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  • Script launching 3 copies of rsync

    - by organicveggie
    I have a simple script that uses rsync to copy a Postgres database to a backup location for use with Point In Time Recovery. The script is run every 2 hours via a cron job for the postgres user. For some strange reason, I can see three copies of rsync running in the process list. Any ideas why this might the case? Here's the cron entry: # crontab -u postgres -l PATH=/bin:/usr/bin:/usr/local/bin 0 */2 * * * /var/lib/pgsql/9.0/pitr_backup.sh And here's the ps list, which shows two copies of rsync running and one sleeping: # ps ax |grep rsync 9102 ? R 2:06 rsync -avW /var/lib/pgsql/9.0/data/ /var/lib/pgsql/9.0/backups/pitr_archives/20110629100001/ --exclude pg_xlog --exclude recovery.conf --exclude recovery.done --exclude pg_log 9103 ? S 0:00 rsync -avW /var/lib/pgsql/9.0/data/ /var/lib/pgsql/9.0/backups/pitr_archives/20110629100001/ --exclude pg_xlog --exclude recovery.conf --exclude recovery.done --exclude pg_log 9104 ? R 2:51 rsync -avW /var/lib/pgsql/9.0/data/ /var/lib/pgsql/9.0/backups/pitr_archives/20110629100001/ --exclude pg_xlog --exclude recovery.conf --exclude recovery.done --exclude pg_log And here's the uber simple script that seems to be the cause of the problem: #!/bin/sh LOG="/var/log/pgsql-pitr-backup.log" base_backup_dir="/var/lib/pgsql/9.0/backups" wal_archive_dir="$base_backup_dir/wal_archives" pitr_archive_dir="$base_backup_dir/pitr_archives" timestamp=`date +%Y%m%d%H%M%S` backup_dir="$pitr_archive_dir/$timestamp" mkdir -p $backup_dir echo `date` >> $LOG /usr/bin/psql -U postgres -c "SELECT pg_start_backup('$backup_dir');" rsync -avW /var/lib/pgsql/9.0/data/ $backup_dir/ --exclude pg_xlog --exclude recovery.conf --exclude recovery.done --exclude pg_log /usr/bin/psql -U postgres -c "SELECT pg_stop_backup();"

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  • django views question

    - by Hulk
    In my django views i have the following def create(request): query=header.objects.filter(id=a)[0] a=query.criteria_set.all() logging.debug(a.details) I get an error saying 'QuerySet' object has no attribute 'details' in the debug statement .What is this error and what should be the correct statemnt to query this.And the model corresponding to this is as follows where as the models has the following: class header(models.Model): title = models.CharField(max_length = 255) created_by = models.CharField(max_length = 255) def __unicode__(self): return self.id() class criteria(models.Model): details = models.CharField(max_length = 255) headerid = models.ForeignKey(header) def __unicode__(self): return self.id() Thanks..

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  • Creating form object for variable kind of form.

    - by Bunny Rabbit
    i want to create a form for users to submit questions in django ..so far the models i have created are class Question(models.Model): statement=models.CharField(max_length=100) class Choice(models.Model): statement=models.CharField(max_length=100) value=models.IntegerField() question=models.ForeignKey(Question) Now i want to write a Form class for creating a above form but the problem is the number of choices are variable,a user can decide how many choices a question must have .How do i do that in django?

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  • How to retrieve items from a django queryset?

