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  • Should entry level programmers be able to answer FizzBuzz?

    - by Bryan Rowe
    When interviewing entry level developers, I have used the FizzBuzz question as a type of acid test. Generally, I ask for a solution in pseudo-code or any language of their choice. If someone can't answer this question -- or get reasonably close, the interview generally ends shortly thereafter and we don't progress to more interesting code questions. In your opinion, is it fair/appropriate/accurate to filter entry-level staff in this manner? Should the average four year college graduate have a reasonable enough foundation to be able to throw up a pseudo-code solution of FizzBuzz?

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  • What is the best answer to give for, "Why do you want to change from your present organization?"

    - by Techmaddy
    At present I am into a very good organization. I am planning to shift because I am not happy with the work that I am getting now. I want to work under a different Manager, but my Manager and team is more dependent on me. I tried so many times, but couldn't change my team. So, I started planning to switch my company. Everyone is asking the same question, "Why do you want to change?". Should I say the truth? I told this in 2 places, but did not see a good response from them. Or is there a better answer that I can give?

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  • Ruby Koans 202: Why does the correct answer give a syntax error?

    - by hlh
    I'm working through the about_classes.rb file in the Ruby Koans, and have hit a brick wall with the "inside_a_method_self_refers_to_the_containing_object" test. Here's the code: class Dog7 attr_reader :name def initialize(initial_name) @name = initial_name end def get_self self end def to_s __ end def inspect "<Dog named '#{name}'>" end end def test_inside_a_method_self_refers_to_the_containing_object fido = Dog7.new("Fido") fidos_self = fido.get_self assert_equal <Dog named 'Fido'>, fidos_self end So, I'm trying to make the first half of the assert_equal evaluate to the second half (fidos_self). When I work it out in irb, fidos_self returns <Dog named 'Fido'>, but I keep receiving a syntax error for that answer. I've seen this similar post: Ruby Koans: Where are the quotes in this return value?, but his solution (putting fido instead of <Dog named 'Fido'>) causes my rake to abort, saying the stack level is too deep. This is driving me nuts. What am I missing here?

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  • MySQL subquery and bracketing

    - by text
    Here are my tables respondents: field sample value respondentid : 1 age : 2 gender : male survey_questions: id : 1 question : Q1 answer : sample answer answers: respondentid : 1 question : Q1 answer : 1 --id of survey question I want to display all respondents who answered the certain survey, display all answers and total all the answer and group them according to the age bracket. I tried using this query: SELECT res.Age, res.Gender, answer.id, answer.respondentid, SUM(CASE WHEN res.Gender='Male' THEN 1 else 0 END) AS males, SUM(CASE WHEN res.Gender='Female' THEN 1 else 0 END) AS females, CASE WHEN res.Age < 1 THEN 'age1' WHEN res.Age BETWEEN 1 AND 4 THEN 'age2' WHEN res.Age BETWEEN 4 AND 9 THEN 'age3' WHEN res.Age BETWEEN 10 AND 14 THEN 'age4' WHEN res.Age BETWEEN 15 AND 19 THEN 'age5' WHEN res.Age BETWEEN 20 AND 29 THEN 'age6' WHEN res.Age BETWEEN 30 AND 39 THEN 'age7' WHEN res.Age BETWEEN 40 AND 49 THEN 'age8' ELSE 'age9' END AS ageband FROM Respondents AS res INNER JOIN Answers as answer ON answer.respondentid=res.respondentid INNER JOIN Questions as question ON answer.Answer=question.id WHERE answer.Question='Q1' GROUP BY ageband ORDER BY res.Age ASC I was able to get the data but the listing of all answers are not present. Do I have to subquery SELECT into my current SELECT statement to show the answers? I want to produce something like this: ex: # of Respondents is 3 ages: 2,3 and 6 Question: what are your favorite subjects? Ages 1-4: subject 1: 1 subject 2: 2 subject 3: 2 total respondents for ages 1-4 : 2 Ages 5-10: subject 1: 1 subject 2: 1 subject 3: 0 total respondents for ages 5-10 : 1

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  • How grouping and totaling are done into three tables using JOIN

