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  • What is wrong with my PHP/MySQL code?

    - by James
    I am building a navigation menu which lists all my categories and subcategories. The problem is it returns only one of these and not all. I have the categories echoed inside the while loop so I'm not sure why it's only showing one result and not all: <?php $query = mysql_query("SELECT * FROM categories_parent"); while ($row = mysql_fetch_assoc($query)) { $id = $row['id']; $name = $row['name']; $slug = $row['slug']; $childStatus = $row['child_status']; // if has child categories if ($childStatus == "1") { echo "<li class='dir'><a href='category.php?slug=$slug'>$name</a>"; echo "<ul id='dropdown'>"; $query = mysql_query("SELECT * FROM categories_child WHERE parent=$id"); while ($row = mysql_fetch_assoc($query)) { $id = $row['id']; $name = $row['name']; $slug = $row['slug']; echo "<li><a href='category.php?slug=$slug'>$name</a></li>"; } echo "</ul>"; echo "</li>"; } // if singular parent else { echo "<li><a href='category.php?slug=$slug'>$name</a></li>"; } } ?> My database tables: -- -- Table structure for table `categories_child` -- CREATE TABLE IF NOT EXISTS `categories_child` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(1000) NOT NULL, `slug` varchar(1000) NOT NULL, `parent` int(11) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=139 ; -- -- Dumping data for table `categories_child` -- INSERT INTO `categories_child` (`id`, `name`, `slug`, `parent`) VALUES (138, 'Britney Spears', 'category/celiberties/britney-spears/', 137), (136, 'Tigers', 'category/animals/tigers/', 136), (137, 'Horses', 'category/animals/horses/', 136), (135, 'Lions', 'category/animals/lions/', 136); -- -- Table structure for table `categories_parent` -- CREATE TABLE IF NOT EXISTS `categories_parent` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(1000) NOT NULL, `slug` varchar(1000) NOT NULL, `child_status` int(1) NOT NULL DEFAULT '0', PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=139 ; -- -- Dumping data for table `categories_parent` -- INSERT INTO `categories_parent` (`id`, `name`, `slug`, `child_status`) VALUES (137, 'Celiberties', 'category/celiberties/', 1), (138, 'TV Shows', 'category/tv-shows/', 0), (136, 'Animals', 'category/animals/', 1);

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  • dynamic html table

    - by coder247
    hello... I've to create a dynamic html table using the values configured in a table. I've a row number,column number and value fields in table. if the values are 1,5 and HELLO correspondingly, then i've to disply this HELLO in row 1 and column 5. The table structure is like the following. row column value 1 5 value1 2 8 value2 Any ideas pls...

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  • mysql select top users problem

    - by moustafa
    i have users table and i have posts table i want select from users the top users that have the big amount of posts from posts table and order them by numbers of posts i can make it by array_count_values() by i cant order it now i think if i make it by one mysql query by left and join will be more better table structure posts id | auther_id

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  • Update Table in Asp.Net MVC

    - by Xulfee
    I have table on page i want to delete record from table and also update table after deletion record. <%= Ajax.ActionLink("Delete Ajax", "PostTypeDelete",new { id = item.int_PostTypeId }, new AjaxOptions{LoadingElementId="status"}) %> I used above code its working fine (it delete record) but it doesn't update table.

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  • jQuery table filter with text, checkboxes, selects

    - by Jeffrey
    Need to filter a table from outside of the table, with a text search, checkboxes, and selects. PicNet Table Filter for jQuery works for both searching and using checkboxes outside of the table... though I can't find any examples of how to get a select box to work. Anyone know? *I might be getting too specific here, but thought I'd at least inquire. I'm also open to possibilities other than PicNet.

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  • jquery delegate table rows selector

    - by Jackob
    I have a table which may contains other inner tables (it's not possible to edit generated markup). I want to create a delegate function for row mouseenter and mouseleave which only triggers for the associated main table rows (and not inner tables rows), as following: $("#tableid").delegate("tr", "mouseenter mouseleave", function(e) { //do stuff here }); But with this selector it selects also the inner table rows, so how can I modify the selector to avoid selecting inner table rows?

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  • MySQL Optimization 20 gig table

    - by user169743
    I have a 20 gig table that has a large amount of inserts and updates daily. This table is also frequently searched. I'd like to know if the MySQL indices can become fragmented and perhaps need to be rebuilt or something similar. I'm finding it difficult to figure out which of the CHECK TABLE, REPAIR TABLE or something similar? Any guidance appreciated, I'm a db newb.

