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  • Do word boundaries work on symbol characters?

    - by Shawn31313
    I'm trying to implement word boundaries in my emoticons feature for a chat. But for some reason I can't seem to get the word boundaries to work. I am new to regex. So when I do: var reg = /\b\Hi\b/gi; var str = 'HiHiHi Hi HiHiHi Hi'; alert(str.replace(reg, '')); This happens: Jsfiddle It actually works fine, and does remove those 2 Hi's that are standing alone. But when I change the reg to an escaped smiley and then change the string: var reg = /\b\:\)\b/gi; var str = 'HiHi:) :) HiHiHi :)'; alert(str.replace(reg, '')); This happens: Jsfiddle It just doesn't work. The string stays the same. Is it that word boundaries can't be used on symbols? If so, how does Facebook do it on their chats?

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  • Question about regex in linux commands.

    - by smwikipedia
    I ran the following command at linux bash: apt-cache search hex.*(view|edit) My intention was to find any software packages whose name/description contains the pattern 'hex.*(view|edit)'. But among the results I got this: kipi-plugins - image manipulation/handling plugins for KIPI aware programs How could this be in the results list? I didn't see any matching string in this result. Is this a bug of the apt-cache search command? Or do I mis-understand how the regex is used by this command? Many thanks.

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  • Regular Expression to get the size value of a CSS property?

    - by thiesdiggity
    I wrote a regular expression to get the size from a CSS property: /(([+-]?\d*\.?\d+(\s)*(px|em|ex|pt|in|pc|mm|cm)?)|thin|medium|thick)(\s|;|$)/i but for some reason its not working as intended. For example, when I run the following: preg_match_all('/(([+-]?\d*\.?\d+(\s)*(px|em|ex|pt|in|pc|mm|cm)?)|thin|medium|thick)(\s|;|$)/i', "border-bottom:1px solid #99999;", $matches); It outputs: 1px 99999; But I only want the 1px value returned. I understand why its returning the above but can't seem to figure out how to only return the size and not the color value. I tried using the following negative lookbehind but it's not working either: /(((?<!#\d{3}|#\d{6})[+-]?\d*\.?\d+(\s)*(px|em|ex|pt|in|pc|mm|cm)?)|thin|medium|thick)(\s|;|$)/i I want to use preg_match_all for those CSS properties that can have multiple size values (i.e. margin). Anyone have any ideas how to get this regex to return only the size values? Thanks for your help!

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  • comma in regex in String.replaceAll() method?

    - by kknight
    My code tries to replace "," with "/" in a string. Should I escape "," in the regex string? Both of the two code snippets generated the same results, so I am confused. Code snippet 1: String test = "a,bc,def"; System.out.println(test.replaceAll("\\,", "/")); Code snippet 2: String test = "a,bc,def"; System.out.println(test.replaceAll(",", "/")); Should I use "," or "\,"? Which is safer? Thanks.

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  • RegularExpressionValidator always fails, but ValidationExpression works in testing

    - by Jerph
    I found the answer to this, but it's a bit of a gotcha so I wanted to share it here. I have a regular expression that validates passwords. They should be 7 to 60 characters with at least one numeric and one alpha character. Pretty standard. I used positive lookaheads (the (?= operator) to implement it: (?=^.{7,60}$)(?=.*[0-9].*)(?=.*[a-zA-Z].*) I checked this expression in my unit tests using Regex.IsMatch(), and it worked fine. However, when I use it in a RegularExpressionValidator, it always fails. Why?

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  • Need to create regular expression in Javascript to check the valid conditional string

    - by user1796078
    I want to create the regular expression in javascript which will check the valid conditional string like -1 OR (1 AND 2) AND 1 -1 OR (1 AND 2) -1 OR 2 -1 OR 1 OR 1 -1 AND 1 AND 1 The string should not contain 'AND' and 'OR'. For example - 1 OR 2 AND 3 is invalid. -It should be (1 OR 2) AND 3 or 1 or (2 AND 3). I tried the following Regex. It works for most of the conditions but it is failing to check the above condition. /^(\s*\(\d+\s(AND|OR)\s\d+\)|\s*\d+)((\s*(AND|OR)\s*)(\(\d+\s(AND|OR)\s\d+\)|\s*\d+))*$/ Can anyone please help me to sort out the above problem.

