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  • Python language API

    - by Oscar Reyes
    Hello. I'm starting with Python coming from java. I was wondering if there exists something similar to JavaDoc API where I can find the class, its methods and and example of how to use it. I've found very helpul to use help( thing ) from the Python ( command line ) I have found this also: http://docs.python.org/ http://docs.python.org/modindex.html But it seems to help when you already the class name you are looking for. In JavaDoc API I have all the classes so if I need something I scroll down to a class that "sounds like" what I need. Or some times I just browse all the classes to see what they do, and when I need a feature my brain recalls me We saw something similar in the javadoc remember!? But I don't seem to find the similar in Python ( yet ) and that why I'm posting this questin. BTW I know that I would eventually will read this: http://docs.python.org/lib/lib.html But, well, I think it is not today.

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  • Hibernate Query Language Problem

    - by Sarang
    Well, I have implemented a distinct query in hibernate. It returns me result. But, while casting the fields are getting interchanged. So, it generates casting error. What should be the solution? As an example, I do have database, "ProjectAssignment" that has three fields, aid, pid & userName. I want all distinct userName data from this table. I have applied query : select distinct userName, aid, pid from ProjectAssignment Whereas the ProjectAssignment.java file has the fields in sequence aid, pid & userName. Now, here the userName is first field in output. So, Casting is not getting possible. Also, query : select aid, pid, distinct userName from ProjectAssignment is not working. What is the proper query for the same ? Or what else the solution ? The code is as below : System Utilization Service Bean Method where I have to retrieve data : public List<ProjectAssignment> getProjectAssignments() { projectAssignments = ProjectAssignmentHelper.getAllResources(); //Here comes the error return projectAssignments; } ProjectAssignmentHelper from where I fetch Data : package com.hibernate; import java.util.List; import org.hibernate.Query; import org.hibernate.Session; public class ProjectAssignmentHelper { public static List<ProjectAssignment> getAllResources() { List<ProjectAssignment> projectMasters; Session session = HibernateUtil.getSessionFactory().openSession(); Query query = session.createQuery("select distinct aid, pid, userName from ProjectAssignment"); projectMasters = (List<ProjectAssignment>) query.list(); session.close(); return projectMasters; } } Hibernate Data Bean : package com.hibernate; public class ProjectAssignment implements java.io.Serializable { private short aid; private String pid; private String userName; public ProjectAssignment() { } public ProjectAssignment(short aid) { this.aid = aid; } public ProjectAssignment(short aid, String pid, String userName) { this.aid = aid; this.pid = pid; this.userName = userName; } public short getAid() { return this.aid; } public void setAid(short aid) { this.aid = aid; } public String getPid() { return this.pid; } public void setPid(String pid) { this.pid = pid; } public String getUserName() { return this.userName; } public void setUserName(String userName) { this.userName = userName; } } Error : For input string: "userName" java.lang.NumberFormatException: For input string: "userName" at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48) at java.lang.Integer.parseInt(Integer.java:447) at java.lang.Integer.parseInt(Integer.java:497) at javax.el.ArrayELResolver.toInteger(ArrayELResolver.java:375) at javax.el.ArrayELResolver.getValue(ArrayELResolver.java:195) at javax.el.CompositeELResolver.getValue(CompositeELResolver.java:175) at com.sun.faces.el.FacesCompositeELResolver.getValue(FacesCompositeELResolver.java:72) at com.sun.el.parser.AstValue.getValue(AstValue.java:116) at com.sun.el.parser.AstValue.getValue(AstValue.java:163) at com.sun.el.ValueExpressionImpl.getValue(ValueExpressionImpl.java:219) at com.sun.faces.facelets.el.TagValueExpression.getValue(TagValueExpression.java:102) at javax.faces.component.ComponentStateHelper.eval(ComponentStateHelper.java:190) at javax.faces.component.ComponentStateHelper.eval(ComponentStateHelper.java:178) at javax.faces.component.UICommand.getValue(UICommand.java:218) at org.primefaces.component.commandlink.CommandLinkRenderer.encodeMarkup(CommandLinkRenderer.java:113) at org.primefaces.component.commandlink.CommandLinkRenderer.encodeEnd(CommandLinkRenderer.java:54) at javax.faces.component.UIComponentBase.encodeEnd(UIComponentBase.java:878) at org.primefaces.renderkit.CoreRenderer.renderChild(CoreRenderer.java:70) at