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  • related to java file handling.

    - by sadia
    In Java how can I take the data of my file on my display screen? I want to use data in my file and also want that data to be displayed on my output screen when I execute my program. Can any body please help by providing me such example in Java language. Thank you!

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  • Easy - Read a file into a array

    - by ineedtehhelpz
    So I have a .dat file that just holds a list of names, each name is on a new line. I am having a day of complete mental blanks but how would I go about getting those names out of the file and puting them into a array. Thanks for any help

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  • What is the best strategy for transforming unicode strings into filenames?

    - by David Cowden
    I have a bunch (thousands) of resources in an RDF/XML file. I am writing a certain subset of the resources to files -- one file for each, and I'm using the resource's title property as the file name. However, the titles are every day article, website, and blog post titles, so they contain characters unsafe for a URI (the necessary step for constructing a valid file path). I know of the Jersey UriBuilder but I can't quite get it to work for my needs as I detailed in a different question on SO. Some possibilities I have considered are: Since each resource should also have an associated URL, I could try to use the name of the file on the server. The down side of this is sometimes people don't name their content logically and I think the title of an article better reflects the content that will be in each text file. Construct a white list of valid characters and parse the string myself defining substitutions for unsafe characters. The downside of this is the result could be just as unreadable as the former solution because presumably the content creators went through a similar process when placing the files on their server. Choose a more generic naming scheme, place the title in the text file along with the other attributes, and tell my boss to live with it. So my question here is, what methods work well for dealing with a scenario where you need to construct file names out of strings with potentially unsafe characters? Is there a solution that better fills out my constraints?

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  • How file permissions are stored in inode?

    - by Debadyuti Maiti
    Suppose there's two pc - "A" and "B". Then if A downloads a files from B , then what would be the file permission of that downloaded file? Is it possible that the downloaded file in A will have an Inode entry with all it's permissions from B & store B's user account as the owner ? If that's the case then is it impossible to change that files permission on A if "others" [as in user-group-others] doesn't have the right to write on that file? e.g. if this is the case , __x __x __x file.txt [On B] then what would be the file permission on A of that same file downloaded from B [e.g. through vsftpd]? __x __x __x file.txt [On A] or rw_x rw_x rw_x file.txt [On A] [i.e. defined by A's default umask value]

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  • Simple script - execute command on selected file

    - by askmoo
    I want to make a script that will execute .jar file on selected file. Later I will add that script to right-click menu via the tool Nautilus Actions or just place it into nautilus-scripts folder. I have a problem creating script. When I am in a usual console screen and want to execute this jar file on any other file, I use this syntax myfile.jar ./someotherfile.xml and the jar file will write the output to the console screen. So I created a file script.sh, added lines in it #!/bin/bash /home/username/myfile.jar $1 But it does not output anything. I know I am doing something wrong. Please help. To sum, I need a script that will use selected file as a parameter, open the gnome-terminal, inside that terminal it will start JAR file and pass it the selected file. I am confident that this is a very simple procedure, but I am total newbie with shell scripting.

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  • Why isn't this file reading/writing program working?

