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Is real-time or synchronous replication possible over WAN link?

- by johnnyb10

The company I work for is looking to implement truly real-time file replication with file locking over a WAN link that spans over 2000 miles. We currently have a 16-drive SAN setup in our east coast office. We also have an office out in Colorado that will have the same exact SAN setup. The idea is to have those two SANs contain the same exact data at all times, which will allow us to work with the same data pool, and which will also provide use with an offsite backup solution, should a failure occur on either end. We're running Server 2008. The objective is to enable users in the east coast office to work on files and have those changes be instantly updated on the Colorado SAN as well. We also need there to be file locking so that there will be no conflicts or overwritten changes if users attempt to work on the same file. Is this scenario even possible, at speeds that would make the files usable? And if so, what software would we need to pull this off? As I understand it, DFS-R does not provide file locking, so if we used that, we would need to go with a third-party product like Peerlock. But I don't even know if DFS-R is an option. Can it replicate quickly enough over a WAN link? Can any product? It seems that if we were to use synchronous replication, the programs would be unacceptably slow, as every write would have to wait for confirmation from the other end of the link. But if we used asynchronous replication, what kind of latency would we be looking at? There is a product from GlobalScape called WAFS that claims to provide "File coherence with real-time file locking, file release, and synchronization" and says that "As files are modified, changes are mirrored instantly using intelligent byte-level differencing to minimize the impact on network bandwidth". So this sounds like synchronous replication, but that doesn't even seem possible, given physical limitations such as the speed of light. If anyone has any experience with this kind of setup, or knows whether it's even possible, I'd appreciate your input and suggestions, including recommendations for software that we should check out.

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Most efficient way to store list structure in XML

- by Mike

Starting a new project and was planning on storing all of my web content in XML. I do not have access to a database so this seemed like the next best thing. One thing I'm struggling with is how to structure the XML for links (which will later be transformed using XSLT). It needs to be fairly flexible as well. Below is what I started with, but I'm starting to question it. <links> <link> <url>http://google.com</url> <description>Google</description> <link> <link> <url>http://yahoo.com</url> <description>Yahoo</description> <links> <url>http://yahoo.com/search</url> <description>Search</description> </link> <link> </links> That should get transformed into Google Yahoo Search Perhaps something like this might work better. <links> <link href="http://google.com">Google</link> <link href="http://yahoo.com">Yahoo <link href="http://yahoo.com/search">Search</link> </link> </links> Does anyone perhaps have a link that talks about structuring web content properly in XML? Thank you. :)

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Invert linear linked list

- by ArtWorkAD

Hi, a linear linked list is a set of nodes. This is how a node is defined (to keep it easy we do not distinguish between node an list): class Node{ Object data; Node link; public Node(Object pData, Node pLink){ this.data = pData; this.link = pLink; } public String toString(){ if(this.link != null){ return this.data.toString() + this.link.toString(); }else{ return this.data.toString() ; } } public void inc(){ this.data = new Integer((Integer)this.data + 1); } public void lappend(Node list){ Node child = this.link; while(child != null){ child = child.link; } child.link = list; } public Node copy(){ if(this.link != null){ return new Node(new Integer((Integer)this.data), this.link.copy()); }else{ return new Node(new Integer((Integer)this.data), null); } } public Node invert(){ Node child = this.link; while(child != null){ child = child.link; } child.link = this;.... } } I am able to make a deep copy of the list. Now I want to invert the list so that the first node is the last and the last the first. The inverted list has to be a deep copy. I started developing the invert function but I am not sure. Any Ideas? Update: Maybe there is a recursive way since the linear linked list is a recursive data structure. I would take the first element, iterate through the list until I get to a node that has no child and append the first element, I would repeat this for the second, third....

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How can I get Symbolic-Name of an Osgi bundle which is using one of my exported packages ?

- by Ozgun

Inside one of my implementation libraries I want to know from which user library request is coming from? Bundle A ClientCode -- ServiceInterface Bundle B ClientCode -- ServiceInterface Bundle C ServiceInterface ServiceImpl. And those interfaces are resolved by one of impl. bundles (Bundle C). Inside that bundle I want to know from which bundle request is coming from (A or B)? Thanks.

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Can a Linksys Router be the cause of bad speeds on a 1.5 mbps link.

- by gramware

We use a Linksys 5-port router at a smal organization with about 20 employees. We recently acquired a 1.5 mbps fibre link, but sometimes the link goes down and speeds are still low. On enquirey from the ISP, this was part of the response, However there maybe throttling due to the router in place. A Linksys is a low end router and may be unable to carried traffic of up to 1536Kbps. We are in a position to deploy a Cisco 871 router on test for 2 wks to eliminate that possibility. Also kindly advise the destination of the ping results they look to high. How true is that about the router throttling the network and need for a bigger one.

