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  • Pagination on blog content type in eZ Publish

    - by foosadi
    Hi, Im not sure if I have missed anything but I am trying to achieve pagination on blog posts within my blog. Is there a setting somewhere to show a certain number of blog posts per page by default? Or am I going to need to add that functionallity myself? Thanks.

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  • Doctrine: Unable to execute either CROSS JOIN or SELECT FROM Table1, Table2?

    - by ropstah
    Using Doctrine I'm trying to execute either a 1. CROSS JOIN statement or 2. a SELECT FROM Table1, Table2 statement. Both seem to fail. The CROSS JOIN does execute, however the results are just wrong compared to executing in Navicat. The multiple table SELECT doesn't event execute because Doctrine automatically tries to LEFT JOIN the second table. The cross join statement (this runs, however it doesn't include the joined records where the refClass User_Setting doesn't have a value): $q = new Doctrine_RawSql(); $q->select('{s.*}, {us.*}') ->from('User u CROSS JOIN Setting s LEFT JOIN User_Setting us ON us.usr_auto_key = u.usr_auto_key AND us.set_auto_key = s.set_auto_key') ->addComponent('u', 'User u') ->addComponent('s', 'Setting s') ->addComponent('us', 'u.User_Setting us') ->where('s.sct_auto_key = ? AND u.usr_auto_key = ?',array(1, $this->usr_auto_key)); And the select from multiple tables (this doesn't event run. It does not spot the many-many relationship between User and Setting in the first ->from() part and throws an exception: "User_Setting" with an alias of "us" in your query does not reference the parent component it is related to.): $q = new Doctrine_RawSql(); $q->select('{s.*}, {us.*}') ->from('User u, Setting s LEFT JOIN User_Setting us ON us.usr_auto_key = u.usr_auto_key AND us.set_auto_key = s.set_auto_key') ->addComponent('u', 'User u') ->addComponent('s', 'Setting s') ->addComponent('us', 'u.User_Setting us') ->where('s.sct_auto_key = ? AND u.usr_auto_key = ?',array(1, $this->usr_auto_key));

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  • Bringing specific results to the front using one MySQL query.

    - by animuson
    I'm setting up my geolocation feature which lists out all the countries in order of name. However, most websites have it set up where the popular countries (such as United States, United Kingdom, Canada, Australia) are at the front of the list (are shown first rather than in their assigned places). Is it possible to achieve this using the same MySQL query that I am already running to select them? SELECT * FROM `global_flags` ORDER BY `country` Is there a better alternative somewhere? Perhaps something that can reorganize the results after the database has already been queried? I don't want to exclude those results and then manually type them at the beginning because that would waste more space in the file.

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  • Function to even out multiple arrays

    - by Moak
    Assume I have a function evenOut($array, $limit){ //returns exactly $limit items } and this data $animals = array(); $animals['barn'] = array_fill(0,20, 'b'); $animals['forest'] = array_fill(0,20, 'f'); $animals['house'] = array_fill(0,20, 'h'); $animals['mountain'] = array_fill(0,20, 'm'); I want to return a maximum of 10 animals, however they should be spread out evenly among the locations they come from. so if i did evenOut($animals,8); i'd get 2 of each('b','b','f','f','h','h','m','m',) evenOut($animals,2); should return ('b','f') if I have this data $animals = array(); $animals['barn'] = array_fill(0,1, 'b'); $animals['forest'] = array_fill(0,3, 'f'); $animals['house'] = array_fill(0,8, 'h'); $animals['mountain'] = array_fill(0,1, 'm'); evenOut($animals,8); expected result would be ('b','f','f','f','h','h','h','m',) evenOut($animals,10); expected result would be ('b','f','f','f','h','h','h','h','h','m',) $animals = array(); $animals['barn'] = array_fill(0,0, 'b'); $animals['forest'] = array_fill(0,3, 'f'); evenOut($animals,10); expected result would be ('f','f','f') I'm not sure how I should approach this, I am hoping there is a simple way

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  • preg_replace - don't include string if $4 is blank

    - by bradenkeith
    I have this expression: $regex_phone = '/^(?:1(?:[. -])?)?(?:\((?=\d{3}\)))?([2-9]\d{2})' .'(?:(?<=\(\d{3})\))? ?(?:(?<=\d{3})[.-])?([2-9]\d{2})' .'[. -]?(\d{4})(?: (?i:ext)\.? ?(\d{1,5}))?$/'; if(!preg_match($regex_phone, $data['phone'])){ $error[] = "Please enter a valid phone number."; }else{ $data['phone'] = preg_replace($regex_phone, '($1) $2-$3 ext.$4', $data['phone']); } That will take a phone number such as: 803-888-8888 ext 2 as well as 803-888-8888 First number formats as: (803) 888-8888 ext.2 -- the desired effect Second number formats as: (803) 888-8888 ext. -- blank extension How can I set it so that if $4 is blank, that ext. won't show? Thanks so much for any help you can offer. I hope this was clear.

