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  • iPhone: fast hash function for storing web images (url) as files (hashed filenames)

    - by Stefan Klumpp
    What is a fast hash function available for the iPhone to hash web urls (images)? I'd like to store the cached web image as a file with a hash as the filename, because I suppose the raw web url could contain strange characters that could cause problems on the file system. The hash function doesn't need to be cryptographic, but it definitely needs to be fast. Example: Input: http://www.calumetphoto.com/files/iccprofiles/icc-test-image.jpg Output: 3573ed9c4d3a5b093355b2d8a1468509 This was done by using MD5(), but since I don't know much about that topic I don't know if it is overkill (- slow).

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  • Get number of times in loop over Hash object

    - by Matt Huggins
    I have an object of type Hash that I want to loop over via hash.each do |key, value|. I would like to get the number of times I've been through the loop starting at 1. Is there a method similar to each that provides this (while still providing the hash key/value data), or do I need to create another counter variable to increment within the loop?

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  • Suggestions for library to hash passwords in JAVA

    - by DutrowLLC
    What JAVA library should I be using to Hash passwords for storage in a database? I was hoping to just take the plain text password, add a random salt, then store the salt and the hashed password in the database. Then when a user wanted to log in, I could just take their submitted password, add the random salt from their account information, hash it and see if it equates to the stored hash password with their account information.

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  • csv to hash data structure conversion using perl

    - by Kavya S
    1. Convert a .csv file to perlhash data structure Format of a .csv file: sw,s1,s2,s3,s4 ver,v1,v2,v3,v4 msword,v2,v3,v1,v1 paint,v4,v2,v3,v3 outlook,v1,v1,v3,v2 my perl script: #!/usr/local/bin/perl use strict; use warnings; use Data::Dumper; my %hash; open my $fh, '<', 'some_file.csv' or die "Cannot open: $!"; while (my $line = <$fh>) { $line =~ s/,,/-/; chomp ($line); my @array = split /,/, $line; my $key = shift @array; $hash{$key} = $line; $hash{$key} = \@array; } print Dumper(\%hash); close $fh; perl hash i.e output should look like: $sw_ver_db = { s1 => { msword => {ver => v2}, paint => {ver => v4}, outlook => {ver => v1}, }, s2 => { msword => {ver => v3}, paint => {ver => v2}, outlook => {ver => v1}, }, s3 => { msword => {ver =>v1}, paint => {ver =>v3}, outlook => {ver =>v3}, }, s4 => { msword => {ver =>v1}, paint => {ver =>v3}, outlook => {ver =>v2}, }, };

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  • Python program to search for specific strings in hash values (coding help)

    - by Diego
    Trying to write a code that searches hash values for specific string's (input by user) and returns the hash if searchquery is present in that line. Doing this to kind of just learn python a bit more, but it could be a real world application used by an HR department to search a .csv resume database for specific words in each resume. I'd like this program to look through a .csv file that has three entries per line (id#;applicant name;resume text) I set it up so that it creates a hash, then created a string for the resume text hash entry, and am trying to use the .find() function to return the entire hash for each instance. What i'd like is if the word "gpa" is used as a search query and it is found in s['resumetext'] for three applicants(rows in .csv file), it prints the id, name, and resume for every row that has it.(All three applicants) As it is right now, my program prints the first row in the .csv file(print resume['id'], resume['name'], resume['resumetext']) no matter what the searchquery is, whether it's in the resumetext or not. lastly, are there better ways to doing this, by searching word documents, pdf's and .txt files in a folder for specific words using python (i've just started reading about the re module and am wondering if this may be the route, rather than putting everything in a .csv file.) def find_details(id2find): resumes_f=open("resume_data.csv") for each_line in resumes_f: s={} (s['id'], s['name'], s['resumetext']) = each_line.split(";") resumetext = str(s['resumetext']) if resumetext.find(id2find): return(s) else: print "No data matches your search query. Please try again" searchquery = raw_input("please enter your search term") resume = find_details(searchquery) if resume: print resume['id'], resume['name'], resume['resumetext']

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  • How to hash and salt passwords

    - by Henrik Skogmo
    I realize that this topic have been brought up sometimes, but I find myself not entirely sure on the topic just yet. What I am wondering about how do you salt a hash and work with the salted hash? If the password is encrypted with a random generated salt, how can the we verify it when the user tries to authenticate? Do we need to store the generated hash in our database as well? Is there any specific way the salt preferably should be generated? Which encryption method is favored to be used? From what I hear sha256 is quite alright. And lastly, would it be an idea to have the hash "re-salted" when the user authenticates? Thank you!

