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  • All client browsers repeatedly asking for NTLM authentication when running through local proxy server

    - by Marko
    All client browsers repeatedly asking for NTLM authentication when running through local proxy server. When pointing browsers through the local proxy to the internet, some but not all clients are being repeatedley prompted to authenticate to the proxy server. I have inspected the headers using firefox live headers as well as fiddler, and in all cases the authentication prompts happen when requesting SSL resources. an example of this would be as follows: GET http://gmail.google.com/mail/ HTTP/1.1 Accept: image/gif, image/jpeg, image/pjpeg, image/pjpeg, application/x-shockwave- flash, application/x-ms-application, application/x-ms-xbap, application/vnd.ms- xpsdocument, application/xaml+xml, */* Accept-Language: en-gb User-Agent: Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 5.1; Trident/4.0; .NET CLR 1.1.4322; .NET CLR 2.0.50727; .NET CLR 3.0.4506.2152; .NET CLR 3.5.30729) Accept-Encoding: gzip, deflate Proxy-Connection: Keep-Alive Host: gmail.google.com GET http://gmail.google.com/mail/ HTTP/1.1 Accept: image/gif, image/jpeg, image/pjpeg, image/pjpeg, application/x-shockwave- flash, application/x-ms-application, application/x-ms-xbap, application/vnd.ms- xpsdocument, application/xaml+xml, */* Accept-Language: en-gb User-Agent: Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 5.1; Trident/4.0; .NET CLR 1.1.4322; .NET CLR 2.0.50727; .NET CLR 3.0.4506.2152; .NET CLR 3.5.30729) Accept-Encoding: gzip, deflate Proxy-Connection: Keep-Alive Host: gmail.google.com Proxy-Authorization: NTLM TlRMTVNTUAABAAAAB7IIogkACQAvAAAABwAHACgAAAAFASgKAAAAD1dJTlhQMUdGTEFHU0hJUDc= GET http://gmail.google.com/mail/ HTTP/1.1 Accept: image/gif, image/jpeg, image/pjpeg, image/pjpeg, application/x-shockwave- flash, application/x-ms-application, application/x-ms-xbap, application/vnd.ms- xpsdocument, application/xaml+xml, */* Accept-Language: en-gb User-Agent: Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 5.1; Trident/4.0; .NET CLR 1.1.4322; .NET CLR 2.0.50727; .NET CLR 3.0.4506.2152; .NET CLR 3.5.30729) Accept-Encoding: gzip, deflate Proxy-Connection: Keep-Alive Proxy-Authorization: NTLM TlRMTVNTUAADA (more stuff goes here I cut it short) Host: gmail.google.com At this point the username and password prompt has appeared in the browser, it does not matter what is typed into this box, correct credentials, random nonsense the browser does not accept anything in this box it will continue to popup. If I press cancel, I sometimes get a http 407 error, but on other occasions I click cancel the website proceeds to download and show normally. This is repeatable with some clients running through my proxy server, but in other cases it does not happen at all. In the cases where a client computer works normally, the only difference I can see is that the 3rd request for SSL resource comes back with a 200 response, see below: CONNECT gmail.google.com:443 HTTP/1.0 User-Agent: Mozilla/5.0 (compatible; MSIE 9.0; Windows NT 6.1; Trident/5.0; MALC) Proxy-Connection: Keep-Alive Content-Length: 0 Host: gmail.google.com Pragma: no-cache Proxy-Authorization: NTLM TlRMTVNTUAADAAAAGAAYAIAAAA A SSLv3-compatible ClientHello handshake was found. I have tried resetting user accounts as well as computer accounts in Active Directory. User accounts and passwords that are being used are correct and the passwords have been reset so they are not out of sync. I have removed the clients and even the proxy server from the domain, and rejoined them. I have installed a complete separate proxy server and get exactly the same problem when I point clients to a different proxy server on a different IP address.

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  • Simple continuously running XMPP client in python

    - by tom
    I'm using python-xmpp to send jabber messages. Everything works fine except that every time I want to send messages (every 15 minutes) I need to reconnect to the jabber server, and in the meantime the sending client is offline and cannot receive messages. So I want to write a really simple, indefinitely running xmpp client, that is online the whole time and can send (and receive) messages when required. My trivial (non-working) approach: import time import xmpp class Jabber(object): def __init__(self): server = 'example.com' username = 'bot' passwd = 'password' self.client = xmpp.Client(server) self.client.connect(server=(server, 5222)) self.client.auth(username, passwd, 'bot') self.client.sendInitPresence() self.sleep() def sleep(self): self.awake = False delay = 1 while not self.awake: time.sleep(delay) def wake(self): self.awake = True def auth(self, jid): self.client.getRoster().Authorize(jid) self.sleep() def send(self, jid, msg): message = xmpp.Message(jid, msg) message.setAttr('type', 'chat') self.client.send(message) self.sleep() if __name__ == '__main__': j = Jabber() time.sleep(3) j.wake() j.send('[email protected]', 'hello world') time.sleep(30) The problem here seems to be that I cannot wake it up. My best guess is that I need some kind of concurrency. Is that true, and if so how would I best go about that? EDIT: After looking into all the options concerning concurrency, I decided to go with twisted and wokkel. If I could, I would delete this post.