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  • .net equivalent for php preg_replace

    - by Hath
    What is the c#.net equivalent for php's preg_replace function? php code is like this: const ALLOW_VALUES = '[^a-z0-9àáâäèéêëìíîïòóôöùûwýÿyÁÂÄÈÉÊËÌÎÏÒÓÔÖÙÛÜWYÝ]'; public function streetTownHash($data, $hashCheck = false, $updateRecord = false) { foreach($data as $key=>$value){ try{ $value = mb_convert_case($value, MB_CASE_LOWER, "UTF-8"); } catch(Exception $e) { echo "Requires extension=php_mbstring.dll enabled ! - $e"; } $valueConcat .= preg_replace('/'.self::ALLOW_VALUES.'/','',$value); # Remove punctuation etc } $streetTownHash = sha1($valueConcat); .... this is as far as i've got but not sure about it.. private SHA1 hash = SHA1.Create(); private string hashAllowed = "[^a-z0-9àáâäèéêëìíîïòóôöùûwýÿyÁÂÄÈÉÊËÌÎÏÒÓÔÖÙÛÜWYÝ]"; public string HashString(string value) { value = // = regex not sure this part var bytes = ASCIIEncoding.UTF8.GetBytes(value); var hashed = hash.ComputeHash(bytes); return ASCIIEncoding.UTF8.GetString(hashed); }

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  • regular expression

    - by Altariste
    Hi, I need to find all invocations of some logging macros in the code. The macro invocation is of the form: DEBUG[1-5] ( "methodName: the logged message", arguments) But the new versions of the macros are prepending the name of the method automatically, so my task is to write a Python script that will remove the duplicate function names specified already by the programmer. I'm using the sub function from the re module. I plan to substitute the part indicated by || signs below : ||DEBUG[1-5] ("methodName: || the logged message", arguments) with simply DEBUG[1-5](" The problem is following: To find the expressions I want to substitute, I use the following regular expression: ((DEBUG | INFO | all other macros names )[1-5]*)\s*\(\"\w+: But it doesn't match the whole expression ( from DEBUG right to the colon ), but only the macro name, that is for example DEBUG5. Is my expression wrong or there is some quirk in the Python regex processing? ( maybe the fact that I use the DEBUG[1-5] as a subgroup has something to do with this? ) Help from anyone more knowledgable than me appreciated :).

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  • String contains all the elements of a list

    - by CSSS
    I am shifting to Python, and am still relatively new to the pythonic approach. I want to write a function that takes a string and a list and returns true if all the elements in the list occur in the string. This seemed fairly simple. However, I am facing some difficulties with it. The code goes something like this: def myfun(str,list): for a in list: if not a in str: return False return True Example : myfun('tomato',['t','o','m','a']) should return true myfun('potato',['t','o','m','a']) should return false myfun('tomato',['t','o','m']) should return true Also, I was hoping if someone could suggest a possible regex approach here. I am trying out my hands on them too.

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  • Why are regular expressions such a complicated, cryptic mess?

    - by steffenj
    Often when I see regular expressions, I only see a total mess of characters. Why does it have to be this way? I guess what I really want to know is: are there alternatives to regular expressions that basically do the same thing but are implemented in a human readable language? [UPDATE] Thanks for all the great responses and inspiration! I wanted to highlight this particular link which shows how a (working) alternative would look like, which may also be a good starting point for learning or "simple" regex expressions. But you also quickly get a feel for the verbosity tradeoff.

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  • Jquery Match() IP Address?

    - by user1635970
    I'm using a jquery script to validate form fields. This works well, but I'd like to change the validation of one field to check for IP Addresses. The regex I want to use is : \b(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\b How do I amend the below to work with this ? (This is how the validation works for email address) jQuery("#Email").validate({ expression: "if (VAL.match(/^[^\\W][a-zA-Z0-9\\_\\-\\.]+([a-zA-Z0-9\\_\\-\\.]+)*\\@[a-zA-Z0-9_]+(\\.[a-zA-Z0-9_]+)*\\.[a-zA-Z]{2,4}$/)) return true; else return false;", message: "Should be a valid Email id" });

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  • Search a string for certain numbers

    - by Hassan Gulzar
    Hello! I'm trying to come up with a lightning fast solution to find portions in a string. Here is a Sample string: "PostLoad successful! You transferred amount of 17.00 Rs to 03334224222. Now use PostLoad by dialing 123. PostLoad on SMS will end on 01-03-2011." Objective: Need to retrieve the bold values: Amount and Cell Number. The string contents change slightly but the cell number will always be a 11 digit. The amount is always with two decimal precision. Any suggestions using C# and RegEx?

