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• Is it possible to convert striped logical volume to linear logical volume?

  - by JooMing

  I've a logical volume that is striped across three physical volumes. I had to move this logical volume to another physical volume. This worked nicely with pvmove command. However, I discovered later that the logical volume is still striped and now all three stripes are on the same physical volume. Is there any way to convert striped logical volumes to linear logical volumes? I'm using LVM2 on linux. I figured that the obvious possibility is to rename the striped logical volume, create a new linear logical volume, and then copy data over, but that requires taking the filesystem system offline for some time. Unfortunately, I can't do that before the next week. Is there any better alternative?

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• Is Linear Tape File System (LTFS) Best For Transportable Storage?

  - by rickramsey

  Those of us in tape storage engineering take a lot of pride in what we do, but understand that tape is the right answer to a storage problem only some of the time. And, unfortunately for a storage medium with such a long history, it has built up a few preconceived notions that are no longer valid. When I hear customers debate whether to implement tape vs. disk, one of the common strikes against tape is its perceived lack of usability. If you could go back a few generations of corporate acquisitions, you would discover that StorageTek engineers recognized this problem and started developing a solution where a tape drive could look just like a memory stick to a user. The goal was to not have to care about where files were on the cartridge, but to simply see the list of files that were on the tape, and click on them to open them up. Eventually, our friends in tape over at IBM built upon our work at StorageTek and Sun Microsystems and released the Linear Tape File System (LTFS) feature for the current LTO5 generation of tape drives as an open specification. LTFS is really a wonderful feature and we’re proud to have taken part in its beginnings and, as you’ll soon read, its future. Today we offer LTFS-Open Edition, which is free for you to use in your in Oracle Enterprise Linux 5.5 environment - not only on your LTO5 drives, but also on your Oracle StorageTek T10000C drives. You can download it free from Oracle and try it out. LTFS does exactly what its forefathers imagined. Now you can see immediately which files are on a cartridge. LTFS does this by splitting a cartridge into two partitions. The first holds all of the necessary metadata to create a directory structure for you to easily view the contents of the cartridge. The second partition holds all of the files themselves. When tape media is loaded onto a drive, a complete file system image is presented to the user. Adding files to a cartridge can be as simple as a drag-and-drop just as you do today on your laptop when transferring files from your hard drive to a thumb drive or with standard POSIX file operations. You may be thinking all of this sounds nice, but asking, “when will I actually use it?” As I mentioned at the beginning, tape is not the right solution all of the time. However, if you ever need to physically move data between locations, tape storage with LTFS should be your most cost-effective and reliable answer. I will give you a few use cases examples of when LTFS can be utilized. Media and Entertainment (M&E), Oil and Gas (O&G), and other industries have a strong need for their storage to be transportable. For example, an O&G company hunting for new oil deposits in remote locations takes very large underground seismic images which need to be shipped back to a central data center. M&E operations conduct similar activities when shooting video for productions. M&E companies also often transfers files to third-parties for editing and other activities. These companies have three highly flawed options for transporting data: electronic transfer, disk storage transport, or tape storage transport. The first option, electronic transfer, is impractical because of the expense of the bandwidth required to transfer multi-terabyte files reliably and efficiently. If there’s one place that has bandwidth, it’s your local post office so many companies revert to physically shipping storage media. Typically, M&E companies rely on transporting disk storage between sites even though it, too, is expensive. Tape storage should be the preferred format because as IDC points out, “Tape is more suitable for physical transportation of large amounts of data as it is less vulnerable to mechanical damage during transportation compared with disk" (See note 1, below). However, tape storage has not been used in the past because of the restrictions created by proprietary formats. A tape may only be readable if both the sender and receiver have the same proprietary application used to write the file. In addition, the workflows may be slowed by the need to read the entire tape cartridge during recall. LTFS solves both of these problems, clearing the way for tape to become the standard platform for transferring large files. LTFS is open and, as long as you’ve downloaded the free reader from our website or that of anyone in the LTO consortium, you can read the data. So if a movie studio ships a scene to a third-party partner to add, for example, sounds effects or a music score, it doesn’t have to care what technology the third-party has. If it’s written back to an LTFS-formatted tape cartridge, it can be read. Some tape vendors like to claim LTFS is a “standard,” but beauty is in the eye of the beholder. It’s a specification at this point, not a standard. That said, we’re already seeing application vendors create functionality to write in an LTFS format based on the specification. And it’s my belief that both customers and the tape storage industry will see the most benefit if we all follow the same path. As such, we have volunteered to lead the way in making LTFS a standard first with the Storage Network Industry Association (SNIA), and eventually through to standard bodies such as American National Standards Institute (ANSI). Expect to hear good news soon about our efforts. So, if storage transportability is one of your requirements, I recommend giving LTFS a look. It makes tape much more user-friendly and it’s free, which allows tape to maintain all of its cost advantages over disk! Note 1 - IDC Report. April, 2011. “IDC’s Archival Storage Solutions Taxonomy, 2011” - Brian Zents Website Newsletter Facebook Twitter

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• Are there IDEs in which the code-completion widget is not a linear list?

