Search Results

Search found 7162 results on 287 pages for 'label printing'.

Page 73/287 | < Previous Page | 69 70 71 72 73 74 75 76 77 78 79 80  | Next Page >

  • Drupal 6: Printing Unadulterated Primary Links and all children...

    - by dcolumbus
    How in the WORLD is possible? I swear, I've read the equivalent of 3 encyclopedias to no avail. I've tried solutions within regions, page.tpl.php and blocks. None of them give me what I need... and I know there are so many other people that need this too! I've come to the conclusion that I want to print out the menu within my page.tpl.php ... so no block solutions, please. I want to be able to loop through the primary menu links (AND children) and rewrite the output so that there's no default Drupal class tagging. The closest I've found is this example: <?php if (is_array($primary_links)) : ?> <ul id="sliding-navigation"> <?php foreach ($primary_links as $link): ?> <li class="sliding-element"><?php $href = $link['href'] == "<front>" ? base_path() : base_path() . drupal_get_path_alias($link['href']); print "<a href='" . $href . "'>" . $link['title'] . "</a>"; ?></li> <?php endforeach; ?> </ul> <?php endif; ?> As you can see, links are being reprinted with a custom UL and LI class ... that's GREAT! However, no children are being printed. How would I extend this code so that all children are a part of the list? NOTE: I don't want the children to only appear on their parent page, they must be present all the time. Otherwise, the drop-down menu I have planned is useless. I sincerely thank you in advance to lessening my gargantuan headache!

    Read the article

  • Why is my program printing out the null termination character?

    - by Tyler Pfaff
    When I run this, it will SOMETIMES print out a null termination character. Most of the time it will, and probably 1/5 times it will print just the characters. void cryptogram::Encrypt(){ cout<<"encrypt"<tempS){ len=tempS.length(); int a=0; for(int j=0;j if(j!=len){ //if the word still has more characters j++; a=0; }else{ //if the word is done being scanned cout<<" "; } } } } } } } So that's it and this is the corresponding EXPECTED output that is printed SOMETIMES xvk bkikhxlr wggbtfkj wiylekgbdhx wjjm hko wigbtubxt xvk iwhj uedjkm glctb gvrmdiwhj iebbdielmeggtbx ctb xvtmk gbtubxvk wjjdxdthgbtubodll khvxvk imkbfdik xt xvk bkudth whj gbtfdjk hko tgxdthm whj tggtbxehdxdkm ctb mxejkhxmibdzdhtltur whj pemxdik mxejdkm mxdh cok wbk wlmt gbkgctb cteb hko zdh cgvrmdikjeiwhj qdhkmdtlturzzkjdydtivkzdmxbrw zdh zdjjlkkjeiwhj w jtixtbdh kjeiwjzdhdmxbittgkbodxv mjme whj eimj This is what normally prints though xvkÈ bkikhxlrÈ wggbtfkjÈ wiylekgbdhxÈ wjjmÈ hkoÈ wigbtubxtÈ xvkÈ iwhjÈ uedjkmÈ glctbÈ gvrmdiwhjÈ iebbdielmeggtbxÈ ctbÈ xvtmkÈ gbtubxvkÈ wjjdxdthgbtubodllÈ khvxvkÈ imkbfdikÈ xtÈ xvkÈ bkudthÈ whjÈ gbtfdjkÈ hkoÈ tgxdthmÈ whjÈ tggtbxehdxdkmÈ ctbÈ mxejkhxmibdzdhtlturÈ whjÈ pemxdikÈ mxejdkmÈ mxdhÈ cokÈ wbkÈ wlmtÈ gbkgctbÈ ctebÈ hkoÈ zdhÈ cgvrmdikjeiwhjÈ qdhkmdtlturzzkjdydtivkzdmxbrwÈ zdhÈ zdjjlkkjeiwhjÈ wÈ jtixtbdhÈ kjeiwjzdhdmxbittgkbodxvÈ mjmeÈ whjÈ eimj or some variation of an odd character at the end of each word This is what the cryptogram array is filled with by the way wyijkcuvdpqlzhtgabmxefonrs

