Search Results

Search found 3261 results on 131 pages for 'bong da city'.

Page 8/131 | < Previous Page | 4 5 6 7 8 9 10 11 12 13 14 15  | Next Page >

  • SQL SERVER – Solution – Puzzle – Statistics are not Updated but are Created Once

    - by pinaldave
    Earlier I asked puzzle why statistics are not updated. Read the complete details over here: Statistics are not Updated but are Created Once In the question I have demonstrated even though statistics should have been updated after lots of insert in the table are not updated.(Read the details SQL SERVER – When are Statistics Updated – What triggers Statistics to Update) In this example I have created following situation: Create Table Insert 1000 Records Check the Statistics Now insert 10 times more 10,000 indexes Check the Statistics – it will be NOT updated Auto Update Statistics and Auto Create Statistics for database is TRUE Now I have requested two things in the example 1) Why this is happening? 2) How to fix this issue? I have many answers – here is the how I fixed it which has resolved the issue for me. NOTE: There are multiple answers to this problem and I will do my best to list all. Solution: Create nonclustered Index on column City Here is the working example for the same. Let us understand this script and there is added explanation at the end. -- Execution Plans Difference -- Estimated Execution Plan Vs Actual Execution Plan -- Create Sample Database CREATE DATABASE SampleDB GO USE SampleDB GO -- Create Table CREATE TABLE ExecTable (ID INT, FirstName VARCHAR(100), LastName VARCHAR(100), City VARCHAR(100)) GO CREATE NONCLUSTERED INDEX IX_ExecTable1 ON ExecTable (City); GO -- Insert One Thousand Records -- INSERT 1 INSERT INTO ExecTable (ID,FirstName,LastName,City) SELECT TOP 1000 ROW_NUMBER() OVER (ORDER BY a.name) RowID, 'Bob', CASE WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%2 = 1 THEN 'Smith' ELSE 'Brown' END, CASE WHEN ROW_NUMBER() OVER (ORDER BY a.name)%20 = 1 THEN 'New York' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 5 THEN 'San Marino' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 3 THEN 'Los Angeles' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 7 THEN 'La Cinega' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 13 THEN 'San Diego' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 17 THEN 'Las Vegas' ELSE 'Houston' END FROM sys.all_objects a CROSS JOIN sys.all_objects b GO -- Display statistics of the table sp_helpstats N'ExecTable', 'ALL' GO -- Select Statement SELECT FirstName, LastName, City FROM ExecTable WHERE City  = 'New York' GO -- Display statistics of the table sp_helpstats N'ExecTable', 'ALL' GO -- Replace your Statistics over here DBCC SHOW_STATISTICS('ExecTable', IX_ExecTable1); GO -------------------------------------------------------------- -- Round 2 -- Insert One Thousand Records -- INSERT 2 INSERT INTO ExecTable (ID,FirstName,LastName,City) SELECT TOP 1000 ROW_NUMBER() OVER (ORDER BY a.name) RowID, 'Bob', CASE WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%2 = 1 THEN 'Smith' ELSE 'Brown' END, CASE WHEN ROW_NUMBER() OVER (ORDER BY a.name)%20 = 1 THEN 'New York' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 5 THEN 'San Marino' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 3 THEN 'Los Angeles' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 7 THEN 'La Cinega' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 13 THEN 'San Diego' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 17 THEN 'Las Vegas' ELSE 'Houston' END FROM sys.all_objects a CROSS JOIN sys.all_objects b GO -- Select Statement SELECT FirstName, LastName, City FROM ExecTable WHERE City  = 'New York' GO -- Display statistics of the table sp_helpstats N'ExecTable', 'ALL' GO -- Replace your Statistics over here DBCC SHOW_STATISTICS('ExecTable', IX_ExecTable1); GO -- Clean up Database DROP TABLE ExecTable GO When I created non clustered index on the column city, it also created statistics on the same column with same name as index. When we populate the data in the column the index is update – resulting execution plan to be invalided – this leads to the statistics to be updated in next execution of SELECT. This behavior does not happen on Heap or column where index is auto created. If you explicitly update the index, often you can see the statistics are updated as well. You can see this is for sure happening if you follow the tell of John Sansom. John Sansom‘s suggestion: That was fun! Although the column statistics are invalidated by the time the second select statement is executed, the query is not compiled/recompiled but instead the existing query plan is reused. It is the “next” compiled query against the column statistics that will see that they are out of date and will then in turn instantiate the action of updating statistics. You can see this in action by forcing the second statement to recompile. SELECT FirstName, LastName, City FROM ExecTable WHERE City = ‘New York’ option(RECOMPILE) GO Kevin Cross also have another suggestion: I agree with John. It is reusing the Execution Plan. Aside from OPTION(RECOMPILE), clearing the Execution Plan Cache before the subsequent tests will also work. i.e., run this before round 2: ————————————————————– – Clear execution plan cache before next test DBCC FREEPROCCACHE WITH NO_INFOMSGS; ————————————————————– Nice puzzle! Kevin As this was puzzle John and Kevin both got the correct answer, there was no condition for answer to be part of best practices. I know John and he is finest DBA around – his tremendous knowledge has always impressed me. John and Kevin both will agree that clearing cache either using DBCC FREEPROCCACHE and recompiling each query every time is for sure not good advice on production server. It is correct answer but not best practice. By the way, if you have better solution or have better suggestion please advise. I am open to change my answer and publish further improvement to this solution. On very separate note, I like to have clustered index on my Primary Key, which I have not mentioned here as it is out of the scope of this puzzle. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, PostADay, Readers Contribution, Readers Question, SQL, SQL Authority, SQL Index, SQL Puzzle, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology Tagged: Statistics

    Read the article

  • "Search Friendly" domain names

    - by Ben
    We bought a few search friendly domain names for the CPA site that I manage. Each of the domains we bought has the name of a nearby city and the word cpa in front of, or behind the city name. The plan is to create a landing page for each of these domains with useful information about business filings, ect. specific to that city, as well as directions to our office from that city. The question is how to best utilize these new domains: Should each domain be set to a 301 redirect to mainsite.com/city ? Should each domain be it's own single page mini-site that links to mainsite.com ? What other options are there and what are the pros/cons? Remember the goal is to be more relevant in searches that use a nearby city name in their search for CPA/accounting services.

