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  • Deleting rows with MySQL LEFT JOIN

    - by fabrik
    Hello! I have two tables, one for job deadlines, one for describe a job. Each job can take a status and some statuses means the jobs' deadlines must be deleted from the other table. I can easily SELECT the jobs/deadlines that meets my criteria with a LEFT JOIN: SELECT * FROM `deadline` LEFT JOIN `job` ON deadline.job_id = job.job_id WHERE `status` = 'szamlazva' OR `status` = 'szamlazhato' OR `status` = 'fizetve' OR `status` = 'szallitva' OR `status` = 'storno' (status belongs to job table not deadline) But when i'd like to delete these rows from deadline, MySQL throws an error. My query is: DELETE FROM `deadline` LEFT JOIN `job` ON deadline.job_id = job.job_id WHERE `status` = 'szamlazva' OR `status` = 'szamlazhato' OR `status` = 'fizetve' OR `status` = 'szallitva' OR `status` = 'storno' MySQL error says nothing: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'LEFT JOIN `job` ON deadline.job_id = job.job_id WHERE `status` = 'szaml' at line 1 How can i turn my SELECT into a working DELETE query? Thanks, fabrik

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  • Left Join Returning Extra Rows T-SQL?

    - by davemackey
    I have the following query: select * from ACADEMIC a left join RESIDENCY r on a.PEOPLE_CODE_ID = r.PEOPLE_CODE_ID where a.ACADEMIC_TERM='Fall' and r.ACADEMIC_TERM='Fall' and a.ACADEMIC_SESSION='' and a.ACADEMIC_YEAR = (Select Year(GetDate())) and r.ACADEMIC_YEAR = (Select Year(GetDate())) and (CLASS_LEVEL LIKE 'FR%' OR a.CLASS_LEVEL LIKE 'SO' OR a.CLASS_LEVEL LIKE 'JR' OR a.CLASS_LEVEL LIKE 'SR%') and r.RESIDENT_COMMUTER='R' For each person in the database it returns two rows with identical information. Yet, when I do the same query without the left join: select * from ACADEMIC a where a.ACADEMIC_TERM='Fall' and a.ACADEMIC_SESSION='' and a.ACADEMIC_YEAR = (Select Year(GetDate())) and (CLASS_LEVEL LIKE 'FR%' OR a.CLASS_LEVEL LIKE 'SO' OR a.CLASS_LEVEL LIKE 'JR' OR a.CLASS_LEVEL LIKE 'SR%') ORDER BY PEOPLE_ID It returns only one row for each person. I'm doing a left join - why is it adding an extra row? Shouldn't it only do that if I add a right join?

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  • SQL - Multiple join conditions using OR?

    - by Brandi
    I have a query that is using multiple joins. The goal is to say "Out of table A, give me all the customer numbers in which you can match table A's EmailAddress with either email_to or email_from of table B. Ignore nulls, internal emails, etc.". It seems like it would be better to use an or condition in the join than multiple joins since it is the same table. When I try to use AND/OR it does not give the behaviour I expect... AND finishes in a reasonable time, but yields no results (I know that there are matches, so it must be some flaw in my logic) and OR never finishes (I have to kill it). Here is example code to illustrate the question: --my original query SELECT DISTINCT a.CustomerNo FROM A a WITH (NOLOCK) LEFT JOIN B e WITH (NOLOCK) ON a.EmailAddress = e.email_from RIGHT JOIN B f WITH (NOLOCK) ON a.EmailAddress = f.email_to WHERE a.EmailAddress NOT LIKE '%@mydomain.___' AND a.EmailAddress IS NOT NULL AND (e.email_from IS NOT NULL OR f.email_to IS NOT NULL) Here is what I tried, (I am attempting logical equivalence): SELECT DISTINCT a.CustomerNo FROM A a WITH (NOLOCK) LEFT JOIN B e WITH (NOLOCK) ON a.EmailAddress = e.email_from OR a.EmailAddress = e.email_to WHERE a.EmailAddress NOT LIKE '%@mydomain.___' AND a.EmailAddress IS NOT NULL AND (e.email_from IS NOT NULL OR e.email_to IS NOT NULL) So my question is two-fold: Why does having AND in the above query work in a few seconds and OR goes for minutes and never completes? What am I missing to make a logically equivalent statement that has only one join?

