Search Results

Search found 17140 results on 686 pages for 'records management'.

Page 75/686 | < Previous Page | 71 72 73 74 75 76 77 78 79 80 81 82  | Next Page >

  • Rails 3 find all associated records has_many :through

    - by Sergey
    I would like to list all posts that are connected with some specific category. I have: class Post < ActiveRecord::Base has_many :category_posts has_many :categories, :through => :category_posts end class Category < ActiveRecord::Base has_many :category_posts has_many :posts, :through => :category_posts end class CategoryPost < ActiveRecord::Base belongs_to :category belongs_to :post end And I wanna do something like this Post.where(["category.id = ?", params[:category_id]]) It indeed is very simple task, but I don't know what I should be looking for (keywords). It's the same problem like this, but in rails.

    Read the article

  • Connect Digest : 2012-07-06

    - by AaronBertrand
    I've filed a few Connect items recently that I think are important. In #752210 , I complain that the documentation for DDL triggers suggests that they can prevent certain DDL from being run, which is not the case at all. http://connect.microsoft.com/SQLServer/feedback/details/752210/doc-ddl-trigger-topic-suggests-that-rollbacks-run-before-action In #745796 , I complain that scripting datetime data in Management Studio yields output that contains a binary representation instead of a human-readable...(read more)

    Read the article

  • MySQL query : all records of one table plus count of another table

    - by Ricardo
    Hello Guys! I have 2 tables: User and Picture. The Picture table has the key of the user. So basically each user can have multiple pictures, and each picture belongs to one user. Now, I am trying to make the following query: I want to select all the user info plus the total number of pictures that he has (even if it's 0). How can I do that? Probably it sounds quite simple, but I am trying and trying and can't seem to find the right query. The only thing I could select is this info, but only for users that have at least 1 picture, meaning that the Pictures table has at least one record for that key... But I also wanna consider the users that don't have any. Any idea? Thanks!

    Read the article

  • What performance indicators can I use to convince management that I need my development PC upgraded?

    - by Aaron Daniels
    At work, my PC is slow. I feel that I can be way more productive if I just wasn't waiting for Visual Studio and everything else to respond. My PC isn't bad (dual-core, 3GB of RAM), but there is a lot of corporate software and whatnot to slow everything down and sometimes lock it up. Now, some developers have begun getting Windows 7 machines with 8 GB of RAM. Of course, I start salivating at this. However, I was told that I "had to justify" why I should get a new machine. I can think of a lot of different things, but I am curious as to what every one else on SO would have to say. NOTE: Ideally, these reasons should be specifically related to .NET development in Visual Studio on a Windows machine. This isn't a "how can I make my machine faster" question.

    Read the article

  • Rails: three most recent records by unique belongs_to associated record

    - by Dennis Collective
    class User has_many :comments end class Comment belongs_to :user named_scope :recent, :order => 'comments.created_at DESC' named_scope :limit, lambda { |limit| {:limit => limit}} named_scope :by_unique_users end what would I put in the :by_unique_users so that I can do Comment.recent.by_unique_users.limit(3), and only get one comment per user on sqlite named_scope :by_unique_user, :group = "user_id" works, but makes it freak out on postgres, which is deployed on production PGError: ERROR: column "comments.id" must appear in the GROUP BY clause or be used in an aggregate function

    Read the article

  • ATG Live Webcast Nov. 8th: Advanced Management of EBS with Oracle Enterprise Manager

