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  • Project-wide additional library paths -- MSVS2008

    - by sacamano
    Hi there. I'm setting up a VC++ project in MS Visual Studio 2008 that'll be used by several people. I wanted to keep things as simple as possible so I've set up Additional Include Directories via the Project properties. I've also set up additional library files via Tools - Options - Projects and Solutions - VC++ Directories. However, my issue is that I really need to set up Additional library PATHs, because I am using an SDK which does inline linking of libraries. I could just tell each one of the participants to manually add the library path to their MSVS2008 environment, but it would be handy if I could integrate the RELATIVE library path in the project itself.

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  • Locale C++ shared library in /usr/local/lib

    - by Dave
    I'm venturing into the world of C++ and Linux, and am having problems linking against a shared library. I have a library, libicuuc.so.44.1, installed in /usr/local/lib. There is also a link in the same directory, libicuuc.so.44 pointing to that library. My /etc/ld.so.conf reads: include /etc/ld.so.conf.d/*.conf I have a file, /etc/ld.so.conf.d/libc.conf, that contains: # libc default configuration /usr/local/lib However, when I compile my program (that includes LIBS += -licuuc), I get the following error at runtime: error while loading shared libraries: libicuuc.so.44: cannot open shared object file: No such file or directory I am using Qt Creator on Ubuntu 10.04. Any help is greatly appreciated!

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  • How to list library dependencies of a non-native binary?

    - by lvella
    When developing for native platform, I can use ldd to list all the shared libraries (.so files) a binary executable I build will try to load upon start-up. But when cross-compiling, I don't know how to get the same information. The ldd is not a normal binutils utility, like strip or ar, that can be built alongside gcc for cross compiling, but instead, it is a cryptic shell script that apparently can only run on native platform. So, using the cross-target binutils tools, is there any way to get a list of the dynamically linked dependency for of a foreign binary?

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  • Unit testing of static library that involves NSDocumentDirectory and other iOS App specific calls.

    - by Shiun
    Hi, I'm attempting to run unit tests for a static library that attempts to create/write/read a file in the document directory. Since this is a static library and not an application for the iOS, attempts to reference the NSDocumentDirectory is returning me directory for the form "/Users//Library/Application Support/iPhone Simulator/Documents" This directory does not exist. When attempting to access a directory from an actual application, the NSDocumentDirectory returns something of the form: "/Users//Library/Application Support/iPhone Simulator/4.2/FEDBEF5F-1326-4383-A087-CDA1B865E61A/Documents" (Please note the simulator version as well as application ID as part of the path) How can I overcome this shortcoming in the unit test framework for static libraries that implement tests that require iOS app specific calls? Thanks in advance.

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  • Conditional Regular Expression testing of a CSV

    - by Alastair Pitts
    I am doing some client side validation in ASP.NET MVC and I found myself trying to do conditional validation on a set of items (ie, if the checkbox is checked then validate and visa versa). This was problematic, to say the least. To get around this, I figured that I could "cheat" by having a hidden element that would contain all of the information for each set, thus the idea of a CSV string containing this information. I already use a custom [HiddenRequired] attribute to validate if the hidden input contains a value, with success, but I thought as I will need to validate each piece of data in the csv, that a regular expression would solve this. My regular expression work is extremely weak and after a good 2 hours I've almost given up. This is an example of the csv string: true,3,24,over,0.5 to explain: true denotes if I should validate the rest. I need to conditionally switch in the regex using this 3 and 24 are integers and will only ever fall in the range 0-24. over is a string and will either be over or under 0.5 is a decimal value, of unknown precision. In the validation, all values should be present and at least of the correct type Is there someone who can either provide such a regex or at least provide some hints, i'm really stuck!

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  • XSLT: Regular Expression function does not work?