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  • MySQL LEFT OUTER JOIN virtual table

    - by user1707323
    I am working on a pretty complicated query let me try to explain it to you. Here is the tables that I have in my MySQL database: students Table --- `students` --- student_id first_name last_name current_status status_change_date ------------ ------------ ----------- ---------------- -------------------- 1 John Doe Active NULL 2 Jane Doe Retread 2012-02-01 students_have_courses Table --- `students_have_courses` --- students_student_id courses_course_id s_date e_date int_date --------------------- ------------------- ---------- ---------- ----------- 1 1 2012-01-01 2012-01-04 2012-01-05 1 2 2012-01-05 NULL NULL 2 1 2012-01-10 2012-01-11 NULL students_have_optional_courses Table --- `students_have_optional_courses` --- students_student_id optional_courses_opcourse_id s_date e_date --------------------- ------------------------------ ---------- ---------- 1 1 2012-01-02 2012-01-03 1 1 2012-01-06 NULL 1 5 2012-01-07 NULL Here is my query so far SELECT `students_and_courses`.student_id, `students_and_courses`.first_name, `students_and_courses`.last_name, `students_and_courses`.courses_course_id, `students_and_courses`.s_date, `students_and_courses`.e_date, `students_and_courses`.int_date, `students_have_optional_courses`.optional_courses_opcourse_id, `students_have_optional_courses`.s_date, `students_have_optional_courses`.e_date FROM ( SELECT `c_s_a_s`.student_id, `c_s_a_s`.first_name, `c_s_a_s`.last_name, `c_s_a_s`.courses_course_id, `c_s_a_s`.s_date, `c_s_a_s`.e_date, `c_s_a_s`.int_date FROM ( SELECT `students`.student_id, `students`.first_name, `students`.last_name, `students_have_courses`.courses_course_id, `students_have_courses`.s_date, `students_have_courses`.e_date, `students_have_courses`.int_date FROM `students` LEFT OUTER JOIN `students_have_courses` ON ( `students_have_courses`.`students_student_id` = `students`.`student_id` AND (( `students_have_courses`.`s_date` >= `students`.`status_change_date` AND `students`.current_status = 'Retread' ) OR `students`.current_status = 'Active') ) WHERE `students`.current_status = 'Active' OR `students`.current_status = 'Retread' ) `c_s_a_s` ORDER BY `c_s_a_s`.`courses_course_id` DESC ) `students_and_courses` LEFT OUTER JOIN `students_have_optional_courses` ON ( `students_have_optional_courses`.students_student_id = `students_and_courses`.student_id AND `students_have_optional_courses`.s_date >= `students_and_courses`.s_date AND `students_have_optional_courses`.e_date IS NULL ) GROUP BY `students_and_courses`.student_id; What I want to be returned is the student_id, first_name, and last_name for all Active or Retread students and then LEFT JOIN the highest course_id, s_date, e_date, and int_date for the those students where the s_date is since the status_change_date if status is 'Retread'. Then LEFT JOIN the highest optional_courses_opcourse_id, s_date, and e_date from the students_have_optional_courses TABLE where the students_have_optional_courses.s_date is greater or equal to the students_have_courses.s_date and the students_have_optional_courses.e_date IS NULL Here is what is being returned: student_id first_name last_name courses_course_id s_date e_date int_date optional_courses_opcourse_id s_date_1 e_date_1 ------------ ------------ ----------- ------------------- ---------- ---------- ------------ ------------------------------ ---------- ---------- 1 John Doe 2 2012-01-05 NULL NULL 1 2012-01-06 NULL 2 Jane Doe NULL NULL NULL NULL NULL NULL NULL Here is what I want being returned: student_id first_name last_name courses_course_id s_date e_date int_date optional_courses_opcourse_id s_date_1 e_date_1 ------------ ------------ ----------- ------------------- ---------- ---------- ------------ ------------------------------ ---------- ---------- 1 John Doe 2 2012-01-05 NULL NULL 5 2012-01-07 NULL 2 Jane Doe NULL NULL NULL NULL NULL NULL NULL Everything is working except one thing, I cannot seem to get the highest students_have_optional_courses.optional_courses_opcourse_id no matter how I form the query Sorry, I just solved this myself after writing this all out I think it helped me think of the solution. Here is the solution query: SELECT `students_and_courses`.student_id, `students_and_courses`.first_name, `students_and_courses`.last_name, `students_and_courses`.courses_course_id, `students_and_courses`.s_date, `students_and_courses`.e_date, `students_and_courses`.int_date, `students_optional_courses`.optional_courses_opcourse_id, `students_optional_courses`.s_date, `students_optional_courses`.e_date FROM ( SELECT `c_s_a_s`.student_id, `c_s_a_s`.first_name, `c_s_a_s`.last_name, `c_s_a_s`.courses_course_id, `c_s_a_s`.s_date, `c_s_a_s`.e_date, `c_s_a_s`.int_date FROM ( SELECT `students`.student_id, `students`.first_name, `students`.last_name, `students_have_courses`.courses_course_id, `students_have_courses`.s_date, `students_have_courses`.e_date, `students_have_courses`.int_date FROM `students` LEFT OUTER JOIN `students_have_courses` ON ( `students_have_courses`.`students_student_id` = `students`.`student_id` AND (( `students_have_courses`.`s_date` >= `students`.`status_change_date` AND `students`.current_status = 'Retread' ) OR `students`.current_status = 'Active') ) WHERE `students`.current_status = 'Active' OR `students`.current_status = 'Retread' ) `c_s_a_s` ORDER BY `c_s_a_s`.`courses_course_id` DESC ) `students_and_courses` LEFT OUTER JOIN ( SELECT * FROM `students_have_optional_courses` ORDER BY `students_have_optional_courses`.optional_courses_opcourse_id DESC ) `students_optional_courses` ON ( `students_optional_courses`.students_student_id = `students_and_courses`.student_id AND `students_optional_courses`.s_date >= `students_and_courses`.s_date AND `students_optional_courses`.e_date IS NULL ) GROUP BY `students_and_courses`.student_id;