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  • HTML table ignoring element-style width

    - by sangil
    HTML table ignoring element-style width I have an HTML table where certain cells have very long text contents. I want to specify a width (in pixels) for these cells using jQuery, but the rendered table just ignores the given width. Is there any way to force the table to respect this width? Thanks! JSFiddle: http://jsfiddle.net/sangil/6hejy/35/ (If you inspect the cell you can see the the computed width is different than the element-style width) HTML: <div id="tblcont" class="tblcont"> <table id="pivot_table"> <tbody> <tr> <th id="h0" >product</th> <th id="h1" >price</th> <th id="h2" >change</th> </tr> <tr> <!-- this is the cell causing trouble --> <td id="c00" >Acer 2400 aaaaaaaaaaaaaaaaaaaaaaaaaa</td> <td id="c01" >3212</td> <td id="c02" >219</td> </tr> <tr> <td id="c10" >Acer</td> <td id="c11" >3821</td> <td id="c12" >206</td> </tr> </tbody> </table> </div> CSS: .tblcont { overflow: hidden; width: 500px; } table { table-layout: fixed; border-collapse: collapse; overflow-x: scroll; border-spacing:0; width: 100%; } th, td { overflow: hidden; text-overflow: ellipsis; word-wrap: break-word; } th { height: 50px; } ?Javascript: $(document).ready(function() { // THIS LINE HAS NO EFFECT! $('#c00').width(30); });

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  • Sphinx Mysql Tutorial Help

    - by Frederico
    I have just implemented the Sphinx Storage Engine, and created my first Sphinx table, I'm trying to convert from using my Fulltext MyISAM table, so I figured I would just dump all the data into a sphinx table.. obviously I was wrong. Are there any great tutorials that really take you through transforming a fulltext search on MySQL to a sphinx table? Thanks in advance.

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  • PHP MySQL Select multiple tables

    - by Jordan Pagaduan
    Is it posibble to select 3 tables at a time in 1 database? Table 1: employee -- employee_id -- first_name -- last_name -- middle_name -- birthdate -- address -- gender -- image -- salary Table 2: logs -- log_id -- full_name -- employee_id -- date -- time -- status Table 2: logout -- log_id -- full_name -- employee_id -- date -- time -- status I wanted to get the value of employee table where $id of selected. Then the $id also get the value of log.time, log.date, logout.time, and logout.date. I already try using UNION but nothing happens.

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  • Insert Registration Data in MySQL using PHP

    - by J M 4
    I may not be asking this in the best way possible but i will try my hardest. Thank you ahead of time for your help: I am creating an enrollment website which allows an individual OR manager to enroll for medical testing services for professional athletes. I will NOT be using the site as a query DB which anybody can view information stored within the database. The information is instead simply stored, and passed along in a CSV format to our network provider so they can use as needed after the fact. There are two possible scenarios: Scenario 1 - Individual Enrollment If an individual athlete chooses to enroll him/herself, they enter their personal information, submit their payment information (credit/bank account) for processing, and their information is stored in an online database as Athlete1. Scenario 2 - Manager Enrollment If a manager chooses to enroll several athletes he manages/ promotes for, he enters his personal information, then enters the personal information for each athlete he wishes to pay for (name, address, ssn, dob, etc), then submits payment information for ALL athletes he is enrolling. This number can range from 1 single athlete, up to 20 athletes per single enrollment (he can return and complete a follow up enrollment for additional athletes). Initially, I was building the database to house ALL information regardless of enrollment type in a single table which housed over 400 columns (think 20 athletes with over 10 fields per athlete such as name, dob, ssn, etc). Now that I think about it more, I believe create multiple tables (manager(s), athlete(s)) may be a better idea here but still not quite sure how to go about it for the following very important reasons: Issue 1 If I list the manager as the parent table, I am afraid the individual enrolling athlete will not show up in the primary table and will not be included in the overall registration file which needs to be sent on to the network providers. Issue 2 All athletes being enrolled by a manager are being stored in SESSION as F1FirstName, F2FirstName where F1 and F2 relate to the id of the fighter. I am not sure technically speaking how to store multiple pieces of information within the same table under separate rows using PHP. For example, all athleteswill have a first name. The very basic theory of what i am trying to do is: If number_of_athletes 1, store F1FirstName in row 1, column 1 of Table "Athletes"; store F1LastName in row 1, column 2 of Table "Athletes"; store F2FirstName in row 2, column 1 of Table "Athletes"; store F2LastName in row 2, column 2 of table "Athletes"; Does this make sense? I know this question is very long and probably difficult so i appreciate the guidance.