    Read the article

  • HUD layer not being added on my scene

    - by Shailesh_ios
    I have a CCScene which already holds my gameLayer and I am trying to add HUD layer on that.But the HUD layer is not getting added in my scene, I can say that because I have set up a CCLabel on HUD layer and when I run my project, I cannot see that label. Here's what I am doing : In my gameLayer: +(id) scene { CCScene *scene = [CCScene node]; GameScreen *layer = [GameScreen node]; [scene addChild: layer]; HUDclass * otherLayer = [HUDclass node]; [scene addChild:otherLayer]; layer.HC = otherLayer;// HC is reference to my HUD layer in @Interface of gameLayer return scene; } And then in my HUD layer I have just added a CCLabelTTF in its init method like this : -(id)init { if ((self = [super init])) { CCLabelTTF * label = [CCLabelTTF labelWithString:@"IN WEAPON CLASS" fontName:@"Arial" fontSize:15]; label.position = ccp(240,160); [self addChild:label]; } return self; } But now when I run my project I dont see that label, What am I doing wrong here ..? Any Ideas.. ? Thanks in advance for your time.

    Read the article

  • Why is my code not printing anything to stdout?

    - by WM
    I'm trying to calculate the average of a student's marks: import java.util.Scanner; public class Average { public static void main(String[] args) { int mark; int countTotal = 0; // to count the number of entered marks int avg = 0; // to calculate the total average Scanner Scan = new Scanner(System.in); System.out.print("Enter your average: "); String Name = Scan.next(); while (Scan.hasNextInt()) { mark = Scan.nextInt(); countTotal++; avg = avg + ((mark - avg) / countTotal); } System.out.print( Name + " " + avg ); } }

    Read the article

  • Using .add() on the same widget more than once

    - by Dillon Gilmore
    I asked this question on Reddit and was directed here. http://www.reddit.com/r/Ubuntu/comments/vhadl/quickly_dynamic_ui/ Unfortunately I am having the same issue and the problems seems that you can only use .add() on a widget once. So here is my code, self.ui.labels = [] for titles in entries: label = Gtk.Label() self.ui.labels.append(label) self.ui.viewport1.add(self.ui.labels[-1]) self.ui.paned1.show_all() Now, for fun I decided "What would happen if I just manually did..." self.ui.viewport1.add(Gtk.Label()) self.ui.viewport1.add(Gtk.Button()) self.ui.viewport1.add(Gtk.Entry()) For my first code snippet I get this error, Gtk-CRITICAL **: gtk_viewport_add: assertion gtk_bin_get_child (bin) == NULL' failed The error happens an unknown amount of times because the list entries can vary in length, but for my second code snippet it happens exactly twice. This means that when I viewport1.add() it works the first time, but all adds after that receive the error above. So my question, is there a way in python to use .add() on the same widget more than once?

    Read the article

  • How to display image in second layer in Cocos2d

    - by PeterK
    I am very new at Cocos2d and is testing to displaying an image over the "Hello World" text on a second layer and need help to get it work. I guess it is some basic stuff here and appreciate any tips etc. with this. I know that if i put the display-code (myLayer1) in the "init" it work or do the call [self goHere] from the "init" in myLayer1 it works but i want to call the "goHere" directly. I have the following code: HelloWorld.m: #import "HelloWorldLayer.h" #import "myLayer1.h" // HelloWorldLayer implementation @implementation HelloWorldLayer +(CCScene *) scene { // 'scene' is an autorelease object. CCScene *scene = [CCScene node]; // 'layer' is an autorelease object. HelloWorldLayer *layer = [HelloWorldLayer node]; myLayer1 *layer1 = [myLayer1 node]; // add layer as a child to scene [scene addChild: layer]; [scene addChild: layer1]; // return the scene return scene; } // on "init" you need to initialize your instance -(id) init { // always call "super" init // Apple recommends to re-assign "self" with the "super" return value if( (self=[super init])) { // create and initialize a Label CCLabelTTF *label = [CCLabelTTF labelWithString:@"Hello World" fontName:@"Marker Felt" fontSize:64]; // ask director the the window size CGSize size = [[CCDirector sharedDirector] winSize]; // position the label on the center of the screen label.position = ccp( size.width /2 , size.height/2 ); // add the label as a child to this Layer [self addChild: label]; myLayer1 *a1 = [myLayer1 new]; [a1 goHere]; [myLayer1 release]; } return self; } myLayer1.m: #import "myLayer1.h" @implementation myLayer1 -(void)goHere { NSLog(@">>>>goHere<<<<"); CGSize size = [[CCDirector sharedDirector] winSize]; CCSprite *vv = [CCSprite spriteWithFile:@"hand.png"]; vv.position = ccp( size.width /2 , size.height/2 ); [self addChild:vv z:3]; } -(id) init { // always call "super" init // Apple recommends to re-assign "self" with the "super" return value if( (self=[super init])) { } return self; } @end

    Read the article

  • How do you prevent Git from printing 'remote:' on each line of the output of a post-recieve hook?