    - by text
    Here are my tables respondents: field sample value respondentid : 1 age : 2 gender : male survey_questions: id : 1 question : Q1 answer : sample answer answers: respondentid : 1 question : Q1 answer : 1 --id of survey question I want to display all respondents who answered the certain survey, display all answers and total all the answer and group them according to the age bracket. I tried using this query: $sql = "SELECT res.Age, res.Gender, answer.id, answer.respondentid, SUM(CASE WHEN res.Gender='Male' THEN 1 else 0 END) AS males, SUM(CASE WHEN res.Gender='Female' THEN 1 else 0 END) AS females, CASE WHEN res.Age < 1 THEN 'age1' WHEN res.Age BETWEEN 1 AND 4 THEN 'age2' WHEN res.Age BETWEEN 4 AND 9 THEN 'age3' WHEN res.Age BETWEEN 10 AND 14 THEN 'age4' WHEN res.Age BETWEEN 15 AND 19 THEN 'age5' WHEN res.Age BETWEEN 20 AND 29 THEN 'age6' WHEN res.Age BETWEEN 30 AND 39 THEN 'age7' WHEN res.Age BETWEEN 40 AND 49 THEN 'age8' ELSE 'age9' END AS ageband FROM Respondents AS res INNER JOIN Answers as answer ON answer.respondentid=res.respondentid INNER JOIN Questions as question ON answer.Answer=question.id WHERE answer.Question='Q1' GROUP BY ageband ORDER BY res.Age ASC"; I was able to get the data but the listing of all answers are not present. What's wrong with my query. I want to produce something like this: ex: # of Respondents is 3 ages: 2,3 and 6 Question: what are your favorite subjects? Ages 1-4: subject 1: 1 subject 2: 2 subject 3: 2 total respondents for ages 1-4 : 2 Ages 5-10: subject 1: 1 subject 2: 1 subject 3: 0 total respondents for ages 5-10 : 1

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  • SQL SERVER – Monday Morning Puzzle – Query Returns Results Sometimes but Not Always

    - by pinaldave
    The amount of email I receive sometime it is impossible for me to answer every email. Nonetheless I try to answer pretty much every email I receive. However, quite often I receive such questions in email that I have no answer to them because either emails are not complete or they are out of my domain expertise. In recent times I received one email which had only one or two lines but indeed attracted my attention to it. The question was bit vague but it indeed made me think. The answer was not straightforward so I had to keep on writing the answer as I remember it. However, after writing the answer I do not feel satisfied. Let me put this question in front of you and see if we all can come up with a comprehensive answer. Question: I am beginner with SQL Server. I have one query, it sometime returns a result and sometime it does not return me the result. Where should I start looking for a solution and what kind of information I should send to you so you can help me with solving. I have no clue, please guide me. Well, if you read the question, it is indeed incomplete and it does not contain much of the information at all. I decided to help him and here is the answer, which I started to compose. Answer: As there are not much information in the original question, I am not confident what will solve your problem. However, here are the few things which you can try to look at and see if that solves your problem. Check parameter which is passed to the query. Is the parameter changing at various executions? Check connection string – is there some kind of logic around it? Do you have a non-deterministic component in your query logic? (In other words – does your result is based on current date time or any other time based function?) Are you facing time out while running your query? Is there any error in error log? What is the business logic in your query? Do you have all the valid permissions to all the objects used in the query? Are permissions changing or query accessing a different object in various executions? (Add your suggestions here) Meanwhile, have you ever faced this situation? If yes, do share your experience in the comment area. I will send a copy of my book SQL Server Interview Questions and Answers to one of the most interesting comment. The winner will be announced by next Monday.  Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Interview Questions and Answers, SQL Puzzle, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • DEV C ++ Error: expected declaration before '}' token

