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  • xml dom node children

    - by matt
    Need some help I've got lots of code and i want to make it shorter i know there's a way but I can't remember it this is code example: <?xml version="1.0" encoding="ISO-8859-1"?> <bookstore> <book category="cooking"> <title lang="en">Everyday Italian</title> <author>Giada De Laurentiis</author> <year>2005</year> <price>30.00</price> </book> <book category="children"> <title lang="en">Harry Potter</title> <author>J K. Rowling</author> <year>2005</year> <price>29.99</price> </book> <book category="web"> <title lang="en">XQuery Kick Start</title> <author>James McGovern</author> <author>Per Bothner</author> <author>Kurt Cagle</author> <author>James Linn</author> <author>Vaidyanathan Nagarajan</author> <year>2003</year> <price>49.99</price> </book> <book category="web" cover="paperback"> <title lang="en">Learning XML</title> <author>Erik T. Ray</author> <year>2003</year> <price>39.95</price> </book> </bookstore As you can see the different nodes, children now is there a way to make this code smaller so I don't have to keep writing the nodes and children

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  • php code to return xml

    - by anwar
    hi there i have a question and need help on this from you guys . I have a database created for a game called gamesleaderboard and the fields are id, player_name, score, leveltime. and my task is after getting the score, i have to insert it to a database and sort the dbase accordingly. after sorting, the code will return an xml in the following structure: Ahmad100080 Basel95090 Samer920100 Seyd900110 Ahmad100080 Basel95090 Samer920100 Seyd900110 Ahmad100080 Basel95090 plz tell me the necessary details how to do this thankyou.

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  • How to insert sub root node in xml file

