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  • Message Driven Bean with Java Message Queue down

    - by Rafa de Castro
    I have the following problem deploying my application. It uses JMS and a remote openMQ for communication between servers. The problem is that the connection is not fully reliable so it can be up or down. For reconnecting I set the jms reconnect glassfish property so it reconnects if at some moment the connection gets lost. The problem arises when i try to deploy the application and there is no connection. It looks like it keeps retrying the connection but the application does not finish deployment until connection is available. Is it possible to configure it in any way that the deployment continues even if there is no connection and keeps retrying until there is connection available? Thanks a lot.

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  • Servlet receives null from Remote EJB3 Session Bean

    - by Hank
    I'm sure this is a beginner error... So I have a JEE6 application with entities, facades (implementing the persistence layer) and Stateless Session Beans (EJB3) with Remote interfaces (providing access to the entities via facades). This is working fine. Via the SLSB I can retrieve and manipulate entities. Now, I'm trying to do this from a Web Application (deployed on the same Glassfish, entity+interface definitions from JEE app imported as separate jar). I have a Servlet, that receives an instance of the SLSB injected. I get it to retrieve an entity, and the following happens (I can see it in the logs): the remote SLSB gets instantiated, its method called SLSB instantiates the facade, calls the 'get' method facade retrieves object from DB, returns it SLSB returns the object to the caller (all is good until here) calling servlet receives .. null !! What is going wrong? This should work, right? MyServlet: public class MyServlet extends HttpServlet { @EJB private CampaignControllerRemote campaignController; // remote SLSB protected void processRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { response.setContentType("text/plain"); PrintWriter out = response.getWriter(); try { Campaign c = campaignController.getCampaign(5L); // id of an existing campaign out.println("Got "+ c.getId()); // c is null !! } finally { out.close(); } } ... } Pls let me know if you want to see other code, and I'll update the post.

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  • Exposing model object using bindings in custom NSCell of NSTableView

    - by Hooligancat
    I am struggling trying to perform what I would think would be a relatively common task. I have an NSTableView that is bound to it's array via an NSArrayController. The array controller has it's content set to an NSMutableArray that contains one or more NSObject instances of a model class. What I don't know how to do is expose the model inside the NSCell subclass in a way that is bindings friendly. For the purpose of illustration, we'll say that the object model is a person consisting of a first name, last name, age and gender. Thus the model would appear something like this: @interface PersonModel : NSObject { NSString * firstName; NSString * lastName; NSString * gender; int * age; } Obviously the appropriate setters, getters init etc for the class. In my controller class I define an NSTableView, NSMutableArray and an NSArrayController: @interface ControllerClass : NSObject { IBOutlet NSTableView * myTableView; NSMutableArray * myPersonArray; IBOutlet NSArrayController * myPersonArrayController; } Using Interface Builder I can easily bind the model to the appropriate columns: myPersonArray --> myPersonArrayController --> table column binding This works fine. So I remove the extra columns, leaving one column hidden that is bound to the NSArrayController (this creates and keeps the association between each row and the NSArrayController) so that I am down to one visible column in my NSTableView and one hidden column. I create an NSCell subclass and put the appropriate drawing method to create the cell. In my awakeFromNib I establish the custom NSCell subclass: PersonModel * aCustomCell = [[[PersonModel alloc] init] autorelease]; [[myTableView tableColumnWithIdentifier:@"customCellColumn"] setDataCell:aCustomCell]; This, too, works fine from a drawing perspective. I get my custom cell showing up in the column and it repeats for every managed object in my array controller. If I add an object or remove an object from the array controller the table updates accordingly. However... I was under the impression that my PersonModel object would be available from within my NSCell subclass. But I don't know how to get to it. I don't want to set each NSCell using setters and getters because then I'm breaking the whole model concept by storing data in the NSCell instead of referencing it from the array controller. And yes I do need to have a custom NSCell, so having multiple columns is not an option. Where to from here? In addition to the Google and StackOverflow search, I've done the obligatory walk through on Apple's docs and don't seem to have found the answer. I have found a lot of references that beat around the bush but nothing involving an NSArrayController. The controller makes life very easy when binding to other elements of the model entity (such as a master/detail scenario). I have also found a lot of references (although no answers) when using Core Data, but Im not using Core Data. As per the norm, I'm very grateful for any assistance that can be offered!

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  • MVVM View Model DTOs

    - by Burt
    I have a WCF based application that uses the services to access repositories on the server side. I am passing DTOs from the server to the client and was wondering how best to make the DTOs part pf the view model. I have a workign example of just plain properties on the view model but was unsure how to deal with actual DTO objects and any possible conversion between the DTO and the Vview model properties.

