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  • django urls.py regex isn't working

    - by Phil
    This is for Django 1.2.5 and Python 2.7 on Wamp Server running apache version 2.2.17. My problem is that the my URLConf in urls.py isn't redirecting, it's just throwing a 404 error. urls.py: from django.conf.urls.defaults import * # Uncomment the next two lines to enable the admin: #from django.contrib import admin #admin.autodiscover() urlpatterns = patterns('', (r'^app/$', include('app.views.index')), # Uncomment the admin/doc line below to enable admin documentation: #(r'^admin/doc/', include('django.contrib.admindocs.urls')), # Uncomment the next line to enable the admin: #(r'^admin/', include(admin.site.urls)), ) views.py from django.http import HttpResponse def index(request): return HttpResponse("Hello World") I'm getting the following error: ImportError at /app/ No module named index I'm stumped as I'm only learning Django, can anybody see something wrong with my code? Here's my PythonPath: ['C:\Windows\system32\python27.zip', 'C:\Python27\Lib', 'C:\Python27\DLLs', 'C:\Python27\Lib\lib-tk', 'C:\wamp\bin\apache\Apache2.2.17', 'C:\wamp\bin\apache\apache2.2.17\bin', 'C:\Python27', 'C:\Python27\lib\site-packages', 'c:\wamp\www\seetwo']

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  • rename files with the same name

    - by snorpey
    Hi. I use the following function to rename thumbnails. For example, if I upload a file called "image.png" to an upload folder, and this folder already has a file named "image.png" in it, the new file automatically gets renamed to "image-copy-1.png". If there also is a file called "image-copy-1.png" it gets renamed to "image-copy-2.png" and so on. The following function returns the new filename. At least that's what it is supposed to do... The renaming doesn't seeem to work correctly, though. Sometimes it produces strange results, like: 1.png 1-copy-1.png 1-copy-2.png 1-copy-2-copy-1.png 1-copy-2-copy-3.png I hope you understand my problem, despite my description being somewhat complex... Can you tell me what went wrong here? (bonus question: Is regular expressions the right tool for doing this kind of stuff?) <?php function renameDuplicates($path, $file) { $fileName = pathinfo($path . $file, PATHINFO_FILENAME); $fileExtension = "." . pathinfo($path . $file, PATHINFO_EXTENSION); if(file_exists($path . $file)) { $fileCopy = $fileName . "-copy-1"; if(file_exists($path . $fileCopy . $fileExtension)) { if ($contains = preg_match_all ("/.*?(copy)(-)(\\d+)/is", $fileCopy, $matches)) { $copyIndex = $matches[3][0]; $fileName = substr($fileCopy, 0, -(strlen("-copy-" . $copyIndex))) . "-copy-" . ($copyIndex + 1); } } else { $fileName .= "-copy-1"; } } $returnValue = $fileName . $fileExtension; return $returnValue; }?>

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  • Splitting a string according to a delimiter when elements in the string can contain the delimiter

    - by Vivin Paliath
    I have a string that looks like this: "#Text() #SomeMoreText() #TextThatContainsDelimiter(#blah) #SomethingElse()" I'd like to get back [#Text(), #SomeMoreText(), #TextThatContainsDelimiter(#blah), #SomethingElse()] One way I thought about doing this was to require that the # to be escaped into \#, which makes the input string: "#Text() #SomeMoreText() #TextThatContainsDelimiter(\#blah) #SomethingElse()" I can then split it using /[^\\]#/ which gives me: [#Text(), SomeMoreText, TextThatContainsDelimiter(\#blah), SomethingElse()] The first element will contain # but I can strip it out. However, is there a cleaner way to do this without having to escape the #, and which ensures that the first element will not contain a #? Basically I'd like it to split by # only if the # is not enclosed by parentheses. My hunch is that since the # is context-sensitive and and regular expressions are only suited for context-free strings, this may not be the right tool. If so, would I have to write a grammar for this and roll my own parser/lexer?

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  • Regular expression for checking website url

    - by Linto davis
    I need to check the web address, using regular expression. if user type url as www.test.com http://www.test.com https://www.test.com i have a regular expression like /^(http\:\/\/[a-zA-Z0-9_-]+(?:.[a-zA-Z0-9_-]+)*.[a-zA-Z]{2,4}(?:\/[a-zA-Z0-9_]+)*(?:\/[a-zA-Z0-9_]+.[a-zA-Z]{2,4}(?:\?[a-zA-Z0-9_]+\=[a-zA-Z0-9_]+)?)?(?:\&[a-zA-Z0-9_]+\=[a-zA-Z0-9_]+)*)$/ but it will only allow the second option only. how can i modify the regular expression so that , it should accept 1st and 3rd option too

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  • Wanted: a very simple java RegExp API

    - by itsadok
    I'm tired of writing Pattern p = Pattern.compile(... Matcher m = p.matcher(str); if (m.find()) { ... Over and over again in my code. I was going to write a helper class to make it neater, but I then I wondered: is there a library that tries to provide a simpler facade for Regular Expressions in Java? I'm thinking something in the style of commons-lang and Guava.

