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  • browser instant updates with ajax/jquery

    - by wcpro
    I'm trying to reverse engineer how facebook handles their notifications, where when you get a message you get instantly notified via the browser. I've fiddled with it for a little bit and realized that there is always a pending GET request "listening" if you will to some sort of update from the server. This appears to be some sort of observer pattern. I was just wondering if this pattern was documented somewhere.

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  • jQuery ajax response not operating correctly

    - by mmarceau
    Ok this is frustrating... The code below works "correctly" as far as sending the email address to the SaveEmail URL and it gets saved correctly each time I change the drop down. However it only outputs the "Successful" message once, no matter how many times I change the value in the drop down. The "data" that is returned is "Successful". I would like to show the message for a couple seconds, then fade it out. It works correctly the first time I change the drop down, after that the change happens and the value gets saved, but the "Successful" message doesn't display. jQuery code: $('#AgentEmails').change(function() { var NewAddress = $('#AgentEmails').val(); $.post('SaveEmail.aspx', { email: NewAddress }, function(data) { $('#SelectMsg').html("<b>" + data + "</b>").fadeOut(); }); }); HTML code: <select ID='AgentEmails' runat='server'> <option value="[email protected]">TEST</option> </select><span id='SelectMsg'></span> What needs to be changed in my code to make this operate correctly? Thanks for the help.

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  • Stop then restart submit() after ajax check

    - by jeerose
    I asked a question [here] recently and it's just not providing me with an answer. Here's what I want to do and you can see my first attempt at the link above: User submits form Stop default submit action check to see if a similar entry exists in database If it does, display a notice asking them if they want to submit anyway and give an option to let them submit anyway (enable default action and submit it). If it does not, enable the default action on the form and let it submit I'm at a loss. Any help is appreciated. Thanks gang.

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  • Pass data via ajax to dialog Jquery

    - by user342391
    I am trying to post data from my form to a jquery dialog that loads external content. I am serializing the form data which works (appears in the url) but the dialog won't open: $("#wavajax button").click(function() { $.post({url: 'player/index.php', data: $("#wavajax").serialize(), success: function (data) { $("#recordingdialog").load("player/index.php", [], function(){ $("#recordingdialog").dialog("open"); } }); return false; }); What am I doing wrong, am I going about it the right way???

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  • facebook comments ajax

    - by Shunsho
    I have a function that load a jquery ui accordion (differents accordions based on different id) When I click on the tab titled "Facebook Comments" I do: $("#myaccordion").bind('accordionchange', function(event, ui) { id = $("#myaccordion").data('id'); switch (ui.newHeader.text()) { case "Facebook Comments": displayFb(id); break; } }); The "displayFB" function is: function displayFb(id){ $.get('/fbcomments/' + id, function(data) { $("#facecomm").append(data); }); } Where www.myweb.com/fbcomments/id is: <div id="fb-root"></div> <script>(function(d, s, id) { var js, fjs = d.getElementsByTagName(s)[0]; if (d.getElementById(id)) return; js = d.createElement(s); js.id = id; js.src = "//connect.facebook.net/es_ES/all.js#xfbml=1"; fjs.parentNode.insertBefore(js, fjs); }(document, 'script', 'facebook-jssdk'));</script> <div class="fb-comments" data-href="<?php echo '/fbcomments/'.$id ?>" data-num-posts="10" data-width="220"></div> When I load the homepage, then choose an accordion, then open a Facebook Comments, it works perfect. If I reload the page and choose another accordion, work perfect again. The problem is when I choose another accordion or the same again without reload the whole page. The accordions loads very well, all the data on them (some tabs of images, text, videos, etc), but the facebook comments don't appear. I tried: loading the #fb-root and facebook comment <script> on the main layout....doesn't work. adding FB.XFBML.parse(); into displayFB function....doesn't work adding FB.XFBML.parse(); into a $(document).ready(function(){} ...doesn't work. Thank you for reading and try to help!!

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  • jquery: How to deal with 'this' in ajax callbacks

    - by Svish
    I currently have code similar to this for a form: $('#some-form') .submit(function() { // Make sure we are not already busy if($(this).data('busy')) return false; $(this).data('busy', true); // Do post $.post("some/url", $(this).serialize(), function(data) { if(data.success) // Success is a boolean I set in the result on the server { // Deal with data } else { // Display error } $('#some-form') .removeData('busy'); }); return false; }); My issue is that I would like to somehow remove the need for knowing the form id in the post callback. In the end where I remove the busy data from the form, I'd like to somehow not have that hard coded. Is there any way I can do this? Is there a way I can hand whatever is in this to the post callback function? Since I know the id right now, I can get around it by doing what I have done, but I'd like to know how to not be dependant on knowing the id, since often I don't have an id. (For example if I have a link in each row in a table and all the rows have the same click handler.

