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  • Where to place web server root?

    - by nefo_x
    Hello everybody, I've just made an upgrade and now partly thinking on web-server directory structure for local workstation for web-development on linux platform. Running multiple hosts and different projects required. Where is it better to put all the server's docroots? /var/www? /srv? /www? I plan to make it as separate partition - could it be good for backups? :) I'm looking forward to your thoughts on this.

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  • Redirecting only if user asks for the root of the domain nad are froma particular country

    - by lphmedia
    Hi, I need a rule and condition to handle this scenario: User from US visits www.domain.com, domain.com, www.domain.com/ or domain.com/ this should be redirected to www.domain.com/usvisitor/ However, if a user from the US visits www.domain.com/anydirectory it will let them straight through without a redirection occurring. eg. RewriteEngine On RewriteBase / GeoIPEnable On GeoIPDBFile /var/share/GeoIP/GeoIP.dat RewriteEngine on RewriteCond %{ENV:GEOIP_COUNTRY_CODE} ^US$ RewriteCond %{HTTP_HOST} ^domain.com$ [L] RewriteRule ^/$ http://www.domain.com/usvisitor$1 [L] I know the RewriteConditons and rules are wrong - just can't get my head around it!

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  • include and Get not working on index

    - by diego
    I have a problem with my index.php, i have this small script that decides what content to deliver <?php $clase = $_GET['clase']; if ($clase == empresa) {include ("empresa.php");} elseif ($clase == productos) {include("productos.php");} else {include ($_SERVER['DOCUMENT_ROOT']."/inicio.html"); } ?> it works when i go to www.mysite.com/index.php but when i go to www.mysite.com it doesnt and i cant just figure our why.

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  • Can Django be used for non web apps?

    - by Leeks and Leaks
    I noticed in the main Django introductin they show a feature that maps python objects to the database. This doesn't strike me as being mutually exclusive with with development, is there any reason why this can't be used for non web apps? Is it easy to separate out?

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  • Ruby Win32Api get single character non-blocking

    - by Markus Orreilly
    I'm trying to write a simple game working with two threads, one thread to get input from the user, and another thread to animate some scenes. I'm able to get characters without pressing ENTER just fine, but it blocks in the animating thread until the user presses a key. Does anyone know of a way to get a character from the keyboard non-blocking?

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  • reading root element in xml not the child

    - by Umesha MS
    Hi I am working on an application which reads XML file. Here I am trying to read the node under the not under the node . When I tried to read the I get both. Please help me to solve the problem. Bellow is the sample. "a" "x"..."/X" "b" "name" 123 "/name" "/b" "name" main "/name" "c".."/c" "/a" QDomDocument mDocument; QDomElement mDocumentElement; if (!mDocument.setContent(file.readAll())) { return ; } mDocumentElement = mDocument.documentElement(); QDomNodeList list = mDocumentElement.elementsByTagName("a").at(0).toElement().elementsByTagName("name"); int count = list.count(); for (int i = 0; i < count; i++) { QString str = list.at(i).nodeValue(); QMessageBox::information(this, "text", str, QMessageBox::Yes, 0); }

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  • Where is the root [closed]

    - by smwikipedia
    I read the manual page of the "mount" command, at it reads as below: All files accessible in a Unix system are arranged in one big tree, the file hierarchy, rooted at /. These files can be spread out over several devices. The mount command serves to attach the file system found on some device to the big file tree. My question is: Where is this "big tree" located?

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  • Copying to /system - android

    - by user1675783
    I am been trying to copy a apk from assets of another apk to /system. Here is what I have done,it was working in my previous app but not in this.I have added permission for wrtiting external storage. It is successfully copying to internal storage,not not to /system. Is there any way to directly copy to /system? copyStream("y.apk","/sdcard/x.apk"); Process mSuProcess; mSuProcess = Runtime.getRuntime().exec("su"); new DataOutputStream(mSuProcess.getOutputStream()).writeBytes("mount -o remount rw /system"); DataOutputStream mSuDataOutputStream = new DataOutputStream(mSuProcess.getOutputStream()); mSuDataOutputStream.writeBytes("cp /sdcard/x.apk /system/app/x.apk"); mSuDataOutputStream.writeBytes("exit\n");

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  • How do I increase the open files limit for a non-root user?