    - by pravakar
    Hi guys hope all are doing good. I want to create one sub root node in my xml file like, <CapitalJobsList xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <JobAds> -- element to create <JobAd> <AdvertiserDetails> <AdvertiserId>718508549</AdvertiserId> <AdvertiserName>ABC</AdvertiserName> </AdvertiserDetails> <ConsultantDetails> <ContactName>Naga Divakar</ContactName> <ContactPhone>6239 7755</ContactPhone> <ContactEmail>[email protected]</ContactEmail> <ContactFax>12345678912</ContactFax> </ConsultantDetails> <JobAdDetails> <DateEntered>2009-10-03T21:09:35.500</DateEntered> <AdvertiserJobRef>83754865</AdvertiserJobRef> <Title>IT Operations Manager</Title> <DescriptionShort>Large scale/exciting projects Mentor and manage o...</DescriptionShort> <Description>Large scale/exciting projects Mentor and manage others Management/technical mix This is a fantastic opportunity to join a high profile client who is active across both the commercial and Government domain. As the IT Operations Manager you will be responsible for leading and mentoring a small team of Infrastructure Engineers to ensure the availability and performance of the IT infrastructure. You w</Description> <SalaryMin>0.00</SalaryMin> <SalaryMax>0.00</SalaryMax> <WorkType xsi:nil="true" /> <Location>) as [JobAd/JobAdDetails/Bullets], isnull(Job</Location> <PostCode>2600</PostCode> <ClosingDate>2009-11-01T00:00:00</ClosingDate> <Keywords xsi:nil="true" /> <ApplyEmail xsi:nil="true" /> <ApplyURL>http://jobview.careerone.com.au/GetJob.aspx?JobID=83754865</ApplyURL> </JobAdDetails> <JobAdOptions> <BlindPost xsi:nil="true" /> <AdFormatType xsi:nil="true" /> <AdTemplateName xsi:nil="true" /> <ShowContactDetails xsi:nil="true" /> <ShowSalary xsi:nil="true" /> <HasVideo xsi:nil="true" /> <ResumeRequired>1</ResumeRequired> <ResidentsOnly>0</ResidentsOnly> </JobAdOptions> <CategoryList> <Category xsi:nil="true" /> </CategoryList> <RegionsList> <Region>ACT</Region> </RegionsList> <LevelsList> <Level xsi:nil="true" /> </LevelsList> </JobAd> <JobAd> <AdvertiserDetails> <AdvertiserId>718508549</AdvertiserId> <AdvertiserName>ABC</AdvertiserName> </AdvertiserDetails> <ConsultantDetails> <ContactName>Naga Divakar</ContactName> <ContactPhone>6239 7755</ContactPhone> <ContactEmail>[email protected]</ContactEmail> <ContactFax>12345678912</ContactFax> </ConsultantDetails> <JobAdDetails> <DateEntered>2009-10-03T21:09:35.530</DateEntered> <AdvertiserJobRef>83731488</AdvertiserJobRef> <Title>SAP Developers Required in Canberra - 12 month contract</Title> <DescriptionShort>My client, a large government department in Canbe...</DescriptionShort> <Description>My client, a large government department in Canberra, seeks two SAP Developers for 12 month ongoing contracts. Two SAP Developers Required Expert level ABAP programming skills Large SAP landscape - SAP R/3, SAP Web, SAP BI, SAP ITS My client, a large government department in Canberra, seeks two SAP Developers for 12 month ongoing contracts. My client is a large government department in Canberra, a</Description> <SalaryMin>0.00</SalaryMin> <SalaryMax>0.00</SalaryMax> <WorkType xsi:nil="true" /> <Location>) as [JobAd/JobAdDetails/Bullets], isnull(Job</Location> <PostCode>2600</PostCode> <ClosingDate>2009-11-01T00:00:00</ClosingDate> <Keywords xsi:nil="true" /> <ApplyEmail xsi:nil="true" /> <ApplyURL>http://jobview.careerone.com.au/GetJob.aspx?JobID=83731488</ApplyURL> </JobAdDetails> <JobAdOptions> <BlindPost xsi:nil="true" /> <AdFormatType xsi:nil="true" /> <AdTemplateName xsi:nil="true" /> <ShowContactDetails xsi:nil="true" /> <ShowSalary xsi:nil="true" /> <HasVideo xsi:nil="true" /> <ResumeRequired>1</ResumeRequired> <ResidentsOnly>0</ResidentsOnly> </JobAdOptions> <CategoryList> <Category xsi:nil="true" /> </CategoryList> <RegionsList> <Region>ACT</Region> </RegionsList> <LevelsList> <Level xsi:nil="true" /> </LevelsList> </JobAd> </JobAds> </CapitalJobsList> I have used the sql query for xml path like: select r.advid as [JobAd/AdvertiserDetails/AdvertiserId], CompanyName as [JobAd/AdvertiserDetails/AdvertiserName], firstname +'' ''+ lastname as [JobAd/ConsultantDetails/ContactName], WorkPhone as [JobAd/ConsultantDetails/ContactPhone], AdvEmail as [JobAd/ConsultantDetails/ContactEmail], FaxNo as [JobAd/ConsultantDetails/ContactFax], Job_CreatedDate as [JobAd/JobAdDetails/DateEntered], Job_Id as [JobAd/JobAdDetails/AdvertiserJobRef], Job_Title as [JobAd/JobAdDetails/Title], substring(Job_Description,0,50)+''...'' as [JobAd/JobAdDetails/DescriptionShort], Job_Description as [JobAd/JobAdDetails/Description], CONVERT(DECIMAL(10,2),MinSalary) as [JobAd/JobAdDetails/SalaryMin], CONVERT(DECIMAL(10,2),MaxSalary) as [JobAd/JobAdDetails/SalaryMax], Job_Type as [JobAd/JobAdDetails/WorkType], isnull(Job_Bullets,'') as [JobAd/JobAdDetails/Bullets], isnull(Job_Location,'') as [JobAd/JobAdDetails/Location], Job_PostCode as [JobAd/JobAdDetails/PostCode], Job_ExpireDate as [JobAd/JobAdDetails/ClosingDate], Job_Keywords as [JobAd/JobAdDetails/Keywords], ApplyEmail as [JobAd/JobAdDetails/ApplyEmail], Job_BrandURL+Job_Id as [JobAd/JobAdDetails/ApplyURL], BlindPost as [JobAd/JobAdOptions/BlindPost], AdFormatType as [JobAd/JobAdOptions/AdFormatType], AdTemplateName as [JobAd/JobAdOptions/AdTemplateName], ShowContactDetails as [JobAd/JobAdOptions/ShowContactDetails], ShowSalary as [JobAd/JobAdOptions/ShowSalary], HasVideo as [JobAd/JobAdOptions/HasVideo], ResumeRequired as [JobAd/JobAdOptions/ResumeRequired], ResidentsOnly as [JobAd/JobAdOptions/ResidentsOnly], Job_Category as [JobAd/CategoryList/Category], Job_Location_State as [JobAd/RegionsList/Region], [Level] as [JobAd/LevelsList/Level] from DR_Adv_Registration r, DR_CareerOne_ACTJobs j where r.Advid = j.Advid and job_location_city like(''%'+''+ @City +''+'%'') and job_location_state in('''+ @State +''') and job_status=1 for xml path(''''), Root(''CapitalJobsList''),ELEMENTS XSINIL So, suggest me how to get the sub root node. Thanks in advance