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  • how to submit using link with my current code(php+jquery+ajax)

    - by ruslyrossi
    My current Code : <script type="text/javascript"> $(document).ready(function() { $('#form').ajaxForm( { target: '#preview', success: function() { $('#success_box').addClass('success') setTimeout(function() { $('#success_box').fadeOut('slow'); }, 3100); // <-- time in milliseconds } }); }); </script> <form action="controller/product_edit_update.php" method="post" id="form" name="form" > bla..bla.. <input type="submit" value="Save" /></form> but now i want to add submit link with <a href="" id="submit_with_link" >Save</a>

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  • ajax security ?

    - by Tony
    When I look back my codes that written earlier time, I found something terribly bad. Whenever I want to delete a record in the database, I did like this : $.post("deleteAction.do",{recordId:10}); I cannot prevent a malicious user visit my database operation url directly : deleteAction.do?recordId=10 What's the solution for this kind of problem ?

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  • Ajax using Rails

    - by Steve
    Hi, I have a favourite and un-favourite functionality in my application and I am using jQuery. This functionality works partially. The page gets loaded, and when I click the 'favourite' button(it is inside add_favourite_div element), it sends a XHR request and the post is set as favourite. Then a new div called "remove_favourite_div" replaces its place.Now when I click the remove favourite(which is part of remove_favourite_div), it sends a normal http request inside of xhr. The structure when the page gets loaded first time <div id="favourite"> <div id="add_favourite_div"> <form method="post" id="add_favourite" action="/viewpost/add_favourite"> <div style="margin: 0pt; padding: 0pt; display: inline;"> <input type="hidden" value="w873BgYHLxQmadUalzMRUC+1ql4AtP3U7f78dT8x9ho=" name="authenticity_token"> </div> <input type="hidden" value="3" name="Favourite[post_id]" id="Favourite_place_id"> <input type="hidden" value="2" name="Favourite[user_id]" id="Favourite_user_id"> <input type="submit" value="Favourite" name="commit"><br> </form> </div> </div> DOM after clicking on the unfavourite button <div id="favourite"> <div id="remove_favourite_div"> <form method="post" id="remove_favourite" action="/viewpost/remove_favourite"> <div style="margin: 0pt; padding: 0pt; display: inline;"> <input type="hidden" value="w873BgYHLxQmadUalzMRUC+1ql4AtP3U7f78dT8x9ho=" name="authenticity_token"> </div> <input type="hidden" value="3" name="Favourite[post_id]" id="Favourite_place_id"> <input type="hidden" value="2" name="Favourite[user_id]" id="Favourite_user_id"> <input type="submit" value="UnFavourite" name="commit"><br> </form> </div> </div> In my application.js, I have two functions to trigger the xhr request $("#add_favourite").submit(function(){ alert("add favourite"); action = $(this).attr("action") $.post(action,$(this).serialize(),null,"script"); return false; }); $("#remove_favourite").submit(function(){ alert("remove favourite"); action = $(this).attr("action"); $.post(action,$(this).serialize(),null,"script"); return false; }); Here, when the post is initially not a favourite, favourite button is displayed and when i clicked on the button, $("#add_favourite").submit gets called and unfavourite form is displayed correctly, but now when I click on the un-favourite button, $("#remove_favourite").submit does not get called. The whole scenario is true in both ways, I mean favourite-Unfavourite and Unfavourite-favourite Can someone please help me to solve this Thanks

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  • Mapping restful ajax requests to spring

    - by Diones
    I have this piece of code: @RequestMapping(value = "/test.json", method = RequestMethod.GET) @ResponseStatus(HttpStatus.OK) public @ResponseBody Object[] generateFile(@RequestParam String tipo) { Object[] variaveis = Variavel.getListVariavelByTipo(tipo); return variaveis; } As far as I know it should take a request to test.json?tipo=H and return the JSON representation of Variavel[], however when I make such request I get: HTTP Status 406 - type Status report message descriptionThe resource identified by this request is only capable of generating responses with characteristics not acceptable according to the request "accept" headers () By using the following function I can get the expected json: @RequestMapping(value = "/teste.json") public void testeJson(Model model, @RequestParam String tipo) { model.addAttribute("data", Variavel.getListVariavelByTipo("H")); } What I'm doing wrong?