org.primefaces.renderkit.CoreRenderer.renderChildren(CoreRenderer.java:54) at org.primefaces.component.datatable.DataTableRenderer.encodeTable(DataTableRenderer.java:525) at org.primefaces.component.datatable.DataTableRenderer.encodeMarkup(DataTableRenderer.java:407) at org.primefaces.component.datatable.DataTableRenderer.encodeEnd(DataTableRenderer.java:193) at javax.faces.component.UIComponentBase.encodeEnd(UIComponentBase.java:878) at org.primefaces.renderkit.CoreRenderer.renderChild(CoreRenderer.java:70) at org.primefaces.renderkit.CoreRenderer.renderChildren(CoreRenderer.java:54) at org.primefaces.component.tabview.TabViewRenderer.encodeContents(TabViewRenderer.java:198) at org.primefaces.component.tabview.TabViewRenderer.encodeMarkup(TabViewRenderer.java:130) at org.primefaces.component.tabview.TabViewRenderer.encodeEnd(TabViewRenderer.java:48) at javax.faces.component.UIComponentBase.encodeEnd(UIComponentBase.java:878) at javax.faces.component.UIComponent.encodeAll(UIComponent.java:1620) at javax.faces.render.Renderer.encodeChildren(Renderer.java:168) at javax.faces.component.UIComponentBase.encodeChildren(UIComponentBase.java:848) at javax.faces.component.UIComponent.encodeAll(UIComponent.java:1613) at javax.faces.component.UIComponent.encodeAll(UIComponent.java:1616) at javax.faces.component.UIComponent.encodeAll(UIComponent.java:1616) at com.sun.faces.application.view.FaceletViewHandlingStrategy.renderView(FaceletViewHandlingStrategy.java:380) at com.sun.faces.application.view.MultiViewHandler.renderView(MultiViewHandler.java:126) at com.sun.faces.lifecycle.RenderResponsePhase.execute(RenderResponsePhase.java:127) at com.sun.faces.lifecycle.Phase.doPhase(Phase.java:101) at com.sun.faces.lifecycle.LifecycleImpl.render(LifecycleImpl.java:139) at javax.faces.webapp.FacesServlet.service(FacesServlet.java:313) at org.apache.catalina.core.StandardWrapper.service(StandardWrapper.java:1523) at org.apache.catalina.core.ApplicationDispatcher.doInvoke(ApplicationDispatcher.java:802) at org.apache.catalina.core.ApplicationDispatcher.invoke(ApplicationDispatcher.java:664) at org.apache.catalina.core.ApplicationDispatcher.processRequest(ApplicationDispatcher.java:497) at org.apache.catalina.core.ApplicationDispatcher.doDispatch(ApplicationDispatcher.java:468) at org.apache.catalina.core.ApplicationDispatcher.dispatch(ApplicationDispatcher.java:364) at org.apache.catalina.core.ApplicationDispatcher.forward(ApplicationDispatcher.java:314) at org.apache.jasper.runtime.PageContextImpl.forward(PageContextImpl.java:783) at org.apache.jsp.welcome_jsp._jspService(welcome_jsp.java from :59) at org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:109) at javax.servlet.http.HttpServlet.service(HttpServlet.java:847) at org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:406) at org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:483) at org.apache.jasper.servlet.JspServlet.service(JspServlet.java:373) at javax.servlet.http.HttpServlet.service(HttpServlet.java:847) at org.apache.catalina.core.StandardWrapper.service(StandardWrapper.java:1523) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:279) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:188) at org.apache.catalina.core.StandardPipeline.invoke(StandardPipeline.java:641) at com.sun.enterprise.web.WebPipeline.invoke(WebPipeline.java:97) at com.sun.enterprise.web.PESessionLockingStandardPipeline.invoke(PESessionLockingStandardPipeline.java:85) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:185) at org.apache.catalina.connector.CoyoteAdapter.doService(CoyoteAdapter.java:332) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:233) at com.sun.enterprise.v3.services.impl.ContainerMapper.service(ContainerMapper.java:165) at com.sun.grizzly.http.ProcessorTask.invokeAdapter(ProcessorTask.java:791) at com.sun.grizzly.http.ProcessorTask.doProcess(ProcessorTask.java:693) at com.sun.grizzly.http.ProcessorTask.process(ProcessorTask.java:954) at com.sun.grizzly.http.DefaultProtocolFilter.execute(DefaultProtocolFilter.java:170) at com.sun.grizzly.DefaultProtocolChain.executeProtocolFilter(DefaultProtocolChain.java:135) at com.sun.grizzly.DefaultProtocolChain.execute(DefaultProtocolChain.java:102) at com.sun.grizzly.DefaultProtocolChain.execute(DefaultProtocolChain.java:88) at com.sun.grizzly.http.HttpProtocolChain.execute(HttpProtocolChain.java:76) at com.sun.grizzly.ProtocolChainContextTask.doCall(ProtocolChainContextTask.java:53) at com.sun.grizzly.SelectionKeyContextTask.call(SelectionKeyContextTask.java:57) at com.sun.grizzly.ContextTask.run(ContextTask.java:69) at com.sun.grizzly.util.AbstractThreadPool$Worker.doWork(AbstractThreadPool.java:330) at com.sun.grizzly.util.AbstractThreadPool$Worker.run(AbstractThreadPool.java:309) at java.lang.Thread.run(Thread.java:619)

