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  • SQL 2K5 - Multiple databases vs. Multiple files

    - by Bob Palmer
    Hey all, quick question. Our current legacy system was built using multiple distinct databases (about ten of them). These are all part of the same discreet system, and a large number of SPs and functionalty span multiple databases. There are also key relationships that span (for example, a header table may be in database A with history, etc. in database B). When deploying multiple copies of our app to the same server therefore, we have to use multiple instances (because the database names are coded into so many sprocs). We're evaluating the idea of taking these ten databases (about 30gb total with individual sizes ranging from 100mb to 10gb) and merging them into a single database. Currently, we have our databases spread accross multiple spindles for better IO. The question I have is whether or not there is any performance loss or benefit of having 10 different databases vs. 10 different database files? i.e. rather than having three databases (A, B, and C) Disk D: A.mdf (1gb) Disk E: B.mdf (4gb) Disk F: C.mdf (10gb) Disk G: A_Log.ldf, B_Log.ldf, C_Log.ldf have one database (X) Disk D: X1.mdf (5gb) Disk E: X2.mdf (5gb) Disk F: X3.mdf (5gb) Disk G: X1_log.ldf,X2_log.ldf,X3_log.ldf Thanks! -Bob

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  • inverse relation to multiple inheriting classes in django

    - by Ofri Raviv
    Here are my schematic models: class Law(models.Model): ... class Bill(models.Model): ... # data for a proposed law, or change of an existing law class PrivateBill(Bill): ... # data for a Bill that was initiated by a parliament member class GovernmentBill(Bill): ... # data for a Bill that was initiated by the government It is possible and likely that in the future I (or maybe someone else) would want to add more Bill types. Every Bill should point to a Law (indicating what law this bill is going to change) and my question is: What is the best way to implement this? If I add the ForeignKey(Law) to Bill, I'll have a relation from every Bill to Law, but a Law would only have an inverse relation to Bills (bill_set), and not a different inverse relation to each type of bill. Of course I'll be able to filter each type of bill to get only the ones pointing to a specific Law, but this is something I think I'll need to use often, so I think having privatebill_set, governmentbill_set etc would make the code more readable. Another possible solution is to add the foreign key to each of the inheriting classes (this would give me a privatebill_set, governmentbill_set, futurebill_set), but that seems hairy because I would be relying on future programmers to remember to add that relation. How would you solve this?

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  • Technology to Prevent Multiple logins to the Same Computer

    - by Ngu Soon Hui
    OK, this is a similar question to this. Actually I am trying to prevent people from multiple login into one single computer and use my application simultaneously. This is because I want to stop them from buying one license, install it on a machine, and use certain remote desktop technologies to do multiple user login. I want to prevent them from violating the license agreement. Is there anyway that I can do in my application for this? Or is multiple login simultaneously is simply not possible?

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  • Multiple EyeFinity Display groups

    - by Shinrai
    Is it possible with an EyeFinity enabled card to make multiple display groups at once? I was playing with a FirePro 2460 and while a 4x1 or 2x2 display group works quite nicely, if I make a 2x1 display group and then select one of the other displays to try to make a second 2x1 display group, it disables the first one. Is there any way to circumvent this behavior and set up two separate spans on the same card? Additionally, can you set up distinct display groups if they're on different cards? I will have the opportunity to test several of these cards in one machine very shortly, but I'm curious if anyone has any experience. EDIT: I can confirm that you can make multiple spans on multiple cards (as long as they don't cross cards, obviously) (If the answers are different for FirePro/FireMV cards and Radeon cards, that is helpful and relevant knowledge - I doubt it, though.)

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  • Multiple EyeFinity Display groups

    - by Shinrai
    Is it possible with an EyeFinity enabled card to make multiple display groups at once? I was playing with a FirePro 2460 and while a 4x1 or 2x2 display group works quite nicely, if I make a 2x1 display group and then select one of the other displays to try to make a second 2x1 display group, it disables the first one. Is there any way to circumvent this behavior and set up two separate spans on the same card? Additionally, can you set up distinct display groups if they're on different cards? I will have the opportunity to test several of these cards in one machine very shortly, but I'm curious if anyone has any experience. EDIT: I can confirm that you can make multiple spans on multiple cards (as long as they don't cross cards, obviously) (If the answers are different for FirePro/FireMV cards and Radeon cards, that is helpful and relevant knowledge - I doubt it, though.)