    - by Francesca
    What does this mean? My program goes like this: (NOTE: The line that has the error was the line coming before case 2.) case 1: { cout<< "C * H * E * M * I * S * T * R * Y \n\n"; cout<< "1) What is the valence electron configuration of Selenium (Se)?\n\n"; cout<< "\na) 1s2 2s2 2p6 3s2\n\n"; cout<< "\nb) 1s2 2s2 2p2\n\n"; cout<< "\nc)4s2 4p4\n\n"; cout<< "\nd) 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p5\n\n"; cout<< "Enter your answer:\n"; cin>> answer; if (answer == 'c') { cout<<"Your answer is correct. Please press the enter key to proceed to the next question.\n\n"; } else cout<< "The correct answer is C. Please press the enter key to proceed to the next question.\n\n"; getch (); } getch (); cout<< "2) Which element yields the biggest atomic radius?\n\n"; cout<< "\na) Ca\n\n"; cout<< "\nb) Xe\n\n"; cout<< "\nc) B\n\n"; cout<< "\nd) Cs\n\n"; cout<< "Enter your answer:\n"; cin>> answer; if (answer == 'd') { cout<< "Your answer is correct. Please press the enter key to proceed to the next question.\n\n"; } else cout<< "The correct answer is D. Please press the enter key to proceed to the next question.\n\n"; getch (); } cout<< "3) Name the ionic compound K2 Cr2 O7\n\n"; cout<< "\na) potassium chloride\n\n"; cout<< "\nb) potassium carbonate\n\n"; cout<< "\nc) potassium chromite\n\n"; cout<< "\nd) potassium chromate\n\n"; cout<< "Enter your answer:\n"; cin>> answer; if (answer == 'd') { cout<< "Your answer is correct. Please press the enter key to proceed to the next question.\n\n"; } else cout<< "The correct answer is D. Please press the enter key to proceed to the next question.\n\n"; getch (); } } case 2: { cout<< "G * E * O * M * E * T * R * Y \n\n"; The error, as noted in the title is expected declaration before '}' token at the line noted in my opening paragraph.

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  • SQL SERVER – Basic Calculation and PEMDAS Order of Operation

    - by pinaldave
    After thinking a long time, I have decided to write about this blog post. I had no plan to create a blog post about this subject but the amount of conversation this one has created on my Facebook page, I decided to bring up a few of the question and concerns discussed on the Facebook page. There are more than 10,000 comments here so far. There are lots of discussion about what should be the answer. Well, as far as I can tell there is a big debate going on on Facebook, for educational purpose you should go ahead and read some of the comments. They are very interesting and for sure teach some new stuff. Even though some of the comments are clearly wrong they have made some good points and I believe it for sure develops some logic. Here is my take on this subject. I believe the answer is 9 as I follow PEMDAS  Order of Operation. PEMDAS stands for  parentheses, exponents, multiplication, division, addition, subtraction. PEMDAS is commonly known as BODMAS in India. BODMAS stands for Brackets, Orders (ie Powers and Square Roots, etc), Division, Multiplication,  Addition and Subtraction. PEMDAS and BODMAS are almost same and both of them follow the operation order from LEFT to RIGHT. Let us try to simplify above statement using the PEMDAS or BODMAS (whatever you prefer to call). Step 1: 6 ÷ 2 (1+2) (parentheses first) Step 2: = 6 ÷ 2 * (1+2) (adding multiplication sign for further clarification) Step 3: = 6 ÷ 2* (3) (single digit in parentheses – simplify using operator) Step 4: = 6 ÷ 2 * 3 (Remember next Operation should be LEFT to RIGHT) Step 5: = 3 * 3 (because 6 ÷ 2 = 3; remember LEFT to RIGHT) Step 6: = 9 (final answer) Some often find Step 4 confusing and often ended up multiplying 2 and 3 resulting Step 5 to be 6 ÷ 6, this is incorrect because in this case we did not follow the order of LEFT to RIGHT. When we do not follow the order of operation from LEFT to RIGHT we end up with the answer 1 which is incorrect. Let us see what SQL Server returns as a result. I executed following statement in SQL Server Management Studio SELECT 6/2*(1+2) It is clear that SQL Server also thinks that the answer should be 9. Let us go ahead and ask Google what will be the answer of above question in Google I have searched for the following term: 6/2(1+2) The result also says the answer should be 9. If you want a further reference here is a great video which describes why the answer should be 9 and not 1. And here is a fantastic conversation on Google Groups. Well, now what is your take on this subject? You are welcome to share constructive feedback and your answer may be different from my answer. NOTE: A healthy conversation about this subject is indeed encouraged but if there is a single bad word or comment is flaming it will be deleted without any notification (it does not matter how valuable information it contains). Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: About Me, PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • How should I fix problems with file permissions while restoring from Time Machine?