    - by Fedor Steeman
    Ok, this one has been driving me up the wall... I have a xslt function that is supposed to split out the Zip-code part from a Zip+City string depending on the country. I cannot get it to work! This is what I got so far: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:exslt="http://exslt.org/functions" xmlns:xs="http://www.w3.org/2001/XMLSchema"> <xsl:function name="exslt:GetZip" as="xs:string"> <xsl:param name="zipandcity" as="xs:string"/> <xsl:param name="countrycode" as="xs:string"/> <xsl:choose> <xsl:when test="$countrycode='DK'"> <xsl:analyze-string select="$zipandcity" regex="(\d{4}) ([A-Za-zÆØÅæøå]{3,24})"> <xsl:matching-substring> <xsl:value-of select="regex-group(1)"/> </xsl:matching-substring> <xsl:non-matching-substring> <xsl:text>fail</xsl:text> </xsl:non-matching-substring> </xsl:analyze-string> </xsl:when> <xsl:otherwise> <xsl:text>error</xsl:text> </xsl:otherwise> </xsl:choose> </xsl:function> I am running it on a source XML where the following values are passed to the function: zipandcity: "DK-2640 København SV" countrycode: "DK" ...will output 'fail'! I think there is something I am misunderstanding here...

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  • Sanitize a string with non-alphanum repetition

    - by Toto
    I need to sanitize article titles when (creative) users try to "attract attention" with some non-alphanum repetition. Exemples: Buy my product !!!!!!!!!!!!!!!!!!!!!!!! Buy my product !? !? !? !? !? !? Buy my product !!!!!!!!!.......!!!!!!!! Buy my product <----------- Some acceptable solution would be to reduce the repetition of non-alphanum to 2. So I would get: Buy my product !! Buy my product !? !? Buy my product !!..!! Buy my product <-- This solution did not work that well: preg_replace('/(\W{2,})(?=\1+)/', '', $title) Any idea how to do it in PHP with regex? Other better solution is also welcomed (I cannot strip all the non-alphanum characters as they can make sense). Edit: the objective is only to avoid most common issues. The other creative cases will be sanitized manually or sanitized with an other regex.

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  • How do I match complete XML objects in a string?

    - by cyclotis04
    I'm attempting to find complete XML objects in a string. They have been placed in the string by an XmlSerializer, but may or may not be complete. I've toyed with the idea of using a regular expression, because it seems like the kind of thing they were built for, except for the fact that I'm trying to parse XML. I'm trying to find complete objects in the form: <?xml version="1.0"?> <type> <field>value</field> ... </type> My thought was a regex to find <?xml version="1.0"?><type> and </type>, but if a field has the same name as type, it obviously won't work. There's plenty of documentation on XML parsers, but they seem to all need a complete, fully-formed document to parse. My XML objects can be in a string surrounded by pretty much anything else (including other complete objects). hw<e>reR@lot$0fr@ndm&nchrs%<?xml version="1.0"?><type><field>...</field>...</type>@ndH#r$omOre!!>nuT6erjc?y!<?xml version="1.0"?><type><field>...</field>...</type>ty!=] A regex would be able to match a string while excluding the random characters, but not find a complete XML object. I'd like some way to extract an object, parse it with a serializer, then repeat until the string contains no more valid objects.

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  • Why can't I use accented characters next to a word boundary?

    - by Rexxars
    I'm trying to make a dynamic regex that matches a persons name. It works without problems on most names, until I ran into accented characters at the end of the name. Example: Some Fancy Namé The regex I've used so far is: /\b(Fancy Namé|Namé)\b/i Used like this: "Goal: Some Fancy Namé. Awesome.".replace(/\b(Fancy Namé|Namé)\b/i, '<a href="#">$1</a>'); This simply won't match. If I replace the é with a e, it matches just fine. If I try to match a name such as "Some Fancy Naméa", it works just fine. If I remove the word last word boundary anchor, it works just fine. Why doesn't the word boundary flag work here? Any suggestions on how I would get around this problem? I have concidered using something like this, but I'm not sure what the performance penalties would be like: "Some fancy namé. Allow me to ellaborate.".replace(/([\s.,!?])(fancy namé|namé)([\s.,!?]|$)/g, '$1<a href="#">$2</a>$3') Suggestions? Ideas?