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  • Making only a part of model field available in Django

    - by Hellnar
    Hello I have a such model: GENDER_CHOICES = ( ('M', 'Male'), ('F', 'Female') ) class Profile(models.Model): user = models.ForeignKey(User) gender = models.CharField(max_length=1, choices=GENDER_CHOICES) class FrontPage(models.Model): female = models.ForeignKey(User,related_name="female") male = models.ForeignKey(User,related_name="male") Once I attempt to add a new FrontPage object via the Admin page, I can select "Female" profiles for the male field of FrontPage, how can I restrict that? Thanks

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  • django model Form. Include fields from related models

    - by Tom
    Hi. I have a model, called Student, which has some fields, and a OneToOne relationship with user (django.contrib.auth.User). class Student(models.Model): phone = models.CharField(max_length = 25 ) birthdate = models.DateField(null=True) gender = models.CharField(max_length=1,choices = GENDER_CHOICES) city = models.CharField(max_length = 50) personalInfo = models.TextField() user = models.OneToOneField(User,unique=True) Then, I have a ModelForm for that model class StudentForm (forms.ModelForm): class Meta: model = Student Using the fields attribute in class Meta, i've managed to show only some fields in a template. However, can I indicate which user fields to show? Something as: fields =('personalInfo','user.username') is currently not showing anything. Works with only StudentFields though/ Thanks in advance.

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  • How to customize pickle for django model objects

    - by muudscope
    I need to pickle a complex object that refers to django model objects. The standard pickling process stores a denormalized object in the pickle. So if the object changes on the database between pickling and unpickling, the model is now out of date. (I know this is true with in-memory objects too, but the pickling is a convenient time to address it.) So what I'd like is a way to not pickle the full django model object. Instead just store its class and id, and re-fetch the contents from the database on load. Can I specify a custom pickle method for this class? I'm happy to write a wrapper class around the django model to handle the lazy fetching from db, if there's a way to do the pickling.

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  • Referencing Entity from external data model - Core Data

    - by Ben Reeves
    I have a external library which includes a core data model, I would like to add a new entity to this model which has a relationship with one of the entities from the library. I know I could modify the original, but is there a way to without needing to pollute the library? I tried just creating a new model with an entity named the same, but that doesn't work: * Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: 'Can't merge models with two different entities named 'Host''

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  • Alternate datasource for django model?

    - by slypete
    I'm trying to seamlessly integrate some legacy data into a django application. I would like to know if it's possible to use an alternate datasource for a django model. For example, can I contact a server to populate a list of a model? The server would not be SQL based at all. Instead it uses some proprietary tcp based protocol. Copying the data is not an option, as the legacy application will continue to be used for some time. Would a custom manager allow me to do this? This model should behave just like any other django model. It should even pluggable to the admin interface. What do you think? Thanks, Pete

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  • Model associations

    - by Kalyan M
    I have two models Library and Book. In my Library model, I have an array - book_ids. The primary key of Book model is ID. How do I create a has_many :books relation in my library model? This is a legacy database we are using with rails. Thanks.

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  • Dynamic model choice field in django formset using multiple select elements

    - by Aryeh Leib Taurog
    I posted this question on the django-users list, but haven't had a reply there yet. I have models that look something like this: class ProductGroup(models.Model): name = models.CharField(max_length=10, primary_key=True) def __unicode__(self): return self.name class ProductRun(models.Model): date = models.DateField(primary_key=True) def __unicode__(self): return self.date.isoformat() class CatalogItem(models.Model): cid = models.CharField(max_length=25, primary_key=True) group = models.ForeignKey(ProductGroup) run = models.ForeignKey(ProductRun) pnumber = models.IntegerField() def __unicode__(self): return self.cid class Meta: unique_together = ('group', 'run', 'pnumber') class Transaction(models.Model): timestamp = models.DateTimeField() user = models.ForeignKey(User) item = models.ForeignKey(CatalogItem) quantity = models.IntegerField() price = models.FloatField() Let's say there are about 10 ProductGroups and 10-20 relevant ProductRuns at any given time. Each group has 20-200 distinct product numbers (pnumber), so there are at least a few thousand CatalogItems. I am working on formsets for the Transaction model. Instead of a single select menu with the several thousand CatalogItems for the ForeignKey field, I want to substitute three drop-down menus, for group, run, and pnumber, which uniquely identify the CatalogItem. I'd also like to limit the choices in the second two drop-downs to those runs and pnumbers which are available for the currently selected product group (I can update them via AJAX if the user changes the product group, but it's important that the initial page load as described without relying on AJAX). What's the best way to do this? As a point of departure, here's what I've tried/considered so far: My first approach was to exclude the item foreign key field from the form, add the substitute dropdowns by overriding the add_fields method of the formset, and then extract the data and populate the fields manually on the model instances before saving them. It's straightforward and pretty simple, but it's not very reusable and I don't think it is the right way to do this. My second approach was to create a new field which inherits both MultiValueField and ModelChoiceField, and a corresponding MultiWidget subclass. This seems like the right approach. As Malcolm Tredinnick put it in a django-users discussion, "the 'smarts' of a field lie in the Field class." The problem I'm having is when/where to fetch the lists of choices from the db. The code I have now does it in the Field's __init__, but that means I have to know which ProductGroup I'm dealing with before I can even define the Form class, since I have to instantiate the Field when I define the form. So I have a factory function which I call at the last minute from my view--after I know what CatalogItems I have and which product group they're in--to create form/formset classes and instantiate them. It works, but I wonder if there's a better way. After all, the field should be able to determine the correct choices much later on, once it knows its current value. Another problem is that my implementation limits the entire formset to transactions relating to (CatalogItems from) a single ProductGroup. A third possibility I'm entertaining is to put it all in the Widget class. Once I have the related model instance, or the cid, or whatever the widget is given, I can get the ProductGroup and construct the drop-downs. This would solve the issues with my second approach, but doesn't seem like the right approach.