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  • Calculated control on subform based on current record

    - by rtochip
    I have the following: main form "customer" from a "customer" table. subform "invoices" with fields "invoice date", "invoice amount" "customer id" etc. from a table "invoices" whenever user clicks or goes to a record in the "invoices" sub form. I would like a "total so far" control to calculate the sum of the "invoices amount" up until the date of the current record being "clicked" or selected. i.e. for customer microsoft with invoices: 1) may 2 09, $150 2) may 3 09, $200 3) may 4 09, $500 If user clicks on record 2), "total so far" should show $350 If user clicks on record 1), "total so far" should show $150 If user clicks on record 3), "total so far" should show $850 Currently, I am using DSum function on an event "OnCurrent" in the subform "invoices" to set the "total so far" value. Is this method slow, inefficient? Any other simpler,cleaner,more elegant,faster, efficient method using ms access features? I want the "invoices" subform to show ALL the invoices for this customer no matter which record is clicked.

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  • What is an Efficient algorithm to find Area of Overlapping Rectangles

    - by namenlos
    My situation Input: a set of rectangles each rect is comprised of 4 doubles like this: (x0,y0,x1,y1) they are not "rotated" at any angle, all they are "normal" rectangles that go "up/down" and "left/right" with respect to the screen they are randomly placed - they may be touching at the edges, overlapping , or not have any contact I will have several hundred rectangles this is implemented in C# I need to find The area that is formed by their overlap - all the area in the canvas that more than one rectangle "covers" (for example with two rectangles, it would be the intersection) I don't need the geometry of the overlap - just the area (example: 4 sq inches) Overlaps shouldn't be counted multiple times - so for example imagine 3 rects that have the same size and position - they are right on top of each other - this area should be counted once (not three times) Example The image below contains thre rectangles: A,B,C A and B overlap (as indicated by dashes) B and C overlap (as indicated by dashes) What I am looking for is the area where the dashes are shown - AAAAAAAAAAAAAAAAAAAAAAAAAAAAAA AAAAAAAAAAAAAAAAAAAAAAAAAAAAAA AAAAAAAAAAAAAAAAAAAAAAAAAAAAAA AAAAAAAAAAAAAAAAAAAAAAAAAAAAAA AAAAAAAAAAAAAAAAAAAAAAAAAAAAAA AAAAAAAAAAAAAAAAAAAAAAAAAAAAAA AAAAAAAAAAAAAAAAAAAAAAAAAAAAAA AAAAAAAAAAAAAAAAAAAAAAAAAAAAAA AAAAAAAAAAAAAAAA--------------BBB AAAAAAAAAAAAAAAA--------------BBB AAAAAAAAAAAAAAAA--------------BBB AAAAAAAAAAAAAAAA--------------BBB BBBBBBBBBBBBBBBBB BBBBBBBBBBBBBBBBB BBBBBBBBBBBBBBBBB BBBBBB-----------CCCCCCCC BBBBBB-----------CCCCCCCC BBBBBB-----------CCCCCCCC CCCCCCCCCCCCCCCCCCC CCCCCCCCCCCCCCCCCCC CCCCCCCCCCCCCCCCCCC CCCCCCCCCCCCCCCCCCC

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  • Oracle(10) SQL: calculating final sum depending on two field

    - by Zsolt Botykai
    First the disclaimer: I never learnt any programming in school, and just have to deal with various SQL problems (too). So now I've got two tables, TABLE1: ACCNO BAL1 BAL2 11111 20 10 And TABLE2 (which has the ACCNO key, of course) related rows to '11111': DATENUM AMT 1 -5 2 -10 3 8 4 -23 5 100 6 -120 7 140 Now I have to find the new BAL1 and BAL2 using the following rules: BAL1 AMT must be substracted from or added to BAL1 until BAL1 == 0 (and BAL2 0) if BAL1 reaches 0 then the (if any) remainder of BAL1 must be substracted from BAL2 if BAL2 reaches 0 too, from then only BAL1 should be modified. So using the above data: DATENUM AMT BAL1 BAL2 0 0 20 10 /*starting record*/ 1 -5 15 10 2 -10 5 10 3 8 13 10 4 -23 0 0 5 100 100 0 6 -120 -20 0 7 140 20 0 And I need the last two BAL1 and BAL2. How can I calculate them using (Oracle 10) SQL?

