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  • python gui events out of order

    - by dave
    from Tkinter import * from tkMessageBox import * class Gui: def __init__(self, root): self.container = Frame(root) self.container.grid() self.inputText = Text(self.container, width=50, height=8) self.outputText = Text(self.container, width=50, height=8, bg='#E0E0E0', state=DISABLED) self.inputText.grid(row=0, column=0) self.outputText.grid(row=0, column=1) self.inputText.bind("<Key>", self.translate) def translate(self, event): input = self.inputText.get(0.0, END) output = self.outputText.get(0.0, END) self.outputText.config(state=NORMAL) self.outputText.delete(0.0, END) self.outputText.insert(INSERT, input) self.outputText.config(state=DISABLED) showinfo(message="Input: %s characters\nOutput: %s characters" % (len(input), len(input))) root = Tk() #toplevel object app = Gui(root) #call to the class where gui is defined root.mainloop() #enter event loop Working on a gui in tkinter I'm a little confused as to the sequence the event handlers are run. If you run the above code you'll hopefully see... 1) Editing the text widget triggers the event handler but it seems to fire it off without registering the actual change, 2) Even when the text widget is cleared (ie, keep pressing BackSpace) it still seems to have a one character length string, 3) The output widget only receives its update when the NEXT event trigger is fired despite the fact the data came on the previous event. Is this just how bindings work in tkinter or am i missing something here? The behaviour i would like when updating the input widget is: 1) Show the change, 2) Enter event handler, 3) Update output widget, 4) Show message box.

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  • Return latitude/longitude based on entered address

    - by Don
    I'm building a php based application for a client to enter in addresses for their customers' buildings. They'd like the ability to view the location on a map (either as individuals or grouped in a city search). What I'm trying to accomplish is a lookup once the address is entered into a form that populates the database, so after they enter in the addresss, city, state, zip (these are all US locations) they could click a "get lat/long info" link/button that would check to make sure the data is complete, then would lookup the address and return the latitude/longitude into the appropriate form fields. Then the form could be submitted to store the info, and I could later just pull the lat/long when plotting on a map. 1) Does this make sense, or would I be better off just doing the lookup when it's time to plot it? 2) Does anyone have any pointers to solve this problem? I've seen some of the Google/Yahoo API's but it looks like this is more based on the plotting a point part. I may be able to modify it to suit my needs, but I'm just trying to cut some research time posting here with the hopes one of you may have a more direct route. I'll RTFM if I have to... Thanks, D.

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  • doubt in javascript name validation

    - by raja
    Hi: I am using the below validation for textbox which accepts only alphabets and maximum of 50 characters. I am passing the object directly in the parameter. The below case by giving the field name i.e "my_text" directly is working is working fine. But if i pass it in variable, that time it is not working(commented the if statement). Please help me. My requirement is each time when we enter the charater, the hardcode field name should not be used in the validation. <html><head> <script language=JavaScript> function check_length(my_form,fieldName) { alert(fieldName); // if (my_form.fieldName.value.length >= maxLen) { if (my_form.my_text.value.length >= maxLen) { var msg = "You have reached your maximum limit of characters allowed"; alert(msg); my_form.my_text.value = my_form.my_text.value.substring(0, maxLen); } else{ var keyCode = window.event.keyCode; if ((keyCode < 65 || keyCode > 90) && (keyCode < 97 || keyCode > 123) && keyCode != 32) { window.event.returnValue = false; alert("Enter only Alphabets"); } my_form.text_num.value = maxLen - my_form.my_text.value.length;} } </script> </head> <body> <form name=my_form method=post> <input type="text" onKeyPress=check_length(this.form,this.name); name=my_text rows=4 cols=30> <br> <input size=1 value=50 name=text_num> Characters Left </form> </body> </html>

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  • Java Code for calculating Leap Year, is this code correct ?