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  • Multiple database connection in Rails

    - by Sanal
    I'm using active_delegate for multiple connection in Rails. Here I'm using mysql as master_database for some models,and postgresql for some other models. Problem is that when I try to access the mysql models, I'm getting the error below! Stack trace shows that, it is still using the postgresql adapter to access my mysql models! RuntimeError: ERROR C42P01 Mrelation "categories" does not exist P15 F.\src\backend\parser\parse_relation.c L886 RparserOpenTable: SELECT * FROM "categories" STACKTRACE =========== d:/ruby/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/active_record/connection_adapters/abstract_adapter.rb:212:in `log' d:/ruby/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/active_record/connection_adapters/postgresql_adapter.rb:507:in `execute' d:/ruby/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/active_record/connection_adapters/postgresql_adapter.rb:985:in `select_raw' d:/ruby/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/active_record/connection_adapters/postgresql_adapter.rb:972:in `select' d:/ruby/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/active_record/connection_adapters/abstract/database_statements.rb:7:in `select_all_without_query_cache' d:/ruby/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/active_record/connection_adapters/abstract/query_cache.rb:60:in `select_all' d:/ruby/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/active_record/connection_adapters/abstract/query_cache.rb:81:in `cache_sql' d:/ruby/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/active_record/connection_adapters/abstract/query_cache.rb:60:in `select_all' d:/ruby/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/active_record/base.rb:661:in `find_by_sql' d:/ruby/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/active_record/base.rb:1553:in `find_every' d:/ruby/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/active_record/base.rb:615:in `find' D:/ROR/Aptana/dedomenon/app/models/category.rb:50:in `get_all_with_exclusive_scope' D:/ROR/Aptana/dedomenon/app/models/category.rb:50:in `get_all_with_exclusive_scope' D:/ROR/Aptana/dedomenon/app/controllers/categories_controller.rb:48:in `index' here is my database.yml file postgre: &postgre adapter: postgresql database: codex host: localhost username: postgres password: root port: 5432 mysql: &mysql adapter: mysql database: project host: localhost username: root password: root port: 3306 development: <<: *postgre test: <<: *postgre production: <<: *postgre master_database: <<: *mysql and my master_databse model is like this class Category < ActiveRecord::Base delegates_connection_to :master_database, :on => [:create, :save, :destroy] end Anyone has any solution??

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  • Deploying Data Mining Models using Model Export and Import, Part 2