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  • A brief question about JS or AJAX

    - by Luke
    I have been finding ways around this for a long time but think it's time I addressed it. If I have a page that has a dropdown menu, is there anyway I can select a value which will subsequently load other values further down. Can this be done without a page reload? I will give you an example. Say I was making some tools for an admin panel, but first of all they needed to select a member to work with. They would select the member and then below, the fields about that member would be populated based on what was selected in the first menu. As I have already asked, can this be done without a page reload? Thanks for reading.

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  • cakephp droplist/form - xml and ajax

    - by gudinne
    Hello- I'm complete noob in Cakephp - here goes... I have a website set up with Cakephp framework. I have been tasked with creating two dropdown forms to compare/show data. When the user selects an item from the dropdown from either one of the forms it is to show the content below on website. I was thinking this data would need to be stored in an xml file. How do I create and sync two dropdown forms with xml data within Cakephp? The page the form is on is the view(.ctp) file. Thanks

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  • ajax + freewebhostingarea body tag replacement

    - by mandnd
    im using freewebhostingarea and he searches for the body tag and add a banner the problem is im using ipb shoutbox (3.0.x) and everytime there a tbody tag he keeps putting that banner so the shoutbox is full of banners heres the code http://pastebin.com/d4KZJqu9

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  • posting array of text fields using jquery and ajax

    - by tabia
    i dont want to use serialize() function please help me with this. I am a beginner html <input type='button' value='Add Tier Flavor' id='Add'> <input type='button' value='Remove Tier Flavor' id='Remove'> <div id='batch'> <div id="BatchDiv1"> <h4>Batch #1 :</h4> <label>Flavor<input class="textbox" type='text' id="fl1" name="fl[]" value=""/></label></br> <label>Filling<input class="textbox" type='text' id="fi1" name="fi[]" value="" /></label></br> <label>Frosting<input class="textbox" type='text' id="fr1" name="fr[]" value=""/></label></br> </div> </div> <br> </div> this is a dynamically added fields using javascript the code is: javascript <script src="http://code.jquery.com/jquery-1.10.1.min.js"></script> <script type="text/javascript"> $(document).ready(function(){ var counter = 2; $("#Add").click(function () { if(counter>5){ alert("Only 5 Tiers allow"); return false; } var newBatchBoxDiv = $(document.createElement('div')).attr("id", 'BatchDiv' + counter); newBatchBoxDiv.html('<h4>Batch #'+ counter + ' : </h4>' + '<label> Flavor<input type="text" name="fl[]" id="fl' + counter + '" value=""></label><br>'+ '<label> Filling<input type="text" name="fi[]" id="fi' + counter + '" value=""></label><br>'+ '<label> Frosting<input type="text" name="fr[]" id="fr' + counter + '" value=""></label><br>' ); newBatchBoxDiv.appendTo("#batch"); counter++; }); $("#Remove").click(function () { if(counter==1){ alert("No more tier to remove"); return false; } counter--; $("#BatchDiv" + counter).remove(); }); }); </script> i am trying to post the values in an array to post it onto next .php page i am using this var user_cupfl = $('input[name^="fl"]').serialize(); var user_cupfi = $('input[name^="fi"]').serialize(); var user_cupfr = $('input[name^="fr"]').serialize(); serialize is not passing the values. :( on second page i am trying to mail it using $message .= "<tr><td><strong>Cake Flavors(according to batches):</strong> </td><td><pre>" .implode("\n", $user_cupfl). "</pre></td></tr>"; $message .= "<tr><td><strong>Filling type (Inside the cake):</strong> </td><td><pre>" .implode("\n", $user_cupfi). "</pre></td></tr>"; $message .= "<tr><td><strong>Frosting type (top of the cake):</strong> </td><td><pre>" .implode("\n", $user_cupfr). "</pre></td></tr>"; i m posting array like this $user_cupfl=filter_var($_POST["userCupfl"], FILTER_SANITIZE_STRING); $user_cupfi=filter_var($_POST["userCupfi"], FILTER_SANITIZE_STRING); $user_cupfr=filter_var($_POST["userCupfr"], FILTER_SANITIZE_STRING); your replies will be highly appreciated

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  • How to get final destination URL from AJAX?