    - by Matt Hodan
    I recently configured an EC2 instance with a Git deployment workflow that resembles Heroku, but I can't seem to figure out how Heroku prevents the Git post-receive hook from outputting 'remote:' on each line. Consider the following two examples (one from my EC2 project and one from a Heroku project): My EC2 project: git push prod master Counting objects: 9, done. Delta compression using up to 2 threads. Compressing objects: 100% (5/5), done. Writing objects: 100% (5/5), 456 bytes, done. Total 5 (delta 3), reused 0 (delta 0) remote: remote: Receiving push remote: Deploying updated files (by resetting HEAD) remote: HEAD is now at bf17da8 test commit remote: Running bundler to install gem dependencies remote: Fetching source index for http://rubygems.org/ remote: Installing rake (0.8.7) remote: Installing abstract (1.0.0) ... remote: Installing railties (3.0.0) remote: Installing rails (3.0.0) remote: Your bundle is complete! It was installed into ./.bundle/gems remote: Launching (by restarting Passenger)... done remote: To ssh://[email protected]/~/apps/app_name e8bd06f..bf17da8 master -> master Heroku: $> git push heroku master Counting objects: 179, done. Delta compression using up to 2 threads. Compressing objects: 100% (89/89), done. Writing objects: 100% (105/105), 42.70 KiB, done. Total 105 (delta 53), reused 0 (delta 0) -----> Heroku receiving push -----> Rails app detected -----> Gemfile detected, running Bundler version 1.0.3 Unresolved dependencies detected; Installing... Using --without development:test Fetching source index for http://rubygems.org/ Installing rake (0.8.7) Installing abstract (1.0.0) ... Installing railties (3.0.0) Installing rails (3.0.0) Your bundle is complete! It was installed into ./.bundle/gems Compiled slug size is 4.8MB -----> Launching... done http://your_app_name.heroku.com deployed to Heroku To [email protected]:your_app_name.git 3bf6e8d..642f01a master -> master

    Read the article

  • php form doesnt submit one of the fields

    - by steve
    i have bought a template that have built in contact form problem is that it submits every thing except "company" name i have spent few hours messing around with it but cant get to work it. if you can point me to some solution i would be greatful thanks in advance this is contact form <form action="php/contact.php" method="post" id="contactform"> <ol> <li> <label for="name">your name <span class="red">*</span></label> <input id="name" name="name" class="text" /> </li> <li> <label for="email">Your email <span class="red">*</span></label> <input id="email" name="email" class="text" /> </li> <li> <label for="company">Company Name</label> <input id="company" name="company" class="text" /> </li> <li> <label for="subject">Subject</label> <input id="subject" name="subject" class="text" /> </li> <li> <label for="message">Message <span class="red">*</span></label> <textarea id="message" name="message" rows="6" cols="50"></textarea> </li> <li class="buttons"> <input type="image" name="imageField" id="imageField" src="images/button.jpg" /> </li> </ol> </form> this is java script <script type="text/javascript"> // <![CDATA[ jQuery(document).ready(function(){ $('#contactform').submit(function(){ var action = $(this).attr('action'); $.post(action, { name: $('#name').val(), email: $('#email').val(), company: $('#company').val(), subject: $('#subject').val(), message: $('#message').val() }, function(data){ $('#contactform #submit').attr('disabled',''); $('.response').remove(); $('#contactform').before('<p class="response">'+data+'</p>'); $('.response').slideDown(); if(data=='Thanks for your message, will contact you soon.') $('#contactform').slideUp(); } ); return false; }); }); // ]]> </script> this is php script if(!$_POST) exit; $email = $_POST['email']; //$error[] = preg_match('/\b[A-Z0-9._%-]+@[A-Z0-9.-]+.[A-Z]{2,4}\b/i', $POST['email']) ? '' : 'INVALID EMAIL ADDRESS'; if(!eregi("^[a-z0-9]+([\.-][a-z0-9]+)" ."@"."([a-z0-9]+([.-][a-z0-9]+))+"."\.[a-z]{2,}"."$",$email )){ $error.="Invalid email address entered"; $errors=1; } if($errors==1) echo $error; else{ $values = array ('name','email','message'); $required = array('name','email','message'); $your_email = "[email protected]"; $email_subject = "New Message: ".$_POST['subject']; $email_content = "new message:\n"; foreach($values as $key => $value){ if(in_array($value,$required)){ if ($key != 'subject' && $key != 'company') { if( empty($_POST[$value]) ) { echo 'Please fill in all required fields, marked with *'; exit; } } $email_content .= $value.': '.$_POST[$value]."\n"; } } if(@mail($your_email,$email_subject,$email_content)) { echo 'Thanks for your message, will contact you soon.'; } else { echo 'ERROR!'; } }