    - by Ibn Saeed
    Hello I am following "The Art and Science of Java" book and it shows how to calculate a leap year. The book uses ACM Java Task Force's library. Here is the code the books uses: import acm.program.*; public class LeapYear extends ConsoleProgram { public void run() { println("This program calculates leap year."); int year = readInt("Enter the year: "); boolean isLeapYear = ((year % 4 == 0) && (year % 100 != 0) || (year % 400 == 0)); if (isLeapYear) { println(year + " is a leap year."); } else println(year + " is not a leap year."); } } Now, this is how I calculated the leap year. import acm.program.*; public class LeapYear extends ConsoleProgram { public void run() { println("This program calculates leap year."); int year = readInt("Enter the year: "); if ((year % 4 == 0) && year % 100 != 0) { println(year + " is a leap year."); } else if ((year % 4 == 0) && (year % 100 == 0) && (year % 400 == 0)) { println(year + " is a leap year."); } else { println(year + " is not a leap year."); } } } Is there anything wrong with my code or should i use the one provided by the book ? EDIT :: Both of the above code works fine, What i want to ask is which code is the best way to calculate the leap year.

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  • Programming help Loop adding

    - by Deonna
    I know this probably really simple but Im not sure what im doing wrong... The assignment states: For the second program for this lab, you are to have the user enter an integer value in the range of 10 to 50. You are to verify that the user enters a value in that range, and continue to prompt him until he does give you a value in that range. After the user has successfully entered a value in that range, you are to display the sum of all the integers from 1 to the value entered. I have this so far: #include <iostream.h> int main () { int num, sum; cout << "do-while Loop Example 2" << endl << endl; do { cout << "Enter a value from 10 to 50: "; cin >> num; if (num < 10 || num > 50) cout << "Out of range; Please try again..." << endl; } while (num < 10 || num > 50); { int i; int sum = 0; for (num = 1; num <= 50; num ++) sum = sum + num; } cout << endl << "The sum is " << sum << endl; return 0; } Im just not sure exactly what i'm doing wrong... I keep getting the wrong sum for the total...

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  • python global variable not working in apache

    - by Suhail
    I am facing issue with the global variable, when i run in the django development server it works fine, but in apache it doesn't work here is the code below: red= "/foodfolio3/test/" def showAddRecipe(request): #global objc if "userid" in request.session: objc["ErrorMsgURL"]= "" try: urlList= request.POST URL= str(urlList['url']) URL= URL.strip('http://') URL= "http://" + URL recipe= __addRecipeUrl__(URL) if (recipe == 'FailToOpenURL') or (recipe == 'Invalid-website-URL'): #request.session["ErrorMsgURL"]= "Kindly check URL, Please enter a valid URL" objc["ErrorMsgURL"]= "Kindly check URL, Please enter a valid URL" print "here global_context =", objc arurl= HttpResponseRedirect("/foodfolio3/add/import/") arurl['ErrorMsgURL']= objc["ErrorMsgURL"] #return HttpResponseRedirect("/foodfolio3/add/import/") #return render_to_response('addRecipeUrl.html', objc, context_instance = RequestContext(request)) return (arurl) else: objc["recipe"] = recipe return render_to_response('addRecipe.html', objc, context_instance = RequestContext(request)) except: objc["recipe"] = "" return render_to_response('addRecipe.html', objc, context_instance = RequestContext(request)) else: global red red= "/foodfolio3/add/" return HttpResponseRedirect("/foodfolio3/login") def showAddRecipeUrl(request): if "userid" in request.session: return render_to_response('addRecipeUrl.html', objc, context_instance = RequestContext(request)) else: global red red= "/foodfolio3/add/import/" return HttpResponseRedirect("/foodfolio3/login") def showLogin(request): obj = {} obj["error_message"] = "" obj["registered"] = "" if request.method == "POST": if (red == "/foodfolio3/test"): next= '/foodfolio3/recipes' else: next= red try: username = request.POST['username'] password = request.POST['password'] user = authenticate(username=username, password=password) except: user = authenticate(request=request) if user is not None: if user.is_active: login(request, user) request.session["userid"] = user.id # Redirect to a success page. return HttpResponseRedirect(next) this code works fine in django development server, but in apache, the url is getting redirected to '/foodfolio3/recipes'

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  • Apache is looking for htaccess and htpasswd files that aren't there