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When clicking an irc:// link, a new instance of chatzilla opens instead of the existing one being used.

- by WebDevHobo

That is my problem in a nutshell. I'm running Win7 32-bit. I have chatzilla on XulRunner, so not as the Firefox add-on. When I clock any irc:// link, a new instance of Chatzilla will be started. I have a lot of startup-commands set, so all those will be executed. I stop the new instance before it takes off, but this is rather annoying. Firefox application setting just link to the path where the executable is, with no option to set any command-line stuff to make the existing instance be used. Is there any firefox or windows setting that I can manipulate, so that when firefox calls chatzilla.exe, the existing instance is used instead of a new one opened?

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How would i go about showing the closest paragraph element to a unique link with jQuery?

- by Nike

The title is a bit rusty, sorry about that. Now let me explain what i'm trying to do. I have a few listed items, like this: <li> <a id="toggle" class="0"><h4>ämne<small>2010-04-17 kl 12:54</small></h4></a> <p id="meddel" class="0">text</p> </li> <li class='odd'> <a id="toggle" class="1"><h4>test<small>2010-04-17 kl 15:01</small></h4></a> <p id="meddel" class="1">test meddelande :) [a]http://youtube.com[/a]</p> </li> The function i'm trying to achieve, is that when a user clicks a "toggle" link (the h4 text), i want the paragraph element below it to fade in. I thought of the idea of giving both the toggle link and the paragraph the same class, and then somehow make it get the paragraph with the same class as the toggle link clicked, and show it? But i'm not entirely sure how to do that either, and tbh, it doesn't sound like the greatest idea, but maybe that's the only way? I don't know... Is there some way to just simply get the nearest paragraph (below the link) with the id "meddel" and fade it in? That sounds a bit easier... I hope you can at least give me a few hints. Thanks in advance, -Nike

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Can you link an NTFS junction point to a directory on a Network Attached Storage?

- by Zachary Burt

I'm using Windows, and I want to use Dropbox to back up a folder outside my Dropbox directory. So I want to create a junction point from my target directory to my Dropbox folder. Accoding to the Wikipedia article on NTFS junction points, which the Dropbox answer links to: "Junction points can only link to directories on a local volume; junction points to remote shares are unsupported." I am looking to link to a directory on networked attached storage, which would not be a local volume, I believe. What should I do?

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I want a hyperlink to open a browser tab, then all subsequent link clicks go to the same tab

- by rossmcm

I suspect I'm out of luck on this one, but here goes... Say I have a CHM help file that has http:// hyperlinks embedded in the help pages. When the user clicks on a hyperlink of the style: <a href="http://www.example.com" target="_blank">click here!</a> a browser window is opened and the target web page is displayed. If a browser is already open a new tab is created and the target displayed in that. If the user clicks on another link (or the same link) another browser window/tab opens, and so on. Is there any way I can force all clicks of the links to go to the same tab/browser window?

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Finding part of a string that a user has sent via POST

- by blerh

My users can send links from popular file hosts like Rapidshare, Megaupload, Hotfile and FileFactory. I need to somehow find out what filehost they sent the link from and use the correct class for it appropriately. For example, if I sent a Rapidshare link in a form on my web page, I need to somehow cycle through each file host that I allow until I find the text rapidshare.com, then I know the user has posted a Rapidshare link. Perhaps a PHP example: switch($_POST['link']) { case strstr($_POST['link'], 'rapidshare.com'): // the link is a Rapidshare one break; case strstr($_POST['link'], 'megaupload.com'): // the link is a Megaupload one break; case strstr($_POST['link'], 'hotfile.com'): // the link is a Hotfile one break; case strstr($_POST['link'], 'filefactory.com'): // the link is a Filefactory one break; } However, I know for a fact this isn't correct and I'd rather not use a huge IF statement if I can help it. Does anyone have any solution to this problem? If you need me to explain more I can try, English isn't my native language so it's kinda hard. Thanks all.

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How to output multicolumn html without "widows"?