    - by user320950
    This program is supposed to read files and write them. I took the file open checks out because they kept causing errors. The problem is that the files open like they are supposed to and the names are correct but nothing is on any of the text screens. Do you know what is wrong? #include<iostream> #include<fstream> #include<cstdlib> #include<iomanip> using namespace std; int main() { ifstream in_stream; // reads itemlist.txt ofstream out_stream1; // writes in items.txt ifstream in_stream2; // reads pricelist.txt ofstream out_stream3;// writes in plist.txt ifstream in_stream4;// read recipt.txt ofstream out_stream5;// write display.txt float price=' ',curr_total=0.0; int wrong=0; int itemnum=' '; char next; in_stream.open("ITEMLIST.txt", ios::in); // list of avaliable items out_stream1.open("listWititems.txt", ios::out); // list of avaliable items in_stream2.open("PRICELIST.txt", ios::in); out_stream3.open("listWitdollars.txt", ios::out); in_stream4.open("display.txt", ios::in); out_stream5.open("showitems.txt", ios::out); in_stream.close(); // closing files. out_stream1.close(); in_stream2.close(); out_stream3.close(); in_stream4.close(); out_stream5.close(); system("pause"); in_stream.setf(ios::fixed); while(in_stream.eof()) { in_stream >> itemnum; cin.clear(); cin >> next; } out_stream1.setf(ios::fixed); while (out_stream1.eof()) { out_stream1 << itemnum; cin.clear(); cin >> next; } in_stream2.setf(ios::fixed); in_stream2.setf(ios::showpoint); in_stream2.precision(2); while((price== (price*1.00)) && (itemnum == (itemnum*1))) { while (in_stream2 >> itemnum >> price) // gets itemnum and price { while (in_stream2.eof()) // reads file to end of file { in_stream2 >> itemnum; in_stream2 >> price; price++; curr_total= price++; in_stream2 >> curr_total; cin.clear(); // allows more reading cin >> next; } } } out_stream3.setf(ios::fixed); out_stream3.setf(ios::showpoint); out_stream3.precision(2); while((price== (price*1.00)) && (itemnum == (itemnum*1))) { while (out_stream3 << itemnum << price) { while (out_stream3.eof()) // reads file to end of file { out_stream3 << itemnum; out_stream3 << price; price++; curr_total= price++; out_stream3 << curr_total; cin.clear(); // allows more reading cin >> next; } return itemnum, price; } } in_stream4.setf(ios::fixed); in_stream4.setf(ios::showpoint); in_stream4.precision(2); while ( in_stream4.eof()) { in_stream4 >> itemnum >> price >> curr_total; cin.clear(); cin >> next; } out_stream5.setf(ios::fixed); out_stream5.setf(ios::showpoint); out_stream5.precision(2); out_stream5 <<setw(5)<< " itemnum " <<setw(5)<<" price "<<setw(5)<<" curr_total " <<endl; // sends items and prices to receipt.txt out_stream5 << setw(5) << itemnum << setw(5) <<price << setw(5)<< curr_total; // sends items and prices to receipt.txt out_stream5 << " You have a total of " << wrong++ << " errors " << endl; }

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  • Calling class in Java after editing file used in as source for table