    - by [email protected]
    In my last post, Deploying Data Mining Models using Model Export and Import, we explored using DBMS_DATA_MINING.EXPORT_MODEL and DBMS_DATA_MINING.IMPORT_MODEL to enable moving a model from one system to another. In this post, we'll look at two distributed scenarios that make use of this capability and a tip for easily moving models from one machine to another using only Oracle Database, not an external file transport mechanism, such as FTP. The first scenario, consider a company with geographically distributed business units, each collecting and managing their data locally for the products they sell. Each business unit has in-house data analysts that build models to predict which products to recommend to customers in their space. A central telemarketing business unit also uses these models to score new customers locally using data collected over the phone. Since the models recommend different products, each customer is scored using each model. This is depicted in Figure 1.Figure 1: Target instance importing multiple remote models for local scoring In the second scenario, consider multiple hospitals that collect data on patients with certain types of cancer. The data collection is standardized, so each hospital collects the same patient demographic and other health / tumor data, along with the clinical diagnosis. Instead of each hospital building it's own models, the data is pooled at a central data analysis lab where a predictive model is built. Once completed, the model is distributed to hospitals, clinics, and doctor offices who can score patient data locally.Figure 2: Multiple target instances importing the same model from a source instance for local scoring Since this blog focuses on model export and import, we'll only discuss what is necessary to move a model from one database to another. Here, we use the package DBMS_FILE_TRANSFER, which can move files between Oracle databases. The script is fairly straightforward, but requires setting up a database link and directory objects. We saw how to create directory objects in the previous post. To create a database link to the source database from the target, we can use, for example: create database link SOURCE1_LINK connect to <schema> identified by <password> using 'SOURCE1'; Note that 'SOURCE1' refers to the service name of the remote database entry in your tnsnames.ora file. From SQL*Plus, first connect to the remote database and export the model. Note that the model_file_name does not include the .dmp extension. This is because export_model appends "01" to this name.  Next, connect to the local database and invoke DBMS_FILE_TRANSFER.GET_FILE and import the model. Note that "01" is eliminated in the target system file name.  connect <source_schema>/<password>@SOURCE1_LINK; BEGIN  DBMS_DATA_MINING.EXPORT_MODEL ('EXPORT_FILE_NAME' || '.dmp',                                 'MY_SOURCE_DIR_OBJECT',                                 'name =''MY_MINING_MODEL'''); END; connect <target_schema>/<password>; BEGIN  DBMS_FILE_TRANSFER.GET_FILE ('MY_SOURCE_DIR_OBJECT',                               'EXPORT_FILE_NAME' || '01.dmp',                               'SOURCE1_LINK',                               'MY_TARGET_DIR_OBJECT',                               'EXPORT_FILE_NAME' || '.dmp' );  DBMS_DATA_MINING.IMPORT_MODEL ('EXPORT_FILE_NAME' || '.dmp',                                 'MY_TARGET_DIR_OBJECT'); END; To clean up afterward, you may want to drop the exported .dmp file at the source and the transferred file at the target. For example, utl_file.fremove('&directory_name', '&model_file_name' || '.dmp');

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  • Multiple inheritance in OOPS

    - by user145610
    I'm confused about an OOPS feature, multiple inheritance. Does OOPS allow Multiple Inheritance? Is Multiple Inheritance a feature of OOPS? If Multiple Inheritance is a feature then why don't languages like C#, VB.NET, java etc. support multiple inheritance? But those languages are considered as strongly supported OOPS language. Can anyone address this question?

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  • Django syncdb not making tables for my app

    - by Rosarch
    It used to work, and now it doesn't. python manage.py syncdb no longer makes tables for my app. From settings.py: INSTALLED_APPS = ( 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'mysite.myapp', 'django.contrib.admin', ) What could I be doing wrong? The break appeared to coincide with editing this model in models.py, but that could be total coincidence. I commented out the lines I changed, and it still doesn't work. class MyUser(models.Model): user = models.ForeignKey(User, unique=True) takingReqSets = models.ManyToManyField(RequirementSet, blank=True) takingTerms = models.ManyToManyField(Term, blank=True) takingCourses = models.ManyToManyField(Course, through=TakingCourse, blank=True) school = models.ForeignKey(School) # minCreditsPerTerm = models.IntegerField(blank=True) # maxCreditsPerTerm = models.IntegerField(blank=True) # optimalCreditsPerTerm = models.IntegerField(blank=True) UPDATE: When I run python manage.py loadddata initial_data, it gives an error: DeserializationError: Invalid model identifier: myapp.SomeModel Loading this data had worked fine before. This error is thrown on the very first data object in the data file.

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  • Django says the "id may not be NULL" but why is it?

    - by Oli
    I'm going crazy today. I just tried to insert a new record and it threw back a "post_blogpost.id may not be NULL" error. Here's my model: class BlogPost(models.Model): title = models.CharField(max_length=100) slug = models.SlugField(max_length=100) who = models.ForeignKey(User, default=1) when = models.DateTimeField() intro = models.TextField(blank=True, null=True) content = models.TextField(blank=True, null=True) counter = models.PositiveIntegerField(default=0) published = models.BooleanField(default=False) css = models.TextField(blank=True, null=True) class Meta: ordering = ('-when', 'id') There are a number of functions beneath the model too but I won't include them in full here. Their names are: content_cache_key, clear_cache, __unicode__, reads, read, processed_content. I'm adding through the admin... And I'm running out of hair.