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  • Hash default value not being used

    - by ba
    Today I tried the following snippets of code and I don't understand why I get different results between them. As far as I can understand they are the same. One uses the default value off Hash and the other snippet creates an empty array for the key before it'll be accessed. Anyone who understands what's going on? :) # Hash default if the key doesn't have a value set is an empty Array a = Hash.new([]) a[:key] << 2 # => [2] p a # => {} nil p a[:key] # => [2] # Explicitly add an array for all nodes before creating b = Hash.new b[:key] ||= [] b[:key] << 2 # => [2] p b # => {:key=>[2]}

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  • Built in python hash() function

    - by sm1
    Windows XP, Python 2.5: hash('http://stackoverflow.com') Result: 1934711907 Google App Engine (http://shell.appspot.com/): hash('http://stackoverflow.com') Result: -5768830964305142685 Why is that? How can I have a hash function which will give me same results across different platforms (Windows, Linux, Mac)?

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  • Remove the hash after Ajax loading (I'm ajaxing wordpress 8-) )

    - by Alberto
    Hi everybody, I followed this great tutorial to"ajax" my blog:http://www.deluxeblogtips.com/2010/05/how-to-ajaxify-wordpress-theme.html But it creates some problems and I think the problem is in the hash that ajax creates. So, after the content is loaded, how can I remove the hash from the url? I copy my code here: jQuery(document).ready(function($) { var $mainContent = $("#content"), siteUrl = "http://" + top.location.host.toString(), url = ''; $(document).delegate("a[href^='"+siteUrl+"']:not([href*=/wp-admin/]):not([href*=/wp-login.php]):not([href$=/feed/]):not([href*=/go.php]):not(.comment-reply-link)", "click", function() { location.hash = this.pathname; $('html, body').animate({scrollTop:0}, 'fast'); return false; }); $("#searchform").submit(function(e) { location.hash = '?s=' + $("#search").val(); e.preventDefault(); }); $(window).bind('hashchange', function(){ url = window.location.hash.substring(1); if (!url) { return; } url = url + " #inside"; $mainContent.html('<div id="loader">Caricamento in corso...</div>').load(url, function() { //$mainContent.animate({opacity: "1"}); scriptss(); }); }); $(window).trigger('hashchange'); }); Thank all very much!

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  • Error comparing hash to hashed mysql password (output values are equal)

    - by Charlie
    Im trying to compare a hashed password value in a mysql database with the hashed value of an inputted password from a login form. However, when I compare the two values it says they aren't equal. I removed the salt to simply, and then tested what the outputs were and got the same values $password1 = $_POST['password']; $hash = hash('sha256', $password1); ...connect to database, etc... $query = "SELECT * FROM users WHERE username = '$username1'"; $result = mysql_query($query); $userData = mysql_fetch_array($result); if($hash != $userData['password']) //incorrect password { echo $hash."|".$userData['password']; die(); } ...other code... Sample output: 7816ee6a140526f02289471d87a7c4f9602d55c38303a0ba62dcd747a1f50361| 7816ee6a140526f02289471d87a7c4f9602d55c38303a0ba62dcd747a1f50361 Any thoughts?

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  • SQL SERVER 2008 JOIN hints

    - by Nai
    Hi all, Recently, I was trying to optimise this query UPDATE Analytics SET UserID = x.UserID FROM Analytics z INNER JOIN UserDetail x ON x.UserGUID = z.UserGUID Estimated execution plan show 57% on the Table Update and 40% on a Hash Match (Aggregate). I did some snooping around and came across the topic of JOIN hints. So I added a LOOP hint to my inner join and WA-ZHAM! The new execution plan shows 38% on the Table Update and 58% on an Index Seek. So I was about to start applying LOOP hints to all my queries until prudence got the better of me. After some googling, I realised that JOIN hints are not very well covered in BOL. Therefore... Can someone please tell me why applying LOOP hints to all my queries is a bad idea. I read somewhere that a LOOP JOIN is default JOIN method for query optimiser but couldn't verify the validity of the statement? When are JOIN hints used? When the sh*t hits the fan and ghost busters ain't in town? What's the difference between LOOP, HASH and MERGE hints? BOL states that MERGE seems to be the slowest but what is the application of each hint? Thanks for your time and help people! I'm running SQL Server 2008 BTW. The statistics mentioned above are ESTIMATED execution plans.