    - by iCode
    This is happening on Ubuntu Release 12.04 (precise) 64-bit Kernel Linux 3.2.0-25-virtual I'm trying to increase the number of open files allowed for a user. This is for an my ecplise java application where the current limit of 1024 is not enough. According to the posts I've found so far, I should be able to put lines into /etc/security/limits.conf like this; soft nofile 4096 hard nofile 4096 to increase the number of open files allowed for all users. But, that's not working for me, and I think the problem is not related to that file. For all users, the default limit is 1024, regardless of what is in /etc/security/limits.conf (I have been rebooting after changing that file) $ ulimit -n 1024 Now, despite the entries in /etc/security/limits.conf I can't increase that; $ ulimit -n 2048 -bash: ulimit: open files: cannot modify limit: Operation not permitted The weird part is that I can change the limit downwards, but can't change it upwards - even to go back to a number which is below the original limit; $ ulimit -n 800 $ ulimit -n 800 $ ulimit -n 900 -bash: ulimit: open files: cannot modify limit: Operation not permitted As root, I can change that limit to whatever I want, up or down. It doesn't even seem to care about the supposedly system-wide limit in /proc/sys/fs/file-max # cat /proc/sys/fs/file-max 188897 # ulimit -n 188898 # ulimit -n 188898 So far, I haven't found any way to increase the open files limit for a non-root user, and I really don't want to be running my application as root. How should I properly do this? I have looked at all the posted and tried the given options but no luck!

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  • Should mobile webpages have hreflang links to non-mobile pages?

    - by Noam
    My site has multilingual links, which are specified like this on non-mobile pages: <link rel="alternate" hreflang="en" href="http://mydomain.com/page" /> <link rel="alternate" hreflang="jp" href="http://ja.mydomain.com/page" /> <link rel="alternate" hreflang="ko" href="http://ko.mydomain.com/page" /> In addition, these non-mobile pages link to a mobile version: <link rel="alternate" media="only screen and (max-width: 640px)" href="/mobile/page" /> Now the question is about what links should be in the mobile page, which isn't translated to different languages now. Is this enough: <link rel="canonical" href="/page"/> Or should I also have the same group of hreflangs that point to non-mobile pages?

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  • start-stop-daemon can't find executable that's right in front of it