  - by Uri

  Most mainstream IDEs use code-completion in the form of a linear list of suggestions (typically methods). Are there any IDEs (mainstream or not) or IDE plugins that use a non-linear widget, such as a tree? (e.g., pick category first, then the actual recommendation)? I'm working on an IDE feature and want to make sure I'm not reinventing the wheel or infringing some patent.

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• Linear Interpolation. How to implement this algorithm in C ? (Python version is given)

  - by psihodelia

  There exists one very good linear interpolation method. It performs linear interpolation requiring at most one multiply per output sample. I found its description in a third edition of Understanding DSP by Lyons. This method involves a special hold buffer. Given a number of samples to be inserted between any two input samples, it produces output points using linear interpolation. Here, I have rewritten this algorithm using Python: temp1, temp2 = 0, 0 iL = 1.0 / L for i in x: hold = [i-temp1] * L temp1 = i for j in hold: temp2 += j y.append(temp2 *iL) where x contains input samples, L is a number of points to be inserted, y will contain output samples. My question is how to implement such algorithm in ANSI C in a most effective way, e.g. is it possible to avoid the second loop? NOTE: presented Python code is just to understand how this algorithm works. UPDATE: here is an example how it works in Python: x=[] y=[] hold=[] num_points=20 points_inbetween = 2 temp1,temp2=0,0 for i in range(num_points): x.append( sin(i*2.0*pi * 0.1) ) L = points_inbetween iL = 1.0/L for i in x: hold = [i-temp1] * L temp1 = i for j in hold: temp2 += j y.append(temp2 * iL) Let's say x=[.... 10, 20, 30 ....]. Then, if L=1, it will produce [... 10, 15, 20, 25, 30 ...]

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• Can a Highcharts range selector use non-date linear ranges?

  - by Simon

  I am using the HighStock JS lib to produce a chart that uses a linear series (not a time-series) for the xAxis. I'd still like to use the range-selector in order to zoom to pre-determined ranges within my linear series. Is this possible? For example; say my xAxis has a series: [[121,616],[122,600],[123,605],[124,585.5],[125,575.5],[126,580.5],[127,582],[128,582],[129,584],[130,583]] I'd like to use the range selector to zoom to the last n in the series.

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• How can I merge two lists and sort them working in 'linear' time?

  - by Sergio Tapia

  I have this, and it works: # E. Given two lists sorted in increasing order, create and return a merged # list of all the elements in sorted order. You may modify the passed in lists. # Ideally, the solution should work in "linear" time, making a single # pass of both lists. def linear_merge(list1, list2): finalList = [] for item in list1: finalList.append(item) for item in list2: finalList.append(item) finalList.sort() return finalList # +++your code here+++ return But, I'd really like to learn this stuff well. :) What does 'linear' time mean?

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• Is there a linear-time performance guarantee with using an Iterator?

  - by polygenelubricants

  If all that you're doing is a simple one-pass iteration (i.e. only hasNext() and next(), no remove()), are you guaranteed linear time performance and/or amortized constant cost per operation? Is this specified in the Iterator contract anywhere? Are there data structures/Java Collection which cannot be iterated in linear time? java.util.Scanner implements Iterator<String>. A Scanner is hardly a data structure (e.g. remove() makes absolutely no sense). Is this considered a design blunder? Is something like PrimeGenerator implements Iterator<Integer> considered bad design, or is this exactly what Iterator is for? (hasNext() always returns true, next() computes the next number on demand, remove() makes no sense). Similarly, would it have made sense for java.util.Random implements Iterator<Double>?

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• LVM vs RAID0 vs RAID "linear" - Combine 2 disks as one, data recovery?

  - by leto

  Hi there, given two 2TB USB external disks that have to be combined to one 4TB volume and formatted with one big Filesystem (XFS), I have a small question to ask. Does LVM provide better Data recovery, should one disk be unplugged/damaged by being able to recover the data of the still working disk or is everything lost? I would appreciate a solution where only the data of one disk is lost and I can recover the content of the other with the usual filesystem/lvm/raid tools. Is that possible with LVM or RAID "linear"? This is for storing unimportant files that can be retrieved from backup, but I want to save time :) Thank you in advance

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• What characteristic of networking/TCP causes linear relation between TCP activity and latency?

