinition Height="Auto"/> <RowDefinition Height="Auto"/> </Grid.RowDefinitions> <Grid.ColumnDefinitions> <ColumnDefinition Width="*" /> <ColumnDefinition Width="*" /> <ColumnDefinition Width="*" /> <ColumnDefinition Width="*" /> <ColumnDefinition Width="*" /> </Grid.ColumnDefinitions> <!-- CALL BID --> <TextBlock Text="Bid" Foreground="Gray" HorizontalAlignment="Left" Grid.Row="0" Grid.Column="0" FontSize="18" Margin="5,0,5,0"/> <TextBlock x:Name="CallBidTextBlock" Text="{Binding CallBid}" Foreground="Blue" HorizontalAlignment="Left" Grid.Row="1" Grid.Column="0" Margin="5,0,5,5" FontSize="18"/> <!-- CALL ASK --> <TextBlock Text="Ask" Foreground="Gray" HorizontalAlignment="Left" Grid.Row="2" Grid.Column="0" FontSize="18" Margin="5,0,5,0"/> <TextBlock x:Name="CallAskTextBlock" Text="{Binding CallAsk}" Foreground="Blue" HorizontalAlignment="Left" Grid.Row="3" Grid.Column="0" Margin="5,0,5,0" FontSize="18"/> <!-- CALL LAST --> <TextBlock Text="Last" Foreground="Gray" HorizontalAlignment="Left" Grid.Row="0" Grid.Column="1" FontSize="18" Margin="5,0,5,0"/> <TextBlock x:Name="CallLastTextBlock" Text="{Binding CallLast}" Foreground="Blue" HorizontalAlignment="Left" Grid.Row="1" Grid.Column="1" Margin="5,0,5,5" FontSize="18"/> <!-- CALL NET CHANGE --> <TextBlock Text="Net Ch" Foreground="Gray" HorizontalAlignment="Left" Grid.Row="2" Grid.Column="1" FontSize="18" Margin="5,0,5,0"/> <TextBlock x:Name="CallNetChTextBlock" Text="{Binding CallNetChange}" Foreground="{Binding CallNetChangeForeground}" HorizontalAlignment="Left" Grid.Row="3" Grid.Column="1" Margin="5,0,5,5" FontSize="18"/> <!-- STRIKE --> <TextBlock Text="Strike" Foreground="Gray" HorizontalAlignment="Center" Grid.Row="1" Grid.Column="2" FontSize="18" Margin="5,0,5,0"/> <Border Background="{Binding StrikeBackground}" HorizontalAlignment="Center" Grid.Row="2" Grid.Column="2" Margin="5,0,5,5"> <TextBlock x:Name="StrikeTextBlock" Text="{Binding Strike}" Foreground="Blue" FontSize="18"/> </Border> <!-- PUT LAST --> <TextBlock Text="Last" Foreground="Gray" HorizontalAlignment="Right" Grid.Row="0" Grid.Column="3" FontSize="18" Margin="5,0,5,0"/> <TextBlock x:Name="PutLastTextBlock" Text="{Binding PutLast}" Foreground="Blue" HorizontalAlignment="Right" Grid.Row="1" Grid.Column="3" Margin="5,0,5,5" FontSize="18"/> <!-- PUT NET CHANGE --> <TextBlock Text="Net Ch" Foreground="Gray" HorizontalAlignment="Right" Grid.Row="2" Grid.Column="3" FontSize="18" Margin="5,0,5,0"/> <TextBlock x:Name="PutNetChangeTextBlock" Text="{Binding PutNetChange}" Foreground="{Binding PutNetChangeForeground}" HorizontalAlignment="Right" Grid.Row="3" Grid.Column="3" Margin="5,0,5,5" FontSize="18"/> <!-- PUT BID --> <TextBlock Text="Bid" Foreground="Gray" HorizontalAlignment="Right" Grid.Row="0" Grid.Column="4" FontSize="18" Margin="5,0,15,0"/> <TextBlock x:Name="PutBidTextBlock" Text="{Binding PutBid}" Foreground="Blue" HorizontalAlignment="Right" Grid.Row="1" Grid.Column="4" Margin="5,0,15,5" FontSize="18"/> <!-- PUT ASK --> <TextBlock Text="Ask" Foreground="Gray" HorizontalAlignment="Right" Grid.Row="2" Grid.Column="4" FontSize="18" Margin="5,0,15,0"/> <TextBlock x:Name="PutAskTextBlock" Text="{Binding PutAsk}" Foreground="Blue" HorizontalAlignment="Right" Grid.Row="3" Grid.Column="4" Margin="5,0,15,5" FontSize="18"/> <!-- BOTTOM LINE SEPARATOR--> <Rectangle Fill="Black" Height="1" Grid.ColumnSpan="5" VerticalAlignment="Bottom" Grid.Row="3"/> </Grid> </DataTemplate> </ItemsControl.ItemTemplate> </ItemsControl> <!--<Grid> <Grid.RowDefinitions> <RowDefinition/> </Grid.RowDefinitions> <Grid.ColumnDefinitions> <ColumnDefinition/> <ColumnDefinition/> </Grid.ColumnDefinitions> <ProgressRing x:Name="CustomProgressRing" Height="40" Width="40" IsActive="true" Grid.Column="0" Margin="20" Foreground="White"/> <TextBlock x:Name="CustomTextBlock" Height="auto" Width="auto" FontSize="25" Grid.Column="1" Margin="20"/> <Border BorderBrush="#FFFFFF" BorderThickness="1" Grid.ColumnSpan="2"/> </Grid>--> </ScrollViewer> </DataTemplate> </FlipView.ItemTemplate>