    - by sharataka
    I'm trying to get the video element in a queryset but am having trouble retrieving it. user_channel = Everything.objects.filter(profile = request.user, playlist = 'Channel') print user_channel[0] #returns the first result without error print user_channel[0]['video'] #returns error Models.py: class Everything(models.Model): profile = models.ForeignKey(User) playlist = models.CharField('Playlist', max_length = 2000, null=True, blank=True) platform = models.CharField('Platform', max_length = 2000, null=True, blank=True) video = models.CharField('VideoID', max_length = 2000, null=True, blank=True) video_title = models.CharField('Title of Video', max_length = 2000, null=True, blank=True) def __unicode__(self): return u'%s %s %s %s %s' % (self.profile, self.playlist, self.platform, self.video, self.video_title)

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  • Finding object count where a field is unique in Django

    - by Johnd
    I have a model that is something like this: class Input(models.Model): details = models.CharField(max_length=1000) user = models.ForeignKey(User) class Case(Input): title = models.CharField(max_length=200) views = models.IntegerField() class Argument(Input): case = models.ForeignKey(Case) side = models.BooleanField() A user can submit many arguments, per case. I want to be able to say how many users have submitted side=true arguments. I mean if 1 user had 10 arguments and another user had 2 arguments (both side=true) I'd want the count to be 2, not 12.

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  • SQL SERVER – Fix : Error : 3117 : The log or differential backup cannot be restored because no files

    - by pinaldave
    I received the following email from one of my readers. Dear Pinal, I am new to SQL Server and our regular DBA is on vacation. Our production database had some problem and I have just restored full database backup to production server. When I try to apply log back I am getting following error. I am sure, this is valid log backup file. Screenshot is attached. [Few other details regarding server/ip address removed] Msg 3117, Level 16, State 1, Line 1 The log or differential backup cannot be restored because no files are ready to roll forward. Msg 3013, Level 16, State 1, Line 1 RESTORE LOG is terminating abnormally. Screenshot attached. [Removed as it contained live IP address] Please help immediately. Well I have answered this question in my earlier post, 2 years ago, over here SQL SERVER – Fix : Error : Msg 3117, Level 16, State 4 The log or differential backup cannot be restored because no files are ready to rollforward. However, I will try to explain it a little more this time. For SQL Server database to be used it should in online state. There are multiple states of SQL Server Database. ONLINE (Available – online for data) OFFLINE RESTORING RECOVERING RECOVERY PENDING SUSPECT EMERGENCY (Limited Availability) If the database is online, it means it is active and in operational mode. It will not make sense to apply further log from backup if the operations have continued on this database. The common practice during the backup restore process is to specify the keyword RECOVERY when the database is restored. When RECOVERY keyword is specified, the SQL Server brings back the database online and will not accept any further log backups. However, if you want to restore more than one backup files, i.e. after restoring the full back up if you want to apply further differential or log backup you cannot do that when database is online and already active. You need to have your database in the state where it can further accept the backup data and not the online data request. If the SQL Server is online and also accepts database backup file, then there can be data inconsistency. This is the reason that when there are more than one database backup files to be restored, one has to restore the database with NO RECOVERY keyword in the RESTORE operation. I suggest you all to read one more post written by me earlier. In this post, I explained the time line with image and graphic SQL SERVER – Backup Timeline and Understanding of Database Restore Process in Full Recovery Model. Sample Code for reference: RESTORE DATABASE AdventureWorks FROM DISK = 'C:\AdventureWorksFull.bak' WITH NORECOVERY; RESTORE DATABASE AdventureWorks FROM DISK = 'C:\AdventureWorksDiff.bak' WITH RECOVERY; In this post, I am not trying to cover complete backup and recovery. I am just attempting to address one type of error and its resolution. Please test these scenarios on the development server. Playing with live database backup and recovery is always very crucial and needs to be properly planned. Leave a comment here if you need help with this subject. Similar Post: SQL SERVER – Restore Sequence and Understanding NORECOVERY and RECOVERY Note: We will cover Standby Server maintenance and Recovery in another blog post and it is intentionally, not covered this post. Reference : Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, Readers Question, SQL, SQL Authority, SQL Backup and Restore, SQL Error Messages, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • TCO Models: Oracle invites you to the next webcast dedicated to Partners on Oracle Hardware and Solutions