    Read the article

  • Geek City: What gets logged for SELECT INTO operations?

    - by Kalen Delaney
    Last week, I wrote about logging for index rebuild operations. I wanted to publish the result of that testing as soon as I could, because that dealt with a specific question I was trying to answer. However, I actually started out my testing by looking at the logging that was done for a different operation, and ending up generating some new questions for myself. Before I starting testing the index rebuilds, I thought I would just get warmed up by observing the logging for SELECT INTO. I thought I...(read more)

    Read the article

  • Simple HTML5 Friendly Markup Sample

    - by Geertjan
    From a demo done by David Heffelfinger (who has a great Java EE 7 screencast series here), on HTML5 friendly markup. index.xhtml:  <?xml version='1.0' encoding='UTF-8' ?> <!DOCTYPE html> <html xmlns="http://www.w3.org/1999/xhtml" xmlns:jsf="http://xmlns.jcp.org/jsf"> <title>Data Entry Page</title> <body> <form method="POST" jsf:id='form'> <table> <tr> <td>Name:</td> <td><input jsf:id='name' type="text" jsf:value="${person.name}" /></td> </tr> <tr> <td>City</td> <th><input jsf:id='city' type="text" jsf:value="${person.city}"/></th> </tr> <tr> <td><input type="submit" value="Submit" jsf:action="confirmation" /></td> </tr> </table> </form> </body> </html> confirmation.xhtml: <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE html> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Data Confirmation Page</title> </head> <body> <h1>#{person.name}</h1> from <h2>#{person.city}</h2> </body> </html> Person.java: package org.demo; import javax.enterprise.inject.Model; @Model public class Person { String name; String city; public String getName() { return name; } public void setName(String name) { this.name = name; } public String getCity() { return city; } public void setCity(String city) { this.city = city; } }

    Read the article

  • Geek City: What gets logged for index rebuild operations?

    - by Kalen Delaney
    This blog post was inspired by a question from a future student. Someone who was already booked for my SQL Server Internals class in June asked for some information on a current problem he was having with transaction log writes causing excessive wait times during index rebuild operations when run in ONLINE mode. He wanted to know if switching to BULK_LOGGED recovery could help. I knew the difference between ALTER INDEX in FULL vs BULK_LOGGED recovery when doing normal OFFLINE rebuilds, but I wasn't...(read more)

    Read the article

  • Google Analytics for subdomains

    - by Sebastian
    I have two WordPress multisites under one domain - city-x.domain.com and city-y.domain.com. domain.com is a landing page where you select your city, and a cookie will redirect the user to that city on subsequent visits. I'd like to be able to track the number of hits on all pages on domain.com, city-x.domain.com and city-y.domain.com separately and combined. How is this On a side note, I've heard that GA underestimates hits. As this is important for advertising purposes, is there a better free service?

    Read the article

  • Loading city/state from SQL Server to Google Maps?

    - by knawlejj
    I'm trying to make a small application that takes a city & state and geocodes that address to a lat/long location. Right now I am utilizing Google Map's API, ColdFusion, and SQL Server. Basically the city and state fields are in a database table and I want to take those locations and get marker put on a Google Map showing where they are. This is my code to do the geocoding, and viewing the source of the page shows that it is correctly looping through my query and placing a location ("Omaha, NE") in the address field, but no marker, or map for that matter, is showing up on the page: function codeAddress() { <cfloop query="GetLocations"> var address = document.getElementById(<cfoutput>#Trim(hometown)#,#Trim(state)#</cfoutput>).value; if (geocoder) { geocoder.geocode( {<cfoutput>#Trim(hometown)#,#Trim(state)#</cfoutput>: address}, function(results, status) { if (status == google.maps.GeocoderStatus.OK) { var marker = new google.maps.Marker({ map: map, position: results[0].geometry.location, title: <cfoutput>#Trim(hometown)#,#Trim(state)#</cfoutput> }); } else { alert("Geocode was not successful for the following reason: " + status); } }); } </cfloop> } And here is the code to initialize the map: var geocoder; var map; function initialize() { geocoder = new google.maps.Geocoder(); var latlng = new google.maps.LatLng(42.4167,-90.4290); var myOptions = { zoom: 5, center: latlng, mapTypeId: google.maps.MapTypeId.ROADMAP } var marker = new google.maps.Marker({ position: latlng, map: map, title: "Test" }); map = new google.maps.Map(document.getElementById("map_canvas"), myOptions); } I do have a map working that uses lat/long that was hard coded into the database table, but I want to be able to just use the city/state and convert that to a lat/long. Any suggestions or direction? Storing the lat/long in the database is also possible, but I don't know how to do that within SQL.