    - by Andrew Grimm
    While restoring files from a Time Machine backup, I got the error message "The operation can’t be completed because you don’t have permission to access some of the items." because of problems with files in one folder. What's the safest way to deal with this? The folder in question has permissions like: Andrew-Grimms-MacBook-Pro:kmer agrimm$ pwd /Volumes/Time Machine Backups/Backups.backupdb/Andrew Grimm’s MacBook Pro/2010-12-09-224309/Macintosh HD/Users/agrimm/ruby/kmer Andrew-Grimms-MacBook-Pro:kmer agrimm$ ls -ltra total 6156896 drwxrwxrwx@ 19 agrimm staff 680 18 Jan 2008 Saccharomyces_cerevisiae -r--------@ 1 agrimm staff 60221852 4 Aug 2009 hs_ref_GRCh37_chrY.fa -r--------@ 1 agrimm staff 157488804 4 Aug 2009 hs_ref_GRCh37_chrX.fa (snip a few files) -r--------@ 1 agrimm staff 676063 27 Oct 2009 NC_001143.fna -rw-r--r--@ 1 agrimm staff 6148 23 Mar 2010 .DS_Store drwxr-xr-x@ 3 agrimm staff 1530 23 Mar 2010 . drwxr-xr-x@ 30 agrimm staff 1054 20 Nov 14:43 .. Is it ok to do sudo chmod, or is there a safer approach? Background: Files within the original folder on my computer also had weird permissions - I suspect I may have used sudo to copy some files from a thumbdrive onto my computer.

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  • MySQL GROUP BY and JOIN

    - by christian
    Guys what's wrong with this SQL query: $sql = "SELECT res.Age, res.Gender, answer.*, $get_sum, SUM(CASE WHEN res.Gender='Male' THEN 1 else 0 END) AS males, SUM(CASE WHEN res.Gender='Female' THEN 1 else 0 END) AS females FROM Respondents AS res INNER JOIN Answers as answer ON answer.RespondentID=res.RespondentID INNER JOIN Questions as question ON answer.Answer=question.id WHERE answer.Question='Q1' GROUP BY res.Age ORDER BY res.Age ASC"; the $get_sum is an array of sql statement derived from another table: $sum[]= "SUM(CASE WHEN answer.Answer=".$db->f("id")." THEN 1 else 0 END) AS item".$db->f("id"); $get_sum = implode(', ', $sum); the query above return these values: Age: 20 item1 0 item2 1 item3 1 item4 1 item5 0 item6 0 Subtotal for Age 20 3 Age: 24 item1 2 item2 2 item3 2 item4 2 item5 1 item6 0 Subtotal for Age 24 9 It should return: Subtotal for Age 20 1 Subtotal for Age 24 2 In my sample data there are 3 respondents 2 are 24 yrs of age and the other one is 20 years old.

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  • Questions every good .NET developer should be able to answer?

    - by splattne
    My company is about to hire .NET developers. We work on a variety of .NET platforms: ASP.NET, Compact Framework, Windowsforms, Web Services. I'd like to compile a list/catalog of good questions, a kind of minimum standard to see if the applicants are experienced. So, my question is: What questions do you think should a good .NET programmer be able to respond? I'd also see it as a checklist for myself, in order to see where my own deficits are (there are many...). *UPDATE: It want to make clear that we're not testing only for .NET knowledge, and that problem solving capabilities and general programming skills are even more important to us.