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  • Javascript BBCode Parser recognizes only first list element

    - by nolandark
    I have a really simple Javascript BBCode Parser for client-side live preview (don't want to use Ajax for that). The problem ist, this parser only recognizes the first list element: function bbcode_parser(str) { search = new Array( /\[b\](.*?)\[\/b\]/, /\[i\](.*?)\[\/i\]/, /\[img\](.*?)\[\/img\]/, /\[url\="?(.*?)"?\](.*?)\[\/url\]/, /\[quote](.*?)\[\/quote\]/, /\[list\=(.*?)\](.*?)\[\/list\]/i, /\[list\]([\s\S]*?)\[\/list\]/i, /\[\*\]\s?(.*?)\n/); replace = new Array( "<strong>$1</strong>", "<em>$1</em>", "<img src=\"$1\" alt=\"An image\">", "<a href=\"$1\">$2</a>", "<blockquote>$1</blockquote>", "<ol>$2</ol>", "<ul>$1</ul>", "<li>$1</li>"); for (i = 0; i < search.length; i++) { str = str.replace(search[i], replace[i]); } return str;} [list] [*] adfasdfdf [*] asdfadsf [*] asdfadss [/list] only the first element is converted to a HTML List element, the rest stays as BBCode: adfasdfdf [*] asdfadsf [*] asdfadss I tried playing around with "\s", "\S" and "\n" but I'm mostly used to PHP Regex and totally new to Javascript Regex. Any suggestions?

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  • Merging two Regular Expressions to Truncate Words in Strings

    - by Alix Axel
    I'm trying to come up with the following function that truncates string to whole words (if possible, otherwise it should truncate to chars): function Text_Truncate($string, $limit, $more = '...') { $string = trim(html_entity_decode($string, ENT_QUOTES, 'UTF-8')); if (strlen(utf8_decode($string)) > $limit) { $string = preg_replace('~^(.{1,' . intval($limit) . '})(?:\s.*|$)~su', '$1', $string); if (strlen(utf8_decode($string)) > $limit) { $string = preg_replace('~^(.{' . intval($limit) . '}).*~su', '$1', $string); } $string .= $more; } return trim(htmlentities($string, ENT_QUOTES, 'UTF-8', true)); } Here are some tests: // Iñtërnâtiônàlizætiøn and then the quick brown fox... (49 + 3 chars) echo dyd_Text_Truncate('Iñtërnâtiônàlizætiøn and then the quick brown fox jumped overly the lazy dog and one day the lazy dog humped the poor fox down until she died.', 50, '...'); // Iñtërnâtiônàlizætiøn_and_then_the_quick_brown_fox_... (50 + 3 chars) echo dyd_Text_Truncate('Iñtërnâtiônàlizætiøn_and_then_the_quick_brown_fox_jumped_overly_the_lazy_dog and one day the lazy dog humped the poor fox down until she died.', 50, '...'); They both work as it is, however if I drop the second preg_replace() I get the following: Iñtërnâtiônàlizætiøn_and_then_the_quick_brown_fox_jumped_overly_the_lazy_dog and one day the lazy dog humped the poor fox down until she died.... I can't use substr() because it only works on byte level and I don't have access to mb_substr() ATM, I've made several attempts to join the second regex with the first one but without success. Please help S.M.S., I've been struggling with this for almost an hour. EDIT: I'm sorry, I've been awake for 40 hours and I shamelessly missed this: $string = preg_replace('~^(.{1,' . intval($limit) . '})(?:\s.*|$)?~su', '$1', $string); Still, if someone has a more optimized regex (or one that ignores the trailing space) please share: "Iñtërnâtiônàlizætiøn and then " "Iñtërnâtiônàlizætiøn_and_then_" EDIT 2: I still can't get rid of the trailing whitespace, can someone help me out?