    Read the article

  • Speed up SQL Server queries with PREFETCH

    - by Akshay Deep Lamba
    Problem The SAN data volume has a throughput capacity of 400MB/sec; however my query is still running slow and it is waiting on I/O (PAGEIOLATCH_SH). Windows Performance Monitor shows data volume speed of 4MB/sec. Where is the problem and how can I find the problem? Solution This is another summary of a great article published by R. Meyyappan at www.sqlworkshops.com.  In my opinion, this is the first article that highlights and explains with working examples how PREFETCH determines the performance of a Nested Loop join.  First of all, I just want to recall that Prefetch is a mechanism with which SQL Server can fire up many I/O requests in parallel for a Nested Loop join. When SQL Server executes a Nested Loop join, it may or may not enable Prefetch accordingly to the number of rows in the outer table. If the number of rows in the outer table is greater than 25 then SQL will enable and use Prefetch to speed up query performance, but it will not if it is less than 25 rows. In this section we are going to see different scenarios where prefetch is automatically enabled or disabled. These examples only use two tables RegionalOrder and Orders.  If you want to create the sample tables and sample data, please visit this site www.sqlworkshops.com. The breakdown of the data in the RegionalOrders table is shown below and the Orders table contains about 6 million rows. In this first example, I am creating a stored procedure against two tables and then execute the stored procedure.  Before running the stored proceudre, I am going to include the actual execution plan. --Example provided by www.sqlworkshops.com --Create procedure that pulls orders based on City --Do not forget to include the actual execution plan CREATE PROC RegionalOrdersProc @City CHAR(20) AS BEGIN DECLARE @OrderID INT, @OrderDetails CHAR(200) SELECT @OrderID = o.OrderID, @OrderDetails = o.OrderDetails       FROM RegionalOrders ao INNER JOIN Orders o ON (o.OrderID = ao.OrderID)       WHERE City = @City END GO SET STATISTICS time ON GO --Example provided by www.sqlworkshops.com --Execute the procedure with parameter SmallCity1 EXEC RegionalOrdersProc 'SmallCity1' GO After running the stored procedure, if we right click on the Clustered Index Scan and click Properties we can see the Estimated Numbers of Rows is 24.    If we right click on Nested Loops and click Properties we do not see Prefetch, because it is disabled. This behavior was expected, because the number of rows containing the value ‘SmallCity1’ in the outer table is less than 25.   Now, if I run the same procedure with parameter ‘BigCity’ will Prefetch be enabled? --Example provided by www.sqlworkshops.com --Execute the procedure with parameter BigCity --We are using cached plan EXEC RegionalOrdersProc 'BigCity' GO As we can see from the below screenshot, prefetch is not enabled and the query takes around 7 seconds to execute. This is because the query used the cached plan from ‘SmallCity1’ that had prefetch disabled. Please note that even if we have 999 rows for ‘BigCity’ the Estimated Numbers of Rows is still 24.   Finally, let’s clear the procedure cache to trigger a new optimization and execute the procedure again. DBCC freeproccache GO EXEC RegionalOrdersProc 'BigCity' GO This time, our procedure runs under a second, Prefetch is enabled and the Estimated Number of Rows is 999.   The RegionalOrdersProc can be optimized by using the below example where we are using an optimizer hint. I have also shown some other hints that could be used as well. --Example provided by www.sqlworkshops.com --You can fix the issue by using any of the following --hints --Create procedure that pulls orders based on City DROP PROC RegionalOrdersProc GO CREATE PROC RegionalOrdersProc @City CHAR(20) AS BEGIN DECLARE @OrderID INT, @OrderDetails CHAR(200) SELECT @OrderID = o.OrderID, @OrderDetails = o.OrderDetails       FROM RegionalOrders ao INNER JOIN Orders o ON (o.OrderID = ao.OrderID)       WHERE City = @City       --Hinting optimizer to use SmallCity2 for estimation       OPTION (optimize FOR (@City = 'SmallCity2'))       --Hinting optimizer to estimate for the currnet parameters       --option (recompile)       --Hinting optimize not to use histogram rather       --density for estimation (average of all 3 cities)       --option (optimize for (@City UNKNOWN))       --option (optimize for UNKNOWN) END GO Conclusion, this tip was mainly aimed at illustrating how Prefetch can speed up query execution and how the different number of rows can trigger this.

    Read the article

  • How can I get a distinct list of elements in a hierarchical query?

    - by RenderIn
    I have a database table, with people identified by a name, a job and a city. I have a second table that contains a hierarchical representation of every job in the company in every city. Suppose I have 3 people in the people table: [name(PK),title,city] Jim, Salesman, Houston Jane, Associate Marketer, Chicago Bill, Cashier, New York And I have thousands of job type/location combinations in the job table, a sample of which follow. You can see the hierarchical relationship since parent_title is a foreign key to title: [title,city,pay,parent_title] Salesman, Houston, $50000, CEO Cashier, Houston, $25000 CEO, USA, $1000000 Associate Marketer, Chicago, $75000 Senior Marketer, Chicago, $125000 ..... The problem I'm having is that my Person table is a composite key, so I don't know how to structure the start with part of my query so that it starts with each of the three jobs in the cities I specified. I can execute three separate queries to get what I want, but this doesn't scale well. e.g.: select * from jobs start with city = (select city from people where name = 'Bill') and title = (select title from people where name = 'Bill') connect by prior parent_title = title UNION select * from jobs start with city = (select city from people where name = 'Jim') and title = (select title from people where name = 'Jim') connect by prior parent_title = title UNION select * from jobs start with city = (select city from people where name = 'Jane') and title = (select title from people where name = 'Jane') connect by prior parent_title = title How else can I get a distinct list (or I could wrap it with a distinct if not possible) of all the jobs which are above the three people I specified?