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  • Sort/Group XML data with PHP?

    - by Volmar
    I'm trying to make a page using data from the discogs.com (XML)-API. i've been parsing it with simpleXML and it's working pretty well but there is some things i'm not sure how to do. Here is part of the XML: <releases> <release id="1468764" status="Accepted" type="Main"> <title>Versions</title> <format>12", EP</format> <label>Not On Label</label> <year>1999</year> </release> <release id="72246" status="Accepted" type="Main"> <title>The M.O.F Blend</title> <format>LP</format> <label>Blenda Records</label> <year>2002</year> </release> <release id="890064" status="Accepted" type="Main"> <title>The M.O.F Blend</title> <format>CD</format> <label>Blenda Records</label> <year>2002</year> </release> <release id="1563561" status="Accepted" type="TrackAppearance"> <title>Ännu En Gång Vol. 3</title> <trackinfo>Backtrack</trackinfo> <format>Cass, Comp, Mix</format> <label>Hemmalaget</label> <year>2001</year> </release> </releases> What i want to achieve is something similair to how discogs presents the releases: http://www.discogs.com/artist/Mics+Of+Fury where diferent versions of the same release are sorted together. (see. The M.O.F Blend in my link) This is done on discogs with having a master release that features the other releases. unfortunately this information isn't present in the API data, so i want to do the same thing by grouping the <release>-nodes with the same <title>-tags, or add a flag to the <releases> that don't have a unique <title>? any good ideas on the best way of doing this? i also like to know if it's possible to count the <release>-nodes (child of releases) that have the same type-attribute? like in this example count the releases with the type "Main"? maybe it's better to do this things with XMLReader or XPath?

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  • How to decode ASN.1 to XML with erlang

    - by shian
    Hi I use asn1 module in erlang to decode. The output is like {'UL-CCCH-Message',asn1_NOVALUE, {rrcConnectionRequest, {'RRCConnectionRequest', {'tmsi-and-LAI', {'TMSI-and-LAI-GSM-MAP', [1,0,0,0,0,1,1,1,1,1,1,0,1,0,0,0,0,1,1,0,1,1,0,1,0,1,1, 1,1,0,1,0], {'LAI', {'PLMN-Identity',[2,2,6],[0,1]}, [0,1,1,1,1,0,0,1,1,0,0,0,1,1,0,1]}}}, terminatingBackgroundCall,noError, {'MeasuredResultsOnRACH', {'MeasuredResultsOnRACH_currentCell', {fdd, {'MeasuredResultsOnRACH_currentCell_modeSpecificInfo_fdd', {'cpich-Ec-N0',39}}}}, asn1_NOVALUE}, asn1_NOVALUE}}} How can I output XML instead of erlang term?

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  • Python modify an xml file

    - by michele
    I have this xml model. link text So I have to add some node (see the text commented) to this file. How I can do it? I have writed this partial code but it doesn't work: xmldoc=minidom.parse(directory) child = xmldoc.createElement("map") for node in xmldoc.getElementsByTagName("Environment"): node.appendChild(child) Thanks in advance.

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  • Does an XPathDocument load the whole xml document?

    - by Wires
    If I do XPathDocument doc = new XPathDocument("filename.xml"); Does that load the entire document into memory? I'm writing a mobile phone app and the document might store lots of data that doesn't ever need to all be loaded at the same time. Mobile phones don't usually have too much ram!