    - by user1094092
    Having an issue where Apache is requesting authentication, and looking for an .htpasswd file, based on instructions from an .htaccess file that's no longer in DocumentRoot. Background: In my DocumentRoot, I'd previously copied an .htaccess and .htpasswd file from another machine (along with all of the other website files). .htaccess contents: AuthType Basic AuthName "Password is required" AuthUserFile /some/directory/that/was/on/the/other/server/not/this/one/.htpasswd Require valid-user Here's the catch: I moved .htaccess and .htpasswd out of DocumentRoot and even renamed the files. There is no longer an .htaccess file in DocumentRoot at all. But, when I try to access localhost from a browser, I am prompted to enter the login and password. When I enter the login and password (from the old, not-in-DocumentRoot .hpasswd file), I get a 500 Internal Server error and the log shows: [error] [client 127.0.0.1] (2)No such file or directory: Could not open password file: /some/directory/that/was/on/the/other/server/not/this/one/.htpasswd This has been quite a puzzle, because there's no longer a .htaccess or .htpasswd file anywhere in DocumentRoot !! Have tried several apache restarts and also tried using a blank .htaccess file in the DocumentRoot. Even grepped the entire machine for references to AuthType Basic to see if I missed anything. httpd.conf looks normal enough...I can post that if needed, but this question seems long enough as it is :) Thanks for any assistance you can provide

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  • Is there a FAST way to export and install an app on my phone, while signing it with my own keystore?

    - by Alexei Andreev
    So, I've downloaded my own application from the market and installed it on my phone. Now, I am trying to install a temporary new version from Eclipse, but here is the message I get: Re-installation failed due to different application signatures. You must perform a full uninstall of the application. WARNING: This will remove the application data! Please execute 'adb uninstall com.applicationName' in a shell. Launch canceled! Now, I really really don't want to uninstall the application, because I will lose all my data. One solution I found is to Export my application, creating new .apk, and then install it via HTC Sync (probably a different program based on what phone you have). The problem is this takes a long time to do, since I need to enter the password for the keystore each time and then wait for HTC Sync. It's a pain in the ass! So the question is: Is there a way to make Eclipse automatically use my keystore to sign the application (quickly and automatically)? Or perhaps to replace debug keystore with my own? Or perhaps just tell it to remember the password, so I don't have to enter it every time...? Or some other way to solve this problem?

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  • Release edit in QTableWidget Cell

    - by Schomin
    Basically I am trying to give the enter key the same functionality as the return key has when editing a cell in a qtablewidget. If editing a cell and enter is pressed I want it to jump out of editing that cell just like return does. It feels like I've literally tried everything. I've even tried passing a return press event to qcoreapplication. It seems like if your editing a cell and you press a key to trigger an action it wont happen. That seems to be what the problem is and I'm not sure how to get around that. I've been setting up all of my keyboard shortcuts for this program as actions because it seems easier to set up. Is there another way to do this that would allow the key event to happen when editing a cell? Can anyone help out with this? Thank you in advance. Tried this. It didn't work for me. http://stackoverflow.com/questions/518447/how-can-i-tell-a-qtablewidget-to-end-editing-a-cell

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  • How to change this C++ code to make input work better

    - by Phenom
    cout << "Input street number: "; cin >> streetnum; cout << "Input street name: "; cin >> streetname; cout << "Input resource name: "; cin >> rName; cout << "Input architectural style: "; cin >> aStyle; cout << "Input year built: "; cin >> year; The problem with the above code happens if you enter in spaces between words. For example if I enter "Ampitheater Parkway" for streetname, then it puts "Ampitheater" in streetname, skips the prompt for resource name and enters "Parkway" into the next field. How can I fix this?

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  • How use unobtrusive validation without a model

    - by Ross Cyrus
    i have simple a form wich made by htmlHelper(mvc3) then inside of it i have 2 input field 1:type=text 2:type=submit to submit the form. there is no model behind.so i need to perfom a clientside validation on the textfield before submit it to the server.but i dont know how. i tried this puting manualy the 'data-* artibute , but does not work : @using( Html.BeginForm()) { <label for="UserName" >User Name</label> <div class="editor-field"> <input type="text" data-val="true" data-val-requierd="You must provide an user Name" id="userName" name="userName" placeholder="Enter Your User Name" /> </div> <input type="submit" value="Recover" /> } the "jquery.validate.min.js" and jquery.validate.unobtrusive.min.js and jquery.validate.min.js and jquery.validate.unobtrusive.min.js are loaded to the page. It doesnt let me to answer my self ,so i put it here : I solve it my self,just made an other view wich has its own model and Required on its propertyis and then just copy the renderd html to my own,and i got this and works : <input data-val="true" data-val-required="You must provide an user Name" id="UserName" name="UserName" type="text" value="" placeholder="Enter your User Name"/> <span class="field-validation-valid" data-valmsg-for="UserName" data-valmsg-replace="true"></span> And there is no type="Required".any way thank you guys.

