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  • JNDI InvalidnameException for CN 'LastName, FirstName'

    - by user321524
    Hi: I am writing to active directory using JNDI, it is successful for "CN=Yuri Gagarin,OU=Admins,DC=ead,DC=ubc,DC=ca"; but fails for "CN=Gagarin, Yuri,OU=Admins,DC=ead,DC=ubc,DC=ca". I need to store displayName, cn, name in the format 'lastName, FirstName'. What do I need to do to get this going? Thanks very much.

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  • Why a "private static" is not seen in a method?

    - by Roman
    I have a class with the following declaration of the fields: public class Game { private static String outputFileName; .... } I set the value of the outputFileName in the main method of the class. I also have a write method in the class which use the outputFileName. I always call write after main sets value for outputFileName. But write still does not see the value of the outputFileName. It say that it's equal to null. Could anybody, pleas, tell me what I am doing wrong? ADDED As it is requested I post more code: In the main: String outputFileName = userName + "_" + year + "_" + month + "_" + day + "_" + hour + "_" + minute + "_" + second + "_" + millis + ".txt"; f=new File(outputFileName); if(!f.exists()){ try { f.createNewFile(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } } System.out.println("IN THE MAIN!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!"); System.out.println("------>" + outputFileName + "<------"); This line outputs me the name of the file. Than in the write I have: public static void write(String output) { // Open a file for appending. System.out.println("==========>" + outputFileName + "<============"); ...... } And it outputs null.

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  • log4j properties file: how to configure ?

    - by EugeneP
    Is it right that the procedure of using log4j looks like this: 1) put a .properties file somewhere in a project folder 2) in an initialization method, that runs only once, invoke PropertyConfigurator.configure("path_to_file"); 3) in every method we need to use logger we define a static logger variable and simply invoke getLogger(class) I'm asking you this: what if the initialization module is not defined? Where to put "log4j.properties" file so that we wouldn't need to invoke propertyconfigurator.configure at all, or if it's not possible, is it ok to invoke PropertyConfigurator.configure("path_to_file") in every method that uses a logger?

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  • Where did this class come from?

    - by Karl
    How would you go about establishing where a class ( or maybe resource ) has been loaded from? I am trying to work out exactly where a class has been loaded from. Does anyone know if you can find out the following: Which Jar file did the class come from ? What classloader loaded the file?

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  • The fastest way to do a collection subtraction

    - by Tony
    I have two Sets. Set<B> b is the subset of Set<A> a. they're both very huge Sets. I want to subtract b from a , what's the best practice to do this common operation ? I've written to many codes like this , and I don't think it's efficient. what's your idea ? for(int i = 0 ; i < a.size(); i++) { for (int j=0 ; j < b.size() ;j++) { // do comparison , if found equals ,remove from a break; } } And I want to find an algorithm , not only applies to Sets, also works for Array.

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  • Invoke a subclass method of an anonymous class

    - by arjacsoh
    I am trying right now to dig into anonymous classes and one question was just arised I 'd prefer not to refer to much details and to pose my question straightforward: How can I invoke the method sizzle() in the following anonymous class: public class Popcorn { public void pop() { System.out.println("popcorn"); } } class Food { Popcorn p = new Popcorn() { public void sizzle() { System.out.println("anonymous sizzling popcorn"); } public void pop() { System.out.println("anonymous popcorn"); } }; public void popIt() { p.pop(); // OK, Popcorn has a pop() method p.sizzle(); // Not Legal! Popcorn does not have sizzle() } } It is known and definite in polymorphism rules that a refernce of a superclass cannot invoke methods of subclass without downcasting (even if it refers to an object of the given subclass). However in the above case what is the "key" to invoke the sizzle() method?

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  • Counting the number of visitors for a web page - JavaScript and Struts

    - by Dj
    Hi i am Dhananjay, I need to keep track of the number of visitors to a web page. I have planned like this: on load of the home page, I will call a javascript callCounter(); From javascript, I need then to call an action and update a record in database. Please help me with this. How do i call the action? I should be in the same home jsp after updating database. Thanks in advance, Dhananjay

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  • Interrupt an Http Request blocked in read() on Android