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  • Django - Better evaluation of relationship at the model level

    - by Brant
    Here's a simple relational pair of models. class Shelf(models.Model): name = models.CharField(max_length=100) def has_books(self): if Book.objects.filter(shelf=self): return True else: return False class Book(models.Model): shelf = models.ForeignKey(Shelf) name = models.CharField(max_length=100) Is there a better (or alternative) way to write the "has_book" method? I'm not a fan of the double database hit but I want to do this at the model level.

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  • Logging from symfony's model layer

    - by naag
    I'm currently working on a project with symfony 1.4 and Doctrine 1.2. I'm looking for a proper way to do logging from the model layer. In some model classes I use the record hook postSave() to create a ZIP file using exec() (since PHP zip doesn't provide for storage method 'Stored'). To be sure that everythings works fine I check the return code and log an error if something goes wrong. My first naive approach was to do it like this: if ($returnCode != 0) { sfContext::getInstance()->getLogger()->debug(...); } As you know, this doesn't work so well because sfContext belongs to the controller layer and shouldn't be used from the model layer. My next try was to use the model's constructor to pass in an sfLogger instance, but this doesn't work due to Doctrine 1.2 reserving the constructor for internal use (Doctrine 1.2 Documentation). I'm looking forward for your suggestions!

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  • Learning MVC - Maintaining model state

    - by GenericTypeTea
    First of all, I'm very new to MVC. Bought the books, but not got the T-Shirt yet. I've put together my first little application, but I'm looking at the way I'm maintaining my model and I don't think it looks right. My form contains the following: <% using (Html.BeginForm("Reconfigured", null, FormMethod.Post, new { id = "configurationForm" })) { %> <%= Html.DropDownList("selectedCompany", new SelectList(Model.Companies, Model.SelectedCompany), new { onchange = "$('#configurationForm').submit()" })%> <%= Html.DropDownList("selectedDepartment", new SelectList(Model.Departments, Model.SelectedDepartment), new { onchange = "$('#configurationForm').submit()" })%> <%=Html.TextArea("comment", Model.Comment) %> <%} %> My controller has the following: public ActionResult Index(string company, string department, string comment) { TestModel form = new TestModel(); form.Departments = _someRepository.GetList(); form.Companies = _someRepository.GetList(); form.Comment = comment; form.SelectedCompany = company; form.SelectedDepartment = department; return View(form); } [HttpPost] public ActionResult Reconfigured(string selectedCompany, string selectedDepartment, string comment) { return RedirectToAction("Index", new { company = selectedCompany, department = selectedDepartment, comment = comment}); } And finally, this is my route: routes.MapRoute( "Default", "{controller}/{company}/{department}", new { controller = "CompanyController", action = "Index", company="", department="" } ); Now, every time I change DropDownList value, all my values are maintained. I end up with a URL like the following after the Reconfigure action is called: http://localhost/Main/Index/Company/Sales?comment=Foo%20Bar Ideally I'd like the URL to remain as: http://localhost/Main/Index My routing object is probably wrong. This can't be the right way? It seems totally wrong to me as for each extra field I add, I have to add the property into the Index() method? I had a look at this answer where the form is passed through TempData. This is obviously an improvement, but it's not strongly typed? Is there a way to do something similar but have it strongly typed? This may be a simple-enough question, but the curse of 10 years of WinForms/WebForms makes this MVC malarky hard to get your head 'round.