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  • LINQ-to-SQL - Join, Count

    - by ile
    I have following query: var result = ( from role in db.Roles join user in db.Users on role.RoleID equals user.RoleID where user.CreatedByUserID == userID orderby user.FirstName ascending select new UserViewModel { UserID = user.UserID, PhotoID = user.PhotoID.ToString(), FirstName = user.FirstName, LastName = user.LastName, FullName = user.FirstName + " " + user.LastName, Email = user.Email, PhoneNumber = user.Phone, AccessLevel = role.Name }); Now, I need to modify this query... Other table I have is table Deals. I would like to count how many deals user created last month and last year. I tried something like this: var result = ( from role in db.Roles join user in db.Users on role.RoleID equals user.RoleID //join dealsYear in db.Deals on date.Year equals dealsYear.DateCreated.Year join dealsYear in ( from deal in db.Deals group deal by deal.DateCreated into d select new { DateCreated = d.Key, dealsCount = d.Count() } ) on date.Year equals dealsYear.DateCreated.Year into dYear join dealsMonth in ( from deal in db.Deals group deal by deal.DateCreated into d select new { DateCreated = d.Key, dealsCount = d.Count() } ) on date.Month equals dealsMonth.DateCreated.Month into dMonth where user.CreatedByUserID == userID orderby user.FirstName ascending select new UserViewModel { UserID = user.UserID, PhotoID = user.PhotoID.ToString(), FirstName = user.FirstName, LastName = user.LastName, FullName = user.FirstName + " " + user.LastName, Email = user.Email, PhoneNumber = user.Phone, AccessLevel = role.Name, DealsThisYear = dYear, DealsThisMonth = dMonth }); but here is even syntax not correct. Any idea? Btw, is there any good book of LINQ to SQL with examples?

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  • error with linq join

    - by Luca Romagnoli
    I have this linq query: var segreterie = from s in db.USR_Utenti join h in db.USR_Accounts on new {s.ID, settings.GruppoSegreteria} equals new {h.USR_UtentiReference,h.ID_Gruppo} select s; that has this problem: The type of one of the expressions in the join clause is incorrect. Type inference failed in the call to 'Join'. how can i do to solve it?

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  • Why is my left join not returning nulls?