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  • Kernel oops on Linux running in VirtualBox breaks some IO-related functionality on the server

    - by Kristoffer E
    We are having problems with CentOS release 6.3 running in VirtualBox on Windows 7 machines. The symptoms are the following: Everything works as normal for several hours, even days. Then something happens which breaks the system. What we still can do after this something happens: Access the web server Use existing SSH sessions to run top and free What does not work: Starting new SSH sessions (hangs after username and password is entered) Running ls in existing SSH sessions (hangs) SSI includes from our web servers that fetch data from remote machines probably more What we see on the server when this something happens is the following: Load average go from basically nothing to around 3 CPU usage is still low (5%) Disk activity is low (running iostat) Plenty of memory available Plenty of disk space available In /var/log/messages we get the following: Jun 14 01:10:48 devvm kernel: e1000 0000:00:03.0: eth0: Detected Tx Unit Hang Jun 14 01:10:48 devvm kernel: Tx Queue <0> Jun 14 01:10:48 devvm kernel: TDH <2e> Jun 14 01:10:48 devvm kernel: TDT <30> Jun 14 01:10:48 devvm kernel: next_to_use <30> Jun 14 01:10:48 devvm kernel: next_to_clean <2e> Jun 14 01:10:48 devvm kernel: buffer_info[next_to_clean] Jun 14 01:10:48 devvm kernel: time_stamp <1038284db> Jun 14 01:10:48 devvm kernel: next_to_watch <2f> Jun 14 01:10:48 devvm kernel: jiffies <103828b42> Jun 14 01:10:48 devvm kernel: next_to_watch.status <0> Jun 14 01:10:50 devvm kernel: e1000 0000:00:03.0: eth0: Detected Tx Unit Hang Jun 14 01:10:50 devvm kernel: Tx Queue <0> Jun 14 01:10:50 devvm kernel: TDH <2e> Jun 14 01:10:50 devvm kernel: TDT <30> Jun 14 01:10:50 devvm kernel: next_to_use <30> Jun 14 01:10:50 devvm kernel: next_to_clean <2e> Jun 14 01:10:50 devvm kernel: buffer_info[next_to_clean] Jun 14 01:10:50 devvm kernel: time_stamp <1038284db> Jun 14 01:10:50 devvm kernel: next_to_watch <2f> Jun 14 01:10:50 devvm kernel: jiffies <103829312> Jun 14 01:10:50 devvm kernel: next_to_watch.status <0> Jun 14 01:10:52 devvm kernel: ------------[ cut here ]------------ Jun 14 01:10:52 devvm kernel: WARNING: at net/sched/sch_generic.c:261 dev_watchdog+0x26d/0x280() (Not tainted) Jun 14 01:10:52 devvm kernel: Hardware name: VirtualBox Jun 14 01:10:52 devvm kernel: NETDEV WATCHDOG: eth0 (e1000): transmit queue 0 timed out Jun 14 01:10:52 devvm kernel: Modules linked in: vboxsf(U) ipv6 ppdev parport_pc parport microcode sg vboxguest(U) i2c_piix4 i2c_core e1000 snd_intel8x0 snd_ac97_codec ac97_bus snd_seq snd_seq_device snd_pcm snd_timer snd soundcore snd_page_alloc pcnet32 mii ext4 mbcache jbd2 sd_mod crc_t10dif ahci dm_mirror dm_region_hash dm_log dm_mod [last unloaded: scsi_wait_scan] Jun 14 01:10:52 devvm kernel: Pid: 0, comm: swapper Not tainted 2.6.32-279.el6.x86_64 #1 Jun 