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  • Oracle OpenWorld Kicks Off Today Delivering A Full Week of Insight, Education, and Unique Experiences

    - by Jeri Kelley
    San Francisco has been transformed into a sea of red and more than 50,000 attendees from 140 countries will converge in the Bay Area for a week of education and insight into Oracle's strategy and roadmap on today’s leading technology initiatives, including engineered systems, cloud computing, business analytics and big data, and customer experience.  Tonight kicked off with Oracle CEO Larry Ellison discussing how Oracle is taking a fundamentally different approach to delivering technology that is engineered to work together to give customers extreme performance, simplicity, and cost savings.  The jam-packed week continues with: More than 2,500 educational sessions Nearly 3,500 customer and partner speakers from marquee brands sharing how they are using Oracle technology to power their businesses Over 400 Oracle product demonstrations in the DEMOgrounds – make sure to stop by to see the latest demonstrations for our Customer Experience solutions including Oracle Commerce, Oracle RightNow, Oracle WebCenter, Oracle Fusion CRM, Oracle Social Relationship Management, and more. With more educational content than ever before, OpenWorld also expands to include six sub-conferences within the main OpenWorld umbrella including the Customer Experience Summit @ OpenWorld which runs October 3rd-5th.  All of this education and insight comes with some fun as well.  OpenWorld has become an exciting destination with new experiences unveiled each year including the debut of the first annual Oracle OpenWorld Music Festival, featuring some of today’s hottest acts, emerging bands and DJs over five nights playing at locations throughout San Francisco. Our Customer Experience team will be blogging and tweeting all week to keep you up-to-date so be sure to subscribe to our Customer Experience blog and follow us on Twitter and Facebook: @OracleCX @OracleCommerce @OracleCRM Facebook.com/OracleCustomerExperience If you are at OpenWorld, we hope you have a great week and get the knowledge you need to take your Oracle applications to the next level.  And, if you were not able to make it this year, be sure to tune into the sessions that are broadcast live online. 

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  • What is So Unique About Node.js?

    - by Adrian Shum
    Recently there has been a lot of praise for Node.js. I am not a developer that has had much exposure to network application. From my bare understanding of Nodes.js, its strength is: we have only one thread handling multiple connections, providing an event-based architecture. However, for example in Java, I can create only one thread using NIO/AIO (which is non-blocking APIs from my bare understanding), and handle multiple connections using that thread, and I provide an event-based architecture to implement the data handling logic (shouldn't be that difficult by providing some callback etc) ? Given JVM being a even more mature VM than V8 (I expect it to run faster too), and event-based handling architecture seems to be something not difficult to create, I am not sure why Node.js is attracting so much attention. Did I miss some important points?

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  • Why Nodes.js being that "unique"?

    - by Adrian Shum
    Recently years there are lots of praise to Nodes.js. I am not a developer that have much exposure on network application. From my bare understanding of Nodes.js, its strength is: We are having only on thread handling multiple connections, providing a event-based architecture. However, for example in Java, what if I am having only one thread, using NIO/AIO (which is non-blocking APIs from my bare understanding), and handle multiple connections using that thread, and I provide an event-based architecture to implement the data handling logic (shouldn't be that difficult by providing some callback etc) ? Given JVM being a even more mature VM than V8 (I expect it run faster too), and event-based handling architecture seems not something difficult to create. I am not sure why Nodes.js is attracting so much attention. Did I miss some important points?

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  • Oracle Database Appliance - How to Sell a Unique Product : Webcast Replay

    - by Cinzia Mascanzoni
    Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:10.0pt; font-family:"Calibri","sans-serif"; mso-bidi-font-family:"Times New Roman";} Learn about: ODA Benefits : Fast, Easy, Cost Efficient, Highly Reliable Feedback from early Customer Wins : What can we learn? Objection Handling : Overcoming the most common customer questions Going beyond the Database: The ODA Eco System for applications, backup & more If you missed the  webcasts in April, go on the EMEA VAD Resource Center - Enablement Tab, click here and follow the instruction to access the replay.