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  • RAR Password recovery / hash extraction on Mac OS X

    - by Josh K
    I'm running Mac OS X 10.6.2 and have been handed a couple of old files that need to be extracted. Old backups or finances or bills I believe. They are RAR files, and password protected. Is there a way to extract the hash from these files so I can feed it into John The Ripper or Cain and Abel? Edit I have downloaded cRARk, but unfortunately nothing I have (SimplyRAR, RAR Expander, The Unarchiver) will extract it without a password. Can someone verify that I'm crazy and there is no password on the Mac version?

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  • RAR Password recovery / hash extraction on OS X

    - by Josh K
    I'm running 10.6.2 and have been handed a couple of old files that need to be extracted. Old backups or finances or bills I believe. They are RAR files, and password protected. Is there a way to extract the hash from these files so I can feed it into John The Ripper or Cain and Abel? Edit I have downloaded cRARk, but unfortunately nothing I have (SimplyRAR, RAR Expander, The Unarchiver) will extract it without a password. Can someone verify that I'm crazy and there is no password on the Mac version?

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  • Crawling an ajax based page with both a hash fragment and a meta tag

    - by Christofian
    According to google's documentation on crawling ajax based web pages, if a url contains a hash fragment, or something at the end of an url that looks like #helloworld, and if there is an ! after the #, as in #!helloworld, google will then request the url url?_escaped_fragment_=helloworld. I currently have an ajax based webpage that I want google to be able to crawl. Sometimes, the page uses hash fragments, and for those situations I set up the server so it will return an html snapshot for that page using _escaped_fragment_. However, that webpage often does not load a hash fragment, and when that happens the webpage still loads content using ajax. I couldn't find a good solution to enable ajax crawling for pages that sometimes have a hash fragment and sometimes don't. How can I tell google to use _escaped_fragment_ when there is a hash fragment, and to use something else to get an html snapshot of a page when there isn't a hash fragment?

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  • Salting a public hash

    - by Sathvik
    Does it make any sense at all to salt a hash which might be available publicly? It doesn't really make sense to me, but does anyone actually do that? UPDATE - Some more info: An acquaintance of mine has a common salted-hash function which he uses throughout his code. So I was wondering if it made any sense at-all, to do so. Here's the function he used: hashlib.sha256(string+SALT).hexdigest() Update2: Sorry if it wasn't clear. By available publicly I meant, that it is rendered in the HTML of the project (for linking, etc) & can thus be easily read by a third party. The project is a python based web-app which involves user-created pages which are tracked using their hashes like myproject.com/hash so thus revealing the hash publicly. So my question is, whether in any circumstances would any sane programmer salt such a hash? Question: Using hashlib.sha256(string+SALT).hexdigest() vs hashlib.sha256(string).hexdigest() , when the hash isn't a secret.

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  • Take most significant 8 bytes of the MD5 hash of a string as a long (in Ruby)

    - by Nate Murray
    Hey Friends, I'm trying to implement a java "hash" function in ruby. Here's the java side: import java.nio.charset.Charset; import java.security.MessageDigest; /** * @return most significant 8 bytes of the MD5 hash of the string, as a long */ protected long hash(String value) { byte[] md5hash; md5hash = md5Digest.digest(value.getBytes(Charset.forName("UTF8"))); long hash = 0L; for (int i = 0; i < 8; i++) { hash = hash << 8 | md5hash[i] & 0x00000000000000FFL; } return hash; } So far, my best guess in ruby is: # WRONG - doesn't work properly. #!/usr/bin/env ruby -wKU require 'digest/md5' require 'pp' md5hash = Digest::MD5.hexdigest("0").unpack("U*") pp md5hash hash = 0 0.upto(7) do |i| hash = hash << 8 | md5hash[i] & 0x00000000000000FF end pp hash Problem is, this ruby code doesn't match the java output. For reference, the above java code given these strings returns the corresponding long: "00038c53790ecedfeb2f83102e9115a522475d73" => -2059313900129568948 "0" => -3473083983811222033 "001211e8befc8ac22dd265ecaa77f8c227d0007f" => 3234260774580957018 Thoughts: I'm having problems getting the UTF8 bytes from the ruby string In ruby I'm using hexdigest, I suspect I should be using just digest instead The java code is taking the md5 of the UTF8 bytes whereas my ruby code is taking the bytes of the md5 (as hex) Any suggestions on how to get the exact same output in ruby?