14 01:10:52 devvm kernel: Call Trace: Jun 14 01:10:52 devvm kernel: <IRQ> [<ffffffff8106b747>] ? warn_slowpath_common+0x87/0xc0 Jun 14 01:10:52 devvm kernel: [<ffffffff8106b836>] ? warn_slowpath_fmt+0x46/0x50 Jun 14 01:10:52 devvm kernel: [<ffffffff814595fd>] ? dev_watchdog+0x26d/0x280 Jun 14 01:10:52 devvm kernel: [<ffffffff81099138>] ? sched_clock_cpu+0xb8/0x110 Jun 14 01:10:52 devvm kernel: [<ffffffff81459390>] ? dev_watchdog+0x0/0x280 Jun 14 01:10:52 devvm kernel: [<ffffffff8107e897>] ? run_timer_softirq+0x197/0x340 Jun 14 01:10:52 devvm kernel: [<ffffffff810a21c0>] ? tick_sched_timer+0x0/0xc0 Jun 14 01:10:52 devvm kernel: [<ffffffff8102b40d>] ? lapic_next_event+0x1d/0x30 Jun 14 01:10:52 devvm kernel: [<ffffffff81073ec1>] ? __do_softirq+0xc1/0x1e0 Jun 14 01:10:52 devvm kernel: [<ffffffff81096c50>] ? hrtimer_interrupt+0x140/0x250 Jun 14 01:10:52 devvm kernel: [<ffffffff8100c24c>] ? call_softirq+0x1c/0x30 Jun 14 01:10:52 devvm kernel: [<ffffffff8100de85>] ? do_softirq+0x65/0xa0 Jun 14 01:10:52 devvm kernel: [<ffffffff81073ca5>] ? irq_exit+0x85/0x90 Jun 14 01:10:52 devvm kernel: [<ffffffff81505be0>] ? smp_apic_timer_interrupt+0x70/0x9b Jun 14 01:10:52 devvm kernel: [<ffffffff8100bc13>] ? apic_timer_interrupt+0x13/0x20 Jun 14 01:10:52 devvm kernel: <EOI> [<ffffffff810387cb>] ? native_safe_halt+0xb/0x10 Jun 14 01:10:52 devvm kernel: [<ffffffff810149cd>] ? default_idle+0x4d/0xb0 Jun 14 01:10:52 devvm kernel: [<ffffffff81009e06>] ? cpu_idle+0xb6/0x110 Jun 14 01:10:52 devvm kernel: [<ffffffff814e433a>] ? rest_init+0x7a/0x80 Jun 14 01:10:52 devvm kernel: [<ffffffff81c21f7b>] ? start_kernel+0x424/0x430 Jun 14 01:10:52 devvm kernel: [<ffffffff81c2133a>] ? x86_64_start_reservations+0x125/0x129 Jun 14 01:10:52 devvm kernel: [<ffffffff81c21438>] ? x86_64_start_kernel+0xfa/0x109 Jun 14 01:10:52 devvm kernel: ---[ end trace 2c7bb984812cf120 ]--- Jun 14 01:10:52 devvm kernel: e1000 0000:00:03.0: eth0: Reset adapter Jun 14 01:10:53 devvm abrtd: Directory 'oops-2013-06-14-01:10:53-1537-0' creation detected Jun 14 01:10:53 devvm abrt-dump-oops: Reported 1 kernel oopses to Abrt Jun 14 01:10:53 devvm abrtd: Can't open file '/var/spool/abrt/oops-2013-06-14-01:10:53-1537-0/uid': No such file or directory Jun 14 01:10:55 devvm kernel: Bridge firewalling registered After this we see for a while, every two minutes: Jun 14 01:14:22 devvm kernel: INFO: task events/0:19 blocked for more than 120 seconds. Jun 14 01:14:22 devvm kernel: "echo 0 > /proc/sys/kernel/hung_task_timeout_secs" disables this message. Jun 14 01:14:22 devvm kernel: events/0 D 0000000000000000 0 19 2 0x00000000 Jun 14 01:14:22 devvm kernel: ffff880116c4fb90 0000000000000046 00000000ffffffff 0000000000000008 Jun 14 01:14:22 devvm kernel: 0000000000016680 0000000000016680 ffff880028210400 0000000000016680 Jun 14 01:14:22 devvm kernel: ffff880116c4daf8 ffff880116c4ffd8 000000000000fb88 ffff880116c4daf8 Jun 14 01:14:22 devvm kernel: Call Trace: Jun 