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  • jQuery check offset

    - by Glister
    HTML: <ul class="clients"> <li> <div class="over left">Description</div> <div class="inner">Image</div> </li> </ul> CSS: .clients { margin-right: -20px; } .clients li { float: left; width: 128px; height: 120px; margin: 0 20px 20px 0; border: 1px solid #c2c2c2; } .clients .over { display: none; position: absolute; width: 250px; font-size: 11px; line-height: 16px; background: #ecf5fb; margin: 3px 0 0 3px; padding: 18px; z-index: 25; } .clients .right { margin: 3px 0 0 -161px; } .clients .inner { width: 128px; height: 120px; overflow: hidden; } So, we have a list of floated squares and a popup blocks in each, which have absolute position. JS: jQuery(function($) { $('input[title!=""]').hint(); $(".clients li").bind('mouseover mouseout',function(){$(this).find("div.over").toggle()}); }); If over - show, else - hide. Quite ok, but it must be more advanced, we should catch an offset and give a class to .over block: if offset from right (corner of browser window) less than 150px, then add class "right" for a .over block. if offset from right more than 150px - add class "left" for a .over block. How can we do it?

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  • Manipulating / Resizing / Scaling an image in vb.net

    - by Christian Payne
    Imagine I have a rectangle say 400px x 300px. Then let’s say I want to load an image in that. All of this is very easy using Sytem.Drawing.DrawImage. But then I want to leave the left hand side as 300px but change the right hand side to 250 px. I can draw the box using 4 DrawLines but I don’t know how to squash the image into the new shape. I want the right hand side of the shape to be 250, the left size 300 and the top and bottom 400px. I can’t use DrawImage as it expects the left and right sizes to be the same. Is there a way to manipulate the image into the new shape? I've looked at other questions, but they only apply where the left and right hand side is equal. Any thoughts on how to squash an image into a shape which did not have parallel sides? (If it helps, I'm happy to sacrifice image quality to fit the right shape.)

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  • background image disappears when position relative used in firefox

