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  • Enable Soap for PHP 5.5.x on CentOS 6.5

    - by Chris Mancini
    Unfortunately I have to support soap on my server for the Fedex webservice. I recompiled PHP enabling support and it works via CLI but not PHP-fpm. They both point to the same ini file and both show the module loaded, but only CLI shows the configuration values. Output of php -i | grep -i soap Configuration File (php.ini) Path => /usr/local/etc Loaded Configuration File => /usr/local/etc/php.ini Configure Command => './configure' '--prefix=/usr/local' '--with-config-file-path=/usr/local/etc' '--with-config-file-scan-dir=/usr/local/etc/php_user/' '--enable-fpm' '--enable-ftp' '--enable-libxml' '--enable-mbstring' '--enable-pdo' '--enable-soap' '--enable-sockets=shared' '--enable-zip' '--with-curl' '--with-fpm-group=nginx' '--with-fpm-user=nginx' '--with-freetype-dir=/usr/lib64/' '--with-gd' '--with-jpeg-dir=/usr/lib64/' '--with-libdir=lib64' '--with-mcrypt' '--with-openssl' '--with-pdo-mysql' '--with-pear' '--with-readline' '--with-tidy' '--with-xsl' '--with-zlib' '--without-pdo-sqlite' '--without-sqlite3' soap Soap Client => enabled Soap Server => enabled soap.wsdl_cache => 1 => 1 soap.wsdl_cache_dir => /tmp => /tmp soap.wsdl_cache_enabled => 1 => 1 soap.wsdl_cache_limit => 5 => 5 soap.wsdl_cache_ttl => 86400 => 86400 Output from php-fpm phpinfo(): Configuration File (php.ini) Path /usr/local/etc Loaded Configuration File /usr/local/etc/php.ini SOAP Brad Lafountain, Shane Caraveo, Dmitry Stogov Please help, I have tried so many things...

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  • Have an unprivileged non-account user ssh into another box?

    - by Daniel Quinn
    I know how to get a user to ssh into another box with a key: ssh -l targetuser -i path/to/key targethost But what about non-account users like apache? As this user doesn't have a home directory to which it can write a .ssh directory, the whole thing keeps failing with: $ sudo -u apache ssh -o StrictHostKeyChecking=no -l targetuser -i path/to/key targethost Could not create directory '/var/www/.ssh'. Warning: Permanently added '<hostname>' (RSA) to the list of known hosts. Permission denied (publickey). I've tried variations using -o UserKnownHostsFile=/dev/null and setting $HOME to /dev/null and none of these have done the trick. I understand that sudo could probably fix this for me, but I'm trying to avoid having to require a manual server config since this code will be deployed on a number of different environments. Any ideas? Here's a few examples of what I've tried that don't work: $ sudo -u apache export HOME=path/to/apache/writable/dir/ ssh -o StrictHostKeyChecking=no -o UserKnownHostsFile=path/to/apache/writable/dir/.ssh/known_hosts -l deploy -i path/to/key targethost $ sudo -u apache ssh -o StrictHostKeyChecking=no -o UserKnownHostsFile=path/to/apache/writable/dir/.ssh/known_hosts -l deploy -i path/to/key targethost $ sudo -u apache ssh -o StrictHostKeyChecking=no -o UserKnownHostsFile=/dev/null -l deploy -i path/to/key targethost Eventually, I'll be using this solution to run rsync as the apache user.

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  • Are my Linux symbolic links acting correctly?

    - by Andy Castles
    Hi all I've been using Linux on and off for the last 15 years and today I came across something in bash that surprised me. Setup the following directory structure: $ cd /tmp $ mkdir /tmp/symlinktest $ mkdir /tmp/symlinktest/dir $ mkdir /tmp/symlinktarget Now create two sym links in symlinktest pointing to symlinktarget: $ cd /tmp/symlinktest $ ln -s ../symlinktarget Asym $ ln -s ../symlinktarget Bsym Now, in bash, the following tab completion does strange things. Type the following: $ cd dir $ cd ../A[TAB] Pressing the tab key above completes the line to: $ cd ../Asym/ as I expected. Now press enter to change into Asym and type: $ cd ../B[TAB] This time pressing the tab key completes the link to: $ cd ../Bsym[space] Note that there is now a space after the Bsym and there is no trailing slash. My question is, why when changing from the physical directory "dir" to Asym it recognises that Asym is a link to a directory, but when changing from one sym link to another, it doesn't recognise that it's a link to a directory? In addition, if I try to create a new file within Asym, I get an error message: $ cd /tmp/symlinktest/Asym $ cat hello > ../Bsym/file.txt -bash: ../Bsym/file.txt: No such file or directory I always thought that symlinks were mostly transparent except to programs that need to manipulate them. Is this normal behaviour? Many thanks, Andy

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  • PHP 5.4.9 Mysqli issue

    - by Vitaly
    On Ubuntu 12.04 server I had PHP 5.4.9 installed from the source: ./configure --prefix=/etc/php --with-apxs2=/etc/apache2/bin/apxs --with-config-file-path=/etc/php --with-config-file-scan-dir=/etc/php/conf.d --with-libxml-dir=/usr/local/libxml2 --with-xsl=/usr/local/libxslt --with-mysql --with-zlib --with-pdo-mysql --enable-calendar --with-gd --with-iconv-dir --enable-mbstring --enable-soap --enable-sockets --enable-zip --with-curl --with-openssl --with-kerberos --with-tidy' Then, using apt-get, I had mysql server and phpMyAdmin installed. Unfortunatelly phpMyAdmin keep saying that 'mysqli' and 'mcrypt' not installed. php -m | grep mysqli just confirms it. So I tried to install mysqli with "apt-get install php5-mysqli", but just got message to do it by means of "php5-mysqlnd" or "php5-mysql". Even though they are already installed (according to phpinfo()) I tried - doesn't work. However, in php.ini, there's mysqli staff like "extension=php_mysqli.dll", but no "extension=mysqli.so". And block [MySQLi] with some uncommented settings also present. Since this is my first attempt to build php from source I reckon I did some silly mistake. Any help is greatly appreciated.

