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  • Variable won't store in session

    - by Mittens
    So I'm trying to store the "rank" of a user when they log in to a control panel which displays different options depending on the given rank. I used the same method as I did for storing and displaying the username, which is displayed on the top of each page and works just fine. I can't for the life of me figure out why it won't work for the rank value, but I do know that it is not saving it in the session. Here is the bit that's not working; $username = ($_POST['username']); $password = hash('sha512', $_POST['password']); $dbhost = 'mysql:host=¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦;dbname=¦¦¦¦¦¦¦¦¦¦¦'; $dbuser = '¦¦¦¦¦¦¦¦¦¦¦'; $dbpassword = '¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦'; try { $db = new PDO($dbhost, $dbuser, $dbpassword); $statement = $db->prepare("select password from users where email = :name"); $statement->execute(array(':name' => $username)); $result = $statement->fetch(); $pass = $result[password]; $rank = $result[rank];} catch(PDOException $e) {echo $e->getMessage();} if ($password == $pass) { session_start(); $_SESSION['username'] = $username; $_SESSION['rank'] = $rank; header('Location: http://¦¦¦¦¦¦¦¦¦.ca/manage.php'); } else{ include'../../includes/head.inc'; echo '<h1>Incorrect username or password.</h1>'; include'../../includes/footer.inc'; } I'm also new to the whole PDO thing, hence why my method of authenticating the password is pretty sketchy.

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  • C++ enum in foreach

    - by Spencer
    I've have a card class for a blackjack game with the following enums: enum Rank { Ace, Two, Three, Four, Five, Six, Seven, Eight, Nine, Ten, Jack, Queen, King }; enum Suit { Clubs, Diamonds, Hearts, Spades }; When I create the deck I want to write the code like this: // foreach Suit in Card::Suit // foreach Rank in Card::Rank // add new card(rank, suit) to deck I believe there is no foreach in c++. However, how do I traverse an enum? Thanks, Spencer

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  • Ranking - an Introduction

    - by PointsToShare
    © 2011 By: Dov Trietsch. All rights reserved Ranking Ranking is quite common in the internet. Readers are asked to rank their latest reading by clicking on one of 5 (sometimes 10) stars. The number of stars is then converted to a number and the average number of stars as selected by all the readers is proudly (or shamefully) displayed for future readers. SharePoint 2007 lacked this feature altogether. SharePoint 2010 allows the users to rank items in a list or documents in a library (the two are actually the same because a library is actually a list). But in SP2010 the computation of the average is done later on a timer rather than on-the-spot as it should be. I suspect that the reason for this shortcoming is that they did not involve a mathematician! Let me explain. Ranking is kept in a related list. When a user rates a document the rank-list is added an item with the item id, the user name, and his number of stars. The fact that a user already ranked an item prevents him from ranking it again. This prevents the creator of the item from asking his mother to rank it a 5 and do it 753 times, thus stacking the ballot. Some systems will allow a user to change his rating and this will be done by updating the rank-list item. Now, when the timer kicks off, the list is spanned and for each item the rank-list items containing this id are summed up and divided by the number of votes thus yielding the new average. This is obviously very time consuming and very server intensive. In the 18th century an early actuary named James Dodson used what the great Augustus De Morgan (of De Morgan’s law) later named Commutation tables. The labor involved in computing a life insurance premium was staggering and also very error prone. Clerks with pencil and paper would multiply and add mountains of numbers to do the task. The more steps the greater the probability of error and the more expensive the process. Commutation tables created a “summary” of many steps and reduced the work 100 fold. So had Microsoft taken a lesson in the history of computation, they would have developed a much faster way for rating that may be done in real-time and is also 100 times faster and less CPU intensive. How do we do this? We use a form of commutation. We always keep the number of votes and the total of stars. One simple division gives us the average. So we write an event receiver. When a vote is added, we just add the stars to the total-stars and 1 to the number of votes. We then recomputed the average. When a vote is updated, we reduce the total by the old vote, increase it by the new vote and leave the number of votes the same. Again we do the division to get the new average. When a vote is deleted (highly unlikely and maybe even prohibited), we reduce the total by that vote and reduce the number of votes by 1… Gone are the days of spanning lists, counting items, and tallying votes and we have no need for a timer process to run it all. This is the first of a few treatises on ranking. Even though I discussed the math and the history thereof, in here I am only going to solve the presentation issue. I wanted to create the CSS and Jscript needed to display the stars, create the various effects like hovering and clicking (onmouseover, onmouseout, onclick, etc.) and I wanted to create a general solution with any number of stars. When I had it all done, I created the ranking game so that I could test it. The game is interesting in and on itself, so here it is (or go to the games page and select “rank the stars”). BTW, when you play it, look at the source code and see how it was all done.  Next, how the 5 stars are displayed in the New and Update forms. When the whole set of articles will be done, you’ll be able to create the complete solution. That’s all folks!