    - by toomanyairmiles
    So I'm trying to add a badge to the top right corner of a site I'm doing some work on. z-index works to float the object above the page content but each time i try to use position relative the background image disappears only position absolute shows the image. I don't really want to use absolute as the image needs to be positioned on the right hand side of the sites menu bar not the right hand side of the viewport. Any thoughts or advice appreciated <div class="badge-box"> <a href="http://www.google.com" class="badge">Book Now!</a> </div> <div id="header"> <a href="index.php"><img src="images/pixel.gif" width="378" height="31" alt="Welcome to Gwynfryn Farm Cottages" /></a> </div> <div id="main-menu"> <div> <a href="/">Home</a> <a href="/cottages.php">Our Cottages</a> <a href="/gwynfryn.php">Bed &amp; Breakfast</a> <a href="/rates.php">Price Guide</a> <a href="/llanbedr.php">Location &amp; Local Attractions</a> <a href="/news.php">News &amp; Special Offers</a> <a href="/contact.php">Contact Us</a> </div> </div> .badge-box { width: 1030px; margin-left: auto; margin-right: auto; border: 0px solid red; } .badge { background: url(../images/badge.png) 0px 0px no-repeat; width: 148px; height: 148px; text-indent: -10000px; position: relative; z-index: 999; } #header { width: 960px; height: 40px; margin-left:auto; margin-right:auto; margin-top:20px; padding: 20px 0px 0px 20px; background: #58564f url(../images/header-top-background.png); } #main-menu { width: 980px; margin-left: auto; margin-right: auto; height: 35px; /*background: red;*/ background: #58564f url(../images/header-bottom-background.png); font-family: Georgia, "Times New Roman", Times, serif; } #main-menu div { width: 776px; height: 35px; margin-left: auto; margin-right: auto; background: blue; } #main-menu div a { display: block; float: left; padding: 5px 10px 0px 10px; height: 30px; color: #FFFFFF; font-size: 1.2em; text-align: center; background: green; } #main-menu div a:hover { background-color: #333333; }

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  • How to make my robot move in a rectangular path along the black tape?

    - by Sahat
    I am working on a robot, it's part of the summer robotics workshop in our college. We are using C-STAMP micro controllers by A-WIT. I was able to make it move, turn left, turn right, move backward. I have even managed to make it go along the black tape using a contrast sensor. I send the robot at 30-45 degrees toward the black tape on the table and it aligns itself and starts to move along the black tape. It jerks a little, probably due to my programming logic below, it's running a while loop and constantly checking if statements, so it ends up trying to turn left and right every few milliseconds, which explains the jerking part. But it's okay, it works, not as smooth as I want it to work but it works! Problem is that I can't make my robot go into a rectangular path of the black tape. As soon as it reaches the corner it just keeps going straight instead of making a left/right turn. Here's my attempt. The following code is just part of the code. My 2 sensors are located right underneath the robot, next to the front wheel, almost at the floor level. It has "index" value ranging from 0 to 8. I believe it's 8 when you have a lot of light coming into the sensor , and 0 when it's nearly pitch black. So when the robot moves into the black-tape-zone, the index value drops, and based on that I have an if-statement telling my robot to either turn left or right. To avoid confusion I didn't post the entire source code, but only the logical part responsible for the movement of my robot along the black tape. while(1) { // don't worry about these. // 10 and 9 represent Sensor's PIN location on the motherboard V = ANALOGIN(10, 1, 0, 0, 0); V2 = ANALOGIN(9, 1, 0, 0, 0); // i got this "formula" from the example in my Manual. // V stands for voltage of the sensor. // it gives me the index value of the sensor. 0 = darkest, 8 = lightest. index = ((-(V - 5) / 5) * 8 + 0.5); index2 = ((-(V2 - 5) / 5) * 8 + 0.5); // i've tweaked the position of the sensors so index > 7 is just right number. // the robot will move anywhere on the table just fine with index > 7. // as soon as it drops to or below 7 (i.e. finds black tape), the robot will // either turn left or right and then go forward. // lp & rp represent left-wheel pin and right-wheel pin, 1 means run forever. // if i change it from 1 to 100, it will go forward for 100ms. if (index > 7 && index2 > 7) goForward(lp, rp, 1); if (index <= 7) { turnLeft(lp, rp, 1); goForward(lp, rp, 1); // this is the tricky part. i've added this code last minute // trying to make my robot turn, but i didn't work. if (index > 4) { turnLeft(lp, rp, 1); goForward(lp, rp, 1); } } else if (index2 <= 7) { turnRight(lp, rp, 1); goForward(lp, rp, 1); // this is also the last minute addition. it's same code as above // but it's for the 2nd sensor. if (index2 > 4) { turnRight(lp, rp, 1); goForward(lp, rp, 1); } } I've spent the entire day trying to figure it out. I've pretty much exhausted all avenues. Asking for the solution on stackoverflow is my very last option now. Thanks in advance! If you have any questions about the code, let me know, but comments should be self-explanatory.