    Read the article

  • Launcher tooltip display issues

    - by Tudor
    I've just installed Ubuntu 12.04.1, and it seems that i have some issues with the launcher: if i hover the mouse on an icon, it shows an horizontal line instead of the icon's name. if i hover it again, then it will show me the correctly displayed name, in label and all. The thing is pretty annoying. First hover no label (just that line), second hover, label. Video drivers are installed ! Any thoughts? Thank you

    Read the article

  • Firefox and Chrome Display "top: -5px differently"

    - by Kevin
    Using Google Web Toolkit, I have a DIV parent with a DIV and anchor children. <div class="unseen activity"> <div class = "unseen-label"/> <a href .../> </div> With the following CSS, Chrome shows the "unseen label" slightly below the anchor. which is positioned correctly in both Chrome and FireFox. However, FireFox shows the label in line with the anchor. .unseen-activity div.unseen-label { display: inline-block; position: relative; top: -5px; } and .unseen-activity a { background: url('style/images/refreshActivity.png') no-repeat; background-position: 0 2px; height: 20px; overflow: hidden; margin-left: 10px; display: inline-block; margin-top: 2px; padding-left: 20px; padding-right: 10px; position: relative; top: 2px; } Please tell me how to change my CSS so that Chrome render the label centered to the anchor. However, I need to keep FireFox happy and rendered correctly.

    Read the article

  • JAVA Gui on Hello World [closed]

    - by user58892
    I am designing, implementing, testing, and debuging a GUI-based version of a “Hello, World!” program in a JFrame that includes a JLabel that reads “Hello, World!” and I am trying to use a layout manager, and an Exit button to close the program. Here's what I have so far, I would really apreciate if you could help on it syntax. I am 90% done but tried hard and it couldn't run. import java.awt.*; // Needed for flow layout manager import javax.swing.*; //All swing components live in the javax.swing package import javax.swing.JButton; //to recognize buttons import javax.swing.JFrame; import javax.swing.JPanel; import javax.swing.JTextField; public class HelloWorld { public static void main(String[] args) { //creates the label. The JLabel constructor //takes an optional argument which set the text of the label /* The text will be aligned with the center of the frame * otherwise it will align on the left. */ JLabel label= new JLabel("Hello World!"); new FlowWindow(); label.setHorizontalAlignment (SwingConstants.CENTER); JFrame frame = new JFrame("Hello"); //create exit button JButton button1 = new JButton("Exit"); //Add exit button to the content pane. add(button1); frame.add(label); frame.setSize(300, 300); frame.setVisible(true); frame.setLocationRelativeTo(null); frame.toFront(); } public static void FlowWindow() { //Add a new FlowLayout()); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); } }

    Read the article

  • Printf is not printing anything to output? C++ SDL

    - by Qasim
    I am trying to use "printf" in my Visual C++ project however it is not working. Using Lazy Foo's tutorial, I set up SDL in my project, but when I play it, printf doesnt do anything. #include "SDL.h" #include <stdio.h> int main( int argc, char* args[] ) { printf("Testing"); return 0; } The output looks like this: The program '[4664] SDL Testing.exe: Native' has exited with code 0 (0x0). And that's about it. What could be wrong?

    Read the article

  • printing menu in terminal and choosing an option, how to?

    - by carlos
    I'm a haskell beginner. I'm trying to make a program that shows a menu through terminal and ask user to introduce an option. Here is the code: main :: IO () main = do putStrLn "0 <- quit" putStrLn "1 <- Hello" putStr "Choose an option: " c <- getChar case c of '0' -> return () '1' -> putChar '\n' >> putStrLn "Hello World" >> main When I use this module in the ghci interpreter everything works like it's suposed to do. But if i compile this with: ghc hello.hs and run it in the terminal, it doesn't display the line "Choose an option:" before ask for a char to be introduced. I think this may be caused because of haskell lazy nature and I don't know how to fix it. Any ideas?