    - by mseika
    The Oracle Hardware and Solutions Webcast Series is a sequence of one-hour Sales-Oriented Web Seminars, dedicated to Oracle Partners. This is your opportunity to learn about Oracle's Servers, Storage and Solutions strategy and portfolio, and their business value for you and your customers. The next appointment is for Wednesday, June 22, at 9am UKT / 10am CET:Total Cost of Ownership Models Examples: How we can sell Oracle HW and SW together, with better TCO, and benefits for both Oracle and the Partner!with Ilkka Vanhanen, Business Development Manager, Oracle EMEA Hardware Strategy Organization, who will talk about:   Concrete examples of the HW/SW TCO Model   Understand the competitive advantage provided by Oracle-on-Oracle Solutions   How Partners get new business from Oracle-on-Oracle Solutions   How Oracle is changing the game in Enterprise IT   Key benefits for both SW Resellers and HW Resellers   To register click here , then click on the “Servers and Solutions Webcasts” tab.          

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  • When using MVVM, should you create new viewmodels, or swap out the models?

    - by ConditionRacer
    Say I have a viewmodel like this: public class EmployeeViewModel { private EmployeeModel _model; public Color BackgroundColor { get; set; } public Name { get { return _model.Name; } set { _model.Name = value; NotifyPropertyChanged(Name); } } } So this viewmodel binds to a view that displays an employee. The thing to think about is, does this viewmodel represent an employee, or a "displayable" employee. The viewmodel contains some things that are view specific, for instance the background color. There can be many employees, but only one employee view. With this in mind, when changing the displayed employee, does it make sense to create a new EmployeeViewModel and rebind to the view, or simply swap out the EmployeeModel. Is the distinction even important, or is it a matter of style? I've always leaned toward creating new viewmodels, but I am working on a project where the viewmodels are created once and the models are swapped out. I'm not sure how I feel about this, though it seems to work fine.

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  • Windows xp recovery console without Ntfs.sys? (0x00000024 BSOD)

    - by Kalle
    I have two physical disks in a computer, for simlicity lets call them C and D. C: got Windows XP and D: got some data. The problem is that whenever i have D: connected i can't boot windows. I get some BSOD called 0x00000024/NTFS_FILE_SYSTEM. Same thing if i boot up windows with D: disconnected and then connect it once windows has loaded. The KB article about this problem says that i have to run chkdsk but i can't get to somewhere where i can run this because i get a BSOD whenever the disk is connected! Even the recovery-console BSODs if D: is connected. The final option in the KB is to boot the computer on Windows 2000 Setup disks where you edit some file to manually disable the ntfs.sys driver and then run chkdsk. The problem is that i don't have any floppy drive. Is there any way to boot the built in recovery console with ntfs.sys disabled or to burn the floppy version to a cd after you've extracted and modified it on the harddrive? Right now the Windows xp bootable floppy creator(2) is asking me which floppy drive to extract to which i can't answer because i have none :/ Other solutions to the root problem is also appreciated :) (2) ht tp://www.microsoft.com/downloads/details.aspx?FamilyID=55820edb-5039-4955-bcb7-4fed408ea73f&displaylang=en

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  • How to restart boot Windows 7 after upgrading to a SSHD on SONY VAIO with recovery discs?

    - by Boris Okun
    The original HDD on my Sony VAIO still works, but has a damaged sector 0 and I was constantly prompted to replace the HDD because of the imminent failure. I created recovery discs as instructed, used a USB external HDD for complete back up (including Windows image back up). After installing the SSHD and using recovery discs to upload Windows and boot, I am getting the Windows welcome screen. Right after that, I'm getting the following message: Windows couldn't complete the installation. To install Windows on this computer, restart the installation. I have tried repeating the process many times all kinds of different ways and I still receive the same message. Also, when I tried to change to partitioning as the other option offered, I get the message: Windows Setup could not configure Windows to run on this computer's hardware. All troubleshooting for hardware and PCU came out solid. I tried to load the image back up from the external drive, but can't load the driver. The computer doesn't see it. Does anyone have a clue or has encountered something similar?