- by user314850

I need to output to HTML a list of categorized links in exactly three columns of text. They must be displayed similar to columns in a newspaper or magazine. So, for example, if there are 20 lines total the first and second columns would contain 7 lines and the last column would contain 6. The list must be dynamic; it will be regularly changed. The tricky part is that the links are categorized with a title and this title cannot be a "widow". If you have a page layout background you'll know that this means the titles cannot be displayed at the bottom of the column -- they must have at least one link underneath them, otherwise they should bump to the next column (I know, technically it should be two lines if I were actually doing page layout, but in this case one is acceptable). I'm having a difficult time figuring out how to get this done. Here's an example of what I mean: Shopping Link 3 Link1 Link 1 Link 4 Link2 Link 2 Link 3 Link 3 Cars Link 1 Music Games Link 2 Link 1 Link 1 Link 2 News As you can see, the "News" title is at the bottom of the middle column, and so is a "widow". This is unacceptable. I could bump it to the next column, but that would create an unnecessarily large amount of white space at the bottom of the second column. What needs to happen instead is that the entire list needs to be re-balanced. I'm wondering if anyone has any tips for how to accomplish this, or perhaps source code or a plug in. Python is preferable, but any language is fine. I'm just trying to get the general concept down.

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XPath ordered priority attribute search

- by user94000

I want to write an XPath that can return some link elements on an HTML DOM. The syntax is wrong, but here is the gist of what I want: //web:link[@text='Login' THEN_TRY @href='login.php' THEN_TRY @index=0] THEN_TRY is a made-up operator, because I can't find what operator(s) to use. If many links exist on the page for the given set of [attribute=name] pairs, the link which matches the most left-most attribute(s) should be returned instead of any others. For example, consider a case where the above example XPath finds 3 links that match any of the given attributes: link A: text='Sign In', href='Login.php', index=0 link B: text='Login', href='Signin.php', index=15 link C: text='Login', href='Login.php', index=22 Link C ranks as the best match because it matches the First and Second attributes. Link B ranks second because it only matches the First attribute. Link A ranks last because it does not match the First attribute; it only matches the Second and Third attributes. The XPath should return the best match, Link C. If more than one link were tied for "best match", the XPath should return the first best link that it found on the page.

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How do I get a PDF link in a Word document to open in the default browser?

- by Tweek

I'm trying to create a Word document with links to resources on the web. If I create a hyperlink to a regular HTML file, when I click on the link, it opens in my default browser (Google Chrome) as expected. However, if I click on a link to a PDF file on a website, it opens in Internet Explorer. Before it opens, I also get the following prompt: Microsoft Office Opening http://www.example.com/example.pdf Some files can contain viruses or otherwise be harmful to your computer. It is important to be certain that this file is from a trustworthy source. Would you like to open this file? OK Cancel I'm using Office 2010, but I'm asking for a user who is using Office 2007 and is experiencing the same issue. (His default browser is Firefox.) We're both on Windows 7.

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MS Excel: Can I link images using a relative path?

- by Port Islander 2009

I am working on an MS Excel document that contains a lot of (around 200) images. They are currently saved within the document, so the file becomes huge and working gets very slow. Linking the pictures without saving them works very well - I now have the Excel document and a folder "pictures" next to it that contains all my image files. However, when I move the document and the folder to a new location, all my pictures disappear. This seems to be because Excel saves the link information as absolute paths. (Update: Actually, according to this thread, Excel stores the link information as relative paths as well. Now I really don't know why my links break down..) Is there a convenient way to save them as relative paths or have Excel automatically update the path information? Update: It's important that the images get displayed on the sheet and can be printed. I am working with Microsoft Excel for Mac 2008 and 2011. I really appreciate your help.

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How to ALWAYS link an image in MS Word 2010 instead of embedding it?

- by grunwald2.0

I want to only link, not embed, pictures in my Word document. Yet I got a lot of images to insert! And I want to spare me the additional click into the dropdown menu one and for all, so the question is, is there any way to set "link image(s)" as default? Because I didn't find anything in the Word settings, only totally useless detail settings. This "detail" has been overseen by Microsoft it seems! :( I would provide you with a screenshot, but it would be German anyways. I think the guys who use image linking in Word since v2007, will know what I mean. Thank you in advance! Best regards

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Does a HDMI-to-DVI (dual link) adapter exist? I don't care about the price

- by alex k

My monitor supports full-resolution display (2560x1440) only when connected to through either the DVI-D dual link port, or the DisplayPort. My laptop, though, has neither of these two kinds of output. Instead, all it's got is a HDMI port (which is version 1.3, and I also read that the laptop's graphics chipset supports 2560x1440 at 60Hz). So I'm wondering whether anyone has ever seen an HDMI-to-DVI dual link adapter, which will carry my ultra-highres signal to the monitor I just bought. So far I haven't seen any, and don't even know whether such an adapter (which I understand would have to be active, USB-powered and expensive (but I don't care)) exists.