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  • Java App Engine - ranked counter

    - by Richard
    I understand the sharded counter, here: http://code.google.com/appengine/articles/sharding_counters.html The problem is that a simple counter will not work in my application. I am sorting my entities by a particular variable so I am returned not so much a count, but more of a rank. My current method is: SELECT COUNT(this) FROM Entity.class WHERE value <= ? Result + 1 is then the rank of the parameter in relation to the value variable in the persistent Entity objects. The limitation of this is the highest rank being returned is 1001 because count() can give a maximum of 1000. The reason I cannot store the rank on the Entity object is that the ranks are updated very often, and re-setting this rank variable would be much too costly. Any ideas on the best way to accomplish this?

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  • Counting distinct and duplicate attribute values in an array

    - by keruilin
    I have an array of users that's sorted in descending order based on total_points. I need to find the rank of each user in that array. The issue is that more than one user can have the same total points and, thus, the same rank. For example, three users could be in 3rd place with 200 Points. Here's my current code: class Leader < ActiveRecord::Base def self.points_leaders all_leaders = all_points_leaders # returns array of users sorted by total_points in desc order all_leaders_with_rank = [] all_leaders.each do |user| rank = all_leaders.index(user)+1 all_leaders_with_rank << Ldr.new(rank, user) # Ldr is a Struct end return all_leaders_with_rank end end How must I modify the code so that the correct rank is returned, and not just the value of the index position?

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  • how to sort xml data in jQuery

    - by pixeltocode
    how can i sort all officers based on their ranks jQuery $.get('officers.xml', function(grade){ $(grade).find('officer').each(function(){ var $rank = $(this).attr('rank'); }); }); XML (officer.xml) <grade> <officer rank="2"></student> <officer rank="3"></student> <officer rank="1"></student> </grade> thanks.

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  • Zend Framework Db Select Join table help

    - by tester2001
    I have this query: SELECT g.title, g.asin, g.platform_id, r.rank FROM games g INNER JOIN ranks r ON ( g.id = r.game_id ) ORDER BY r.rank DESC LIMIT 5` Now, this is my JOIN using Zend_Db_Select but it gives me array error $query = $this-select(); $query-from(array('g' = 'games'), array()); $query-join(array('r' = 'ranks'), 'g.id = r.game_id', array('g.title', 'g.asin', 'g.platform_id', 'r.rank')); $query-order('r.rank DESC'); $query-limit($top); $resultRows = $this-fetchAll($query); return $resultRows; Anyone know what I could be doing wrong? I want to get all the columns in 'games' to show and the 'rank' column in the ranks table.

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  • Optimise & improve performance of this MYSQL query

    - by David
    SELECT u.id, u.honour, COUNT(*) + 1 AS rank FROM user_info u INNER JOIN user_info u2 ON u.honour < u2.honour WHERE u.id = '$id' AND u2.status = 'Alive' AND u2.rank != '14' This query is currently utterly raping my server. It works out based on your honour what rank you are within the 'user_info' table which stores it out of all our users. Screenshot for explain. http://cl.ly/370z0v2Y3v2X1t1r1k2A SELECT u.id, u.honour, COUNT(*)+1 as rank FROM user_info u USE INDEX (prestigeOptimiser) INNER JOIN user_info u2 ON u.honour < u2.honour WHERE u.id='3' AND u2.status='Alive' AND u2.rank!='14'

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  • How to ORDER BY non-column field?