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  • SFTP, ChrootDirectory and multiple users

    - by mdo
    I need a setup where I can put the contents of several user folders to a DMZ server from where external clients can download it, protocol SFTP, Linux, OpenSSH. To ease administration we want to use one single user for the upload. What does work is to define ChrootDirectory /home/sftp/ in sshd_config, set the according ownership and modes and define a home dir in passwd so that the working directory of the user fits. This is my structure: /home/sftp/uploader/user1/file1.txt /user2/file2.txt The uploader user can write file1.txt and file2.txt to the corresponding folders and by having the user folders (user1, user2) set to the users' primary group + setting SETGUID on the folders the users are able to even delete the files (which is necessary). Only problem: because /home/sftp/ is the chroot base dir the users can change updir and see other users' folders, though not being able to change into because of access rights. Requirement: We want to prevent users to change to /home/sftp/uploader/ and see other users' folders. My requirements are to use SFTP, have one upload user and every user must have write access to his home dir. Obviously it's not an option to use something like ChrootDirectory %h because every path component of the chroot path needs to have limited access rights, so as far as I understand this does not work.

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  • Apache directory access with virtual host

    - by alexeygaidamaka
    I have a virtual host with a configuration like that. When i'm trying to get into foobar.com/dir providing valid username/password pair i get 403 forbidden page instead of that directory contents. www.foobar.com/dir has 777 rights, .httpaswd is chmoded 644. But i can't figure out why i am still not seeing contents. Please, give me a hint. ServerAdmin webmaster@localhost ServerName www.foobar.com ServerAlias www.foobar.com DocumentRoot /var/www/foobar <Directory /> Options FollowSymLinks AllowOverride All </Directory> <Directory /var/www/foobar> Options -Indexes FollowSymLinks AllowOverride All Order allow,deny allow from all </Directory> ScriptAlias /cgi-bin/ /usr/lib/cgi-bin/ <Directory "/usr/lib/cgi-bin"> AllowOverride None Options +ExecCGI -MultiViews +SymLinksIfOwnerMatch Order allow,deny Allow from all </Directory> <Directory /var/www/foobar/dir> AllowOverride AuthConfig AuthName "Authorize yourself, please!" AuthType Basic AuthUserFile /etc/apache2/.htpasswd AuthGroupFile /dev/null Allow from All Order Allow,Deny Require valid-user

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  • How can I monitor network traffic?

    - by WIndy Weather
    I have a home network with about 10 devices including BluRay player [netflix] and both windows and linux machines. I need to collect network traffic statistics so that if questions come up about how much traffic I'm using I have the answer independent of my ISP. I've looked at DD-WRT, but I see that even buying a new router that will be supported is a problem since I might get the wrong version of the hardware. I have a DIR-655 and a DIR-501 - neither of which is supported. I don't mind buying new hardware, but it looks like a crap-shoot to get one that will work. DD-WRT looks like a bad solution unless someone knows of a place to get a router that is guaranteed to work. Does someone know of an arduino or other SBC solution? I have plenty of NAT routers already, so I just need traffic statistics for external traffic. The network is GBit Ethernet inside and Cable / soon to be DSL outside. The DIR-655 only gives me "packets", not bytes transferred oddly enough. Thanks, ww

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  • Virtual Host Configuration and mod_rewrite - Removing PHP Extension and Adding Forward Slash

    - by nicorellius
    On my production server, things are fine: PHP extension removal and trailing slash rules are in place in my .htaccess file. But locally, this isn't working (well, partially, anyway). I'm running Apache2 with a virtual host for the site in question. I decided to not use the .htaccess file in this case and just add the rules to the httpd-vhosts.conf file instead, which, I've heard, if possible on your server, is a better way to go. The virtual host is working and the URL I use for my site is like this: devserver:9090 Here is my httpd-vhosts.conf file: NameVirtualHost *:9090 # for stuff other than this site <VirtualHost *:9090> ServerAdmin admin@localhost DocumentRoot "/opt/lampstack/apache2/htdocs" ServerName localhost </VirtualHost> # for site in question <VirtualHost *:9090> ServerAdmin admin@localhost DocumentRoot "/opt/lampstack/apache2/htdocs/devserver" ServerName devserver <Directory "/opt/lampstack/apache2/htdocs/devserver"> Options Indexes FollowSymLinks Includes AllowOverride None Order allow,deny Allow from all </Directory> <IfModule rewrite_module> RewriteEngine ON # remove PHP extension and add trailing slash # note - this doesn't work for directories, and throws 404 # TODO - fix so directories use index.php RewriteCond %{REQUEST_FILENAME} !-d RewriteCond %{THE_REQUEST} ^GET\ /[^?\s]+\.php RewriteRule (.*)\.php$ /$1/ [R=302,L] RewriteCond %{REQUEST_FILENAME} !-d RewriteRule (.*)/$ /$1.php [L] RewriteCond %{REQUEST_FILENAME}.php -f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule .*[^/]$ /$0/ [R=302,L] </IfModule> # error docs ErrorDocument 404 /errors/404.php </VirtualHost> The problem I'm facing is that when I go to directories on the site, I get a 404 error. So for example, this: devserver:9090/page.php goes to devserver:9090/page/ but going to a directory (that has an index.php): devserver:9090/dir/ throws 404 error page. If I type in devserver:9090/dir/index.php I get devserver:9090/dir/index/ and the contents I want appear... Can anyone help me with my rewrite rules?

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  • Two folders with identical names causing many problems.