    Read the article

  • When I add meta:resourcekey to LinkButton it hides label contained in link button.

    - by Vinay Pandey
    For the code below:- <asp:LinkButton ID="lbtnTest" runat="server" CssClass="toolbar" CommandArgument="Test" meta:resourcekey="lbtnTest1" OnCommand="ChangeText"> <asp:Literal ID="litTest" Text="My Text" runat="server" meta:resourcekey="litTest" /> </asp:LinkButton> When I remove meta:resourcekey="lbtnTest1" from the link button then litTest is rendered properly whereas if I have meta:resourcekey="lbtnTest1" in link button it doesn't display text for litTest. Any idea what I am doing wrong here?

    Read the article

  • Google Analytics recording event based on <a> title attribute

    - by rlsaj
    I am declaring: var title = (typeof(el.attr('title')) != 'undefined' ) ? el.attr('title') :""; and then have the following: else if (title.match(/^"Matching Content"\:/i)) { elEv.category = "Matching Content Click"; elEv.action = "click-Matching-Content"; elEv.label = href.replace(/^https?\:\/\//i, ''); elEv.non_i = true; elEv.loc = href; } However, using Google Analytics debugger this is not being recorded. Any suggestions? The complete function is: if (typeof jQuery != 'undefined') { jQuery(document).ready(function gLinkTracking($) { var filetypes = /\.(avi|csv|dat|dmg|doc.*|exe|flv|gif|jpg|mov|mp3|mp4|msi|pdf|png|ppt.*|rar|swf|txt|wav|wma|wmv|xls.*|zip)$/i; var baseHref = ''; if (jQuery('base').attr('href') != undefined) baseHref = jQuery('base').attr('href'); jQuery('a').on('click', function (event) { var el = jQuery(this); var track = true; var href = (typeof(el.attr('href')) != 'undefined' ) ? el.attr('href') :""; var title = (typeof(el.attr('title')) != 'undefined' ) ? el.attr('title') :""; var isThisDomain = href.match(document.domain.split('.').reverse()[1] + '.' + document.domain.split('.').reverse()[0]); if (!href.match(/^javascript:/i)) { var elEv = []; elEv.value=0, elEv.non_i=false; if (href.match(/^mailto\:/i)) { elEv.category = "Email link"; elEv.action = "click-email"; elEv.label = href.replace(/^mailto\:/i, ''); elEv.loc = href; } else if (title.match(/^"Matching Content"\:/i)) { elEv.category = "Matching Content Click"; elEv.action = "click-Matching-Content"; elEv.label = href.replace(/^https?\:\/\//i, ''); elEv.non_i = true; elEv.loc = href; } else if (href.match(filetypes)) { var extension = (/[.]/.exec(href)) ? /[^.]+$/.exec(href) : undefined; elEv.category = "File Downloaded"; elEv.action = "click-" + extension[0]; elEv.label = href.replace(/ /g,"-"); elEv.loc = baseHref + href; } else if (href.match(/^https?\:/i) && !isThisDomain) { elEv.category = "External link"; elEv.action = "click-external"; elEv.label = href.replace(/^https?\:\/\//i, ''); elEv.non_i = true; elEv.loc = href; } else if (href.match(/^tel\:/i)) { elEv.category = "Telephone link"; elEv.action = "click-telephone"; elEv.label = href.replace(/^tel\:/i, ''); elEv.loc = href; } else track = false; if (track) { _gaq.push(['_trackEvent', elEv.category.toLowerCase(), elEv.action.toLowerCase(), elEv.label.toLowerCase(), elEv.value, elEv.non_i]); if ( el.attr('target') == undefined || el.attr('target').toLowerCase() != '_blank') { setTimeout(function() { location.href = elEv.loc; }, 400); return false; } } } }); }); }

    Read the article

  • Why is my program getting slower and slower ?