  - by DeLongey

  The core of this problem is that our application uses websockets for real-time interfaces. We are testing our app in a new environment but strangely we're noticing an increasing delay in TCP websocket packets associated with an increase in websocket activity. For example, if one websocket event occurs without any other activity in a 1-minute period, the response from the server is instantaneous. However, if we slowly increase client activity the latency in server response increases with a linear relationship (each packet will take more time to reach the client with more activity). For those wondering this is NOT app-related since our logs show that our server is running and responding to requests in under 100ms as desired. The delay starts once the server processes the request and creates the TCP packet and sends it to the client (and not the other way around). Architecture This new environment runs with a Virtual IP address and uses keepalived on a load balancer to balance the traffic between instances. Two boxes sit behind the balancer and all traffic runs through it. Our host provider manages the balancer and we do not have control over that part of the architecture. Theory Could this somehow be related to something buffering the packets in the new environment? Thanks for your help.

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• How do I find the median of numbers in linear time using heaps?

  - by eSKay

  Wikipedia says: Selection algorithms: Finding the min, max, both the min and max, median, or even the k-th largest element can be done in linear time using heaps. All it says is that it can be done, not how. Can you give me some start on how this can be done using heaps?

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• Does anybody have any tool to generate Linear temporal logic or CTL from sequence diagram?

  - by user326180

  I have a sequence diagram of an application. can anybody help to generate Linear temporal Logic or Computational tree logic from sequence diagram automatically or does anybody have any tool to do same. plz help Thanks in advance.

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• How to compute palindrome from a stream of characters in sub-linear space/time?

  - by wrick

  I don't even know if a solution exists or not. Here is the problem in detail. You are a program that is accepting an infinitely long stream of characters (for simplicity you can assume characters are either 1 or 0). At any point, I can stop the stream (let's say after N characters were passed through) and ask you if the string received so far is a palindrome or not. How can you do this using less sub-linear space and/or time.

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• At which n does binary search become faster than linear search on a modern CPU?

  - by joeforker

  Due to the wonders of branch prediction, a binary search can be slower than a linear search through an array of integers. On a typical desktop processor, how big does that array have to get before it would be better to use a binary search? Assume the structure will be used for many lookups.

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• linearRGB conversion to/from HSL

  - by Otaku

  Does anyone know of a way to get HSL from an linearRGB color (not an sRGB color)? I've seen a lot of sRGB<-HSL conversions, but nothing for linearRGB<-HSL. Not sure if it is fundementally the same conversion with minor tweaks, but I'd appreciate any insight someone may have on this. Linear RGB is not the same as linearizing sRGB (which is taking [0,255] and making it [0,1]). Linear RGB transformation from/to sRGB is at http://en.wikipedia.org/wiki/SRGB. In VBA, this would be expressed (taking in linearized sRGB values [0,1]): Public Function sRGB_to_linearRGB(value As Double) If value < 0# Then sRGB_to_linearRGB = 0# Exit Function End If If value <= 0.04045 Then sRGB_to_linearRGB = value / 12.92 Exit Function End If If value <= 1# Then sRGB_to_linearRGB = ((value + 0.055) / 1.055) ^ 2.4 Exit Function End If sRGB_to_linearRGB = 1# End Function Public Function linearRGB_to_sRGB(value As Double) If value < 0# Then linearRGB_to_sRGB = 0# Exit Function End If If value <= 0.0031308 Then linearRGB_to_sRGB = value * 12.92 Exit Function End If If value < 1# Then linearRGB_to_sRGB = 1.055 * (value ^ (1# / 2.4)) - 0.055 Exit Function End If linearRGB_to_sRGB = 1# End Function I have tried sending in Linear RGB values to standard RGB_to_HSL routines and back out from HSL_to_RGB, but it does not work. I have seen almost no references that this can be done, except for two: A reference on http://en.wikipedia.org/wiki/HSL_and_HSV#cite_note-9 (numbered item 10). A reference on an open source project Grafx2 @ http://code.google.com/p/grafx2/issues/detail?id=63#c22 in which the contributor states that he has done Linear RGB <- HSL conversion and provides some C code in an attachment to his comment in a .diff file (which I can't really read :( ) My intent is to send from sRGB (for example, FF99FF (R=255, G=153, B=255)) to Linear RGB (R=1.0, G=0.318546778125092, B=1.0) using the code above (for example, the G=153 would be obtained in Linear RGB from sRGB_to_linearRGB(153 / 255)) to HSL, modify the Saturation by 350% and going back from HSL-Linear RGB-sRGB, the result would be FF19FF (R=255, G=25, B=255). Using available functions from .NET, such as .getHue from a System.Drawing.Color does not work in any sRGB space above 100% modulation of any HSL value, hence the need for Linear RGB to be sent in instead of sRGB.

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• What's the correct way to represent a linear process in CocoaTouch (UIKit)?