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  • preg_match_all and newlines inside quotes

    - by David
    Another noob regex problem/question. I'm probably doing something silly so I thought I'd exploit the general ingenuity of the SO regulars ;) Trying to match newlines but only if they occur within either double quotes or single quotes. I also want to catch strings that are between quotes but contain no newlines. Okay so there's what i got, with output. Below that, will be the output I would like to get. Any help would be greatly appreciated! :) I use Regex Coach to help me create my patterns, being a novice and all. According to RC, The pattern I supply does match all occurances within the data, but in my PHP, it skips over the multi-line part. I have tried with the 'm' pattern modifier already, to no avail. Contents of $CompressedData: <?php $Var = "test"; $Var2 = "test2"; $Var3 = "blah blah blah blah blah blah blah blah blah"; $Var4 = "hello"; ?> Pattern / Code: preg_match_all('!(\'|")(\b.*\b\n*)*(\'|")!', $CompressedData, $Matches); Current print_r output of $Matches: Array ( [0] => Array ( [0] => "test" [1] => "test2" [2] => "hello" ) ... } DESIRED print_r output of $Matches: Array ( [0] => Array ( [0] => "test" [1] => "test2" [2] => "blah blah blah blah blah blah blah blah blah" [3] => "hello" ) ... }

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  • Extracting email addresses in an html block in ruby/rails

    - by corroded
    I am creating a parser that wards off against spamming and harvesting of emails from a block of text that comes from tinyMCE (so it may or may not have html tags in it) I've tried regexes and so far this has been successful: /\b[A-Z0-9._%+-]+@[A-Z0-9.-]+\.[A-Z]{2,4}\b/i problem is, i need to ignore all email addresses with mailto hrefs. for example: <a href="mailto:[email protected]">[email protected]</a> should only return the second email add. To get a background of what im doing, im reversing the email addresses in a block so the above example would look like this: <a href="mailto:[email protected]">moc.liam@tset</a> problem with my current regex is that it also replaces the one in href. Is there a way for me to do this with a single regex? Or do i have to check for one then the other? Is there a way for me to do this just by using gsub or do I have to use some nokogiri/hpricot magicks and whatnot to parse the mailtos? Thanks in advance! Here were my references btw: so.com/questions/504860/extract-email-addresses-from-a-block-of-text so.com/questions/1376149/regexp-for-extracting-a-mailto-address im also testing using this: http://rubular.com/ edit here's my current helper code: def email_obfuscator(text) text.gsub(/\b[A-Z0-9._%+-]+@[A-Z0-9.-]+\.[A-Z]{2,4}\b/i) { |m| m = "<span class='anti-spam'>#{m.reverse}</span>" } end which results in this: <a target="_self" href="mailto:<span class='anti-spam'>moc.liamg@tset</span>"><span class="anti-spam">moc.liamg@tset</span></a>

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  • Need variable width negative lookbehind replacement

    - by Technoh
    I have looked at many questions here (and many more websites) and some provided hints but none gave me a definitive answer. I know regular expressions but I am far from being a guru. This particular question deals with regex in PHP. I need to locate words in a text that are not surrounded by a hyperlink of a given class. For example, I might have This <a href="blabblah" class="no_check">elephant</a> is green and this elephant is blue while this <a href="blahblah">elephant</a> is red. I would need to match against the second and third elephants but not the first (identified by test class "no_check"). Note that there could more attributes than just href and class within hyperlinks. I came up with ((?<!<a .*class="no_check".*>)\belephant\b) which works beautifully in regex test software but not in PHP. Any help is greatly appreciated. If you cannot provide a regular expression but can find some sort of PHP code logic that would circumvent the need for it, I would be equally grateful.

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  • Extracting one word based on special character using Regular Expression in C#

    - by Jankhana
    I am not very good at regular expression but want to do some thing like this : string="c test123 d split" I want to split the word based on "c" and "d". this can be any word which i already have. The string will be given by the user. i want "test123" and "split" as my output. and there can be any number of words i.e "c test123 d split e new" etc. c d e i have already with me. I want just the next word after that word i.e after c i have test123 and after d i have split and after e i have new so i need test123 and split and new. how can I do this??? And one more thing I will pass just c first than d and than e. not together all of them. I tried string strSearchWord="c "; Regex testRegex1 = new Regex(strSearchWord); List lstValues = testRegex1.Split("c test123 d split").ToList(); But it's working only for last character i.e for d it's giving the last word but for c it includes test123 d split. How shall I do this???

