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  • How often do you use google, to answer programming relatated questions? [closed]

    - by Mercfh
    I hope this isn't too subjective, but it is programming related and Im curious. Alot of times I feel.......dumb for lack of a better word when I have to look something up. Alot of times I forget all the specificity of a language and have to look up something like "Doing XXX in C++" for instance, or something along the lines of that. How often do you guys as Programmers both Professionally and On your own have to use google to look up something. Or do most people just kind of remember these things. I guess what Im really asking is, do you often have to use google or other web-search sites to remember how to do what is seemingly "simple" things with languages but you've just forgotten? Please tell me im not the ONLY one.

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  • Rules of Holes #3 -A Better Shovel is NOT the Answer!

    - by ArnieRowland
    You stopped digging. You looked around and saw that you were still in the Hole. You needed to get out. AHA! Problem solved, you thought. You'll just get a better and more efficient shovel! Sorry, I have to tell you that switching to a more efficient shovel is unlikely to help you get out of the Hole. Yes, your resumed digging may be faster, more directed, and even well planned and articulated. But you will still be in the Hole, and digging. And that's just not the solution. A new process (scrum,...(read more)

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  • Rules of Holes #3: A Better Shovel is NOT the Answer!

    - by ArnieRowland
    You stopped digging. You looked around and saw that you were still in the Hole. You needed to get out. AHA! Problem solved, you thought. You'll just get a better and more efficient shovel! I regret to tell you that the Third Rule of Holes applies: Switching to a more efficient shovel is unlikely to help you get out of the Hole . Yes, your resumed digging may be faster, more directed, and even well planned and articulated. But you will still be in the Hole, and digging. And that's just not the solution....(read more)

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  • What can I do when the interviewer doesn't know the answer to his/her own question?

    - by bjskishore123
    Yesterday I had a terrible experience in an interview. Interviewer asked me about pure virtual function. I said, It may or may not have definition in base class, but derived classes should provide definition unless they also want to be abstract class. But interviewer kept on asking that "Can pure virtual have definition !!! ???"... I said yes. Again he said "Pure ?" I said yes. It is allowed, derived classes can explicitly call that function if they want that particular behavior. He sent me out. I am sure that he doesn't know the fact that pure virtual function can have definition. How to deal with this kind of Interviewers ? After asking 2nd time, should i lie that it can't have definition ? :) Or i should stick to my words and loose the job opportunity ?

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  • What is Site Rubix? Find the Answer Here!

    Online Marketing has really taken off lately, and that has come as no surprise. Many people who currently work "for the man" have found that man to be untrustworthy, as so many have lost their jobs through cut backs and downsizing.

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  • What do ptLineDist and relativeCCW do?

    - by Fasih Khatib
    I saw these methods in the Line2D Java Docs but did not understand what they do? Javadoc for ptLineDist says: Returns the distance from a point to this line. The distance measured is the distance between the specified point and the closest point on the infinitely-extended line defined by this Line2D. If the specified point intersects the line, this method returns 0.0 Doc for relativeCCW says: Returns an indicator of where the specified point (PX, PY) lies with respect to the line segment from (X1, Y1) to (X2, Y2). The return value can be either 1, -1, or 0 and indicates in which direction the specified line must pivot around its first endpoint, (X1, Y1), in order to point at the specified point (PX, PY). A return value of 1 indicates that the line segment must turn in the direction that takes the positive X axis towards the negative Y axis. In the default coordinate system used by Java 2D, this direction is counterclockwise. A return value of -1 indicates that the line segment must turn in the direction that takes the positive X axis towards the positive Y axis. In the default coordinate system, this direction is clockwise. A return value of 0 indicates that the point lies exactly on the line segment. Note that an indicator value of 0 is rare and not useful for determining colinearity because of floating point rounding issues. If the point is colinear with the line segment, but not between the endpoints, then the value will be -1 if the point lies "beyond (X1, Y1)" or 1 if the point lies "beyond (X2, Y2)".

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  • Want to Optimize Your Own Site? Then SEO Classes Are the Answer

    If you have decided to learn search engine optimization because you would like your website to gain higher ranking by adding targeted keywords then the best way to do this would be to attend SEO classes online. This way you won't have to pay professional SEO companies as you will be capable of setting up your own business in no time one you have completed your training.