  - by UloPe

  I need to represent a linear process (think wizard) in an iPad app. In principle I could use a UINavigationController and just keep pushing new controllers for each step of the process. But this seems rather inefficient since the process I'm modeling has no notion of navigating backwards so all previous views would pointlessly stay around and use up resources. At the moment I keep adding and removing a subview to one "master" viewcontroller and basically swapping out the contents. This works but feels rather clunky and I hope there is some nicer way to achieve this. Additionally there needs to be an animated transition between the views. (I have this working at the moment via beginAnimations / commitAnimations)

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• How would I go about setting a CSS gradient background in JavaScript?

  - by Dan

  The CSS gradient is described here, but I have no idea how to select for these properties in JavaScript. I would rather not use jQuery for this if at all possible. EDIT: Just doing the following doesn't seem to work... document.getElementById("selected-tab").style.background = "#860432"; document.getElementById("selected-tab").style.background = "-moz-linear-gradient(#b8042f, #860432)"; document.getElementById("selected-tab").style.background = "-o-linear-gradient(#b8042f, #860432)"; document.getElementById("selected-tab").style.background = "-webkit-gradient(linear, 0% 0%, 0% 100%, from(#b8042f), to(#860432))"; document.getElementById("selected-tab").style.background = "-webkit-linear-gradient(#b8042f, #860432)";

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• How to calculate continuous motion with angular velocity in 2d

  - by Rulk

  I'm really new with physics. Maybe someone would be able to help me to solve the next problem: I need to calculate position of an agent on the plane(2D) in next time step where time step is large(20+ seconds) What I know about agent's motion: Initial Position Direction(normalised vector) Velocity(linear function from time ) - object always moves along it's direction Angular Velocity(linear function from time) Optional: External force direction External force (linear function from time) Running discreet simulation with t-0 is not an option.