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  • Graduating soon with a computer science degree, but have unique circumstances [closed]

    - by Donnie
    I joined the Navy in 1998, and was admitted into Nuclear Power Training. I got my electrician's mate certificate, but was put on medical hold when I was in Nuclear Power Training. I was sent to the Naval Hospital, and received a medical (honorable) discharge in the middle of 2000. I decided to stay at home and raise my son, and my girlfriend worked. a few years ago, I decided that I want to work as a programmer, so I went to college and will soon be graduating with a degree in computer science. I hope to finish with a relatively high GPA, 3.8 or 3.9. My question is this: How much, if any, of my Navy experience should I put on my resume? And how do I explain my nine year gap as a stay at home dad? Do I even try to explain it? I know recent college graduates typically have no experience, but obviously I'm not the typical college graduate. Will my long absence from working, or my relatively short duration in the Navy hurt my chances? Should I just put the college on my resume, and hope that HR thinks I'm younger than I am? Obviously, then, my age would show at the interview and there would be questions. Any help is appreciated.

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  • Why Unique and Quality Content?

    Its rightly said in the search engine optimization block that "Content Is King." This term is coined a hell of a lot number of times in the virtual world, then you can count. Let us have a look why is it so?

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  • Unique Content is the Best Way to Win the SEO Game

    It has always been the case that in the world of search engine optimisation content is king - well almost always and it affects search engine ranking. Gone are the days when you could saturate your website with keywords and hide them by using identical font and background colours. And you certainly cannot create articles with so many keywords that they don't actually make sense any more.

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  • Overview: Unique offerings for OPN members

    - by michaela.seika(at)oracle.com
    You need knowledge and skills to pass the exams to get specialised. We have mapped the Bootcamps and Courses that will enable you to do this. Oracle University knows that you need knowledge and skills quickly and recognises that you learn fast. Accelerate your learning curve by taking one of our OPN Only Bootcamps . They have highly attractive prices and your OPN discount is applied on top of this. View the schedule for each country at the following webpage:http://education.oracle.com/pls/web_prod-plq-dad/db_pages.getpage?page_id=400&p_name=OPNOFFERS

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  • Are "skip deltas" unique to svn?

    - by echinodermata
    The good folks who created the SVN version control system use a structure they refer to as "skip deltas" to store the revision history of files internally. A revision is stored as a delta against an earlier revision. However, revision N is not necessarily stored as a delta against revision N-1, like this: 0 <- 1 <- 2 <- 3 <- 4 <- 5 <- 6 <- 7 <- 8 <- 9 Instead, revision N is stored as a delta against N-f(N), where f(N) is the greatest power of two that divides N: 0 <- 1 2 <- 3 4 <- 5 6 <- 7 0 <------ 2 4 <------ 6 0 <---------------- 4 0 <------------------------------------ 8 <- 9 (Superficially it looks like a skip list but really it's not that similar - for instance, skip deltas are not interested in supporting insertion in the middle of the list.) You can read more about it here. My question is: Do other systems use skip deltas? Were skip deltas known/used/published before SVN, or did the creators of SVN invent it themselves?

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  • Bookmark Your Greatness With Unique SEO Tips

    If you want a way to make your website stand out from the rest, having a social bookmarking service is a great way to have your site filtered out from the rest. Having your website sent to over a hundred different social bookmarking websites where they will be marked as quality and not filtered out when viewers perform searches.

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  • MySQL unique clustered constraint not constraining as expected

    - by igor
    I'm creating a table with: CREATE TABLE movies ( id INT AUTO_INCREMENT PRIMARY KEY, name CHAR(255) NOT NULL, year INT NOT NULL, inyear CHAR(10), CONSTRAINT UNIQUE CLUSTERED (name, year, inyear) ); (this is jdbc SQL) Which creates a MySQL table with a clustered index, "index kind" is "unique", and spans the three clustered columns: full size However, once I dump my data (without exceptions thrown), I see that the uniqueness constraint has failed: SELECT * FROM movies WHERE name = 'Flawless' AND year = 2007 AND inyear IS NULL; gives: id, name, year, inyear 162169, 'Flawless', 2007, NULL 162170, 'Flawless', 2007, NULL Does anyone know what I'm doing wrong here?