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  • query for inner join of table 4.

    - by amol kadam
    hi.... I'm facing the problem of inner join of table 4 following is query given plz see & give me solution select INSURED.FNAME + ' ' + INSURED.LNAME AS MNAME ,INSURED.MEMBCODE as MEMBERCODE ,INSURED.POLICYNO AS POLICYNO ,INSURED.POLICYFRMDATE AS POLICYFROMDATE ,INSURED.POLICYTODATE AS POLICYTODATE , MEMBERSHIP.MRKEXTNAME AS MARKETINGEXECUTIVE ,MEMBERSHIP.EMPLOYEECOUNT AS EMPLOYEECOUNT ,INSURED.CLAIMID AS CLAIMID ,POLICY.POLICYTYPE ,POLICY.COVAMTHOSPITAL as SUMINSURED ,ORGANIZATION.ORGANIZATIONNAME from ((INSURED inner join MEMBERSHIP on MEMBERSHIP.MEMBERSHIPID=INSURED.MEMBERSHIPID) inner join POLICY on MEMBERSHIP.POLICYNAME=POLICY.POLICYNAME) inner join ORGANIZATION on ORGANIZATION.ORGANIZATIONID=MEMBERSHIP.ORGANIZATIONID WHERE INSUREDID=427

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  • nested join linq-to-sql queries

    - by ile
    var result = ( from contact in db.Contacts where contact.ContactID == id join referContactID in db.ContactRefferedBies on contact.ContactID equals referContactID.ContactID join referContactName in db.Contacts on contact.ContactID equals referContactID.ContactID orderby contact.ContactID descending select new ContactReferredByView { ContactReferredByID = referContactID.ContactReferredByID, ContactReferredByName = referContactName.FirstName + " " + referContactName.LastName }).Single(); Problem is in this line: join referContactName in db.Contacts on contact.ContactID equals referContactID.ContactID where referContactID.ContactID is called from the above join line. How to nest these two joins? Thanks in advance! Ile

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  • Join 2 children tables with a parent tables without duplicated