    - by Griz
    In sql server 2008, I have the following query: select c.title as categorytitle, s.title as subcategorytitle, i.title as itemtitle from categories c join subcategories s on c.categoryid = s.categoryid left join itemcategories ic on s.subcategoryid = ic.subcategoryid left join items i on ic.itemid = i.itemid where (ic.isactive = 1 or ic.isactive is null) and i.siteid = 132 order by c.title, s.title I am trying to get items in their subcategories, but I still want to return a record if there are no items in the category or subcategory. Subcategories that have no items are never returned. What am I doing wrong? Thank you EDIT Modified query with a second left join and where clause, but it's still not returning nulls. :/

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  • join query with lowstock products with another table in magento

    - by muralikalpana
    I want to display some attributes in reports/products/lowstock grid. here how can i join another table with lowstock product id? here is the query /** @var $collection Mage_Reports_Model_Resource_Product_Lowstock_Collection */ $collection = Mage::getResourceModel('reports/product_lowstock_collection') ->addAttributeToSelect('*') ->setStoreId($storeId) ->filterByIsQtyProductTypes() ->joinInventoryItem('qty') ->joinInventoryItem('low_stock_date') ->useManageStockFilter($storeId) ->useNotifyStockQtyFilter($storeId) ->setOrder('qty', Varien_Data_Collection::SORT_ORDER_ASC); here i have to join with this productid with another table. i am not getting results if i use this query. $collection->getSelect()->join(array('t2' => 'lowstockorders'),'lowstock_inventory_item.product_id = t2.product_id','t2.product_id'); please anybody tell me how to join these tables thanks, murali

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  • multiple join query in entity framework

    - by gvLearner
    I have following tables tasks id | name | proj_id 1 | task1 | 1 2 | task2 | 1 3 | task3 | 1 projects id | name 1 | sample proj1 2 | demo project budget_versions id | version_name| proj_id 1 | 50 | 1 budgets id | cost | budget_version_id | task_id 1 | 3000 | 1 | 2 2 | 5000 | 1 | 1 I need to join these tables to get a result as below task_id | task_name | project_id | budget_version | budget_id | cost 1 | task1 | 1 | 1 | 2 |5000 2 | task2 | 1 | 1 | 1 |3000 3 | task3 | 1 | NULL | NULL |NULL select tsk.id,tsk.name, tsk.project_id, bgtver.id, bgt.id, bgt.cost from TASK tsk left outer join BUDGET_VERSIONS bgtver on tsk.project_id= bgtver.project_id left outer join BUDGETS bgt on bgtver.id = bgt.budget_version_id and tsk.id = bgt.task_id where bgtver.id = 1

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  • Filezilla Install Problem: Hash Sum Mismatch

    - by kyleskool
    I'm new to the Ubuntu scene, and I tried to install Filezilla today by going to terminal and typing "sudo apt-get install filezilla", and got this error: Failed to fetch http://us.archive.ubuntu.com/ubuntu/pool/universe/w/wxwidgets2.8/libwxbase2.8-0_2.8.12.1-6ubuntu2_amd64.deb Hash Sum mismatch Failed to fetch http://us.archive.ubuntu.com/ubuntu/pool/universe/w/wxwidgets2.8/libwxgtk2.8-0_2.8.12.1-6ubuntu2_amd64.deb Hash Sum mismatch Failed to fetch http://universe/t/tinyxml/libtinyxml2.6.2_2.6.2-1build1_amd64.deb Hash Sum mismatch Failed to fetch http://universe/f/filezilla/filezilla-common_3.5.3-1ubuntu2_all.deb Hash Sum mismatch Failed to fetch http://universe/f/filezilla/filezilla_3.5.3-1ubuntu2_amd64.deb Hash Sum mismatch E: Unable to fetch some archives, maybe run apt-get update or try with --fix-missing? Running it again with "--fix-missing" appended to the command didn't work, nor did running apt-get update. Any suggestion? Thanks!

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  • Good hash function for a 2d index

    - by rlbond
    I have a struct called Point. Point is pretty simple: struct Point { Row row; Column column; // some other code for addition and subtraction of points is there too } Row and Column are basically glorified ints, but I got sick of accidentally transposing the input arguments to functions and gave them each a wrapper class. Right now I use a set of points, but repeated lookups are really slowing things down. I want to switch to an unordered_set. So, I want to have an unordered_set of Points. Typically this set might contain, for example, every point on a 80x24 terminal = 1920 points. I need a good hash function. I just came up with the following: struct PointHash : public std::unary_function<Point, std::size_t> { result_type operator()(const argument_type& val) const { return val.row.value() * 1000 + val.col.value(); } }; However, I'm not sure that this is really a good hash function. I wanted something fast, since I need to do many lookups very quickly. Is there a better hash function I can use, or is this OK?