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  • How do I create a check constraint?

    - by Zack Peterson
    Please imagine this small database... Diagram Tables Volunteer Event Shift EventVolunteer ========= ===== ===== ============== Id Id Id EventId Name Name EventId VolunteerId Email Location VolunteerId Phone Day Description Comment Description Start End Associations Volunteers may sign up for multiple events. Events may be staffed by multiple volunteers. An event may have multiple shifts. A shift belongs to only a single event. A shift may be staffed by only a single volunteer. A volunteer may staff multiple shifts. Check Constraints Can I create a check constraint to enforce that no shift is staffed by a volunteer that's not signed up for that shift's event? Can I create a check constraint to enforce that two overlapping shifts are never staffed by the same volunteer?

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  • MYSQL: Error: Cannot add or update a child row: a foreign key constraint fails

    - by DalivDali
    Hi all, Using MySQL on Windows OS, and am getting an error upon attempting to create a foreign key between two tables: CREATE TABLE tf_traffic_stats ( domain_name char(100) NOT NULL, session_count int(11) NULL, search_count int(11) NULL, click_count int(11) NULL, revenue float NULL, rpm float NULL, cpc float NULL, traffic_date date NOT NULL DEFAULT '0000-00-00', PRIMARY KEY(domain_name,traffic_date)) and CREATE TABLE td_domain_name ( domain_id int(10) UNSIGNED AUTO_INCREMENT NOT NULL, domain_name char(100) NOT NULL, update_date date NOT NULL, PRIMARY KEY(domain_id)) The following statement gives me the error present in the subject line (cannot add or update a child row: a foreign key constraint fails): ALTER TABLE td_domain_name ADD CONSTRAINT FK_domain_name FOREIGN KEY(domain_name) REFERENCES tf_traffic_stats(domain_name) ON DELETE RESTRICT ON UPDATE RESTRICT Can someone point me in the right direction of what may be causing the error. I also have a foreign key referencing td_domain_name.domain_id, but I don't think this should be interfering... Appreciate it!

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  • SQL CHECK constraint issues

    - by blahblah
    I'm using SQL Server 2008 and I have a table with three columns: Length, StartTime and EndTime. I want to make a CHECK constraint on this table which says that: if Length == NULL then StartTime <> NULL and EndTime <> NULL else StartTime == NULL and EndTime == NULL I've begun to try things like this: Length == NULL AND StartTime <> NULL AND EndTime <> NULL Obviously this is not enough, but even this simple expression will not validate. I get the error: "Error validating 'CK_Test_Length_Or_Time'. Do you want to edit the constraint?" Any ideas on how to go about doing this?

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  • Identifying which value of a multi-row inserts fails foreign key constraint

    - by Jonathan
    I have a multi-row insert that looks something like: insert into table VALUES (1, 2, 3), (4, 5, 6), (7, 8, 9); Assume the first attribute (1, 4, 7) is a foreign key to another table and assume that this referenced table does not have the value '4'. A MySQLExeption is thrown with error code 1452. EXCEPTION: Cannot add or update a child row: a foreign key constraint fails (dbName/tableName, CONSTRAINT id FOREIGN KEY (customer_id) REFERENCES referencedTable (customer_id)) Is there a way to identify which value caused the error? I would love to give my user an error message that said something like: Error: '4' does not exist in the referenced table. I am using the .NET mysql connector to execute the insert. Thanks- Jonathan

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  • After Trigger execute before constraint check in oracle

    - by satakare
    Hi, I have After Insert/Update trigger on Table T1 which get the referential data for Col1 from T2 and does some work and insert it into another table. The col1 is FK to Table T2. When user insert the incorrect or non existing value into the Col1 and if trigger is disabled I am getting constraint error that is fine. But when trigger is enabled and user insert the wrong value in Col1 trigger is getting fired and shows the 'no data found' error message. Actually I am expecting the table to throw constraint error, but trigger is throwing it. Please let me know your comments about this trigger behaviour.

