Android -- How to position View off-screen?
- by borg17of20
Hello all,
I'm trying to animate a simple ImageView in my application and I want it to slide in from the bottom of the screen and come to a resting position where the top 50px of the view is off the top of the screen (e.g. the final position of the ImageView should be -50px in X). I've tried to use the AbsoluteLayout to do this, but this actually cuts off the top 50px of the ImageView such that the top 50px is never rendered. I need to have the top 50px of the ImageView visible/rendered while it's animating and then simply have it come to a rest slightly off-screen. I hope I've explained that well enough.
Here is what I'm currently using as a layout and the slide-in animation (this currently doesn't render the top 50px of the ImageView):
Layout:
<?xml version="1.0" encoding="utf-8"?>
<AbsoluteLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_height="fill_parent"
android:layout_width="fill_parent"
android:id="@+id/QuickPlayClipLayout">
<ImageView android:id="@+id/Clip"
android:background="@drawable/clip"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:layout_y="-50dp">
</ImageView>
</AbsoluteLayout>
Animation:
<?xml version="1.0" encoding="utf-8"?>
<set xmlns:android="http://schemas.android.com/apk/res/android">
<translate android:fromYDelta="100%p"
android:toYDelta="0"
android:duration="1000"/>
<alpha android:fromAlpha="0.0"
android:toAlpha="1.0"
android:duration="1000" />
</set>
Thanks in advance.