    - by twk
    Using the Apache Http stack on Android, I'm trying to force a thread out of a call to read. This is what the stack looks like: OSNetworkSystem.receiveStreamImpl(FileDescriptor, byte[], int, int, int) line: not available [native method] OSNetworkSystem.receiveStream(FileDescriptor, byte[], int, int, int) line: 478 PlainSocketImpl.read(byte[], int, int) line: 565 SocketInputStream.read(byte[], int, int) line: 87 SocketInputBuffer(AbstractSessionInputBuffer).fillBuffer() line: 103 SocketInputBuffer(AbstractSessionInputBuffer).read(byte[], int, int) line: 134 IdentityInputStream.read(byte[], int, int) line: 86 EofSensorInputStream.read(byte[], int, int) line: 159 Fetcher.readStream() line: 89 I've tried InputStream.close(), Thread.Interrupt(), and HttpUriRequest.abort(), without any success. Any ideas? I'm also open to some kind of non-blocking IO, but I don't see any way to do that with the HttpUriRequest object. Thanks!

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  • Servlet requests are executed sequentially for no apparent reason in Glassfish v3

    - by Fabien Benoit
    Hi, I'm using Glassfish 3 Web profile and can't get http workers to execute concurrently requests on a servlet. This is how i observed the problem. I've made a very simple servlet, that writes the current thread name to the standard output and sleep for 10 seconds : protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { System.out.println(Thread.currentThread().getName()); try { Thread.sleep(10000); // 10 sec } catch (InterruptedException ex) {} } } And when i'm running several simultaneous requests, I clearly see in the logs that the requests are sequentially executed (one trace every 10 seconds). INFO: http-thread-pool-8080-(2) (10 seconds later...) INFO: http-thread-pool-8080-(1) (10 seconds later...) INFO: http-thread-pool-8080-(2) etc. All my GF settings are untouched - it's the out-of-the-box config (the default thread pool is 2 threads min, 5 max if I recall properly). ...I really don't understand why the sleep() block all the others worker threads. Any insight would be greatly appreciated ! Thanks, Fabien

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  • Creating JTable Row Header

    - by Chandu
    Hi all, I'm new to JTable.I'm working in Swings using JTable & Toplink(JPA). I have two buttons "add Row", "Del Row" and I have some records displayed from db. when ever "add row" is clicked a new record, row header should be added to JTable with an auto increment number displayed in sequential order to the JTable Row Header. During deletion using "Del row " button the record has to be deleted & not its corresponding header so that next rows got updated to the previous headers & the auto increment number remain unchanged and always be in sequence. please help me on this regard. Thanks in advance, Chandu

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  • Spring and hibernate.cfg.xml

    - by Steve Kuo
    How do I get Spring to load Hibernate's properties from hibernate.cfg.xml? We're using Spring and JPA (with Hibernate as the implementation). Spring's applicationContext.xml specifies the JPA dialect and Hibernate properties: <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalEntityManagerFactoryBean"> <property name="jpaDialect"> <bean class="org.springframework.orm.jpa.vendor.HibernateJpaDialect" /> </property> <property name="jpaProperties"> <props> <prop key="hibernate.dialect">org.hibernate.dialect.MySQLInnoDBDialect</prop> </props> </property> </bean> In this configuration, Spring is reading all the Hibernate properties via applicationContext.xml . When I create a hibernate.cfg.xml (located at the root of my classpath, the same level as META-INF), Hibernate doesn't read it at all (it's completely ignored). What I'm trying to do is configure Hibernate second level cache by inserting the cache properties in hibernate.cfg.xml: <cache usage="transactional|read-write|nonstrict-read-write|read-only" region="RegionName" include="all|non-lazy" />

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  • Sorting a text file by date - Date looks like DD/MM/YYYY

    - by John N
    I am trying to sort the dates from the earliest to the latest. I was thinking about using the bufferedreader and do a try searching the first 2 characters of the string and then the 4th and 5th characters and finally the 7th and 8th characters, ignoring the slashes. The following is an example of the text file I have: 04/24/2010 - 2000.0 (Deposit) 09/05/2010 - 20.0 (Fees) 02/30/2007 - 600.0 (Deposit) 06/15/2009 - 200.0 (Fees) 08/23/2010 - 300.0 (Deposit) 06/05/2006 - 500.0 (Fees)

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  • How do I get the size of a response from a Spring 2.5 HTTP remoting call?

    - by aarestad
    I've been poking around the org.springframework.remoting.httpinvoker package in Spring 2.5 trying to find a way to get visibility into the size of the response, but I keep going around in circles. Via another question I saw here, I think what I want to do is get a handle on the InputStream that represents the response from the server, and then wrap it with an Apache commons-io CountingInputStream. What's the best way to go about doing this? For the moment, I'd be happy with just printing the size of the response to stdout, but eventually I want to store it in a well-known location in my app for optional display.

