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  • Combine regular expressions for splitting camelCase string into words

    - by stou
    I managed to implement a function that converts camel case to words, by using the solution suggested by @ridgerunner in this question: Split camelCase word into words with php preg_match (Regular Expression) However, I want to also handle embedded abreviations like this: 'hasABREVIATIONEmbedded' translates to 'Has ABREVIATION Embedded' I came up with this solution: <?php function camelCaseToWords($camelCaseStr) { // Convert: "TestASAPTestMore" to "TestASAP TestMore" $abreviationsPattern = '/' . // Match position between UPPERCASE "words" '(?<=[A-Z])' . // Position is after group of uppercase, '(?=[A-Z][a-z])' . // and before group of lowercase letters, except the last upper case letter in the group. '/x'; $arr = preg_split($abreviationsPattern, $camelCaseStr); $str = implode(' ', $arr); // Convert "TestASAP TestMore" to "Test ASAP Test More" $camelCasePattern = '/' . // Match position between camelCase "words". '(?<=[a-z])' . // Position is after a lowercase, '(?=[A-Z])' . // and before an uppercase letter. '/x'; $arr = preg_split($camelCasePattern, $str); $str = implode(' ', $arr); $str = ucfirst(trim($str)); return $str; } $inputs = array( 'oneTwoThreeFour', 'StartsWithCap', 'hasConsecutiveCAPS', 'ALLCAPS', 'ALL_CAPS_AND_UNDERSCORES', 'hasABREVIATIONEmbedded', ); echo "INPUT"; foreach($inputs as $val) { echo "'" . $val . "' translates to '" . camelCaseToWords($val). "'\n"; } The output is: INPUT'oneTwoThreeFour' translates to 'One Two Three Four' 'StartsWithCap' translates to 'Starts With Cap' 'hasConsecutiveCAPS' translates to 'Has Consecutive CAPS' 'ALLCAPS' translates to 'ALLCAPS' 'ALL_CAPS_AND_UNDERSCORES' translates to 'ALL_CAPS_AND_UNDERSCORES' 'hasABREVIATIONEmbedded' translates to 'Has ABREVIATION Embedded' It works as intended. My question is: Can I combine the 2 regular expressions $abreviationsPattern and camelCasePattern so i can avoid running the preg_split() function twice?

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  • In Python BeautifulSoup How to move tags

    - by JJ
    I have a partially converted XML document in soup coming from HTML. After some replacement and editing in the soup, the body is essentially - <Text...></Text> # This replaces <a href..> tags but automatically creates the </Text> <p class=norm ...</p> <p class=norm ...</p> <Text...></Text> <p class=norm ...</p> and so forth. I need to "move" the <p> tags to be children to <Text> or know how to suppress the </Text>. I want - <Text...> <p class=norm ...</p> <p class=norm ...</p> </Text> <Text...> <p class=norm ...</p> </Text> I've tried using item.insert and item.append but I'm thinking there must be a more elegant solution. for item in soup.findAll(['p','span']): if item.name == 'span' and item.has_key('class') and item['class'] == 'section': xBCV = short_2_long(item._getAttrMap().get('value','')) if currentnode: pass currentnode = Tag(soup,'Text', attrs=[('TypeOf', 'Section'),... ]) item.replaceWith(currentnode) # works but creates end tag elif item.name == 'p' and item.has_key('class') and item['class'] == 'norm': childcdatanode = None for ahref in item.findAll('a'): if childcdatanode: pass newlink = filter_hrefs(str(ahref)) childcdatanode = Tag(soup, newlink) ahref.replaceWith(childcdatanode) Thanks

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  • Transforming a string to a valid PDO_MYSQL DSN

    - by Alix Axel
    What is the most concise way to transform a string in the following format: mysql:[/[/]][user[:pass]@]host[:port]/db[/] Into a usuable PDO connection/instance (using the PDO_MYSQL DSN), some possible examples: $conn = new PDO('mysql:host=host;dbname=db'); $conn = new PDO('mysql:host=host;port=3307;dbname=db'); $conn = new PDO('mysql:host=host;port=3307;dbname=db', 'user'); $conn = new PDO('mysql:host=host;port=3307;dbname=db', 'user', 'pass'); I've been trying some regular expressions (preg_[match|split|replace]) but they either don't work or are too complex, my gut tells me this is not the way to go but nothing else comes to my mind. Any suggestions?