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  • Regular expression either/or not matching everything

    - by dwatransit
    I'm trying to parse an HTTP GET request to determine if the url contains any of a number of file types. If it does, I want to capture the entire request. There is something I don't understand about ORing. The following regular expression only captures part of it, and only if .flv is the first int the list of ORd values. (I've obscured the urls with spaces because Stackoverflow limits hyperlinks) regex: GET.?(.flv)|(.mp4)|(.avi).? test text: GET http: // foo.server.com/download/0/37/3000016511/.flv?mt=video/xy match output: GET http: // foo.server.com/download/0/37/3000016511/.flv I don't understand why the .*? at the end of the regex isnt callowing it to capture the entire text. If I get rid of the ORing of file types, then it works. Here is the test code in case my explanation doesn't make sense: public static void main(String[] args) { // TODO Auto-generated method stub String sourcestring = "GET http: // foo.server.com/download/0/37/3000016511/.flv?mt=video/xy"; Pattern re = Pattern.compile("GET .?\.flv."); // this works //output: // [0][0] = GET http :// foo.server.com/download/0/37/3000016511/.flv?mt=video/xy // the match from the following ends with the ".flv", not the entire url. // also it only works if .flv is the first of the 3 ORd options //Pattern re = Pattern.compile("GET .?(\.flv)|(\.mp4)|(\.avi).?"); // output: //[0][0] = GET http: // foo.server.com/download/0/37/3000016511/.flv // [0][1] = .flv // [0][2] = null // [0][3] = null Matcher m = re.matcher(sourcestring); int mIdx = 0; while (m.find()){ for( int groupIdx = 0; groupIdx < m.groupCount()+1; groupIdx++ ){ System.out.println( "[" + mIdx + "][" + groupIdx + "] = " + m.group(groupIdx)); } mIdx++; } } }

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  • How to delete sentences starting with a lower case letter?

    - by Ron
    Hello: In the example below the following regex (".*?") was used to remove all dialogue first. The next step is to remove all remaining sentences starting with a lower case letter. Only sentences starting with an upper case letter should remain. Example: exclaimed Wade. Indeed, below them were villages, of crude huts made of timber and stone and mud. Rubble work walls, for they needed little shelter here, and the people were but savages. asked Arcot, his voice a bit unsteady with suppressed excitement. replied Morey without turning from his station at the window. Below them now, less than half a mile down on the patchwork of the Nile valley, men were standing, staring up, collecting in little groups, gesticulating toward the strange thing that had materialized in the air above them. In the example above the following should be deleted only: exclaimed Wade. asked Arcot, his voice a bit unsteady with suppressed excitement. replied Morey without turning from his station at the window. A useful regex or simple Perl or python code is appreciated. I'm using version 7 of Textpipe. Thanks.

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  • Python Regular Expressions: Capture lookahead value (capturing text without consuming it)

    - by Lattyware
    I wish to use regular expressions to split words into groups of (vowels, not_vowels, more_vowels), using a marker to ensure every word begins and ends with a vowel. import re MARKER = "~" VOWELS = {"a", "e", "i", "o", "u", MARKER} word = "dog" if word[0] not in VOWELS: word = MARKER+word if word[-1] not in VOWELS: word += MARKER re.findall("([%]+)([^%]+)([%]+)".replace("%", "".join(VOWELS)), word) In this example we get: [('~', 'd', 'o')] The issue is that I wish the matches to overlap - the last set of vowels should become the first set of the next match. This appears possible with lookaheads, if we replace the regex as follows: re.findall("([%]+)([^%]+)(?=[%]+)".replace("%", "".join(VOWELS)), word) We get: [('~', 'd'), ('o', 'g')] Which means we are matching what I want. However, it now doesn't return the last set of vowels. The output I want is: [('~', 'd', 'o'), ('o', 'g', '~')] I feel this should be possible (if the regex can check for the second set of vowels, I see no reason it can't return them), but I can't find any way of doing it beyond the brute force method, looping through the results after I have them and appending the first character of the next match to the last match, and the last character of the string to the last match. Is there a better way in which I can do this? The two things that would work would be capturing the lookahead value, or not consuming the text on a match, while capturing the value - I can't find any way of doing either.