    - by Bill Sawyer
    The task of managing and monitoring Oracle E-Business Suite environments can be very challenging. The Application Management Pack plug-in is part of Oracle Enterprise Manager 12c Application Management Suite for Oracle E-Business Suite. The Application Management Pack plug-in is designed to monitor and manage all the different technologies that constitute Oracle E-Business Suite applications, including midtier, configuration, host, and database management—to name just a few. Customers that have implemented Oracle Enterprise Manager have experienced dramatic improvements in system visibility, diagnostic capability, and administrator productivity. This webcast will highlight the key features and benefits of Oracle Enterprise Manager, the latest version of the Oracle Application Management Suite for Oracle E-Business Suite. Advanced Management of Oracle E-Business Suite with Oracle Enterprise Manager Date:                Thursday, November 8, 2012Time:               8:00 AM - 9:00 AM Pacific Standard TimePresenters:   Angelo Rosado, Principal Product Manager, E-Business Suite ATG                         Lauren Cohn, Principal Curriculum Developer, E-Business Suite ATGWebcast Registration Link (Preregistration is optional but encouraged)To hear the audio feed:   Domestic Participant Dial-In Number:           877-697-8128    International Participant Dial-In Number:      706-634-9568    Additional International Dial-In Numbers Link:    Dial-In Passcode:                                              103191To see the presentation:    The Direct Access Web Conference details are:    Website URL: https://ouweb.webex.com    Meeting Number:  591460967 If you miss the webcast, or you have missed any webcast, don't worry -- we'll post links to the recording as soon as it's available from Oracle University.  You can monitor this blog for pointers to the replay. And, you can find our archive of our past webcasts and training here. If you have any questions or comments, feel free to email Bill Sawyer (Senior Manager, Applications Technology Curriculum) at BilldotSawyer-AT-Oracle-DOT-com.

    Read the article

  • SQL - suppressing duplicate *adjacent* records

    - by Trevel
    I need to run a Select statement (DB2 SQL) that does not pull adjacent row duplicates based on a certain field. In specific, I am trying to find out when data changes, which is made difficult because it might change back to its original value. That is to say, I have a table that vaguely resembles: A, 5, Jan A, 12, Feb A, 12, Mar A, 12, Apr A, 9, May A, 9, Jun A, 5, Jul And I want to get the results: A, 5, Jan A, 12, Feb A, 9, May A, 5, Jul discarding adjacent duplicates but keeping the last row. The obvious: Select Letter, Number, Min(Month) from Table group by Letter, Number does not work -- it doesn't include the last row.

    Read the article

  • Exclude records matching subquery

    - by Skudd
    There is probably an obvious answer to this question, but I am having one heck of a time getting anywhere with it. Consider the query: SELECT * FROM reports AS r JOIN reportvalues AS rv ON rv.report_id = r.report_id JOIN metrics AS m ON m.metric_id = rv.metric_id WHERE r.report_id NOT IN( SELECT DISTINCT report_id FROM exclude_report ) In this query, exclude_report is a view constructed in a similar manner. Now what happens is the query takes an EXTREMELY long time to execute, presumably because the subquery is being executed over each and every row in the parent query. However, I am finding no feasible means of doing this any other way. Oh great SQL wizards, please advise. I really need a way of doing this all in SQL, which I will be using in SSRS.

    Read the article

  • How to separate production and test assets during development?

    - by bcsanches
    Hi Folks, this is like a complement for Assets Management, database or versioning system?. I am wondering about how to separate development, specially programmers assets from production assets? For example, if we keep all the assets on the same repository, how do you keep with programmers assets and final game assets? Do you keep a separate directory for each of those, allowing duplicates? Or do you use some fancy scheme for striping out the "development" and "test" assets from final build?

    Read the article

  • How to do INSERT into a table records extracted from another table

    - by Martin
    I'm trying to write a query that extracts and transforms data from a table and then insert those data into another table. Yes, this is a data warehousing query and I'm doing it in MS Access. So basically I want some query like this: INSERT INTO Table2(LongIntColumn2, CurrencyColumn2) VALUES (SELECT LongIntColumn1, Avg(CurrencyColumn) as CurrencyColumn1 FROM Table1 GROUP BY LongIntColumn1); I tried but get a syntax error message. What would you do if you want to do this?