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  • Determining whether values can potentially match a regular expression, given more input

    - by Andreas Grech
    I am currently writing an application in JavaScript where I'm matching input to regular expressions, but I also need to find a way how to match strings to parts of the regular expressions. For example: var invalid = "x", potentially = "g", valid = "ggg", gReg = /^ggg$/; gReg.test(invalid); //returns false (correct) gReg.test(valid); //returns true (correct) Now I need to find a way to somehow determine that the value of the potentially variable doesn't exactly match the /^ggg$/ expression, BUT with more input, it potentially can! So for example in this case, the potentially variable is g, but if two more g's are appended to it, it will match the regular expression /^ggg$/ But in the case of invalid, it can never match the /^ggg$/ expression, no matter how many characters you append to it. So how can I determine if a string has or doesn't have potential to match a particular regular expression?

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  • Regular expressions and the question mark

    - by James P.
    I'm having trouble finding a regular expression that matches the following String. Korben;http://feeds.feedburner.com/KorbensBlog-UpgradeYourMind?format=xml;1 One problem is escaping the question mark. Java's pattern matcher doesn't seem to accept \? as a valid escape sequence but it also fails to work with the tester at myregexp.com. Here's what I have so far: ([a-zA-Z0-9])+;http://([a-zA-Z0-9./-]+);[0-9]+ Any suggestions?

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  • Track results of a regular expression extractor in JMeter

    - by Glenn Slaven
    Our server returns a custom 'X-Execution-Time' HTTP response header that returns in miliseconds the time between the server getting a request and our code returning a page, ie how long our code takes to run. I'm using JMeter to do some testing & I'd like to be able to report on this number of over time. I've setup this regular expression extractor: X-Execution-Time:\s(\d+) but I don't know how to get JMeter to report on this number per request so i can get a trend over time

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  • format string (postcode) in ruby

    - by noddy
    I need to re-format a list of UK postcodes and have started with the following to strip whitespace and capitalize: postcode.upcase.gsub(/\s/,'') I now need to change the postcode so the new postcode will be in a format that will match the following regexp: ^([A-PR-UWYZ0-9][A-HK-Y0-9][AEHMNPRTVXY0-9]?[ABEHMNPRVWXY0-9]? {1,2}[0-9][ABD-HJLN-UW-Z]{2}|GIR 0AA)$ I would be grateful of any assistance.

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  • What's a regular language?

    - by Javier Badia
    I've read that you can't parse HTML with regular expressions because HTML is not a regular language. I tried searching Wikipedia, but I didn't understand a word of what the various related articles said. Can someone explain, in simpler terms, what's a regular (or non-regular) language, and why non-regular languages can't be parsed with regexes?

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  • How to remove lowercase sentence fragments from text?

    - by Aaron
    Hello: I'm tyring to remove lowercase sentence fragments from standard text files using regular expresions or a simple Perl oneliner. These are commonly referred to as speech or attribution tags, for example - he said, she said, etc. This example shows before and after using manual deletion: Original: "Ah, that's perfectly true!" exclaimed Alyosha. "Oh, do leave off playing the fool! Some idiot comes in, and you put us to shame!" cried the girl by the window, suddenly turning to her father with a disdainful and contemptuous air. "Wait a little, Varvara!" cried her father, speaking peremptorily but looking at them quite approvingly. "That's her character," he said, addressing Alyosha again. "Where have you been?" he asked him. "I think," he said, "I've forgotten something... my handkerchief, I think.... Well, even if I've not forgotten anything, let me stay a little." He sat down. Father stood over him. "You sit down, too," said he. All lower case sentence fragments manually removed: "Ah, that's perfectly true!" "Oh, do leave off playing the fool! Some idiot comes in, and you put us to shame!" "Wait a little, Varvara!" "That's her character," "Where have you been?" "I think," "I've forgotten something... my handkerchief, I think.... Well, even if I've not forgotten anything, let me stay a little." He sat down. Father stood over him. "You sit down, too," I've changed straight quotes " to balanced and tried: ” (...)+[.] Of course, this removes some fragments but deletes some text in balanced quotes and text starting with uppercase letters. [^A-Z] didn't work in the above expression. I realize that it may be impossible to achieve 100% accuracy but any useful expression, perl, or python script would be deeply appreciated. Cheers, Aaron