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Maddening Linked List problem

- by Mike

This has been plaguing me for weeks. It's something really simple, I know it. Every time I print a singly linked list, it prints an address at the end of the list. #include <iostream> using namespace std; struct node { int info; node *link; }; node *before(node *head); node *after(node *head); void middle(node *head, node *ptr); void reversep(node *head, node *ptr); node *head, *ptr, *newnode; int main() { head = NULL; ptr = NULL; newnode = new node; head = newnode; for(int c1=1;c1<11;c1++) { newnode->info = c1; ptr = newnode; newnode = new node; ptr->link = newnode; ptr = ptr->link; } ptr->link=NULL; head = before(head); head = after(head); middle(head, ptr); //reversep(head, ptr); ptr = head; cout<<ptr->info<<endl; while(ptr->link!=NULL) { ptr=ptr->link; cout<<ptr->info<<endl; } system("Pause"); return 0; } node *before(node *head) { node *befnode; befnode = new node; cout<<"What should go before the list?"<<endl; cin>>befnode->info; befnode->link = head; head = befnode; return head; } node *after(node *head) { node *afnode, *ptr2; afnode = new node; ptr2 = head; cout<<"What should go after the list?"<<endl; cin>>afnode->info; ptr2 = afnode; afnode->link=NULL; ptr2 = head; return ptr2; } void middle(node *head, node *ptr) { int c1 = 0, c2 = 0; node *temp, *midnode; ptr = head; while(ptr->link->link!=NULL) { ptr=ptr->link; c1++; } c1/=2; c1-=1; ptr = head; while(c2<c1) { ptr=ptr->link; c2++; } midnode = new node; cout<<"What should go in the middle of the list?"<<endl; cin>>midnode->info; cout<<endl; temp=ptr->link; ptr->link=midnode; midnode->link=temp; } void reversep(node *head, node *ptr) { node *last, *ptr2; ptr=head; ptr2=head; while(ptr->link!=NULL) ptr = ptr->link; last = ptr; cout<<last->info; while(ptr!=head) { while(ptr2->link!=ptr) ptr2=ptr2->link; ptr = ptr2; cout<<ptr->info; } } I'll admit that this is class work, but even the professor can't figure it out, and says that its probably something insignificant that we're overlooking, but I can't put my mind to rest until I find out what it is.

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Google search results are invalid

- by Rufus

I'm writing a program that lets a user perform a Google search. When the result comes back, all of the links in the search results are links not to other sites but to Google, and if the user clicks on one, the page is fetched not from the other site but from Google. Can anyone explain how to fix this problem? My Google URL consists of this: http://google.com/search?q=gargle But this is what I get back when the user clicks on the Wikipedia search result, which was http://www.google.com/url?q=http://en.wikipedia.org/wiki/Gargling&sa=U&ei=_4vkT5y555Wh6gGBeOzECg&ved=0CBMQejAe&usg=AFQjeNHd1eRV8Xef3LGeH6AvGxt-AF-Yjw <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html lang="en" dir="ltr" class="client-nojs" xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Gargling - Wikipedia, the free encyclopedia</title> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <meta http-equiv="Content-Style-Type" content="text/css" /> <meta name="generator" content="MediaWiki 1.20wmf5" /> <meta http-equiv="last-modified" content="Fri, 09 Mar 2012 12:34:19 +0000" /> <meta name="last-modified-timestamp" content="1331296459" /> <meta name="last-modified-range" content="0" /> <link rel="alternate" type="application/x-wiki" title="Edit this page" > <link rel="edit" title="Edit this page" > <link rel="apple-touch-icon" > <link rel="shortcut icon" > <link rel="search" type="application/opensearchdescription+xml" > <link rel="EditURI" type="application/rsd+xml" > <link rel="copyright" > <link rel="alternate" type="application/atom+xml" title="Wikipedia Atom feed" > <link rel="stylesheet" href="//bits.wikimedia.org/en.wikipedia.org/load.php?debug=false&lang=en&modules=ext.gadget.teahouse%7Cext.wikihiero%7Cmediawiki.legacy.commonPrint%2Cshared%7Cskins.vector&only=styles&skin=vector&*" type="text/css" media="all" /> <style type="text/css" media="all">#mwe-lastmodified { display: none; }</style><meta name="ResourceLoaderDynamicStyles" content="" /> <link rel="stylesheet" href="//bits.wikimedia.org/en.wikipedia.org/load.php?debug=false&lang=en&modules=site&only=styles&skin=vector&*" type="text/css" media="all" /> <style type="text/css" media="all">a:lang(ar),a:lang(ckb),a:lang(fa),a:lang(kk-arab),a:lang(mzn),a:lang(ps),a:lang(ur){text-decoration:none} /* cache key: enwiki:resourceloader:filter:minify-css:7:d5a1bf6cbd05fc6cc2705e47f52062dc */</style>

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Since Google doesn't use nofollow anymore what is smart alternative?