    Read the article

  • MySQL help, counting information on last records

    - by ee12csvt
    I need some advice I have two tables, one holds unique serial numbers of items (items) and the other holds status changes and other information for these items (details) The Tables are set up as follows Item itemID itemName itemDate details detID itemID modlvl status detDate All items have at least one record in the details table, but over time the status has changed or the modification level has changed (Both of these are identified by numbers which are held in other appropriate tables) and a new record is created each time the status/modlvl changes I want to display a table on my webpage using php that identifies the different mod levels of the items and shows a count of each of the current status of the items EDIT Hi Ronnis, This is an example of the data in the tables and what I want to achieve The current Mod Levels range from 1 to 3 Status representations are 1 In Use 2 In Store 3 Being repaired 4 In Transit 5 For Disposal 6 Disposed 7 Lost Item itemID OrigMod created 1000 1 2009-10-01 22:12:12 1001 1 2009-10-01 22:12:12 1002 1 2009-10-01 22:12:12 1003 1 2009-10-01 22:12:12 1004 1 2009-10-01 22:12:12 1005 1 2009-10-01 22:12:12 1006 1 2009-10-01 22:12:12 1007 1 2009-10-01 22:12:12 1008 1 2009-10-01 22:12:12 1009 1 2009-10-01 22:12:12 1010 1 2009-10-01 22:12:12 Details detID itemID modlvl detDate status 1 1000 1 2009-10-01 1 2 1001 1 2009-10-01 1 3 1002 1 2009-10-01 1 4 1003 1 2009-10-01 1 5 1004 1 2009-10-01 1 6 1005 1 2009-10-01 1 7 1006 1 2009-10-01 1 8 1007 1 2009-10-01 1 9 1008 1 2009-10-01 1 10 1009 1 2009-10-01 1 11 1010 1 2009-10-01 1 12 1001 1 2010-02-01 2 13 1001 1 2010-02-03 4 14 1001 1 2010-03-01 3 15 1000 1 2010-03-14 2 16 1001 2 2010-04-01 4 17 1006 1 2010-04-01 2 18 1001 2 2010-04-03 2 19 1006 1 2010-04-14 4 20 1006 1 2010-05-01 5 21 1002 1 2010-05-02 2 22 1003 1 2010-05-10 2 23 1010 1 2010-06-01 2 24 1006 1 2010-06-18 6 25 1010 1 2010-07-01 7 26 1007 1 2010-07-02 2 27 1007 1 2010-07-04 4 28 1003 1 2010-07-10 2 29 1007 1 2010-07-11 3 30 1007 2 2010-07-12 4 31 1007 2 2010-07-15 2 32 1001 2 2010-08-31 1 33 1001 2 2010-09-10 2 34 1001 2 2010-10-01 4 35 1008 1 2010-10-01 2 36 1001 2 2010-10-05 3 37 1008 1 2010-10-05 4 38 1008 1 2010-10-10 3 39 1001 3 2010-10-20 4 40 1001 3 2010-10-25 2 Using the tables above I want to get this result MoLvl Use Store Repd Transit Displ Dispd Lost Total 1 3 3 1 0 0 1 1 9 2 0 1 0 0 0 0 0 1 3 0 1 0 0 0 0 0 1 Total 3 5 1 0 0 1 1 11

    Read the article

  • getting sql records

    - by droidus
    when i run this code, it returns the topic fine... $query = mysql_query("SELECT topic FROM question WHERE id = '$id'"); if(mysql_num_rows($query) > 0) { $row = mysql_fetch_array($query) or die(mysql_error()); $topic = $row['topic']; } but when I change it to this, it doesn't run at all. why is this happening? $query = mysql_query("SELECT topic, lock FROM question WHERE id = '$id'"); if(mysql_num_rows($query) > 0) { $row = mysql_fetch_array($query) or die(mysql_error()); $topic = $row['topic']; $lockedThread = $row['lock']; echo "here: " . $lockedThread; }

    Read the article

  • NHibernate Linq - Duplicate Records

    - by adegiamb
    I am having a problem with duplicate blog post coming back when i run the linq statement below. The issue that a blog post can have the same tag more then once and that's causing the problem. I know when you use criteria you can do the followingcriteria.SetResultTransformer(new DistinctRootEntityResultTransformer()); How can I do the same thing with linq? List<BlogPost> result = (from blogPost in _session.Linq<BlogPost>() from tags in blogPost.Tags where tags.Tag == tag && blogPost.IsPublished && blogPost.Slug != slugToExclude orderby blogPost.DateCreated descending select blogPost).Distinct() .Skip(recordsToSkip).Take(pageSize).ToList();

