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  • Problems installing Ubuntu on unallocated space

    - by Adam
    I've been trying to install Ubuntu on some unallocated space, but I'm getting confused with the manual partition setup. I didn't want to try the other options for it suggested that everything on my drive would be erased (but I might be wrong) I have an old(ish) laptop with a 60GB hard-drive. Theres a Windows 7 partition of 30GB, followed by 20GB of unallocated space, then HP's Windows recovery partition of under 10GB. Do I need to format the empty space in windows first? What's the recommended method in this case?

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  • Desktop Fun: Space Age Fonts

    - by Asian Angel
    Do you have a sci-fi related project such as artwork, wallpapers, or other items that you are working on and need some awesome fonts to add the perfect touch? Then get ready to launch your work into outer space with our Space Age Fonts collection. Note: To manage the fonts on your Windows 7, Vista, & XP systems see our article here. Space And Astronomy HTG Explains: Photography with Film-Based CamerasHow to Clean Your Dirty Smartphone (Without Breaking Something)What is a Histogram, and How Can I Use it to Improve My Photos?

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  • Mouse pointer position to screen space

    - by Ylisar
    If I have a mouse pointer position in pixels of canvas, I can easily convert it to the -1..1 range for both X & Y by lerping by dividing with canvas dimensions. However, the problem is what I should put in Z & W if I want my screen space position to be on the near plane? The step afterwards would be for me to multiply by the inverse of view-projection to take me to world space, where I easily can construct a ray from the cameras world space position.

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  • PowerShell script to find files that are consuming the most disk space

    As you know, SQL Server databases and backup files can take up a lot of disk space. When disk is running low and you need to troubleshoot disk space issues, the first thing to do is to find large files that are consuming disk space. In this article I will show you a PowerShell script that you can use to find large files on your disks. 12 essential tools for database professionalsThe SQL Developer Bundle contains 12 tools designed with the SQL Server developer and DBA in mind. Try it now.

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  • SQL Server database filled the hard drive and freeing up space isn't possible

    - by Jon
    I have a database in SQL Server 2008 on a 1Tb hard drive and it filled the drive, there is only 4Kb free. The MDF file is 323Gb and the LDF is 653Gb. The hard disk this DB is on has no other files on it other than the MDF and LDF so it's impossible to free up any space on the drive. The main hard disk is smaller but there is enough room to transfer the MDF to that drive, in case that helps. This server is overseas at a customer site and it's not possible at the moment to add more disk space to the server. It's also not possible to delete any records because the DB is in a failed mode (due to no disk space) and it doesn't respond to most commands. The Db is currently in full recovery mode which is why the LDF file is so large. This DB really doesn't need to be in full recovery so going forward we plan on switching it to simple mode which will save us a lot of space. I also don't care about losing the LDF file, but I need all of the data. I've spent a lot of time looking for a way out of this problem but everything I've found first involves either freeing up disk space or adding more disk space, neither of which is an option at this time. I'm stuck and any help would be greatly appreciated. I get the following log when trying to switch the DB to online mode. Msg 945, Level 14, State 2, Line 3 Database 'DBNAME' cannot be opened due to inaccessible files or insufficient memory or disk space. See the SQL Server errorlog for details. Msg 5069, Level 16, State 1, Line 3 ALTER DATABASE statement failed. Msg 1101, Level 17, State 12, Line 3 Could not allocate a new page for database 'DBNAME' because of insufficient disk space in filegroup 'DEFAULT'. Create the necessary space by dropping objects in the filegroup, adding additional files to the filegroup, or setting autogrowth on for existing files in the filegroup. I've found the following solutions but none work due to having no disk space on that drive, and since the DB is in a failed state I can't run most commmands. - DBCC SHRINKFILE - can't be run because doing a 'use DBNAME' fails - Detaching the DB and then changing the location of the MDF/LDF files, this fails because the DB is in an offline mode so you can't run detach. I'm at a loss about what else to try. Thanks.