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  • Turn database result into array

    - by Industrial
    Hi everyone, I have just made the update/add/delete part for the "Closure table" way of organizing query hierarchical data that are shown on page 70 in this slideshare: http://www.slideshare.net/billkarwin/sql-antipatterns-strike-back My database looks like this: Table Categories: ID Name 1 Top value 2 Sub value1 Table CategoryTree: child parent 1 1 2 2 2 1 However, I have a bit of an issue getting the full tree back as an multidimensional array from a single query. Here's what I would like to get back: array ( 'topvalue' = array ( 'Subvalue', 'Subvalue2', 'Subvalue3' = array ('Subvalue 1', 'Subvalue 2', 'Subvalue 3' ) ); ); Update: Found this link, but I still have a hard time to convert it into an array: http://karwin.blogspot.com/2010/03/rendering-trees-with-closure-tables.html

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  • WHERE id IN doesn't work in UPDATE

    - by Donator
    UPDATE statistics' SET money = money + '$money' WHERE member_id IN ((SELECT member_id FROM races WHERE l_id = '$mem_id'), $other_id) What's wrong with that? I want to retrieve all member_ids from races and also include to member_id $other_id. Without $other_id it works. By the way, it gives me "Subquery returns more than 1 row" error.

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  • mail function not working for yahoo mail id

    - by Akash
    Hello all, I have written a code to send mail on yahoo or gmail.Mail is sending on gmail but i m not seeing any message in yahoo mail. And in gmail i m seeing all html content with message. here is my code... $headers = "From: \"".$from_name."\" <".$from_email.">\n"; $headers .= "To: \"".$to_name."\" <".$to_email.">\n"; $headers .= "Return-Path: <".$from_email.">\n"; $headers .= "MIME-Version: 1.0\n"; $headers .= "Content-Type: text/HTML; charset=ISO-8859-1\n"; // message $message = ' <html> <head> <title>Registration</title> </head> <body> <table><tr> <td> <a href="#'> Click Here To Activate Your account</a> Thanks To visit site.com </td> </tr> </table> </body> </html>'; if(mail('', $subject, $message, $headers)) echo "successfully register !! please check your mail and clik on confirmation link";

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  • git submodule svn external

    - by Jason
    Let's say I have 3 git repositories, each with a lib and tests folder in the root. All 3 repositories are part of what I want to be a single package, however it is important to me to keep the repositories separate. I am new to git coming from svn, so I have been reading up on submodules and how they differ from svn:externals. In SVN I could have a single lib/vendor/package directory, and inside package I could setup 3 externals pointing to each of my 3 repositories lib directory, renaming it appropriately like lib/vendor/package/a -> repo1/lib lib/vendor/package/b -> repo2/lib lib/vendor/package/c -> repo3/lib but from my understanding this is not possible with git. Am I missing something? Really I'm hoping this can be solved in one of two ways. Someone will point out how to create a 4th git repository which has the other 3 as submodules organized as I have mentioned above (where I can have an a, b, and c folder inside the root) Someone will point out how to set this up using svn:externals in combination with githubs svn support, referencing the lib directory within each git repository (from my understanding this is impossible)

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  • trying to put an mysql result into a string

    - by user1583432
    I'm trying to put an mysql query result into an string I tried to find an answer but all the similar posts were getting subquery answers which is not what I'm trying to do. for example Fruits_tbl ID Fruit Color Number __________________________________ 2 Apple Red 5 $sql = "select Fruits,Color,Number from Fruits_tbl where ID = 2"; $result = $pdo->query($sql); $row = $result->fetch(); print_r($row); This will give me something like Array([0]="Apple", [1]="Red", [2]="5", [Fruit]="Apple", [Color]="Red", [Number]="5") implode will give me 2 of each I want just need a string = "Apple, Red, 5" what I currently have is $string = $row[Fruit].", ".$row[Color].", ".$row['Number'] As you can see that's rather tedious. Is there something like implode but only return the index array or something?

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  • Zend_Services_Twitter, change the API Source name

    - by favo
    Hi, I am sending tweets to Twitter via Zend_Service_Twitter. The tweets appear with a note "via API". I want to set the API Source with a different name, is there already a functionality within the Zend Framework to change it? Or do I need to subclass to get this functionality? Thanks!