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  • Cannot add or update a child row: a foreign key constraint fails

    - by myaccount
    // Getting the id of the restaurant to which we are uploading the pictures $restaurant_id = intval($_GET['restaurant-id']); if(isset($_POST['submit'])) { $tmp_files = $_FILES['rest_pics']['tmp_name']; $target_files = $_FILES['rest_pics']['name']; $tmp_target = array_combine($tmp_files, $target_files); $upload_dir = $rest_pics_path; foreach($tmp_target as $tmp_file => $target_file) { if(move_uploaded_file($tmp_file, $upload_dir."/".$target_file)) { $sql = sprintf(" INSERT INTO rest_pics (branch_id, pic_name) VALUES ('%s', '%s')" , mysql_real_escape_string($restaurant_id) , mysql_real_escape_string(basename($target_file))); $result = mysql_query($sql) or die(mysql_error()); } I get the next error: Cannot add or update a child row: a foreign key constraint fails (rest_v2.rest_pics, CONSTRAINT rest_pics_ibfk_1 FOREIGN KEY (branch_id) REFERENCES rest_branches (branch_id) ON DELETE CASCADE ON UPDATE CASCADE However, this error totally disappears and everything goes well when I put directly the restaurant id (14 for example) instead of $restaurant_id variable in the sql query. The URL am getting the id from is: http://localhost/rest_v2/public_html/admin/add-delete-pics.php?restaurant-id=2 Any help please?

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  • Error 1005 when adding a foreign key constraint on mysql table

    - by luc
    Hello, I have a problem when upgrading a django and mysql app with south. I've tried to make a sql-based upgrade with the code generated by the django sqlall command and I have a similar problem. Here is the sql code: CREATE TABLE `programmations_basissupport` ( `id` integer AUTO_INCREMENT NOT NULL PRIMARY KEY, `value` numeric(6, 0) NOT NULL ) ALTER TABLE `programmations_concert` ADD `basis_support_id` integer AFTER program_status_id; ALTER TABLE `programmations_concert` ADD CONSTRAINT `basis_support_id_refs_id_1e4ed8d7` FOREIGN KEY (`basis_support_id`) REFERENCES `programmations_basissupport` (`id`); An error is raised when adding the FK constraint: ERROR 1005 (HY000): Can't create table 'apidev_mnl.#sql-106e_632b00a' (errno: 150) Does anybody have an idea? Update: DEFAULT values where missing but even if I add the default='' in the django model, the creation of foreign keys fails. Thanks for your help

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  • SQL Check Constraint cannot reference other column

    - by user1777711
    I trying to add this sql check in ALTER TABLE School add Role check_role CHECK (check_role IN ('Teaching Assistant', 'Lecturer', 'Professor')); I get the error below ERROR at line 3: ORA-02438: Column check constraint cannot reference other columns SQL> desc School; Name Null? Type ----------------------------------------- -------- ---------------------------- STAFFNUM NOT NULL VARCHAR2(12) NAME NOT NULL VARCHAR2(50) ADDRESS NOT NULL VARCHAR2(300) DOB DATE I am trying add a column call Role, with the check constraint check_role I am using Oracle SQL. Thanks for all help!

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  • Oracle pl\sql question for my homework in oracle 11G class [migrated]