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  • Using Session Bean provided data on JSF welcome page

    - by takachgeza
    I use JSF managed beans calling EJB methods that are provide data from database. I want to use some data already on the welcome page of the application. What is the best solution for it? EJBs are injected into JSF managed beans and it looks like the injection is done after executing the constructor. So I am not able to call EJB methods in the constructor. The normal place for EJB call is in the JSF action methods but how to call such a method prior to loding the first page of the application? A possible solution would be to call the EJB method conditionally in a getter that is used on the welcome page, for example: public List getProductList(){ if (this.productList == null) this.productList = myEJB.getProductList(); return this.productList; } Is there any better solution? For example, in some config file?

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  • [CakePHP] Can not Bake table model, controller and view

    - by user198003
    I developed small CakePHP application, and now I want to add one more table (in fact, model/controller/view) into system, named notes. I had already created a table of course. But when I run command cake bake model, I do not get table Notes on the list. I can add it manually, but after that I get some errors when running cake bake controller and cake bake view. Can you give me some clue why I have those problems, and how to add that new model?

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  • Ember model is gone when I use the renderTemplate hook

    - by Mickael Caruso
    I have a single template - editPerson.hbs <form role="form"> FirstName: {{input type="text" value=model.firstName }} <br/> LastName: {{input type="text" value=model.lastName }} </form> I want to render this template when the user wants to edit an existing person or create a new person. So, I set up routes: App.Router.map(function(){ this.route("createPerson", { path: "/person/new" }); this.route("editPerson", { path: "/person/:id}); // other routes not show for brevity }); So, I define two routes - one for create and one for edit: App.CreatePersonRoute = Ember.Route.extend({ renderTemplate: function(){ this.render("editPerson", { controller: "editPerson" }); }, model: function(){ return {firstName: "John", lastName: "Smith" }; } }); App.EditPersonRoute = Ember.Route.extend({ model: function(id){ return {firstName: "John Existing", lastName: "Smith Existing" }; } }); So, I hard-code the models. I'm concerned about the createPerson route. I'm telling it to render the editPersonTemplate and to use the editPerson controller (which I don't show because I don't think it matters - but I made one, though.) When I use renderTemplate, I lose the model John Smith, which in turn, won't display on the editTemplate on the web page. Why? I "fixed" this by creating a separate and identical (to editPerson.hbs) createPerson.hbs, and removing the renderTemplate hook in the CreatePerson. It works as expected, but I find it somewhat troubling to have a separate and identical template for the edit and create cases. I looked everywhere for how to properly do this, and I found no answers.

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  • Check if Django model field choices exists

    - by Justin Lucas
    I'm attempting to check if a value exists in the choices tuple set for a model field. For example lets say I have a Model like this: class Vote(models.Model): VOTE_TYPE = ( (1, "Up"), (-1, "Down"), ) value = models.SmallIntegerField(max_length=1, choices=VOTE_TYPES) Now lets say in a view I have a variable new_value = 'Up' that I would like to use as the value field in a new Vote. How can I first check to see if the value of that variable exists in the VOTE_TYPE tuple? Thank you.

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  • Kohana PHP - Multiple apps with shared model

    - by Josamoto
    I'm using Kohana 3 to create a website that has two applications, an admin application and the actual site frontend. I have separated my folders to have the two applications separated, so the hierarchy looks as follows: /applications /admin /classes /controller /... /site /classes /controller /.... My question is, how I need to go about creating a shared /model folder. Essentially, both the admin and site itself operates on the same data, so the database layer and business logic remains more or less the same. So to me, it makes sense to have a single model folder, sitting outside of the two application folders. Is it possible to achieve the following hierarchy: /applications /model --> Where model sits in a neatly generic location, accessible to all applications /admin /classes /controller /... /site /classes /controller /.... Thanks in advance!

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  • Creating Domain Model

    - by Zai
    Hi, I have created a use case of a small application and now I have to create a Domain Model of that use cases of the application and which functions will be implemented in this application. I have no previous experience in Domain Modeling and UML, please suggest me steps to create the domain model or any suggestions, Do I have to have a very solid understanding of Object oriented concepts for creating domain model? The application is simple and creates online poll/voting system and have functions like Register Account, Confirmation Email of account, Membership, Create Poll, Send Poll etc

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  • Java constructor with large arguments or Java bean getter/setter approach

    - by deelo55
    Hi, I can't decide which approach is better for creating objects with a large number of fields (10+) (all mandatory) the constructor approach of the getter/setter. Constructor at least you enforce that all the fields are set. Java Beans easier to see which variables are being set instead of a huge list. The builder pattern DOES NOT seem suitable here as all the fields are mandatory and the builder requires you put all mandatory parameters in the builder constructor. Thanks, D

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