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  • C++ OOP - Can you 'overload a cast' <- hard to explain in 1 sentence

    - by Brandon Miller
    Well, the WinAPI has a POINT struct, but I am trying to make an alternative class to this so you can set the values of x and y from a constructor. /** * X-Y coordinates */ class Point { public: int X, Y; Point(void) : X(0), Y(0) {} Point(int x, int y) : X(x), Y(y) {} Point(const POINT& pt) : X(pt.x), Y(pt.y) {} Point& operator= (const POINT& other) { X = other.x; Y = other.y; } }; // I have an assignment operator and copy constructor. Point myPtA(3,7); Point myPtB(8,5); POINT pt; pt.x = 9; pt.y = 2; // I can assign a 'POINT' to a 'Point' myPtA = pt; // But I also want to be able to assign a 'Point' to a 'POINT' pt = myPtB; Is it possible to overload operator= in a way so that I can assign a Point to a POINT? Or maybe some other method to achieve this? Thanks in advance.

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  • Prolog check if

    - by NickLee
    I'm creating a text adventure game on SWI-Prolog and I want to include (some kind of) dialogs. What I have so far is: dialog1(1):- nl,write('blah blah'),nl write('a: this is answer a'),nl, write('b: this is answer b'),nl. a:- write('respond to answer a'),nl. b:- write('respond to answer b'),nl. That's pretty much the first dialog. Now I want to create a second dialog similar to the first one. dialog1(2):- nl,write('blah blah'),nl, write('a: this is answer a'),nl, write('b: this is answer b'),nl. a:- write('respond to answer a'),nl. b:- write('respond to answer b'),nl. How can I check if the dialog is the first or the second one? I want to do that because when the user types a., I need the right answer a to be shown. I thought I could use something like a(1):- write('respond to answer a'),nl. b(1):- write('respond to answer b'),nl. /* and on the second dialog*/ a(2):- write('respond to answer a'),nl. b(2):- write('respond to answer b'),nl. But still, if the user is on dialog 2 and he types a(1),the first answer will appear.

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  • Why does SFINAE not apply to this?

    - by Simon Buchan
    I'm writing some simple point code while trying out Visual Studio 10 (Beta 2), and I've hit this code where I would expect SFINAE to kick in, but it seems not to: template<typename T> struct point { T x, y; point(T x, T y) : x(x), y(y) {} }; template<typename T, typename U> struct op_div { typedef decltype(T() / U()) type; }; template<typename T, typename U> point<typename op_div<T, U>::type> operator/(point<T> const& l, point<U> const& r) { return point<typename op_div<T, U>::type>(l.x / r.x, l.y / r.y); } template<typename T, typename U> point<typename op_div<T, U>::type> operator/(point<T> const& l, U const& r) { return point<typename op_div<T, U>::type>(l.x / r, l.y / r); } int main() { point<int>(0, 1) / point<float>(2, 3); } This gives error C2512: 'point<T>::point' : no appropriate default constructor available Given that it is a beta, I did a quick sanity check with the online comeau compiler, and it agrees with an identical error, so it seems this behavior is correct, but I can't see why. In this case some workarounds are to simply inline the decltype(T() / U()), to give the point class a default constructor, or to use decltype on the full result expression, but I got this error while trying to simplify an error I was getting with a version of op_div that did not require a default constructor*, so I would rather fix my understanding of C++ rather than to just do what works. Thanks! *: the original: template<typename T, typename U> struct op_div { static T t(); static U u(); typedef decltype(t() / u()) type; }; Which gives error C2784: 'point<op_div<T,U>::type> operator /(const point<T> &,const U &)' : could not deduce template argument for 'const point<T> &' from 'int', and also for the point<T> / point<U> overload.

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  • What's the use of Ant's extension-point if/unless attributes?