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  • Using recursion to to trim a binary tree based on a given min and max value

    - by Justin
    As the title says, I have to trim a binary tree based on a given min and max value. Each node stores a value, and a left/right node. I may define private helper methods to solve this problem, but otherwise I may not call any other methods of the class nor create any data structures such as arrays, lists, etc. An example would look like this: overallRoot _____[50]____________________ / \ __________[38] _______________[90] / \ / _[14] [42] [54]_____ / \ \ [8] [20] [72] \ / \ [26] [61] [83] trim(52, 65); should return: overallRoot [54] \ [61] My attempted solution has three methods: public void trim(int min, int max) { rootFinder(overallRoot, min, max); } First recursive method finds the new root perfectly. private void rootFinder(IntTreeNode node, int min, int max) { if (node == null) return; if (overallRoot.data < min) { node = overallRoot = node.right; rootFinder(node, min, max); } else if (overallRoot.data > max) { node = overallRoot = node.left; rootFinder(node, min, max); } else cutter(overallRoot, min, max); } This second method should eliminate any further nodes not within the min/max, but it doesn't work as I would hope. private void cutter(IntTreeNode node, int min, int max) { if (node == null) return; if (node.data <= min) { node.left = null; } if (node.data >= max) { node.right = null; } if (node.data < min) { node = node.right; } if (node.data > max) { node = node.left; } cutter(node.left, min, max); cutter(node.right, min, max); } This returns: overallRoot [54]_____ \ [72] / [61] Any help is appreciated. Feel free to ask for further explanation as needed.

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  • C++ find largest BST in a binary tree

    - by fonjibe
    what is your approach to have the largest BST in a binary tree? I refer to this post where a very good implementation for finding if a tree is BST or not is bool isBinarySearchTree(BinaryTree * n, int min=std::numeric_limits<int>::min(), int max=std::numeric_limits<int>::max()) { return !n || (min < n->value && n->value < max && isBinarySearchTree(n->l, min, n->value) && isBinarySearchTree(n->r, n->value, max)); } It is quite easy to implement a solution to find whether a tree contains a binary search tree. i think that the following method makes it: bool includeSomeBST(BinaryTree* n) { if(!isBinarySearchTree(n)) { if(!isBinarySearchTree(n->left)) return isBinarySearchTree(n->right); } else return true; else return true; } but what if i want the largest BST? this is my first idea, BinaryTree largestBST(BinaryTree* n) { if(isBinarySearchTree(n)) return n; if(!isBinarySearchTree(n->left)) { if(!isBinarySearchTree(n->right)) if(includeSomeBST(n->right)) return largestBST(n->right); else if(includeSomeBST(n->left)) return largestBST(n->left); else return NULL; else return n->right; } else return n->left; } but its not telling the largest actually. i struggle to make the comparison. how should it take place? thanks

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  • how to reload the whole page through a button placed in a division in jsp

    - by ajeet singh
    when i tried to make web project, i placed the links on the left on one division and a bigger division on the right to load the jsp pages on clicking the links making the main page same... but when there is a need arises to load the whole page by clicking the button placed on the right division, i found that the only page is loaded on the right division jsp calling its action... please help me to sort out this problem..

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  • How to make a control invisible?

    - by Nakilon
    I've made several TextCtrls and Button, but currently users of my application don't want to see them. So I have to hide them temporary (for current build). Here they are: class MainFrame < Wx::Frame def initialize (parent = nil) super nil,:title=>"sometitle",:size=>[600,600] set_sizer Wx::BoxSizer.new Wx::VERTICAL @tag1 = Wx::TextCtrl.new self sizer.add_item @tag1,:flag=>Wx::RIGHT|Wx::EXPAND @tag1.set_value 'property' @tag1title = Wx::TextCtrl.new self sizer.add_item @tag1title,:flag=>Wx::RIGHT|Wx::EXPAND @tag1title.set_value 'title' @tag2 = Wx::TextCtrl.new self sizer.add_item @tag2,:flag=>Wx::RIGHT|Wx::EXPAND @tag2.set_value 'description' @tag2title = Wx::TextCtrl.new self sizer.add_item @tag2title,:flag=>Wx::RIGHT|Wx::EXPAND @tag2title.set_value '' @button_parse = Wx::Button.new self sizer.add_item @button_parse @button_parse.label = "Parse XML" evt_button @button_parse, :click_parse # ...... end # ...... end I see nothing about it in docs and Google is also not a friend for me today.