    - by Bart van Heukelom
    root@mountain-lion:/opt/smartfox# ls -lha total 180K drwxr-xr-x 8 root root 4.0K 2012-06-01 14:09 . drwxr-xr-x 4 root root 4.0K 2012-06-01 09:41 .. drwxr-xr-x 8 root root 4.0K 2009-05-17 21:57 lib lrwxrwxrwx 1 root root 22 2012-06-01 09:41 logs -> /var/opt/smartfox/logs -rwxr-xr-x 1 root root 1.4K 2012-06-01 14:28 run.sh root@mountain-lion:/opt/smartfox# cat run.sh #!/bin/bash java -cp "./:./sfsExtensions/:lib/activation.jar:lib/commons-beanutils.jar:lib/commons-collections-3.2.jar:lib/commons-dbcp-1.2.1.jar:lib/commons-lang-2.3.jar:lib/commons-logging-1.1.jar:lib/commons-pool-1.2.jar:lib/concurrent.jar:lib/ezmorph-1.0.3.jar:lib/h2.jar:lib/js.jar:lib/json-lib-2.1-jdk15.jar:lib/json.jar:lib/jsr173_1.0_api.jar:lib/jysfs.jar:lib/jython.jar:lib/nanoxml-2.2.1.jar:lib/wrapper.jar:lib/xbean.jar:lib/javamail/imap.jar:lib/javamail/mailapi.jar:lib/javamail/pop3.jar:lib/javamail/smtp.jar:lib/jetty/jetty.jar:lib/jetty/jetty-util.jar:lib/jetty/jstl.jar:lib/jetty/multipartrequest.jar:lib/jetty/servlet-api.jar:lib/jetty/standard.jar:lib/jsp-2.1/commons-el-1.0.jar:lib/jsp-2.1/core-3.1.0.jar:lib/jsp-2.1/jsp-2.1.jar:lib/jsp-2.1/jsp-api-2.1.jar:lib/jsp-2.1/jstl.jar:lib/jsp-2.1/standard.jar:lib/lsc.jar:lib/commons-io-1.4.jar" \ it.gotoandplay.smartfoxserver.SmartFoxServer > logs/smartfox.out 2>&1 & JAVAPID=$! echo "Started Smartfox. JVM PID = $JAVAPID" trap "echo Stopping Smartfox.; kill $JAVAPID" INT TERM wait echo "Smartfox stopped." root@mountain-lion:/opt/smartfox# start-stop-daemon --start --make-pidfile --pidfile /var/opt/smartfox/smartfox.pid --exec ./run.sh start-stop-daemon: unable to start ./run.sh (No such file or directory) Why can't start-stop-daemon find the script?

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  • Fatal error on a non-object

    - by Chris Leah
    Hey, so I have created a function to check the DB for unique entries, but when I call the function it doesn't seem to work and gives me a fatal error any ideas ? Thanks :) //Check for unique entries function checkUnique($table, $field, $compared) { $query = $mysqli->query('SELECT '.$mysqli->real_escape_string($field).' FROM '.$mysqli->real_escape_string($table).' WHERE "'.$mysqli->real_escape_string($field).'" = "'.$mysqli->real_escape_string($compared).'"'); if(!$query){ return TRUE; } else { return FALSE; } } The page calling it..... //Start session session_start(); //Check if the session is already set, if so re-direct to the game if(isset($_SESSION['id'], $_SESSION['logged_in'])){ Header('Location: ../main/index.php'); }; //Require database connection require_once('../global/includes/db.php'); require_once('../global/functions/functions.php'); //Check if the form has been submitted if (isset($_POST['signup'])){ //Validate input if (!empty($_POST['username']) && !empty($_POST['password']) && $_POST['password']==$_POST['password_confirm'] && !empty($_POST['email']) && validateEmail($_POST['email']) == TRUE && checkUnique('users', 'email', $_POST['email']) == TRUE && checkUnique('users', 'username', $_POST['username']) == TRUE) { //Insert user to the database $insert_user = $mysqli->query('INSERT INTO (`username, `password`, `email`, `verification_key`) VALUES ("'.$mysqli->real_escape_string($_POST['username']).'", "'.$mysqli-real_escape_string(md5($_POST['password'])).'", "'.$mysqli->real_escape_string($_POST['email']).'", "'.randomString('alnum', 32). '"') or die($mysqli->error()); //Get user information $getUser = $mysqli->query('SELECT id, username, email, verification_key FROM users WHERE username = "'.$mysqli->real_escape_string($_POST['username']).'"' or die($mysqli->error())); //Check if the $getUser returns true if ($getUser->num_rows == 1) { //Fetch associated fields to this user $row = $getUser->fetch_assoc(); //Set mail() variables $headers = 'From: [email protected]'."\r\n". 'Reply-To: [email protected]'."\r\n". 'X-Mailer: PHP/'.phpversion(); $subject = 'Activate your account (Music Battles.net)'; //Set verification email message $message = 'Dear '.$row['username'].', I would like to welcome you to Music Battles. Although in order to enjoy the gmae you must first activate your account. \n\n Click the following link: http://www.musicbattles.net/home/confirm.php?id='.$row['id'].'key='.$row['verification_key'].'\n Thanks for signing up, enjoy the game! \n Music Battles Team'; //Attempts to send the email if (mail($row['email'], $subject, $message, $headers)) { $msg = '<p class="success">Accound has been created, please go activate it from your email.</p>'; } else { $error = '<p class="error">The account was created but your email was not sent.</p>'; } } else { $error = '<p class="error">Your account was not created.</p>'; } } else { $error = '<p class="error">One or more fields contain non or invalid data.</p>'; } } Erorr.... Fatal error: Call to a member function query() on a non-object in /home/mbattles/public_html/global/functions/functions.php on line 5

