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  • How to get search results in XML format

    - by Shibin Moideen
    Hi, I am planning to make an iPhone search app. the user types in the search string. the string will be searched by some search engines like Google, Live, Yahoo ... I need to get the search result in the XML format. Is there any way to do this. Help needed. Please. Thanks and regards, Shibin

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  • WP7 Return the last 7 days of data from an xml web service

    - by cvandal
    Hello, I'm trying to return the last 7 days of data from an xml web service but with no luck. Could someone please explain me to how I would accomplish this? The XML is as follows: <node> <api> <usagelist> <usage day="2011-01-01"> <traffic name="total" unit="bytes">23579797</traffic> </usage> <usage day="2011-01-02"> <traffic name="total" unit="bytes">23579797</traffic> </usage> <usage day="2011-01-03"> <traffic name="total" unit="bytes">23579797</traffic> </usage> <usage day="2011-01-04"> <traffic name="total" unit="bytes">23579797</traffic> </usage> </usagelist> </api> </node> EDIT The data I want to retrieve will be used to populate a line graph. Specificly I require the day attribute value and the traffic element value for the past 7 days. At the moment, I have the code below in place, howevewr it's only showing the first day 7 times and traffic for the first day 7 times. XDocument xDocument = XDocument.Parse(e.Result); var values = from query in xDocument.Descendants("usagelist") select new History { day = query.Element("usage").Attribute("day").Value, traffic = query.Element("usage").Element("traffic").Value }; foreach (History history in values) { ObservableCollection<LineGraphItem> Data = new ObservableCollection<LineGraphItem>() { new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, }; lineGraph1.DataSource = Data; }

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  • Passing input value thru XML loop and return value

    - by Mike Dyer
    "X" is reading the form value, but it is still passing and older "var thisMarket" value. The objective is to take a zip code via HTML form: <form id="market" name="market" onSubmit="return validateZIP(this.zip.value);" method="get" action=""> <input type="text" name="zip" id="zip" value="zipcode" onfocus="if(!this._haschanged){this.value=''};this._haschanged=true;" style="float:left; width:100px; margin-top:5px;"> <input type="image" style="float:left; margin-top:5px; border: 0pt none ; width: 22px; height:17px;" src="images/nav/bottom/linkbar/btn_search_btn.gif" onClick="findLda();"> </form> The script being passed thru is: function findLda(x){ marketName = new Array(); marketURL = new Array(); zip = new Array(); zip_temp = new Array(); zipMatch = false; var shareZip = "Shared Zips"; var thisMarket = "Market value"; xmlDoc=loadXML("/_includes/market.xml"); var Offer,node; document.getElementById('market').innerHTML=''; for(var j=0; j<xmlDoc.getElementsByTagName('market').length; j++){ node = xmlDoc.getElementsByTagName('market')[j]; marketName.push(node.childNodes[3].textContent); marketURL.push(node.childNodes[5].textContent); for(var k=0; k<node.getElementsByTagName('zip').length; k++){ if(node.getElementsByTagName('zip')[k].textContent!=null){ zip_temp.push(node.getElementsByTagName('zip')[k].textContent); } } zip.push(zip_temp); zip_temp = new Array(); } //loop the zip Array to find a match for the query Zip. for(k=0; k<zip.length; k++){ for(m=0; m<zip[k].length; m++){ if(x == zip[k][m].toString()){ zipMatch=true; thisMarket=marketName[k].toString(); } } } alert(thisMarket); } The objective naturally is to take field input (A), pass it thru market.xml - initialize a loop and match a zip (B), alert the result (C). Looking for any direction with what is existing or a completely new direction. Thanks!

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  • Help with XML path views

    - by xmlpath
    Hi all, is there any tool that will give me a view for XML fields like so. I want something that will show me the a view like so, if i select element1 Service/Body/element1 Is there any tool for eclipse for doing the above. Thanks.

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  • c# update xml file

    - by Pila
    I want to replace a xml node that is not a child of the root element. how can I do it - not in .Net 3.5? I don't know the exact path to the node I want to replace, I get the node by XPath query like : XmlElement root = doc.DocumentElement; oldItem = root.SelectSingleNode("//Node1[@name='aaa']//Node2[Item='bbb']/Value"); how can I replace this olditem?

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  • AS3 XML problem

    - by dd
    My Flash project is made of several .swf files, one of them loads XML gallery. everything works fine on my machine, but when I upload it to the testing server gallery content doesn't load. All my paths are relative to Main swf file. I can't make them absolute URLs, b/c I have to deliver zip package. What could be wrong?

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  • xml schema construction

    - by amanrahahla
    in xml can any concept inhert the attribute of the main concept as an example: book( -author -title -isbn -price) and textbook as a subconcept from book can textbook take the same attribute of book and how?