    - by R. A. Chaucer
    In my 'Documents' folder (Win7) I have two folders with names that appear in Explorer to be identical, though their contents are different. I can rename them both to something else (eg: 'Test') and Explorer doesn't complain. The dir listing that cmd.exe and powershell gives me only lists one of them, but also lists this suspicious entry: 20/04/2010 12:16 PM <DIR> ???? Even if I rename the folders to have unique names, one of them still shows up as ???? in cmd.exe. Desktop.ini in my Documents folder doesn't contain anything out of the ordinary. Both folders appear to be read-only in their properties panel, and if I untick the read-only box it will ask me if I want to apply the action recursively, but either way when I close the panel and open it again the folder is once again read-only. They are both set to not inherit permissions. The folder that shows up correctly in the cmd.exe dir listing is the "real" one, the other seems to be automatically created when a program tries to access it. How is this possible?This is driving me nuts!

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  • Apache directory access with virtual host [SOLVED]

    - by alexeygaidamaka
    I have a virtual host with a configuration like that. When i'm trying to get into foobar.com/dir providing valid username/password pair i get 403 forbidden page instead of that directory contents. www.foobar.com/dir has 777 rights, .httpaswd is chmoded 644. But i can't figure out why i am still not seeing contents. Please, give me a hint. ServerAdmin webmaster@localhost ServerName www.foobar.com ServerAlias www.foobar.com DocumentRoot /var/www/foobar <Directory /> Options FollowSymLinks AllowOverride All </Directory> <Directory /var/www/foobar> Options -Indexes FollowSymLinks AllowOverride All Order allow,deny allow from all </Directory> ScriptAlias /cgi-bin/ /usr/lib/cgi-bin/ <Directory "/usr/lib/cgi-bin"> AllowOverride None Options +ExecCGI -MultiViews +SymLinksIfOwnerMatch Order allow,deny Allow from all </Directory> <Directory /var/www/foobar/dir> AllowOverride AuthConfig AuthName "Authorize yourself, please!" AuthType Basic AuthUserFile /etc/apache2/.htpasswd AuthGroupFile /dev/null Allow from All Order Allow,Deny Options +Indexes<<- that one should be added Require valid-user you have to add the line Options +Indexes to see directory contents

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  • Directories Throwing 404 Errors - Virtual Host Configuration and mod_rewrite

    - by nicorellius
    On my production server, things are fine: PHP extension removal and trailing slash rules are in place in my .htaccess file. But locally, this isn't working (well, partially, anyway). I'm running Apache2 with a virtual host for the site in question. I decided to not use the .htaccess file in this case and just add the rules to the httpd-vhosts.conf file instead, which, I've heard, if possible on your server, is a better way to go. The virtual host is working and the URL I use for my site is like this: devserver:9090 Here is my httpd-vhosts.conf file: NameVirtualHost *:9090 # for stuff other than this site <VirtualHost *:9090> ServerAdmin admin@localhost DocumentRoot "/opt/lampstack/apache2/htdocs" ServerName localhost </VirtualHost> # for site in question <VirtualHost *:9090> ServerAdmin admin@localhost DocumentRoot "/opt/lampstack/apache2/htdocs/devserver" ServerName devserver <Directory "/opt/lampstack/apache2/htdocs/devserver"> Options Indexes FollowSymLinks Includes AllowOverride None Order allow,deny Allow from all </Directory> <IfModule rewrite_module> RewriteEngine ON # remove PHP extension and add trailing slash # note - this doesn't work for directories, and throws 404 # TODO - fix so directories use index.php RewriteCond %{REQUEST_FILENAME} !-d RewriteCond %{THE_REQUEST} ^GET\ /[^?\s]+\.php RewriteRule (.*)\.php$ /$1/ [R=302,L] RewriteCond %{REQUEST_FILENAME} !-d RewriteRule (.*)/$ /$1.php [L] RewriteCond %{REQUEST_FILENAME}.php -f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule .*[^/]$ /$0/ [R=302,L] </IfModule> # error docs ErrorDocument 404 /errors/404.php </VirtualHost> The problem I'm facing is that when I go to directories on the site, I get a 404 error. So for example, this: devserver:9090/page.php goes to devserver:9090/page/ but going to a directory (that has an index.php): devserver:9090/dir/ throws 404 error page. If I type in devserver:9090/dir/index.php I get devserver:9090/dir/index/ and the contents I want appear... Can anyone help me with my rewrite rules?

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  • How TiVo is messing up customer support.