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  • Force reload/refresh when pressing the back button

    - by FlyingCat
    I will try my best to explain this. I have an application that show the 50+ projects in my view page. The user can click the individual project and go to the update page to update the project information. Everything works fine except that after user finish updating the individual project information and hit 'back' button on the browser to the previous view page. The old project information (before update) is still there. The user has to hit refresh to see the updated information. It not that bad, but I wish to provide better user experience. Any idea to fix this? Thanks a lot.

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  • When Web page is displayed in a div, Error: Unable to modify the parent container element before the

    - by Jean
    Hello, A url is being displayed in a div as shown below <div id="ipage"> <? $url = "http://www.yahoo.com"; $file1 = fopen($url, "r"); $content = file_get_contents($url); echo $content; ?> </div> And I receive this error Webpage error details Message: HTML Parsing Error: Unable to modify the parent container element before the child element is closed (KB927917) Bright idea to solve this. Thanks Jean

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  • Array to Array pushing in Zend Session object

    - by kate-koopy
    Hello! I have some example of pushing array to array in session object: class someClass extends someOtherOne { ...////// some other code here that starts session and creates namespace public function __add2Session($a,$b) { $namespc = $this -> __getnewNameSpace(); //returns a Zend Session Namesapce (object) if (!isset($namespc -> {$a})) { $namespc -> {$a} = array(); } array_push($namespc -> {$a}, $b); } } ...///////////// $item=array(1=>"one",2=>"two",3=>"three",4=>"four",5=>"five",6=>"six",7=>"seven"); $k = new someClass(); $cart = new Zend_Session_Namespace('Cart'); $k -> __add2Session("items",$item); The result is when I reload the page several times - the value of $cart -> items in the session gets overwritten and not populated. Can somebody explain why it occurs and how do I fix this? I want to have $cart -> items to be an "array in array" like: $cart -> items = array(array(1=>"one",2=>"two"), array(1=>"two",2=>"three"));

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  • Which cms or script for social network wiki?

    - by Jason
    Hi, I am building a social network. I need a cms that will allow users to contribute content. Each content item will need to have a google map, list of features, ratings, comments, etc. And the content must be editable by other users with revision control. Also, each user should have a profile with their bookmarked content items, contributed items, comments, etc. It's very important that I can create a template for the wiki/content entries so that each item looks uniform. (and as a kick in the teeth, I would like to be able to search for wiki items using a radial search or map) Joomla was my first choice, as I've used it for many projects, but the wiki functionality is not there. I was also setting up a grou.ps site, but the wiki is so-so - not feature rich and it really doesn't have the option I need. Additionally, I know someone out there will mention Drupal. I may consider it if I can see it put to use without and overabundance of custom programming (I don't mind initial coding, but drupal requires constant coding & recoding - with this site, I dont' have that time commitment) I thought about using mediawiki with buddypress, but i'm not sure if that's the way to go. Thoughts?

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  • How to kill locked mysql queries

    - by jcure
    Hi, I am creating and testing a mysql join query but each time so far it causes the database tables to lockup and the site hangs. I have to then call the host and they kill the locked queries. Is this something I can do from phpmyadmin so not to bother them while I tweak the script to work? Thanks for any reply.

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  • Nested Array with one foreach Loop?

    - by streetparade
    I need to have access to a array which looks like this. Array ( [0] => Array ( [54] => Array ( [test] => 54 [tester] => result ) ) ) foreach($array as $key=>$value) { echo $key;// prints 0 echo $value;// prints Array /* now i can iterate through $value but i dont want it solve that way example: foreach($value as $k=>$v) { echo $k;//prints test echo $v; //prints 54 } */ } How can iterate just once ? to get the values of test and tester? I hope i could explain my problem clear

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  • select command in mysql doesnot return any row

    - by jeyshree
    i created a database using the command CREATE TABLE login_table2(user_name VARCHAR(32), first_name VARCHAR(32), last_name VARCHAR(32), password VARCHAR(64)); then i inserted a data using command INSERT INTO login_table2(user_name ,first_name , last_name , password ) VALUES('ramya', 'ramya', 'muthu', 'India'); the data got inserted into the table. then i inserted another set of data using command INSERT INTO login_table2(user_name ,first_name , last_name , password ) VALUES('jeyshree', 'jey', 'shree', 'India'); the data got inserted into the table too. then i gave the command SELECT first_name FROM login_table2; the command displayed all the first_ name in the table. however when i gave the command SELECT password FROM login_table2 WHERE user_name = 'ramya'; it does not fetch anything though the entry exist in the table.mention where i am going wrong.awaiting your reply.