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  • Convert regular expression to CFG

    - by user242581
    How can I convert some regular language to its equivalent Context Free Grammar(CFG)? Whether the DFA corresponding to that regular expression is required to be constructed or is there some rule for the above conversion? For example, considering the following regular expression 01+10(11)* How can I describe the grammar corresponding to the above RE?

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  • strange behavior in vim with negative look-behind

    - by João Portela
    So, I am doing this search in vim: /\(\(unum\)\|\(player\)=\)\@<!\"1\" and as expected it does not match lines that have: player="1" but matches lines that have: unum="1" what am i doing wrong? isn't the atom to be negated all of this: \(\(unum\)\|\(player\)=\) naturally just doing: /\(\(unum\)\|\(player\)=\) matches unum= or player=.

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  • Intersection of two regular expressions

    - by Henry
    Hi, Im looking for function (PHP will be the best), which returns true whether exists string matches both regexpA and regexpB. Example 1: $regexpA = '[0-9]+'; $regexpB = '[0-9]{2,3}'; hasRegularsIntersection($regexpA,$regexpB) returns TRUE because '12' matches both regexps Example 2: $regexpA = '[0-9]+'; $regexpB = '[a-z]+'; hasRegularsIntersection($regexpA,$regexpB) returns FALSE because numbers never matches literals. Thanks for any suggestions how to solve this. Henry

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  • Cleaning strings in R: add punctuation w/o overwriting last character

    - by spearmint
    I'm new to R and unable to find other threads with a similar issue. I'm cleaning data that requires punctuation at the end of each line. I am unable to add, say, a period without overwriting the final character of the line preceding the carriage return + line feed. Sample code: Data1 <- "%trn: dads sheep\r\n*MOT: hunn.\r\n%trn: yes.\r\n*MOT: ana mu\r\n%trn: where is it?" Data2 <- gsub("[^[:punct:]]\r\n\\*", ".\r\n\\*", Data1) The contents of Data2: [1] "%trn: dads shee.\r\n*MOT: hunn.\r\n%trn: yes.\r\n*MOT: ana mu\r\n%trn: where is it?" Notice the "p" of sheep was overwritten with the period. Any thoughts on how I could avoid this?

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  • Regexp that matches user-agents of end-user browsers but NOT crawlers with >90 % accuracy

    - by knorv
    I'm trying to construct a regexp that will evaluate to true for User-Agent:s of "browsers navigated by humans", but false for bots. Needless to say the matching will not be exact, but if it gets things right in say 90 % of cases that is more than good enough. My approach so far is to target the User-Agent string of the the five major desktop browsers (MSIE, Firefox, Chrome, Safari, Opera). Specifically I want the regexp NOT to match if the user-agent is a bot (Googlebot, msnbot, etc.). Currently I'm using the following regexp which appears to achieve the desired precision: ^(Mozilla.*(Gecko|KHTML|MSIE|Presto|Trident)|Opera).*$ I've observed small number of false negatives which are mostly mobile browsers. The exceptions all match: (BlackBerry|HTC|LG|MOT|Nokia|NOKIAN|PLAYSTATION|PSP|SAMSUNG|SonyEricsson) My question is: Given the desired accuracy level, how would you improve the regexp? Can you think of any major false positives or false negatives to the given regexp? Please note that the question is specifically about regexp-based User-Agent matching. There are a bunch of other approaches to solving this problem, but those are out of the scope of this question.

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  • Not-quite-JSON string deserialization in Python

    - by cpharmston
    I get the following text as a string from an XML-based REST API 'd':4 'ca':5 'sen':1 'diann':2,6,8 'feinstein':3,7,9 that I'm looking to deserialize into a pretty little Python dictionary: { 'd': [4], 'ca': [5], 'sen': [1], 'diann': [2, 6, 8], 'feinstein': [3, 7, 9] } I'm hoping to avoid using regular expressions or heavy string manipulation, as this format isn't documented and may change. The best I've been able to come up with: members = {} for m in elem.text.split(' '): m = m.split(':') members[m[0].replace("'", '')] = map(int, m[1].split(',')) return members Obviously a terrible approach, but it works, and that's better than anything else I've got right now. Any suggestions on better approaches?

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  • Invert regexp in vim

    - by Chris J
    There's a few "how do I invert a regexp" questions here on stackoverflow, but I can't find one for vim (if it does exist, by goggle-fu is lacking today). In essence I want to match all non-printable characters and delete them. I could write a short script, or drop to a shell and use tr or something similar to delete, but a vim solution would be dandy :-) Vim has the atom \p to match printable characters, however trying to do this :s/[^\p]//g to match the inverse failed and just left me with every 'p' in the file. I've seen the (?!xxx) sequence in other questions, and vim seems to not recognise this sequence. I've not found seen an atom for non-printable chars. In the interim, I'm going to drop to external tools, but if anyone's got any trick up their sleeve to do this, it'd be welcome :-) Ta!