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  • SoundManager / Jquery / Regular expression : Parse class name before certain character To Get SoundI

    - by j-man86
    So I am trying to access a jquery soundmanager variable from one script (wpaudio.js – from the wp-audio plugin) inside of another (init.js – my own javascript). I am creating an alternate pause/play button higher up on the page and need to resume the current soundID, which is contained as part of a class name in the DOM. Here is the code that creates that class name in wpaudio.js: function wpaButtonCheck() { if (!this.playState || this.paused) jQuery('#' + this.sID + '_play').attr('src', wpa_url + '/wpa_play.png'); else jQuery('#' + this.sID + '_play').attr('src', wpa_url + '/wpa_pause.png'); } Here is the output: where wpa0 would be the sID of the sound I need. My current script in init.js is: $('.mixesSidebar #currentSong .playBtn').toggle(function() { soundManager.pauseAll(); $(this).addClass('paused'); }, function() { soundManager.resumeAll(); $(this).removeClass('paused'); }); I need to change resumeAll to "resume(this.sID)", but I need to somehow store the sID onclick and call it in the above function. Alternately, I think a regular expression that could get the class name of the current play button and either parse the string up to the "_play" or use a trim function to get rid of "_play"– but I'm not sure how to do this. Thanks for your help!

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  • How to create Shared VB Array Initialisors for NerdDinner

    - by David A Gibson
    Hello, I am trying to work my way through the NerdDinner tutorial - and as an exercise I'm converting it to VB as I go. I'm not very far in and after having gotten past the C# Yield statement I'm stuck on Shared VB Array Initialisors. static IDictionary<string, Regex> countryRegex = new Dictionary<string, Regex>() { { "USA", new Regex("^[2-9]\\d{2}-\\d{3}-\\d{4}$")}, { "UK", new Regex("(^1300\\d{6}$)|(^1800|1900|1902\\d{6}$)|(^0[2|3|7|8]{1}[0- 9]{8}$)|(^13\\d{4}$)|(^04\\d{2,3}\\d{6}$)")}, { "Netherlands", new Regex("(^\\+[0-9]{2}|^\\+[0- 9]{2}\\(0\\)|^\\(\\+[0-9]{2}\\)\\(0\\)|^00[0-9]{2}|^0)([0-9]{9}$|[0-9\\- \\s]{10}$)")}, Can anyone please help me write this in VB? Public Shared countryRegex As IDictionary(Of String, Regex) = New Dictionary(Of String, Regex)() {("USA", New Regex("^[2-9]\\d{2}-\\d{3}-\\d{4}$"))} This code has an error as it does not accept the String and the Regex as an item for the array. Thanks

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  • Regular expression replace in PL/pgSQL

    - by dreamlax
    If I have the following input (excluding quotes): "The ancestral territorial imperatives of the trumpeter swan" How can I collapse all multiple spaces to a single space so that the input is transformed to: "The ancestral territorial imperatives of the trumpeter swan" This is going to be used in a trigger function on insert/update (which already trims leading/trailing spaces). Currently, it raises an exception if the input contains multiple adjacent spaces, but I would rather it simply transforms it into something valid before inserting. What is the best approach? I can't seem to find a regular-expression replace function for PL/pgSQL. There is a text_replace function, but this will only collapse at most two spaces down to one (meaning three consecutive spaces will collapse to two). Calling this function over and over is not ideal.

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  • Python re.sub MULTILINE caret match

    - by cdleary
    The Python docs say: re.MULTILINE: When specified, the pattern character '^' matches at the beginning of the string and at the beginning of each line (immediately following each newline)... By default, '^' matches only at the beginning of the string... So what's going on when I get the following unexpected result? >>> import re >>> s = """// The quick brown fox. ... // Jumped over the lazy dog.""" >>> re.sub('^//', '', s, re.MULTILINE) ' The quick brown fox.\n// Jumped over the lazy dog.'