    - by Maurice Lam
    When I do an XMLHttpRequest, I always get redirected automatically to the URL (presumably by the headers of the response). For example, if I query "http://www.stackoverflow.com" I will be redirected to "http://stackoverflow.com". How can I get that final URL? (http://stackoverflow.com/ in the example) I checked in the response headers but I cannot seem to find it. (I just used the GET/POST method not HEAD).

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  • Replacing one image with another image through ajax makes it dissappear for a split second

    - by ooo
    I have the following code (asp.net-mvc, jquery) (i have simplified the example to show the issue) where i want to click on an image and have it replaced with another image. This works fine but the first time i click it, the original image disappears (for a split second) before the other image shows up. After that it works seamlessly. Is there any way to eliminate this quirk so there is not split second where no image is shown? Here is my controller code: public ActionResult UpdateFavoriteExercise(int id, string toggle) { if (toggle == "off") { return Content("<img toggle='off' src='/images/vote-favorite-off1.png' border=0'>"); } return Content("<img toggle='on' src='/images/vote-favorite-on1.png' border=0'>"); } Here is my jquery code: $('div.favoriteExercise').live('click', function() { var id = $(this).attr("id"); var toggle = $(this).attr("toggle"); if (toggle == 'off') { onOff = 'on'; } else { onOff = 'off'; } var url = '/Tracker/UpdateFavoriteExercise/' + id + '?toggle=' + onOff; $(this).load(url); $(this).attr("toggle", onOff); });

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  • jquery/ajax load new content when available

    - by Tim
    I know this is quite a vague question -- sorry about that. If I have a forum, shoutbox or something similar where users enter and submit data, running on PHP and MySQL, what is the best way to have the newly submitted content automatically display on the page for all users when it is submitted? Much like a live newsfeed, if you like... The effect sort-of works here at stackoverflow, when you are answering a question you are told when new answer is submitted. I want to test for newly submitted content and then display it automatically. Any suggestions? Many thanks :)

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  • how to test rails js and ajax without a browser

    - by user1679052
    when i use rspec with capybara to test my rails js page , I got the following error: "Selenium::WebDriver::Error::WebDriverError: Could not find Firefox binary (os=linux). " Actually my rails script are all written on the linux server, where there is on brower installed, and any desktop software is not supported on the server (since no X11 is installed). How can I test js in this situation. Or is there and brower that works without X11 installed like wget? Thanks.

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  • Get error with ajax get in jquery to an extern url

    - by user1394983
    I have a big problem. I want get information with an webservice in one URL. But I'mm getting this error: XMLHttpRequest cannot load ht*p://external_url_that_i_trid_to_get. Origin ht*p://localhost:8888 is not allowed by Access-Control-Allow-Origin. Im using this: $.get(url_parsed,date_get,function(data) { if (data.result == 'sucess') { alert(data.data["title"]); } },"json"); How I can resolve this? Regards

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  • Update (ajax) only part of table without affecting whole table

    - by ile
    <table width="100%" border="0" cellspacing="0" cellpadding="0" class="list"> <tr> <th><a href="#" class="sortby">Full Name</a></th> <th><a href="#" class="sortby">City</a></th> <th><a href="#" class="sortby">Country</a></th> <th><a href="#" class="sortby">Status</a></th> <th><a href="#" class="sortby">Education</a></th> <th><a href="#" class="sortby">Tasks</a></th> </tr> <div class="dynamicData"> <tr> <td>Firstname Lastname</a></td> <td>Los Angeles</td> <td>USA</td> <td>Married</td> <td>High School</td> <td>4</td> </tr> </tr> <tr> <td>Firstname Lastname</a></td> <td>Los Angeles</td> <td>USA</td> <td>Married</td> <td>High School</td> <td>4</td> </tr> </div> </table> The idea is to update table rows when clicking on link with clasl "sortby" which is part of th table tag. I tried inserting div but this doesn't work. Separating this in two tables is not good solution because witdh in both tables cell are not following each other. Any other solution? Thanks

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  • jquery.ajax returns content-type "html" on iis while it returns content-type "json" on local host

    - by Sridhar
    Hi, I am using jQuery.ajax function to make an ajax call to a page method in asp.net. I specifically set the content-type to "application/json; charset=utf-8". When I looked at the response in the firebug it says the content-type is html. Following is the code to my ajax call $.ajax({ async: asyncVal, type: "POST", url: url + '/' + webMethod, data: dataPackage, contentType: "application/json; charset=UTF-8", dataType: "json", error: errorFunction, success: successFunction });

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