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  • Client side validation of multiple radio buttons groups

    - by absolutely-free
    This is my code: <html> <head> <title>scoreboard</title> <script> function calculate() { var sum=0; var total=0; for (var i=0; i < document.questions.group1.length; i++){ if (document.questions.group1[i].checked){ sum = parseInt(document.questions.group1[i].value) total = parseInt(total + sum);}} for (var i=0; i < document.questions.group2.length; i++){ if (document.questions.group2[i].checked){ sum = parseInt(document.questions.group2[i].value) total = parseInt(total + sum);}} for (var i=0; i < document.questions.group3.length; i++){ if (document.questions.group3[i].checked){ sum = parseInt(document.questions.group3[i].value) total = parseInt(total + sum);}} alert(total) } </script> </head> <body> <form name="questions"> A:<br> answer a1: <input type="radio" name="group1" value="0"> answer a2: <input type="radio" name="group1" value="1"> answer a3: <input type="radio" name="group1" value="2"> answer a4: <input type="radio" name="group1" value="3"><br> B:<br> answer b1: <input type="radio" name="group2" value="0"> answer b2: <input type="radio" name="group2" value="1"> answer b3: <input type="radio" name="group2" value="2"> answer b4: <input type="radio" name="group2" value="3"><br> C:<br> answer c1: <input type="radio" name="group3" value="0"> answer c2: <input type="radio" name="group3" value="1"> answer c3: <input type="radio" name="group3" value="2"> answer c4: <input type="radio" name="group3" value="3"><br><br> <input type="button" value="total" onclick="calculate()"> </form> </body> </html> How can I replace 'group[x]' in my code by a variable, so the three for-loops are replaced by one (because in reality there are a lot more questions and answers) ?

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  • Is there a supplementary guide/answer key for ruby koans?

    - by corroded
    I have recently tried sharpening my rails skills with this tool: http://github.com/edgecase/ruby_koans but I am having trouble passing some tests. Also I am not sure if I'm doing some things correctly since the objective is just to pass the test, there are a lot of ways in passing it and I may be doing something that isn't up to standards. Is there a way to confirm if I'm doing things right? a specific example: in about_nil, def test_nil_is_an_object assert_equal __, nil.is_a?(Object), "Unlike NULL in other languages" end so is it telling me to check if that second clause is equal to an object(so i can say nil is an object) or just put assert_equal true, nil.is_a?(Object) because the statement is true? and the next test: def test_you_dont_get_null_pointer_errors_when_calling_methods_on_nil # What happens when you call a method that doesn't exist. The # following begin/rescue/end code block captures the exception and # make some assertions about it. begin nil.some_method_nil_doesnt_know_about rescue Exception => ex # What exception has been caught? assert_equal __, ex.class # What message was attached to the exception? # (HINT: replace __ with part of the error message.) assert_match(/__/, ex.message) end end Im guessing I should put a "No method error" string in the assert_match, but what about the assert_equal?

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  • Wrong answer on c# application, finding the n prime of a list of prime numbers.

    - by user300484
    Hello, I am new to C# and I am practicing by trying to solve this easy C# problem. This application will receive an "n" number. After receiving this number, the program has to show the n prime of the list of primes. For example, if the user enters "3", the program is supposed to display "5", because 5 is the third prime starting at 2. I koow that something is wrong with my code but I dont know where is the problem and how I can fix it. Can you please tell me? Thank you :P using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApplication1 { class Program { static void Main(string[] args) { Console.WriteLine("Determinar el n-esimo primo."); long n = Convert.ToInt64(Console.ReadLine()); // N lugar de primos long[] array = new long[n]; long c=0; while (c >= 2) { if(siprimo(c++) == true) for (long i = 0; i < n; i++) { array[i] = c; } } Console.WriteLine(array[n - 1]); Console.ReadLine(); } static private bool siprimo(long x) { bool sp = true; for (long k = 2; k <= x / 2; k++) if (x % k == 0) sp = false; return sp; } } }

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  • Netlogo behaviorspace, How to export each experiment's plot in a separate directory with a unique name? (Answer is by using pathdir extension)

    - by Marzy
    I have a save-plots function which I call it in my final command of behavior space to export selected plots, I could create unique names for plots so they don't replace each other, for example my output file name for one of the plots is like this: DeathRates, PS true, HCHA false 100,true.csv Let FileNameDeathRates ( word "D: /Results/" "DeathRates, " "PS "PS? ", HCHA " HCHA? MPS "," CV? ".csv" ) So far is good, but I want is to have a directory with name of the experiment and export all plots of that experiment in that directory for example: Let DirName( word "D:/Results/" "PS "PS? ", HCHA " HCHA? MPS "," CV? ) Netlogo already exports plots with proper name and I just want the directory name to be different , and of course prior to the experiment the directory does not exist so the directory should be created first , I could not find a command to create a directory in netlogo without pathdir extension. Any idea on how can I do this? Thanks in advance ;)