    Read the article

  • Adding Column While Selecting Table in SQl

    - by kmkperumal
    My First Table is ProjectCustomFields CustomFieldId ProjectId CustomFieldName CustomFieldRequired CustomFieldDataType 69 1 User Name 1 0 72 1 City 1 0 74 1 Email 0 0 82 1 Salary 1 2 My Second Table is ProjectCustomFieldValues CustomFieldValueId ProjectId CustomFieldId CustomFieldValue RecordId 35 1 69 kaliya 1 36 1 72 Bangalore 1 37 1 74 [email protected] 1 41 1 69 Yohesh 2 42 1 72 Delhi 2 43 1 74 2 50 1 69 sss 3 51 1 72 Delhi 3 52 1 74 [email protected] 3 57 1 69 Sunil 4 58 1 72 Mumbai 4 59 1 74 [email protected] 4 60 1 82 20000 4 I tried Below Query Select M.CustomFieldName,N.CustomFieldValue,N.RecordId From (Select G.CustomFieldName,H.RecordId From (Select CustomFieldName From ProjectCustomFields Where ProjectId=1) G Cross Join (Select Distinct RecordId From ProjectCustomFieldValues) H) M Left Join (Select CustFiled.CustomFieldName,CustValue.CustomFieldValue,CustValue.RecordId From ProjectCustomFieldValues CustValue Left Join ProjectCustomFields CustFiled On CustValue.CustomFieldId=CustFiled.CustomFieldId Where CustValue.AuctionId=1 ) N On M.CustomFieldName=N.CustomFieldName And M.RecordId=N.RecordId But I got the result below #CustomFieldName# CustomFieldValue RecordId User Name kaliya 1 City Bangalore 1 Email [email protected] 1 Salary NULL **NULL** User Name Yohesh 2 City Delhi 2 Email 2 Salary NULL **NULL** User Name sss 3 City Delhi 3 Email [email protected] 3 Salary NULL **NULL** User Name NULL **NULL** City NULL **NULL** Email NULL **NULL** Salary NULL **NULL** User Name Sunil 4 City Mumbai 4 Email [email protected] 4 Salary 20000 4 But Expected Result is CustomFieldName CustomFieldValue RecordId User Name kaliya 1 City Bangalore 1 Email [email protected] 1 Salary NULL **1** User Name Yohesh 2 City Delhi 2 Email 2 Salary NULL **2** User Name sss 3 City Delhi 3 Email [email protected] 3 Salary NULL **3** User Name Sunil 4 City Mumbai 4 Email [email protected] 4 Salary 20000 4 Please guide me some one,I tried so much but i got null value in recordId,So I need same recordId above one..

    Read the article

  • Can't parse XML effectively using Python

    - by Harshit Sharma
    import urllib import xml.etree.ElementTree as ET def getWeather(city): #create google weather api url url = "http://www.google.com/ig/api?weather=" + urllib.quote(city) try: # open google weather api url f = urllib.urlopen(url) except: # if there was an error opening the url, return return "Error opening url" # read contents to a string s = f.read() tree=ET.parse(s) current= tree.find("current_condition/condition") condition_data = current.get("data") weather = condition_data if weather == "<?xml version=": return "Invalid city" #return the weather condition #return weather def main(): while True: city = raw_input("Give me a city: ") weather = getWeather(city) print(weather) if __name__ == "__main__": main() gives error , I actually wanted to find values from google weather xml site tags

    Read the article

  • How to implement python to find value between xml tags?

    - by Harshit Sharma
    I am using google site to retrieve weather information , I want to find values between XML tags. Following code give me weather condition of a city , but I am unable to obtain other parameters such as temperature and if possible explain working of split function implied in the code: import urllib def getWeather(city): #create google weather api url url = "http://www.google.com/ig/api?weather=" + urllib.quote(city) try: # open google weather api url f = urllib.urlopen(url) except: # if there was an error opening the url, return return "Error opening url" # read contents to a string s = f.read() # extract weather condition data from xml string weather = s.split("<current_conditions><condition data=\"")[-1].split("\"")[0] # if there was an error getting the condition, the city is invalid if weather == "<?xml version=": return "Invalid city" #return the weather condition return weather def main(): while True: city = raw_input("Give me a city: ") weather = getWeather(city) print(weather) if __name__ == "__main__": main() Thank You

    Read the article

  • Can't make HREF change based on PHP value

    - by Liso22
    I want to retrieve the user's location and then show a link that points to an URL that changes according to that location. I just want to place the user's city name at the end of the HREF. I need this work on my wordpress site, on a static page. I use a plugin called Exec-php which let's me run PHP in pages. I have a plugin that provides me the user's city through the shortcode "[mmjs-city]". I tried to make it work through different paths but I never get the link to work. Here I tried assigning that shortcode to a value, <?php $city= "[mmjs-city]"; echo $city; echo "<a href='?s=" . $city ."'>Search for your city</a>"; ?> I added the first two lines to check whether the shortcode is working or not and if it's correctly assinged to the value $city. That part works. Then it creates the link and put's the value $city at the end of it. But when trying it instead of taking me to: /?s=new+york It takes me to: /?s=%3Cscript%20language=%22javascript%22%3Edocument.write(geoip_city());%3C/script%3E I have no idea what to do. I would be really thankful for any info on how to make it work, it's really an important feature for my site. Please ask for any further info or idk anything. Also this is where I tested that code: http://chusmix.com/?page_id=1129 Thanks