    - by James Fleming
    Ok,  So I've gotten a TiVo and overall, I'm happy, but there have been issues and I suspect I've a defective unit. - Now the nice folks after many service calls were happy to swap it out, and to ensure continuity of service, they sent me a new unit (after a $109 deposit).  That was yesterday. Today, when we go to watch a little TV, and wait for our replacement unit to arrive we find our TiVo service has been suspended. WTF? They have an exchange program, but your unit your waiting to exchange is as dead as a doornail until the replacement arrives. How hard is it to keep the old unit active for an extra week? Here is the exchange w/Tivo below... You are currently number 1 in the queue. We apologize for the delay. We will assign you to an agent as soon as one is available.The average amount of time a customer has to wait is 00:13.  Kaylene (Listening)  Kaylene: Thank you for contacting TiVo! My name is Kaylene. So that I may better assist you, are you an existing customer?  james Fleming: yes I am, but I'm now having second thoughts about being one    Kaylene: Thank you for verifying your information. How may I assist you today James?  james Fleming: I've been having issues w/a tivo box & I'm getting a replacement sent out to me (after paying an additional deposit) and now my current unit is no longer activated  Kaylene: I can help you today!  Kaylene: When we process an exchange we do transfer over the service to the replacement box so it is active and ready to go when you receive it.  james Fleming: which is to say you also make my current box worthless until such time I receive a new box?!?!?  Kaylene: I apologize that your original box was deactivated so we could activate your replacement box.  james Fleming: Why on Earth would I bother to pay in advance for a new box if you were going to kill my existing box.  Kaylene: What features are you needing to use on your current box?  james Fleming: I need to be able to access my netflix subscription (if I'm lucky enough to have it work without rebooting)  Kaylene: Can I have you verify the TiVo Service Number of your TiVo box please?  james Fleming: 7460011906979b4  Kaylene: We have your current box temporary service but not all features are available with temporary service as it is not paid for service.  Kaylene: If you like I can transfer your service back to your current box for now. Then once you receive the new box you will have to call in and have the service transferred back to the new box.  james Fleming: Not paid for? Let's see> one tivo box + 3 year service plan + monthly service + $109 deposit on a second box = what?  Kaylene: Would you like me to transfer your service back to your current box?  james Fleming: Yes - that would be helpful  Kaylene: All you will need to do is contact us again once you receive the new box so we can transfer it back.  Kaylene: I have put your service back on TiVo box 7460011906979b4.  james Fleming: What would also be helpful is your firm informing me to how you'd be cutting service in the interim.  james Fleming: Again - I opted to pay to have a second box delivered BEFORE returning the box I have - thus trying to have a continuity of service..  Kaylene: This is not something we normally do so it is important when you contact us to transfer the service back to the new box when you receive it that you reference this case number: 110622-006089.  Kaylene: I apologize about the inconvenience. You may need  force a few connections for the box to recognize the service again.  james Fleming: If it's not something you normally do than WHY would you have a $109 fee and a term for the service.  james Fleming: I am not mad at you, but your company is not impressing me and I'm blogging about this experience  Kaylene: Again I apologize about the inconvenience but you should be good to go now. Is there anything else I can help you with today?  james Fleming: so I need to go through the re-actviate process or is that somethign you do  Kaylene: When you receive the new TiVo box you need to contact us so we can transfer the service to the new box for you.  james Fleming: sure  Kaylene: Is there anything else I can help you with today James?  james Fleming: Nope - please email this transcript to me  Kaylene: I apologize but we do not have the ability to e-mail you a copy of this transcript. You can view it online at  http://www.tivo.com when you sign into your account or you can copy and paste it now to save it.  Kaylene: Thank you for contacting TiVo today. Your reference number for our conversation is 110622-006089. You can save this for your records, and if necessary, provide this to a later agent to pull up what we discussed. There will be a brief satisfaction survey emailed to you. We would appreciate any feedback on your TiVo Chat Support experience today.  Kaylene: Thank you for using TiVo Chat and have a great day James! Good-bye.  Kaylene has disconnected.

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  • Lubuntu 13.10 unable to connect to cups localhost:631

    - by user142139
    I am using Lubuntu 13.10 (recently upgraded) and am trying to print to a network printer (HP photosmart 7960) through my router (US Robotics 5461). My printer is connected to the router via USB cable. Normally, I would use the cups configuration interface to set up the wireless connection to the printer. I was able to use the printer through the router wirelessly, using Ubuntu 12.04. Now, with my recently upgraded Lubuntu 13.10, I am unable to get the Cups config webpage (http://localhost:631) to come up. In Chromium, I get: This web page is not available. In Firefox, I get: Unable to connect. Firefox can't establish a connection to the server at localhost:631. The CUPS config file details are below. I have this website to help with the router connections for Linux: http://www.usr.com/support/5461/5461-files/printer_installation_linux/index.html My printer's address through the router is: http://192.168.2.1:1631/printers/My_Printer Can you tell me how to fix this? Or, what to add to the cups configuration file to make this work? Please help. Thanks psychicnut CUPS CONFIG FILE DETAILS: # Show general information in error_log. LogLevel warn MaxLogSize 0 SystemGroup lpadmin Listen /var/run/cups/cups.sock Listen /var/run/cups/cups.sock Listen 192.168.2.1:1631 Browsing Off BrowseLocalProtocols dnssd DefaultAuthType Basic WebInterface Yes <Location /> Order allow,deny </Location> <Location /admin> Order allow,deny </Location> <Location /admin/conf> AuthType Default Require user @SYSTEM Order allow,deny </Location> <Policy default> JobPrivateAccess default JobPrivateValues default SubscriptionPrivateAccess default SubscriptionPrivateValues default <Limit Create-Job Print-Job Print-URI Validate-Job> Order deny,allow </Limit> <Limit Send-Document Send-URI Hold-Job Release-Job Restart-Job Purge-Jobs Set-Job-Attributes Create-Job-Subscription Renew-Subscription Cancel-Subscription Get-Notifications Reprocess-Job Cancel-Current-Job Suspend-Current-Job Resume-Job Cancel-My-Jobs Close-Job CUPS-Move-Job CUPS-Get-Document> Require user @OWNER @SYSTEM Order deny,allow </Limit> <Limit CUPS-Add-Modify-Printer CUPS-Delete-Printer CUPS-Add-Modify-Class CUPS-Delete-Class CUPS-Set-Default CUPS-Get-Devices> AuthType Default Require user @SYSTEM Order deny,allow </Limit> <Limit Pause-Printer Resume-Printer Enable-Printer Disable-Printer Pause-Printer-After-Current-Job Hold-New-Jobs Release-Held-New-Jobs Deactivate-Printer Activate-Printer Restart-Printer Shutdown-Printer Startup-Printer Promote-Job Schedule-Job-After Cancel-Jobs CUPS-Accept-Jobs CUPS-Reject-Jobs> AuthType Default Require user @SYSTEM Order deny,allow </Limit> <Limit Cancel-Job CUPS-Authenticate-Job> Require user @OWNER @SYSTEM Order deny,allow </Limit> <Limit All> Order deny,allow </Limit> </Policy> <Policy authenticated> JobPrivateAccess default JobPrivateValues default SubscriptionPrivateAccess default SubscriptionPrivateValues default <Limit Create-Job Print-Job Print-URI Validate-Job> AuthType Default Order deny,allow </Limit> <Limit Send-Document Send-URI Hold-Job Release-Job Restart-Job Purge-Jobs Set-Job-Attributes Create-Job-Subscription Renew-Subscription Cancel-Subscription Get-Notifications Reprocess-Job Cancel-Current-Job Suspend-Current-Job Resume-Job Cancel-My-Jobs Close-Job CUPS-Move-Job CUPS-Get-Document> AuthType Default Require user @OWNER @SYSTEM Order deny,allow </Limit> <Limit CUPS-Add-Modify-Printer CUPS-Delete-Printer CUPS-Add-Modify-Class CUPS-Delete-Class CUPS-Set-Default> AuthType Default Require user @SYSTEM Order deny,allow </Limit> <Limit Pause-Printer Resume-Printer Enable-Printer Disable-Printer Pause-Printer-After-Current-Job Hold-New-Jobs Release-Held-New-Jobs Deactivate-Printer Activate-Printer Restart-Printer Shutdown-Printer Startup-Printer Promote-Job Schedule-Job-After Cancel-Jobs CUPS-Accept-Jobs CUPS-Reject-Jobs> AuthType Default Require user @SYSTEM Order deny,allow </Limit> <Limit Cancel-Job CUPS-Authenticate-Job> AuthType Default Require user @OWNER @SYSTEM Order deny,allow </Limit> <Limit All> Order deny,allow </Limit> </Policy> JobPrivateAccess default JobPrivateValues default SubscriptionPrivateAccess default SubscriptionPrivateValues default