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  • How can I tell System Restore in WIndows 7 recovery console to use my recovered backup drive's restore point data?

    - by Rich Shealer
    My Windows 7 desktop PC failed to boot. It would get to a grayish screen with a mouse and would only respond to the power button. After much examination I found that the problem was not a failed drive as running CHKDSK from the Recovery Console on my main drives passed without any errors. I had been installing various Java version in the days before the failure so I decided to use a restore point to roll backwards. I have an external SATA drive controller with two 2 TB drives mirrored using the Windows mirroring function. My system has been backing up to this drive regularly. The problem is I accidently broke the mirror when testing to see if this drive system might have been causing my boot issue. Connecting it to another machine showed two dynamic drives that were invalid. In the end I reformatted one as an NTFS basic disc and used recovery software on the other to copy all of the files to the reformatted drive. I had to copy the restore points into the new drive's System Volume Information folder by granting rights to that user. I moved the drive back to the original machine and rebooted. I can see my new drive, it even uses the same drive letter as it did in normal mode. Running System Restore it lists a new Automatic Restore point created while sitting at the RC along with all of my backups. Selecting the backup I want (or any other) I get a dialog. The backup drive could not be found. System Restore is looking for restore points on your backup. Make sure the backup drive is on and connected to this computer and then click OK. What do I need to do to allow system restore to see the restore points?

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  • Why the cucumber features keeps running even though it fails?

    - by Millisami
    Its a rails 2.3.5 app. I'm using the rspec and cucumber for testing. When I run autospec, it runs correctly with the warning (Not running features. To run features in autotest, set AUTOFEATURE=true.) as below: [~/rails_apps/automation (campaign)?] ? autospec (Not running features. To run features in autotest, set AUTOFEATURE=true.) (Not running features. To run features in autotest, set AUTOFEATURE=true.) loading autotest/rails_rspec /home/millisami/.rvm/rubies/ree-1.8.7-2010.01/lib/ruby/1.8/pathname.rb:263: warning: `*' interpreted as argument prefix /home/millisami/.rvm/rubies/ree-1.8.7-2010.01/bin/ruby /home/millisami/.rvm/gems/ree-1.8.7-2010.01/gems/rspec-1.3.0/bin/spec --autospec /home/millisami/rails_apps/automation/spec/controllers/campaigns_controller_spec.rb /home/millisami/rails_apps/automation/spec/models/board_spec.rb /home/millisami/rails_apps/automation/spec/models/user_spec.rb /home/millisami/rails_apps/automation/spec/models/campaign_spec.rb /home/millisami/rails_apps/automation/spec/controllers/outlets_controller_spec.rb /home/millisami/rails_apps/automation/spec/controllers/boards_controller_spec.rb /home/millisami/rails_apps/automation/spec/models/outlet_type_spec.rb /home/millisami/rails_apps/automation/spec/models/vendor_spec.rb /home/millisami/rails_apps/automation/spec/controllers/brands_controller_spec.rb /home/millisami/rails_apps/automation/spec/controllers/vendors_controller_spec.rb /home/millisami/rails_apps/automation/spec/controllers/dashboard_controller_spec.rb /home/millisami/rails_apps/automation/spec/models/brand_spec.rb /home/millisami/rails_apps/automation/spec/helpers/dashboard_helper_spec.rb /home/millisami/rails_apps/automation/spec/models/outlet_spec.rb /home/millisami/rails_apps/automation/spec/models/client_spec.rb /home/millisami/rails_apps/automation/spec/controllers/clients_controller_spec.rb -O spec/spec.opts Now, as it suggests, when I run AUTOFEATURE=true autospec, the specs runs and the cuke features as well. But the problem is that it won't stop. It runs the features and runs them again and again in a loop. It doesn't stop after it fails. Is this due to the warning Warning: $KCODE is NONE as shown below?? [~/rails_apps/automation (campaign)?] ? AUTOFEATURE=true autospec loading autotest/cucumber_rails_rspec Warning: $KCODE is NONE. /home/millisami/.rvm/gems/ree-1.8.7-2010.01/gems/treetop-1.4.5/lib/treetop/ruby_extensions/string.rb:31: warning: method redefined; discarding old indent /home/millisami/.rvm/rubies/ree-1.8.7-2010.01/lib/ruby/1.8/pathname.rb:263: warning: `*' interpreted as argument prefix /home/millisami/.rvm/gems/ree-1.8.7-2010.01/gems/activesupport-2.3.5/lib/active_support/core_ext/object/blank.rb:49: warning: method redefined; discarding old blank? /home/millisami/.rvm/rubies/ree-1.8.7-2010.01/bin/ruby /home/millisami/.rvm/gems/ree-1.8.7-2010.01/gems/rspec-1.3.0/bin/spec --autospec /home/millisami/rails_apps/automation/spec/controllers/campaigns_controller_spec.rb /home/millisami/rails_apps/automation/spec/models/board_spec.rb /home/millisami/rails_apps/automation/spec/models/user_spec.rb /home/millisami/rails_apps/automation/spec/models/campaign_spec.rb /home/millisami/rails_apps/automation/spec/controllers/outlets_controller_spec.rb /home/millisami/rails_apps/automation/spec/controllers/boards_controller_spec.rb /home/millisami/rails_apps/automation/spec/models/outlet_type_spec.rb /home/millisami/rails_apps/automation/spec/models/vendor_spec.rb /home/millisami/rails_apps/automation/spec/controllers/brands_controller_spec.rb /home/millisami/rails_apps/automation/spec/controllers/vendors_controller_spec.rb /home/millisami/rails_apps/automation/spec/controllers/dashboard_controller_spec.rb /home/millisami/rails_apps/automation/spec/models/brand_spec.rb /home/millisami/rails_apps/automation/spec/helpers/dashboard_helper_spec.rb /home/millisami/rails_apps/automation/spec/models/outlet_spec.rb /home/millisami/rails_apps/automation/spec/models/client_spec.rb /home/millisami/rails_apps/automation/spec/controllers/clients_controller_spec.rb -O spec/spec.opts