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  • Please help, looking for any answer for long time :How to use SqlDataSource Control to work with Dro

    - by Shantanu Gupta
    I am trying to fetch a column value from a datasource when some value is selected from a dropdownlist on its change event. <asp:DropDownList ID="ddlCityName" runat="server" DataSourceID="dsCity" DataTextField="CityName" DataValueField="CityID" AutoPostBack="True" OnTextChanged="CityName_OnTextChanged"> </asp:DropDownList> <asp:SqlDataSource ID="dsCity" runat="server" ConnectionString="<%$ ConnectionStrings:GmapConnectionString %>" SelectCommand="SELECT * FROM [vcity]" ></asp:SqlDataSource> Here I want to fetch any other column's value that is not binded to a ddlCityName from sqldatasource. I have four columns in datasource i.e. name, id, address, phno. I want to fetch an address of a person who selects some value from ddl.

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  • Why does this log output show the same answer in each iteration?

    - by Will Hancock
    OK, I was reading an article on optimising JS for Googles V8 engine, when i saw this code example... I nearly skimmed over it, but then I saw this; |=; a[0] |= b; a = new Array(); a[0] = 0; for (var b = 0; b < 10; b++) { console.log(a, b) a[0] |= b; // Much better! 2x faster. } a[0] |= b; So I ran it, in my console, with a console.log in the loop and resulted in 15; [15] 0 [15] 1 [15] 2 [15] 3 [15] 4 [15] 5 [15] 6 [15] 7 [15] 8 [15] 9 WHAT?!?! Where the hell does it get 15 from, on every iteration?!?!?! I've been a web dev for 7 years, and this has stumped me and a fellow colleague. Can somebody talk me through this code? Cheers.

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  • May be my example site may answer my question about ajax call... Help me