    Read the article

  • Listing issue, GROUP mysql

    - by SethCodes
    Here is a mock-up example of Mysql table: | ID | Country | City | ________________________________ | 1 | Sweden | Stockholm | | 2 | Sweden | Stockholm | | 3 | Sweden | Lund | | 4 | Sweden | Lund | | 5 | Germany | Berlin | | 6 | Germany | Berlin | | 7 | Germany | Hamburg | | 8 | Germany | Hamburg | Notice how both rows Country and city have repeated values inside them. Using GROUP BY country, city in my PDO query, the values will not repeat while in loop. Here is PDO for this: $query = "SELECT id, city, country FROM table GROUP BY country, city"; $stmt = $db->query($query); while($row = $stmt->fetch(PDO::FETCH_ASSOC)) : The above code will result in an output like this (some editing in-between). GROUP BY works but the country repeats: Sweden - Stockholm Sweden - Lund Germany - Berlin Germany - Hamburg Using bootstrap collapse and above code, I separate the country from the city with a simple drop down collopase. Here is code: <li> <a data-toggle="collapse" data-target="#<?= $row['id']; ?>" href="search.php?country=<?= $row['country']; ?>"> <?= $row['country']; ?> </a> <div id ="<?= $row['id']; ?>" class="collapse in"> //collapse div here <a href="search.php?city=<?= $row['city']; ?>"> <?= $row['city']; ?><br></a> </div> //end </li> It then looks something like this (once collapse is initiated): Sweden > Stockholm Sweden > Lund Germany >Berlin Germany >Hamburg Here is where I face the problem. The above lists the values Sweden and Germany 2 times. I want Sweden and Germany to only list one time, and the cities listed below, so the desired look is to be this: Sweden // Lists one time > Stockholm > Lund Germany // Lists one time >Berlin >Hamburg I have tried using DISTINCT, GROUP_CONTACT and other methods, yet none get my desired output (above). Suggestions? Below is my current full code in action: <? $query = "SELECT id, city, country FROM table GROUP BY country, city"; $stmt = $db->query($query); while($row = $stmt->fetch(PDO::FETCH_ASSOC)) : ?> <li> <a data-toggle="collapse" data-target="#<?= $row['id']; ?>" href="search.php?country=<?= $row['country']; ?>"> <?= $row['country']; ?> </a> <div id ="<?= $row['id']; ?>" class="collapse in"> //collapse div here <a href="search.php?city=<?= $row['city']; ?>"> <?= $row['city']; ?><br></a> </div> //end </li> <? endwhile ?>

    Read the article

  • Roadshow Microsoft – Primeira Parada: Londrina, PR

    - by anobre
    Hoje (23/03) tivemos aqui em Londrina a primeira parada do Roadshow Microsoft, com apresentação de diversos produtos com aplicação em cenários técnicos. Como já é de costume, o evento reuniu alguns dos melhores profissionais de DEV e INFRA, com informações extremamente úteis sobre .NET Framework 4, Entity Framework, Exchange, Sharepoint, entre outras tecnologias e produtos. Na minha visão, o evento conseguiu atender a expectativa dos participantes, através dos cenários técnicos criados para a ficticia Adventure Works (acho que eu conheço esta empresa… :). Através da participação ativa de todos, as tracks de DEV e INFRA tiveram o sucesso aparente no comentário do pessoal nos intervalos e almoço. Depois das palestras, lá por 19h, tivemos um jantar com o pessoal da Microsoft e influenciadores da região, onde, até as 21h, discutimos muita coisa (até Commerce Server!). Esta aproximação com o time de comunidades da Microsoft, além de alguns “penetras” como o próprio Alex disse, é extremamente importante e útil, visto que passamos conhecemos a fundo as intenções e futuras ações da Microsoft visando as comunidades locais. Para concluir, algo que sempre digo: participe de alguma comunidade técnica da sua região. Entre em contato com influenciadores, conheça os grupos de usuários perto de você e não perca tempo. Ter o conhecimento perto de você, contribuir e crescer profissionalmente não tem preço. Obrigado novamente a todo time, em especial a Fabio Hara, Rodrigo Dias, Alex Schulz, Alvaro Rezende, Murilo e Renato Haddad. Abraços. OBS.: Lembre-se: em Londrina e região, procure o Sharpcode! :) OBS. 2: Se você é de Londrina e não participou, não perca mais oportunidades. Alias, se o seu chefe não deixa você ir, se você tem que participar de sorteio para ter uma chance de ir, ou se a sua empresa nem fica sabendo de eventos como este, acho que tá na hora de você pensar em outros opções né? :)

    Read the article

  • What Java data structure/design pattern best models this object, considering it would perform these methods?

    - by zundarz
    Methods: 1. getDistance(CityA,CityB) // Returns distance between two cities 2. getCitiesInRadius(CityA,integer) // Returns cities within a given distance of another city 3. getCitiesBeyondRadius(CityA,integer) //Returns cities beyond a given distance of another city 4. getRemoteDestinations(integer) // Returns all city pairs greater than x distance of each other 5. getLocalDestinations(integer) //Returns all city pairs within x distance of each other