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  • How do I control the direction of the scroll on my coda slider?

    - by lightingwrist
    Hello, I have a coda slider and am unable to determine the direction of the scroll. I have 3 panels that I want to scroll left to right. Sometimes it scrolls left to right, sometimes up and down, and sometimes horizontally. How do I lock it down to go the direction I want? Here is the HTML: <body> <div id="slider_home" class="round_10px"> <ul class="navigation_home"> <li><a href="#scroll_Parents" class="round_10px">Information For Parents</a></li> <li><a href="#scroll_Materials" class="round_10px">Print Materials</a></li> <li><a href="#scroll_Resources" class="round_10px">Online Resources</a></li> </ul> <div id="scroll_bg_home"> <div class="scroll_home"> <div class="scrollContainer_home"> <div class="panel_home" id="scroll_Parents"> content </div> <div class="panel_home" id="scroll_Materials"> content </div> <div class="panel_home" id="scroll_Resources"> content </div> </div> </div> </div> </div> </body> Here is the CSS: #wrapper {width:550px;margin:0px auto;} #intro {padding-bottom:10px;} h2 {margin:0;margin-bottom:14px;padding:0;} #slider {width:631px;margin:10px auto 0px auto;position:relative;} #scroll_bg{height:360px;width:590px;overflow:hidden;position:relative;clear:left;background:#FFFFFF url(images/) no-repeat; margin:0px auto 0px auto} .scroll{ background:transparent; width:550px; height:370px; padding:0px; margin:0px auto; overflow:hidden; } .scrollContainer div.panel {padding:20px 0px;height:330px; width:550px;margin:0px;float:left;} #shade {background:#EDEDEC url(images/shade.jpg) no-repeat 0 0;height:50px;} ul.navigation {list-style:none;margin:0px 0px 0px 23px;padding:0px;padding-bottom:0px;} ul.navigation li {display:inline; margin-right:5px;} ul.navigation li a { background:#FFFFFF;font-family:Arial, Helvetica, sans-serif; font-size:16px; font-weight:bold; color:#CCCCCC;padding:5px 5px 5px 5px;border:1px #F4F4F4 solid;text-decoration: none;} ul.navigation a:hover { color:#EDEDEC;border:1px #E6E6E6 solid;} ul.navigation a.selected {color:#333333;} ul.navigation a:focus {outline:none;} .scrollButtons {position:absolute;top:150px;cursor:pointer;} .scrollButtons.left {left:-37px;top:20px} .scrollButtons.right {right:-32px;top:20px;} .hide {display:none;} And here is the Jquery includes file: // when the DOM is ready... $(document).ready(function () { var $panels = $('#slider_home .scrollContainer_home > div.panel_home'); var $container = $('#slider_home .scrollContainer_home'); // if true, we'll float all the panels left and fix the width // of the container var horizontal = true; // float the panels left if we're going horizontal if (horizontal) { $panels.css({ 'float' : 'left', 'position' : 'relative' // IE fix to ensure overflow is hidden }); // calculate a new width for the container (so it holds all panels) $container.css('width', $panels[0].offsetWidth * $panels.length); } // collect the scroll object, at the same time apply the hidden overflow // to remove the default scrollbars that will appear var $scroll_bg = $('#scroll_bg_home'); var $scroll = $('#slider_home .scroll_home').css('overflow', 'hidden'); // apply our left + right buttons $scroll_bg .before('<img class="scrollButtons_home left" src="styles/images/BackFlip.jpg" />') .after('<img class="scrollButtons_home right" src="styles/images/flipForward.jpg" />'); // handle nav selection function selectNav() { $(this) .parents('ul:first') .find('a') .removeClass('selected') .end() .end() .addClass('selected'); } $('.navigation_home').find('a').click(selectNav); // go find the navigation link that has this target and select the nav function trigger(data) { var el = $('.navigation_home').find('a[href$="' + data.id + '"]').get(0); selectNav.call(el); } if (window.location.hash) { trigger({ id : window.location.hash.substr(1) }); } else { $('.navigation_home a:first').click(); } // offset is used to move to *exactly* the right place, since I'm using // padding on my example, I need to subtract the amount of padding to // the offset. Try removing this to get a good idea of the effect var offset = parseInt((horizontal ? $container.css('paddingTop') : $container.css('paddingLeft')) || 0) * -1; var scrollOptions = { target: $scroll, // the element that has the overflow // can be a selector which will be relative to the target items: $panels, navigation: '.navigation_home a', // selectors are NOT relative to document, i.e. make sure they're unique prev: 'img.left', next: 'img.right', // allow the scroll effect to run both directions axis: 'xy', onAfter: trigger, // our final callback offset: offset, // duration of the sliding effect duration: 500, // easing - can be used with the easing plugin: // http://gsgd.co.uk/sandbox/jquery/easing/ easing: 'swing' }; // apply serialScroll to the slider - we chose this plugin because it // supports// the indexed next and previous scroll along with hooking // in to our navigation. $('#slider_home').serialScroll(scrollOptions); // now apply localScroll to hook any other arbitrary links to trigger // the effect $.localScroll(scrollOptions); // finally, if the URL has a hash, move the slider in to position, // setting the duration to 1 because I don't want it to scroll in the // very first page load. We don't always need this, but it ensures // the positioning is absolutely spot on when the pages loads. scrollOptions.duration = 1; $.localScroll.hash(scrollOptions); });