    - by Bjolds
    I am new to oracle 11G programming and i have run into a tough situation with pl\sql funtions and automation. I ame unsure how to create the function for the automation of Registration system for a College registration system. Here is what i want to do. I want to automate the registrations system so that it automaticly registers students. Then I want a procedure to automate the grading system. I have included the code that i am written to make most of this assignment work which it does but unsure how to incorporate Pl\SQL automated fuctions for the registrations system, and the grading system. So Any help or Ideas I would greatly appreciate please. set Linesize 250 set pagesize 150 drop table student; drop table faculty; drop table Course; drop table Section; drop table location; DROP TABLE courseInstructor; DROP TABLE Registration; DROP TABLE grade; create table student( studentid number(10), Lastname varchar2(20), Firstname Varchar2(20), MI Char(1), address Varchar2(20), city Varchar2(20), state Char(2), zip Varchar2(10), HomePhone Varchar2(10), Workphone Varchar2(10), DOB Date, Pin VARCHAR2(10), Status Char(1)); ALTER TABLE Student Add Constraint Student_StudentID_pk Primary Key (studentID); Insert into student values (1,'xxxxxxxx','xxxxxxxxxx','x','xxxxxxxxxxxxxxx','Columbus','oh','44159','xxx-xxx-xxxx','xxx-xxx-xxxx','06-Mar-1957','1211','c'); create table faculty( FacultyID Number(10), FirstName Varchar2(20), Lastname Varchar2(20), MI Char(1), workphone Varchar2(10), CellPhone Varchar2(10), Rank Varchar2(20), Experience Varchar2(10), Status Char(1)); ALTER TABLE Faculty ADD Constraint Faculty_facultyId_PK PRIMARY KEY (FacultyID); insert into faculty values (1,'xxx','xxxxxxxxxxxx',xxx-xxx-xxxx','xxx-xxx-xxxx','professor','20','f'); create table Course( CourseId number(10), CourseNumber Varchar2(20), CourseName Varchar(20), Description Varchar(20), CreditHours Number(4), Status Char(1)); ALTER TABLE Course ADD Constraint Course_CourseID_pk PRIMARY KEY(CourseID); insert into course values (1,'cit 100','computer concepts','introduction to PCs','3.0','o'); insert into course values (2,'cit 101','Database Program','Database Programming','4.0','o'); insert into course values (3,'Math 101','Algebra I','Algebra I Concepts','5.0','o'); insert into course values (4,'cit 102a','Pc applications','Aplications 1','3.0','o'); insert into course values (5,'cit 102b','pc applications','applications 2','3.0','o'); insert into course values (6,'cit 102c','pc applications','applications 3','3.0','o'); insert into course values (7,'cit 103','computer concepts','introduction systems','3.0','c'); insert into course values (8,'cit 110','Unified language','UML design','3.0','o'); insert into course values (9,'cit 165','cobol','cobol programming','3.0','o'); insert into course values (10,'cit 167','C++ Programming 1','c++ programming','4.0','o'); insert into course values (11,'cit 231','Expert Excel','spreadsheet apps','3.0','o'); insert into course values (12,'cit 233','expert Access','database devel.','3.0','o'); insert into course values (13,'cit 169','Java Programming I','Java Programming I','3.0','o'); insert into course values (14,'cit 263','Visual Basic','Visual Basic Prog','3.0','o'); insert into course values (15,'cit 275','system analysis 2','System Analysis 2','3.0','o'); create table Section( SectionID Number(10), CourseId Number(10), SectionNumber VarChar2(10), Days Varchar2(10), StartTime Date, EndTime Date, LocationID Number(10), SeatAvailable Number(3), Status Char(1)); ALTER TABLE Section ADD Constraint Section_SectionID_PK PRIMARY KEY(SectionID); insert into section values (1,1,'18977','r','21-Sep-2011','10-Dec-2011','1','89','o'); create table Location( LocationId Number(10), Building Varchar2(20), Room Varchar2(5), Capacity Number(5), Satus Char(1)); ALTER TABLE Location ADD Constraint Location_LocationID_pk PRIMARY KEY (LocationID); insert into Location values (1,'Clevleand Hall','cl209','35','o'); insert into Location values (2,'Toledo Circle','tc211','45','o'); insert into Location values (3,'Akron Square','as154','65','o'); insert into Location values (4,'Cincy Hall','ch100','45','o'); insert into Location values (5,'Springfield Dome','SD','35','o'); insert into Location values (6,'Dayton Dorm','dd225','25','o'); insert into Location values (7,'Columbus Hall','CB354','15','o'); insert into Location values (8,'Cleveland Hall','cl204','85','o'); insert into Location values (9,'Toledo Circle','tc103','75','o'); insert into Location values (10,'Akron Square','as201','46','o'); insert into Location values (11,'Cincy Hall','ch301','73','o'); insert into Location values (12,'Dayton Dorm','dd245','57','o'); insert into Location values (13,'Springfield Dome','SD','65','o'); insert into Location values (14,'Cleveland Hall','cl241','10','o'); insert into Location values (15,'Toledo Circle','tc211','27','o'); insert into Location values (16,'Akron Square','as311','28','o'); insert into Location values (17,'Cincy Hall','ch415','73','o'); insert into Location values (18,'Toledo Circle','tc111','67','o'); insert into Location values (19,'Springfield Dome','SD','69','o'); insert into Location values (20,'Dayton Dorm','dd211','45','o'); Alter Table Student Add Constraint student_Zip_CK Check(Rtrim (Zip,'1234567890-') is null); Alter Table