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  • How to load language file in joomla component

    - by jax
    I am creating a joomla component and want to externalise all my strings. I created the appropriate .ini file in the languages folder but when I rum JText::_('TEST_DATA'); It just prints out nothing (could not find the string). How do I tell Joomla to look in the .ini file I created for the component?

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  • how to find difference between two timestamp using hibernate query language

    - by Shekhar
    Hello I am trying to write an hql query which gives me the number of hours between two timestamp. So, far i am unable to do this. I have used hql hour function but that does not work if the timestamp corresponds to different date. Please provide any input. My hql query is select count(*) from com.xxx.Request as request where request.id = :id and hour(current_timestamp - request.lastEventDate) :delay Thanks Shekhar

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  • How to split the story in indesing markup language

    - by BBDeveloper
    Hi All, I am learning indesign, I have a doubt in story splitting... I want to split the story if the same story is used in two different text frames, I am extracting idml file and getting the needed data. My question is, I have a single story which is used by two text frames (Threaded text), and these two textframes are available in two different spreads. Story.xml contains full story, half of the story is displayed in 1st textframe, next half is displayed in 2nd textframe and the same story ID is referred in both the textframes. Now I want to split this story into two, so I want to know that how much content of the story is added in 1st and 2nd textframe, I think if I find that how many characters or words or lines present in each textframe then it will easy to split the story. We can determine the word and character count using the following steps in indesign CS4 Place the insertion point in a text frame to view counts for the entire thread of frames (the story), or select text to view counts only for the selected text. Choose Window Info to display the Info panel. Is there any property or attribute in idml (xml files like prefrence.xml or story.xml or spread.xml) to find out the number of characters/words/lines of single textframe. Can anyone help me to solve this issue. Thanks in advance.

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  • finding the missing values in a range using any scripting language - perl, python or shell script

    - by manu
    Hi everyone I got stuck in one problem of finding the missing values in a range and the range is also variable for the successive rows. Ex. =================== inpt ==================== 673 673 673 676 676 680 2667 2667 2668 2670 2671 2674 ===================== output should be like this =================== 674 675 677 678 679 2669 2672 2673 ======================== This is just one part and the row values can be more also If there is any clarification plz let me know. thanx in advance manu

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  • CodeBlocks, GCC: change project language c and c++?

    - by user394242
    When I select console project to start with, it lets you select c or c++, but once its created.. i can't figure out where to change it, and when you create a win32 gui application, it doesn't give you the option at all, and its default is c++.. where can i change to c? i have been looking in all the project settings for AGES. renaming my file from cpp to .c doesn't seem to do anything, it compiles the file as cpp. i know that without the ide, you just change your exe from g++ to gcc, but how do i set this for the current project in codeblocks?