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  • Foreign Key Relationships

    - by Yehonathan Quartey
    I have two models class Subject(models.Model): name = models.CharField(max_length=100,choices=COURSE_CHOICES) created = models.DateTimeField('created', auto_now_add=True) modified = models.DateTimeField('modified', auto_now=True) syllabus = models.FileField(upload_to='syllabus') def __unicode__(self): return self.name and class Pastquestion(models.Model): subject=models.ForeignKey(Subject) year =models.PositiveIntegerField() questions = models.FileField(upload_to='pastquestions') def __unicode__(self): return str(self.year) Each Subject can have one or more past questions but a past question can have only one subject. I want to get a subject, and get its related past questions of a particular year. I was thinking of fetching a subject and getting its related past question. Currently am implementing my code such that I rather get the past question whose subject and year correspond to any specified subject like this_subject=Subject.objects.get(name=the_subject) thepastQ=Pastquestion.objects.get(year=2000,subject=this_subject) I was thinking there is a better way to do this. Or is this already a better way? Please Do tell ?

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  • Getting the last member of a group on an intermediary M2M

    - by rh0dium
    If we look at the existing docs, what is the best way to get the last member added? This is similar to this but what I want to do is to be able to do this. group = Group.objects.get(id=1) group.get_last_member_added() #This is by ('-date_added') <Person: FOO> I think the best way is through a manager but how do you do this on an intermediary model? class Person(models.Model): name = models.CharField(max_length=128) def __unicode__(self): return self.name class Group(models.Model): name = models.CharField(max_length=128) members = models.ManyToManyField(Person, through='Membership') def __unicode__(self): return self.name class Membership(models.Model): person = models.ForeignKey(Person) group = models.ForeignKey(Group) date_joined = models.DateField() invite_reason = models.CharField(max_length=64)

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  • Value [...] not a valid choice, django-updown

    - by tamara
    I am trying to implemet django-updown https://github.com/weluse/django-updown. When I try to add vote trough the admin panel it says Value 1 not a valid choice. This is the models.py from the application: _SCORE_TYPE_CHOICES = ( ('-1', 'DISLIKE'), ('1', 'LIKE'), ) SCORE_TYPES = dict((value, key) for key, value in _SCORE_TYPE_CHOICES) class Vote(models.Model): content_type = models.ForeignKey(ContentType, related_name="updown_votes") object_id = models.PositiveIntegerField() key = models.CharField(max_length=32) score = models.SmallIntegerField(choices=_SCORE_TYPE_CHOICES) user = models.ForeignKey(User, blank=True, null=True, related_name="updown_votes") ip_address = models.IPAddressField() date_added = models.DateTimeField(default=datetime.datetime.now, editable=False) date_changed = models.DateTimeField(default=datetime.datetime.now, editable=False) Do you have an idea what could be wrong?

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  • Multiple munin-nodes per machine

    - by Alexander T
    I'm collecting statistics remotely through JMX. The munin JMX plugin allows you to select an URL to connect to when aggregating statistics. This allows me to collect statistics from hosts which do not actually have munin-node installed. I find this a desirable property for some systems where I am hindered to install munin-node. How I work today is that if i want to collect JMX stats from machine A without munin-node, I install munin-node on machine B. Machine B then collects data from A via JMX, and reports it to munin-server, which runs on machine C. This setup requires multiple B-type machines: one per C-type machine. I would like to avoid this and instead use only one B-type machine to collect the data from all A-type machines and reports it to the only munin-server (C-type machine). As far as I understand this requires running multiple munin-nodes on B or in some other way report to munin-server that the B-type machine is reporting data from multiple sources. Is this possible? Thank you.