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  • Where's my free space gone? (on my mac) [closed]

    - by Cawas
    Possible Duplicate: Something’s slowly eating my HD space Somehow part of my files from my USB disk, 40GB of it (exactly the space I was missing), were copied to /Volumes/ and when I mounted the disk it was called "600GB Disk 2", while "600GB Disk" was filled with duplicated data. All that happened at once, slowly, just this morning when I turned on my macbook. I could notice that thanks to Disk Inventory X. I could actually see those on GrandPerspective, but I thought it was just scanning my USB limited to that folder for whatever reason. On Disk Inventory I could see the /Volumes/ listing one folder as a folder and the second one as a link, like it should be. Well, looking at that folder, I quickly associated what was in it with my scheduled backup on Carbon Copy Cloner. I'm still not sure why the USB disk was mounted with wrong name, but what happened was CCC store the full path information of the source and destination, so when it tried to do the schedule backup it created the path that didn't exist, and copied everything there - while it should be copying into the mounted volume. While this is solved this time, what else could I have done to diagnose this kind of issue, for the next time?

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  • Merge sort versus quick sort performance

    - by Giorgio
    I have implemented merge sort and quick sort using C (GCC 4.4.3 on Ubuntu 10.04 running on a 4 GB RAM laptop with an Intel DUO CPU at 2GHz) and I wanted to compare the performance of the two algorithms. The prototypes of the sorting functions are: void merge_sort(const char **lines, int start, int end); void quick_sort(const char **lines, int start, int end); i.e. both take an array of pointers to strings and sort the elements with index i : start <= i <= end. I have produced some files containing random strings with length on average 4.5 characters. The test files range from 100 lines to 10000000 lines. I was a bit surprised by the results because, even though I know that merge sort has complexity O(n log(n)) while quick sort is O(n^2), I have often read that on average quick sort should be as fast as merge sort. However, my results are the following. Up to 10000 strings, both algorithms perform equally well. For 10000 strings, both require about 0.007 seconds. For 100000 strings, merge sort is slightly faster with 0.095 s against 0.121 s. For 1000000 strings merge sort takes 1.287 s against 5.233 s of quick sort. For 5000000 strings merge sort takes 7.582 s against 118.240 s of quick sort. For 10000000 strings merge sort takes 16.305 s against 1202.918 s of quick sort. So my question is: are my results as expected, meaning that quick sort is comparable in speed to merge sort for small inputs but, as the size of the input data grows, the fact that its complexity is quadratic will become evident? Here is a sketch of what I did. In the merge sort implementation, the partitioning consists in calling merge sort recursively, i.e. merge_sort(lines, start, (start + end) / 2); merge_sort(lines, 1 + (start + end) / 2, end); Merging of the two sorted sub-array is performed by reading the data from the array lines and writing it to a global temporary array of pointers (this global array is allocate only once). After each merge the pointers are copied back to the original array. So the strings are stored once but I need twice as much memory for the pointers. For quick sort, the partition function chooses the last element of the array to sort as the pivot and scans the previous elements in one loop. After it has produced a partition of the type start ... {elements <= pivot} ... pivotIndex ... {elements > pivot} ... end it calls itself recursively: quick_sort(lines, start, pivotIndex - 1); quick_sort(lines, pivotIndex + 1, end); Note that this quick sort implementation sorts the array in-place and does not require additional memory, therefore it is more memory efficient than the merge sort implementation. So my question is: is there a better way to implement quick sort that is worthwhile trying out? If I improve the quick sort implementation and perform more tests on different data sets (computing the average of the running times on different data sets) can I expect a better performance of quick sort wrt merge sort? EDIT Thank you for your answers. My implementation is in-place and is based on the pseudo-code I have found on wikipedia in Section In-place version: function partition(array, 'left', 'right', 'pivotIndex') where I choose the last element in the range to be sorted as a pivot, i.e. pivotIndex := right. I have checked the code over and over again and it seems correct to me. In order to rule out the case that I am using the wrong implementation I have uploaded the source code on github (in case you would like to take a look at it). Your answers seem to suggest that I am using the wrong test data. I will look into it and try out different test data sets. I will report as soon as I have some results.

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  • What would be the time complexity of counting the number of all structurally different binary trees?

    - by ktslwy
    Using the method presented here: http://cslibrary.stanford.edu/110/BinaryTrees.html#java 12. countTrees() Solution (Java) /** For the key values 1...numKeys, how many structurally unique binary search trees are possible that store those keys? Strategy: consider that each value could be the root. Recursively find the size of the left and right subtrees. */ public static int countTrees(int numKeys) { if (numKeys <=1) { return(1); } else { // there will be one value at the root, with whatever remains // on the left and right each forming their own subtrees. // Iterate through all the values that could be the root... int sum = 0; int left, right, root; for (root=1; root<=numKeys; root++) { left = countTrees(root-1); right = countTrees(numKeys - root); // number of possible trees with this root == left*right sum += left*right; } return(sum); } } I have a sense that it might be n(n-1)(n-2)...1, i.e. n!