    - by user2892290
    I'm currently working on a project, I'll try to subrscibe first. I save data into text file, that I use as a source for browser of that data. The browser is based on table that contains the data. I have to rewrite the source file everytime I delete or edit data. That's where the problem comes in. After deleting or editing data I call a method to create the table again, but the table never creates. Is it possibly made by editing the file and calling the method right after that? If I restart my app the table is successfully created with right data. Take in note that I don't get any error message. This is the method I use for loading data from source file: try (BufferedReader input1 = new BufferedReader(new FileReader("./src/data.src"))) { int lines = 0; while (input1.read() != -1) { if (!(input1.readLine()).equals("")) { lines++; } } input1.close(); if (lines == 0) { JOptionPane.showMessageDialog(null, "No data to load, create a note first!"); new Writer().build(frame); } else { try (BufferedReader input = new BufferedReader(new FileReader("./src/data.src"))) { Game[] g = new Game[lines]; String currentLine; String[] help; int counter = 0; while (lines > 0) { currentLine = input.readLine(); help = currentLine.split("#"); g[counter] = new Game(help[0],help[1], help[2], help[3], help[4], help[5], help[6], help[7], help[8], help[9]); counter++; lines--; } input.close(); final JButton bButton = new backButton().create(frame, mPanel); build(g, frame, bButton); mPanel.add(panel); mPanel.add(panel2); mPanel.add(searchPanel); mPanel.add(bButton); bButton.addActionListener(new ActionListener() { @Override public void actionPerformed(ActionEvent e) { frame.setCursor(Cursor.getPredefinedCursor(Cursor.WAIT_CURSOR)); panel.removeAll(); frame.setCursor(Cursor.getDefaultCursor()); } }); mPanel.setPreferredSize(new Dimension(1000, 750)); panel.setBorder(new EmptyBorder(10, 10, 10, 10)); frame.setLayout(new FlowLayout()); frame.add(mPanel); frame.pack(); JMenuBar menuBar = new Menu().create(frame, mPanel); frame.setJMenuBar(menuBar); frame.setVisible(true); Rectangle rec = GraphicsEnvironment.getLocalGraphicsEnvironment().getMaximumWindowBounds(); int width = (int) rec.getWidth(); int height = (int) rec.getHeight(); frame.setBounds(1, 3, width, height); frame.addComponentListener(new ComponentAdapter() { @Override public void componentMoved(ComponentEvent e) { frame.setLocation(1, 3); } }); And this is the method I use for creating the table: String[][] tableData = new String[g.length][9]; for (int i = 0; i < tableData.length; i++) { tableData[i][0] = g[i].getChampion(); tableData[i][1] = g[i].getRole(); tableData[i][2] = g[i].getEnemy(); tableData[i][3] = g[i].getDifficulty(); tableData[i][4] = g[i].getResult(); tableData[i][5] = g[i].getScore(); tableData[i][6] = g[i].getGameType(); tableData[i][7] = g[i].getPoints(); tableData[i][8] = g[i].getLeague(); } final JLabel searchLabel = new JLabel("Search for champion played."); final JButton searchButton = new JButton("Search"); final JTextField searchText = new JTextField(20); frame.setTitle("LoL Notepad - reading your notes"); JTable table = new JTable(tableData, columnNames); final JScrollPane scrollPane = new JScrollPane(table); scrollPane.setPreferredSize(new Dimension(980, 500)); panel2.setPreferredSize(new Dimension(1000, 550)); panel2.setVisible(false); panel2.setBorder(new EmptyBorder(10, 10, 10, 10)); panel3.setVisible(false); panel.setLayout(new FlowLayout()); panel.add(scrollPane); searchPanel.add(searchLabel); searchPanel.add(searchText); searchPanel.add(searchButton); searchButton.addActionListener(new ActionListener() { @Override public void actionPerformed(ActionEvent e) { try { frame.setCursor(Cursor.getPredefinedCursor(Cursor.WAIT_CURSOR)); search(g, searchText.getText(), frame, bButton); frame.setCursor(Cursor.getDefaultCursor()); } catch (IOException ex) { Logger.getLogger(Reader.class.getName()).log(Level.SEVERE, null, ex); } } }); table.addMouseListener(new MouseAdapter() { @Override public void mousePressed(MouseEvent e) { if (e.getClickCount() == 1) { JTable target = (JTable) e.getSource(); panel.setVisible(false); searchPanel.setVisible(false); bButton.setVisible(false); int row = target.getSelectedRow(); specific(row, g, frame, bButton); } } });

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  • Java - HtmlUnit - Unable to save HTML to file (in some cases)