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  • Get mutually and non mutually existening Fields in same table in Two columns

    - by ranabra
    This is a question similar to another question I posted here but is a little different. I am trying to get a list of all instances of mutual and non-mutual existing Users. What I mean is that the returned result from the query will return a list of users along with their co-worker. It is similar to the question here, but the difference is that non mutual users will be returned too and with out the "duplicity" mutually existing users return in the list (See image below in-order simplify it all). I took the original answer from Thomas (Thanx again Thomas) Select D1.u_username, U1.Permission, U1.Grade, D1.f_username, U2.Permission, U2.Gradefrom tblDynamicUserList As D1    Join tblDynamicUserList As D2        On D2.u_username = D1.f_username            And D2.f_username = D1.u_username    Join tblUsers As U1        On U1.u_username = D1.u_username    Join tblUsers As U2        On U2.u_username = D2.u_username and after some several trials I commented out 2 lines (Below). The returned result are exactly as described in the beginning of this question, but with the "duplicity" returned by mutually existing users in the table. How can I eliminate this duplicity? Select D1.u_username, U1.Permission, U1.Grade, D1.f_username, U2.Permission, U2.Gradefrom tblDynamicUserList As D1    Join tblDynamicUserList As D2        On D2.u_username = D1.f_username            /* And D2.f_username = D1.u_username */    Join tblUsers As U1        On U1.u_username = D1.u_username    Join tblUsers As U2        On U2.u_username = D2.u_username /* WHERE D1.U_userName < D1.f_username */ *Screenshot that hopefully helps explain it all. Database is SQL 2005. Many thanx in advance

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  • install python2.7.3 + numpy + scipy + matplotlib + scikits.statsmodels + pandas0.7.3 correctly