    - by RedWolf
    I'm using the program to send data from database to the Excel file . It works fine at the beginning and then becomes more and more slowly,finally it run out of the memory and the following error ocurrs: "java.lang.OutOfMemoryError: Java heap space...". The problem can be resolved by adding the jvm heap sapce.But the question is that it spends too much time to run out the program. After several minutes,it finished a loop with 4 seconds which can be finished with 0.5 seconds at the beginning . I can't found a solution to make it always run in a certain speed. Is it my code problem? Any clues on this? Here is the code: public void addAnswerRow(List<FinalUsers> finalUsersList,WritableWorkbook book){ if (finalUsersList.size() >0 ) { try { WritableSheet sheet = book.createSheet("Answer", 0); int colCount = 0; sheet.addCell(new Label(colCount++,0,"Number")); sheet.addCell(new Label(colCount++,0,"SchoolNumber")); sheet.addCell(new Label(colCount++,0,"District")); sheet.addCell(new Label(colCount++,0,"SchoolName")); sheet.setColumnView(1, 15); sheet.setColumnView(3, 25); List<Elements> elementsList = this.elementsManager.getObjectElementsByEduTypeAndQuestionnaireType(finalUsersList.get(0).getEducationType().getId(), this.getQuestionnaireByFinalUsersType(finalUsersList.get(0).getFinalUsersType().getId())); Collections.sort(elementsList, new Comparator<Elements>(){ public int compare(Elements o1, Elements o2) { for(int i=0; i< ( o1.getItemNO().length()>o2.getItemNO().length()? o2.getItemNO().length(): o1.getItemNO().length());i++){ if (CommonFun.isNumberic(o1.getItemNO().substring(0, o1.getItemNO().length()>3? 4: o1.getItemNO().length()-1)) && !CommonFun.isNumberic(o2.getItemNO().substring(0, o2.getItemNO().length()>3? 4: o2.getItemNO().length()-1))){ return 1; } if (!CommonFun.isNumberic(o1.getItemNO().substring(0, o1.getItemNO().length()>3? 4: o1.getItemNO().length()-1)) && CommonFun.isNumberic(o2.getItemNO().substring(0,o2.getItemNO().length()>3? 4:o2.getItemNO().length()-1))){ return -1; } if ( o1.getItemNO().charAt(i)!=o2.getItemNO().charAt(i) ){ return o1.getItemNO().charAt(i)-o2.getItemNO().charAt(i); } } return o1.getItemNO().length()> o2.getItemNO().length()? 1:-1; }}); for (Elements elements : elementsList){ sheet.addCell(new Label(colCount++,0,this.getTitlePre(finalUsersList.get(0).getFinalUsersType().getId(), finalUsersList.get(0).getEducationType().getId())+elements.getItemNO()+elements.getItem().getStem())); } int sheetRowCount =1; int sheetColCount =0; for(FinalUsers finalUsers : finalUsersList){ sheetColCount =0; sheet.addCell(new Label(sheetColCount++,sheetRowCount,String.valueOf(sheetRowCount))); sheet.addCell(new Label(sheetColCount++,sheetRowCount,finalUsers.getSchool().getSchoolNumber())); sheet.addCell(new Label(sheetColCount++,sheetRowCount,finalUsers.getSchool().getDistrict().getDistrictNumber().toString().trim())); sheet.addCell(new Label(sheetColCount++,sheetRowCount,finalUsers.getSchool().getName())); List<AnswerLog> answerLogList = this.answerLogManager.getAnswerLogByFinalUsers(finalUsers.getId()); Map<String,String> answerMap = new HashMap<String,String>(); for(AnswerLog answerLog :answerLogList ){ if (answerLog.getOptionsId() != null) { answerMap.put(answerLog.getElement().getItemNO(), this.getOptionsAnswer(answerLog.getOptionsId())); }else if (answerLog.getBlanks()!= null){ answerMap.put(answerLog.getElement().getItemNO(), answerLog.getBlanks()); }else{ answerMap.put(answerLog.getElement().getItemNO(), answerLog.getSubjectiveItemContent()); } } for (Elements elements : elementsList){ sheet.addCell(new Label(sheetColCount++,sheetRowCount,null==answerMap.get(elements.getItemNO())?"0":answerMap.get(elements.getItemNO()))); } sheetRowCount++; } book.write(); book.close(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (RowsExceededException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (WriteException e) { // TODO Auto-generated catch block e.printStackTrace(); } } }

    Read the article

  • How do i convert from milliseconds to seconds units to be shown in a Label?