    - by Phil Bolduc
    I am trying to create an Entity SQL that is a union of two sub-queries. (SELECT VALUE DISTINCT ROW(e.ColumnA, e.ColumnB, 1 AS Rank) FROM Context.Entity AS E WHERE ...) UNION ALL (SELECT VALUE DISTINCT ROW(e.ColumnA, e.ColumnB, 2 AS Rank) FROM Context.Entity AS E WHERE ...) ORDER BY *??* LIMIT 50 I have tried: ORDER BY Rank and ORDER BY e.Rank but I keep getting: System.Data.EntitySqlException: The query syntax is not valid. Near keyword 'ORDER' I do not think it is a problem with the Rank column. I do think it is how I am trying to apply an order by to two different esql statements joined by union all. Could someone suggest: How to apply a ORDER BY to this kind of UNION/UNION ALL statment How to order by the non-entity column expression. Thanks.

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  • Beginner WPF/XML question: How to get an <element> in an <element>?

    - by Niels
    I have a rather simple question. I'm trying to get information out of an XML file, and now I need to get the that's inside another This is my XML code: <author> <name>Random_name1 (Random Name)</name> <uri>http://thisisanrandomurl.com</uri> </author> I can get the info with this code: Name = item.Element(ns + "author").Value, But this gives me: "Random_name1 (Random Name) http://thisisanrandomurl.com" I only want the info inside the tags. Any ideas? Thanks a lot, - Niels

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  • Problem with Python 3.1(syntax error). Im a beginner please help!

    - by Jonathan
    Hi there, im new to pragraming :) I got a problem with sytax error while making a guessing game. the problem is in (if Gender = boy or Boy), the equal(=) letter is a syntax error. Please help! Answer = 23 Guess = () Gender = input("Are you a boy, a girl or an alien? ") if Gender = boy or Boy: print("Nice!", Gender) if Gender = girl or Girl: print("Prepare do die!", Gender) if Gender = alien or Alien: print("AWESOME my", Gender, "Friend!") While Guess != Answer: if Guess < Answer: print("Too low! try again") else: print("too high!" print("Congratulations you guessed correct!", Gender, "Have fun!" Thank

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  • Issues loading Jquery (Galleria) script from inside an i-frame (beginner javascript?)

    - by 103188530284789248582
    Hello, first of all - I'm not entirely new to javascript, but am not fluent in it as I am with html and css, and am especially new to jQuery... so please excuse me if this questions seems easy or obvious, but after days of google I still have no solution to the problem... using jQuery 1.4.2.min, jQuery-ui-1.8.1 .... the site in question: http://homecapture.ca/sets/project_index.html The scenario: I have a tabbed menu generated from an unordered list, when a menu item is clicked it reveals an iframe which links to the page containing an image gallery. I am using jQuery UI tabs for the tabbed menu, and the galleries to which I'm linking are jQuery Galleria pages, automatically generated with Jalbum. The problem: The galleria plug-in only works normally from inside of the containing iframe in Chrome, has inconsistent behaviour in IE8 (seems to work in my local copy, but won't load properly online), and is not loaded properly in Firefox. Instead of displaying a thumbnail area and the first large image, the Galleria page shows the first thumbnail only, then when it is clicked the image it links to, but if you right-click and go Back, the iframe content shows up as a properly rendered Galleria page. Jalbum generates more script in the < head of the page in addition to linking to jquery and the galleria plug-in. All of it seems to be in charge of the gallery navigation , and I have relocated it to the < body of the page, in an effort to make it load after the parent page scripts, and together with the gallery content. At this point I am not sure what else I could do to solve the problem, without digging around in all or some of the library and pluging .js files (which I am not knowledgeable enough to do without some pointers). Has anyone dealt with a similar issue? I'm seeing some solutions for manipulating iframe content from a parent page with jQuery on here, is that what I should be researching instead? Thanks in advance for all the help! ps. I tried posting some code, but it seems I do not have enough 'reputation' for things to work right on here either :)

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  • So many technologies to choose from. Where does the beginner start?