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  • How to split a space separated file?

    - by simplesimon
    Hi I am trying to import this: http://en.wikipedia.org/wiki/List_of_countries_by_continent_%28data_file%29 which is of the format like: AS AF AFG 004 Afghanistan, Islamic Republic of EU AX ALA 248 Åland Islands EU AL ALB 008 Albania, Republic of AF DZ DZA 012 Algeria, People's Democratic Republic of OC AS ASM 016 American Samoa EU AD AND 020 Andorra, Principality of AF AO AGO 024 Angola, Republic of NA AI AIA 660 Anguilla if i do <? explode(" ",$data"); ?> that works fine apart from countries with more than 1 word. how can i split it so i get the first 4 bits of data (the chars/ints) and the 5th bit of data being whatever remains? this is in php thank you

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  • Regexp: Replace only in specific context

    - by blinry
    In a text, I would like to replace all occurrences of $word by [$word]($word) (to create a link in Markdown), but only if it is not already in a link. Example: [$word homepage](http://w00tw00t.org) should not become [[$word]($word) homepage](http://w00tw00t.org). Thus, I need to check whether $word is somewhere between [ and ] and only replace if it's not the case. Can you think of a preg_replace command for this?

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  • How do I locate a particular word in a text file using .NET

    - by cmrhema
    I am sending mails (in asp.net ,c#), having a template in text file (.txt) like below User Name :<User Name> Address : <Address>. I used to replace the words within the angle brackets in the text file using the below code StreamReader sr; sr = File.OpenText(HttpContext.Current.Server.MapPath(txt)); copy = sr.ReadToEnd(); sr.Close(); //close the reader copy = copy.Replace(word.ToUpper(),"#" + word.ToUpper()); //remove the word specified UC //save new copy into existing text file FileInfo newText = new FileInfo(HttpContext.Current.Server.MapPath(txt)); StreamWriter newCopy = newText.CreateText(); newCopy.WriteLine(copy); newCopy.Write(newCopy.NewLine); newCopy.Close(); Now I have a new problem, the user will be adding new words within an angle, say for eg, they will be adding <Salary>. In that case i have to read out and find the word <Salary>. In other words, I have to find all the words, that are located with the angle brackets (<). How do I do that?

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  • stripping a query string with php (preg_replace)

    - by pg
    http://www.chuckecheese.com/rotator.php?cheese=4&id=1 I want to take out the id, leaving the cheese to stand alone. I tried: $qs = preg_replace("[^&id=*]" ,'',$_SERVER[QUERY_STRING]); But that said I was using an improper modifier. I want to remove "$id=" and whatever number comes after it. Are regexp really as hard as they seem for me?

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  • Regular expression for email

    - by Nadeem
    I tried the reg expression ^([a-zA-Z0-9_.-])+@([a-zA-Z0-9_.-])+\.([a-zA-Z])+([a-zA-Z])+ for the email validation. Since I want the user to allow submitting even with the empty email address. So I changed the reg ex to (^([a-zA-Z0-9_.-])+@([a-zA-Z0-9_.-])+\.([a-zA-Z])+([a-zA-Z])+)? But this expression accepts any email address without any validation.

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  • Find ASCII "arrows" in text

    - by ulver
    I'm trying to find all the occurrences of "Arrows" in text, so in "<----=====><==->>" the arrows are: "<----", "=====>", "<==", "->", ">" This works: String[] patterns = {"<=*", "<-*", "=*>", "-*>"}; for (String p : patterns) { Matcher A = Pattern.compile(p).matcher(s); while (A.find()) { System.out.println(A.group()); } } but this doesn't: String p = "<=*|<-*|=*>|-*>"; Matcher A = Pattern.compile(p).matcher(s); while (A.find()) { System.out.println(A.group()); } No idea why. It often reports "<" instead of "<====" or similar. What is wrong?

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  • Simple java regular expression replace question.

    - by Yang
    I have a simple xml file and I want to remove everything before the first tag. ..... item1 .... The following java code is not working: String cleanxml = rawxml.replace("^[\\s\\S]+<item>", ""); What is the correct way to do this? And how do I address the non-greedy issue? Sorry I'm a C# programmer.

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