14 01:14:22 devvm kernel: [<ffffffff8105b483>] ? perf_event_task_sched_out+0x33/0x80 Jun 14 01:14:22 devvm kernel: [<ffffffff814fe6a5>] schedule_timeout+0x215/0x2e0 Jun 14 01:14:22 devvm kernel: [<ffffffff8100975d>] ? __switch_to+0x13d/0x320 Jun 14 01:14:22 devvm kernel: [<ffffffff814fe323>] wait_for_common+0x123/0x180 Jun 14 01:14:22 devvm kernel: [<ffffffff81060250>] ? default_wake_function+0x0/0x20 Jun 14 01:14:22 devvm kernel: [<ffffffff814fe43d>] wait_for_completion+0x1d/0x20 Jun 14 01:14:22 devvm kernel: [<ffffffff8108d093>] __cancel_work_timer+0x1b3/0x1e0 Jun 14 01:14:22 devvm kernel: [<ffffffff8108cbe0>] ? wq_barrier_func+0x0/0x20 Jun 14 01:14:22 devvm kernel: [<ffffffff8108d0f0>] cancel_work_sync+0x10/0x20 Jun 14 01:14:22 devvm kernel: [<ffffffffa01c5ca5>] e1000_down_and_stop+0x25/0x50 [e1000] Jun 14 01:14:22 devvm kernel: [<ffffffffa01cb695>] e1000_down+0x155/0x200 [e1000] Jun 14 01:14:22 devvm kernel: [<ffffffffa01cbcb0>] ? e1000_reset_task+0x0/0xe0 [e1000] Jun 14 01:14:22 devvm kernel: [<ffffffffa01cbd1e>] e1000_reset_task+0x6e/0xe0 [e1000] Jun 14 01:14:22 devvm kernel: [<ffffffff8108c760>] worker_thread+0x170/0x2a0 Jun 14 01:14:22 devvm kernel: [<ffffffff810920d0>] ? autoremove_wake_function+0x0/0x40 Jun 14 01:14:22 devvm kernel: [<ffffffff8108c5f0>] ? worker_thread+0x0/0x2a0 Jun 14 01:14:22 devvm kernel: [<ffffffff81091d66>] kthread+0x96/0xa0 Jun 14 01:14:22 devvm kernel: [<ffffffff8100c14a>] child_rip+0xa/0x20 Jun 14 01:14:22 devvm kernel: [<ffffffff81091cd0>] ? kthread+0x0/0xa0 Jun 14 01:14:22 devvm kernel: [<ffffffff8100c140>] ? child_rip+0x0/0x20 Jun 14 01:14:22 devvm kernel: INFO: task parted:8069 blocked for more than 120 seconds. Jun 14 01:14:22 devvm kernel: "echo 0 > /proc/sys/kernel/hung_task_timeout_secs" disables this message. Jun 14 01:14:22 devvm kernel: parted D 0000000000000003 0 8069 7994 0x00000080 Jun 14 01:14:22 devvm kernel: ffff8800908b3bb8 0000000000000082 0000000000000000 ffff88010ab50080 Jun 14 01:14:22 devvm kernel: ffff880116c7d500 0000000000000001 0000000000000000 0000000000000000 Jun 14 01:14:22 devvm kernel: ffff88010ab50638 ffff8800908b3fd8 000000000000fb88 ffff88010ab50638 Jun 14 01:14:22 devvm kernel: Call Trace: Jun 14 01:14:22 devvm kernel: [<ffffffff814fe6a5>] schedule_timeout+0x215/0x2e0 Jun 14 01:14:22 devvm kernel: [<ffffffff814fe323>] wait_for_common+0x123/0x180 Jun 14 01:14:22 devvm kernel: [<ffffffff81060250>] ? default_wake_function+0x0/0x20 Jun 14 01:14:22 devvm kernel: [<ffffffff8112b6d0>] ? lru_add_drain_per_cpu+0x0/0x10 Jun 14 01:14:22 devvm kernel: [<ffffffff814fe43d>] wait_for_completion+0x1d/0x20 Jun 14 01:14:22 devvm kernel: [<ffffffff8108d177>] flush_work+0x77/0xc0 Jun 14 01:14:22 devvm kernel: [<ffffffff8108cbe0>] ? wq_barrier_func+0x0/0x20 Jun 14 01:14:22 devvm kernel: [<ffffffff8108d2f3>] schedule_on_each_cpu+0x133/0x180 Jun 14 01:14:22 devvm kernel: [<ffffffff811ad440>] ? invalidate_bh_lru+0x0/0x50 Jun 14 01:14:22 devvm