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  • jqgrid and django models

    - by Andrew Gee
    Hi, I have the following models class Employee(Person): job = model.Charfield(max_length=200) class Address(models.Model): street = models.CharField(max_length=200) city = models.CharField(max_length=200) class EmpAddress(Address): date_occupied = models.DateField() date_vacated = models.DateField() employee = models.ForeignKey() When I build a json data structure for an EmpAddress object using the django serialzer it does not include the inherited fields only the EmpAddress fields. I know the fields are available in the object in my view as I can print them but they are not built into the json structure. Does anyone know how to overcome this? Thanks Andrew

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  • Designing a database for a user/points system? (in Django)

    - by AP257
    First of all, sorry if this isn't an appropriate question for StackOverflow. I've tried to make it as generalisable as possible. I want to create a database (MySQL, site running Django) that has users, who can be allocated a certain number of points for various types of action - it's a collaborative game. My requirements are to obtain: the number of points a user has the user's ranking compared to all other users and the overall leaderboard (i.e. all users ranked in order of points) This is what I have so far, in my Django models.py file: class SiteUser(models.Model): name = models.CharField(max_length=250 ) email = models.EmailField(max_length=250 ) date_added = models.DateTimeField(auto_now_add=True) def points_total(self): points_added = PointsAdded.objects.filter(user=self) points_total = 0 for point in points_added: points_total += point.points return points_total class PointsAdded(models.Model): user = models.ForeignKey('SiteUser') action = models.ForeignKey('Action') date_added = models.DateTimeField(auto_now_add=True) def points(self): points = Action.objects.filter(action=self.action) return points class Action(models.Model): points = models.IntegerField() action = models.CharField(max_length=36) However it's rapidly becoming clear to me that it's actually quite complex (in Django query terms at least) to figure out the user's ranking and return the leaderboard of users. At least, I'm finding it tough. Is there a more elegant way to do something like this? This question seems to suggest that I shouldn't even have a separate points table - what do people think? It feels more robust to have separate tables, but I don't have much experience of database design.

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  • Uploading multiple files using Spring MVC 3.0.2 after HiddenHttpMethodFilter has been enabled