    - by user1847866
    Problem I have 3 tables: People, Phones and Emails. Each person has an UNIQUE ID, and each person can have multiple numbers or multiple emails. Simplified it looks like this: +---------+----------+ | ID | Name | +---------+----------+ | 5000003 | Amy | | 5000004 | George | | 5000005 | John | | 5000008 | Steven | | 8000009 | Ashley | +---------+----------+ +---------+-----------------+ | ID | Number | +---------+-----------------+ | 5000005 | 5551234 | | 5000005 | 5154324 | | 5000008 | 2487312 | | 8000009 | 7134584 | | 5000008 | 8451384 | +---------+-----------------+ +---------+------------------------------+ | ID | Email | +---------+------------------------------+ | 5000005 | [email protected] | | 5000005 | [email protected] | | 5000008 | [email protected] | | 5000008 | [email protected] | | 5000008 | [email protected] | | 8000009 | [email protected] | | 5000004 | [email protected] | +---------+------------------------------+ I am trying to joining them together without duplicates. It works great, when I try to join only Emails with People or only Phones with People. SELECT People.Name, People.ID, Phones.Number FROM People LEFT OUTER JOIN Phones ON People.ID=Phones.ID ORDER BY Name, ID, Number; +----------+---------+-----------------+ | Name | ID | Number | +----------+---------+-----------------+ | Steven | 5000008 | 8451384 | | Steven | 5000008 | 24887312 | | John | 5000005 | 5551234 | | John | 5000005 | 5154324 | | George | 5000004 | NULL | | Ashley | 8000009 | 7134584 | | Amy | 5000003 | NULL | +----------+---------+-----------------+ SELECT People.Name, People.ID, Emails.Email FROM People LEFT OUTER JOIN Emails ON People.ID=Emails.ID ORDER BY Name, ID, Email; +----------+---------+------------------------------+ | Name | ID | Email | +----------+---------+------------------------------+ | Steven | 5000008 | [email protected] | | Steven | 5000008 | [email protected] | | Steven | 5000008 | [email protected] | | John | 5000005 | [email protected] | | John | 5000005 | [email protected] | | George | 5000004 | [email protected] | | Ashley | 8000009 | [email protected] | | Amy | 5000003 | NULL | +----------+---------+------------------------------+ However, when I try to join Emails and Phones on People - I get this: SELECT People.Name, People.ID, Phones.Number, Emails.Email FROM People LEFT OUTER JOIN Phones ON People.ID = Phones.ID LEFT OUTER JOIN Emails ON People.ID = Emails.ID ORDER BY Name, ID, Number, Email; +----------+---------+-----------------+------------------------------+ | Name | ID | Number | Email | +----------+---------+-----------------+------------------------------+ | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | John | 5000005 | 5551234 | [email protected] | | John | 5000005 | 5551234 | [email protected] | | John | 5000005 | 5154324 | [email protected] | | John | 5000005 | 5154324 | [email protected] | | George | 5000004 | NULL | [email protected] | | Ashley | 8000009 | 7134584 | [email protected] | | Amy | 5000003 | NULL | NULL | +----------+---------+-----------------+------------------------------+ What happens is - if a Person has 2 numbers, all his emails are shown twice (They can not be sorted! which means they can not be removed by @last) What I want: Bottom line, playing with the @last, I want to end up with somethig like this, but @last won't work if I don't arrange ORDER columns in the righ way - and this seems like a big problem..Orderin the email column. Because seen from the example above: Steven has 2 phone number and 3 emails. The JOIN Emails with Numbers happens with each email - thus duplicated values that can not be sorted (SORT BY does not work on them). **THIS IS WHAT I WANT** +----------+---------+-----------------+------------------------------+ | Name | ID | Number | Email | +----------+---------+-----------------+------------------------------+ | Steven | 5000008 | 8451384 | [email protected] | | | | 24887312 | [email protected] | | | | | [email protected] | | John | 5000005 | 5551234 | [email protected] | | | | 5154324 | [email protected] | | George | 5000004 | NULL | [email protected] | | Ashley | 8000009 | 7134584 | [email protected] | | Amy | 5000003 | NULL | NULL | +----------+---------+-----------------+------------------------------+ Now I'm told that it's best to keep emails and number in separated tables because one can have many emails. So if it's such a common thing to do, what isn't there a simple solution? I'd be happy with a PHP Solution aswell. What I know how to do by now that satisfies it, but is not as pretty. If I do it with GROUP_CONTACT I geat a satisfactory result, but it doesn't look as pretty: I can't put a "Email type = work" next to it. SELECT People.Ime, GROUP_CONCAT(DISTINCT Phones.Number), GROUP_CONCAT(DISTINCT Emails.Email) FROM People LEFT OUTER JOIN Phones ON People.ID=Phones.ID LEFT OUTER JOIN Emails ON People.ID=Emails.ID GROUP BY Name; +----------+----------------------------------------------+---------------------------------------------------------------------+ | Name | GROUP_CONCAT(DISTINCT Phones.Number) | GROUP_CONCAT(DISTINCT Emails.Email) | +----------+----------------------------------------------+---------------------------------------------------------------------+ | Steven | 8451384,24887312 | [email protected],[email protected],[email protected] | | John | 5551234,5154324 | [email protected],[email protected] | | George | NULL | [email protected] | | Ashley | 7134584 | [email protected] | | Amy | NULL | NULL | +----------+----------------------------------------------+---------------------------------------------------------------------+

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  • perl : Passing hash , array through socket program betwen client and server