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  • Rendering ASP.NET MVC Razor Views outside of MVC revisited

    - by Rick Strahl
    Last year I posted a detailed article on how to render Razor Views to string both inside of ASP.NET MVC and outside of it. In that article I showed several different approaches to capture the rendering output. The first and easiest is to use an existing MVC Controller Context to render a view by simply passing the controller context which is fairly trivial and I demonstrated a simple ViewRenderer class that simplified the process down to a couple lines of code. However, if no Controller Context is available the process is not quite as straight forward and I referenced an old, much more complex example that uses my RazorHosting library, which is a custom self-contained implementation of the Razor templating engine that can be hosted completely outside of ASP.NET. While it works inside of ASP.NET, it’s an awkward solution when running inside of ASP.NET, because it requires a bit of setup to run efficiently.Well, it turns out that I missed something in the original article, namely that it is possible to create a ControllerContext, if you have a controller instance, even if MVC didn’t create that instance. Creating a Controller Instance outside of MVCThe trick to make this work is to create an MVC Controller instance – any Controller instance – and then configure a ControllerContext through that instance. As long as an HttpContext.Current is available it’s possible to create a fully functional controller context as Razor can get all the necessary context information from the HttpContextWrapper().The key to make this work is the following method:/// <summary> /// Creates an instance of an MVC controller from scratch /// when no existing ControllerContext is present /// </summary> /// <typeparam name="T">Type of the controller to create</typeparam> /// <returns>Controller Context for T</returns> /// <exception cref="InvalidOperationException">thrown if HttpContext not available</exception> public static T CreateController<T>(RouteData routeData = null) where T : Controller, new() { // create a disconnected controller instance T controller = new T(); // get context wrapper from HttpContext if available HttpContextBase wrapper = null; if (HttpContext.Current != null) wrapper = new HttpContextWrapper(System.Web.HttpContext.Current); else throw new InvalidOperationException( "Can't create Controller Context if no active HttpContext instance is available."); if (routeData == null) routeData = new RouteData(); // add the controller routing if not existing if (!routeData.Values.ContainsKey("controller") && !routeData.Values.ContainsKey("Controller")) routeData.Values.Add("controller", controller.GetType().Name .ToLower() .Replace("controller", "")); controller.ControllerContext = new ControllerContext(wrapper, routeData, controller); return controller; }This method creates an instance of a Controller class from an existing HttpContext which means this code should work from anywhere within ASP.NET to create a controller instance that’s ready to be rendered. This means you can use this from within an Application_Error handler as I needed to or even from within a WebAPI controller as long as it’s running inside of ASP.NET (ie. not self-hosted). Nice.So using the ViewRenderer class from the previous article I can now very easily render an MVC view outside of the context of MVC. Here’s what I ended up in my Application’s custom error HttpModule: protected override void OnDisplayError(WebErrorHandler errorHandler, ErrorViewModel model) { var Response = HttpContext.Current.Response; Response.ContentType = "text/html"; Response.StatusCode = errorHandler.OriginalHttpStatusCode; var context = ViewRenderer.CreateController<ErrorController>().ControllerContext; var renderer = new ViewRenderer(context); string html = renderer.RenderView("~/Views/Shared/GenericError.cshtml", model); Response.Write(html); }That’s pretty sweet, because it’s now possible to use ViewRenderer just about anywhere in any ASP.NET application, not only inside of controller code. This also allows the constructor for the ViewRenderer from the last article to work without a controller context parameter, using a generic view as a base for the controller context when not passed:public ViewRenderer(ControllerContext controllerContext = null) { // Create a known controller from HttpContext if no context is passed if (controllerContext == null) { if (HttpContext.Current != null) controllerContext = CreateController<ErrorController>().ControllerContext; else throw new InvalidOperationException( "ViewRenderer must run in the context of an ASP.NET " + "Application and requires HttpContext.Current to be present."); } Context = controllerContext; }In this case I use the ErrorController class which is a generic controller instance that exists in the same assembly as my ViewRenderer class and that works just fine since ‘generically’ rendered views tend to not rely on anything from the controller other than the model which is explicitly passed.While these days most of my apps use MVC I do still have a number of generic pieces in most of these applications where Razor comes in handy. This includes modules like the above, which when they error often need to display error output. In other cases I need to generate string template output for emailing or logging data to disk. Being able to render simply render an arbitrary View to and pass in a model makes this super nice and easy at least within the context of an ASP.NET application!You can check out the updated ViewRenderer class below to render your ‘generic views’ from anywhere within your ASP.NET applications. Hope some of you find this useful.ResourcesViewRenderer Class in Westwind.Web.Mvc Library (Github)Original ViewRenderer ArticleRazor Hosting Library (GitHub)Original Razor Hosting Article© Rick Strahl, West Wind Technologies, 2005-2013Posted in ASP.NET  MVC   Tweet !function(d,s,id){var js,fjs=d.getElementsByTagName(s)[0];if(!d.getElementById(id)){js=d.createElement(s);js.id=id;js.src="//platform.twitter.com/widgets.js";fjs.parentNode.insertBefore(js,fjs);}}(document,"script","twitter-wjs"); (function() { var po = document.createElement('script'); po.type = 'text/javascript'; po.async = true; po.src = 'https://apis.google.com/js/plusone.js'; var s = document.getElementsByTagName('script')[0]; s.parentNode.insertBefore(po, s); })();