- by SharkTheDark

Since from 2009. Google count nofollow links also as outgoing link, what are alternative to stop Google count outside links from my page? If I make links appear on my page source like this: <span hrefs="http://link" rel="nofollow" link="true">Link Name</span> and then in JavaScript replace span with a tag and replace hrefs with href for every span tag that has link="true". Will this help?

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CodeIgniter PHP stylesheet link. HOW?

- by Jordan Pagaduan

I'm using xampp for my php. And I have download a code igniter and save it on my htdocs. I already made a databasing and a sample page. My only problem is how can I link my css. Where should I save my style.css? How can I call my style.css? <link rel="stylesheet" href="<? base_url(); ?>stylesheet/style.css" type="text/css" media="screen"/> I have this but still have a problem. Is there a step by step on how to link a css? Thank You.

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How can developers use a similar tracking link to Google's results page?

- by Peter Jones

I've read heaps of pages of people trying to implement some kind of tracking system similar to the way Google reroutes search link. Eg: Search "Facebook" in Google, open in a new window, and the link changes to something like: "http://www.google.com.au/url?sa=t&source=web&cd=1&ved=0CBkQFjAA&url=http%3A%2F%2Fwww.facebook.com%2F&rct=j&q=Facebook&ei=sksZTZexJobJccXnxZYK&usg=AFQjCNHTTNi-O4Qgrg6kvGVfKJuRqbuOKw&cad=rja" I'm guessing Google tracks that click and then redirects to the actual site by reading the url parameter. What I wanted to know is if there was a simple way that you can make this kind of functionality work using an onclick event - just change the link href after being clicked to redirect? There's a few threads, but from what I could find, nobody has actually succeeded without problems or limitations. Thanks in advance.

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how to change link url on the web browser's status bar.

- by sunglim

I already read many article about this issue in here, SO. I just want to discuss how to do it. NOT the moral issue. -- for example. at the google search webpage. before I click the link, the link does not indicate the google url. but After I click the link with shift-key, the url on the status bar is changed. this mean the google webpage indicate 'Fake URL'. the google compressed script is too difficult to read and analyze. # edited The second url should work on ie8 even if I click with ctrl key.

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Does Flickr "Know" if a Hotlinked Image Does Not Link Back to Source?

- by Michael Robinson

From Flickr's community guidelines: "Do link back to Flickr when you post your photos elsewhere. The Flickr service makes it possible to post images hosted on Flickr to outside web sites. However, pages on other web sites that display images hosted on flickr.com must provide a link from each photo back to its photo page on Flickr." Our company currently allows image hotlinking for user-uploaded images. It turns out that this has been more popular than we had expected, and I would like to capitalize on this if possible. We will be altering the guidelines to include a clause similar to Flickr's, quoted above. As hotlinking costs us, both in terms of server load and bandwidth, we would like to get at least something out of it, other than merely a warm feeling inside. My question: Does Flickr "know" if a hotlinked image does not link back to its source? Bonus: if Flickr knows, how?

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Java: I am trying to server a zip file through a link, but the file comes out as being empty

- by Ankur

I am trying to server a zip file through a link, but the file comes out as being empty. My app takes a number of files and zips them up, then presents the user with a link to the file so he/she can download it. On the server I can see that the zip file is being created correctly, but when I download it from the server through the normal HTML link provided no data is downloaded i.e. a zip file is created locally but it has file size 0kb. The file names are of the form XPCS.2010-03-09.15.13.42.165.zip - will the dots cause problems?

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Mac OSX: Passing a link to file from user process to kernel module.

- by Inso Reiges

Hello, I need to pass a link to file from a user process to the OSX kernel driver. By link i mean anything that uniquely identifies a file on the local filesystem. I need that link to do I/O on that file in kernel. The most obvious solution seems to pass a file name and use a VFS vnode lookup. However i noticed, that Apple Disk Images helper process passes a raw data array for image-path property to driver when attaching a disk image file: <2f 56 6f 6c 75 6d 65 73 2f 73 74 6f 72 61 67 65 2f 74 65 73 74 32 2e 64 6d 67> What is that diskimages-helper passes to the kernel driver? Some serialized type perhaps? If yes, what type is it and how can i use it?

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