Student ADD Constraint Student_Status_CK Check(Status In('c','t')); Alter Table Student ADD Constraint Student_MI_CK2 Check(RTRIM(MI,'abcdefghijklmnopqrstuvwxyz')is Null); Alter Table Student Modify pin not Null; Alter table Faculty Add Constraint Faculty_Status_CK Check(Status In('f','a','i')); Alter table Faculty ADD Constraint Faculty_Rank_CK Check(Rank In ('professor','doctor','instructor','assistant','tenure')); Alter table Faculty ADD Constraint Faculty_MI_CK2 Check(RTRIM(MI,'abcdefghijklmnopqrstuvwxyz')is Null); Update Section Set Starttime = To_date('09-21-2011 6:00 PM', 'mm-dd-yyyy hh:mi pm'); Update Section Set Endtime = To_date('12-10-2011 9:50 PM', 'mm-dd-yyyy hh:mi pm'); alter table Section Add Constraint StartTime_Status_CK Check (starttime < Endtime); Alter Table Section Add Constraint Section_StartTime_ck check (StartTime < EndTime); Alter Table Section ADD Constraint Section_CourseId_FK FOREIGN KEY (CourseID) References Course(CourseId); Alter Table Section ADD Constraint Section_LocationID_FK FOREIGN KEY (LocationID) References Location (LocationId); Alter Table Section ADD Constraint Section_Days_CK Check(RTRIM(Days,'mtwrfsu')IS Null); update section set seatavailable = '99'; Alter Table Section ADD Constraint Section_SeatsAvailable_CK Check (SeatAvailable < 100); Alter Table Course Add Constraint Course_CreditHours_ck check(CreditHours < = 6.0); update location set capacity = '99'; Alter Table Location Add Constraint Location_Capacity_CK Check(Capacity < 100); Create Table Registration ( StudentID Number(10), SectionID Number(10), Constraint Registration_pk Primary key (studentId, Sectionid)); Insert into registration values (1, 2); Insert into Registration values (2, 3); Insert into registration values (3, 4); Insert into registration values (4, 5); Insert into registration values (5, 6); Insert into registration values (6, 7); Insert into registration values (7, 8); Insert into registration values (8, 9); insert into registration values (9, 10); insert into registration values (10, 11); insert into registration values (9, 12); insert into registration values (8, 13); insert into registration values (7, 14); insert into registration values (6, 15); insert into registration values (5, 17); insert into registration values (4, 18); insert into registration values (3, 19); insert into registration values (2, 20); insert into registration values (1, 21); insert into registration values (2, 22); insert into registration values (3, 23); insert into registration values (4, 24); insert into registration values (5, 25); Insert into registration values (6, 24); insert into registration values (7, 23); insert into registration values (8, 22); insert into registration values (9, 21); insert into registration values (10, 20); insert into registration values (9, 19); insert into registration values (8, 17); Create Table courseInstructor( FacultyID Number(10), SectionID Number(10), Constraint CourseInstructor_pk Primary key (FacultyId, SectionID)); insert into courseInstructor values (1, 1); insert into courseInstructor values (2, 2); insert into courseInstructor values (3, 3); insert into courseInstructor values (4, 4); insert into courseInstructor values (5, 5); insert into courseInstructor values (5, 6); insert into courseInstructor values (4, 7); insert into courseInstructor values (3, 8); insert into courseInstructor values (2, 9); insert into courseInstructor values (1, 10); insert into courseInstructor values (5, 11); insert into courseInstructor values (4, 12); insert into courseInstructor values (3, 13); insert into courseInstructor values (2, 14); insert into courseInstructor values (1, 15); Create table grade( StudentID Number(10), SectionID Number(10), Grade Varchar2(1), Constraint grade_pk Primary key (StudentID, SectionID)); CREATE OR REPLACE TRIGGER TR_CreateGrade AFTER INSERT ON Registration FOR EACH ROW BEGIN INSERT INTO grade (SectionID,StudentID,Grade) VALUES(:New.SectionID,:New.StudentID,NULL); END TR_createGrade; / CREATE OR REPLACE FORCE VIEW V_reg_student_course AS SELECT Registration.StudentID, student.LastName, student.FirstName, course.CourseName, Registration.SectionID, course.CreditHours, section.Days, TO_CHAR(StartTime, 'MM/DD/YYYY') AS StartDate, TO_CHAR(StartTime, 'HH:MI PM') AS StartTime, TO_CHAR(EndTime, 'MM/DD/YYYY') AS EndDate, TO_CHAR(EndTime, 'HH:MI PM') AS EndTime, location.Building, location.Room FROM registration, student, section, course, location WHERE registration.StudentID = student.StudentID AND registration.SectionID = section.SectionID AND section.LocationID = location.LocationID AND section.CourseID = course.CourseID; CREATE OR REPLACE FORCE VIEW V_teacher_to_course AS SELECT courseInstructor.FacultyID, faculty.FirstName, faculty.LastName, courseInstructor.SectionID, section.Days, TO_CHAR(StartTime, 'MM/DD/YYYY') AS StartDate, TO_CHAR(StartTime, 'HH:MI PM') AS StartTime, TO_CHAR(EndTime, 'MM/DD/YYYY') AS EndDate, TO_CHAR(EndTime, 'HH:MI PM') AS EndTime, location.Building, location.Room FROM courseInstructor, faculty, section, course, location WHERE courseInstructor.FacultyID = faculty.FacultyID AND courseInstructor.SectionID = section.SectionID AND section.LocationID = location.LocationID AND section.CourseID = course.CourseID; SELECT * FROM V_reg_student_course; SELECT * FROM V_teacher_to_course;