    Read the article

  • Best way to get a reasonably random key for MYSQL records

    - by Steve N
    Hi there, I need to generate a reasonably random unique key for a table. It should be something like a GUID for MYSQL. I've tried UUID, but it looks like only the first few characters are actually random- the rest are the same every time I insert them. Essentially, it is desirable for this key field to be very difficult to guess, even if you already have one known value in the column. What is the best way to do this, and how should I set up the field data type to store the value efficiently? Thank you, Steve

    Read the article

  • Emails going into junk and spf records

    - by user346443
    Hi, our emails are being flagged as junk. I have two different webistes both with their own dedicted ip address. sitea.com = xx.xx.xx.43 siteb.com = xx.xx.xx.44 Im using hmailserver to host our emails and have the smtp bound to the ip address of xx.xx.xx.42 im aware that i can set up a spf record to state that the what servers emails can be sent from v=spf1 mx ip4:xx.xx.xx.43 mx:mail.sitea.com ip4:xx.xx.xx.42 -all Would the fact that email are not sent from the sites ip's be causing them to be flagged as junk. Cheers Cam

    Read the article

  • SharePoint - Auto-increment dates in new records?

    - by ACal
    Hello, I have a list that's going to be updated with relatively static data weekly, and I wanted to create a workflow to do this automatically. The only field I'm having trouble with is Start Date. I want the new Start Date to be exactly one week after the previous week's (row's) Start Date, but I can't figure out how to capture this. I can't seem to find an easy way to get the value of the previous row. Now, theoretically, I could just have the workflow run once a week on a given day and use [Today] as the value for the field; however, a requirement is that the list can be populated a few weeks in advance if needed. Thanks in advance for any help you can provide!

    Read the article

  • Grouping records by subsets SQL

    - by Stacy
    I have a database with PermitHolders (PermitNum = PK) and DetailedFacilities of each Permit Holder. In the tblPermitDetails table there are 2 columns PermitNum (foreign Key) FacilityID (integer Foreign Key Lookup to Facility table). A permitee can have 1 - 29 items on their permit, e.i. Permit 50 can have a Boat Dock (FacID 4), a Paved walkway (FacID 17) a Retaining Wall (FacID 20) etc. I need an SQL filter/display whatever, ALL PERMIT #s that have ONLY FacIDs 19, 20, or 28, NOT ones that have those plus "x" others,....just that subset. I've worked on this for 4 days, would someone PLEASE help me? I HAVE posted to other BB but have not received any helpful suggestions.

    Read the article

  • how do I get the 2 most recent records

    - by fishhead
    I have a table similar to the example shown below. I would like to be able to select the two most recent entrys for each accountNo. I am using Microsoft SQL. Thank you for any help that you can provide. AccountNo, DateOfOrder, OrderID ----------------------------------------- 123, March 1 2010, 1 222, March 3 2010, 2 123, April 1 2010, 3 345, March 15 2010, 77 123, june 1 2010, 55 123, march 5 2010, 33 345, march 1 2010, 99 222, june 1 2010, 7 222, june 2 2010, 22

    Read the article

  • Learn Linux Command Line for Web Server Management [closed]

    - by Jonathan
    I've searched high and low for a good resource for learning the Linux command line. I've found a handful of separate resources, but none that really can assist in web server management. I'm currently learning through trial an error with 'man' pages, along with Google. I was just wondering if anyone had a solid resource that they used to learn, and would be willing to share it with me. Thanks so much for your time, I really appreciate it! EDIT: I have a few CentOS servers at current, and I know the basics, I'm just trying to get to a more advanced level.