    Read the article

  • Building Queries Systematically

    - by Jeremy Smyth
    The SQL language is a bit like a toolkit for data. It consists of lots of little fiddly bits of syntax that, taken together, allow you to build complex edifices and return powerful results. For the uninitiated, the many tools can be quite confusing, and it's sometimes difficult to decide how to go about the process of building non-trivial queries, that is, queries that are more than a simple SELECT a, b FROM c; A System for Building Queries When you're building queries, you could use a system like the following:  Decide which fields contain the values you want to use in our output, and how you wish to alias those fields Values you want to see in your output Values you want to use in calculations . For example, to calculate margin on a product, you could calculate price - cost and give it the alias margin. Values you want to filter with. For example, you might only want to see products that weigh more than 2Kg or that are blue. The weight or colour columns could contain that information. Values you want to order by. For example you might want the most expensive products first, and the least last. You could use the price column in descending order to achieve that. Assuming the fields you've picked in point 1 are in multiple tables, find the connections between those tables Look for relationships between tables and identify the columns that implement those relationships. For example, The Orders table could have a CustomerID field referencing the same column in the Customers table. Sometimes the problem doesn't use relationships but rests on a different field; sometimes the query is looking for a coincidence of fact rather than a foreign key constraint. For example you might have sales representatives who live in the same state as a customer; this information is normally not used in relationships, but if your query is for organizing events where sales representatives meet customers, it's useful in that query. In such a case you would record the names of columns at either end of such a connection. Sometimes relationships require a bridge, a junction table that wasn't identified in point 1 above but is needed to connect tables you need; these are used in "many-to-many relationships". In these cases you need to record the columns in each table that connect to similar columns in other tables. Construct a join or series of joins using the fields and tables identified in point 2 above. This becomes your FROM clause. Filter using some of the fields in point 1 above. This becomes your WHERE clause. Construct an ORDER BY clause using values from point 1 above that are relevant to the desired order of the output rows. Project the result using the remainder of the fields in point 1 above. This becomes your SELECT clause. A Worked Example   Let's say you want to query the world database to find a list of countries (with their capitals) and the change in GNP, using the difference between the GNP and GNPOld columns, and that you only want to see results for countries with a population greater than 100,000,000. Using the system described above, we could do the following:  The Country.Name and City.Name columns contain the name of the country and city respectively.  The change in GNP comes from the calculation GNP - GNPOld. Both those columns are in the Country table. This calculation is also used to order the output, in descending order To see only countries with a population greater than 100,000,000, you need the Population field of the Country table. There is also a Population field in the City table, so you'll need to specify the table name to disambiguate. You can also represent a number like 100 million as 100e6 instead of 100000000 to make it easier to read. Because the fields come from the Country and City tables, you'll need to join them. There are two relationships between these tables: Each city is hosted within a country, and the city's CountryCode column identifies that country. Also, each country has a capital city, whose ID is contained within the country's Capital column. This latter relationship is the one to use, so the relevant columns and the condition that uses them is represented by the following FROM clause:  FROM Country JOIN City ON Country.Capital = City.ID The statement should only return countries with a population greater than 100,000,000. Country.Population is the relevant column, so the WHERE clause becomes:  WHERE Country.Population > 100e6  To sort the result set in reverse order of difference in GNP, you could use either the calculation, or the position in the output (it's the third column): ORDER BY GNP - GNPOld or ORDER BY 3 Finally, project the columns you wish to see by constructing the SELECT clause: SELECT Country.Name AS Country, City.Name AS Capital,        GNP - GNPOld AS `Difference in GNP`  The whole statement ends up looking like this:  mysql> SELECT Country.Name AS Country, City.Name AS Capital, -> GNP - GNPOld AS `Difference in GNP` -> FROM Country JOIN City ON Country.Capital = City.ID -> WHERE Country.Population > 100e6 -> ORDER BY 3 DESC; +--------------------+------------+-------------------+ | Country            | Capital    | Difference in GNP | +--------------------+------------+-------------------+ | United States | Washington | 399800.00 | | China | Peking | 64549.00 | | India | New Delhi | 16542.00 | | Nigeria | Abuja | 7084.00 | | Pakistan | Islamabad | 2740.00 | | Bangladesh | Dhaka | 886.00 | | Brazil | Brasília | -27369.00 | | Indonesia | Jakarta | -130020.00 | | Russian Federation | Moscow | -166381.00 | | Japan | Tokyo | -405596.00 | +--------------------+------------+-------------------+ 10 rows in set (0.00 sec) Queries with Aggregates and GROUP BY While this system might work well for many queries, it doesn't cater for situations where you have complex summaries and aggregation. For aggregation, you'd start with choosing which columns to view in the output, but this time you'd construct them as aggregate expressions. For example, you could look at the average population, or the count of distinct regions.You could also perform more complex aggregations, such as the average of GNP per head of population calculated as AVG(GNP/Population). Having chosen the values to appear in the output, you must choose how to aggregate those values. A useful way to think about this is that every aggregate query is of the form X, Y per Z. The SELECT clause contains the expressions for X and Y, as already described, and Z becomes your GROUP BY clause. Ordinarily you would also include Z in the query so you see how you are grouping, so the output becomes Z, X, Y per Z.  As an example, consider the following, which shows a count of  countries and the average population per continent:  mysql> SELECT Continent, COUNT(Name), AVG(Population)     -> FROM Country     -> GROUP BY Continent; +---------------+-------------+-----------------+ | Continent     | COUNT(Name) | AVG(Population) | +---------------+-------------+-----------------+ | Asia          |          51 |   72647562.7451 | | Europe        |          46 |   15871186.9565 | | North America |          37 |   13053864.8649 | | Africa        |          58 |   13525431.0345 | | Oceania       |          28 |    1085755.3571 | | Antarctica    |           5 |          0.0000 | | South America |          14 |   24698571.4286 | +---------------+-------------+-----------------+ 7 rows in set (0.00 sec) In this case, X is the number of countries, Y is the average population, and Z is the continent. Of course, you could have more fields in the SELECT clause, and  more fields in the GROUP BY clause as you require. You would also normally alias columns to make the output more suited to your requirements. More Complex Queries  Queries can get considerably more interesting than this. You could also add joins and other expressions to your aggregate query, as in the earlier part of this post. You could have more complex conditions in the WHERE clause. Similarly, you could use queries such as these in subqueries of yet more complex super-queries. Each technique becomes another tool in your toolbox, until before you know it you're writing queries across 15 tables that take two pages to write out. But that's for another day...