    - by Tiny
    I'm using Spring version 3.0.2. I need to upload multiple files using the multiple="multiple" attribute of a file browser such as, <input type="file" id="myFile" name="myFile" multiple="multiple"/> (and not using multiple file browsers something like the one stated by this answer, it indeed works I tried). Although no versions of Internet Explorer supports this approach unless an appropriate jQuery plugin/widget is used, I don't care about it right now (since most other browsers support this). This works fine with commons fileupload but in addition to using RequestMethod.POST and RequestMethod.GET methods, I also want to use other request methods supported and suggested by Spring like RequestMethod.PUT and RequestMethod.DELETE in their own appropriate places. For this to be so, I have configured Spring with HiddenHttpMethodFilter which goes fine as this question indicates. but it can upload only one file at a time even though multiple files in the file browser are chosen. In the Spring controller class, a method is mapped as follows. @RequestMapping(method={RequestMethod.POST}, value={"admin_side/Temp"}) public String onSubmit(@RequestParam("myFile") List<MultipartFile> files, @ModelAttribute("tempBean") TempBean tempBean, BindingResult error, Map model, HttpServletRequest request, HttpServletResponse response) throws IOException, FileUploadException { for(MultipartFile file:files) { System.out.println(file.getOriginalFilename()); } } Even with the request parameter @RequestParam("myFile") List<MultipartFile> files which is a List of type MultipartFile (it can always have only one file at a time). I could find a strategy which is likely to work with multiple files on this blog. I have gone through it carefully. The solution below the section SOLUTION 2 – USE THE RAW REQUEST says, If however the client insists on using the same form input name such as ‘files[]‘ or ‘files’ and then populating that name with multiple files then a small hack is necessary as follows. As noted above Spring 2.5 throws an exception if it detects the same form input name of type file more than once. CommonsFileUploadSupport – the class which throws that exception is not final and the method which throws that exception is protected so using the wonders of inheritance and subclassing one can simply fix/modify the logic a little bit as follows. The change I’ve made is literally one word representing one method invocation which enables us to have multiple files incoming under the same form input name. It attempts to override the method protected MultipartParsingResult parseFileItems(List fileItems, String encoding) {} of the abstract class CommonsFileUploadSupport by extending the class CommonsMultipartResolver such as, package multipartResolver; import java.io.UnsupportedEncodingException; import java.util.HashMap; import java.util.Iterator; import java.util.List; import java.util.Map; import javax.servlet.ServletContext; import org.apache.commons.fileupload.FileItem; import org.springframework.util.StringUtils; import org.springframework.web.multipart.MultipartException; import org.springframework.web.multipart.MultipartFile; import org.springframework.web.multipart.commons.CommonsMultipartFile; import org.springframework.web.multipart.commons.CommonsMultipartResolver; final public class MultiCommonsMultipartResolver extends CommonsMultipartResolver { public MultiCommonsMultipartResolver() { } public MultiCommonsMultipartResolver(ServletContext servletContext) { super(servletContext); } @Override @SuppressWarnings("unchecked") protected MultipartParsingResult parseFileItems(List fileItems, String encoding) { Map<String, MultipartFile> multipartFiles = new HashMap<String, MultipartFile>(); Map multipartParameters = new HashMap(); // Extract multipart files and multipart parameters. for (Iterator it = fileItems.iterator(); it.hasNext();) { FileItem fileItem = (FileItem) it.next(); if (fileItem.isFormField()) { String value = null; if (encoding != null) { try { value = fileItem.getString(encoding); } catch (UnsupportedEncodingException ex) { if (logger.isWarnEnabled()) { logger.warn("Could not decode multipart item '" + fileItem.getFieldName() + "' with encoding '" + encoding + "': using platform default"); } value = fileItem.getString(); } } else { value = fileItem.getString(); } String[] curParam = (String[]) multipartParameters.get(fileItem.getFieldName()); if (curParam == null) { // simple form field multipartParameters.put(fileItem.getFieldName(), new String[] { value }); } else { // array of simple form fields String[] newParam = StringUtils.addStringToArray(curParam, value); multipartParameters.put(fileItem.getFieldName(), newParam); } } else { // multipart file field CommonsMultipartFile file = new CommonsMultipartFile(fileItem); if (multipartFiles.put(fileItem.getName(), file) != null) { throw new MultipartException("Multiple files for field name [" + file.getName() + "] found - not supported by MultipartResolver"); } if (logger.isDebugEnabled()) { logger.debug("Found multipart file [" + file.getName() + "] of size " + file.getSize() + " bytes with original filename [" + file.getOriginalFilename() + "], stored " + file.getStorageDescription()); } } } return new MultipartParsingResult(multipartFiles, multipartParameters); } } What happens is that the last line in the method parseFileItems() (the return statement) i.e. return new MultipartParsingResult(multipartFiles, multipartParameters); causes a compile-time error because the first parameter multipartFiles is a type of Map implemented by HashMap but in reality, it requires a parameter of type MultiValueMap<String, MultipartFile> It is a constructor of a static class inside the abstract class CommonsFileUploadSupport, public abstract class CommonsFileUploadSupport { protected static class MultipartParsingResult { public MultipartParsingResult(MultiValueMap<String, MultipartFile> mpFiles, Map<String, String[]> mpParams) { } } } The reason might be - this solution is about the Spring version 2.5 and I'm using the Spring version 3.0.2 which might be inappropriate for this version. I however tried to replace the Map with MultiValueMap in various ways such as the one shown in the following segment of code, MultiValueMap<String, MultipartFile>mul=new LinkedMultiValueMap<String, MultipartFile>(); for(Entry<String, MultipartFile>entry:multipartFiles.entrySet()) { mul.add(entry.getKey(), entry.getValue()); } return new MultipartParsingResult(mul, multipartParameters); but no success. I'm not sure how to replace Map with MultiValueMap and even doing so could work either. After doing this, the browser shows the Http response, HTTP Status 400 - type Status report message description The request sent by the client was syntactically incorrect (). Apache Tomcat/6.0.26 I have tried to shorten the question as possible as I could and I haven't included unnecessary code. How could be made it possible to upload multiple files after Spring has been configured with HiddenHttpMethodFilter? That blog indicates that It is a long standing, high priority bug. If there is no solution regarding the version 3.0.2 (3 or higher) then I have to disable Spring support forever and continue to use commons-fileupolad as suggested by the third solution on that blog omitting the PUT, DELETE and other request methods forever. Just curiously waiting for a solution and/or suggestion. Very little changes to the code in the parseFileItems() method inside the class MultiCommonsMultipartResolver might make it to upload multiple files but I couldn't succeed in my attempts (again with the Spring version 3.0.2 (3 or higher)).