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  • Wordpress Search Results in Order

    - by Brad Houston
    One of my clients websites, www.kevinsplants.co.uk is not showing the search results in alphabetical order, how do I go about ordering the results in alphabetical order? We are using the Shopp plugin and I believe its that plugin that is generating the results! Cheers, Brad case "orderby-list": if (isset($Shopp->Category->controls)) return false; if (isset($Shopp->Category->smart)) return false; $menuoptions = Category::sortoptions(); $title = ""; $string = ""; $default = $Shopp->Settings->get('default_product_order'); if (empty($default)) $default = "title"; if (isset($options['default'])) $default = $options['default']; if (isset($options['title'])) $title = $options['title']; if (value_is_true($options['dropdown'])) { if (isset($Shopp->Cart->data->Category['orderby'])) $default = $Shopp->Cart->data->Category['orderby']; $string .= $title; $string .= '<form action="'.esc_url($_SERVER['REQUEST_URI']).'" method="get" id="shopp-'.$Shopp->Category->slug.'-orderby-menu">'; if (!SHOPP_PERMALINKS) { foreach ($_GET as $key => $value) if ($key != 'shopp_orderby') $string .= '<input type="hidden" name="'.$key.'" value="'.$value.'" />'; } $string .= '<select name="shopp_orderby" class="shopp-orderby-menu">'; $string .= menuoptions($menuoptions,$default,true); $string .= '</select>'; $string .= '</form>'; $string .= '<script type="text/javascript">'; $string .= "jQuery('#shopp-".$Shopp->Category->slug."-orderby-menu select.shopp-orderby-menu').change(function () { this.form.submit(); });"; $string .= '</script>'; } else { if (strpos($_SERVER['REQUEST_URI'],"?") !== false) list($link,$query) = explode("\?",$_SERVER['REQUEST_URI']); $query = $_GET; unset($query['shopp_orderby']); $query = http_build_query($query); if (!empty($query)) $query .= '&'; foreach($menuoptions as $value => $option) { $label = $option; $href = esc_url($link.'?'.$query.'shopp_orderby='.$value); $string .= '<li><a href="'.$href.'">'.$label.'</a></li>'; } } return $string; break;

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  • data from few MySQL tables sorted by ASC

    - by Andrew
    In the dbase I 've few tables named as aaa_9xxx, aaa_9yyy, aaa_9zzz. I want to find all data with a specified DATE and show it with the TIME ASC. First, I must find a tables in the dbase: $STH_1a = $DBH->query("SELECT table_name FROM information_schema.tables WHERE table_name LIKE 'aaa\_9%' "); foreach($STH_1a as $row) { $table_name_s1[] = $row['table_name']; } Second, I must find a data wit a concrete date and show it with TIME ASC: foreach($table_name_s1 as $table_name_1) { $STH_1a2 = $DBH->query("SELECT * FROM `$table_name_1` WHERE date = '2011-11-11' ORDER BY time ASC "); while ($row = $STH_1a2->fetch(PDO::FETCH_ASSOC)) { echo " ".$table_name_1."-".$row['time']."-".$row['ei_name']." <br>"; } } .. but it shows the data sorted by tables name, then by TIME ASC. I must to have all this data (from all tables) sorted by TIME ASC. Thank You dev-null-dweller, Andrew Stubbs and Jaison Erick for your help. I test the Erick solution : foreach($STH_1a as $row) { $stmts[] = sprintf('SELECT * FROM %s WHERE date="%s"', $row['table_name'], '2011-11-11'); } $stmt = implode("\nUNION\n", $stmts); $stmt .= "\nORDER BY time ASC"; $STH_1a2 = $DBH->query($stmt); while ($row_1a2 = $STH_1a2->fetch(PDO::FETCH_ASSOC)) { echo " ".$row['table_name']."-".$row_1a2['time']."-".$row_1a2['ei_name']." <br>"; } it's working but I've problem with 'table_name' - it's always the LAST table name. //---------------------------------------------------------------------- end the ending solution with all fixes, thanks all for your help, :)) foreach($STH_1a as $row) { $stmts[] = sprintf("SELECT *, '%s' AS table_name FROM %s WHERE date='%s'", $row['table_name'], $row['table_name'], '2011-11- 11'); } $stmt = implode("\nUNION\n", $stmts); $stmt .= "\nORDER BY time ASC"; $STH_1a2 = $DBH->query($stmt); while ($row_1a2 = $STH_1a2->fetch(PDO::FETCH_ASSOC)) { echo " ".$row_1a2['table_name']."-".$row_1a2['time']."-".$row_1a2['ei_name']." <br>"; }

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