    - by Doron Muzar
    I have this code: private void Form1_MouseWheel(object sender, MouseEventArgs e) { if (leave == true) { if (e.Delta > 0) { if (timer1.Interval < 5000) { timer1.Interval += 1000; label2.Text = (timer1.Interval/1000).ToString(); } } else { if (timer1.Interval == 1000) { timer1.Interval -= 100; label2.Text = (timer1.Interval / 1000).ToString(); } } } } The original timer1 interval in the designer is set to 1000 milliseconds. In the mouse wheel event i did that it will show in the label2 the untis in seconds. And indeed when i move the mouse wheel up its slowing the timer and show it in seconds 1 2 3 4 5 The problem is with the second part i wanted that when its getting to 1 second or 1000 milliseconds if i will keep wheel it down it will show the units in 100 and change the timer1.interval in 100 units. So in label2 if it was on 1 second so now i will see 900 800 700 600 500 un till 100. And also the timer1 interval should be change to 900 milliseconds 800 700 600 untill 100. When its get to 100 just stop there dont keep getting under 100. The problem is with this part: if (timer1.Interval == 1000) { timer1.Interval -= 100; label2.Text = (timer1.Interval / 1000).ToString(); } Its not working at all. EDIT** My code now: if (leave == true) { if (e.Delta > 0) { if (timer1.Interval < 5000) { timer1.Interval += 1000; label2.Text = (timer1.Interval / 1000).ToString(); } } else { if (timer1.Interval > 1000) { timer1.Interval -= 1000; label2.Text = (timer1.Interval / 1000).ToString(); } else if (timer1.Interval <= 1000 && timer1.Interval > 100) { timer1.Interval -= 100; label2.Text = (timer1.Interval / (double)1000).ToString(); } } } But now if i was at 5 seconds(5000 milliseconds) now i move the wheel back down its counting 5 4 3 2 1 0 and stop on 0 It dosent show under 1 ...0.9 0.8 0.7 as it did before.

    Read the article

  • What makes one language any better than another when both are designed for the same goals? [closed]

    - by Justin808
    I'm in the process of creating a grammar for a scripting language but as I'm working on it I started to wonder what makes a language good in the first place. I know the goals for my script but there are always 1000 different ways to go about doing things. Goals: Easy to use and understand (not my grandma could do it easy, but the secretary at the front desk could do it or the VP of marketing could do it type of easy) No user defined functions or subroutines. Its use would be in events of objects in a system similar to HyperCard. Conceptually I was thinking of a language like this: set myVariable to 'Hello World' set counter to 0 repeat 5 times with x begin set counter to counter add x end set myVariable to myVariable plus ' ' plus counter popup myVariable set text of label named 'label' to 'new text' set color of label named 'label' to blue The end result would popup a dialog with the contents Hello World 15 it would also change the text of a label and make it blue. But I could do the same thing 1000 different ways. So what makes one language any better than another when both are designed for the same goals?

    Read the article

  • Assembly: Why does jumping to a label that returns via ret cause a segmentation fault?

    - by Terribad
    Linux Assembly Tutorial states: there is one very important thing to remember: If you are planning to return from a procedure (with the RET instruction), don't jump to it! As in "never!" Doing that will cause a segmentation fault on Linux (which is OK – all your program does is terminate), but in DOS it may blow up in your face with various degrees of terribleness. But I cannot understand why does it causes a segmentation fault. it sounds just like returning from a function. I have a situation where I need to implement the logic "If X happens, call procedure A. Otherwise, call procedure B." Is there any other way than jumping around like a kangaroo weaving spaghetti code?

    Read the article

  • Errors not printing correctly..Is this logic flow correct? c++

    - by igor
    Example user input: PA1 9 //correct PJ1 9 //wrong, error printed "Invalid row" because it is not between A and I PA11 9 //wrong, error printer "Invalid column" because it is not between 1 and 9. The problem I am having is that it should clear the remaining input and then ask for the user to enter the "move" again, and it is not. Where did I go wrong? I've been at it for a while and still got no progress.. void clearInput() { cin.clear(); } bool getCoords(int & x, int & y) { char row; while(true){ cin>>row>>y; row=toupper(row); if(/*(id=='P' || id=='p' || id=='D' || id=='d') && */row>='A' && row<='I' && isalpha(row) && y>=1 && y<=9){ x=row-'A'; y=y-1; return true; } else if(!(y>=1 && y<=9)){ cout<<"Invalid column\n"<< endl << endl; cout<<y; clearInput(); cout<<y; //return false; } else{ cout<<"Invalid row\n"<< endl << endl; clearInput(); //cout<<x<<y; //return false; } } }

    Read the article

< Previous Page | 69 70 71 72 73 74 75 76 77 78 79 80  | Next Page >