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• Full Screen Video Tumblr

  - by Kodi Lane

  I have a tumblr theme seen on http://www.kodilane.com and i am trying to make my Video Posts full screen. I have tried editing the code but i can only get the pictures to stretch. I have attached the template i have so far, if you can spot the changes that need to be done to make the video posts stretch full screen like the pictures do i would really appreciate it. Thank You - Kodi <!DOCTYPE html> <html lang="en"> <head> <title>{Title} {block:PostSummary}- {PostSummary}{/block:PostSummary}</title> <link rel="shortcut icon" href="{Favicon}"> <link rel="alternate" type="application/rss+xml" href="{RSS}"> {block:Description} <meta name="description" content="{MetaDescription}" /> {/block:Description} <meta http-equiv="content-type" content="text/html; charset=utf-8" /> {block:Posts} <meta name="if:Reverse Description" content="0"/> <meta name="if:Include Attribution" content="1"/> <meta name="image:Background" content="http://static.tumblr.com/ffvtarv/QxLlmnswt/kims4.jpeg"/> <meta name="font:Body" content="Arial, Helvetica, sans"/> <meta name="color:Body Text" content="#fff"/> <meta name="color:Link" content="#d5d5d5"/> <meta name="color:Hover" content="#fff"/> <style type="text/css"> html, body, div, span, applet, object, iframe, h1, h2, h3, h4, h5, h6, p, blockquote, pre, a, abbr, acronym, address, big, cite, code, del, dfn, em, img, ins, kbd, q, s, samp, small, strike, strong, sub, sup, tt, var, b, u, i, center, dl, dt, dd, ol, ul, li, fieldset, form, label, legend, table, caption, tbody, tfoot, thead, tr, th, td, article, aside, canvas, details, embed, figure, figcaption, footer, header, hgroup, menu, nav, output, ruby, section, summary, time, mark, audio, video { margin: 0; padding: 0; border: 0; font-size: 100%; font: inherit; vertical-align: baseline; } /* HTML5 display-role reset for older browsers */ article, aside, details, figcaption, figure, footer, header, hgroup, menu, nav, section { display: block; } body { line-height: 1; font-family: {font:Body}; } ol, ul, .bigcats li { list-style: none; } .main ol{ list-style:decimal; margin-left:25px; margin-bottom:10px; } .main ul{ list-style: disc; margin-left:25px; margin-bottom:10px; } blockquote, q { quotes: none; font-style: italic; padding:7px 7px; display:block; } ol.notes blockquote a{ line-height:22px; } blockquote:before, blockquote:after, q:before, q:after { content: ''; content: none; } table { border-collapse: collapse; border-spacing: 0; } strong{ color:#9d9d9d; font-weight: bold; } em{ font-style: italic; } {block:IfNotReverseDescription} .article{ max-width:420px; position:fixed; bottom:43px; right:0; } {/block:IfNotReverseDescription} {block:IfReverseDescription} .article{ max-width:420px; position:fixed; bottom:43px; left:0; } {/block:IfReverseDescription} h1, h2{ position:absolute; top:-9999px; left:-9999px; } .nav{ width:100%; padding: 10px 0px 10px 0px; text-align:left; z-index: 10; color:{color:Link}; margin-left:5px; } .navwrap{ background-color:#000; position:fixed; width:100%; bottom:0px; clear:both; /* Firefox 3.6+ */ background: -moz-linear-gradient(left, rgba(0, 0, 0, .5), rgba(0, 0, 0, 0.8)); /* Safari 4-5, Chrome 1-9 */ background: -webkit-gradient(linear, left top, right top, from(rgba(0, 0, 0, .5)), to(rgba(0, 0, 0, 0.8))); /* Safari 5.1+, Chrome 10+ */ background: -webkit-linear-gradient(left, rgba(0, 0, 0, .5), rgba(0, 0, 0, 0.8)); /* Opera 11.10+ */ background: -o-linear-gradient(left, rgba(0, 0, 0, .5), rgba(0, 0, 0, 0.8)); padding-bottom:2px; box-shadow:0px 0px 3px #000000; } .nav ul li{ display:inline; font-size:13px; text-transform:uppercase; color:{color:Link}; list-style:none; text-align:center; } .nav li{ list-style: none; } .nav ul li a, .nav ul li a:visited { color:{color:Link}; padding: 10px 10px 3px 10px; } .nav ul li a:hover{ color:{color:Hover}; } a{ text-decoration:none; } .main a{ border-bottom: 1px {color:Link} dotted; color: {color:Link}; padding: 0 1px; } .main a:hover, .main a:focus{ color:{color:Hover}; border-bottom: transparent 1px solid; } a:visited, .main a:visited, { color: {color:Link}; } a:active {outline: none;} ol.notes, ol.notes li{ margin-bottom:2px; line-height:16px; } .audiometa{ padding-bottom:10px; } h3.push{ margin-bottom:10px; } h3{ margin-bottom:10px; } h3 a{ margin-bottom:10px; font-size:16px; color:{color:Hover}; } .main, .tags{ color:{color:Body Text}; display:block; padding: 15px; font-size: 12px; line-height: 16px; text-align: left; /* fallback */ background-color: #000; /* Firefox 3.6+ */ background: -moz-linear-gradient(left, rgba(0, 0, 0, .8), rgba(0, 0, 0, 0.6)); /* Safari 4-5, Chrome 1-9 */ background: -webkit-gradient(linear, left top, right top, from(rgba(0, 0, 0, .8)), to(rgba(0, 0, 0, 0.6))); /* Safari 5.1+, Chrome 10+ */ background: -webkit-linear-gradient(left, rgba(0, 0, 0, .8), rgba(0, 0, 0, 0.6)); /* Opera 11.10+ */ background: -o-linear-gradient(left, rgba(0, 0, 0, .8), rgba(0, 0, 0, 0.6)); margin-top:5px; box-shadow:0px 0px 3px #000000 } .tags{ padding: 5px 15px; padding-bottom:7px; } .main iframe, .main embed{ margin-left:-5px; margin-top:-5px; } a.more-link, .tags a, .meta a{ line-height:18px; font-size:10px; border-bottom: 1px #888 dotted; color: {color:Link}; padding: 0 1px; margin: 0 2px; } p.meta{ margin-bottom:5px; } .tags a:hover, a.more-link:hover{ color:{color:Hover}; border-bottom: 1px #FFF dotted; } .pagination{ color: {color:Body Text}; padding: 10px 15px; font-size: 10px; line-height: 16px; text-align: left; /* fallback */ background-color: #000; /* Firefox 3.6+ */ background: -moz-linear-gradient(left, rgba(0, 0, 0, .8), rgba(0, 0, 0, 0.6)); /* Safari 4-5, Chrome 1-9 */ background: -webkit-gradient(linear, left top, right top, from(rgba(0, 0, 0, .8)), to(rgba(0, 0, 0, 0.6))); /* Safari 5.1+, Chrome 10+ */ background: -webkit-linear-gradient(left, rgba(0, 0, 0, .8), rgba(0, 0, 0, 0.6)); /* Opera 11.10+ */ background: -o-linear-gradient(left, rgba(0, 0, 0, .8), rgba(0, 0, 0, 0.6)); margin-top:5px; box-shadow:0px 0px 3px #000000 } .pagination:hover{ /* Firefox 3.6+ */ background: -moz-linear-gradient(left, rgba(0, 0, 0, .6), rgba(0, 0, 0, 0.8)); /* Safari 4-5, Chrome 1-9 */ background: -webkit-gradient(linear, left top, right top, from(rgba(0, 0, 0, .6)), to(rgba(0, 0, 0, 0.8))); /* Safari 5.1+, Chrome 10+ */ background: -webkit-linear-gradient(left, rgba(0, 0, 0, .6), rgba(0, 0, 0, 0.8)); /* Opera 11.10+ */ background: -o-linear-gradient(left, rgba(0, 0, 0, .6), rgba(0, 0, 0, 0.8)); } #nextslide { width:48%; height:100%; background: url(http://static.tumblr.com/szanjxb/vI6lmo15u/forward.png) no-repeat right center, url(http://static.tumblr.com/ffvtarv/gemlmnsks/next-shadow.png) repeat-y right; position:fixed; top:0; right:0; float:left; opacity:0; filter:alpha(opacity=0); -webkit-transition: opacity .5s ease-out; -moz-transition: opacity .5s ease-out; -o-transition: opacity .5s ease-out; overflow:none; } p{ margin-bottom: 10px; } p:last-child{ margin-bottom: 0px; } #prevslide{ width:48%; float:left; height:100%; background: url(http://static.tumblr.com/szanjxb/MSClmo15g/back.png) no-repeat left center, url(http://static.tumblr.com/ffvtarv/bKulmnsl6/prev-shadow.png) repeat-y left; position:fixed; top: 0; left: 0; opacity:0; filter:alpha(opacity=0); -webkit-transition: opacity .5s ease-out; -moz-transition: opacity .5s ease-out; -o-transition: opacity .5s ease-out; } #nextslide:hover, #prevslide:hover{ filter:alpha(opacity=100); opacity:1.0; -webkit-transition: opacity .2s ease-out; -moz-transition: opacity .2s ease-out; -o-transition: opacity .2s ease-out; } p.time{ padding-bottom:10px; margin-bottom:10px; text-align: right; } .left{ float:left; } .right{ float:right; } .button{ position:fixed; bottom: 9px; right: 15px; line-height:12px; font-size:13px; color:{color:Link}; cursor: pointer; float:left; padding-bottom:1px; border-bottom: 2px solid transparent; } .button:hover{ color:{color:Link}; } .notes{ line-height: 11px; } ol.notes li{ list-style: none; } .clear { clear: both; display: block; overflow: hidden; visibility: hidden; width: 0; height: 0; } .hidden{ display:none; } {block:Photo} body {background: url({PhotoURL-HighRes}) no-repeat center center fixed black; -webkit-background-size: cover; -moz-background-size: cover; -o-background-size: cover; background-size: cover;} {/block:Photo} {block:Text} body {background: url({image:Background}) no-repeat center center fixed black; -webkit-background-size: cover; -moz-background-size: cover; -o-background-size: cover; background-size: cover;} {/block:Text} {block:Video} body {background: url({image:Background}) no-repeat center center fixed black; -webkit-background-size: cover; -moz-background-size: cover; -o-background-size: cover; background-size: cover;} {/block:Video} {block:Quote} body {background: url({image:Background}) no-repeat center center fixed black; -webkit-background-size: cover; -moz-background-size: cover; -o-background-size: cover; background-size: cover;} {/block:Quote} {block:Link} body {background: url({image:Background}) no-repeat center center fixed black; -webkit-background-size: cover; -moz-background-size: cover; -o-background-size: cover; background-size: cover;} {/block:Link} {block:Audio} body {background: url({image:Background}) no-repeat center center fixed black; -webkit-background-size: cover; -moz-background-size: cover; -o-background-size: cover; background-size: cover;} {block:AlbumArt} body{ background: url({AlbumArtURL}) no-repeat center center fixed black; -webkit-background-size: cover; -moz-background-size: cover; -o-background-size: cover; background-size: cover; } {/block:AlbumArt} {/block:Audio} {block:Answer} body {background: url({image:Background}) no-repeat center center fixed black; -webkit-background-size: cover; -moz-background-size: cover; -o-background-size: cover; background-size: cover;} {/block:Answer} {block:Chat} body {background: url({image:Background}) no-repeat center center fixed black; 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• Big O complexity of simple for not always linear?