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  • Searching for URL's Relative to Site Root in Javascript Source

    - by James
    Hi, I am working on a web site with several other developers and we have had problems where people commit JavaScript code with AJAX calls that use URL's relative to the site root. An example would be /Home/Index which will not work if the site is hosted in a virtual directory. To get round the problem we use a $.url() method to convert it to a full path, e.g. $("#container").load($.url("/Home/Index")) I am trying to write a unit test that will search each JavaScript file and find places where the $.url method is not being used. The only problem is that I cannot seem to write a regex expression to do this. I have tried the following: (?!\$\.url\()"(/\w*)+" But this does not work. I cannot find a way to say that I don't want the $.url in front. Does anyone know if this is possible? Note that I need regular expressions that are compatible with .NET Thanks.

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  • sip.conf configuration file - add new line to each record

    - by Flukey
    I have a sip configuration file which looks like this: [1664] username=1664 mailbox=1664@8360 host=192.168.254.3 type=friend subscribemwi=no [1679] username=1679 mailbox=1679@8360 host=192.168.254.3 type=friend subscribemwi=no [1700] username=1700 mailbox=1700@8360 host=192.168.254.3 type=friend subscribemwi=no [1701] username=1701 mailbox=1701@8360 host=192.168.254.3 type=friend subscribemwi=no For each record I need to add another line (vmxten for each record) for example the above becomes: [1664] username=1664 mailbox=1664@8360 host=192.168.254.3 type=friend subscribemwi=no vmexten=1664 [1679] username=1679 mailbox=1679@8360 host=192.168.254.3 type=friend subscribemwi=no vmexten=1679 [1700] username=1700 mailbox=1700@8360 host=192.168.254.3 type=friend subscribemwi=no vmexten=1700 [1701] username=1701 mailbox=1701@8360 host=192.168.254.3 type=friend subscribemwi=no vmexten=1701 What would you say would be the quickest way to do this? there are hundreds of records in the file, therefore modifying all of the records by hand would take a long time. Would you use Regex? Would you use sed? I'm interested to know how you would approach the problem. Thanks

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  • Get URL parameter function that gets value of url part or returns true if it's there but with no val

    - by LLer
    I'm using the following function to get a URL parameter. function gup(name, url) { name = name.replace(/[\[]/, '\\\[').replace(/[\]]/, '\\\]'); var results = new RegExp('[\\?&]'+name+'=?([^&#]*)').exec(url || window.location.href); return results == null ? null : results[1]; } It works only if the parameter has a value, for example. gup('a', 'http://example.com/page.php?a=1&b=2'); will return 1. But if I try gup('a', 'http://example.com/page.php?a&b=2'); It returns null. I want it to return true because parameter "a" exists in that url, even though it has no value it's still there and gup() should return true. Could I get a bit of help rewriting this? I'm not that good with regex.

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  • Substitute all matches with values in Ruby regular expression

    - by Lewisham
    Hi all, I'm having a problem with getting a Ruby string substitution going. I'm writing a preprocessor for a limited language that I'm using, that doesn't natively support arrays, so I'm hacking in my own. I have a line: x[0] = x[1] & x[1] = x[2] I want to replace each instance with a reformatted version: x__0 = x__1 & x__1 = x__2 The line may include square brackets elsewhere. I've got a regex that will match the array use: array_usage = /(\w+)\[(\d+)\]/ but I can't figure out the Ruby construct to replace each instance one by one. I can't use .gsub() because that will match every instance on the line, and replace every array declaration with whatever the first one was. .scan() complains that the string is being modified if you try and use scan with a .sub()! inside a block. Any ideas would be appreciated!

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  • Need help with regular expressions - URL redirection

    - by paperless
    Hello everyone. I'm trying to redirect an easy to remember url to a php file but I'm having some trouble with the regex. Here's what I have at the moment: RewriteRule ^tcb/([a-zA-Z0-9]{1,})/([a-zA-Z0-9]{1,})/([a-zA-Z0-9]{1,}) /tcb/lerbd.php?autocarro=$1&tipo=$2&dsd=$3 It is working but only if I supply all 3 arguments. I want the last two arguments to be optional so it either works with only the first or all three. I'm hoping you can help me with this. Thank you very much.