    - by pavun_cool
    Hi All . In sockets I have written the client server program . First I tried to send the normal string among them it sends fine . After that I am trying to send the hash and array values from client to server and server to client . When I printing the values using Dumper . It is giving me only reference . What Should I do for getting accessing the actual values in client server . Server Program: use IO::Socket; use strict; use warnings; my %hash = ( "name" => "pavunkumar " , "age" => 20 ) ; my $new = \%hash ; #Turn on System variable for Buffering output $| = 1; # Creating a a new socket my $socket= IO::Socket::INET->new(LocalPort=>5000,Proto=>'tcp',Localhost => 'localhost','Listen' => 5 , 'Reuse' => 1 ); die "could not create $! \n" unless ( $socket ); print "\nUDPServer Waiting port 5000\n"; my $new_sock = $socket->accept(); my $host = $new_sock->peerhost(); while(<$new_sock>) { #my $line = <$new_sock>; print Dumper "$host $_"; print $new_sock $new . "\n"; } print "$host is closed \n" ; Client Program use IO::Socket; use Data::Dumper ; use warnings ; use strict ; my %hash = ( "file" =>"log.txt" , size => "1000kb") ; my $ref = \%hash ; # This client for connecting the specified below address and port # INET function will create the socket file and establish the connection with # server my $port = shift || 5000 ; my $host = shift || 'localhost'; my $recv_data ; my $send_data; my $socket = new IO::Socket::INET ( PeerAddr => $host , PeerPort => $port , Proto => 'tcp', ) or die "Couldn't connect to Server\n"; while (1) { my $line = <stdin> ; print $socket $ref."\n"; if ( $line = <$socket> ) { print Dumper $line ; } else { print "Server is closed \n"; last ; } } I have given my sample program about what I am doing , Can any one tell me what I am doing wrong in this code. And what I need to do for accessing the hash values . Thanks in Advance

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  • "Too much recursion" error when loading the same page with a hash

    - by Elliott
    Hi, I have a site w/ an image gallery ("Portfolio") page. There is drop-down navigation that allows a user to view a specific image in the portfolio from any page on the site. The links in the navigation use a hash, and that hash is read and converted into a string of an image filename. The image src attribute on the /portfolio/ page is then swapped out with the new image filename. This works fine if I'm clicking the dropdown link from a page OTHER THAN the /portfolio/ page itself. However if I take the same action from the /portfolio/ page, I get a "too much recursion" error in Firefox. Here's the code: Snippet of the nav markup: <li>Portfolio Category A <ul> <li><a href="/portfolio/#dining-room-table">Dining Room Table</a></li> <li><a href="/portfolio/#bathroom-mirror">Bathroom Mirror</a></li> </ul> </li> JS that reads the hash, converts it to an image filename, and swaps out the image on the page: $(document).ready(function() { if(location.pathname.indexOf("/portfolio/") > -1) { var hash = location.hash; var new_image = hash.replace("#", "")+".jpg"; swapImage(new_image); } }); function swapImage(new_image) { setTimeout(function() { $("img#current-image").attr("src", "/images/portfolio/work/"+new_image); }, 100); } I'm using the setTimeout function because I'm fading out the old image before making the swap, then fading it back in. I initially thought this was the function that was causing the recursion error, but when I remove the setTimeout I still have this problem. Does this have to do with a closure I'm not aware of? I'm pretty green on closures. JS that listens for the click on the nav: $("nav.main li.dropdown li ul li").click(function() { $(this).find("a").click(); $("nav.main").find("ul ul").hide(); $("nav.main li.hover").removeClass("hover"); }); I haven't implemented the fade in/out functionality for the dropdown nav yet, but I have implemented it for Next and Previous arrows, which can also be used to swap out images using the same swapImage function. Here's that code: $("#scroll-arrows a").click(function() { $("#current-image").animate({ opacity: 0 }, 100); var current_image = $("#current-image").attr("src").split("/").pop(); var new_image; var positions = getPositions(current_image); if($(this).is(".right")) { new_image = positions.next_img; } else { new_image = positions.prev_img; } swapImage(new_image); $("#current-image").animate({ opacity: 1 }, 100); return false; }); Here's the error I'm getting in Firefox: too much recursion var ret = handleObj.handler.apply( this, arguments ); jquery.js (line 1936) Thanks for any advice.