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  • Big O Complexity of a method

    - by timeNomad
    I have this method: public static int what(String str, char start, char end) { int count=0; for(int i=0;i<str.length(); i++) { if(str.charAt(i) == start) { for(int j=i+1;j<str.length(); j++) { if(str.charAt(j) == end) count++; } } } return count; } What I need to find is: 1) What is it doing? Answer: counting the total number of end occurrences after EACH (or is it? Not specified in the assignment, point 3 depends on this) start. 2) What is its complexity? Answer: the first loops iterates over the string completely, so it's at least O(n), the second loop executes only if start char is found and even then partially (index at which start was found + 1). Although, big O is all about worst case no? So in the worst case, start is the 1st char & the inner iteration iterates over the string n-1 times, the -1 is a constant so it's n. But, the inner loop won't be executed every outer iteration pass, statistically, but since big O is about worst case, is it correct to say the complexity of it is O(n^2)? Ignoring any constants and the fact that in 99.99% of times the inner loop won't execute every outer loop pass. 3) Rewrite it so that complexity is lower. What I'm not sure of is whether start occurs at most once or more, if once at most, then method can be rewritten using one loop (having a flag indicating whether start has been encountered and from there on incrementing count at each end occurrence), yielding a complexity of O(n). In case though, that start can appear multiple times, which most likely it is, because assignment is of a Java course and I don't think they would make such ambiguity. Solving, in this case, is not possible using one loop... WAIT! Yes it is..! Just have a variable, say, inc to be incremented each time start is encountered & used to increment count each time end is encountered after the 1st start was found: inc = 0, count = 0 if (current char == start) inc++ if (inc > 0 && current char == end) count += inc This would also yield a complexity of O(n)? Because there is only 1 loop. Yes I realize I wrote a lot hehe, but what I also realized is that I understand a lot better by forming my thoughts into words...

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  • Is there a shorthand term for O(n log n)?

    - by jemfinch
    We usually have a single-word shorthand for most complexities we encounter in algorithmic analysis: O(1) == "constant" O(log n) == "logarithmic" O(n) == "linear" O(n^2) == "quadratic" O(n^3) == "cubic" O(2^n) == "exponential" We encounter algorithms with O(n log n) complexity with some regularity (think of all the algorithms dominated by sort complexity) but as far as I know, there's no single word we can use in English to refer to that complexity. Is this a gap in my knowledge, or a real gap in our English discourse on computational complexity?

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  • How to free up space on /boot? [closed]