    - by Walter White
    Hi all, I am having intermittent issues saving the response HTML in HtmlUnit. Caused by: java.io.IOException: Unable to save file:C:\ccview\PP50773_4.0_walter\TSC_hca\Applications\HCA_J2EE\HCA\target\HtmlUnitTests\single\1\com\pnc\tsc\hca\ui\test\SiteCrawler\crawlSiteAsProvider\10.SiteCrawler.crawl.html at com.pnc.tsc.hca.ui.util.GetUtil.save(GetUtil.java:128) at com.pnc.tsc.hca.ui.util.GetUtil.add(GetUtil.java:75) at com.pnc.tsc.hca.ui.util.GetUtil.click(GetUtil.java:49) at com.pnc.tsc.hca.ui.test.SiteCrawler.crawl(SiteCrawler.java:87) at com.pnc.tsc.hca.ui.test.SiteCrawler.crawl(SiteCrawler.java:61) at com.pnc.tsc.hca.ui.test.SiteCrawler.crawl(SiteCrawler.java:63) at com.pnc.tsc.hca.ui.test.SiteCrawler.crawl(SiteCrawler.java:63) at com.pnc.tsc.hca.ui.test.SiteCrawler.crawl(SiteCrawler.java:63) at com.pnc.tsc.hca.ui.test.SiteCrawler.crawl(SiteCrawler.java:54) at com.pnc.tsc.hca.ui.test.SiteCrawler.crawlSiteAsProvider(SiteCrawler.java:50) ... 15 more Caused by: java.lang.RuntimeException: java.io.IOException: The system cannot find the path specified at com.gargoylesoftware.htmlunit.html.XmlSerializer.getAttributesFor(XmlSerializer.java:165) at com.gargoylesoftware.htmlunit.html.XmlSerializer.printOpeningTag(XmlSerializer.java:126) at com.gargoylesoftware.htmlunit.html.XmlSerializer.printXml(XmlSerializer.java:83) at com.gargoylesoftware.htmlunit.html.XmlSerializer.printXml(XmlSerializer.java:93) at com.gargoylesoftware.htmlunit.html.XmlSerializer.printXml(XmlSerializer.java:93) at com.gargoylesoftware.htmlunit.html.XmlSerializer.asXml(XmlSerializer.java:73) at com.gargoylesoftware.htmlunit.html.XmlSerializer.save(XmlSerializer.java:55) at com.gargoylesoftware.htmlunit.html.HtmlPage.save(HtmlPage.java:2259) at com.pnc.tsc.hca.ui.util.GetUtil.save(GetUtil.java:126) ... 24 more Caused by: java.io.IOException: The system cannot find the path specified at java.io.WinNTFileSystem.createFileExclusively(Native Method) at java.io.File.createNewFile(File.java:883) at com.gargoylesoftware.htmlunit.html.XmlSerializer.createFile(XmlSerializer.java:216) at com.gargoylesoftware.htmlunit.html.XmlSerializer.getAttributesFor(XmlSerializer.java:160) ... 32 more Now, the parent directory exists and some other files have already been written to the directory. Looking at the filename, I don't see anything that would stand out as a red flag indicating the filename is bad. What can I do to correct this error? Thanks, Walter

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  • Downloading file from server (asp.net) to IE8 Content-Disposition problem with file name

    - by David
    I am downloading a file from the server/database via aspx page. When using the content-disposition inline the document opens in correct application but the file name is the same as the web page. I want the document to open in say MS Word but with the correct file name. Here is the code that I am using Response.Buffer = true; Response.ClearContent(); Response.ClearHeaders(); Response.Clear(); Response.ContentType = MimeType(fileName); //function to return the correct MIME TYPE Response.AddHeader("Content-Disposition", @"inline;filename=" + fileName); Response.AddHeader("Content-Length", image.Length.ToString()); Response.BinaryWrite(image); Response.Flush(); Response.Close(); So again, I want the file to open in MS Word with the correct document file name so that the user can properly save/view. Ideas? thanks

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  • ASP.NET file transfer from local machine to another machine

    - by Imcl
    I basically want to transfer a file from the client to the file storage server without actual login to the server so that the client cannot access the storage location on the server directly. I can do this only if i manually login to the storage server through windows login. I dont want to do that. This is a Web-Based Application. Using the link below, I wrote a code for my application. I am not able to get it right though, Please refer the link and help me ot with it... http://stackoverflow.com/questions/263518/c-uploading-files-to-file-server The following is my code:- protected void Button1_Click(object sender, EventArgs e) { filePath = FileUpload1.FileName; try { WebClient client = new WebClient(); NetworkCredential nc = new NetworkCredential(uName, password); Uri addy = new Uri("\\\\192.168.1.3\\upload\\"); client.Credentials = nc; byte[] arrReturn = client.UploadFile(addy, filePath); Console.WriteLine(arrReturn.ToString()); } catch (Exception ex) { Console.WriteLine(ex.Message); } } The following line doesn't execute... byte[] arrReturn = client.UploadFile(addy, filePath); This is the error I get: An exception occurred during a WebClient request

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  • Mercurial Editor: "abort: The system cannot find the file specified"