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  • PHP Class Question

    - by Jerry
    Hi all I am trying to build a PHP class to check the username and password in MySql. I am getting "mysql_query(): supplied argument is not a valid MySQL-Link resource in D:\2010Portfolio\football\main.php on line 38" database has errors:" message. When I move my userQuery code out of my Class, it works fine. Only if it is inside my Class. I am not sure if the problem is that I don't build the connection to mysql inside my Class or not. Thanks for any helps!! Here is my code <?php $userName=$_POST['userName']; $userPw=$_POST['password']; class checkUsers { public $userName; public $userPw; function checkUsers($userName='', $userPw=''){ $this->userName=$userName; $this->userPw=$userPw; } function check1(){ if (empty($this->userName) || empty($this->userPw)){ $message="<strong>Please Enter Username and Password</strong>"; }else{ //line 38 is next line $userQuery=mysql_query("SELECT userName, userPw FROM user WHERE userName='$this->userName' and userPw='$this->userPw'", $connection); if (!$userQuery){ die("database has errors: ". mysql_error()); } if(mysql_num_rows($userQuery)==0){ $message="Please enter valid username and password"; } }//end empty check return $message; }//end check1 method }//end Class $checkUser=new checkUsers($userName, $userPw); echo $checkUser->check1(); ?> I appreciate any helps!!!!

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  • How to see external libraries code when debugging

    - by Sanva
    Hello!! First of all... this is my message #1 in this place, so... please be nice with me ;) I just started recently to study Gnome apps/libraries and I found that debuggers are an excellent way to learn, because seeing the code running helps a lot in understanding the structure of the program. But I have a problem. For example, debugging gnome-panel I found a lot of calls to external functions (basically the GTK+ functions), and although pretending to see all the code of all the functions applications like this call would be crazy, there are a lot that will be very interesting to see in action. The problem is that the debugger hasn't the code of those libraries loaded and it can't show it to me —at most it shows the line number where the execution is. I'm using Nemiver and when it tries to enter in an external function it claims because it can't find a file it supposed to be somewhere. For example, trying to enter in gtk_window_set_default_icon_name it tries to load /build/buildd/gtk+2.0-2.16.1/gtk/gtkwindow.c, and calling XSetIOErrorHandler, ../../src/ErrHndlr.c. So now I think that I'm doing something wrong... Why Nevimer are looking for those source files in those places?? My system does not even have the /build/buildd/ folders... and I don't know if I'm doing something wrong or I need to install somethig or what. Any suggestion? How do you debug this kind of applications? Best regards and thanks a lot for your time —and forgive me if my English is bad.

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  • Segmentation fault in C recursive Combination (nCr)

    - by AruniRC
    PLease help me out here. The program is supposed to recursively find out the combination of two numbers. nCr = n!/ (r!(n-r)! ). I'm getting this error message when i compile it on GCC. Here's what the terminal shows: Enter two numbers: 8 4 Segmentation fault (Program exited with code:139) The code is given here: #include<stdio.h> float nCr(float, float, float); int main() { float a, b, c; printf("Enter two numbers: \n"); scanf("%f%f", &a, &b); c = nCr(a, b, a-b); printf("\n%.3f", c); return 0; } float nCr(float n, float r, float p) { if(n<1) return (1/(p*r))*(nCr(1, r-1, p-1)); if(r<1) return (n/(p*1))*(nCr(n-1, 1, p-1)); if(p<1) return (n/r)*(nCr(n-1, r-1, 1)); return ( n/(p*r) )*nCr(n-1, r-1, p-1); }

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  • how to put header authentication into a form using php?