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  • replace \n and \r\n with <br /> in java

    - by Bala R
    This has been asked several times for several languages but I can't get it to work. I have a string like this String str = "This is a string.\nThis is a long string."; And I'm trying to replace the \n with <br /> using str = str.replaceAll("(\r\n|\n)", "<br />"); but the \n is not getting replaced. I tried to use this RegEx Tool to verify and I see the same result. The input string does not have a match for "(\r\n|\n)". What am i doing wrong ?

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  • [Bash] Save part of matching pattern to variable

    - by Ben
    I want to extract a substring matching a pattern and save it to a file. An example string: Apr 12 19:24:17 PC_NMG kernel: sd 11:0:0:0: [sdf] Attached SCSI removable disk I want to extract the part between the brackets, in this case []. I tried to do something like grep -e '[$subtext]' to save the text in the brackets to a variable. Of course it doesn't work, but I am looking for a way similar to this. It would be very elegant to include a variable in a regex like this. What can I do best? Thanks!

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  • Removing repeated characters, including spaces, in one line

    - by Thumper
    I currently have a string, say $line='55.25040882, 3,,,,,,', that I want to remove all whitespace and repeated commas and periods from. Currently, I have: $line =~ s/[.,]{2,}//; $line =~ s/\s{1,}//; Which works, as I get '55.25040882,3', but when I try $line =~ s/[.,\s]{2,}//; It pulls out the ", " and leaves the ",,,,,,". I want to retain the first comma and just get rid of the whitespace. Is there a way to elegantly do this with one line of regex? Please let me know if I need to provide additional information.

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  • Creating Slugs from Titles?

    - by James Jeffery
    I have everything in place to create slugs from titles, but there is one issue. My RegEx replaces spaces with hyphens. But when a user types "Hi     there" (multiple spaces) the slug ends up as "Hi-----there". When really it should be "Hi-there". Should I create the regular expression so that it only replaces a space when there is a character either side? Or is there an easier way to do this?

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  • @Path and regular expression (Jersey/REST)

    - by Castanho
    Hi there! I'm using Jersey in a REST project and I'm needing to use regular expression. Digging about it is simple like: @Path("/resources) public class MyResource { @GET @Path("{subResources:.*}/bar") public String get() {...} } But, I'm only capable of using regex if in my @Path contains a variable or text value, example: @Path("{SubResource1}/{subResources:.*}/bar") Or @Path("hardCodeString/{subResources:.*}/bar") Today I could run with this solution of a variable, but is not oK for my perspective. Question Does anyone have worked with something related? I'm doing something wrong? I think that this could be a bug, when working with more then one @Path, one in the Class and other in the Method. Any tips is appreciated! Regards

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  • Regex: Match opening/closing chars with spaces

    - by Israfel
    I'm trying to complete a regular expression that will pull out matches based on their opening and closing characters, the closest I've gotten is ^(\[\[)[a-zA-Z.-_]+(\]\]) Which will match a string such as "[[word1]]" and bring me back all the matches if there is more than one, The problem is I want it to pick up matchs where there may be a space in so for example "[[word1 word2]]", now this will work if I add a space into my pattern above however this pops up a problem that it will only get one match for my entire string so for example if I have a string "Hi [[Title]] [[Name]] [[surname]], How are you" then the match will be "[[Title]] [[Name]] [[surname]]" rather than 3 matches "[[Title]]", "[[Name]]", "[[surname]]". I'm sure I'm just a char or two away in the Regex but I'm stuck, How can I make it return the 3 matches. Thanks

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  • Invalid XML Replace Content in PHP

    - by streetparade
    I have a invalid XML like this Warning: count() [function.count]: Node no longer exists in /var/bla/test.php <?xml version="1.0" encoding="ISO-8859-1"?> <nodes> <some>test</some> </nodes> Now i need a regex which would replace the Warning: count() [function.count]: Node no longer exists in /var/bla/test.php with "" how can i do that? The above xml is is not generated on my localmachine, its a api call which returned a invalid xml

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  • Matching Word with regular expression

    - by lbar
    I have the following text file: ... "somewords MYWORD";123123123123 "someother MYWORDOTHER";456456456456 "somedifferent MYWORDDIFFERENT";789789789 ... i need to match the word MYWORD, MYWORDOTHER, MYWORDDIFFERENT and then substitute the space before this word with ";". Someone can figure out a regex? I have done something like that: +[^ ][^ ][^ ][^ ][^ ][^ ][^ ]"; but this works only with a specific word lenght. I need to modify to get any word of any leght. Any help? Thank you.

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