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  • Creating packages in code - Workflow

    This is just a quick one prompted by a question on the SSIS Forum, how to programmatically add a precedence constraint (aka workflow) between two tasks. To keep the code simple I’ve actually used two Sequence containers which are often used as anchor points for a constraint. Very often this is when you have task that you wish to conditionally execute based on an expression. If it the first or only task in the package you need somewhere to anchor the constraint too, so you can then set the expression on it and control the flow of execution. Anyway, back to my code sample, here’s a quick screenshot of the finished article: Now for the code, which is actually pretty simple and hopefully the comments should explain exactly what is going on. Package package = new Package(); package.Name = "SequenceWorkflow"; // Add the two sequence containers to provide anchor points for the constraint // If you use tasks, it follows exactly the same pattern, they all derive from Executable Sequence sequence1 = package.Executables.Add("STOCK:Sequence") as Sequence; sequence1.Name = "SEQ Start"; Sequence sequence2 = package.Executables.Add("STOCK:Sequence") as Sequence; sequence2.Name = "SEQ End"; // Add the precedence constraint, here we use the package's constraint collection // as it hosts the two objects we want to constrain (link) // The default constraint is a basic On Success constraint just like in the designer PrecedenceConstraint constraint = package.PrecedenceConstraints.Add(sequence1, sequence2); // Change the settings to use a (dummy) expression only constraint.EvalOp = DTSPrecedenceEvalOp.Expression; constraint.Expression = "1 == 1";   The complete code file is available to download below. SequenceWorkflow.cs

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