    - by Robert Menteer
    When you define an extension-point in an Ant build file you can have it conditional by using the if or unless attribute. On a target the if/unless prevent it's tasks from being run. But an extension-point doesn't have any tasks to conditionally run, so what does the condition do? My thought (which proved to be incorrect in Ant 1.8.0) is it would prevent any tasks that extend the extension-point from being run. Here is an example build script showing the problem: <project name = "ext-test" default = "main"> <property name = "do.it" value = "false" /> <extension-point name = "init"/> <extension-point name = "doit" depends = "init" if = "${do.it}" /> <target name = "extend-init" extensionOf = "init"> <echo message = "Doing extend-init." /> </target> <target name = "extend-doit" extensionOf = "doit"> <echo message = "Do It! (${do.it})" /> </target> <target name = "main" depends = "doit"> <echo message = "Doing main." /> </target> </project> Using the command: ant -v Relults in: Apache Ant version 1.8.0 compiled on February 1 2010 Trying the default build file: build.xml Buildfile: /Users/bob/build.xml Detected Java version: 1.6 in: /System/Library/Frameworks/JavaVM.framework/Versions/1.6.0/Home Detected OS: Mac OS X parsing buildfile /Users/bob/build.xml with URI = file:/Users/bob/build.xml Project base dir set to: /Users/bob parsing buildfile jar:file:/Users/bob/Documents/Development/3P-Tools/apache-ant-1.8.0/lib/ant.jar!/org/apache/tools/ant/antlib.xml with URI = jar:file:/Users/bob/Documents/Development/3P-Tools/apache-ant-1.8.0/lib/ant.jar!/org/apache/tools/ant/antlib.xml from a zip file Build sequence for target(s) `main' is [extend-init, init, extend-doit, doit, main] Complete build sequence is [extend-init, init, extend-doit, doit, main, ] extend-init: [echo] Doing extend-init. init: extend-doit: [echo] Do It! (false) doit: Skipped because property 'false' not set. main: [echo] Doing main. BUILD SUCCESSFUL Total time: 0 seconds You will notice the target extend-doit is executed but the extention-point itself is skipped. Since an extention-point doesn't have any tasks exactly what has been skipped? Any targets that depend on the extention-point still get executed since a skipped target is a successful target. What is the value of the if/unless attributes on an extention-point?

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  • Questions every good Java/J2EE Developer should be able to answer?

    - by Rachel
    I was going through Questions every good .Net developer should be able to answer and was highly impressed with the content and approach of this question, and so in the same spirit, I am asking this question for Java/J2EE Developer. What questions do you think should a good Java/J2EE programmer be able to answer? I am marking this question as community wiki as it is not user specific and it aims to serve programming community at large. Looking forward for some amazing responses. EDIT: Please answer questions too, as suggested in the comments, so that people could learn something new regarding the language, too.

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  • How do I set the current point in a CG graphics context?

    - by Joe
    When running the code below in the iphone simulator I get the error : CGContextClosePath: no current point. Why is the current point not being set? Or is the context not set to the correct state? CGContextBeginPath(ctx); CGMutablePathRef pathHolder; pathHolder = CGPathCreateMutable(); //move to point for the initial point NSLog(@"Drawing a state point %f, %f", [[holder.points objectAtIndex:0] floatValue], [[holder.points objectAtIndex:1] floatValue]); CGPathMoveToPoint(pathHolder, NULL, [[holder.points objectAtIndex:0] floatValue], [[holder.points objectAtIndex:1] floatValue]); for(int x = 2; x < [holder.points count] - 1; x += 2) { NSLog(@"Drawing a state point %f, %f", [[holder.points objectAtIndex:x] floatValue], [[holder.points objectAtIndex:(x+1)] floatValue]); CGPathAddLineToPoint(pathHolder, NULL, [[holder.points objectAtIndex:x] floatValue], [[holder.points objectAtIndex:(x+1)] floatValue]); } CGContextClosePath(ctx); CGContextFillPath(ctx);

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  • Can I configure Wndows NDES server to use Triple DES (3DES) algorithm for PKCS#7 answer encryption?