kernel: [<ffffffff8112ae35>] lru_add_drain_all+0x15/0x20 Jun 14 01:14:22 devvm kernel: [<ffffffff811adf6a>] invalidate_bdev+0x2a/0x50 Jun 14 01:14:22 devvm kernel: [<ffffffff8125e9a4>] blkdev_ioctl+0x3b4/0x6e0 Jun 14 01:14:22 devvm kernel: [<ffffffff811b381c>] block_ioctl+0x3c/0x40 Jun 14 01:14:22 devvm kernel: [<ffffffff8118dec2>] vfs_ioctl+0x22/0xa0 Jun 14 01:14:22 devvm kernel: [<ffffffff8118e064>] do_vfs_ioctl+0x84/0x580 Jun 14 01:14:22 devvm kernel: [<ffffffff8118e5e1>] sys_ioctl+0x81/0xa0 Jun 14 01:14:22 devvm kernel: [<ffffffff8100b0f2>] system_call_fastpath+0x16/0x1b In /var/spool/abrt/oops-2013-06-14-01:10:53-1537-0 we can see the following information: In backtrace: WARNING: at net/sched/sch_generic.c:261 dev_watchdog+0x26d/0x280() (Not tainted) Hardware name: VirtualBox NETDEV WATCHDOG: eth0 (e1000): transmit queue 0 timed out Modules linked in: vboxsf(U) ipv6 ppdev parport_pc parport microcode sg vboxguest(U) i2c_piix4 i2c_core e1000 snd_intel8x0 snd_ac97_codec ac97_bus snd_seq snd_seq_device snd_pcm snd_timer snd soundcore snd_page_alloc pcnet32 mii ext4 mbcache jbd2 sd_mod crc_t10dif ahci dm_mirror dm_region_hash dm_log dm_mod [last unloaded: scsi_wait_scan] Pid: 0, comm: swapper Not tainted 2.6.32-279.el6.x86_64 #1 Call Trace: <IRQ> [<ffffffff8106b747>] ? warn_slowpath_common+0x87/0xc0 [<ffffffff8106b836>] ? warn_slowpath_fmt+0x46/0x50 [<ffffffff814595fd>] ? dev_watchdog+0x26d/0x280 [<ffffffff81099138>] ? sched_clock_cpu+0xb8/0x110 [<ffffffff81459390>] ? dev_watchdog+0x0/0x280 [<ffffffff8107e897>] ? run_timer_softirq+0x197/0x340 [<ffffffff810a21c0>] ? tick_sched_timer+0x0/0xc0 [<ffffffff8102b40d>] ? lapic_next_event+0x1d/0x30 [<ffffffff81073ec1>] ? __do_softirq+0xc1/0x1e0 [<ffffffff81096c50>] ? hrtimer_interrupt+0x140/0x250 [<ffffffff8100c24c>] ? call_softirq+0x1c/0x30 [<ffffffff8100de85>] ? do_softirq+0x65/0xa0 [<ffffffff81073ca5>] ? irq_exit+0x85/0x90 [<ffffffff81505be0>] ? smp_apic_timer_interrupt+0x70/0x9b [<ffffffff8100bc13>] ? apic_timer_interrupt+0x13/0x20 <EOI> [<ffffffff810387cb>] ? native_safe_halt+0xb/0x10 [<ffffffff810149cd>] ? default_idle+0x4d/0xb0 [<ffffffff81009e06>] ? cpu_idle+0xb6/0x110 [<ffffffff814e433a>] ? rest_init+0x7a/0x80 [<ffffffff81c21f7b>] ? start_kernel+0x424/0x430 [<ffffffff81c2133a>] ? x86_64_start_reservations+0x125/0x129 [<ffffffff81c21438>] ? x86_64_start_kernel+0xfa/0x109 In cmdline: ro root=/dev/mapper/vg_01-lv_root rd_NO_LUKS LANG=en_US.UTF-8 KEYBOARDTYPE=pc KEYTABLE=sv-latin1 rd_NO_MD SYSFONT=latarcyrheb-sun16 rd_LVM_LV=vg_01/lv_root crashkernel=129M@0M rhgb quiet rd_LVM_LV=vg_01/lv_swap rd_NO_DM rhgb quie Additional information: # uname -a Linux devvm 2.6.32-279.el6.x86_64 #1 SMP Fri Jun 22 12:19:21 UTC 2012 x86_64 x86_64 x86_64 GNU/Linux # cat /etc/redhat-release CentOS release 6.3 (Final) VirtualBox version 4.2.6. Any insight in how we can proceed with troubleshooting this is appreciated. If you need more information, just let me know.