    - by Phrogz
    Possible Duplicate: Free up more space on /boot I logged onto my server today to find the message: => /boot is using 98.9% of 91MB When I look at /boot I see that it is indeed very low on space, and has old-kernel files in it: phrogz@planar:~$ df -h /boot Filesystem Size Used Avail Use% Mounted on /dev/sda1 92M 54M 33M 63% /boot phrogz@planar:~$ la /boot total 81880 drwxr-xr-x 4 root root 3072 2011-12-02 06:26 ./ drwxr-xr-x 22 root root 4096 2011-09-29 06:37 ../ -rw-r--r-- 1 root root 646419 2011-03-01 19:02 abi-2.6.32-30-server -rw-r--r-- 1 root root 646419 2011-04-08 17:07 abi-2.6.32-31-server -rw-r--r-- 1 root root 646454 2011-04-20 16:53 abi-2.6.32-32-server -rw-r--r-- 1 root root 646454 2011-07-29 16:07 abi-2.6.32-33-server -rw-r--r-- 1 root root 646710 2011-09-13 18:00 abi-2.6.32-34-server -rw-r--r-- 1 root root 646820 2011-10-11 11:10 abi-2.6.32-35-server -rw-r--r-- 1 root root 110687 2011-03-01 19:02 config-2.6.32-30-server -rw-r--r-- 1 root root 110676 2011-04-08 17:07 config-2.6.32-31-server -rw-r--r-- 1 root root 110687 2011-04-20 16:53 config-2.6.32-32-server -rw-r--r-- 1 root root 110687 2011-07-29 16:07 config-2.6.32-33-server -rw-r--r-- 1 root root 110687 2011-09-13 18:00 config-2.6.32-34-server -rw-r--r-- 1 root root 110687 2011-10-11 11:10 config-2.6.32-35-server drwxr-xr-x 3 root root 6144 2011-12-02 06:26 grub/ -rw-r--r-- 1 root root 8258196 2011-05-18 11:58 initrd.img-2.6.32-30-server -rw-r--r-- 1 root root 8259568 2011-05-23 20:24 initrd.img-2.6.32-31-server -rw-r--r-- 1 root root 8257374 2011-05-30 07:47 initrd.img-2.6.32-32-server -rw-r--r-- 1 root root 8287489 2011-08-10 06:37 initrd.img-2.6.32-33-server -rw-r--r-- 1 root root 8288075 2011-09-29 06:37 initrd.img-2.6.32-34-server drwx------ 2 root root 12288 2011-05-18 11:46 lost+found/ -rw-r--r-- 1 root root 160280 2010-03-23 03:40 memtest86+.bin -rw-r--r-- 1 root root 2179117 2011-03-01 19:02 System.map-2.6.32-30-server -rw-r--r-- 1 root root 2179628 2011-04-08 17:07 System.map-2.6.32-31-server -rw-r--r-- 1 root root 2178240 2011-04-20 16:53 System.map-2.6.32-32-server -rw-r--r-- 1 root root 2178382 2011-07-29 16:07 System.map-2.6.32-33-server -rw-r--r-- 1 root root 2178952 2011-09-13 18:00 System.map-2.6.32-34-server -rw-r--r-- 1 root root 2179333 2011-10-11 11:10 System.map-2.6.32-35-server -rw-r--r-- 1 root root 1336 2011-03-01 19:08 vmcoreinfo-2.6.32-30-server -rw-r--r-- 1 root root 1336 2011-04-08 17:13 vmcoreinfo-2.6.32-31-server -rw-r--r-- 1 root root 1336 2011-04-20 16:54 vmcoreinfo-2.6.32-32-server -rw-r--r-- 1 root root 1336 2011-07-29 16:08 vmcoreinfo-2.6.32-33-server -rw-r--r-- 1 root root 1336 2011-09-13 18:03 vmcoreinfo-2.6.32-34-server -rw-r--r-- 1 root root 1336 2011-10-11 11:11 vmcoreinfo-2.6.32-35-server -rw-r--r-- 1 root root 4111552 2011-03-01 19:02 vmlinuz-2.6.32-30-server -rw-r--r-- 1 root root 4113344 2011-04-08 17:07 vmlinuz-2.6.32-31-server -rw-r--r-- 1 root root 4106528 2011-04-20 16:53 vmlinuz-2.6.32-32-server -rw-r--r-- 1 root root 4107648 2011-07-29 16:07 vmlinuz-2.6.32-33-server -rw-r--r-- 1 root root 4108960 2011-09-13 18:00 vmlinuz-2.6.32-34-server -rw-r--r-- 1 root root 4111040 2011-10-11 11:10 vmlinuz-2.6.32-35-server I was able to find the old kernel packages like so: phrogz@planar:/boot$ dpkg -l | grep linux-image ii linux-image-2.6.32-30-server 2.6.32-30.59 Linux kernel image for version 2.6.32 on x86 ii linux-image-2.6.32-31-server 2.6.32-31.61 Linux kernel image for version 2.6.32 on x86 ii linux-image-2.6.32-32-server 2.6.32-32.62 Linux kernel image for version 2.6.32 on x86 ii linux-image-2.6.32-33-server 2.6.32-33.72 Linux kernel image for version 2.6.32 on x86 ii