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  • Python minidom and UTF-8 encoded XML with hash references

    - by Jakob Simon-Gaarde
    Hi I am experiencing some difficulty in my home project where I need to parse a SOAP request. The SOAP is generated with gSOAP and involves string parameters with special characters like the danish letters "æøå". gSOAP builds SOAP requests with UTF-8 encoding by default, but instead of sending the special chatacters in raw format (ie. bytes C3A6 for the special character "æ") it sends what I think is called character hash references (ie. &#195;&#166;). I don't completely understand why gSOAP does it this way as I can see that it has marked the incomming payload as being UTF-8 encoded anyway (Content-Type: text/xml; charset=utf-8), but this is besides the question (I think). Anyway I guess gSOAP probably is obeying transport rules, or what? When I parse the request from gSOAP in python with xml.dom.minidom.parseString() I get element values as unicode objects which is fine, but the character hash references are not decoded as UTF-8 character codes. It unescapes the character hash references, but does not decode the string afterwards. In the end I have a unicode string object with UTF-8 encoding: So if the string "æble" is contained in the XML, it comes like this in the request: "&#195;&#166;ble" After parsing the XML the unicode string in the DOM Text Node's data member looks like this: u'\xc3\xa6ble' I would expect it to look like this: u'\xe6ble' What am I doing wrong? Should I unescape the SOAP XML before parsing it, or is it somewhere else I should be looking for the solution, maybe gSOAP? Thanks in advance. Best regards Jakob Simon-Gaarde

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  • How to create Hash object/array using jquery?

    - by Patrick
    Hi folks I know there is a Hash() object in the Javascript prototype framework, but is there anything in Jquery like this? As I would like to stick with one javascript framework, rather than mixing the Prototype Frame work and the JQuery framework and use at the same time, as I worry there will be conflict and create side-effects. So my question is: how to create Hash object/array using jquery? Here is my function: /* prototype framework, I want to change this to jQuery! */ var starSaves = new Hash(); function myHover(id, pos) { var starStrip = $('star_strip_' + id); if (starSaves.keys().indexOf(id) == -1) { var starSave = new Array(); var imgs = starStrip.select("img") alert(imgs); for (var i = 0; i < imgs.length; i++) { starSave[starSave.length] = imgs[i].src; if (i < pos) imgs[i].src = "/images/star_1.gif"; else imgs[i].src = "/images/star_0.gif"; } starSaves.set(id, starSave); } }

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  • Join mp4 files in linux

    - by Jose Armando
    I want to join two mp4 files to create a single one. The video streams are encoded in h264 and the audio in aac. I can not re-encode the videos to another format due to computational reasons. Also, I cannot use any gui programs, all processing must be performed with linux command line utilities. FFmpeg cannot do this for mpeg4 files so instead I used MP4Box e.g. MP4Box -add video1.mp4 -cat video2.mp4 newvideo.mp4 unfortunately the audio gets all mixed up. I thought that the problem was that the audio was in aac so I transcoded it in mp3 and used again MP4Box. In this case the audio is fine for the first half of newvideo.mp4 (corresponding to video1.mp4) but then their is no audio and I cannot navigate in the video also. My next thought was that the audio and video streams had some small discrepancies in their lengths that I should fix. So for each input video I splitted the video and audio streams and then joined them with the -shortest option in ffmpeg. thus for the first video I ran avconv -y -i video1.mp4 -c copy -map 0:0 videostream1.mp4 avconv -y -i video1.mp4 -c copy -map 0:1 audiostream1.m4a avconv -y -i videostream1.mp4 -i audiostream1.m4a -c copy -shortest video1_aligned.mp4 similarly for the second video and then used MP4Box as previously. Unfortunately this didn't work either. The only success I had was when I joined the video streams separetely (i.e. videostream1.mp4 and videostream2.mp4) and the audio streams (i.e. audiostream1.m4a and audiostream2.m4a) and then joined the video and audio in a final file. However, the synchronization is lost for the second half of the video. Concretelly, there is a 1 sec delay of audio and video. Any suggestions are really welcome.