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  • Dynamic model choice field in django formset using multiple select elements

    - by Aryeh Leib Taurog
    I posted this question on the django-users list, but haven't had a reply there yet. I have models that look something like this: class ProductGroup(models.Model): name = models.CharField(max_length=10, primary_key=True) def __unicode__(self): return self.name class ProductRun(models.Model): date = models.DateField(primary_key=True) def __unicode__(self): return self.date.isoformat() class CatalogItem(models.Model): cid = models.CharField(max_length=25, primary_key=True) group = models.ForeignKey(ProductGroup) run = models.ForeignKey(ProductRun) pnumber = models.IntegerField() def __unicode__(self): return self.cid class Meta: unique_together = ('group', 'run', 'pnumber') class Transaction(models.Model): timestamp = models.DateTimeField() user = models.ForeignKey(User) item = models.ForeignKey(CatalogItem) quantity = models.IntegerField() price = models.FloatField() Let's say there are about 10 ProductGroups and 10-20 relevant ProductRuns at any given time. Each group has 20-200 distinct product numbers (pnumber), so there are at least a few thousand CatalogItems. I am working on formsets for the Transaction model. Instead of a single select menu with the several thousand CatalogItems for the ForeignKey field, I want to substitute three drop-down menus, for group, run, and pnumber, which uniquely identify the CatalogItem. I'd also like to limit the choices in the second two drop-downs to those runs and pnumbers which are available for the currently selected product group (I can update them via AJAX if the user changes the product group, but it's important that the initial page load as described without relying on AJAX). What's the best way to do this? As a point of departure, here's what I've tried/considered so far: My first approach was to exclude the item foreign key field from the form, add the substitute dropdowns by overriding the add_fields method of the formset, and then extract the data and populate the fields manually on the model instances before saving them. It's straightforward and pretty simple, but it's not very reusable and I don't think it is the right way to do this. My second approach was to create a new field which inherits both MultiValueField and ModelChoiceField, and a corresponding MultiWidget subclass. This seems like the right approach. As Malcolm Tredinnick put it in a django-users discussion, "the 'smarts' of a field lie in the Field class." The problem I'm having is when/where to fetch the lists of choices from the db. The code I have now does it in the Field's __init__, but that means I have to know which ProductGroup I'm dealing with before I can even define the Form class, since I have to instantiate the Field when I define the form. So I have a factory function which I call at the last minute from my view--after I know what CatalogItems I have and which product group they're in--to create form/formset classes and instantiate them. It works, but I wonder if there's a better way. After all, the field should be able to determine the correct choices much later on, once it knows its current value. Another problem is that my implementation limits the entire formset to transactions relating to (CatalogItems from) a single ProductGroup. A third possibility I'm entertaining is to put it all in the Widget class. Once I have the related model instance, or the cid, or whatever the widget is given, I can get the ProductGroup and construct the drop-downs. This would solve the issues with my second approach, but doesn't seem like the right approach.

