Search Results

Search found 33140 results on 1326 pages for 'skip list'.

Page 781/1326 | < Previous Page | 777 778 779 780 781 782 783 784 785 786 787 788  | Next Page >

  • acknowledgments in latex

    - by biosci
    I'm in a documentclass{article} in Latex. How would I put the name of an advisor on the first page? I've seen examples in latex for things like \principaladvisor{} but that seems to be done with the thesis class. I'm guessing with the article class I'd list the advisor as a co-author or something. How do I do that?

    Read the article

  • Mysql select most frequent and sort alphabetically

    - by user2605793
    I am trying to select the most common 100 names from a table then display the list showing the names and count. I want the user to be able to re-sort the list alphabetically rather than based on count. I thought the following code would do it. It works for the default sort by count but fails on the sort alphabetically. The line "$count = mysql_num_rows($table);" gives an error: mysql_num_rows() expects parameter 1 to be resource, boolean given. Any help would be greatly appreciated. // Get most popular surnames echo '<h2>Most Common Surnames</h2>'; if ($sort == "") { // default sort by count echo '<a href="http://mysite/names.php?id='.$id.'&sort=name">Sort by name</a><br>'; $query = "SELECT family_name, COUNT(*) as count FROM namefile WHERE record_key = $id GROUP BY family_name ORDER BY count DESC LIMIT 100"; } else { // sort alphabetically echo '<a href="http://mysite/names.php?id='.$id.'">Sort by count</a><br>'; $query = "SELECT * FROM ( SELECT family_name, COUNT(*) as count FROM namefile WHERE record_key = $id GROUP BY family_name ORDER BY count DESC LIMIT 100) AS alpha ORDER BY family_name"; } $table = mysql_query($query); $count = mysql_num_rows($table); $tot = 0; $i = 0; echo '<table><tr>'; while ($tot < $count2) { $rec2 = mysql_fetch_array($table2); echo '<td>'.$rec2[0].'</td><td>'.$rec2[1].'</td><td width="40">&nbsp;</td><td>'; if ($i++ == 6) { echo '</tr><tr>'; $i = 0; } $tot++; } echo '</tr></table><br>'; UPDATE: I needed to add "AS alpha" to give the outer select a unique name. (alpha is just a random name I made up.) It now works perfectly. Code updated for the benefit of any others who need something similar.

    Read the article

  • How to deploy to Tomcat from NetBeans?

    - by deamon
    I've added Tomcat in the "Tools Servers" menu and as you can see it appears in the list of servers: But when I try to run my project, I cannot select Tomcat! The drop-down with servers is empty. I tried it with NetBeans 6.8 and 6.9 Beta. Any idea?

    Read the article

  • Leading zeroes in php

    - by sanders
    Hello, I would like to present a list from 0 to 59 of with the numbers 0 to 9 have a leading zero. This is my code but it doesn't work so far. Any idea's? for($i=0; $i<60; $i++){ if($i< 10){ sprintf("%0d",$i); } array_push($this->minutes,$i); }

    Read the article

  • many-to-many mapping in NHibernate

    - by Chris Stewart
    I'm looking to create a many to many relationship using NHibernate. I'm not sure how to map these in the XML files. I have not created the classes yet, but they will just be basic POCOs. Tables Person personId name Competency competencyId title Person_x_Competency personId competencyId Would I essentially create a List in each POCO for the other class? Then map those somehow using the NHibernate configuration files?

    Read the article

  • Java: most efficient way to defensively copy an int[]?

    - by Jason S
    I have an interface DataSeries with a method int[] getRawData(); For various reasons (primarily because I'm using this with MATLAB, and MATLAB handles int[] well) I need to return an array rather than a List. I don't want my implementing classes to return the int[] array because it is mutable. What is the most efficient way to copy an int[] array (sizes in the 1000-1000000 length range) ? Is it clone()?

    Read the article

  • Core Data - Best way to save a "number of items"

    - by Daniel Granger
    The user will have a static list of items to choose from. Using a Picker View they will choose one of the items and then select how many of them they want. Whats the best way to save this in core data? A Struct? struct order { NSInteger item; NSInteger numberOf; }; Or some sort of relationship? Many Thanks

    Read the article

  • output redirection in UNIX

    - by Happy Mittal
    I am a beginner in UNIX. I am finding some difficulty in input/output redirection. ls -l temp cat temp Here why temp file is shown in the list and moreover, it is showing 0 characters. wc temp temp cat temp here output is 0 0 0 temp. Why lines, words, characters are 0. Please help me to undestand this concept.

    Read the article

  • Can't find this.Controls - what am I missing?

    - by Adam S
    Sorry for a potentially dumb question, I am still new at this. I really appreciate your help. Referring to http://stackoverflow.com/questions/1536739/c-get-control-by-name/1536756#1536756 But I don't have a "this.Controls" available. Is there something I am missing here? In other words, when I type "this." and visual studio populates a list of option, there is no "Controls" option.

    Read the article

  • ASP.NET lisbox - Selected first item, always

    - by Lijo
    I have a list box which is populated using a dictioanry. When I iterate throught the selected items using the following code, it always show only the first items as selected - even if the first item is not selected. Have you ever encountered this scenario? Could you please help on this? foreach (ListItem item in lstProcessName.Items) { if (item.Selected == true) { selectedNewSales.Add(item.Text); } }

    Read the article

  • JQuery - Iterate through SELECT options

    - by user208662
    Hello, I have a SELECT element in HTML. This element represents a drop down list. I'm trying to understand how to iterate through the options in the SELECT element via JQuery. How do I use JQuery to display the value and text of each option in a SELECT element? I just want to display them in an alert() box. Thank you!

    Read the article

  • No Android project type in Eclipse->File->New-Project

    - by Rubberman
    I am running CentOS 5.5 x86_64 with JDK 1.6, Eclipse Galileo, and the 0.9.7 ADT is installed; however, after installation, the Android project type is not available. I have checked in the installed packages list and it is installed. Anybody encounter this problem before? Could it be due to my use of the 64-bit java VM that is installed on my system?

    Read the article

  • Overinclusion of libraries C++

    - by wyatt
    I'm reading about how to put a makefile together, but no-one seems to mention what to do if your files require different sets of libraries, they all seem to use the same set of libraries for each file. Since it seems unlikely that every single file has the same libraries, I take it the list they use must amalgamate all of the libraries required across the project. I just wanted to know if there's any downside to including too many libraries, or if the compiler works out which ones are needed and ignores the rest? Thanks

    Read the article

  • MySQL select date, join statistic data - how?

    - by Webnet
    I have some statistics I need to report on a monthly basis. I need my query to return 0's for statistics which aren't there. The only way I know to do this is to use SQL to generate a list of days within the specified time period and LEFT JOIN the statistic data that I need to report on. Problem is.... I've never not selected from a table like that... how do I do that?

    Read the article

  • Looking for a fast hash-function.

    - by Julian
    Hello, I'm looking for a special hash-function. Let's say I have a large list of strings, if I order them by their hash-values they should be ordered quasi randomly. The most important point is: it must be super fast. I've tried md5 and sha1 and they're using to much cpu power. Clashes are not a problem. I'm using javascript, so it shouldn't be too complicated to implement.

    Read the article

  • How to hide folder in SSRS Report Builder?

    - by tnafoo
    When I click File - Open on Report Builder, I can see a list of folders under Report Server Home root folder. But I don't want end-user to see any of the folders under root unless I grant them access. I tried hiding and removing permission on the folders but they are still visible in the root folder.

    Read the article

< Previous Page | 777 778 779 780 781 782 783 784 785 786 787 788  | Next Page >