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  • Regular Expression Newbie

    - by Registered User
    I need to parse strings inputs where the columns are separated by columns and any field that contains a comma in the data is wrapped in quotes (commas separated, quoted text identifiers). For this project I need to remove the quotes and any commas that occur between pairs of quotes. Basically, I need to remove commas and quotes that are contained in fields while preserving the commas that are used to separate the fields. Here's a little code I put together that handles the simple scenario: // Sample input 1: This works and covers 99% of the records that I need to parse. string str1 = "[email protected],2010/03/27 12:2:02,,some_first_name,some_last_name,,\"This Address Works, Suite 200\",Some City,TN,09876-5432,9795551212x123,XYZ"; str1 = Regex.Replace(str1, "\"([^\"^,]*),([^\"^,]*)\"", "$1$2"); Console.WriteLine(str1); // Outputs: [email protected],2010/03/27 12:2:02,,some_first_name,some_last_name,,This Address Works Suite 200,Some City,TN,09876-5432,9795551212x123,XYZ Although this code works for most of my records, it doesn't work when a field contains more than one commas. What I would like to do is modify the code so that it remove each instance of a comma contained within the column no matter how many commas there are in the field. I don't want to hard code only handling 2 commas, or 3 commas, or 25 commas. The code should just remove all the commas in the field. Below is an example of what my code doesn't handle properly. // Sample input 2: This doesn't work since there is more than 1 comma between the quotes. string str2 = "[email protected],2010/03/27 12:2:02,,some_first_name,some_last_name,,\"i,l,k,e, c,o,m,m,a,s, i,n ,m,y, f,i,e,l,d\",Some City,TN,09876-5432,9795551212x123,XYZ"; str2 = Regex.Replace(str2, "\"([^\"^,]*),([^\"^,]*)\"", "$1$2"); Console.WriteLine(str2); // Desired output: [email protected],2010/03/27 12:2:02,,some_first_name,some_last_name,,i like commas in my field,Some City,TN,09876-5432,9795551212x123,XYZ Any help would be appreciated for this Regular Expression newbie.

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  • Regular expression for finding non-breaking string names in code and then breaking them up for SQL q

    - by Rob Segal
    I am trying to devlop a regex for finding camel case strings in several code files I am working with so I can break them up into separate words for use in a SQL query. I have strings of the form... EmailAddress FirstName MyNameIs And I want them like this... Email Address First Name My Name Is An example SQL query which I currently have is... select FirstName, MyNameIs from MyTables I need the queries in the form... select FirstName as 'First Name', MyNameIs as 'My Name Is' from MyTables Any time a new capital letter appears that should be a new grouping which I can pick out of the matched string. I currently have the following regex... ([A-Z][a-z]+)+ Which does match the cases I have shown above but when I want to perform a replace I need to define groups. Currently I have tried... (([A-Z])([a-z]+))+ Which sort of works. It will pick out "Address" as the first grouping from "EmailAddress" as opposed to "Email" which is what I was expecting. No doubt there is something I'm misunderstanding here so any help is greatly appreciated.

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  • Detect remote charset in php

    - by yallaa
    Hello, I would like to determine a remote page's encoding through detection of the Content-Type header tag <meta http-equiv="Content-Type" content="text/html; charset=XXXXX" /> if present. I retrieve the remote page and try to do a regex to find the required setting if present. I am still learning hence the problem below... Here is what I have: $EncStart = 'charset='; $EncEnd = '" \/\>'; preg_match( "/$EncStart(.*)$EncEnd/s", $RemoteContent, $RemoteEncoding ); echo = $RemoteEncoding[ 1 ]; The above does indeed echo the name of the encoding but it does not know where to stop so it prints out the rest of the line then most of the rest of the remote page in my test. Example: When testing a remote russian page it printed: windows-1251" / rest of page .... Which means that $EncStart was okay, but the $EncEnd part of the regex failed to stop the matching. This meta header usually ends in 3 different possibility after the name of the encoding. "> | "/> | " /> I do not know weather this is usable to satisfy the end of the maching and if yes how to escape it. I played with different ways of doing it but none worked. Thank you in advance for lending a hand.