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  • Posting from ASP.NET WebForms page to another URL

    - by hajan
    Few days ago I had a case when I needed to make FORM POST from my ASP.NET WebForms page to an external site URL. More specifically, I was working on implementing Simple Payment System (like Amazon, PayPal, MoneyBookers). The operator asks to make FORM POST request to a given URL in their website, sending parameters together with the post which are computed on my application level (access keys, secret keys, signature, return-URL… etc). So, since we are not allowed nesting another form inside the <form runat=”server”> … </form>, which is required because other controls in my ASPX code work on server-side, I thought to inject the HTML and create FORM with method=”POST”. After making some proof of concept and testing some scenarios, I’ve concluded that I can do this very fast in two ways: Using jQuery to create form on fly with the needed parameters and make submit() Using HttpContext.Current.Response.Write to write the form on server-side (code-behind) and embed JavaScript code that will do the post Both ways seemed fine. 1. Using jQuery to create FORM html code and Submit it. Let’s say we have ‘PAY NOW’ button in our ASPX code: <asp:Button ID="btnPayNow" runat="server" Text="Pay Now" /> Now, if we want to make this button submit a FORM using POST method to another website, the jQuery way should be as follows: <script src="http://ajax.aspnetcdn.com/ajax/jquery/jquery-1.5.1.js" type="text/javascript"></script> <script type="text/javascript">     $(function () {         $("#btnPayNow").click(function (event) {             event.preventDefault();             //construct htmlForm string             var htmlForm = "<form id='myform' method='POST' action='http://www.microsoft.com'>" +                 "<input type='hidden' id='name' value='hajan' />" +             "</form>";             //Submit the form             $(htmlForm).appendTo("body").submit();         });     }); </script> Yes, as you see, the code fires on btnPayNow click. It removes the default button behavior, then creates htmlForm string. After that using jQuery we append the form to the body and submit it. Inside the form, you can see I have set the htttp://www.microsoft.com URL, so after clicking the button you should be automatically redirected to the Microsoft website (just for test, of course for Payment I’m using Operator's URL). 2. Using HttpContext.Current.Response.Write to write the form on server-side (code-behind) and embed JavaScript code that will do the post The C# code behind should be something like this: public void btnPayNow_Click(object sender, EventArgs e) {     string Url = "http://www.microsoft.com";     string formId = "myForm1";     StringBuilder htmlForm = new StringBuilder();     htmlForm.AppendLine("<html>");     htmlForm.AppendLine(String.Format("<body onload='document.forms[\"{0}\"].submit()'>",formId));     htmlForm.AppendLine(String.Format("<form id='{0}' method='POST' action='{1}'>", formId, Url));     htmlForm.AppendLine("<input type='hidden' id='name' value='hajan' />");     htmlForm.AppendLine("</form>");     htmlForm.AppendLine("</body>");     htmlForm.AppendLine("</html>");     HttpContext.Current.Response.Clear();     HttpContext.Current.Response.Write(htmlForm.ToString());     HttpContext.Current.Response.End();             } So, with this code we create htmlForm string using StringBuilder class and then just write the html to the page using HttpContext.Current.Response.Write. The interesting part here is that we submit the form using JavaScript code: document.forms["myForm1"].submit() This code runs on body load event, which means once the body is loaded the form is automatically submitted. Note: In order to test both solutions, create two applications on your web server and post the form from first to the second website, then get the values in the second website using Request.Form[“input-field-id”] I hope this was useful post for you. Regards, Hajan

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  • Html.RenderAction Failed when Validation Failed