    - by Killroy
    I have a problem getting Mercurial to recognise my editor. I have a file, c:\windows\notepad.exe and typing "notepad" at the command prompt works. I can commit by using the "-m" argument to supply the commit title. But a simple "hg commit" brings up the error. A call to "hg --traceback commit" brings up: Traceback (most recent call last): File "mercurial\dispatch.pyc", line 47, in _runcatch File "mercurial\dispatch.pyc", line 466, in _dispatch File "mercurial\dispatch.pyc", line 336, in runcommand File "mercurial\dispatch.pyc", line 517, in _runcommand File "mercurial\dispatch.pyc", line 471, in checkargs File "mercurial\dispatch.pyc", line 465, in <lambda> File "mercurial\util.pyc", line 401, in check File "mercurial\commands.pyc", line 708, in commit File "mercurial\cmdutil.pyc", line 1150, in commit File "mercurial\commands.pyc", line 706, in commitfunc File "mercurial\localrepo.pyc", line 836, in commit File "mercurial\cmdutil.pyc", line 1155, in commiteditor File "mercurial\cmdutil.pyc", line 1184, in commitforceeditor File "mercurial\ui.pyc", line 361, in edit File "mercurial\util.pyc", line 383, in system File "subprocess.pyc", line 470, in call File "subprocess.pyc", line 621, in __init__ File "subprocess.pyc", line 830, in _execute_child WindowsError: [Error 2] The system cannot find the file specified abort: The system cannot find the file specified I've tried setting the HGEDITOR environment variable, setting "visual =" and "editor =" in the Mercurial.ini file. I tried full path as well as command only. I also tried copying the notepad.exe file into both the current folder as well as the mercurial folder. Ideally I would like to use the editor at this location "C:\PortableApps\Notepad++Portable\Notepad++Portable.exe", but at this stage I would be happy with any editor!

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  • Which type of file parsing easiest and efficient and good ?(html,pdf,csv,text)

    - by Harikrishna
    I want to parse the html file, pdf file, csv file and text file. Now parsing for which type of file (specified above) is easiest and efficient ? Like parsing for html file is easiest and efficient OR parsing for pdf file is easiest and efficient OR parsing for csv file is easiest and efficient ? I am asking this question because I want to parse pdf ,html ,csv and text file through common parsing code if possible. And now suppose if parsing for html is easiest and efficient then : I will write the parsing code for html file and will try to convert pdf file to the html file(if possible)so the code written for parsing html file will also work for pdf file also. And thus I will try to convert pdf,csv and text file to html file.And write the code for parsing html file and thus this code will parse html,pdf,csv and text file. Suppose if parsing for pdf is easiest and efficient then : I will convert html,csv and text file to pdf and write the code for parsing pdf file.So the code for parsing pdf file can parse html,csv and text file. So my question is (1) Which type of file parsing is easiest and efficient (pdf,csv,html,text) ? (2) And converting files(pdf,text,html,csv) to eachother is possible. Like if html parsing easiest then pdf to html,text to html and csv to html.

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  • Eclipse / Aptana File Sync Solutions

    - by Brad
    Our development team uses Eclipse + Aptana to do their web development work. Currently, most of them are mapping their Eclipse projects directly to the web server. I'd rather them create a local project and use that to sync to the web server project directory they are working on. The issue is that there aren't any good solutions which is just appalling given the popularity of the two. The FileSync plugin for Eclipse is only one-way. Meaning if another developer makes a change to the file on the server, another dev isn't even notified and could overwrite the change. The File Transfer option in Aptana 2.0 doesn't support any sort of Sync, just manually uploading/downloading files. The Sync option in Aptana 1.5.1 doesn't allow you to merge files when they are different. You can only update one or the other. It does however allow you to view a diff (but only if you right click and select) and in that diff you can't make any changes. I did find a way to allow files to be uploaded to their Sync repositories in Aptana using Eclipse Monkey. However it doesn't work if a user saves multiple files at once, 'Save All', again it doesn't work. And additionally, there is no notification if a user opens a local file that has an updated copy on the server. I tried to add one using Eclipse Monkey but I couldn't find any sort of listener in the Eclipse API to do it and any Eclipse Monkey documentation is far and few between. My only solution at this point is just to let them continue to map directly to the server or ask them to do a manual download before they do any work (but again what if someone uploads a change right after they do that). Anyone have any ideas?