  - by i30817

  I'm sure most of you know that a nested loop has O(n^2) complexity if the function input size is n for(int i = 0; i < n; i++){ for(int j = 0; j < n; j++){ ... } } I think that this is similar, by a analogous argument, but i'm not sure can anyone confirm? for(int i = 0, max = n*n; i < max; i++{ ... } If so i guess that there is some kinds of code whose big O mapping is not immediately obvious besides recursion and subroutines.

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• How to fill a Path in Android with a linear gradient?

  - by Carl Whalley

  Given a closed Path object result is like this: http://www.tutorialguide.net/images/adobe_photoshop/0043/001.jpg. Although that is a rectangle I'm looking for something which works with any closed Path.

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• Pure Java open-source libraries for portfolio selection (= constrained, non-linear optimization)?

  - by __roland__

  Does anyone know or has experience with a pure Java library to select portfolios or do some similar kinds of quadratic programming with constraints? There seems to be a lot of tools, as already discussed elsewhere - but what I would like to use is a pure Java implementation. Since I want to call the library from within another open-source software with a BSD-ish license I would prefer LGPL over GPL. Any help is appreciated. If you don't know such libraries, which is the most simple algorithm you would suggest to implement? It has to cope with an inequality constraint (all x_i = 0) and an equality constraint (sum of all x_i = 1).

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• In an AVL tree, at what condition the balancing is to be done? proper code in c languge

  - by bachchan

  Binary search follows Divide and Conquer method where as linear Search doesn't follw.The time complexity of Binary Search in O(log n) but incase of linear search the time complexity is O(n). Thats way Binary search is having bettr prior than linear search. But it is true when the list of items is large incase of smaller list linear is best(i.e.- it is only when the Best Case concern)

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• finding the total number of distinct shortest paths between 2 nodes in undirected weighted graph in linear time?

  - by logan

  I was wondering, that if there is a weighted graph G(V,E), and I need to find a single shortest path between any two vertices S and T in it then I could have used the Dijkstras algorithm. but I am not sure how this can be done when we need to find all the distinct shortest paths from S to T. Is it solvable on O(n) time? I had one more question like if we assume that the weights of the edges in the graph can assume values only in certain range lets say 1 <=w(e)<=2 will this effect the time complexity?

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• How to make a transition in flex 4 on a fill that contains a linear gradient?

  - by Totty

  <?xml version="1.0" encoding="utf-8"?> <s:Rect id="background" top="0" right="0" bottom="0" left="0" height="30"> <s:fill> <s:SolidColor color="#000000"/> </s:fill> <s:fill.over> <s:LinearGradient rotation="90"> <s:GradientEntry color="#FF5800" alpha="1.0" ratio="0"/> <s:GradientEntry color="#EE0202" alpha="1.0" ratio="1"/> </s:LinearGradient> </s:fill.over> <s:fill.down> <s:LinearGradient rotation="90"> <s:GradientEntry color="#EE0202" alpha="1.0" ratio="0"/> <s:GradientEntry color="#AF0000" alpha="1.0" ratio="1"/> </s:LinearGradient> </s:fill.down> </s:Rect> <s:RichText id="labelDisplay" paddingLeft="10" paddingRight="10" textAlign="center" fontFamily="Myriad Pro" fontSize="16" tabStops="S0 S50 S100 S150" color="#FFFFFF" y="8" color.over="#000000" tabStops.over="S0 S50 S100 S150" color.down="#000000" tabStops.down="S0 S50 S100 S150" color.disabled="#EE0202" tabStops.disabled="S0 S50 S100 S150" color.up="#EE0202" tabStops.up="S0 S50 S100 S150"> <s:filters> <s:DropShadowFilter includeIn="over" blurX="0" blurY="0" distance="1" hideObject="false" inner="false" color="#FFFFFF" strength="1" alpha="1" quality="2" knockout="false" angle="45.0"/> <s:DropShadowFilter includeIn="down" blurX="0" blurY="0" distance="1" hideObject="false" inner="false" color="#CCCCCC" strength="1" alpha="1" quality="2" knockout="false" angle="45.0"/> <s:BlurFilter includeIn="disabled" blurX="4.0" blurY="4.0" quality="2"/> </s:filters> </s:RichText> here is the code, I would like to make a smooth transition when enters the "over" state. any help?

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• css menu <ul><li> dinamically centered or width of buttons that covers the whole page