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  • C# Regex - Match and replace, Auto Increment

    - by Marc Still
    I have been toiling with a problem and any help would be appreciated. Problem: I have a paragraph and I want to replace a variable which appears several times (Variable = @Variable). This is the easy part, but the portion which I am having difficulty is trying to replace the variable with different values. I need for each occurrence to have a different value. For instance, I have a function that does a calculation for each variable. What I have thus far is below: private string SetVariables(string input, string pattern){ Regex rx = new Regex(pattern); MatchCollection matches = rx.Matches(input); int i = 1; if(matches.Count > 0) { foreach(Match match in matches) { rx.Replace(match.ToString(), getReplacementNumber(i)); i++ } } I am able to replace each variable that I need to with the number returned from getReplacementNumber(i) function, but how to I put it back into my original input with the replaced values, in the same order found in the match collection? Thanks in advance! Marcus

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  • removing phone number from a document.

    - by Grant Collins
    Hi, I've got a challenge that I am hoping that the SO community is able to help me with. I trying to parse a lot of html documents in my PHP application to remove personal details, such as names, addresses and phone numbers. I can remove most of these details without too much trouble, however the phone number is a real problem for me. My idea is to take the text from these documents and the use a regex to identify the phone numbers and replace them with another value such as 'xxxx'. I've got 2 regex that I am using one for UK landline numbers and one for UK cell/mobile numbers. However when I try and run them against the text it just returns an empty string. I am using the following preg_replace code: $pattens = array( '/^(((\+44\s?\d{4}|\(?0\d{4}\)?)\s?\d{3}\s?\d{3})|((\+44\s?\d{3}|\(?0\d{3}\)?)\s?\d{3}\s?\d{4})|((\+44\s?\d{2}|\(?0\d{2}\)?)\s?\d{4}\s?\d{4}))(\s?\#(\d{4}|\d{3}))?$/', '/^(\+44\s?7\d{3}|\(?07\d{3}\)?)\s?\d{3}\s?\d{3}$/' ); $replace = array('xxxxx', 'xxxxx'); //do the search for the numbers. $updatedContents = preg_replace($pattens, $replace, $htmlContents); At the moment this is causing me a lot of head scratching as I thought that I had this nailed, but at the moment I can't see what's wrong?? I am sure that it is something really simple. Thanks, Grant

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  • AWK: compare apache dates without using regular expression

    - by smallmeans
    I'm writing a loganalysis application and wanted to grab apache log records between two certain dates. Assume that a date is formated as such: 22/Dec/2009:00:19 (day/month/year:hour:minute) Currently, I'm using a regular expression to replace the month name with its numeric value, remove the separators, so the above date is converted to: 221220090019 making a date comparison trivial.. but.. Running a regex on each record for large files, say, one containing a quarter million records, is extremely costly.. is there any other method not involving regex substitution? Thanks in advance Edit: here's the function doing the convertion/comparison function dateInRange(t, from, to) { sub(/[[]/, "", t); split(t, a, "[/:]"); match("JanFebMarAprMayJunJulAugSepOctNovDec", a[2]); a[2] = sprintf("%02d", (RSTART + 2) / 3); s = a[3] a[2] a[1] a[4] a[5]; return s >= from && s <= to; } "from" and "to" are the intervals in the aforementioned format, and "t" is the raw apache log date/time field (e.g [22/Dec/2009:00:19:36)

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  • Regular expression test can't decide between true and false (JavaScript)

    - by nw
    I get this behavior in both Chrome (Developer Tools) and Firefox (Firebug). Note the regex test returns alternating true/false values: > var re = /.*?\bbl.*\bgr.*/gi; undefined > re /.*?\\bbl.*\\bgr.*/gi > re.test("Blue-Green"); true > re.test("Blue-Green"); false > re.test("Blue-Green"); true > re.test("Blue-Green"); false However, testing the same regex as a literal: > /.*?\bbl.*\bgr.*/gi.test("Blue-Green"); true > /.*?\bbl.*\bgr.*/gi.test("Blue-Green"); true > /.*?\bbl.*\bgr.*/gi.test("Blue-Green"); true > /.*?\bbl.*\bgr.*/gi.test("Blue-Green"); true I can't explain this and it's making debugging very difficult. Can anyone explain this behavior?

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