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  • Where to put default-servlet-handler in Spring MVC configuration

    - by gigadot
    In my web.xml, the default servlet mapping, i.e. /, is mapped to Spring dispatcher. In my Spring dispatcher configuration, I have DefaultAnnotationHandlerMapping, ControllerClassNameHandlerMapping and AnnotationMethodHandlerAdapter which allows me to map url to controllers either by its class name or its @Requestmapping annotation. However, there are some static resources under the web root which I also want spring dispatcher to serve using default servlet. According to Spring documentation, this can be done using <mvc:default-servlet-handler/> tag. In the configuration below, there are 4 candidate locations that I marked which are possible to insert this tag. Inserting the tag in different location causes the dispatcher to behave differently as following : Case 1 : If I insert it at location 1, the dispatcher will no longer be able to handle mapping by the @RequestMapping and controller class name but it will be serving the static content normally. Cas 2, 3 : It will be able to handle mapping by the @RequestMapping and controller class name as well as serving the static content if other mapping cannot be done successfully. Case 4 : It will not be able to serve the static contents. Therefore, Case 2 and 3 are desirable .According to Spring documentation, this tag configures a handler which precedence order is given to lowest so why the position matters? and Which is the best position to put this tag? <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd"> <context:annotation-config/> <context:component-scan base-package="webapp.controller"/> <!-- Location 1 --> <!-- Enable annotation-based controllers using @Controller annotations --> <bean id="annotationUrlMapping" class="org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping"/> <!-- Location 2 --> <bean id="controllerClassNameHandlerMapping" class="org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping"/> <!-- Location 3 --> <bean id="annotationMethodHandlerAdapter" class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter"/> <!-- Location 4 --> <mvc:default-servlet-handler/> <!-- All views are JSPs loaded from /WEB-INF/jsp --> <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"/> <property name="prefix" value="/WEB-INF/jsp/"/> <property name="suffix" value=".jsp"/> </bean> </beans>

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  • Test problem using JUnitPerf

    - by allenzzzxd
    Hi, guys, I'm writing a JUnit test using JUnitPerf. Here, I want to generate some entries and use them to update a database. To test the capacity of the database, I want several test to run simultaneously or randomly, so I use, for example: Test loadTest = new LoadTest(testCase, n); But, still, I have to insure that in each test, a different update source will be used so that a different entry in the database will be updated. So my question is how can I realize this? Thanks a lot Allen

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  • JPA @ManyToMany on only one side?

    - by Ethan Leroy
    I am trying to refresh the @ManyToMany relation but it gets cleared instead... My Project class looks like this: @Entity public class Project { ... @ManyToMany(cascade = CascadeType.ALL, fetch = FetchType.EAGER) @JoinTable(name = "PROJECT_USER", joinColumns = @JoinColumn(name = "PROJECT_ID", referencedColumnName = "ID"), inverseJoinColumns = @JoinColumn(name = "USER_ID", referencedColumnName = "ID")) private Collection<User> users; ... } But I don't have - and I don't want - the collection of Projects in the User entity. When I look at the generated database tables, they look good. They contain all columns and constraints (primary/foreign keys). But when I persist a Project that has a list of Users (and the users are still in the database), the mapping table doesn't get updated gets updated but when I refresh the project afterwards, the list of Users is cleared. For better understanding: Project project = ...; // new project with users that are available in the db System.out.println(project getUsers().size()); // prints 5 em.persist(project); System.out.println(project getUsers().size()); // prints 5 em.refresh(project); System.out.println(project getUsers().size()); // prints 0 So, how can I refresh the relation between User and Project?

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  • How this is code is getting compiled even though we are using a constant which is defined later?

    - by GK
    In the following code DEFAULT_CACHE_SIZE is declared later, but it is used to assign a value to String variable before than that, so was curious how is it possible? public class Test { public String getName() { return this.name; } public int getCacheSize() { return this.cacheSize; } public synchronized void setCacheSize(int size) { this.cacheSize = size; System.out.println("Cache size now " + this.cacheSize); } private final String name = "Reginald"; private int cacheSize = DEFAULT_CACHE_SIZE; private static final int DEFAULT_CACHE_SIZE = 200; }

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  • Tomcat - Redirect to Error Page when ServletContextListener fails