  - by Tony Stark

  I am building a home page for my minecraft server. Probably in the following 4-6 months I will opend my second and this is why I am in trouble. My first site is 1000 pixel wide, and the second will be 1200. First big difference. My menus are dinamically generated by my php code. It checks on my databases if there is another button or it is over. These buttons can be added or removed directly online. Another big issue is the browser compatibility. In a survey I did on our previous server I had a lot of users using: chrome, internet explorer, safari and firefox. That means that I must find a solution that is compatible with most browsers. What do I have to do? I came up with this CSS, which is touch compatible, it allows menus to be swapped to the left and it is enough to set 1 parameter to fix it for every page width. Sadly it is left aligned. body, nav, ul, li, a {margin: 0; padding: 0;} body {font-family: Verdana,"Helvetica Neue", Helvetica, Arial, sans-serif; } a {text-decoration: none;} .container { max-width: 900px; margin: 0px auto 0px auto; } .toggleMenu { display: none; background: #666; padding: 10px 15px; color: #999999; } .nav { border: 1px solid #424242; background-color: #121212; filter: progid:DXImageTransform.Microsoft.gradient(startColorstr='#686868', endColorstr='#121212'); background-image: -moz-linear-gradient(#686868, #121212); background-image: -webkit-gradient(linear, left top, left bottom, from(#686868), to(#121212)); background-image: -webkit-linear-gradient(#686868, #121212); background-image: -o-linear-gradient(#686868, #121212); background-image: -ms-linear-gradient(#686868, #121212); background-image: linear-gradient(#686868, #121212); -moz-box-shadow: 0 1px 1px #777, 0 1px 0 #666 inset; -webkit-box-shadow: 0 1px 1px #777, 0 1px 0 #666 inset; box-shadow: 0 1px 1px #777, 0 1px 0 #666 inset; list-style: none; *zoom: 1; position: relative; } .nav:before,.nav:after { content: " "; display: table; } .nav:after { clear: both; } .nav ul { list-style: none; width: 11em; z-index: 1; background-color: #121212; -moz-box-shadow: 0 -1px rgba(255,255,255,.3); -webkit-box-shadow: 0 -1px 0 rgba(255,255,255,.3); box-shadow: 0 -1px 0 rgba(255,255,255,.3); } .nav a { padding: 10px 15px; color:#999999; text-transform: uppercase; font: bold 11px Arial, Helvetica; text-decoration: none; text-shadow: 0 1px 0 #000; *zoom: 1; } .nav a:hover{ color:#000000; background-color: #B2B2B2; filter: progid:DXImageTransform.Microsoft.gradient(startColorstr='#D3D3D3', endColorstr='#B2B2B2'); background-image: -moz-linear-gradient(#D3D3D3, #B2B2B2); background-image: -webkit-gradient(linear, left top, left bottom, from(#D3D3D3), to(#B2B2B2)); background-image: -webkit-linear-gradient(#D3D3D3, #B2B2B2); background-image: -o-linear-gradient(#D3D3D3, #B2B2B2); background-image: -ms-linear-gradient(#D3D3D3, #B2B2B2); background-image: linear-gradient(#D3D3D3, #B2B2B2); } /*Delimitazione di ogni tab | HOME | */ .nav li { position: relative; border-right: 1px solid #424242; -moz-box-shadow: 1px 0 0 #686868; -webkit-box-shadow: 1px 0 0 #686868; box-shadow: 1px 0 0 #686868; } .nav > li { float: left; border-top: 1px solid #424242; z-index: 200; } .nav > li > .parent { background-image: url("../downArrow.png"); background-repeat: no-repeat; background-position: center right; } .nav > li li > .parent { background-image: url("../rightArrow.png"); background-repeat: no-repeat; background-position: center right; } .nav > li > a { display: block; } .nav li ul { position: absolute; left: -9999px; z-index: 100; } /* freccetta che indica un sottomenu nell'ultimo tab */ .nav > li:last-child li > .parent{ background-image: url("../leftArrow.png"); background-repeat: no-repeat; background-position: left; } /*flip subsubmenu*/ .nav li.last.hover > ul { left:auto; right: 0; } .nav > li.hover > ul { left: 0; } .nav li li.hover > ul { left: 100%; top: 0; } /* Spostare il 2^ sottomenu a sinistra */ .nav li.last li.hover ul { left:auto; right: 100%; top:0; } .nav li li a { display: block; background-color: #686868; -moz-box-shadow: 0 -1px rgba(255,255,255,.3); -webkit-box-shadow: 0 -1px 0 rgba(255,255,255,.3); box-shadow: 0 -1px 0 rgba(255,255,255,.3); z-index:100; border-top: 1px solid #686868; } .nav li li li a { background-color: #686868; -moz-box-shadow: 0 -1px rgba(255,255,255,.3); -webkit-box-shadow: 0 -1px 0 rgba(255,255,255,.3); box-shadow: 0 -1px 0 rgba(255,255,255,.3); z-index:200; border-top: 1px solid #686868; } .nav li li li li a { display: block; background-color: #686868; -moz-box-shadow: 0 -1px rgba(255,255,255,.3); -webkit-box-shadow: 0 -1px 0 rgba(255,255,255,.3); box-shadow: 0 -1px 0 rgba(255,255,255,.3); z-index:300; border-top: 1px solid #686868; } .nav li li li li a { background-color: #686868; -moz-box-shadow: 0 -1px rgba(255,255,255,.3); -webkit-box-shadow: 0 -1px 0 rgba(255,255,255,.3); box-shadow: 0 -1px 0 rgba(255,255,255,.3); z-index:400; border-top: 1px solid #686868; } @media screen and (max-width: 768px) { .active { display: block; } .nav > li { float: none; } .nav > li > .parent { background-position: 95% 50%; } .nav li li .parent { background-image: url("../downArrow.png"); background-repeat: no-repeat; background-position: 95% 50%; } .nav ul { display: block; width: 100%; } .nav > li.hover > ul , .nav li li.hover ul { position: static; } } My girlfriend (who adapted this code) is really busy for school and cannot help me. Leaving the borders on the whole square (page width), is it possible to make buttons cover the page width dinamically? Or is it possible to center the buttons? Thank you very much!

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