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  • fastest way to copy a table in mysql

    - by Anon
    which one is the fastest way to completely copy a table on mysql ? CREATE TABLE copy LIKE original; INSERT INTO copy SELECT * FROM original; or CREATE TABLE copy SELECT * FROM original; ALTER TABLE copy ADD PRIMARY KEY (id); or theres another way ? PS. can't use command-line tools like mysqldump, must be on-the-fly.

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  • make VIEW of SHOW TABLE query

    - by cneeds
    Is there a way to make a VIEW of this SHOW TABLE query? SHOW FULL TABLES FROM `db_name` WHERE `Table_type` = "Base table" When I save this as a view (using phpMyAdmin) I get #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'SHOW FULL TABLES FROM `db_name` WHERE `Table_type` = "Base table"' at line 4 when phpMyAdmin tries to execute this CREATE ALGORITHM = UNDEFINED VIEW `Tables` AS SHOW FULL TABLES FROM `db_name` WHERE `Table_type` = "Base table"

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  • multiple lines in a cell of a table

    - by Tim
    I has a table as shown in this figure: The latex code for the table is: \begin{table} \begin{tabular}{ | c | c | } \hline \includegraphics[scale=0.45]{../0_1.eps} & 1.10 2.20 3.30 4.40 \\ \hline \end{tabular} \end{table} I would like to make the four numbers appear in different line inside the second cell, in order to reduce its width. I wonder how to do it? Thanks and regards!

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  • Java exercise - display table with 2d array

    - by TheHacker66
    I'm struggling to finish a java exercise, it involves using 2d arrays to dinamically create and display a table based on a command line parameter. Example: java table 5 +-+-+-+-+-+ |1|2|3|4|5| +-+-+-+-+-+ |2|3|4|5|1| +-+-+-+-+-+ |3|4|5|1|2| +-+-+-+-+-+ |4|5|1|2|3| +-+-+-+-+-+ |5|1|2|3|4| +-+-+-+-+-+ What i have done so far: public static void main(String[] args) { int num = Integer.parseInt(args[0]); String[][] table = new String[num*2+1][num]; int[] numbers = new int[num]; int temp = 0; for(int i=0; i<numbers.length; i++) numbers[i] = i+1; // wrong for(int i=0; i<table.length; i++){ for(int j=0; j<num;j++){ if(i%2!=0){ temp=numbers[0]; for(int k=1; k<numbers.length; k++){ numbers[k-1]=numbers[k]; } numbers[numbers.length-1]=temp; for(int l=0; l<numbers.length; l++){ table[i][j] = "|"+numbers[l]; } } else table[i][j] = "+-"; } } for(int i=0; i<table.length; i++){ for(int j=0; j<num; j++) System.out.print(table[i][j]); if(i%2==0) System.out.print("+"); else System.out.print("|"); System.out.println();} } This doesn't work, since it prints 1|2|3|4 in every row, which isn't what i need. I found the issue, and it's because the first for loop changes the array order more times than needed and basically it returns as it was at the beginning. I know that probably there's a way to achieve this by writing more code, but i always tend to nest as much as possible to "optimize" the code while i write it, so that's why i tried solving this exercise by using less variables and loops as possible. Thanks in advance for your help!

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  • mysql join table - selecting the newest row

    - by cmancre
    Hi, I have the following two MySQL tables TABLE NAMES NAME_ID NAME 1 name1 2 name2 3 name3 TABLE STATUS STATUS_ID NAME_ID TIMESTAMP 1 1 2010-12-20 12:00 2 2 2010-12-20 10:00 3 3 2010-12-20 10:30 4 3 2010-12-20 14:00 I would like to select all info from table NAMES and add most recent correspondent TIMESTAMP column from table STATUS RESULT NAME_ID NAME TIMESTAMP 1 name1 2010-12-20 12:00 2 name2 2010-12-20 10:00 3 name3 2010-12-20 14:00 Am stuck on this one. How do I left join only on the newer timestamp?