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  • Merging XML records into one

    - by BhanuPratap Tarigopula
    I am new to XSLT. I have requirement of merging and adding. XML: <OrderDetails> <OrderDetail action="add"> <OrderedUnits>18</OrderedUnits> <Date>2013-09-30T00:00:00</Date> <LocationCode>3202</LocationCode> <PONumber>022548295755</PONumber> </OrderDetail> <OrderDetail action="add"> <OrderedUnits>12</OrderedUnits> <Date>2013-09-30T00:00:00</Date> <LocationCode>3202</LocationCode> <PONumber>022548295755</PONumber> </OrderDetail> <IOrderDetail action="add"> <OrderedUnits>18</OrderedUnits> <Date>2013-09-30T00:00:00</Date> <LocationCode>3202</LocationCode> <PONumber>022548295762</PONumber> </OrderDetail> <OrderDetails> If the LocationCode, Date, and PONumber fields match, I need to add the OrderedUnits and make it only one entry. Expected output XML: <OrderDetails> <OrderDetail action="add"> <OrderedUnits>30</OrderedUnits> <Date>2013-09-30T00:00:00</Date> <LocationCode>3202</LocationCode> <PONumber>022548295755</PONumber> </OrderDetail> <IOrderDetail action="add"> <OrderedUnits>18</OrderedUnits> <Date>2013-09-30T00:00:00</Date> <LocationCode>3202</LocationCode> <PONumber>022548295762</PONumber> </OrderDetail> <OrderDetails> How can I write this XSLT?

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  • Convert text to xml

    - by Nave
    I want to convert a tab delimited text file to a XML file. I was able to do it with a single character delimiter. But how do i extend it to tabs? I am coding in C# and using Visual Studio 2010.

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  • xml appending issue - in ie, chrome browsers

    - by 3gwebtrain
    Hi, i am using this coding for my xml information to append in to html. As well it works fine. but in the ie7,ie8 as well chrome browser it's not propelry. This code work9ing well with firefox,opera, safari.. i unable to find, what is the mistake i made this.. any one help me please? $(function(){ var thisPage; var parentPage; $('ul.left-navi li a').each(function(){ $('ul.left-navi li a').removeClass('current'); var pathname = (window.location.pathname.match(/[^\/]+$/)[0]); var currentPage = $(this).attr('href'); var pathArr = new Array(); pathArr = pathname.split("."); var file = pathArr[pathArr.length - 2]; thisPage = file; if(currentPage==pathname){ $(this).addClass("active"); } }) $.get('career-utility.xml',function(myData){ var receivedData = myData; var myXml = $(myData).find(thisPage); parentPage = thisPage; var overviewTitle = myXml.find('overview').attr('title'); var description = myXml.find('discription').text(); var mainsublinkTitle = myXml.find('mainsublink').attr('title'); var thisTitle = myXml.find("intro").attr('title'); var thisIntro = myXml.find("introinfo").text(); $('<h3>'+overviewTitle+'</h3>').appendTo('.overViewInfo'); $('<p>'+description+'</p>').appendTo('.overViewInfo'); var sublinks = myXml.find('mainsublink').children('sublink'); $('#intro h3').append(thisTitle); $('#intro').append(thisIntro); sublinks.each(function(numsub){ var newSubLink = $(this); var sublinkPage = $(this).attr('pageto'); var linkInfo = $(this).text(); $('ul.career-link').append('<li><a href="'+sublinkPage+'">'+linkInfo+'</a></li>'); }) // alert('thisTitle : '+thisTitle+'thisIntro :'+thisIntro); $(myXml).find('listgroup').each(function(index){ var count = index; var listGroup = $(this); var listGroupTitle = $(this).attr('title'); var shortNote = $(this).attr('shortnote'); var subLink = $(this).find('sublist'); var firstList = $(this).find('list'); $('.grouplist').append('<div class="list-group"><h3>'+listGroupTitle+'</h3><ul class="level-one level' + count + '"></ul></div>'); firstList.each(function(listnum) { $(this).wrapInner('<li>') .find('sublistgroup').wrapInner('<ul>').children().unwrap() .find('sublist').wrapInner('<li>').children().unwrap(); // Append content of 'list' node $('ul.level'+count).append($(this).children()); }); }); }); })

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