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  • Matching unmatched strings based on a unknown pattern

    - by Polity
    Alright guys, i really hurt my brain over this one and i'm curious if you guys can give me any pointers towards the right direction i should be taking. The situation is this: Lets say, i have a collection of strings (let it be clear that the pattern of this strings is unknown. For a fact, i can say that the string contain only signs from the ASCII table and therefore, i dont have to worry about weird Chinese signs). For this example, i take the following collection of strings (note that the strings dont have to make any human sence so dont try figguring them out :)): "[001].[FOO].[TEST] - 'foofoo.test'", "[002].[FOO].[TEST] - 'foofoo.test'", "[003].[FOO].[TEST] - 'foofoo.test'", "[001].[FOO].[TEST] - 'foofoo.test.sample'", "[002].[FOO].[TEST] - 'foofoo.test.sample'", "-001- BAR.[TEST] - 'bartest.xx1", "-002- BAR.[TEST] - 'bartest.xx1" Now, what i need to have is a way of finding logical groups (and subgroups) of these set of strings, so in the above example, just by rational thinking, you can combine the first 3, the 2 after that and the last 2. Also the resulting groups from the first 5 can be combined in one main group with 2 subgroups, this should give you something like this: { { "[001].[FOO].[TEST] - 'foofoo.test'", "[002].[FOO].[TEST] - 'foofoo.test'", "[003].[FOO].[TEST] - 'foofoo.test'", } { "[001].[FOO].[TEST] - 'foofoo.test.sample'", "[002].[FOO].[TEST] - 'foofoo.test.sample'", } { "-001- BAR.[TEST] - 'bartest.xx1", "-002- BAR.[TEST] - 'bartest.xx1" } } Sorry for the layout above but indenting with 4 spaces doesnt seem to work correctly (or im frakk'n it up). Anyways, I'm not sure how to approach this problem (how to get the result desired as indicated above). First of, i thought of creating a huge set of regexes which would parse most known patterns but the amount of different patterns is just to huge that this isn't realistic. Another think i thought of was parsing each indidual word within a string (so strip all non alphabetic or numeric characters and split by those), and if X% matches, i can assume the strings belong to the same group. (where X wil probably be around 80/90). However, i find the area of speculation kinda big. For example, when matching strings with each 20 words, the change of hitting above 80% is kinda big (that means that 4 words can differ), however when matching only 8 words, 2 words at most can differ. My question to you is, what would be a logical approach in the above situation? Thanks in advance!

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  • Matching a date in perl

    - by Zerobu
    Hello, I want to match a date in the format day/month/year. where day is two digits month is two digits and year is four digits. Also, I want to check see if it is a valid date, for example knows when is leap year, and know which month has 30days, 31days and 28, or 29 days for Februrary.

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  • how to match all group and subgroup in pcre

    - by mono
    a ip or other string, like "11.22.33.44" or "aa.bb.cc.dd". basically, I think it is very easy, (([\d\w]+)+\.)+[\d\w]+ but the problem is which group these submatches are in. not like ip, some string is consist of lots of words+separate in pcre, I don't know how to extract it all words -- "aa bb cc dd ..."

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  • Regular expression works normally, but fails when placed in an XML schema

    - by Eli Courtwright
    I have a simple doc.xml file which contains a single root element with a Timestamp attribute: <?xml version="1.0" encoding="utf-8"?> <root Timestamp="04-21-2010 16:00:19.000" /> I'd like to validate this document against a my simple schema.xsd to make sure that the Timestamp is in the correct format: <?xml version="1.0" encoding="utf-8"?> <xs:schema attributeFormDefault="unqualified" elementFormDefault="qualified" xmlns:xs="http://www.w3.org/2001/XMLSchema"> <xs:element name="root"> <xs:complexType> <xs:attribute name="Timestamp" use="required" type="timeStampType"/> </xs:complexType> </xs:element> <xs:simpleType name="timeStampType"> <xs:restriction base="xs:string"> <xs:pattern value="(0[0-9]{1})|(1[0-2]{1})-(3[0-1]{1}|[0-2]{1}[0-9]{1})-[2-9]{1}[0-9]{3} ([0-1]{1}[0-9]{1}|2[0-3]{1}):[0-5]{1}[0-9]{1}:[0-5]{1}[0-9]{1}.[0-9]{3}" /> </xs:restriction> </xs:simpleType> </xs:schema> So I use the lxml Python module and try to perform a simple schema validation and report any errors: from lxml import etree schema = etree.XMLSchema( etree.parse("schema.xsd") ) doc = etree.parse("doc.xml") if not schema.validate(doc): for e in schema.error_log: print e.message My XML document fails validation with the following error messages: Element 'root', attribute 'Timestamp': [facet 'pattern'] The value '04-21-2010 16:00:19.000' is not accepted by the pattern '(0[0-9]{1})|(1[0-2]{1})-(3[0-1]{1}|[0-2]{1}[0-9]{1})-[2-9]{1}[0-9]{3} ([0-1]{1}[0-9]{1}|2[0-3]{1}):[0-5]{1}[0-9]{1}:[0-5]{1}[0-9]{1}.[0-9]{3}'. Element 'root', attribute 'Timestamp': '04-21-2010 16:00:19.000' is not a valid value of the atomic type 'timeStampType'. So it looks like my regular expression must be faulty. But when I try to validate the regular expression at the command line, it passes: >>> import re >>> pat = '(0[0-9]{1})|(1[0-2]{1})-(3[0-1]{1}|[0-2]{1}[0-9]{1})-[2-9]{1}[0-9]{3} ([0-1]{1}[0-9]{1}|2[0-3]{1}):[0-5]{1}[0-9]{1}:[0-5]{1}[0-9]{1}.[0-9]{3}' >>> assert re.match(pat, '04-21-2010 16:00:19.000') >>> I'm aware that XSD regular expressions don't have every feature, but the documentation I've found indicates that every feature that I'm using should work. So what am I mis-understanding, and why does my document fail?