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  • How to import classes into other classes within the same file in Python

    - by Chris
    I have the file below and it is part of a django project called projectmanager, this file is projectmanager/projects/models.py . Whenever I use the python interpreter to import a Project just to test the functionality i get a name error for line 8 that FileRepo() cannot be found. How Can I import these classes correctly? Ideally what I am looking for is each Project to contain multiple FileRepos which each contain and unknown number of files. Thanks for any assistance in advance. #imports from django.db import models from django.contrib import admin #Project is responsible for ensuring that each project contains all of the folders and file storage #mechanisms a project needs, as well as a unique CCL# class Project(models.Model): ccl = models.CharField(max_length=30) Techpacks = FileRepo() COAS = FileRepo() Shippingdocs = FileRepo() POchemspecs = FileRepo() Internalpos = FileRepo() Finalreports = FileRepo() Batchrecords = FileRepo() RFPS = FileRepo() Businessdev = FileRepo() QA = FileRepo() Updates = FileRepo() def __unicode__(self): return self.ccl #ProjectFile is the file object used by each FileRepo component class ProjectFile(models.Model): file = models.FileField(uploadto='ProjectFiles') def __unicode__(self): return self.file #FileRepo is the model for the "folders" to be used in a Project class FileRepo(models.Model): typeOf = models.CharField(max_length=30) files = models.ManyToManyField(ProjectFile) def __unicode__(self): return self.typeOf

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  • extending django usermodel

    - by imran-glt
    Hi i am trying to create a signup form for my django app. for this i have extended the user model. This is my Forms.py from contact.models import register from django import forms from django.contrib import auth class registerForm(forms.ModelForm): class Meta: model=register fields = ('latitude', 'longitude', 'status') class Meta: model = auth.models.User # this gives me the User fields fields = ('username', 'first_name', 'last_name', 'email') and this is my model.py from django.db import models from django.contrib.auth.models import User STATUS_CHOICES = ( ('Online', 'Online.'), ('Busy', 'Busy.'), ('AppearOffline', 'AppearOffline.'),) class register(models.Model): user = models.ForeignKey('auth.User', unique = True) latitude = models.DecimalField(max_digits=8, decimal_places=6) longitude = models.DecimalField(max_digits=8, decimal_places=6) status = models.CharField(max_length=8,choices=STATUS_CHOICES, blank= True, null=True) i dont know where i am making a mistake. the users passwords are not accepted at the login and the latitude and logitude are not saved against the created user user. i am fiarly new to django and dont know what to do any body have any solution .?