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  • Convert your Hash keys to object properties in Ruby

    - by kerry
    Being a Ruby noob (and having a background in Groovy), I was a little surprised that you can not access hash objects using the dot notation.  I am writing an application that relies heavily on XML and JSON data.  This data will need to be displayed and I would rather use book.author.first_name over book[‘author’][‘first_name’].  A quick search on google yielded this post on the subject. So, taking the DRYOO (Don’t Repeat Yourself Or Others) concept.  I came up with this: 1: class ::Hash 2:  3: # add keys to hash 4: def to_obj 5: self.each do |k,v| 6: if v.kind_of? Hash 7: v.to_obj 8: end 9: k=k.gsub(/\.|\s|-|\/|\'/, '_').downcase.to_sym 10: self.instance_variable_set("@#{k}", v) ## create and initialize an instance variable for this key/value pair 11: self.class.send(:define_method, k, proc{self.instance_variable_get("@#{k}")}) ## create the getter that returns the instance variable 12: self.class.send(:define_method, "#{k}=", proc{|v| self.instance_variable_set("@#{k}", v)}) ## create the setter that sets the instance variable 13: end 14: return self 15: end 16: end This works pretty well.  It converts each of your keys to properties of the Hash.  However, it doesn’t sit very well with me because I probably will not use 90% of the properties most of the time.  Why should I go through the performance overhead of creating instance variables for all of the unused ones? Enter the ‘magic method’ #missing_method: 1: class ::Hash 2: def method_missing(name) 3: return self[name] if key? name 4: self.each { |k,v| return v if k.to_s.to_sym == name } 5: super.method_missing name 6: end 7: end This is a much cleaner method for my purposes.  Quite simply, it checks to see if there is a key with the given symbol, and if not, loop through the keys and attempt to find one. I am a Ruby noob, so if there is something I am overlooking, please let me know.

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  • ruby hash problem

    - by sameera207
    HI All I have the following hash {:charge_payable_response={:return="700", :ns2="http://ws.myws.com/"}} How can i get the value of the key :return (700) thanks in advance cheers sameera

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  • How do I delete a [sub]hash based off of the keys/values of another hash?

    - by Zack
    Lets assume I have two hashes. One of them contains a set of data that only needs to keep things that show up in the other hash. e.g. my %hash1 = ( test1 => { inner1 => { more => "alpha", evenmore => "beta" } }, test2 => { inner2 => { more => "charlie", somethingelse => "delta" } }, test3 => { inner9999 => { ohlookmore => "golf", somethingelse => "foxtrot" } } ); my %hash2 = ( major=> { test2 => "inner2", test3 => "inner3" } ); What I would like to do, is to delete the whole subhash in hash1 if it does not exist as a key/value in hash2{major}, preferably without modules. The information contained in "innerX" does not matter, it merely must be left alone (unless the subhash is to be deleted then it can go away). In the example above after this operation is preformed hash1 would look like: my %hash1 = ( test2 => { inner2 => { more => "charlie", somethingelse => "delta" } }, ); It deletes hash1{test1} and hash1{test3} because they don't match anything in hash2. Here's what I've currently tried, but it doesn't work. Nor is it probably the safest thing to do since I'm looping over the hash while trying to delete from it. However I'm deleting at the each which should be okay? This was my attempt at doing this, however perl complains about: Can't use string ("inner1") as a HASH ref while "strict refs" in use at while(my ($test, $inner) = each %hash1) { if(exists $hash2{major}{$test}{$inner}) { print "$test($inner) is in exists.\n"; } else { print "Looks like $test($inner) does not exist, REMOVING.\n"; #not to sure if $inner is needed to remove the whole entry delete ($hash1{$test}{$inner}); } }

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  • Adding one subquery makes query a little slower, adding another makes it way slower