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  • How to determine if a file will be logically moved or physically moved.

    - by Frederic Morin
    The facts: When a file is moved, there's two possibilities: The source and destination file are on the same partition and only the file system index is updated The source and destination are on two different file system and the file need to be moved byte per byte. (aka copy on move) The question: How can I determine if a file will be either logically or physically moved ? I'm transferring large files (700+ megs) and would adopt a different behaviors for each situation. Edit: I've already coded a moving file dialog with a worker thread that perform the blocking io call to copy the file a meg at a time. It provide information to the user like rough estimate of the remaining time and transfer rate. The problem is: how do I know if the file can be moved logically before trying to move it physically ?

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  • Dynamically created iframe used to download file triggers onload with firebug but not without

    - by justkt
    EDIT: as this problem is now "solved" to the point of working, I am looking to have the information on why. For the fix, see my comment below. I have an web application which repeatedly downloads wav files dynamically (after a timeout or as instructed by the user) into an iframe in order to trigger the a default audio player to play them. The application targets only FF 2 or 3. In order to determine when the file is downloaded completely, I am hoping to use the window.onload handler for the iframe. Based on this stackoverflow.com answer I am creating a new iframe each time. As long as firebug is enabled on the browser using the application, everything works great. Without firebug, the onload never fires. The version of firebug is 1.3.1, while I've tested Firefox 2.0.0.19 and 3.0.7. Any ideas how I can get the onload from the iframe to reliably trigger when the wav file has downloaded? Or is there another way to signal the completion of the download? Here's the pertinent code: HTML (hidden's only attribute is display:none;): <div id="audioContainer" class="hidden"> </div> JavaScript (could also use jQuery, but innerHTML is faster than html() from what I've read): waitingForFile = true; // (declared at the beginning of closure) $("#loading").removeClass("hidden"); var content = "<iframe id='audioPlayer' name='audioPlayer' src='" + /path/to/file.wav + "' onload='notifyLoaded()'></iframe>"; document.getElementById("audioContainer").innerHTML = content; And the content of notifyLoaded: function notifyLoaded() { waitingForFile = false; // (declared at beginning of the closure) $("#loading").addClass("hidden"); } I have also tried creating the iframe via document.createElement, but I found the same behavior. The onload triggered each time with firebug enabled and never without it. EDIT: Fixed the information on how the iframe is being declared and added the callback function code. No, no console.log calls here.

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  • Iterating through folders and files in batch file?

    - by Will Marcouiller
    Here's my situation. A project has as objective to migrate some attachments to another system. These attachments will be located to a parent folder, let's say "Folder 0" (see this question's diagram for better understanding), and they will be zipped/compressed. I want my batch script to be called like so: BatchScript.bat "c:\temp\usd\Folder 0" I'm using 7za.exe as the command line extraction tool. What I want my batch script to do is to iterate through the "Folder 0"'s subfolders, and extract all of the containing ZIP files into their respective folder. It is obligatory that the files extracted are in the same folder as their respective ZIP files. So, files contained in "File 1.zip" are needed in "Folder 1" and so forth. I have read about the FOR...DO command on Windows XP Professional Product Documentation - Using Batch Files. Here's my script: @ECHO OFF FOR /D %folder IN (%%rootFolderCmdLnParam) DO FOR %zippedFile IN (*.zip) DO 7za.exe e %zippedFile I guess that I would also need to change the actual directory before calling 7za.exe e %zippedFile for file extraction, but I can't figure out how in this batch file (through I know how in command line, and even if I know it is the same instruction "cd"). Anyone's help is gratefully appreciated.