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  • Use regular expressions to match an ? but not a \?

    - by J.Milly
    I have a PHP regular expression that has been functioning fairly well to parse some odd legacy client templates until recently when we found an escaped question mark (\?) included in a template expression. I'm not strong enough with my regular expression-fu to wrap my feeble noodle around a negative look ahead or some techno-mumbo-jumbo so, tips or points in the right direction would be greatly appreciated. My PHP: preg_match_all("/\{\{IF (.*)\?(.*):(.*)\}\}/U", $template, $m, PREG_SET_ORDER);

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  • PHP Form Validation Regular Expression, no symbols or numbers

    - by MrEnder
    Ok I am trying to get the users First Name the form gets their name perfectly fine and posts it into a variable. Now I am trying to do error checking else if(!preg_match("/^[\w-]+$/", $firstNameSignup)) { $firstNameSignupError = "Your first name cannot contain numbers or symbols, you entered " . $firstNameSignup; $firstNameSignup = ""; } I tried the above code and it does not like me but my if statement if(!isset($firstNameSignup) || $firstNameSignup == "") { $firstNameSignupError = "You must enter your first name"; } works fine so I know that the error is in that else if statement... most likely in my regular expression any help??? I'm totally at a loss (really new to PHP and regular expressions) Thanks Shelby

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  • Turning HTML character entities to 'regular' letters... why is it only partially working?

    - by Jack W-H
    I'm using all of the below to take a field called 'code' from my database, get rid of all the HTML entities, and print it 'as usual' to the site: <?php $code = preg_replace('~&#x([0-9a-f]+);~ei', 'chr(hexdec("\\1"))', $code); $code = preg_replace('~&#([0-9]+);~e', 'chr("\\1")', $code); $code = html_entity_decode($code); ?> However the exported code still looks like this: progid:DXImageTransform.Microsoft.AlphaImageLoader(src=’img/the_image.png’); See what's going on there? How many other things can I run on the string to turn them into darn regular characters?! Thanks! Jack

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  • Warning: preg_match() [function.preg-match]: Unknown modifier '/' problem

    - by SonOfOmer
    I am building custom implementation of php MVC routing engine, and I have custom routes like one in $routes array below. Each time when I send asynchronous GET request like xmlhttp.open("GET","someurl"); I get following message Warning: preg_match() [function.preg-match]: Unknown modifier '/' problem but with synchronous (normal) request it all works fine <?php $routes = array( array('url' => '/^someurl$/', 'controller' => 'somecontroller', 'view' => 'someview') ); $url = $_SERVER['REQUEST_URI']; $url = substr( $url, 1 ); $params = array(); $route_match = false; foreach($routes as $urls => $route) { if(preg_match($route['url'], $url, $matches)) { $params = array_merge($params, $matches); $route_match = true; break; } } require_once(CONTROLLER_PATH.$route['controller'].'.php'); ?> string(11) "/^someurl$/" is the result of var_dump($route['url']); Thanks.

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  • JavaScript String Replace with a tricky regular expression

    - by Juri
    Hi. I'm trying to work out what regular expression I would need to change this string html = '<img style="width: 311px; height: 376px;" alt="test" src="/img/1268749322.jpg" />'; to this html = '<img width="311" height="376" alt="test" src="/img/1268749322.jpg" />'; with the help of Javascript.replace. This is my start: html = html.replace(/ style="width:\?([0-9])px*"/g, "width=\"$1\""); Can anyone help me? THANKS

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