    - by boldnik
    ...using Linux (xubuntu). How to install python2.7.3 + numpy + scipy + matplotlib + scikits.statsmodels + pandas0.7.3 correctly ? My final aim is to have them working. The problem: ~$ python --version Python 2.7.3 so i already have a system-default 2.7.3, which is good! ~$ dpkg -s python-numpy Package: python-numpy Status: install ok installed and i already have numpy installed! great! But... ~$ python Python 2.7.3 (default, Oct 23 2012, 01:07:38) [GCC 4.6.1] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> import numpy as nmp Traceback (most recent call last): File "<stdin>", line 1, in <module> ImportError: No module named numpy this module couldn't be find by python. The same with scipy, matplotlib. Why? ~$ sudo apt-get install python-numpy [...] Reading package lists... Done Building dependency tree Reading state information... Done python-numpy is already the newest version. [...] why it does not see numpy and others ? update: >>> import sys >>> print sys.path ['', '/usr/local/lib/python27.zip', '/usr/local/lib/python2.7', '/usr/local/lib/python2.7/plat-linux2', '/usr/local/lib/python2.7/lib-tk', '/usr/local/lib/python2.7/lib-old', '/usr/local/lib/python2.7/lib-dynload', '/usr/local/lib/python2.7/site-packages'] >>> so i do have /usr/local/lib/python2.7 ~$ pip freeze Warning: cannot find svn location for distribute==0.6.16dev-r0 BzrTools==2.4.0 CDApplet==1.0 [...] matplotlib==1.0.1 mutagen==1.19 numpy==1.5.1 [...] pandas==0.7.3 papyon==0.5.5 [...] pytz==2012g pyxdg==0.19 reportlab==2.5 scikits.statsmodels==0.3.1 scipy==0.11.0 [...] zope.interface==3.6.1 as you can see, those modules are already installed! But! ls -la /usr/local/lib/ gives ONLY python2.7 dir. And still ~$ python -V Python 2.7.3 and import sys sys.version '2.7.3 (default, Oct 23 2012, 01:07:38) \n[GCC 4.6.1]' updated: Probably I've missed another instance... One at /usr/Python-2.7.3/ and second (seems to be installed "by hands" far far ago) at /usr/python2.7.3/Python-2.7.3/ But how two identical versions can work at the same time??? Probably, one of them is "disabled" (not used by any program, but I don't know how to check if any program uses it). ~$ ls -la /usr/bin/python* lrwxrwxrwx 1 root root 9 2011-11-01 11:11 /usr/bin/python -> python2.7 -rwxr-xr-x 1 root root 2476800 2012-09-28 19:48 /usr/bin/python2.6 -rwxr-xr-x 1 root root 1452 2012-09-28 19:45 /usr/bin/python2.6-config -rwxr-xr-x 1 root root 2586060 2012-07-21 01:42 /usr/bin/python2.7 -rwxr-xr-x 1 root root 1652 2012-07-21 01:40 /usr/bin/python2.7-config lrwxrwxrwx 1 root root 9 2011-10-05 23:53 /usr/bin/python3 -> python3.2 lrwxrwxrwx 1 root root 11 2011-09-06 02:04 /usr/bin/python3.2 -> python3.2mu -rwxr-xr-x 1 root root 2852896 2011-09-06 02:04 /usr/bin/python3.2mu lrwxrwxrwx 1 root root 16 2011-10-08 19:50 /usr/bin/python-config -> python2.7-config there is a symlink python-python2.7, maybe I can ln -f -s this link to exact /usr/Python-2.7.3/python destination without harm ?? And how correctly to remove the 'copy' of 2.7.3?

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  • Java saying XML Document Not Well Formed

    - by Pyroclastic
    Hey all. Java's XML parser seems to be thinking that my XML document is not well formed following the root element, but I've validated it with several tools and they all disagree. It's probably an error in my code rather than in the document itself, I'd really appreciate any help you all could offer me. Here is my Java method: private void loadFromXMLFile(File f) throws ParserConfigurationException, IOException, SAXException { File file = f; DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); DocumentBuilder db; Document doc = null; db = dbf.newDocumentBuilder(); doc = db.parse(file); doc.getDocumentElement().normalize(); String desc = ""; String due = ""; String comment = ""; NodeList tasksList = doc.getElementsByTagName("task"); for (int i = 0; i < tasksList.getLength(); i++) { NodeList attributes = tasksList.item(i).getChildNodes(); for (int j = 0; i < attributes.getLength(); j++) { Node attribute = attributes.item(i); if (attribute.getNodeName() == "description") { desc = attribute.getTextContent(); } if (attribute.getNodeName() == "due") { due = attribute.getTextContent(); } if (attribute.getNodeName() == "comment") { comment = attribute.getTextContent(); } tasks.add(new Task(desc, due, comment)); } desc = ""; due = ""; comment = ""; } } And here is the XML file I'm trying to load: <?xml version="1.0"?> <tasklist> <task> <description>Task 1</description> <due>Due date 1</due> <comment>Comment 1</comment> <completed>false</completed> </task> <task> <description>Task 2</description> <due>Due date 2</due> <comment>Comment 2</comment> <completed>false</completed> </task> <task> <description>Task 3</description> <due>Due date 3</due> <comment>Comment 3</comment> <completed>true</completed> </task> </tasklist> And here is the error message java is throwing for me: run: [Fatal Error] tasks.xml:28:3: The markup in the document following the root element must be well-formed. May 17, 2010 6:07:02 PM todolist.TodoListGUI SEVERE: null org.xml.sax.SAXParseException: The markup in the document following the root element must be well-formed. at com.sun.org.apache.xerces.internal.parsers.DOMParser.parse(DOMParser.java:239) at com.sun.org.apache.xerces.internal.jaxp.DocumentBuilderImpl.parse(DocumentBuilderImpl.java:283) at javax.xml.parsers.DocumentBuilder.parse(DocumentBuilder.java:208) at todolist.TodoListGUI.loadFromXMLFile(TodoListGUI.java:199) at todolist.TodoListGUI.(TodoListGUI.java:42) at todolist.Main.main(Main.java:25) BUILD SUCCESSFUL (total time: 19 seconds) For reference TodoListGUI.java:199 is doc = db.parse(file); If context is helpful to anyone here, I'm trying to write a simple GUI application to manage a todo list that can read and write to and from XML files defining the tasks. Any advice is appreciated!