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  • C# ASP.NET FILE TRANSFER FROM LOCAL MACHINE TO ANOTHER MACHINE

    - by Imcl
    I basically want to transfer a file from the client to the file storage server without actual login to the server so that the client cannot access the storage location on the server directly. I can do this only if i manually login to the storage server through windows login. I dont want to do that. This is a Web-Based Application. Using the link below, I wrote a code for my application. I am not able to get it right though, Please refer the link and help me ot with it... http://stackoverflow.com/questions/263518/c-uploading-files-to-file-server The following is my code:- protected void Button1_Click(object sender, EventArgs e) { filePath = FileUpload1.FileName; try { WebClient client = new WebClient(); NetworkCredential nc = new NetworkCredential(uName, password); Uri addy = new Uri("\\\\192.168.1.3\\upload\\"); client.Credentials = nc; byte[] arrReturn = client.UploadFile(addy, filePath); Console.WriteLine(arrReturn.ToString()); } catch (Exception ex) { Console.WriteLine(ex.Message); } } The following line doesn't execute... byte[] arrReturn = client.UploadFile(addy, filePath); THIS IS THE ERROR I GET :- "An exception occurred during a WebClient request"

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  • Choose a local file w/o uploading the chosen file

    - by Austin Hyde
    I am making a simple development tool for myself using PHP on my local development server. I would like a way to have a simple file-chooser to select a file without uploading it, but just retaining the file path. This is useful, because I will be the only one using the tool, and so PHP will have access to the chosen file without having it uploaded. My first thought is to have a <input type="file"...>, but as far as I know, there's no way to prevent the upload from happening. Is there a way to do this?

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  • icacls giving an error message "The System cannot Find the File Specified" When executed on folder

    - by someshine
    I have a remote share in windows 7 and accessing the same share from windows 2008. I have a small script in PHP which denys the read permission on a folder in a share and again give the full permissions on that folder in the share and deletes that folder .Here the Problem is "Denying the Read Permission is working fine and again assigning full permission on that folder in the share is not working .Iam using icacls for assigning all the permissions .When i try to assign the Full permission on that folder in the share It is giving error message "The system cannot find the file specified ".When we output the command from the script and execute it on commandline it is working fine .Why is it not working from my PHP script .Please Advise me $dir_name = "testdir"; $share_path = "\\SERVERABCD\myshare"; mkdir($share_path."\$dir_name"); $path_escaped = '"'.$path.'"'; $user = getenv('USERNAME'); $cmd = 'icacls ' . $path_escaped . ' /deny ' . $user . ':(OI)(CI)(R)'; exec($cmd); //From This statement it is giving error message "the System cannot find the file Specified" $cmd = 'icacls ' . $path_escaped . ' /remove:d' .' '. $user; exec($cmd); $cmd = 'icacls ' . $path_escaped . ' /grant ' . $user . ':(OI)(CI)(F)'; exec($cmd); if(file_exists($share_path."\$dir_name")){ rmdir($share_path."\$dir_name"); } ? //This Scripts Works Fine For Files on shares where as it says "The System cannot find the file specified" for folders from second $cmd statement .

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  • Sending a file over web service from java to .net

    - by Goran
    Hello, I have built .NET 1.1 Web Service which should accept files and save them. Here is the code of the webmethod: [WebMethod] public bool SaveDocument(Byte[] docbinaryarray, string docname) { string dirPath = @"C:\Temp\WSTEST\"; if(!Directory.Exists(dirPath)) { Directory.CreateDirectory(dirPath); } string filePath = dirPath + docname; FileStream objfilestream = new FileStream(filePath, FileMode.Create, FileAccess.ReadWrite); objfilestream.Write(docbinaryarray, 0, docbinaryarray.Length); objfilestream.Close(); return true; } When I make a client in .NET with reference to this Web service everything goes great, but when a college of mine tries to send me a file from a JAVA client I don't get the actuall file. All I get is byte array with only one element. Definition of byte array for file, in WSDL looks like this: <s:element minOccurs="0" maxOccurs="1" name="docbinaryarray" type="s:base64Binary" /> He sends me base64binary and fails every time. All I get is Byte array with only one element inside.