    Read the article

  • How to select all options from a drop list in php / mysql

    - by Mirage81
    Thanks to stackoverflow.com's frienly experts I've managed to create my first php + mysql application. The code searches a mysql database for last names and cities. The choices are made through two drop lists like these: Choose city: All cities Liverpool Manchester Choose last name: All last names Lennon Gallagher The code would return eg. all the Lennons living in Liverpool. However, I haven't been able to make the options "All cities" and "All last names" to work so that the code would return eg. all the Lennons living in any city or all the people living in Liverpool. So, how can that be done? The code so far: index.php <?php $conn = mysql_connect('localhost', 'user', 'password') or die("Connection failed"); mysql_select_db("database", $conn) or die("Switch database failed"); //this gets the cities from the database to the drop list $query = "SELECT DISTINCT city FROM user".mysql_real_escape_string($city); $result = mysql_query($query, $conn); $options=""; while ($row=mysql_fetch_array($result)) { $city=$row["city"]; $options.="<OPTION VALUE=\"$city\">".$city; } //this gets the last names from the database to the drop list $query2 = "SELECT DISTINCT lastname FROM user".mysql_real_escape_string($lastname); $result2 = mysql_query($query2, $conn); $options2=""; while ($row2=mysql_fetch_array($result2)) { $lastname=$row2["lastname"]; $options2.="<OPTION VALUE=\"$lastname\">".$lastname; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> <html> <head> <meta content="text/html; charset=ISO-8859-1" http-equiv="content-type"> <title>test</title> </head> <body> <form action="get.php" method="post"> <p> <select name="city"> <option value=0>Choose <option value=1>All cities <?=$options?> </select> </p> <p> <select name="lastname"> <option value=0>Choose <option value=1>All last names <?=$options2?> </select> </p> <p> <input value="Search" type="submit"> </p> </form> <br> </body> </html> get.php <?php $conn = mysql_connect('localhost', 'user', 'password') or die("Connection failed"); mysql_select_db("database", $conn) or die("Switch database failed"); $query = "SELECT * FROM user WHERE city = '".mysql_real_escape_string($_POST['city'])."' AND lastname = '".mysql_real_escape_string($_POST['lastname'])."'"; $result = mysql_query($query, $conn); echo $rowcount; $zerorows=true; while ($row = mysql_fetch_assoc($result)) { $zerorows=false; echo '<b>City: </b>'.htmlspecialchars($row[city]).'<br />'; echo '<b>Last name: </b>'.htmlspecialchars($row[lastname]).'<br />'; echo '<b>Information: </b>'.htmlspecialchars($row[information]).'<br />'.'<br />'; } if($zerorows) echo "No results"; mysql_close($conn); ?>

    Read the article

  • Is my hard drive about to die?

    - by Hristo Deshev
    I have two hard drives set up as a RAID 1 array on my server (Linux, software RAID using mdadm) and one of them just got me this "present" in syslog: Nov 23 02:05:29 h2 kernel: [7305215.338153] ata1.00: exception Emask 0x0 SAct 0x1 SErr 0x0 action 0x0 Nov 23 02:05:29 h2 kernel: [7305215.338178] ata1.00: irq_stat 0x40000008 Nov 23 02:05:29 h2 kernel: [7305215.338197] ata1.00: failed command: READ FPDMA QUEUED Nov 23 02:05:29 h2 kernel: [7305215.338220] ata1.00: cmd 60/08:00:d8:df:da/00:00:3a:00:00/40 tag 0 ncq 4096 in Nov 23 02:05:29 h2 kernel: [7305215.338221] res 41/40:08:d8:df:da/00:00:3a:00:00/00 Emask 0x409 (media error) <F> Nov 23 02:05:29 h2 kernel: [7305215.338287] ata1.00: status: { DRDY ERR } Nov 23 02:05:29 h2 kernel: [7305215.338305] ata1.00: error: { UNC } Nov 23 02:05:29 h2 kernel: [7305215.358901] ata1.00: configured for UDMA/133 Nov 23 02:05:32 h2 kernel: [7305218.269054] ata1.00: exception Emask 0x0 SAct 0x1 SErr 0x0 action 0x0 Nov 23 02:05:32 h2 kernel: [7305218.269081] ata1.00: irq_stat 0x40000008 Nov 23 02:05:32 h2 kernel: [7305218.269101] ata1.00: failed command: READ FPDMA QUEUED Nov 23 02:05:32 h2 kernel: [7305218.269125] ata1.00: cmd 60/08:00:d8:df:da/00:00:3a:00:00/40 tag 0 ncq 4096 in Nov 23 02:05:32 h2 kernel: [7305218.269126] res 41/40:08:d8:df:da/00:00:3a:00:00/00 Emask 0x409 (media error) <F> Nov 23 02:05:32 h2 kernel: [7305218.269196] ata1.00: status: { DRDY ERR } Nov 23 02:05:32 h2 kernel: [7305218.269215] ata1.00: error: { UNC } Nov 23 02:05:32 h2 kernel: [7305218.341565] ata1.00: configured for UDMA/133 Nov 23 02:05:35 h2 kernel: [7305221.193342] ata1.00: exception Emask 0x0 SAct 0x1 SErr 0x0 action 0x0 Nov 23 02:05:35 h2 kernel: [7305221.193368] ata1.00: irq_stat 0x40000008 Nov 23 02:05:35 h2 kernel: [7305221.193386] ata1.00: failed command: READ FPDMA QUEUED Nov 23 02:05:35 h2 kernel: [7305221.193408] ata1.00: cmd 60/08:00:d8:df:da/00:00:3a:00:00/40 tag 0 ncq 4096 in Nov 23 02:05:35 h2 kernel: [7305221.193409] res 41/40:08:d8:df:da/00:00:3a:00:00/00 Emask 0x409 (media error) <F> Nov 23 02:05:35 h2 kernel: [7305221.193474] ata1.00: status: { DRDY ERR } Nov 23 02:05:35 h2 kernel: [7305221.193491] ata1.00: error: { UNC } Nov 23 02:05:35 h2 kernel: [7305221.388404] ata1.00: configured for UDMA/133 Nov 23 02:05:38 h2 kernel: [7305224.426316] ata1.00: exception Emask 0x0 SAct 0x1 SErr 0x0 action 0x0 Nov 23 02:05:38 h2 kernel: [7305224.426343] ata1.00: irq_stat 0x40000008 Nov 23 02:05:38 h2 kernel: [7305224.426363] ata1.00: failed command: READ FPDMA QUEUED Nov 23 02:05:38 h2 kernel: [7305224.426387] ata1.00: cmd 60/08:00:d8:df:da/00:00:3a:00:00/40 tag 0 ncq 4096 in Nov 23 02:05:38 h2 kernel: [7305224.426388] res 41/40:08:d8:df:da/00:00:3a:00:00/00 Emask 0x409 (media error) <F> Nov 23 02:05:38 h2 kernel: [7305224.426459] ata1.00: status: { DRDY ERR } Nov 23 02:05:38 h2 kernel: [7305224.426478] ata1.00: error: { UNC } Nov 23 02:05:38 h2 kernel: [7305224.498133] ata1.00: configured for UDMA/133 Nov 23 02:05:41 h2 kernel: [7305227.400583] ata1.00: exception Emask 0x0 SAct 0x1 SErr 0x0 action 0x0 Nov 23 02:05:41 h2 kernel: [7305227.400608] ata1.00: irq_stat 0x40000008 Nov 23 02:05:41 h2 kernel: [7305227.400627] ata1.00: failed command: READ FPDMA QUEUED Nov 23 02:05:41 h2 kernel: [7305227.400649] ata1.00: cmd 60/08:00:d8:df:da/00:00:3a:00:00/40 tag 0 ncq 4096 in Nov 23 02:05:41 h2 kernel: [7305227.400650] res 41/40:08:d8:df:da/00:00:3a:00:00/00 Emask 0x409 (media error) <F> Nov 23 02:05:41 h2 kernel: [7305227.400716] ata1.00: status: { DRDY ERR } Nov 23 02:05:41 h2 kernel: [7305227.400734] ata1.00: error: { UNC } Nov 23 02:05:41 h2 kernel: [7305227.472432] ata1.00: configured for UDMA/133 From what I read so far, I am not sure if read errors mean that a hard drive is dying on me (no write errors so far). I've had hard drive errors in the past and those always had errors about failing to write to specific sectors in the logs. Not this time. Should I be replacing the drive? Could something else be causing the problem? I've scheduled a smartctl -t long test that will finish in a couple of hours. I hope this will give me some more info.