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  • MySQL Database Query - Codeigniter

    - by user2450349
    I am building an application with Codeigniter and need some help with a DB query. I have a table called users with the following fields: user_id, user_name, user_password, user_email, user_role, user_manager_id In my app, I pull all records from the user table using the following: function get_clients() { $this->db->select('*'); $this->db->where('user_role', 'client'); $this->db->order_by("user_name", "Asc"); $query = $this->db->get("users"); return $query->result_array(); } This works as expected, however when I display the results in the view, I also want to display a new column called Manager which will display the managers user_name field. The user_manager_id is the id of the user from the same table. Im guessing you can create an outer join on the same table but not sure. In the view, I am displaying the returned info as follows: <table class="table table-striped" id="zero-configuration"> <thead> <tr> <th>Name</th> <th>Email</th> <th>Manager</th> </tr> </thead> <tbody> <?php foreach($clients as $row) { ?> <tr> <td><?php echo $row['user_name']; ?> (<?php echo $row['user_username']; ?>)</td> <td><?php echo $row['user_email']; ?></td> <td><?php echo $row['???']; ?></td> </tr> <?php } ?> </tbody> </table> Any idea of how I can form the query and display the manager name is the view? Example: user_id user_name user_password user_email user_role user_manager_id 1 Ollie adjjk34jcd [email protected] client null 2 James djklsdfsdjk [email protected] client 1 When i query the database, i want to display results like this: Ollie [email protected] James [email protected] Ollie

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  • is Payment table needed when you have an invoice table like this?

    - by EBAGHAKI
    this is my invoice table: Invoice Table: invoice_id creation_date due_date payment_date status enum('not paid','paid','expired') user_id total_price I wonder if it's Useful to have a payment table in order to record user payments for invoices. payment table can be like this: payment_id payment_date invoice_id price_paid status enum('successful', 'not successful')

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  • MYSQL UPDATE with IN and Subquery

    - by Johal
    Hi i have tables like this : table entry : id | total_comments ___________ 1 | 0 2 | 0 3 | 0 4 | 0 table comments : id | eid | comment ___________ 1 | 1 | comment sdfd 2 | 1 | testing testing 3 | 1 | comment text 4 | 2 | dummy comment 5 | 2 | sample comment 6 | 1 | fg fgh dfh Query i write : UPDATE entry SET total_comments = total_comments + 1 WHERE id IN ( SELECT eid FROM comments WHERE id IN (1,2,3,4,5,6)) Results i get is : table entry : id | total_comments ___________ 1 | 1 2 | 1 3 | 0 4 | 0 Expected results : table entry : id | total_comments ___________ 1 | 4 2 | 2 3 | 0 4 | 0 Any help will be appreciated.

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  • Bulk Update in MYSQl

    - by user351806
    I have a site which has client side and admin side. There is a table called account History. which contains fields like uid | accountBalance | PaymentStatus | Date. Now this table has to be updated every month for all the paid users and the table is bulk. So what is the best way to update the table every month.Do i need to select all the uid's and update.

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  • PHP/MySQL allowing current user to edit there account information