    Read the article

  • CodeIgniter Question: How to delete records using ActiveRecord with mySQL function as WHERE conditio

    - by Jhourlad Estrella
    I have a table named ChatSessions where I keep track of active users in the chatroom. I need to prune expired user sessions from the table every 10 minutes. Using pure php-mysql is plain simple but I'm totally clueless how to convert this into ActiveRecord in CodeIgniter. The plain SQL query is below: SELECT * FROM `ChatSessions` WHERE `SessionExpires` < DATE_SUB( NOW( ) , INTERVAL 10 MINUTE ) Can anybody tell me what is the equivalent code in CodeIgniter using ActiveRecord? Thanks in advanced.

    Read the article

  • Duplicate / Copy records in the same MySQL table

    - by Digits
    Hello, I have been looking for a while now but I can not find an easy solution for my problem. I would like to duplicate a record in a table, but of course, the unique primary key needs to be updated. I have this query: INSERT INTO invoices SELECT * FROM invoices AS iv WHERE iv.ID=XXXXX ON DUPLICATE KEY UPDATE ID = (SELECT MAX(ID)+1 FROM invoices) the proble mis that this just changes the ID of the row instead of copying the row. Does anybody know how to fix this ? Thank you verrry much, Digits //edit: I would like to do this without typing all the field names because the field names can change over time.

    Read the article

  • Need method to seek next/previous records id without cycling through all records.

    - by dqhendricks
    I am using MySQL and PHP. I have a MySQL blog post result set with id fields, and publish_date fields. I display one blog post per page, and the script knows which blog post to display based on $_GET['id'], which correlates to each blog entry's id field. I would like to reference them by id in the url, because I would like each blog post to have a perminant url. I would like to order the blog posts by publish date (descending). Now, on each page there will be next and previous links, which contain the $_GET['id'] value for the next and previous blog posts. How can I figure out what the id of the next and previous blog posts (determined by it's publish_date order) without cycling through each mysql result row? I can't mysql_data_seek(), because I do not know the row index of the current blog post id. I do not want to store a row index in a GET variable because the urls would no longer be perminant. I obviously cannot store the row index in a SESSION variable because then direct links to specific blog posts would have broken next and previous links. Any suggestions would be greatly appreciated.

    Read the article

  • How to remove duplicate records in a table?

    - by Mason Wheeler
    I've got a table in a testing DB that someone apparently got a little too trigger-happy on when running INSERT scripts to set it up. The schema looks like this: ID UNIQUEIDENTIFIER TYPE_INT SMALLINT SYSTEM_VALUE SMALLINT NAME VARCHAR MAPPED_VALUE VARCHAR It's supposed to have a few dozen rows. It has about 200,000, most of which are duplicates in which TYPE_INT, SYSTEM_VALUE, NAME and MAPPED_VALUE are all identical and ID is not. Now, I could probably make a script to clean this up that creates a temporary table in memory, uses INSERT .. SELECT DISTINCT to grab all the unique values, TRUNCATE the original table and then copy everything back. But is there a simpler way to do it, like a DELETE query with something special in the WHERE clause?

    Read the article

  • SQL COUNT records in table 2 JOINS away

    - by Fred K
    Using MySQL, I have three tables: projects: ID name 1 "birthday party" 2 "soccer match" 3 "wine tasting evening" 4 "dig out garden" 5 "mountainbiking" 6 "making music" batches: ID projectID templateID when 1 1 1 7 days before 2 1 1 1 day before 3 4 2 21 days before 4 4 1 7 days before 5 5 1 7 days before 6 3 5 7 days before 7 3 3 14 days before 8 5 1 14 days before templates: ID message 1 "Hi, I'd like to invite ..." 2 "Dear Sir, Madam, ..." 3 "Can you please ..." 4 "Would you like to ..." 5 "To all dear friends ..." 6 "Does any of you guys ..." I would like to display a table of templates and the number of projects they're used in. So, the result should be: templateID projectCount 1 3 2 1 3 1 4 0 5 1 6 0 I've tried all kinds of SQL queries using various JOINs, but I guess this is too complicated for me. Is it possible to get this result using a single SQL statement?

    Read the article

< Previous Page | 71 72 73 74 75 76 77 78 79 80 81 82  | Next Page >