    - by SkyWookie
    Hey guys, for the page I am doing needs a login authentication using Twitter (using tweetphp API). For test purposes I used this code below to do a successful login: if (!isset($_SERVER['PHP_AUTH_USER'])){ header('WWW-Authenticate: Basic realm="Enter your Twitter username and password:"'); header('HTTP/1.0 401 Unauthorized'); echo 'Please enter your Twitter username and password to view your followers.'; exit(); } $username = $_SERVER['PHP_AUTH_USER']; $password = $_SERVER['PHP_AUTH_PW']; The problem now is, I want to integrate it into a form, so far I have the following: <form action="logincheck.php" method="post" class="niceform" > <fieldset> <legend>Twitter Login:</legend> <dl> <dt><label for="email">Twitter Username:</label></dt> <dd><input type="text" name="username" id="username" size="32" maxlength="128" /></dd> </dl> <dl> <dt><label for="password">Password:</label></dt> <dd><input type="password" name="password" id="password" size="32" maxlength="32" /></dd> </dl> </fieldset> <fieldset class="action"> <input type="submit" name="submit" id="submit" value="Submit" /> I am sending it to logincheck.php, this is where I think I get stuck. I am not sure how to compare the form data with Twitter's login data. I was trying a similar if statement as I used in the first code (box that pops up before page loads), but I couldn't wrap my head around it. Thanks again guys!

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  • Trying to output a list using class

    - by captain morgan
    Am trying to get the moving average of a price..but i keep getting an attribute error in my Moving_Average class. ('Moving_Average' object has no attribute 'days'). Here is what I have: class Moving_Average: def calculation(self, alist:list,days:int): m = self.days prices = alist[1::2] average = [0]* len(prices) signal = ['']* len(prices) for m in range(0,len(prices)-days+1): average[m+2] = sum(prices[m:m+days])/days if prices[m+2] < average[m+2]: signal[m+2]='SELL' elif prices[m+2] > average[m+2] and prices[m+1] < average[m+1]: signal[m+2]='BUY' else: signal[m+2] ='' return average,signal def print_report(symbol:str,strategy:str): print('SYMBOL: ', symbol) print('STRATEGY: ', strategy) print('Date Closing Strategy Signal') def user(): strategy = ''' Which of the following strategy would you like to use? * Simple Moving Average [S] * Directional Indicator[D] Please enter your choice: ''' if signal_strategy in 'Ss': days = input('Please enter the number of days for the average') days = int(days) strategy = 'Simple Moving Average {}-days'.format(str(days)) m = Moving_Average() ma = m.calculation(gg, days) print(ma) gg is an list that contains date and prices. [2013-10-01,60,2013-10-02,60] The output is supposed to look like: Date Price Average Signal 2013-10-01 60.0 2013-10-02 60.0 60.00 BUY

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  • Inorder tree traversal in binary tree in C

    - by srk
    In the below code, I'am creating a binary tree using insert function and trying to display the inserted elements using inorder function which follows the logic of In-order traversal.When I run it, numbers are getting inserted but when I try the inorder function( input 3), the program continues for next input without displaying anything. I guess there might be a logical error.Please help me clear it. Thanks in advance... #include<stdio.h> #include<stdlib.h> int i; typedef struct ll { int data; struct ll *left; struct ll *right; } node; node *root1=NULL; // the root node void insert(node *root,int n) { if(root==NULL) //for the first(root) node { root=(node *)malloc(sizeof(node)); root->data=n; root->right=NULL; root->left=NULL; } else { if(n<(root->data)) { root->left=(node *)malloc(sizeof(node)); insert(root->left,n); } else if(n>(root->data)) { root->right=(node *)malloc(sizeof(node)); insert(root->right,n); } else { root->data=n; } } } void inorder(node *root) { if(root!=NULL) { inorder(root->left); printf("%d ",root->data); inorder(root->right); } } main() { int n,choice=1; while(choice!=0) { printf("Enter choice--- 1 for insert, 3 for inorder and 0 for exit\n"); scanf("%d",&choice); switch(choice) { case 1: printf("Enter number to be inserted\n"); scanf("%d",&n); insert(root1,n); break; case 3: inorder(root1); break; default: break; } } }

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  • c++ issues with cin.fail() in my program

    - by Wallace
    I want to use input y to do saving thing,and r to do resuming, but then i write it in the following codes,and then I input y or r,I just to be noticed ""Please enter two positve numbers" this line code "if(x==(int)('y'))"and next line is ignored.how could this happen int main(){ cout<<"It's player_"<<player+1<<"'s turn please input a row and col,to save and exit,input 0,resume game input"<<endl; while(true){ cin>>x; if(x==(int)('y')) {save();has_saved=true;break;} if(x==(int)('r')) {resume();has_resumed=true;break;} cin>>y; if(cin.fail()){ cout<<"Please enter two positve numbers"<<endl; cin.clear(); cin.sync();} else if (x>n||x<1||y<1||y>n) { cout<<"your must input a positive number less or equal than "<<n<<endl; continue;} else if(chessboard[x][y]!=' ') {cout<<"Wrong input please try again!"<<endl; continue;} else { chessboard[x][y]=player_symbol[player+1]; break; } } }