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  • update XML file

    - by Pila
    I want to replace an XML node that is not a child of the root element. How can I do it - not in .NET 3.5? I don't know the exact path to the node I want to replace, I get the node by XPath query like: XmlElement root = doc.DocumentElement; oldItem = root.SelectSingleNode("//Node1[@name='aaa']//Node2[Item='bbb']/Value"); How can I replace this old item?

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  • One log4j.xml - many scripts

    - by psed
    One of my utility jar files is used by different nix scripts, located in different categories. Problem: unable to initialize log4j framework (unable to find log4j.xml). Solution, that allows to configure logger correctly while launching jar classes by different scripts - usage of env vars and force configuring using DOMConfigurtor.configure(pathToConfXml) method. is it possible to avoid path hardcoding and configure logger inside of a script? Appreciate all your help. Thanks.

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  • What is the best way to read and write cXML documents in C# ?

    - by tetranz
    I know this is a vague open ended question. I'm hoping to get some general direction. I need to add cXML punchout to an ASP.NET C# site / application. This is replacing something that I wrote years ago in ColdFusion. I'm a reasonably experienced C# developer but I haven't done much with XML. There seems to be lots of different options for processing XML in .NET. Here's the open ended question: Assuming that I have an XML document in some form, eg a file or a string, what is the best way to read it into my code? I want to get the data and then query databases etc. The cXML document size and our traffic volumes are easily small enough so that loading the a cXML document into memory is not a problem. Should I: 1) Manually build classes based on the dtd and use the XML Serializer? 2) Use a tool to generate classes. There are sample cXML files downloadable from Ariba.com. I tried xsd.exe to generate an xsd and then xsd.exe /c to generate classes. When I try to deserialize I get errors because there seems to be "confusion" around whether some elements should be single values or arrays. I tried the CodeXS online tool but that gives errors in it's log and errors if I try to deserialize a sample document. 2) Create a dataset and ReadXml()? 3) Create a typed dataset and ReadXml()? 4) Use Linq to XML. I often use Linq to Objects so I'm familiar with Linq in general but I'm struggling to see what it gives me in this situation. 5) Some other means. I guess I need to improve my understanding of XML in general but even so ... am I missing some obvious way of doing this? In the old ColdFusion site I found a free component ("tag") which basically ignored any schema and read the XML into a "structure" which is essentially a series of nested hash tables which was then easy to read in code. That was probably quite sloppy but it worked. I also need to generate XML files from my C# objects. Maybe Linq to XML will be good for that. I could start with a default "template" document and manipulate it before saving. Thanks for any pointers ...

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  • php DOM, get values from xml document, php xml

    - by Michael
    I'm trying to get some information (itemID, title, price and mileage) for multiple listings from ebay website using their api . So far I got this link up http://open.api.ebay.com/shopping?callname=GetMultipleItems&responseencoding=XML&appid=Morcovar-c74b-47c0-954f-463afb69a4b3&siteid=0&version=525&IncludeSelector=ItemSpecifics&ItemID=220617293997,250645537939,230485306218 I've saved the document as .xml file using php curl and now I need to get/extract the values(itemID, title, price and mileage) into arrays and store them in database. Unfortunately I never worked with php dom and I can't figure it out how to extract the values . I tried to follow the tutorial found on IBM website http://www.ibm.com/developerworks/library/os-xmldomphp/ but I had no success. Some help would be highly appreciated.

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  • Trying to send XML via EMail and the XML includes a byte[]

    - by barbary
    Hello All, I want to send an email that has a machine readable part you cut and paste into an asp.net page and you get the information. I have stored all the information in an object and then used an XMLSerizer to create some xml. It all worked fine until I added some Images as byte[] to the object. If I dump the resulting string to disk then I can recreate the object fine but after it appears in the email client and I try to cut and paste it it never works. Clearly there are non standard characters coming out that email clients don't like. Is there some encoding I could apply to my XML that would make it display correctly in an email client? Then I could cut, paste, decode and deserilize to get my object back. Please an example of how to encode the string in c# would be great.

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  • XML Parsing Error: junk after document element