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  • WPF WebBrowser NavigateToString vs NavigateToStream (hebrew/non-utf8 encodings)

    - by David E
    When I use WPF WebBrowser's NavigateToString method to display UTF8 html (with hebrew text in it) it's displayed perfectly. However, when I try to use the NavigateToString to display html with hebrew text in it in a non-utf8 encoding (CodePage 1255 to be exact) the hebrew is messed up. I checked the cp1255 string in Visual Studio's debugger and it looks great, and also when I save the source of the web browser's contents and open it with an external browser it looks great. If I use the NavigateToStream method instead of the NavigateToString method it works great. What's the problem with the NavigateToString? am I doing something wrong?

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  • Python - Calling a non python program from python?

    - by Seafoid
    Hi, I am currently struggling to call a non python program from a python script. I have a ~1000 files that when passed through this C++ program will generate ~1000 outputs. Each output file must have a distinct name. The command I wish to run is of the form: program_name -input -output -o1 -o2 -o3 To date I have tried: import os cwd = os.getcwd() files = os.listdir(cwd) required_files = [] for i in file: if i.endswith('.ttp'): required_files.append(i) So, I have an array of the neccesary files. My problem - how do I iterate over the array and for each entry, pass it to the above command (program_name) as an argument and specify a unique output id for each file? Much appreciated, S :-)

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  • The parameters dictionary contains a null entry for parameter 'productId' of non-nullable type 'Syst

    - by Naim
    Hi Guys, I am trying to implement an edit page in order administrator to modify data in database.Unfortunately I am encountering an error. The code below: public ViewResult Edit(int productId) { // Do something here } but I am getting this error: "The parameters dictionary contains a null entry for parameter 'productId' of non-nullable type 'System.Int32' for method 'System.Web.Mvc.ViewResult Edit(Int32)' in 'WebUI.Controllers.AdminController'. To make a parameter optional its type should be either a reference type or a Nullable type. Parameter name: parameters" I changed my route in Global.asax.cs like this: routes.MapRoute( "Admin", "Admin/{action}/{ productId}", new { controller = "Admin", action = "Edit", productId= "" } ); but still I am getting the error Thanks for your help! Naim

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  • Rsync on Windows - Socket operation on non-socket

    - by TLS
    I get the following error when trying to run the latest Cygwin version of rsync in Windows XP SP2. The error occurs for attempts at both local syncs (that is: source and destination on the local harddisk only) and remote syncs (using "-e ssh" from the openssh package). Any advice on how to fix/workaround it? bash-3.2$ rsync -a dir1 dir2 rsync: Failed to dup/close: Socket operation on non-socket (108) rsync error: error in IPC code (code 14) at /home/lapo/packaging/tmp/rsync-2.6.9/pipe.c(143) [receiver=2.6.9] rsync: read error: Connection reset by peer (104) rsync error: error in IPC code (code 14) at /home/lapo/packaging/tmp/rsync-2.6.9/io.c(604) [sender=2.6.9]

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