    - by booota
    Okay I have this ajax call $('.updatecom .registercomplaint').click(function(){ updatecomplaints(); }); This calls the function updatecomplaints() function updatecomplaints() { var tno = $(".updatecom #tno").val(); var status = $(".updatecom #status").val(); if(status=='DONE') { $(".updatecom #con").val(''); } var tname = $(".updatecom #tname").val(); var rg11 = $(".updatecom #crg11").val(); var rg06 = $(".updatecom #crg06").val(); var tvpins = $(".updatecom #tvpins").val(); var jointer = $(".updatecom #jointer").val(); var cquantity = $(".updatecom #conqty").val(); var nooftv = $(".updatecom #tvno").val(); var misc = $(".updatecom #misc").val(); var tcomments = $(".updatecom #tcomments").val(); var con = $(".updatecom #con").val(); //alert(tno+status+tname+rg11+rg06+tvpins+jointer+cquantity+nooftv+misc+tcomments+con); $.ajax( { type: "POST", url: "up_functions.php", data: "ticket="+ tno +"& opt=upcom" +"& status="+ status +"& tname="+ tname +"& rg11="+ rg11 +"& rg06="+ rg06 +"& tvpins="+ tvpins +"& jointer="+ jointer +"& cquantity="+ cquantity +"& nooftv="+ nooftv +"& misc="+ misc +"& tcomments="+ tcomments +"& con="+ con, success: function(response) { alert(response); } }); } here is my up_functions.php $tno = htmlspecialchars(trim($_REQUEST['ticket'])); $status = htmlspecialchars(trim($_REQUEST['status'])); $tname = htmlspecialchars(trim($_REQUEST['tname'])); $rg11 = htmlspecialchars(trim($_REQUEST['rg11'])); $rg06 = htmlspecialchars(trim($_REQUEST['rg06'])); $tvpins = htmlspecialchars(trim($_REQUEST['tvpins'])); $jointer = htmlspecialchars(trim($_REQUEST['jointer'])); $cquantity = htmlspecialchars(trim($_REQUEST['cquantity'])); $nooftv = htmlspecialchars(trim($_REQUEST['nooftv'])); $misc = htmlspecialchars(trim($_REQUEST['misc'])); $tcomments = htmlspecialchars(trim($_REQUEST['tcomments'])); $con = htmlspecialchars(trim($_REQUEST['con'])); $result=$ptr-upcomticketinfo($tno,$status,$tname,$rg11,$rg06,$tvpins,$jointer,$cquantity,$nooftv,$misc,$tcomments,$con); echo $result; and here is my upconticketinfo() php function function upcomticketinfo($tno,$status,$tname,$rg11,$rg06,$tvpins,$jointer,$cquantity,$nooftv,$misc,$tcomments,$con) { if($con!='' || $con!=NULL) { $this-query = "update booking discription set STATUS='$status',CLOSED ON='$con' where TICKET NO='$tno'"; $this-q_result = mysql_query($this-query,$this-conn) or die(mysql_error()); if($this-q_result) { $query = "update tech detail set TECH NAME='$tname',CABLE RG11='$rg11',CABLE RG06='$rg06',TV PINS USED='$tvpins',JOINTER USED='$jointer',CONNECTOR QTY='$cquantity',NO OF TV='$nooftv',MISC='$misc',TECH COMMENTS='$tcomments' where BOOKING='$tno'"; $q_result = mysql_query($query,$this-conn) or die(mysql_error()); if($q_result) { $response = "updated"; } else { $response = "error"; } } else { $response = "error"; } } else { $this-query = "update booking discription set STATUS='$status' where TICKET NO='$tno'"; $this-q_result = mysql_query($this-query,$this-conn) or die(mysql_error()); if($this-q_result) { $query = "update tech detail set TECH NAME='$tname',CABLE RG11='$rg11',CABLE RG06='$rg06',TV PINS USED='$tvpins',JOINTER USED='$jointer',CONNECTOR QTY='$cquantity',NO OF TV='$nooftv',MISC='$misc',TECH COMMENTS='$tcomments' where BOOKING='$tno'"; $q_result = mysql_query($query,$this-conn) or die(mysql_error()); if($q_result) { $response = "updated"; } else { $response = "error"; } } else { $response = "error"; } } return $response; } Question is that, this code is working just fine in IE8 i.e i am using... but it is not working in FF 3.6.3... I have checked each n everything... One thing is that the code works fine on FF too only when i debug the page with firebug debugger. Otherwise the alert in ajax success shows itself with nothing in it... Help me... Goto link text Enter 6628 in the Ticket No. box under Update Complaint Status section... A new form will open. In that form press update... Try it in FF and IE... IE8 shows the results as needed but FF does not...

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  • When I overload the assignment operator for my simple class array, I get the wrong answer I espect

    - by user299648
    //output is "01234 00000" but the output should be or what I want it to be is // "01234 01234" because of the assignment overloaded operator #include <iostream> using namespace std; class IntArray { public: IntArray() : size(10), used(0) { a= new int[10]; } IntArray(int s) : size(s), used(0) { a= new int[s]; } int& operator[]( int index ); IntArray& operator =( const IntArray& rightside ); ~IntArray() { delete [] a; } private: int *a; int size; int used;//for array position }; int main() { IntArray copy; if( 2>1) { IntArray arr(5); for( int k=0; k<5; k++) arr[k]=k; copy = arr; for( int j=0; j<5; j++) cout<<arr[j]; } cout<<" "; for( int j=0; j<5; j++) cout<<copy[j]; return 0; } int& IntArray::operator[]( int index ) { if( index >= size ) cout<<"ilegal index in IntArray"<<endl; return a[index]; } IntArray& IntArray::operator =( const IntArray& rightside ) { if( size != rightside.size )//also checks if on both side same object { delete [] a; a= new int[rightside.size]; } size=rightside.size; used=rightside.used; for( int i = 0; i < used; i++ ) a[i]=rightside.a[i]; return *this; }

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  • How can I use TDD to solve a puzzle with an unknown answer?