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  • Blackberry development on scripting language ?

    - by zvr
    From what I've seen, the preferred way to develop Blackberry applications is Java. Is this the only way? I'm dreaming of a rapid application environment where you can create GUIs (using the Blackberry UI components). Something like a port of Tcl/Tk on Blackberry... or Python/Tkinter... or something new, but similar. Does something like that exist ? (I doubt it) Can something like that exist ? (i.e., given the money, is it feasible/reasonable/...)

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  • Can you help with this assembly language code?

    - by Mugen
    Hi, I've been looking through a piece of code of a pc game that I'm trying to "improve". (ok so maybe I suck at the game but I still want to play it). Could you please look into the following code: fld dword ptr[ebp+00007B1C] fsub dword ptr[esp+64] fst dword ptr[ebp+00007B1C] call 004A2E48 This code is called every second for the level countdown timer. I need to stay on a particular level for a few minutes. If I can modify the above code so that the value pushed into the address [ebp+00007B1C] is 0 then the game level will always time out and it will save me playing those crazy "survival" minigames. I'll explain what I understand from this code. Dont worry, you dont have to go deep into this. In the first line we get the timer value. For example if 97 seconds are remaining then it is here that this value is loaded. In the second line a value (1 second) is subtracted from 97. In the third line 96 is again moved to memory. And finally we have the function call that will do other processing based on the time remaining. Now all I need to do is patch this piece of code somehow so that the value that is pushed is 0 (in the third step). Can you please help me out with this?

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  • Avoiding Mixup of Language Details

    - by DarenW
    Today someone asked me what was wrong with their source code. It was obvious. "Use double equals in place of that single equal in that if statement. Um, i think..." As i remember some languages actually take a single equals for comparison. Since i sometimes forget or mix up the syntax details among the several languages i use, i stepped over to my laptop to try a quickie experiment... It costs a bit of time and is a break in the flow to try "quick" experiments (though maybe the practice is good for memory.) What tips do you have for keeping straight in your mind the syntax (and other) details of multiple languages? (And nowadays, this applies just as well to the many wiki-like markups!)

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  • Fan Programming Language - Help

    - by baeltazor
    hey all, I'm creating an FWT application in FAN (http://www.fandev.org/) and every time I run my application, the ms-dos command prompt window appears (as well as my main application form). I don't want this ms-dos window to be shown, but i also don't know how to get rid of it, please help somebody :( it's giving me nightmares

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  • Object tree navigation language in Java

    - by lewap
    In the system which I'm currently developing I often have to navigate an object tree and based on its state and values take actions. In normal Java this results in tedious for loops, if statements etc... Are there alternative ways to achieve tree navigation, similar to XPath for XML? I know there is JXPath and OGNL, but do you know any other libraries for such purpose? Do you know any libraries which generate bytecodes for specific tree navigation expressions to make the processing as fast as Java native fors and ifs?

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  • Assembly language 8086

    - by rkrahu
    I v porblem in assembly 8086, I can't use 2D array when I m using like this mov ar[cx][dx] then arising error and when I want to us SI and DI both in arrary then also find error. I need answer quickly thanks for your help

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  • Which language to learn

    - by Pmarcoen
    I am fresh out of college, I'm pretty skilled in weblanguages like PHP, Perl, Javascript (JQuery). I have some basic skills in java, experienced c++ a little. People have been telling me c# is a good way to go because a lot of companies look for .NET developers. What would be a good next move for me ?