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  • Inner Join with more than a field

    - by Leandro
    Precise to do a select with inner join that has relationship in more than a field among the tables Exemple: DataSet dt = new Select().From(SubConta.Schema) .InnerJoin(PlanoContabilSubConta.EmpSubContaColumn, SubConta.CodEmpColumn) .InnerJoin(PlanoContabilSubConta.FilSubContaColumn, SubConta.CodFilColumn) .InnerJoin(PlanoContabilSubConta.SubContaColumn, SubConta.TradutorColumn) .Where(PlanoContabilSubConta.Columns.EmpContabil).IsEqualTo(cEmp) .And(PlanoContabilSubConta.Columns.FilContabil).IsEqualTo(cFil) .And(PlanoContabilSubConta.Columns.Conta).IsEqualTo(cTrad) .ExecuteDataSet(); But the generated sql is wrong: exec sp_executesql N'/* GetDataSet() */ SELECT [dbo].[SubContas].[CodEmp], [dbo].[SubContas].[CodFil], [dbo].[SubContas].[Tradutor], [dbo].[SubContas].[Descricao], [dbo].[SubContas].[Inativa], [dbo].[SubContas].[DataImplantacao] FROM [dbo].[SubContas] INNER JOIN [dbo].[PlanoContabilSubContas] ON [dbo].[SubContas].[CodEmp] = [dbo].[PlanoContabilSubContas].[EmpSubConta] INNER JOIN [dbo].[PlanoContabilSubContas] ON [dbo].[SubContas].[CodFil] = [dbo].[PlanoContabilSubContas].[FilSubConta] INNER JOIN [dbo].[PlanoContabilSubContas] ON [dbo].[SubContas].[Tradutor] = [dbo].[PlanoContabilSubContas].[SubConta] WHERE EmpContabil = @EmpContabil0 AND FilContabil = @FilContabil1 AND Conta = @Conta2 ',N'@EmpContabil0 varchar(1),@FilContabil1 varchar(1),@Conta2 varchar(1)',@EmpContabil0='1',@FilContabil1='1',@Conta2='1' What should be made to generate this sql? exec sp_executesql N'/* GetDataSet() */ SELECT [dbo].[SubContas].[CodEmp], [dbo].[SubContas].[CodFil], [dbo].[SubContas].[Tradutor], [dbo].[SubContas].[Descricao], [dbo].[SubContas].[Inativa], [dbo].[SubContas].[DataImplantacao] FROM [dbo].[SubContas] INNER JOIN [dbo].[PlanoContabilSubContas] ON [dbo].[SubContas].[CodEmp] = [dbo].[PlanoContabilSubContas].[EmpSubConta] AND [dbo].[SubContas].[CodFil] = [dbo].[PlanoContabilSubContas].[FilSubConta] AND [dbo].[SubContas].[Tradutor] = [dbo].[PlanoContabilSubContas].[SubConta] WHERE EmpContabil = @EmpContabil0 AND FilContabil = @FilContabil1 AND Conta = @Conta2 ',N'@EmpContabil0 varchar(1),@FilContabil1 varchar(1),@Conta2 varchar(1)',@EmpContabil0='1',@FilContabil1='1',@Conta2='1'

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  • Difference b/w putting condition in JOIN clause versus WHERE clause

    - by user244953
    Suppose I have 3 tables. Sales Rep Rep Code First Name Last Name Phone Email Sales Team Orders Order Number Rep Code Customer Number Order Date Order Status Customer Customer Number Name Address Phone Number I want to get a detailed report of Sales for 2010. I would be doing a join. I am interested in knowing which of the following is more efficient and why ? SELECT O.OrderNum, R.Name, C.Name FROM Order O INNER JOIN Rep R ON O.RepCode = R.RepCode INNER JOIN Customer C ON O.CustomerNumber = C.CustomerNumber WHERE O.OrderDate >= '01/01/2010' OR SELECT O.OrderNum, R.Name, C.Name FROM Order O INNER JOIN Rep R ON (O.RepCode = R.RepCode AND O.OrderDate >= '01/01/2010') INNER JOIN Customer C ON O.CustomerNumber = C.CustomerNumber

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