linux-image-2.6.32-34-server 2.6.32-34.77 Linux kernel image for version 2.6.32 on x86 iF linux-image-2.6.32-35-server 2.6.32-35.78 Linux kernel image for version 2.6.32 on x86 iU linux-image-server 2.6.32.36.42 Linux kernel image on Server Equipment. …and I can see that many of them are older than my current image: phrogz@planar:/boot$ uname -a Linux planar 2.6.32-34-server #77-Ubuntu SMP Tue Sep 13 20:54:38 UTC 2011 x86_64 GNU/Linux However, I can't actually remove them due to an unmet dependency: phrogz@planar:/boot$ sudo apt-get --purge remove linux-image-2.6.32-30-server Reading package lists... Done Building dependency tree Reading state information... Done You might want to run `apt-get -f install' to correct these: The following packages have unmet dependencies: linux-image-server: Depends: linux-image-2.6.32-36-server but it is not going to be installed E: Unmet dependencies. Try 'apt-get -f install' with no packages (or specify a solution). But I can't fix the dependency (presumably due to low disk space): phrogz@planar:/boot$ sudo apt-get -f install Reading package lists... Done Building dependency tree Reading state information... Done Correcting dependencies... Done The following packages were automatically installed and are no longer required: liblcms1 linux-headers-2.6.32-32-server libnspr4-0d linux-headers-2.6.32-33-server linux-headers-2.6.32-32 linux-headers-2.6.32-33 linux-headers-2.6.32-34 libcups2 tzdata-java libjpeg62 linux-headers-2.6.32-34-server libavahi-client3 ca-certificates-java libnss3-1d Use 'apt-get autoremove' to remove them. The following extra packages will be installed: linux-image-2.6.32-36-server Suggested packages: fdutils linux-doc-2.6.32 linux-source-2.6.32 linux-tools The following NEW packages will be installed: linux-image-2.6.32-36-server 0 upgraded, 1 newly installed, 0 to remove and 8 not upgraded. 3 not fully installed or removed. Need to get 0B/31.8MB of archives. After this operation, 128MB of additional disk space will be used. Do you want to continue [Y/n]? (Reading database ... 145200 files and directories currently installed.) Unpacking linux-image-2.6.32-36-server (from .../linux-image-2.6.32-36-server_2.6.32-36.79_amd64.deb) ... Done. dpkg: error processing /var/cache/apt/archives/linux-image-2.6.32-36-server_2.6.32-36.79_amd64.deb (--unpack): failed in buffer_write(fd) (10, ret=-1): backend dpkg-deb during `./boot/vmlinuz-2.6.32-36-server': No space left on device dpkg-deb: subprocess paste killed by signal (Broken pipe) Running postrm hook script /usr/sbin/update-grub. Generating grub.cfg ... Found linux image: /boot/vmlinuz-2.6.32-35-server Found linux image: /boot/vmlinuz-2.6.32-34-server Found initrd image: /boot/initrd.img-2.6.32-34-server Found linux image: /boot/vmlinuz-2.6.32-33-server Found initrd image: /boot/initrd.img-2.6.32-33-server Found linux image: /boot/vmlinuz-2.6.32-32-server Found initrd image: /boot/initrd.img-2.6.32-32-server Found linux image: /boot/vmlinuz-2.6.32-31-server Found initrd image: /boot/initrd.img-2.6.32-31-server Found linux image: /boot/vmlinuz-2.6.32-30-server Found initrd image: /boot/initrd.img-2.6.32-30-server Found memtest86+ image: /memtest86+.bin done Errors were encountered while processing: /var/cache/apt/archives/linux-image-2.6.32-36-server_2.6.32-36.79_amd64.deb E: Sub-process /usr/bin/dpkg returned an error code (1) How do I free up space on /boot so that I can fix my dependencies? Should I just delete the files manually? And then, should I resize my /boot to be larger, so this doesn't happen again? If so, how? If not, what maintenance should I be running regularly to prevent the accumulation of this cruft?