    - by O.Shevchenko
    I am running SCEP client to enroll certificates on NDES server. If OpenSSL is not in FIPS mode - everything works fine. In FIPS mode i get the following error: pkcs7_unwrap():pkcs7.c:708] error decrypting inner PKCS#7 139968442623728:error:060A60A3:digital envelope routines:FIPS_CIPHERINIT:disabled for fips:fips_enc.c:142: 139968442623728:error:21072077:PKCS7 routines:PKCS7_decrypt:decrypt error:pk7_smime.c:557: That's because NDES server uses DES algorithm to encrypt returned PKCS#7 packet. I used the following debug code: /* Copy enveloped data from PKCS#7 */ bytes = BIO_read(pkcs7bio, buffer, sizeof(buffer)); BIO_write(outbio, buffer, bytes); p7enc = d2i_PKCS7_bio(outbio, NULL); /* Get encryption PKCS#7 algorithm */ enc_alg=p7enc->d.enveloped->enc_data->algorithm; evp_cipher=EVP_get_cipherbyobj(enc_alg->algorithm); printf("evp_cipher->nid = %d\n", evp_cipher->nid); The last string always prints: evp_cipher-nid = 31 defined in openssl-1.0.1c/include/openssl/objects.h #define SN_des_cbc "DES-CBC" #define LN_des_cbc "des-cbc" #define NID_des_cbc 31 I use 3DES algorithm for PKCS7 requests encryption in my code (pscep.enc_alg = (EVP_CIPHER *)EVP_des_ede3_cbc()) and NDES server accepts these requests, but it always returns answer encrypted with DES. Can I configure Wndows NDES server to use Triple DES (3DES) algorithm for PKCS#7 answer encryption?

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  • How do I point a new domain to start on a page that's not index.html on separate hosting? [closed]

    - by Owen Campbell-Moore
    Possible Duplicate: How do I point a new domain to start on a page that's not index.html on separate hosting? I'm using a service called SquareSpace to host my site, and today I'm registering the domain for it. Basically, how do I make it so when somebody types www.tedxoxford.com it points at http://www.tedxoxford.com/landing (currently http://tedxoxford.squarespace.com/landing) instead of the default index? Is this possible? Squarespace is quite a restricted CMS and means that your logos etc all point to the index so I don't want people ending up on my landing/splash page every time they want the home page, only on the first time they type in the URL. A dirty hack would be to check the refferer and redirect anyone hitting the index to the landing page, but that's a lot of loading overhead I'd rather avoid...

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  • Le monde sur le point de se « noyer dans les données » selon le président d'Oracle qui prédit une crise du stockage et du traitement

    Le monde sur le point de se « noyer dans les données » Selon le président d'Oracle qui prédit une crise du stockage et de traitement Dans une déclaration au Times de Londres, le coprésident d'Oracle Mark Hurd a évoqué le sujet de « la croissance exponentielle » des données. Il prédit que celle-ci soit sur le point de déclencher un problème majeur dans les opérations de stockage, de traitement et d'analyse en temps réel. [IMG]http://idelways.developpez.com/news/images/oracle-marc-hurd.jpg[/IMG] Mark Hurd Selon Hurd, le nombre de dispositifs connectés à internet et fournissant des données pour les entreprises va croître po...

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  • What does a DHCP-client consider to be the "best" answer?

    - by Nils
    We have training rooms where normally Windows XP is installed (via PXE). The "normal" DNS/DHCP infrastructure are Windows-Servers. The training room has its own VLAN (different from the Windows servers), so there is most propably an IP helper for DHCP requests active on the Cisco router where all PCs from that room are connected to. Now we wanted to convert some of the PCs to Linux instead. The idea was: Put our own Laptop with a DHCP server into the VLAN of the room and override the "normal" DHCP response. The idea was that this should work, since a directly attached DHCP server in that VLAN should have a faster response-time than the "normal" DHCP server located some hops away from that VLAN. It turned out that this did not work. We had to manually release the lease on the original DHCP server to get it working. On the Laptop we did see the client requesting the IP and "our" dhcp was sending NACKs to the Windows IP request, before that we did offer our own response. Old Question: Why did this not work out as expected? What is making the PC regain its old lease? Update 2012-08-08: The regain-issue has been explained in the DHCP-RFC. Now this explains why the PC regains its old lease. Now we do release the IP from the Windows-DHCP-server before giving it another try. Again - the Windows-DHCP-server wins. I suspect that there is some algorithm for the dhcp-client which determines the "best" dhcp-answer for the client. The new question is: How does the client choose the "best" answer?

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  • Turn your laptop into a wireless Access Point with Windows 7!