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  • Creating a directory in linux assembly language

    - by Jayson Kane
    I am trying to create a small assembly program to create a folder. I looked up the system call for creating a directory on this page: http://www.ctyme.com/intr/rb-8144.htm It says that it is identified by 27h. How would I go about implementing the "mkdir somename" in assembly? I am aware that the program should move 27 into eax but I am unsure where to go next. I have googled quite a bit and no one seems to have posted anthing about this online. This is my current code (I don't know in which register to put filename and so on) section .data section .text global _start mov eax, 27 mov ???????? .... int 80h Thanks

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  • Algorithm to Render a Horizontal Binary-ish Tree in Text/ASCII form

    - by Justin L.
    It's a pretty normal binary tree, except for the fact that one of the nodes may be empty. I'd like to find a way to output it in a horizontal way (that is, the root node is on the left and expands to the right). I've had some experience expanding trees vertically (root node at the top, expanding downwards), but I'm not sure where to start, in this case. Preferably, it would follow these couple of rules: If a node has only one child, it can be skipped as redundant (an "end node", with no children, is always displayed) All nodes of the same depth must be aligned vertically; all nodes must be to the right of all less-deep nodes and to the left of all deeper nodes. Nodes have a string representation which includes their depth. Each "end node" has its own unique line; that is, the number of lines is the number of end nodes in the tree, and when an end node is on a line, there may be nothing else on that line after that end node. As a consequence of the last rule, the root node should be in either the top left or the bottom left corner; top left is preferred. For example, this is a valid tree, with six end nodes (node is represented by a name, and its depth): [a0]------------[b3]------[c5]------[d8] \ \ \----------[e9] \ \----[f5] \--[g1]--------[h4]------[i6] \ \--------------------[j10] \-[k3] Which represents the horizontal, explicit binary tree: 0 a / \ 1 g * / \ \ 2 * * * / \ \ 3 k * b / / \ 4 h * * / \ \ \ 5 * * f c / \ / \ 6 * i * * / / \ 7 * * * / / \ 8 * * d / / 9 * e / 10 j (branches folded for compactness; * representing redundant, one-child nodes; note that *'s are actual nodes, storing one child each, just with names omitted here for presentation sake) (also, to clarify, I'd like to generate the first, horizontal tree; not this vertical tree) I say language-agnostic because I'm just looking for an algorithm; I say ruby because I'm eventually going to have to implement it in ruby anyway. Assume that each Node data structure stores only its id, a left node, and a right node. A master Tree class keeps tracks of all nodes and has adequate algorithms to find: A node's nth ancestor A node's nth descendant The generation of a node The lowest common ancestor of two given nodes Anyone have any ideas of where I could start? Should I go for the recursive approach? Iterative?

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  • How to counter the "one true language" perspective?

    - by Rob Wells
    How do you work with someone when they haven't been able to see that there is a range of other languages out there beyond "The One True Path"? I mean someone who hasn't realised that the modern software professional has a range of tools in his toolbox. The person whose knee jerk reaction is, for example, "We must do this is C++!" "Everything must be done in C++!" What's the best approach to open people up to the fact that "not everything is a nail"? How may I introduce them to having a well-equipped toolbox, selecting the best tool for the job at hand?

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  • Classic assembly language texts not using x86?

    - by wrp
    I'm looking for texts that give detailed treatment of assembly programming principles and don't use x86 as the target architecture. I haven't found any recent books like that, but I would expect that there were some good ones written in the 1970s and 1980s, when whole applications were still written in assembly. The architecture used should also be one of the cleaner designs, such as the 6502 or VAX.

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  • Is there a declarative language for data definitions?

    - by Jekke
    Reading about WPF and thinking about my application's data store at the same time led me to wonder if there are any languages or tools that allow you to define relational data in a declarative way? A shallow Google search suggests no such thing exists. Yet it seems so obviously useful. The kind of tool I have in mind would declaratively describe (at least) entities, relationships and views is a platform-agnostic way that would act as an abstraction layer between data-driven applications and their datastores. Does any such tool exist?

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  • assembly language programming (prime number)

    - by chris
    Prompt the user for a positive three digit number, then read it. Let's call it N. Divide into N all integer values from 2 to (N/2)+1 and test to see if the division was even, in which case N is instantly shown to be non-prime. Output a message printing N and saying that it is not prime. If none of those integer values divide evenly (remainder never is zero), then N is shown to be prime. Output a message printing N and saying that it is prime. Ask the user if he or she wants to test another number; if the user types "n" or "N", quit. If "y" or "Y", jump back and repeat. Comments in your code are essential. Hi. I am kinda in rush to do this.. please help me doing it. I'll be much appreciated. thank you

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