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  • When is assembler faster than C?

    - by Adam Bellaire
    One of the stated reasons for knowing assembler is that, on occasion, it can be employed to write code that will be more performant than writing that code in a higher-level language, C in particular. However, I've also heard it stated many times that although that's not entirely false, the cases where assembler can actually be used to generate more performant code are both extremely rare and require expert knowledge of and experience with assembler. This question doesn't even get into the fact that assembler instructions will be machine-specific and non-portable, or any of the other aspects of assembler. There are plenty of good reasons for knowing assembler besides this one, of course, but this is meant to be a specific question soliciting examples and data, not an extended discourse on assembler versus higher-level languages. Can anyone provide some specific examples of cases where assembler will be faster than well-written C code using a modern compiler, and can you support that claim with profiling evidence? I am pretty confident these cases exist, but I really want to know exactly how esoteric these cases are, since it seems to be a point of some contention.

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  • RSA encryption results in server execution timeout

    - by Nilambari
    Hi, I am using PHP Crypt_RSA (http://pear.php.net/package/Crypt_RSA) for encrypting and decrypting the contents. Contents are of 1kb size. Following are the results: keylength = 1024 Encryption function takes time: 225 secs keylength = 2048 Encryption function takes time: 115 secs I need to reduce this execution time as most of the live apache servers have 120 sec limit for execution time. How to reduce this execution time? RSA alorithm docs says the only 1024 - 2048 keys are generated. I ACTUALLY tried to generate larger key, but it always results in execution timeout. How do i work on reducing encryption - decryption execution time? Thanks, Nila

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  • Using WCF to expose underlying process

    - by Steven
    I think I must be a little dull because I'm having so much difficulty with this. I use WCF for pretty much everything in-house, it's the most appropriate technology. I have a new Silverlight 3 app that is connecting to the WCF service and that's working fine. Where the problem begins is: Because of the expense in creating the objects within this service and the high correlation of individual objects being shared between clients I want to have a console application that basically gathers/calculates/caches all the data for the service 24/7 and the service basically connects to the console app (or whatever it is) and gets the pre-processed data. eg, think of it in terms of a stock reporting app (which it is). Person A has a portfolio of x, y z Person B has a portfolio of x, q, z, r The service needs to provide updated metrics on how their portfolio is performing. So instead of every 1 second processing person A, then person B, the app independently gathers the stock price and persons position information into memory and the service just queries the in memory result. Thanks for your help, I really am feeling dumb right now.

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  • Big O, how do you calculate/approximate it?

    - by Sven
    Most people with a degree in CS will certainly know what Big O stands for. It helps us to measure how (in)efficient an algorithm really is and if you know in what category the problem you are trying to solve lays in you can figure out if it is still possible to squeeze out that little extra performance.* But I'm curious, how do you calculate or approximate the complexity of your algorithms? *: but as they say, don't overdo it, premature optimization is the root of all evil, and optimization without a justified cause should deserve that name as well.

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  • Performing your own runtime analysis of your code in C#

    - by Matt
    I have written a large C# app with many methods in many classes. I'm trying to keep a log of what gets called and how often during my development. (I keep a record in a DB) Every method is padded with the following calls: void myMethod() { log(entering,args[]); log(exiting,args[]); } Since I want to do this for all my methods, is there a better way to do this then having to replicate those lines of code in every method?

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  • A[i] * A[j] = k in O(nlog(n))

    - by gleb-pendler
    A is an Array of n positive int numbers k given int Algorithm should find if there is a pair of numbers which product gives the result a. A[i] * A[j] = k b. A[i] = A[j] + k if there is such a couple the algorithm should return thier index. thanks in advance.

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  • Performance optimization strategies of last resort?

    - by jerryjvl
    There are plenty of performance questions on this site already, but it occurs to me that almost all are very problem-specific and fairly narrow. And almost all repeat the advice to avoid premature optimization. Let's assume: the code already is working correctly the algorithms chosen are already optimal for the circumstances of the problem the code has been measured, and the offending routines have been isolated all attempts to optimize will also be measured to ensure they do not make matters worse What I am looking for here is strategies and tricks to squeeze out up to the last few percent in a critical algorithm when there is nothing else left to do but whatever it takes. Ideally, try to make answers language agnostic, and indicate any down-sides to the suggested strategies where applicable. I'll add a reply with my own initial suggestions, and look forward to whatever else the SO community can think of.

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  • long processes php

    - by significance
    hi, i need to run a really long php script (four and half, five hours). the script sometimes runs successfully, but sometimes gets killed inexplicably (poss something to do with the shared hosting??). i think that the solution maybe to run the script is smaller chunks. in order to do this i have written a script that stores it's status & position in an xml file, and executes one chunk of the script, before moving the position on. i am having problems hooking up the last bit of the script, which should end the current process & re-execute the script. or maybe i am barking up the wrong tree completely! i have read through what i can find on SO and elsewhere but i'm still none the wiser :( please help!!! dan

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  • Too slow gwt develpment mode !

    - by Ehsan Khodarahmi
    I'm using eclipse galileo with latest GWT 2.0 version in development mode, but it runs really slow (i should wait about 1 minute to open one page, but after compilation, my application works very well when I run it using tomcat 5.5). My code is not too heavy & i guess there is an os-related or software inconsistency problem, because I'd this problem before, but when i reinstalled my windows vista sp2 (I formatted my windows drive & reinstalled it), my problem solved for just some days & then again it became to slow ! I didn't install any special software on my windows, so i really dont know why this problem occures ??? any suggestion ?

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  • Biggest performance improvement you've had with the smallest change?

    - by JoelFan
    What's the biggest performance improvement you've had with the smallest change? For example, I once improved the performance of a certain page on a high-profile web app by a factor of 10, just by moving "where customerID = ?" to a different place inside a complicated SQL statement (before my change it had been selecting all customers in a join, then later selecting out the desired customer).

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  • How to run 64 bit apps on 32 bit os

    - by Sirish Kumar
    Hi, I am using 32 bit openSUSE OS, and I am using a cross compiler to build 64 bit application( it does not support building 32 apps) as our software will be deployed on a machine which is 64 bit OS. As testing on target is not always possible, is there anyway to run this applications on my 32 bit OS.