    - by David Nudelman
    Windows 7 offers a very cool feature where you can connect multiple devices to any wired and wireless network connection (hotel, cable, 3G, UMTS, EDGE, WIFI, RJ45, Ethernet, etc.) by turning your own laptop into a wireless AP (Access Point) to relay those devices not directly connected to the internet. For this just enter these two commands to an elevated (right click on CMD.EXE, run as administrator): netsh wlan set hostednetwork mode=allow ssid=YOURFRIENDLYSSID key=SOMEPASSWORD netsh wlan start hostednetwork At this point, if Internet Connection Sharing (ICS) is setup, anyone can connect to your SoftAP (if they know the PWD of course) and the traffic will be sent through whatever adapter you want. You can actually bridge it across an entirely different adapter... or the same on a different Wifi LAN. A GUI to set this up can be downloaded for free here: http://www.connectify.me/

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  • Auto-mount CD/DVD drive to single, specific mount point every time?

    - by Christopher Parker
    Currently, whenever I insert a CD or DVD into my DVD drive, it mounts to a location such as /media/<LABEL>, where <LABEL> is the arbitrary label assigned to the optical disc. I remember, once upon a time, CD and DVD media being reliably located at /media/cdrom0 or something similar. Why was this changed? And how do I get this old behavior back for this drive? I can understand this behavior for USB sticks. It makes sense for those. But not for CD/DVD media, in my opinion. For example, because of this, I have no way to configure Wine to point to my DVD drive, as the mount point changes with every single CD I insert. TL;DR: How do I make CD/DVD media always mount to /media/cdrom0?

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  • Applications: The mathematics of movement, Part 1