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  • django 1.1 beta issue

    - by ha22109
    Hello all, I m using django 1.1 beta.I m facing porblem in case of list_editable.First it was throughing exception saying need ordering in case of list_editable" then i added ordering in model but know it is giving me error.The code is working fine with django1.1 final. here is my code model.py class User(models.Model): advertiser = models.ForeignKey(WapUser,primary_key=True) status = models.CharField(max_length=20,choices=ADVERTISER_INVITE_STATUS,default='invited') tos_version = models.CharField(max_length=5) contact_email = models.EmailField(max_length=80) contact_phone = models.CharField(max_length=15) contact_mobile = models.CharField(max_length=15) contact_person = models.CharField(max_length=80) feedback=models.BooleanField(choices=boolean_choices,default=0) def __unicode__(self): return self.user.login class Meta: db_table = u'roi_advertiser_info' managed=False ordering=['feedback',] admin.py class UserAdmin(ReadOnlyAdminFields, admin.ModelAdmin): list_per_page = 15 fields = ['advertiser','contact_email','contact_phone','contact_mobile','contact_person'] list_display = ['advertiser','contact_email','contact_phone','contact_mobile','contact_person','status','feedback'] list_editable=['feedback'] readonly = ('advertiser',) search_fields = ['advertiser__login_id'] radio_fields={'approve_auto': admin.HORIZONTAL} list_filter=['status','feedback'] admin.site.register(User,UserADmin)

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  • Why is Django reverse() failing with unicode?

    - by JeffS
    Here is a django models file that is not working as I would expect. I would expect the to_url method to do the reverse lookup in the urls.py file, and get a url that would correspond to calling that view with arguments supplied by the Arguments model. from django.db import models class Element(models.Model): viewname = models.CharField(max_length = 200) arguments = models.ManyToManyField('Argument', null = True, blank = True ) @models.permalink def to_url(self): d = dict( self.arguments.values_list('key', 'value') ) return (self.viewname, (), d) class Argument(models.Model): key = models.CharField(max_length=200) value = models.CharField(max_length=200) The value d ends up as a dictionary from a unicode string to another unicode string, which I believe, should work fine with the reverse() method that would be called by the permalink decorator, however, it results in: TypeError: reverse() keywords must be strings

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  • django admin gives warning "Field 'X' doesn't have a default value"

    - by noam
    I have created two models out of an existing legacy DB , one for articles and one for tags that one can associate with articles: class Article(models.Model): article_id = models.AutoField(primary_key=True) text = models.CharField(max_length=400) class Meta: db_table = u'articles' class Tag(models.Model): tag_id = models.AutoField(primary_key=True) tag = models.CharField(max_length=20) article=models.ForeignKey(Article) class Meta: db_table = u'article_tags' I want to enable adding tags for an article from the admin interface, so my admin.py file looks like this: from models import Article,Tag from django.contrib import admin class TagInline(admin.StackedInline): model = Tag class ArticleAdmin(admin.ModelAdmin): inlines = [TagInline] admin.site.register(Article,ArticleAdmin) The interface looks fine, but when I try to save, I get: Warning at /admin/webserver/article/382/ Field 'tag_id' doesn't have a default value

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  • list editabale error

    - by ha22109
    Hello all, I m using django 1.1 beta.I m facing porblem in case of list_editable.First it was throughing exception saying need ordering in case of list_editable" then i added ordering in model but know it is giving me error.The code is working fine with django1.1 final. here is my code model.py class User(models.Model): advertiser = models.ForeignKey(WapUser,primary_key=True) status = models.CharField(max_length=20,choices=ADVERTISER_INVITE_STATUS,default='invited') tos_version = models.CharField(max_length=5) contact_email = models.EmailField(max_length=80) contact_phone = models.CharField(max_length=15) contact_mobile = models.CharField(max_length=15) contact_person = models.CharField(max_length=80) feedback=models.BooleanField(choices=boolean_choices,default=0) def __unicode__(self): return self.user.login class Meta: db_table = u'roi_advertiser_info' managed=False ordering=['feedback',] admin.py class UserAdmin(ReadOnlyAdminFields, admin.ModelAdmin): list_per_page = 15 fields = ['advertiser','contact_email','contact_phone','contact_mobile','contact_person'] list_display = ['advertiser','contact_email','contact_phone','contact_mobile','contact_person','status','feedback'] list_editable=['feedback'] readonly = ('advertiser',) search_fields = ['advertiser__login_id'] radio_fields={'approve_auto': admin.HORIZONTAL} list_filter=['status','feedback'] admin.site.register(User,UserADmin)