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  • Getting User input with Scanner

    - by Giannis
    I am trying to have a scanner take input in a loop. Once the user wants to finish he can exit this loop. I have tried many different ways to do it but there is always some problem. This is the code: Scanner sc = new Scanner(System.in); System.out.println("Continue?[Y/N]"); while (sc.hasNext()&& (sc.next().equals("Y"))) { System.out.println("Enter first name"); String name = sc.nextLine(); System.out.println("Enter surname"); String surname = sc.nextLine(); . . . System.out.println("Continue?[Y/N]"); } } The problem with the code above, which also happens on different methods I tried, is that when the user types Y, the scanner will skip the first input for first name,and jump to the surname. If the user types N the loop stops correctly. Someone can explain the reason this happens, and how to overcome using scanner class? p.s: Doing something like while(sc.nextLine().equals("Y")), will cause the loop to terminate before getting input from user after first run of the loop.

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  • To OpenID or not to OpenID? Is it worth it?

    - by Eloff
    Does OpenID improve the user experience? Edit Not to detract from the other comments, but I got one really good reply below that outlined 3 advantages of OpenID in a rational bottom line kind of way. I've also heard some whisperings in other comments that you can get access to some details on the user through OpenID (name? email? what?) and that using that it might even be able to simplify the registration process by not needing to gather as much information. Things that definitely need to be gathered in a checkout process: Full name Email (I'm pretty sure I'll have to ask for these myself) Billing address Shipping address Credit card info There may be a few other things that are interesting from a marketing point of view, but I wouldn't ask the user to manually enter anything not absolutely required during the checkout process. So what's possible in this regard? /Edit (You may have noticed stackoverflow uses OpenID) It seems to me it is easier and faster for the user to simply enter a username and password in a signup form they have to go through anyway. I mean you don't avoid entering a username and password either with OpenID. But you avoid the confusion of choosing a OpenID provider, and the trip out to and back from and external site. With Microsoft making Live ID an OpenID provider (More Info), bringing on several hundred million additional accounts to those provided by Google, Yahoo, and others, this question is more important than ever. I have to require new customers to sign up during the checkout process, and it is absolutely critical that the experience be as easy and smooth as possible, every little bit harder it becomes translates into lost sales. No geek factor outweighs cold hard cash at the end of the day :) OpenID seems like a nice idea, but the implementation is of questionable value. What are the advantages of OpenID and is it really worth it in my scenario described above?

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  • php not well formed?

    - by Idealflip
    Hi Everyone, when my site loads, it stops half way because of specific php code. When I try commenting out the php code, the whole page loads properly (input boxes, buttons etc.) This is the code that causes the issue <?php //if the add location button is clicked, the add location, the whole form will not be submitted if($_REQUEST['command'] == 'Add'){ if($_POST['companyLocation'] == ""){ $errmsg="Please enter a location1"; } elseif($_POST['companySize'] == ""){ $errmsg="Please enter a size for the location"; } else{ $location = Location::instance(); $testing = $location->doesExist($_POST['companyLocation']); if ($testing == true){ $errmsg="Location already exists"; } else{ $objLocation = new Obj_Location(); $objLocation->set_Name($_POST['companyLocation']); $objLocation->set_Size($_POST['companySize']); $location->addLocation($objLocation); $location->saveInstance(); } } } //this is the part that breaks! when I comment it out, the page loads properly. $location = Location::instance(); $location->deleteItem($_GET["item"]); $location->saveInstance(); $location->listItems(); ?>

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  • Prime Numbers in C?

    - by Ali Azam Rana
    FIRST PROGRAM #include<stdio.h> void main() { int n,c; printf("enter a numb"); scanf("%i",n); for(c=2;c<=n;c++) { if(n%c==0) break; } if(c==n) printf("\nprime\n"); else printf("\nnot prime\n"); getchar(); } SECOND PROGRAM #include <stdio.h> int main() { printf("Enter a Number\n"); int in,loop,rem,chk; scanf("%d",&in); for (loop = 1; loop <=in; loop++) { rem = in % loop; if(rem == 0) chk = chk +1; } if (chk == 2) printf("\nPRIME NUM ENTERED\n"); else printf("\nNUM ENTERED NOT PRIME\n"); getchar(); } the 2nd program works other was the one my friend wrote the program looks fine but on checking it by stepping into we found that the if condition in first program is coming true under every input so whats the logical error here please help me found out......