    - by Sahat
    WPF Silverlight Windows phone 7 w/ Silverlight iPhone OS w/ Objective-C Cocoa w/ Objective-C ASP.NET Android Facebook FBML HTML5 I will be graduating with B.S. in Computer Science soon and have to decide what do I want to learn from this list. I believe it's better to focus on one thing, master it and build up a portfolio to enhance my resume. Bachelor's Degree with no experience, no portfolio won't do me any good. It won't get me a job by itself. I need to have something that will greatly boost my resume. What would it be? iPhone development? ASP.NET web development? Facebook development? Or completely something else that I haven't listed? I understand it's natural for silverlight developers to say "Learn Silverlight", and iPhone developers say "Learn iPhone SDK and Objective-C". So please try to give a constructive, non-biased, non-objective opinion on which technology should I focus on. Please don't close the topic for "subjective/argumentative" reasons. I am just looking for some guidance.

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  • Beginner problem / error with ansi-c and gcc under ubuntu.

    - by Framester
    Hi, I am just starting programming ansi c with gcc under ubuntu (9.04). I get following error messages: error messages: main.c:6: error: expected identifier or ‘(’ before ‘/’ token In file included from /usr/include/stdio.h:75, from main.c:9: /usr/include/libio.h:332: error: expected specifier-qualifier-list before ‘size_t’ /usr/include/libio.h:364: error: expected declaration specifiers or ‘...’ before ‘size_t’ /usr/include/libio.h:373: error: expected declaration specifiers or ‘...’ before ‘size_t’ /usr/include/libio.h:493: error: expected ‘=’, ‘,’, ‘;’, ‘asm’ or ‘__attribute__’ before ‘_IO_sgetn’ In file included from main.c:9: /usr/include/stdio.h:314: error: expected declaration specifiers or ‘...’ before ‘size_t’ /usr/include/stdio.h:682: error: expected ‘=’, ‘,’, ‘;’, ‘asm’ or ‘__attribute__’ before ‘fread’ /usr/include/stdio.h:688: error: expected ‘=’, ‘,’, ‘;’, ‘asm’ or ‘__attribute__’ before ‘fwrite’ main.c:12: error: expected identifier or ‘(’ before ‘/’ token I assume it is a very simple problem, maybe in the configuration of ubuntu or gcc. I am new to programming under linux as well. I googled for help and went through a tutorial but could not find an answer. Thank you! code: #include <stdio.h> #include <math.h> int main() { printf("TestOutput\n"); return (0); } command: ~/Documents/projects/Trials$ gcc -Wall -ansi main.c

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  • Where can an absolute beginner of Kohana PHP go to learn how to use it from the ground up?

    - by Sergio Tapia
    Hi guys! I have a month of free time and I've decided to launch my own website. It's going to be big and have dymanic content where different users with different roles can perform modifications to the site. Place comments, rate stores, list items, etc. This sound like a perfect opportunity for me to expand my horizons and learn a PHP Framework. I've used PHP bare bones before but nothing too complex. As of now, do you think Kohana is a mature framework to use? I've used Zend in the past for a course in Uni but it sucked horribly, I was new to the MVC model, but Zend had pretty much zero workable tutorials and guides for newbies. That's why I hated it. Where can I go to learn how to use Kohana from a retarded starting point? Thank you very much for your time.

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  • Beginner Question: For extract a large subset of a table from MySQL, how does Indexing, order of tab