    - by user1837896
    i have created 2 pages update.php edit.php we start on edit.php so here is edit.php's script <?php session_start(); $id = $_SESSION["id"]; $username = $_POST["username"]; $fname = $_POST["fname"]; $password = $_POST["password"]; $email = $_POST["email"]; mysql_connect('mysql13.000webhost.com', 'a2670376_Users', 'Password') or die(mysql_error()); echo "MySQL Connection Established! <br>"; mysql_select_db("a2670376_Pass") or die(mysql_error()); echo "Database Found! <br>"; $query = "UPDATE members SET username = '$username', fname = '$fname', password = '$password' WHERE id = '$id'"; $res = mysql_query($query); if ($res) echo "<p>Record Updated<p>"; else echo "Problem updating record. MySQL Error: " . mysql_error(); ?> <form action="update.php" method="post"> <input type="hidden" name="id" value="<?=$id;?>"> ScreenName:<br> <input type='text' name='username' id='username' maxlength='25' style='width:247px' name="username" value="<?=$username;?>"/><br> FullName:<br> <input type='text' name='fname' id='fname' maxlength='20' style='width:248px' name="ud_img" value="<?=$fname;?>"/><br> Email:<br> <input type='text' name='email' id='email' maxlength='50' style='width:250px' name="ud_img" value="<?=$email;?>"/><br> Password:<br> <input type='text' name='password' id='password' maxlength='25' style='width:251px' value="<?=$password;?>"/><br> <input type="Submit"> </form> now here is the update.php page where i am having the MAJOR problem <?php session_start(); mysql_connect('mysql13.000webhost.com', 'a2670376_Users', 'Password') or die(mysql_error()); mysql_select_db("a2670376_Pass") or die(mysql_error()); $id = (int)$_SESSION["id"]; $username = mysql_real_escape_string($_POST["username"]); $fname = mysql_real_escape_string($_POST["fname"]); $email = mysql_real_escape_string($_POST["email"]); $password = mysql_real_escape_string($_POST["password"]); $query="UPDATE members SET username = '$username', fname = '$fname', email = '$email', password = '$password' WHERE id='$id'"; mysql_query($query)or die(mysql_error()); if(mysql_affected_rows()>=1){ echo "<p>($id) Record Updated<p>"; }else{ echo "<p>($id) Not Updated<p>"; } ?> now on edit.php i fill out the form to edit the account "test" while i am logged into it now once the form if filled out i click on |Submit!| button and it takes me to update.php and it returns this (0) Not Updated (0) <= id of user logged in Not Updated <= MySql Error from mysql_query($query)or die(mysql_error()); if(mysql_affected_rows()>=1){ i want it to update the user logged in and if i am not mistaken in this script it says $id = (int)$_SESSION["id"]; witch updates the user with the id of the person who is logged in but it isnt updating its saying that no tables were effected if it helps heres my MySql Database picture just click here http://i50.tinypic.com/21juqfq.png if this could possibly be any help to find the solution i have 2 more files delete.php and delete_ac.php they have can remove users from my sql database and they show the user id and it works there are no bugs in this script at all PLEASE DO NOT MAKE SUGGESTIONS FOR THE SCRIPTS BELOW delete.php first <?php $host="mysql13.000webhost.com"; // Host name $username="a2670376_Users"; // Mysql username $password="PASSWORD"; // Mysql password $db_name="a2670376_Pass"; // Database name $tbl_name="members"; // Table name // Connect to server and select database. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // select record from mysql $sql="SELECT * FROM $tbl_name"; $result=mysql_query($sql); ?> <table border="0" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC"> <tr> <td colspan="8" style="bgcolor: #FFFFFF"><strong><img src="http://i47.tinypic.com/u6ihk.png" height="30" widht="30">Delete data in mysql</strong> </td> </tr> <tr> <td align="center" bgcolor="#FFFFFF"><strong>Id</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>UserName</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>FullName</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Password</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Email</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Date</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Ip</strong></td> <td align="center" bgcolor="#FFFFFF">&nbsp;</td> </tr> <?php while($rows=mysql_fetch_array($result)){ ?> <tr> <td bgcolor="#FFFFFF"><? echo $rows['id']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['username']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['fname']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['password']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['email']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['date']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['ip']; ?></td> <td bgcolor="#FFFFFF"><a href="delete_ac.php?id=<? echo $rows['id']; ?>">delete</a></td> </tr> <?php // close while loop } ?> </table> <?php // close connection; sql_close(); ?> and now delete_ac.php <table width="500" border="0" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC"> <tr> <td colspan="8" bgcolor="#FFFFFF"><strong><img src="http://t2.gstatic.com/images? q=tbn:ANd9GcS_kwpNSSt3UuBHxq5zhkJQAlPnaXyePaw07R652f4StmvIQAAf6g" height="30" widht="30">Removal Of Account</strong> </td> </tr> <tr> <td align="center" bgcolor="#FFFFFF"> <?php $host="mysql13.000webhost.com"; // Host name $username="a2670376_Users"; // Mysql username $password="javascript00"; // Mysql password $db_name="a2670376_Pass"; // Database name $tbl_name="members"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // get value of id that sent from address bar $id=$_GET['id']; // Delete data in mysql from row that has this id $sql="DELETE FROM $tbl_name WHERE id='$id'"; $result=mysql_query($sql); // if successfully deleted if($result){ echo "Deleted Successfully"; echo "<BR>"; echo "<a href='delete.php'>Back to main page</a>"; } else { echo "ERROR"; } ?> <?php // close connection mysql_close(); ?> </td> </tr> </table>

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