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  • An error saying unidentifed function "push", "pop", and"display" occurs, what should i add to fix i

    - by Alesha Aris
    #include<stdio.h> #include<iostream.h> #include<conio.h> #include<stdlib.h>(TOP) #include<fstream.h> #define MAX 5 int top = -1; int stack_arr[MAX]; main() { int choice; while(1) { printf("1.Push\n"); printf("2.Pop\n"); printf("3.Display\n"); printf("4.Quit\n"); printf("Enter your choice : "); scanf("%d",&choice); switch(choice) { case 1 : push(); break; case 2: pop(); break; case 3: display(); break; case 4: exit(1); default: printf("Wrong choice\n"); }/*End of switch*/ }/*End of while*/ }/*End of main()*/ push() { int pushed_item; if(top == (MAX-1)) printf("Stack Overflow\n"); else { printf("Enter the item to be pushed in stack : "); scanf("%d",&pushed_item); top=top+1; stack_arr[top] = pushed_item; } }/*End of push()*/ pop() { if(top == -1) printf("Stack Underflow\n"); else { printf("Popped element is : %d\n",stack_arr[top]); top=top-1; } }/*End of pop()*/ display() { int i; if(top == -1) printf("Stack is empty\n"); else { printf("Stack elements :\n"); for(i = top; i >=0; i--) printf("%d\n", stack_arr[i] ); } }/*End of display()*/

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  • Optimization in Common Decalaration

    - by Pratik
    Its a 3-tier ASP.NET Website Project In Data Layer there is class "Common Decalaration" in which lot of common things are mentioned. Something this way : public class CommonDeclartion { #region Common Messages public const string RECORD_INSERT_MSG = "Record Inserted Successfully "; public const string RECORD_UPDATE_MSG = "Record Updated Successfully"; public const string RECORD_DELETE_MSG = "Record Deleted Successfully"; public const string ERROR_MSG = "Error Ocuured while Perfoming This Action."; public const string UserID_Incorrect = "Please Enter The Correct User ID."; public const string RECORD_ALREADY_EXIT = "Record Already Exit"; public const string NO_RECORD = "No Record found."; #endregion } Can this be more optimized in terms of : 1.Perfomance 2.Security(if any) 3.Code Readablity or Reusablity I thought of using enum but can't figure that out : enum CommonMessages { RECORD_INSERT_MSG "Record Inserted Successfully.", RECORD_UPDATE_MSG "Record Updated Successfully.", RECORD_DELETE_MSG "Record Deleted Successfully.", ERROR_MSG "Error Ocuured while Perfoming This Action.", UserID_Incorrect "Please Enter The Correct User ID.", RECORD_ALREADY_EXIT "Record Already Exit.", NO_RECORD "No Record found.", } or else should keep them in some collections like dictionary/NameValueCollection or so or i have to keep them in XML in form of key/value pair and reterive from it ? What can be better way keeping in mind 1.Perfomance 2.Security(if any) 3.Code Readablity or Reusablity

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  • jQuery Form Validation being bypassed

    - by user1953681
    Can someone tell me what is wrong with my jQuery validation? It is not validating my form, rather, just ignoring the code resulting in no check of the inputs. Form: <form class="form" accept-charset="UTF-8" action="URL-to-complete-form" method="POST" onsubmit="return validateForm();"> <input class="form-name" type="text" placeholder="Name"></div> <input class="form-email" type="text"placeholder="Email"></div> <input style="background-color: #fc8f12;" type="submit" value="Subscribe"> </div> </form> Javascript: function validateForm() { // Validate Name var title = $(".form-name").val(); if (title=="" ||title=="Name" || title==null) { } else { alert("Please enter a name!"); } // Validate Email var email = $(".form-email").val(); if ((/(.+)@(.+){2,}\.(.+){2,}/.test(email)) || email=="" || email=="Email" || email==null) { } else { alert("Please enter a valid email"); } return false; } Thank you all for your time and help.

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