    - by Shaun
    RenderAction method had been introduced when ASP.NET MVC 1.0 released in its MvcFuture assembly and then final announced along with the ASP.NET MVC 2.0. Similar as RenderPartial, the RenderAction can display some HTML markups which defined in a partial view in any parent views. But the RenderAction gives us the ability to populate the data from an action which may different from the action which populating the main view. For example, in Home/Index.aspx we can invoke the Html.RenderPartial(“MyPartialView”) but the data of MyPartialView must be populated by the Index action of the Home controller. If we need the MyPartialView to be shown in Product/Create.aspx we have to copy (or invoke) the relevant code from the Index action in Home controller to the Create action in the Product controller which is painful. But if we are using Html.RenderAction we can tell the ASP.NET MVC from which action/controller the data should be populated. in that way in the Home/Index.aspx and Product/Create.aspx views we just need to call Html.RenderAction(“CreateMyPartialView”, “MyPartialView”) so it will invoke the CreateMyPartialView action in MyPartialView controller regardless from which main view. But in my current project we found a bug when I implement a RenderAction method in the master page to show something that need to connect to the backend data center when the validation logic was failed on some pages. I created a sample application below.   Demo application I created an ASP.NET MVC 2 application and here I need to display the current date and time on the master page. I created an action in the Home controller named TimeSlot and stored the current date into ViewDate. This method was marked as HttpGet as it just retrieves some data instead of changing anything. 1: [HttpGet] 2: public ActionResult TimeSlot() 3: { 4: ViewData["timeslot"] = DateTime.Now; 5: return View("TimeSlot"); 6: } Next, I created a partial view under the Shared folder to display the date and time string. 1: <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<dynamic>" %> 2:  3: <span>Now: <% 1: : ViewData["timeslot"].ToString() %></span> Then at the master page I used Html.RenderAction to display it in front of the logon link. 1: <div id="logindisplay"> 2: <% 1: Html.RenderAction("TimeSlot", "Home"); %> 3:  4: <% 1: Html.RenderPartial("LogOnUserControl"); %> 5: </div> It’s fairly simple and works well when I navigated to any pages. But when I moved to the logon page and click the LogOn button without input anything in username and password the validation failed and my website crashed with the beautiful yellow page. (I really like its color style and fonts…)   How ASP.NET MVC executes Html.RenderAction In this example all other pages were rendered successful which means the ASP.NET MVC found the TimeSolt action under the Home controller except this situation. The only different is that when I clicked the LogOn button the browser send an HttpPost request to the server. Is that the reason of this bug? I created another action in Home controller with the same action name but for HttpPost. 1: [HttpPost] 2: [ActionName("TimeSlot")] 3: public ActionResult TimeSlot(object dummy) 4: { 5: return TimeSlot(); 6: } Or, I can use the AcceptVerbsAttribute on the TimeSlot action to let it allow both HttpGet and HttpPost. 1: [AcceptVerbs("GET", "POST")] 2: public ActionResult TimeSlot() 3: { 4: ViewData["timeslot"] = DateTime.Now; 5: return View("TimeSlot"); 6: } And then repeat what I did before and this time it worked well. Why we need the action for HttpPost here as it’s just data retrieving? That is because of how ASP.NET MVC executes the RenderAction method. In the source code of ASP.NET MVC we can see when proforming the RenderAction ASP.NET MVC creates a RequestContext instance from the current RequestContext and created a ChildActionMvcHandler instance which inherits from MvcHandler class. Then the ASP.NET MVC processes the handler through the HttpContext.Server.Execute method. That means it performs the action as a stand-alone request asynchronously and flush the result into the  TextWriter which is being used to render the current page. Since when I clicked the LogOn the request was in HttpPost so when ASP.NET MVC processed the ChildActionMvcHandler it would find the action which allow the current request method, which is HttpPost. Then our TimeSlot method in HttpGet would not be matched.   Summary In this post I introduced a bug in my currently developing project regards the new Html.RenderAction method provided within ASP.NET MVC 2 when processing a HttpPost request. In ASP.NET MVC world the underlying Http information became more important than in ASP.NET WebForm world. We need to pay more attention on which kind of request it currently created and how ASP.NET MVC processes.   Hope this helps, Shaun   All documents and related graphics, codes are provided "AS IS" without warranty of any kind. Copyright © Shaun Ziyan Xu. This work is licensed under the Creative Commons License.

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  • Font gets enlarged when rotating screen

    - by queueoverflow
    I have a new ThinkPad X220 Tablet with Kubuntu 12.04. When I rotate the screen 90° with a script, the fonts of all programs that I open after the rotation have ugly huge fonts. #!/bin/sh # Find the line in "xrandr -q --verbose" output that contains current screen orientation and "strip" out current orientation. rotation="$(xrandr -q --verbose | grep 'connected' | egrep -o '\) (normal|left|inverted|right) \(' | egrep -o '(normal|left|inverted|right)')" # Using current screen orientation proceed to rotate screen and input tools. case "$rotation" in normal) # rotate to the left xrandr -o right xsetwacom set "Wacom ISDv4 E6 Pen stylus" rotate cw xsetwacom set "Wacom ISDv4 E6 Finger touch" rotate cw xsetwacom set "Wacom ISDv4 E6 Pen eraser" rotate cw ;; right) # rotate to normal xrandr -o normal xsetwacom set "Wacom ISDv4 E6 Pen stylus" rotate none xsetwacom set "Wacom ISDv4 E6 Finger touch" rotate none xsetwacom set "Wacom ISDv4 E6 Pen eraser" rotate none ;; esac

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  • WCF Operations and Multidimensional Arrays

    - by JoshReuben
    You cant pass MultiD arrays accross the wire using WCF - you need to pass jagged arrays. heres 2 extension methods that will allow you to convert prior to serialzation and convert back after deserialization:         public static T[,] ToMultiD<T>(this T[][] jArray)         {             int i = jArray.Count();             int j = jArray.Select(x => x.Count()).Aggregate(0, (current, c) => (current > c) ? current : c);                         var mArray = new T[i, j];             for (int ii = 0; ii < i; ii++)             {                 for (int jj = 0; jj < j; jj++)                 {                     mArray[ii, jj] = jArray[ii][jj];                 }             }             return mArray;         }         public static T[][] ToJagged<T>(this T[,] mArray)         {             var cols = mArray.GetLength(0);             var rows = mArray.GetLength(1);             var jArray = new T[cols][];             for (int i = 0; i < cols; i++)             {                 jArray[i] = new T[rows];                 for (int j = 0; j < rows; j++)                 {                     jArray[i][j] = mArray[i, j];                 }             }             return jArray;         } enjoy!

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  • Ubuntuone fails to sync with 'File Sync starting...' displayed

    - by a different ben
    I am on 12.04 using ubuntuone-client 3.0.1-0ubuntu1.0.1. I actually have two machines that I sync with, having the same Ubuntu version and ubuntuone-client version. One is fine, the other is not. File sync has frozen within a user-defined folder under my home folder. The graphical client reports in the top-right corner: 'File Sync starting...', but this doesn't change. I have two files with changes that show a syncing overlay in Nautilus. They are both very small text files. Here are some details: harb@joan:~$ u1sdtool --status State: READY connection: With User Not Network description: ready to connect is_connected: False is_error: False is_online: False queues: WORKING harb@joan:~$ u1sdtool --current-transfers Current uploads: 0 Current downloads: 0 The status seems to suggest that I am not connected to a network, however I am connected to a network - in fact I am accessing this machine via NX. Is it not working because I am connected via NX? Happy to provide other info, just not sure what would be useful.