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  • Django save, column specified twice

    - by realshadow
    Hey, I would like to save a modified model, but I get Programming error - that a field is specified twice. class ProductInfo(models.Model): product_info_id = models.AutoField(primary_key=True) language_id = models.IntegerField() product_id = models.IntegerField() description = models.TextField(blank=True) status = models.IntegerField() model = models.CharField(max_length=255, blank=True) label = models.ForeignKey(Category_info, verbose_name = 'Category_info', db_column = 'language_id', to_field = 'node_id', null = True) I get this error because the foreign key uses as db_column language_id. If I will delete it, my object will be saved properly. I dont quite understand whats going on and since I have defined almost all of my models this way, I fear its totally wrong or maybe I just missunderstood it... Any ideas? Regards

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  • Prepopulate drop-box according to another drop-box choice in Django Admin

    - by onorua
    I have models like this: class User(models.Model): Switch = models.ForeignKey(Switch, related_name='SwitchUsers') Port = models.ForeignKey(Port) class Switch(models.Model): Name = models.CharField(max_length=50) class Port(models.Model): PortNum = models.PositiveIntegerField() Switch = models.ForeignKey(Switch, related_name = "Ports") When I'm in Admin interface and choose Switch from Switches available, I would like to have Port prepopulated accordingly with Ports from the related Switch. As far as I understand I need to create some JS script to prepopulate it. Unfortunately I don't have this experience, and I would like to keep things simple as it possible and don't rewrite all Django admin interface. Just add this functionality for one Field. Could you please help me with my problem? Thank you.

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  • Django: Geocoding an address on form submission?

    - by User
    Trying to wrap my head around django forms and the django way of doing things. I want to create a basic web form that allows a user to input an address and have that address geocoded and saved to a database. I created a Location model: class Location(models.Model): address = models.CharField(max_length=200) city = models.CharField(max_length=100) state = models.CharField(max_length=100, null=True) postal_code = models.CharField(max_length=100, null=True) country = models.CharField(max_length=100) latitude = models.DecimalField(max_digits=18, decimal_places=10, null=True) longitude = models.DecimalField(max_digits=18, decimal_places=10, null=True) And defined a form: class LocationForm(forms.ModelForm): class Meta: model = models.Location exclude = ('latitude','longitude') In my view I'm using form.save() to save the form. This works and saves an address to the database. I created a module to geocode an address. I'm not sure what the django way of doing things is, but I guess in my view, before I save the form, I need to geocode the address and set the lat and long. How do I set the latitude and longitude before saving?

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  • Trying and expand the contrib.auth.user model and add a "relatipnships" manage

    - by dotty
    I have the following model setup. from django.db import models from django.contrib.auth.models import User class SomeManager(models.Manager): def friends(self): # return friends bla bla bla class Relationship(models.Model): """(Relationship description)""" from_user = models.ForeignKey(User, related_name='from_user') to_user = models.ForeignKey(User, related_name='to_user') has_requested_friendship = models.BooleanField(default=True) is_friend = models.BooleanField(default=False) objects = SomeManager() relationships = models.ManyToManyField(User, through=Relationship, symmetrical=False) relationships.contribute_to_class(User, 'relationships') Here i take the User object and use contribute_to_class to add 'relationships' to the User object. The relationship show up, but if call User.relationships.friends it should run the friends() method, but its failing. Any ideas how i would do this? Thanks

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