    - by Jake
    I am using the following script to generate a RSS feed for my site: <?php class RSS { public function RSS() { $root = $_SERVER['DOCUMENT_ROOT']; require_once ("../connect.php"); } public function GetFeed() { return $this->getDetails() . $this->getItems(); } private function dbConnect() { DEFINE ('LINK', mysql_connect (DB_HOST, DB_USER, DB_PASSWORD)); } private function getDetails() { $detailsTable = "rss_feed_details"; $this->dbConnect($detailsTable); $query = "SELECT * FROM ". $detailsTable ." WHERE feed_category = ''"; $result = mysql_db_query (DB_NAME, $query, LINK); while($row = mysql_fetch_array($result)) { $details = '<?xml version="1.0" encoding="ISO-8859-1" ?> <rss version="2.0"> <channel> <title>'. $row['title'] .'</title> <link>'. $row['link'] .'</link> <description>'. $row['description'] .'</description> <language>'. $row['language'] .'</language> <image> <title>'. $row['image_title'] .'</title> <url>'. $row['image_url'] .'</url> <link>'. $row['image_link'] .'</link> <width>'. $row['image_width'] .'</width> <height>'. $row['image_height'] .'</height> </image>'; } return $details; } private function getItems() { $itemsTable = "rss_posts"; $this->dbConnect($itemsTable); $query = "SELECT * FROM ". $itemsTable ." ORDER BY id DESC"; $result = mysql_db_query (DB_NAME, $query, LINK); $items = ''; while($row = mysql_fetch_array($result)) { $items .= '<item> <title>'. $row["title"] .'</title> <link>'. $row["link"] .'</link> <description><![CDATA['.$row["readable_date"]."<br /><br />".$row["description"]."<br /><br />".']]></description> </item>'; } $items .= '</channel> </rss>'; return $items; } } ?> The baffling thing is, the script works perfectly fine on my localhost but gives the following error on my remote server: XML Parsing Error: junk after document element Location: http://mysite.com/rss/main/ Line Number 2, Column 1:<b>Parse error</b>: syntax error, unexpected T_STRING in <b>/home/studentw/public_html/rss/global-reach/rssClass.php</b> on line <b>1</b><br /> ^ Can someone please tell me what's wrong?

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  • What is this XML Parse Error?

    - by Jake
    I am using the following script to generate a RSS feed for my site: <?php class RSS { public function RSS() { $root = $_SERVER['DOCUMENT_ROOT']; require_once ("../connect.php"); } public function GetFeed() { return $this->getDetails() . $this->getItems(); } private function dbConnect() { DEFINE ('LINK', mysql_connect (DB_HOST, DB_USER, DB_PASSWORD)); } private function getDetails() { $detailsTable = "rss_feed_details"; $this->dbConnect($detailsTable); $query = "SELECT * FROM ". $detailsTable ." WHERE feed_category = ''"; $result = mysql_db_query (DB_NAME, $query, LINK); while($row = mysql_fetch_array($result)) { $details = '<?xml version="1.0" encoding="ISO-8859-1" ?> <rss version="2.0"> <channel> <title>'. $row['title'] .'</title> <link>'. $row['link'] .'</link> <description>'. $row['description'] .'</description> <language>'. $row['language'] .'</language> <image> <title>'. $row['image_title'] .'</title> <url>'. $row['image_url'] .'</url> <link>'. $row['image_link'] .'</link> <width>'. $row['image_width'] .'</width> <height>'. $row['image_height'] .'</height> </image>'; } return $details; } private function getItems() { $itemsTable = "rss_posts"; $this->dbConnect($itemsTable); $query = "SELECT * FROM ". $itemsTable ." ORDER BY id DESC"; $result = mysql_db_query (DB_NAME, $query, LINK); $items = ''; while($row = mysql_fetch_array($result)) { $items .= '<item> <title>'. $row["title"] .'</title> <link>'. $row["link"] .'</link> <description><![CDATA['.$row["readable_date"]."<br /><br />".$row["description"]."<br /><br />".']]></description> </item>'; } $items .= '</channel> </rss>'; return $items; } } ?> The baffling thing is, the script works perfectly fine on my localhost but gives the following error on my remote server: XML Parsing Error: junk after document element Location: http://mysite.com/rss/main/ Line Number 2, Column 1:<b>Parse error</b>: syntax error, unexpected T_STRING in <b>/home/studentw/public_html/rss/global-reach/rssClass.php</b> on line <b>1</b><br /> ^

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  • How to convert XML to a HTML table using XSL for-each

    - by Meeeee
    I am trying to convert some XML with XSL, to make the output look better and more readable for other users. I have some XML along the lines of: <G> <OE> <example1>Sample 1</example1> <example2>Sample 2</example2> <var name="name1"> <integer>1</integer> </var> </OE> </G> I want to get all the details from it and display it in a table so I use the following XSL code: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:template match="/"> <html> <body> <h2>Heading</h2> <table border="1"> <tr bgcolor="#3399FF"> <th>Example 1</th> <th>Example 2</th> <th>Var name</th> <th>Int</th> </tr> <xsl:for-each select="G/OE"> <xsl:for-each select="var"> <tr> <td> <xsl:value-of select="Example 1" /> </td> <td> <xsl:value-of select="Example 2" /> </td> <td> <xsl:value-of select="@name" /> </td> <td> <xsl:value-of select="integer" /> </td> </tr> </xsl:for-each> </xsl:for-each> </table> </body> </html> </xsl:template> </xsl:stylesheet> I know that the following XSL won't work properly. I want the output to be: Sample 1, Sample 2, name1, 1 - in a table format. My problem is I don't know how to do this. In the above XSL code it will only retrieve var and integer. If I only use the top <xsl:for-each>, then only the first two are retrieved. I have tried moving the 2nd <xsl:for-each> after the first to have been selected, so between: <td><xsl:value-of select="Example 2"/></td> and <td><xsl:value-of select="@name"/></td> I get an error. Is there any way to solve this problem? Thanks for the help.

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