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  • How to execute ant using java and captured the output?

    - by Iso
    Hi, I have an ant build file that contains JUnit test suite that I would like to execute. Currently I just right click and run the build file from Eclipse. I want to write a java code that can execute the ant build file automatically. So I just run the code and ant will be executed. Second is I want to capture the test result. Currently the result is based on JUnit HTML report. I want to make my own simple test report. I read there is JUnitResultFormatter but I can't find the instructional step by step how to use it. Can anyone point me the reference? Thanks in advance.

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  • Are doubles faster than floats in c#?

    - by Trap
    I'm writing an application which reads large arrays of floats and performs some simple operations with them. I'm using floats because I thought it'd be faster than doubles, but after doing some research I've found that there's some confusion about this topic. Can anyone elaborate on this? Thanks.

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  • How to prove worst-case number of inversions in a heap is O(nlogn)?

    - by Jacques
    I am busy preparing for exams, just doing some old exam papers. The question below is the only one I can't seem to do (I don't really know where to start). Any help would be appreciated greatly. Use the O(nlogn) comparison sort bound, the theta(n) bound for bottom-up heap construction, and the order complexity if insertion sort to show that the worst-case number of inversions in a heap is O(nlogn).

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  • Best way to reverse a string in C# 2.0

    - by Guy
    I've just had to write a string reverse function in C# 2.0 (i.e. LINQ not available) and came up with this: public string Reverse(string text) { char[] cArray = text.ToCharArray(); string reverse = String.Empty; for (int i = cArray.Length - 1; i > -1; i--) { reverse += cArray[i]; } return reverse; } Personally I'm not crazy about the function and am convinced that there's a better way to do it. Is there?

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  • WSRM error on Server running SQL databases

    - by Adam
    I have a Server Running Windows Server 2008 Enterprise Edition With SQL 2005. There is no problems with the server in its day to day functions but i am getting a Warning in the Event Log every 5 minutes with the following: Windows System Resource Manager encountered the following error 0x80010117. User Name will not be logged in the subsequent event logs. Error 0x80010117 User Action Address the error condition, and then try again. This has been happening for over 2 weeks now and i cannot find anything online to help! If i could have some help, then it would much appreciated. Thanks

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  • Time Service will not start on Windows Server - System error 1290

    - by paradroid
    I have been trying to sort out some time sync issues involving two domain controllers and seem to have ended up with a bigger problem. It's horrible. They are both virtual machines (one being on Amazon EC2), which I think may complicate things regarding time servers. The primary DC with all the FSMO roles is on the LAN. I reset its time server configuration like this (from memory): net stop w32time w23tm /unregister shutdown /r /t 0 w32tm /register w32tm /config /manualpeerlist:”0.uk.pool.ntp.org,1.uk.pool.ntp.org,2.uk.pool.ntp.org,3.uk.pool.ntp.org” /syncfromflags:manual /reliable:yes /update W32tm /config /update net start w32time reg QUERY HKEY_LOCAL_MACHINE\SYSTEM\CurrentControlSet\Services\W32Time\Config /v AnnounceFlags I checked to see if it was set to 0x05, which it was. The output for... w32tm /query /status Leap Indicator: 0(no warning) Stratum: 1 (primary reference - syncd by radio clock) Precision: -6 (15.625ms per tick) Root Delay: 0.0000000s Root Dispersion: 10.0000000s ReferenceId: 0x4C4F434C (source name: "LOCL") Last Successful Sync Time: 10/04/2012 15:03:27 Source: Local CMOS Clock Poll Interval: 6 (64s) While this was not what was intended, I thought I would sort it out after I made sure that the remote DC was syncing with it first. On the Amazon EC2 remote replica DC (Windows Server 2008 R2 Core)... net stop w32time w32tm /unregister shutdown /r /t 0 w32time /register net start w32time This is where it all goes wrong System error 1290 has occurred. The service start failed since one or more services in the same process have an incompatible service SID type setting. A service with restricted service SID type can only coexist in the same process with other services with a restricted SID type. If the service SID type for this service was just configured, the hosting process must be restarted in order to start this service. I cannot get the w32time service to start. I've tried resetting the time settings and tried to reverse what I have done. The Ec2Config service cannot start either, as it depends on the w32time service. All the solutions I have seen involve going into the telephony service registry settings, but as it is Server Core, it does not have that role, and I cannot see the relationship between that and the time service. w32time runs in the LocalService group and this telephony service which does not exist on Core runs in the NetworkService group. Could this have something to do with the process (svchost.exe) not being able to be run as a domain account, as it now a domain controller, but originally it ran as a local user group, or something like that? There seem to be a lot of cases of people having this problem, but the only solution has to do with the (non-existant on Core) telephony service. Who even uses that?

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