    Read the article

  • Geolocation SQL query not finding exact location

    - by Iridium52
    I have been testing my geolocation query for some time now and I haven't found any issues with it until now. I am trying to search for all cities within a given radius, often times I'm searching for cities surrounding a city using that city's coords, but recently I tried searching around a city and found that the city itself was not returned. I have these cities as an excerpt in my database: city latitude longitude Saint-Mathieu 45.316708 -73.516253 Saint-Édouard 45.233374 -73.516254 Saint-Michel 45.233374 -73.566256 Saint-Rémi 45.266708 -73.616257 But when I run my query around the city of Saint-Rémi, with the following query... SELECT tblcity.city, tblcity.latitude, tblcity.longitude, truncate((degrees(acos( sin(radians(tblcity.latitude)) * sin(radians(45.266708)) + cos(radians(tblcity.latitude)) * cos(radians(45.266708)) * cos(radians(tblcity.longitude - -73.616257) ) ) ) * 69.09*1.6),1) as distance FROM tblcity HAVING distance < 10 ORDER BY distance desc I get these results: city latitude longitude distance Saint-Mathieu 45.316708 -73.516253 9.5 Saint-Édouard 45.233374 -73.516254 8.6 Saint-Michel 45.233374 -73.566256 5.3 The town of Saint-Rémi is missing from the search. So I tried a modified query hoping to get a better result: SELECT tblcity.city, tblcity.latitude, tblcity.longitude, truncate(( 6371 * acos( cos( radians( 45.266708 ) ) * cos( radians( tblcity.latitude ) ) * cos( radians( tblcity.longitude ) - radians( -73.616257 ) ) + sin( radians( 45.266708 ) ) * sin( radians( tblcity.latitude ) ) ) ),1) AS distance FROM tblcity HAVING distance < 10 ORDER BY distance desc But I get the same result... However, if I modify Saint-Rémi's coords slighly by changing the last digit of the lat or long by 1, both queries will return Saint-Rémi. Also, if I center the query on any of the other cities above, the searched city is returned in the results. Can anyone shed some light on what may be causing my queries above to not display the searched city of Saint-Rémi? I have added a sample of the table (with extra fields removed) below. I'm using MySQL 5.0.45, thanks in advance. CREATE TABLE `tblcity` ( `IDCity` int(1) NOT NULL auto_increment, `City` varchar(155) NOT NULL default '', `Latitude` decimal(9,6) NOT NULL default '0.000000', `Longitude` decimal(9,6) NOT NULL default '0.000000', PRIMARY KEY (`IDCity`) ) ENGINE=MyISAM AUTO_INCREMENT=52743 DEFAULT CHARSET=latin1 AUTO_INCREMENT=52743; INSERT INTO `tblcity` (`city`, `latitude`, `longitude`) VALUES ('Saint-Mathieu', 45.316708, -73.516253), ('Saint-Édouard', 45.233374, -73.516254), ('Saint-Michel', 45.233374, -73.566256), ('Saint-Rémi', 45.266708, -73.616257);

    Read the article

< Previous Page | 4 5 6 7 8 9 10 11 12 13 14 15  | Next Page >