    - by matthewsteele
    Recently I wrote a Ruby program to determine solutions to a "Scramble Squares" tile puzzle: I used TDD to implement most of it, leading to tests that looked like this: it "has top, bottom, left, right" do c = Cards.new card = c.cards[0] card.top.should == :CT card.bottom.should == :WB card.left.should == :MT card.right.should == :BT end This worked well for the lower-level "helper" methods: identifying the "sides" of a tile, determining if a tile can be validly placed in the grid, etc. But I ran into a problem when coding the actual algorithm to solve the puzzle. Since I didn't know valid possible solutions to the problem, I didn't know how to write a test first. I ended up writing a pretty ugly, untested, algorithm to solve it: def play_game working_states = [] after_1 = step_1 i = 0 after_1.each do |state_1| step_2(state_1).each do |state_2| step_3(state_2).each do |state_3| step_4(state_3).each do |state_4| step_5(state_4).each do |state_5| step_6(state_5).each do |state_6| step_7(state_6).each do |state_7| step_8(state_7).each do |state_8| step_9(state_8).each do |state_9| working_states << state_9[0] end end end end end end end end end So my question is: how do you use TDD to write a method when you don't already know the valid outputs? If you're interested, the code's on GitHub: Tests: https://github.com/mattdsteele/scramblesquares-solver/blob/master/golf-creator-spec.rb Production code: https://github.com/mattdsteele/scramblesquares-solver/blob/master/game.rb

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  • jQuery show/hide for FAQ using the next() function

    - by jon_brockman
    Maybe it's because it's Friday but I'm stuck on a simple problem. I'm building a FAQ page where a user clicks on a question, revealing the answer beneath it. I'm trying to get the next() function to just grab the next instance of an "answer" div but, despite not getting any JS errors, the hidden div isn't showing. Here's the code: .answer { display:none; } $("a.question").click(function(){ $(this).next(".answer").toggle(); }); <a href="#" class="question">Queston 1</a> <div class="answer">Answer 1</div> <a href="#" class="question">Queston 2</a> <div class="answer">Answer 2</div>

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  • When asked "How do I make a website?" how do you answer?

    - by Luke CK
    A (non-technical) friend of mine has asked me how to make a website. I get this question all the time. After a few questions I found out that she has an idea that could turn into a commercial site. I described three options to her: a) Get a book/enroll in a class/follow some online tutorials and learn how to do it. She's pretty smart and her personality seems like a good match for this sort of thing so I'm sure she could learn but she doesn't have a lot of time spare. Maybe if she started with one of those WYSIWYG editors at first? I stressed that this would take a longer than a couple of weekends of playing around. b) Hire someone to build it. Ranges from ultra cheap to ultra expensive, crappy to good and everything in between. I didn't mention sites like Rentacoder because she hasn't worked on a project like this before and doesn't know what to ask for. At this stage she'd likely ask for a Youtube-MySpace-Google for a few hundred bucks because she doesn't yet understand just how much is involved. c) Find someone technical and partner up with them. I explained that this can either work really well or be a disaster because she'd have to give up some of her ownership of the idea. How do you respond in these situations?

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  • Rails - Beginner wants feedback on how they've modeled their app and how to do it better.

    - by adam
    I think the way I've modelled my app is a bit fishy and i need to rejig things, im just not sure how. I've already re-jigged and refactored before. It took a long time ( I'm a beginner ) and I'm hesitant to it again in case i head off in the wrong direction again. Basic Idea, user can submit an answer, another user can mark it correct or incorrect. If incorrect they have to write the correct answer. Users can view their and everybody else's correct and incorrect answers. So I did it this way class Answer has_one: correction end class Correction belongs_to :answer end when a user marks an answer as correct, I set checked_at:DateTime and checked_by_id:integer on the Answer object to keep track of who checked the answer and when. For incorrect answers I create a correction object which holds the correct answer and again checked_by and checked_at details. I don't like this because I have checked_by and checked_at in both models. It just doesn't sit right. Possible solutions are: Create a third model such as VerifiedAnswer and move the checked_by/at attributes to that. It will handle the situtation where an answer is marked correct. Or are these models thin enough (they dont have any other attributes) that I can just have one model ( Answer ) that has all the attributes to store all this information?

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