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  • Web Space Reseller Packages At Affordable Rates

    There are very few companies out there selling web space reseller packages at competitive rates. As a matter of fact, getting hold of web space reseller packages at highly competitive rates is a very... [Author: John Anthony - Web Design and Development - May 18, 2010]

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  • Resize the disk space of Ubuntu 12.04

    - by lara
    I m using Wubi 12.04. While I installed, the disk size was 18 GB. Now I m almost running out the space. But I have enough space in Windows drive in which I installed Wubi. I tried to increase the size of Ubuntu from this link https://help.ubuntu.com/community/ResizeandDuplicateWubiDisk But It gives the msg wubi-resize.sh: The new size (5 GB) isn't sufficient to hold your wubi-resize.sh: existing install (18 GB) plus a freespace buffer What should I do?

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  • SQL Server Compressed Backups Disk Space Needs

    SQL Server 2008 and later offers the ability to create compressed backup files. When creating the compressed backup, how much space is really needed and when does the space get allocated for the backup file? The Future of SQL Server Monitoring "Being web-based, SQL Monitor enables you to check on your servers from almost any location" Jonathan Allen.Try SQL Monitor now.

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  • update manager - insufficient storage space (false alarm)

    - by itsols
    I'm trying to run Update Manager but it keeps reporting that there's not enough space. Here's the screenshot: I ran sudo apt-get update && sudo apt-get upgrade from the terminal but still update manager says that there are updates and I cannot seem to get pass this message. I have even removed many programs from my system and there is supposed to be at least 6GB of disk space free. What can I do?

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  • What app can i use to track disk space?

    - by acidzombie24
    I dont know what is going on but my disk space seems to be going down and i am not downloading anything. What app can i use on windows to keep track of diskspace? I used windirstat which tells you how much data a folder is holding but i still cant figure out the problem. I did notice a folder holding 1.7gb for visual studio's intellitrack (or whatever that thing is called)

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  • Disable password complexity rule in Active Directory

    - by Dan Revell
    Where do I go to disable the password complexity policy for the domain. I've logged onto the domain controller (Windows Server 2008) and found the option in local policies which is of course locked from any changes. However I can't find the same sort of policies in the group policy manager. Which nodes do I have to expand out to find it?

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  • Reclaim Vertical UI Space by Adding a Toolbar to the Left or Right Side of Firefox

    - by Asian Angel
    Do you need to make the most efficient use possible of vertical UI space on your system’s screen, but have horizontal space to spare? Now you can shift the toolbar icons and their awesome functionality to a slim sidebar in Firefox using the Vertical Toolbar extension. As you can see above the sidebar even picked up on our Personas Theme to help it blend in nicely with the rest of the browser. You can access the options for the new toolbar by right clicking within the toolbar area. These are the options for the toolbar…you can choose the side of Firefox that works best for toolbar placement, adjust display, hiding, & animation settings, define how the buttons display, and add/remove additional buttons as desired. Once you open the Customize Toolbar Window make any desired additions or removals just like you would before on the top UI section and close when finished. Note: Works with Firefox 4.0b7pre – 4.0.* Vertical Toolbar [Mozilla Add-ons] Latest Features How-To Geek ETC How to Enable User-Specific Wireless Networks in Windows 7 How to Use Google Chrome as Your Default PDF Reader (the Easy Way) How To Remove People and Objects From Photographs In Photoshop Ask How-To Geek: How Can I Monitor My Bandwidth Usage? Internet Explorer 9 RC Now Available: Here’s the Most Interesting New Stuff Here’s a Super Simple Trick to Defeating Fake Anti-Virus Malware Comix is an Awesome Comics Archive Viewer for Linux Get the MakeUseOf eBook Guide to Speeding Up Windows for Free Need Tech Support? Call the Star Wars Help Desk! [Video Classic] Reclaim Vertical UI Space by Adding a Toolbar to the Left or Right Side of Firefox Androidify Turns You into an Android-style Avatar Reader for Android Updates; Now with Feed Widgets and More

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  • Sharing My Thoughts on Space Flight

    - by Grant Fritchey
    This went out in the DBA newsletter from Red Gate, but I enjoyed writing it so much, I thought I'd share it to a wider audience: I grew up watching the US space program. I watched men walk on the moon for the first time in 1969, when I was only six years old. From that moment on, I dreamed of going into space. I studied aeronautics and tried to get into the Air Force Academy, all in preparation for my long career as an astronaut. Clearly, that didn't quite work out for me. But it sure could for you. At Red Gate, we're running a new contest: DBA in Space. The prize is a sub-orbital flight. When I first got word of this contest, my immediate response was, "And you need me to go right away and do a test flight? Excellent!" No, no test flight needed, plus I was pretty low on the list of volunteers. "That's OK, I'll just enter." Then I was told that, as a Red Gate employee, I couldn't win. My next response was, "I quit".eventually, I was talked down off the ledge, and agreed to help make this special for some other DBA. Many (most?) of us are science fiction fans, either the soft science of Star Trek and Star Wars, or the hard science of Niven and Pournelle, or Allen Steele. We watched the Shuttles go up and land. We've been dreaming of our own trips into orbit and our vacation-home on the Moon for a long, long time. All that might not arrive on schedule, but you've got a shot at breaking clear of the atmosphere. The first stage is a video quiz, starring Brad McGehee, and it's live at www.DBAinSpace.com now. Go for it. Good luck and God speed!