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  • Dual Use (Mice and Keyboayd) of Windows 7

    - by jmalais
    I saw some answers to this question however they were fairly old (at least 2 years) and primarily for Vista or previous Windows OS versions. My question is this: Is there a program that allows a single Windows 7 computer to have multiple users (2 needed) and allow for two mice and two keyboards on two screens. What I'm trying to achieve: I'd like for the ability to play a game on one monitor while another person surfs the web, uses a program, or possibly play a different game. Any ideas?

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  • MVC Design Pattern to Combine Multiple Models for use

    - by roverred
    In my design, I have multiple models and each model has a controller. I need to use all the models to process some operation. Most examples I see are pretty simple with 1 view, 1 controller, and 1 model. How would you get all these models together? Only ways I can think of are 1) Have a top-level controller which has a reference to every controller. Those controllers will have a getter/setter function for their model. Does this violate MVC because every controller should have a model? 2) Have an Intermediate class to combine every model into a one model. Then you create a controller for that new super model. Do you know of any better ideas? Thanks.

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  • Are session aware Models a bad thing?

    - by kevtufc
    I'm thinking specifically in Rails here, but I suspect this is a wider question. In a Rails web application I'm using data from the session in models in order that the models know who is logged in. I use this in a method which filters out some data from the database depending on a very simple permissions system. The thing is: using sessions in models in Rails requires a bit of a workaround. It works, but I've a feeling that it's something that I shouldn't be doing and I'm worried there's a big gotcha I'm missing. I suppose the Right Thing To Do would be to return all the data and filter out the not-wanted bits in the controller before passing that to the view, but doing it in the model seems to avoid quite a bit of code duplication and so feels "cleaner." Can anyone tell me why or shouldn't do this? Or that it's not a problem?

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  • KVM Switch for multiple monitors possible?

    - by jasondavis
    I have been curious about this for YEARS! I have never used a KVM switch (keyboard, mouse, monitor) switch to allow you to use 1 keyboard, mouse, monitor to operate 2 or more computers however I understand the concept and what they are for, just never really had a huge need for 1 until now. Here is my issue though. If possible I need to have a KVM switch hooked up to 2 computers in my room. The catch, I have 2-3 monitors on the PC, so I am looking for a way to have a KVM switch that will support multiple monitors. So PC #1 can be using a mouse, keyboard, 2-3 monitors like normal. I then hit the switch and it makes my mouse, keyboard, and 2-3 monitors switch to PC #2. Has anyone ever heard of a KVM switch being able to support multiple monitors like I described? Or how I can achieve this goal? Please help.

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  • Exchange 2010 Multiple accounts in one mailbox

    - by durilai
    I am looking for best practice or recommended ways of doing the following: I have a user that has 2 email addresses, he accesses them via POP 3 and OWA. He need to be able to send as each of the addresses. I do not want to create multiple AD accounts or mailboxes, but would like to be able to provide that visual separation. Is this possible, I know using Outlook I am able to add multiple POP3 accounts and he can send from whichever he choose, but how to enable this is OWA, as well as on a mobile using POP3. Thanks

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  • Single database with multiple instances of Django

    - by jwesonga
    I have a Django project where the company will have a main site like www.ourcompany.org and a bunch of sub-domains like project.ourcompany.org. Content appearing in the sub-domains like case studies should also appear in the main site. I've decided to use multiple instances of Django BUT one database for each sub-domain so that I can have some flexibility and take advantage of the Sites framework. What I'm not sure of is how to access the models across the multiple instances. If I have a model: class CaseStudy(models.Model): title=models.CharField(max_length=100) site=models.ManyToMany(Site) Do I need to create this model in every instance so that I can have access to the object?

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