    - by Jason Swett
    This is fast: select ba.name, penamt.value penamt, #address_line4.value address_line4 from account a join customer c on a.customer_id = c.id join branch br on a.branch_id = br.id join bank ba on br.bank_id = ba.id join account_address aa on aa.account_id = a.id join address ad on aa.address_id = ad.id join state s on ad.state_id = s.id join import i on a.import_id = i.id join import_bundle ib on i.import_bundle_id = ib.id join (select * from unused where heading_label = 'PENAMT') penamt ON penamt.account_id = a.id #join (select * from unused where heading_label = 'Address Line 4') address_line4 ON address_line4.account_id = a.id where i.active=1 And this is fast: select ba.name, #penamt.value penamt, address_line4.value address_line4 from account a join customer c on a.customer_id = c.id join branch br on a.branch_id = br.id join bank ba on br.bank_id = ba.id join account_address aa on aa.account_id = a.id join address ad on aa.address_id = ad.id join state s on ad.state_id = s.id join import i on a.import_id = i.id join import_bundle ib on i.import_bundle_id = ib.id #join (select * from unused where heading_label = 'PENAMT') penamt ON penamt.account_id = a.id join (select * from unused where heading_label = 'Address Line 4') address_line4 ON address_line4.account_id = a.id where i.active=1 But this is slow: select ba.name, penamt.value penamt, address_line4.value address_line4 from account a join customer c on a.customer_id = c.id join branch br on a.branch_id = br.id join bank ba on br.bank_id = ba.id join account_address aa on aa.account_id = a.id join address ad on aa.address_id = ad.id join state s on ad.state_id = s.id join import i on a.import_id = i.id join import_bundle ib on i.import_bundle_id = ib.id join (select * from unused where heading_label = 'PENAMT') penamt ON penamt.account_id = a.id join (select * from unused where heading_label = 'Address Line 4') address_line4 ON address_line4.account_id = a.id where i.active=1 Why is it fast when I include just one of the two subqueries but slow when I include both? I would think it should be twice as slow when I include both, but it takes a really long time. On on MySQL.

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  • Perl, creating a hash of hashes.

    - by Mike
    Based on my current understanding of hashes in Perl, I would expect this code to print "hello world." It instead prints nothing. %a=(); %b=(); $b{str} = "hello"; $a{1}=%b; $b=(); $b{str} = "world"; $a{2}=%b; print "$a{1}{str} $a{2}{str}"; I assume that a hash is just like an array, so why can't I make a hash contain another?

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  • Ruby method Array#<< not updating the array in hash

    - by Mladen Jablanovic
    Inspired by http://stackoverflow.com/questions/2552363/how-can-i-marshal-a-hash-with-arrays I wonder what's the reason that Array#<< won't work properly in the following code: h = Hash.new{Array.new} #=> {} h[0] #=> [] h[0] << 'a' #=> ["a"] h[0] #=> [] # why?! h[0] += ['a'] #=> ["a"] h[0] #=> ["a"] # as expected Does it have to do with the fact that << changes the array in-place, while Array#+ creates a new instance?

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  • Flattening hash into string in Ruby

    - by fahadsadah
    Is there a way to flatten a hash into a string, with optional delimiters between keys and values, and key/value pairs? For example, print {:a => :b, :c => :d}.flatten('=','&') should print a=b&c=d I wrote some code to do this, but I was wondering if there was a neater way: class Hash def flatten(keyvaldelimiter, entrydelimiter) string = "" self.each do |key, value| key = "#{entrydelimiter}#{key}" if string != "" #nasty hack string += "#{key}#{keyvaldelimiter}#{value}" end return string end end print {:a => :b, :c => :d}.flatten('=','&') #=> 'c=d&a=b' Thanks

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  • Perl, get all hash values

    - by Mike
    Let's say in Perl I have a list of hash references, and each is required to contain a certain field, let's say foo. I want to create a list that contains all the mappings of foo. If there is a hash that does not contain foo the process should fail. @hash_list = ( {foo=>1}, {foo=>2} ); my @list = (); foreach my $item (@hash_list) { push(@list,$item->{foo}); } #list should be (1,2); Is there a more concise way of doing this in Perl?

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  • Ruby: merge two hash as one and with value connected

    - by scalalala
    Hi guys: 2 hash: h1 = { "s1" => "2009-7-27", "s2" => "2010-3-6", "s3" => "2009-7-27" } h2 = { "s1" => "12:29:15", "s2" => "10:00:17", "s3" => "12:25:52" } I want to merge the two hash as one like this: h = { "s1" => "2009-7-27 12:29:15", "s2" => "2010-3-6 10:00:17", "s3" => "2009-7-27 2:25:52" } what is the best way to do this? thanks!

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