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  • JavaScript 3D space ship rotation

    - by user36202
    I am working with a fairly low-level JavaScript 3D API (not Three.js) which uses euler angles for rotation. In most cases, euler angles work quite well for doing things like aligning buildings, operating a hovercraft, or looking around in the first-person. However, in space there is no up or down. I want to control the ship's roll, pitch, and yaw. To do that, some people would use a local coordinate system or a permenant matrix or quaternion or whatever to represent the ship's angle. However, since I am not most people and am using a library that deals exclusively in euler angles, I will be using relative angles to represent how to rotate the ship in space and getting the resulting non-relative euler angles. For you math nerds, that means I need to convert 3 euler angles (with Y being the vertical axis, X representing the pitch, and Z representing a roll which is unaffected by the other angles, left-handed system) into a 3x3 orientation matrix, do something fancy with the matrix, and convert it back into the 3 euler angles. Euler to matrix to euler. Somebody has posted something similar to this on SO (http://stackoverflow.com/questions/1217775/rotating-a-spaceship-model-for-a-space-simulator-game) but he ended up just working with a matrix. This will not do for me. Also, I am using JavaScript, not C++. What I want essentially are the functions do_roll, do_pitch, and do_yaw which only take in and put out euler angles. Many thanks.

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  • No space left on disk

    - by Ned
    folks. I'm trying to copy/move files to an external 1 TB hard drive with about 50 GB remaining space. I receive a "no space left on disk" when I try. I've moved files off and retried, but still get the same message. Disk Usage Analyzer, Properties, and freeware Treesize all report available hard drive space of about 50 GB. I've tried df -i (50 GB available) and df -k, with the latter reporting only 1% of inode usage. I've been able to save files from Firefox to the drive also. I can't even rename files without getting the message. Yesterday in the midst of trying to figure this out I tried to move 4 files to the drive and got the message. Today, I found them on the drive. What's up with that? (That's the only time that has happened to my knowledge.) Is this an ubuntu problem? or is my hard drive just about to fail because of something like a controller problem? Any thoughts would be appreciated.

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  • LibGDX drawing map using tiles without space

    - by Enayat Muradi
    I am making a board game. To draw the map on the board I use different tiles. On some screen the map looks good but on some other screens there is a space between the tiles. How can I do so there won't be any space between the tiles? I am designing my game with the size 480x800. To fit other screens I stretch it. My tiles looks like this: I draw the map using a for loop to draw the tile in different (x,y) position on screen. Here is what I mean with space between tiles: Screen with 240x400 Screen with 360x600, here there is no spacing between tiles. I use camera and the screen to draw I don't use stage. I have also tried to use Viewport but I get the same results. cam = new OrthographicCamera();cam.setToOrtho(true, gameWidth, gameHeight); batcher = new SpriteBatch(); batcher.setProjectionMatrix(cam.combined); shapeRenderer = new ShapeRenderer(); shapeRenderer.setProjectionMatrix(cam.combined); How can I do to solve the problem?

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  • Getting file system free space

    - by Fred Riley
    This isn't a problem as such, more a request for information based on ignorance of the Linux filesystem. The very short question is: How do I find out how much free and used space there is on the volume from which Ubuntu is running? More detail: I'm running Ubuntu 12.04 from a 64Gb USB3 stick, created from booting up a year-old Ubuntu 12.04 DVD and running Startup Disk Creator. The reason for this is that the Master Boot Record on my hard disk, holding Windoze 7, has gone belly-up, and whilst awaiting a recovery disk I'm running Ubunto off USB or DVD as a 'trial'. (And will continue to run Ubuntu after restoring Windoze, as I've rediscovered my love of the penguin :o)) After installing Ubuntu on the stick I ran the software update app, which downloaded some 450Mb of updates and took a couple of hours to install to the stick. A couple of times I got a message saying that disk space was short. So I looked in the file manager (or whatever it's called these days) and couldn't see the stick listed, just: SYSTEM hard disk (listed as 479Gb Filesystem) two other partitions that had been created by Windoze "4.3GB Filesystem" which when I try to open gives the error "Could not find /cow", and when I try to unmount it tells me I can't because it's not mounted - D'OH!! Edit: screenshot of file manager Edit: screenshot of low disk space warning What I can't see is the USB stick from which I'm running Ubuntu. Where's it gone, anybody know? This is tangentially related to a previous question of mine about system tools, in that I'm trying to get control and knowledge of the system in the newest incarnation of Ubuntu.

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