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  • Is there a programming language that performs currying when named parameters are omitted?

    - by Adam Gent
    Many functional programming languages have support for curried parameters. To support currying functions the parameters to the function are essentially a tuple where the last parameter can be omitted making a new function requiring a smaller tuple. I'm thinking of designing a language that always uses records (aka named parameters) for function parameters. Thus simple math functions in my make believe language would be: add { left : num, right : num } = ... minus { left : num, right : num } = .. You can pass in any record to those functions so long as they have those two named parameters (they can have more just "left" and "right"). If they have only one of the named parameter it creates a new function: minus5 :: { left : num } -> num minus5 = minus { right : 5 } I borrow some of haskell's notation for above. Has any one seen a language that does this?

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  • problem with converting simple code to silverlight app.

    - by Sara
    Hi. I have this code for window form application and I have been attempting to convert it to a Silverlight application but it does not work!. There is a Textbox and I attached KeyDown event handler to it. when the user press the arrow key ( left or right) while the focus on the textbox, it will write . or -. When it is window form i used e.KeyCode and Keys.Right and its works great but when it is silverlight I used e.Key and key.Right and the program doesn't work good because the arrows do the 2 functions moving and write ./-. How I can work this out in Silverlight? (My English not good) The code ( window form): private void textBox1_KeyDown(object sender, KeyEventArgs e) { if (sender is TextBox) { TextBox textBox = (TextBox)sender; if (e.KeyCode == Keys.Left || e.KeyCode == Keys.Right) { e.Handled = true; char insert; if (e.KeyCode == Keys.Left) { insert = '.'; } else { insert = '-'; } int i = textBox.SelectionStart; textBox.Text = textBox.Text.Insert(i, insert.ToString()); textBox.Select(i + 1, 0); } } } (and Silverlight): private void textBox1_KeyDown(object sender, KeyEventArgs e) { if (sender is TextBox) { TextBox textBox = (TextBox)sender; if (e.Key == Key.Left || e.Key == Key.Right) { e.Handled = true; char insert; if (e.Key == Key.Left) { insert = '.'; } else { insert = '-'; } int i = textBox.SelectionStart; textBox.Text = textBox.Text.Insert(i, insert.ToString()); textBox.Select(i + 1, 0); } } } I don't understand, is there huge different effect between using Keycode/Keys and Key/Key or because something else?

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