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  • using property file along with config file to be used with mxmlc

    - by whoopy_whale
    Hi, I'm trying to run mxmlc in the following manner. mxmlc -load-config+=mycfg.xml C:\\projects\\src\\main.mxml -output myswf.swf In the config file, I want to keep some values configurable, for example the paths of the external libraries. Is it possible to include a property file into the config file and use it as {property_name} in the config file? Or is it possible to pass certain arguments from the command line itself that will override/replace the corresponding values in the config file, like the -D option in the ant command? Please provide your suggestions.

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  • How to download .exe file with progress bar - VB 2012

    - by user2839828
    I am trying to create an updater for my program which automatically download's the latest version of my program from the web. Now I want this process to be done using a progress bar (so when the download progress is at 50% the progress bar is half-way through). This is my code: Private Sub client_ProgressChanged(ByVal sender As Object, ByVal e As DownloadProgressChangedEventArgs) Dim bytesIn As Double = Double.Parse(e.BytesReceived.ToString()) Dim totalBytes As Double = Double.Parse(e.TotalBytesToReceive.ToString()) Dim percentage As Double = bytesIn / totalBytes * 100 client.Value = Int32.Parse(Math.Truncate(percentage).ToString()) End Sub Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click Dim url As String = "MY DOWNLOAD LINK" 'Download Dim client As WebClient = New WebClient AddHandler client.DownloadProgressChanged, AddressOf client_ProgressChanged AddHandler client.DownloadFileCompleted, AddressOf client_DownloadCompleted client.DownloadFileAsync(New Uri(url), "C:\Users\User\Desktop\BACKUP\TESTING\New folder\1.exe") End Sub End Class Now I know that the place where the file is saved has been inputed manually by me , but I will change that later. My problem currently is that the file is not being downloaded. However when I change the DownloadFileAsync method to DownloadFile , my program downloads the file. However with the DownloadFile method I will not be able to use the progress bar to track the download progress. Any help is much appreciated :-)

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  • Trying to write a video file using OpenCV

    - by Ted pottel
    Hi , I’m trying to use OpenCV to write a video file. I have a simple program that loads frames from a video file then accepts to save them At first the cvCreateVideoWrite always return NULL. I got a answer from your group saying it returns separate images and to try to change the file name to test0001.png, this worked. But now the cvWriteFrame function always fails, the code is CString path; path="d:\\mice\\Test_Day26_2.avi"; CvCapture* capture = cvCaptureFromAVI(path); IplImage* img = 0; CvVideoWriter *writer = 0; int isColor = 1; int fps = 25; // or 30 int frameW = 640; // 744 for firewire cameras int frameH = 480; // 480 for firewire cameras writer=cvCreateVideoWriter("d:\\mice\\test0001.png",CV_FOURCC('P','I','M','1'), fps,cvSize(frameW,frameH),isColor); if (writer==0) MessageBox("could not open writter"); int nFrames = 50; for(int i=0;i<nFrames;i++){ if (!cvGrabFrame(capture)) MessageBox("could not grab frame"); img=cvRetrieveFrame(capture); // retrieve the captured frame if (img==0) MessageBox("could not retrive data"); if (!cvWriteFrame(writer,img) ) MessageBox("could not write frame"); } cvReleaseVideoWriter(&writer); Any help would be GREAT - Ted

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  • Sql Server Backup and move backup file: How to cope with file permissions?

    - by Stefan Steinegger
    With our product we have a simple backup tool for the sql server database. This tool should just make a full backup and restore to and from any folder. Of course, the user (usually an administrator) needs permission to write to the target folder. To avoid the problem of not being able to perform a backup to a network drive, I write the backup to a temp file in the Sql Server backup directory. Then I move it to the target folder. This requires permission to delete the temporary file from the sql servers backup folder. Restore is the same in the other direction. This seemed to work fine until someone tested it on vista, where the user does not have write access to the backup folder by default. So there are many solutions to solve this, but none of them seemed to be really nice. One solution would be to find another folder for the temporary file. Both the sql server user as well as the administrator performing the backup need read and write permissions. Is there such a directory? Any other ideas? Thanks a lot.

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