    - by chongman
    Sorry if this is too simple, but thanks in advance for helping. This is for MySQL but might be relevant for other RDMBSs tblA has 4 columns: colA, colB, colC, mydata, A_id It has about 10^9 records, with 10^3 distinct values for colA, colB, colC. tblB has 3 columns: colA, colB, B_id It has about 10^4 records. I want all the records from tblA (except the A_id) that have a match in tblB. In other words, I want to use tblB to describe the subset that I want to extract and then extract those records from tblA. Namely: SELECT a.colA, a.colB, a.colC, a.mydata FROM tblA as a INNER JOIN tblB as b ON a.colA=b.colA a.colB=b.colB ; It's taking a really long time (more than an hour) on a newish computer (4GB, Core2Quad, ubuntu), and I just want to check my understanding of the following optimization steps. ** Suppose this is the only query I will ever run on these tables. So ignore the need to run other queries. Now my questions: 1) What indexes should I create to optimize this query? I think I just need a multiple index on (colA, colB) for both tables. I don't think I need separate indexes for colA and colB. Another stack overflow article (that I can't find) mentioned that when adding new indexes, it is slower when there are existing indexes, so that might be a reason to use the multiple index. 2) Is INNER JOIN correct? I just want results where a match is found. 3) Is it faster if I join (tblA to tblB) or the other way around, (tblB to tblA)? This previous answer says that the optimizer should take care of that. 4) Does the order of the part after ON matter? This previous answer say that the optimizer also takes care of the execution order.

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  • Jquery Basic Beginner Question: How do i make my function reusable?

    - by obikodi
    I have spent the last few hours attempting to do this on my own, and using Google to find a solution but to no avail. So if you can help out i would super appreciate it! Basically I have a page which has 3 separate biographies in 'preview mode', which shows only the first paragraph of each bio. When you click on 'read more' for one bio it opens up the 'full mode'. What is happening at the moment, is if i click on one 'read more' link, it opens up the full mode on all 3 bio's. How do i edit the following code so; It only opens the full mode bio of the link i click on Make it reusable so i don't have to duplicate the code 3 times for each bio $("a#btnReadMore").click(function(){ $('.readMoreSlider').slideToggle("fast"); $(this).toggleClass("readMoreSliderActive"); return false; }); Thanks for your help!

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  • PHP Beginner: How to pass PHP variable from one PHP code segment to another ?

    - by Misha Moroshko
    I have index.php which uploads a file to server and sets several PHP variables (like $target_folder_and_file_name). index.php also has the following line (it was originally index.html): <script language="JavaScript" src="main.js.php"></script> After index.php returned to the browser, the browsers asks for main.js.php from the server (right?). Can I access somehow $target_folder_and_file_name from the PHP code in main.js.php ?

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  • Fluent NHibernate beginner problem: How to convert single column data to custom class?

    - by Stefan Ahlm
    I am very new to Fluent NHibernate and I have a problem that I cant find the answer to. I have a string column in my database table, containing a mathematical expression i.e: "10 + 15 * 5". On my entity I have a property that I call Formula and this returns a class that contains the mathematical "formula" (not as a string). I beleive this post http://intellect.dk/post/Implementing-custom-types-in-nHibernate.aspx explains how to solve it for NHibernate. But I am not sure... How do I get this working with Fluent NHibernate?

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  • Beginner, learning as I go - how to get C#/SQLite db set up and ready for testing?

    - by ChrisC
    I've messed with Access a little bit in the past, had one class on OO theory, and one class on console c++ apps. Now, as a hobby project, I'm undertaking to write an actual app, which will be a database app using System.Data.SQLite and C#. I have the db's table structure planned. I have System.Data.SQLite installed and connected to VS Pro. I entered my tables and columns in VS, but that's where I'm stuck. I really don't know how to finish the db set up so I can start creating queries and testing the db structure. Can someone give me guidance to online resources that will help me learn how to get the db properly set up so I can proceed with testing it? I'm hoping for online resources specific to beginners using C# and System.Data.SQLite, but I'll use the closest I can get. Thanks.

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  • JSP - Beginner question , Bypass the if..statement on page load?

    - by TatMing
    i am new in JSP,i have some problem with the following code : <%@ page contentType="text/html;charset=Big5" %> <html> <head> <title></title> </head> <body> <form method="post" action="InsertStudent.jsp"> <input type="text" size="20" name="txtName" /> <input type="text" size="20" name="txtDob" /> <input type="text" size="20" name="txtProStudied" /> <input type="submit" name="B1" value="Submit" /> </form> <% if (request.getParameter("txtName") !="" && request.getParameter("txtDob") != "" && request.getParameter("txtProStudied") != "" ) { out.println("...bypass the if....statement"); } %> </body> </html> If run this code, the out.println will fire even the 3 input box have value or not..

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