    - by TechTwaddle
    Before you continue reading this post, a suggestion; if you haven’t read “Programming Windows Phone 7 Series” by Charles Petzold, go read it. Now. If you find 150+ pages a little too long, at least go through Chapter 5, Principles of Movement, especially the section “A Brief Review of Vectors”. This post is largely inspired from this chapter. At this point I assume you know what vectors are, how they are represented using the pair (x, y), what a unit vector is, and given a vector how you would normalize the vector to get a unit vector. Our task in this post is simple, a marble is drawn at a point on the screen, the user clicks at a random point on the device, say (destX, destY), and our program makes the marble move towards that point and stop when it is reached. The tricky part of this task is the word “towards”, it adds a direction to our problem. Making a marble bounce around the screen is simple, all you have to do is keep incrementing the X and Y co-ordinates by a certain amount and handle the boundary conditions. Here, however, we need to find out exactly how to increment the X and Y values, so that the marble appears to move towards the point where the user clicked. And this is where vectors can be so helpful. The code I’ll show you here is not ideal, we’ll be working with C# on Windows Mobile 6.x, so there is no built-in vector class that I can use, though I could have written one and done all the math inside the class. I think it is trivial to the actual problem that we are trying to solve and can be done pretty easily once you know what’s going on behind the scenes. In other words, this is an excuse for me being lazy. The first approach, uses the function Atan2() to solve the “towards” part of the problem. Atan2() takes a point (x, y) as input, Atan2(y, x), note that y goes first, and then it returns an angle in radians. What angle you ask. Imagine a line from the origin (0, 0), to the point (x, y). The angle which Atan2 returns is the angle the positive X-axis makes with that line, measured clockwise. The figure below makes it clear, wiki has good details about Atan2(), give it a read. The pair (x, y) also denotes a vector. A vector whose magnitude is the length of that line, which is Sqrt(x*x + y*y), and a direction ?, as measured from positive X axis clockwise. If you’ve read that chapter from Charles Petzold’s book, this much should be clear. Now Sine and Cosine of the angle ? are special. Cosine(?) divides x by the vectors length (adjacent by hypotenuse), thus giving us a unit vector along the X direction. And Sine(?) divides y by the vectors length (opposite by hypotenuse), thus giving us a unit vector along the Y direction. Therefore the vector represented by the pair (cos(?), sin(?)), is the unit vector (or normalization) of the vector (x, y). This unit vector has a length of 1 (remember sin2(?) + cos2(?) = 1 ?), and a direction which is the same as vector (x, y). Now if I multiply this unit vector by some amount, then I will always get a point which is a certain distance away from the origin, but, more importantly, the point will always be on that line. For example, if I multiply the unit vector with the length of the line, I get the point (x, y). Thus, all we have to do to move the marble towards our destination point, is to multiply the unit vector by a certain amount each time and draw the marble, and the marble will magically move towards the click point. Now time for some code. The application, uses a timer based frame draw method to draw the marble on the screen. The timer is disabled initially and whenever the user clicks on the screen, the timer is enabled. The callback function for the timer follows the standard Update and Draw cycle. private double totLenToTravelSqrd = 0; private double startPosX = 0, startPosY = 0; private double destX = 0, destY = 0; private void Form1_MouseUp(object sender, MouseEventArgs e) {     destX = e.X;     destY = e.Y;     double x = marble1.x - destX;     double y = marble1.y - destY;     //calculate the total length to be travelled     totLenToTravelSqrd = x * x + y * y;     //store the start position of the marble     startPosX = marble1.x;     startPosY = marble1.y;     timer1.Enabled = true; } private void timer1_Tick(object sender, EventArgs e) {     UpdatePosition();     DrawMarble(); } Form1_MouseUp() method is called when ever the user touches and releases the screen. In this function we save the click point in destX and destY, this is the destination point for the marble and we also enable the timer. We store a few more values which we will use in the UpdatePosition() method to detect when the marble has reached the destination and stop the timer. So we store the start position of the marble and the square of the total length to be travelled. I’ll leave out the term ‘sqrd’ when speaking of lengths from now on. The time out interval of the timer is set to 40ms, thus giving us a frame rate of about ~25fps. In the timer callback, we update the marble position and draw the marble. We know what DrawMarble() does, so here, we’ll only look at how UpdatePosition() is implemented; private void UpdatePosition() {     //the vector (x, y)     double x = destX - marble1.x;     double y = destY - marble1.y;     double incrX=0, incrY=0;     double distanceSqrd=0;     double speed = 6;     //distance between destination and current position, before updating marble position     distanceSqrd = x * x + y * y;     double angle = Math.Atan2(y, x);     //Cos and Sin give us the unit vector, 6 is the value we use to magnify the unit vector along the same direction     incrX = speed * Math.Cos(angle);     incrY = speed * Math.Sin(angle);     marble1.x += incrX;     marble1.y += incrY;     //check for bounds     if ((int)marble1.x < MinX + marbleWidth / 2)     {         marble1.x = MinX + marbleWidth / 2;     }     else if ((int)marble1.x > (MaxX - marbleWidth / 2))     {         marble1.x = MaxX - marbleWidth / 2;     }     if ((int)marble1.y < MinY + marbleHeight / 2)     {         marble1.y = MinY + marbleHeight / 2;     }     else if ((int)marble1.y > (MaxY - marbleHeight / 2))     {         marble1.y = MaxY - marbleHeight / 2;     }     //distance between destination and current point, after updating marble position     x = destX - marble1.x;     y = destY - marble1.y;     double newDistanceSqrd = x * x + y * y;     //length from start point to current marble position     x = startPosX - (marble1.x);     y = startPosY - (marble1.y);     double lenTraveledSqrd = x * x + y * y;     //check for end conditions     if ((int)lenTraveledSqrd >= (int)totLenToTravelSqrd)     {         System.Console.WriteLine("Stopping because destination reached");         timer1.Enabled = false;     }     else if (Math.Abs((int)distanceSqrd - (int)newDistanceSqrd) < 4)     {         System.Console.WriteLine("Stopping because no change in Old and New position");         timer1.Enabled = false;     } } Ok, so in this function, first we subtract the current marble position from the destination point to give us a vector. The first three lines of the function construct this vector (x, y). The vector (x, y) has the same length as the line from (marble1.x, marble1.y) to (destX, destY) and is in the direction pointing from (marble1.x, marble1.y) to (destX, destY). Note that marble1.x and marble1.y denote the center point of the marble. Then we use Atan2() to get the angle which this vector makes with the positive X axis and use Cosine() and Sine() of that angle to get the unit vector along that same direction. We multiply this unit vector with 6, to get the values which the position of the marble should be incremented by. This variable, speed, can be experimented with and determines how fast the marble moves towards the destination. After this, we check for bounds to make sure that the marble stays within the screen limits and finally we check for the end condition and stop the timer. The end condition has two parts to it. The first case is the normal case, where the user clicks well inside the screen. Here, we stop when the total length travelled by the marble is greater than or equal to the total length to be travelled. Simple enough. The second case is when the user clicks on the very corners of the screen. Like I said before, the values marble1.x and marble1.y denote the center point of the marble. When the user clicks on the corner, the marble moves towards the point, and after some time tries to go outside of the screen, this is when the bounds checking comes into play and corrects the marble position so that the marble stays inside the screen. In this case the marble will never travel a distance of totLenToTravelSqrd, because of the correction is its position. So here we detect the end condition when there is not much change in marbles position. I use the value 4 in the second condition above. After experimenting with a few values, 4 seemed to work okay. There is a small thing missing in the code above. In the normal case, case 1, when the update method runs for the last time, marble position over shoots the destination point. This happens because the position is incremented in steps (which are not small enough), so in this case too, we should have corrected the marble position, so that the center point of the marble sits exactly on top of the destination point. I’ll add this later and update the post. This has been a pretty long post already, so I’ll leave you with a video of how this program looks while running. Notice in the video that the marble moves like a bot, without any grace what so ever. And that is because the speed of the marble is fixed at 6. In the next post we will see how to make the marble move a little more elegantly. And also, if Atan2(), Sine() and Cosine() are a little too much to digest, we’ll see how to achieve the same effect without using them, in the next to next post maybe. Ciao!