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  • effect and model vertex declaration compatibility

    - by Vodácek
    I have normal model drawing code. When I try to draw model without UV coordinates I got this exception: System.InvalidOperationException: The current vertex declaration does not include all the elements required by the current vertex shader. TextureCoordinate0 is missing. at Microsoft.Xna.Framework.Graphics.GraphicsDevice.VerifyCanDraw( Boolean bUserPrimitives, Boolean bIndexedPrimitives) at Microsoft.Xna.Framework.Graphics.GraphicsDevice.DrawIndexedPrimitives( PrimitiveType primitiveType, Int32 baseVertex, Int32 minVertexIndex, Int32 numVertices, Int32 startIndex, Int32 primitiveCount) at Microsoft.Xna.Framework.Graphics.ModelMeshPart.Draw() at Microsoft.Xna.Framework.Graphics.ModelMesh.Draw() ... I know what cause the exception, but is possible to avoid it? Is possible to check model before drawing it with current shader for vertex declaration compatibility?

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  • WordPress bot issues

    - by Paul
    I need to implement a blog into a clients site as he is unhappy with his current basic CMS driven solution. It needs to suit both seo and the current style and as I'm a front end dev/designer and they don't have budget to redevelop - the only solution I can think of is to setup a Wordpress blog and restyle to suit. My only worry about this is the current press reports on WordPress being affected by webbots. I understand the main worry Is if you use an id of admin, but I'm concerned that regardless of this the site could be bombarded with bot requests and cause timeouts! Is this valid? If so is there any way to avoid this issue!? If not can anyone recommend another good SEO friendly blog solution!?

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  • How to make "xrandr" work with GMA500?

    - by Nwbie
    Is it error at driver of graphic chip or Xorg or kernel? I am Asus T91mt with GMA500, Ubuntu 12.04.1. I would like too see only a notice of connection at least. A log of xrandr: $ lspci | grep VGA 00:02.0 VGA compatible controller: Intel Corporation System Corporation System Controller Hub (SCH Poulcbo) Graphics Controller (rev 07) vp@vc:~$ xrandr --verbose xrandr: Failed to get size of gamma for output default Screen 0: minimum 1024 x 600, current 1024 x 600, maximum 1024 x 600 default connected 1024x600+0+0 (0x138) normal (normal) 0mm x 0mm Identifier: 0x137 Timestamp: 26863 Subpixel: unknown Clones: CRTC: 0 CRTCs: 0 Transform: 1.000000 0.000000 0.000000 0.000000 1.000000 0.000000 0.000000 0.000000 1.000000 filter: 1024x600 (0x138) 0.0MHz *current h: width 1024 start 0 end 0 total 1024 skew 0 clock 0.0KHz v: height 600 start 0 end 0 total 600 clock 0.0Hz vp@vc:~$ xrandr --prop xrandr: Failed to get size of gamma for output default Screen 0: minimum 1024 x 600, current 1024 x 600, maximum 1024 x 600 default connected 1024x600+0+0 0mm x 0mm 1024x600 0.0* vp@vc:~$ Please help, i am linux newbie and i am tired ;/

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  • Join Gretchen Alarcon In Person for an Oracle HCM Applications Strategy Updates

    - by jay.richey
    How can you benefit from staying current and moving to the latest release of your Oracle HCM applications? Where does Fusion HCM fit in and what do they mean to your existing investments? What does Oracle offer in terms of SaaS for HCM? What is Oracle doing to maintain excellence in your current applications portfolio while innovating in new and creative ways? Join us for an exclusive breakfast briefing where you will have the opportunity to hear about Oracle's current blockbuster releases for HCM: PeopleSoft 9.1 and E-Business Suite 12.1. Take this opportunity to hear about what the latest releases mean to you and learn how organizations like yours are successfully moving forward. Our featured speaker, Gretchen Alarcon, Oracle's Vice President of Fusion HCM Product Strategy will share how Oracle's latest HCM offerings - Fusion HCM and Fusion Talent Management On Demand - can work alongside your Oracle PeopleSoft, E-Business Suite, or JD Edwards HR foundation to show immediate business value. This event promises to provide you with an opportunity to share experiences, best practices, challenges, and successes with fellow business executives. Coming to: Chicago, Minneaoplis, St. Louis

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  • How to handle compensation issue

    - by Ali
    I consider myself an expert Software Developer. Recently, I noticed my current company posted a new job through a recruting firm requiring half experience than I have and even lesser set of skills. However, they are offering the same salary as my current salary. When I joined my current company a year ago, they declined to pay my asking salary. My evaluations are good and there are critical projects in the pipeline where my involvement is crucial for their success. I'm little confused on how to handle this situation. I don't want to come across threatning or any thing like that.

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  • which kernels can I safely purge?

    - by ecoologic
    I use the main answer of this question quite often to clear some space, but now I'm in extreme need and I'd like to better understand which kernels are safe to purge, my list is the following 10:50:58-673 - ~> dpkg -l | grep -Eo "^.i +linux-(image|headers)[^ ]+" | cut -c 5- | grep --color -E "$|"`uname -r` linux-headers-2.6.38-15 linux-headers-2.6.38-15-generic linux-headers-2.6.38-15-generic-pae linux-headers-2.6.38-16 linux-headers-2.6.38-16-generic linux-headers-2.6.38-16-generic-pae # current one linux-headers-generic linux-headers-generic-pae linux-headers-server linux-image-2.6.38-15-generic-pae linux-image-2.6.38-16-generic-pae linux-image-generic-pae linux-image-server Is it enough to keep linux-headers-2.6.38-15 linux-headers-2.6.38-15-generic linux-headers-2.6.38-15-generic-pae linux-headers-2.6.38-16 linux-headers-2.6.38-16-generic linux-headers-2.6.38-16-generic-pae # current one Or would this be enough linux-headers-2.6.38-15-generic-pae linux-headers-2.6.38-16-generic-pae # current one Or which other would be the shortest (keeping the previous one too)? And why?

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