    - by Vic
    When Tomcat starts it calls my ServletContextListener to obtain a database connection, which I will later use in other servlets with getServletContext(). It is called in my web.xml as: listener listener-class org.ppdc.database.DBCPoolingListener /listener-class /listener (I removed the < because they wouldn't display properly in this message. If I cannot connect to the database when Tomcat starts up I get a 404 error, because Tomcat cannot start the application. How can I redirect the user to a custom error page at this point? I tried the following in my web.xml (I have the < brackets in the original): (error-page) (error-code404/error-code) (location/file_not_found.html/location) (/error-page) Any ideas on how to redirect a user to one of my error pages when Tomcat tries to start the application? Thanks Vic

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  • Database connection timeout

    - by Clinton Bosch
    Hi I have read so many articles on the Internet about this problem but none seem to have a clear solution. Please could someone give me a definite answer as to why I am getting database timeouts. The app is a GWT app that is being hosted on a Tomcat 5.5 server. I use spring and the session factory is created in the applicationContext.xml as follows <bean id="sessionFactory" class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean"> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect">${connection.dialect}</prop> <prop key="hibernate.connection.username">${connection.username}</prop> <prop key="hibernate.connection.password">${connection.password}</prop> <prop key="hibernate.connection.url">${connection.url}</prop> <prop key="hibernate.connection.driver_class">${connection.driver.class}</prop> <prop key="hibernate.show_sql">${show.sql}</prop> <prop key="hibernate.hbm2ddl.auto">update</prop> <prop key="hibernate.c3p0.min_size">5</prop> <prop key="hibernate.c3p0.max_size">20</prop> <prop key="hibernate.c3p0.timeout">1800</prop> <prop key="hibernate.c3p0.max_statements">50</prop> <prop key="hibernate.c3p0.idle_test_period">300</prop> </props> </property> <property name="annotatedClasses"> <list> <value>za.co.xxxx.traintrack.server.model.Answer</value> <value>za.co.xxxx.traintrack.server.model.Company</value> <value>za.co.xxxx.traintrack.server.model.CompanyRegion</value> <value>za.co.xxxx.traintrack.server.model.Merchant</value> <value>za.co.xxxx.traintrack.server.model.Module</value> <value>za.co.xxxx.traintrack.server.model.Question</value> <value>za.co.xxxx.traintrack.server.model.User</value> <value>za.co.xxxx.traintrack.server.model.CompletedModule</value> </list> </property> </bean> <bean id="dao" class="za.co.xxxx.traintrack.server.DAO"> <property name="sessionFactory" ref="sessionFactory"/> <property name="adminUsername" value="${admin.user.name}"/> <property name="adminPassword" value="${admin.user.password}"/> <property name="godUsername" value="${god.user.name}"/> <property name="godPassword" value="${god.user.password}"/> </bean> All works fine untile the next day: INFO | jvm 1 | 2010/06/15 14:42:27 | 2010-06-15 18:42:27,804 WARN [JDBCExceptionReporter] : SQL Error: 0, SQLState: 08S01 INFO | jvm 1 | 2010/06/15 14:42:27 | 2010-06-15 18:42:27,821 ERROR [JDBCExceptionReporter] : The last packet successfully received from the server was 38729 seconds ago.The last packet sent successfully to the server was 38729 seconds ago, which is longer than the server configured value of 'wait_timeout'. You should consider either expiring and/or testing connection validity before use in your application, increasing the server configured values for client timeouts, or using the Connector/J connection property 'autoReconnect=true' to avoid this problem. INFO | jvm 1 | 2010/06/15 14:42:27 | Jun 15, 2010 6:42:27 PM org.apache.catalina.core.ApplicationContext log INFO | jvm 1 | 2010/06/15 14:42:27 | SEVERE: Exception while dispatching incoming RPC call I have read so many different things (none of which worked), please help

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  • How convince other developers not to ignore Exceptions?

    - by Mnementh
    Recently I encountered a bug in an application I took over from another developer. I debugged for the reason and over an hour later I realized, that the problem wasn't the code producing the exception, but some code executed before this returning wrong data. If I dived into this, I encountered the following: try { ... } catch (XYException e){} If the Exception would have been propagated (a change I did), I would have found the reason for the bugs in a few minutes, as the stacktrace had pointed me to the problem. So how can I convince other developers to never catch and ignore exceptions in this way?

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  • Best practice for DAO pattern ?

    - by Tony
    I've seen a lot of codes use a service-dao pattern , I don't know the origin of this pattern . It force the front layer call service , then delegates some of the service task to dao. I want to ask : Does DAO layer do purely data access related task ? What about exception encapsulation ? Is there other pattern can be used to replace this ?

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