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  • How can I ensure our project gets developed successfully, without having any project management experience? [migrated]

    - by Raven13
    I'm a web developer who is part of a three-man team that has been tasked with a rather large and complex development project. Other than some direction and impetus from management, we're pretty much on our own to develop the new website. None of us have any project management experience nor do my two coworkers seem like they would be interested in taking on that role, so I feel like it's up to me to implement some kind of structure to the development process in order to avoid issues down the road. What can I do as a developer without project management experience to ensure that our project gets developed successfully and avoid the pitfalls of developing a project without a plan?

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  • How can I test if a point lies between two parallel lines?

    - by Harold
    In the game I'm designing there is a blast that shoots out from an origin point towards the direction of the mouse. The width of this blast is always going to be the same. Along the bottom of the screen (what's currently) squares move about which should be effected by the blast that the player controls. Currently I am trying to work out a way to discover if the corners of these squares are within the blast's two bounding lines. I thought the best way to do this would be to rotate the corners of the square around an origin point as if the blast were completely horizontal and see if the Y values of the corners were less than or equal to the width of the blast which would mean that they lie within the effected region, but I can't work out

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  • Wavefront mesh: determine which face a point belongs to?

    - by Mina Samy
    I have a 3D mesh Wavefront .obj file. Is there any algorithm that takes an arbitrary point coordinates as input and determines which face of the mesh that point belongs to ?? The mesh is rendered on the screen, then the user clicks on it, I want to determine which part of the mesh the user has clicked on ? Here's the code using LibGDX: Vector3 intersection=new Vector3(); Ray ray=camera.getPickRay(x, y); //vertices is an array that hold the coordinates of the mesh boolean ok=Intersector.intersectRayTriangles(ray, vertices, intersection); Thanks

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  • How do I find the closest points(thereby forming a polygon) enclosing a particular point?(see image)

    - by nilspin
    I am working with a game engine, and my task is to add code for simulating fracture of rigid meshes. Right now I'm only working on breaking a cube. I am using Voronoi's algorithm to make a (realistic)fractured shard and I am using the half-plane method to generate a voronoi cell. Now the way I do this is for every seed point, I make planes that are perpendicular bisector planes(the straight black lines in the image) with rest of the seed points and I calculate the intersections of all these planes to give me distinct points(all the orange dots). I've gotten this far. Out of all these calculated intersection points, I only need the ones that are closest and enclosing the seed point(the points encircled in red) and I need to discard all the rest. Information that I have : 1) Plane equations of all planes(defined by normalized normal vectors and their distance from origin) 2) Points of intersection(that I've calculated) Can anybody help me find out how I can find the points encircled in red? Thanks.

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  • How do I stop Banshee from putting a notification in the panel for every song?

    - by Dave M G
    As a playlist or internet radio station plays, a notification pops up in the top right corner every time the song changes. I can't find any way either within Banshee or settings in general to stop this. How do I stop Banshee from putting a notification in the panel for every song? Further, can I stop Banshee from outputting any notifications at all? Update: I tried going into Banshee ? Edit ? Preferences ? Extensions, and disabled the Sound Menu Integration, but this does not seem to stop notifications.

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