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  • preg_replace, exact opposite of a preg_match

    - by SoLoGHoST
    I need to do a preg_replace for the exact opposite of this preg_match regular expression: preg_match('#^(\w+/){0,2}\w+\.\w+$#', $string); So I need to replace all strings that are not valid with an empty string - '' So it needs to remove the first / and last / if found, and all non-valid characters, that is the only valid characters are A-Z, a-z, 0-9, _, ., and / (if it's not the first or last characters of the string). How can I accomplish this with the preg_replace? Thanks :)

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  • RegularExpression Validator doesn't display error message.

    - by Rudi Ramey
    I have a regular expression validation control initialized to validate a textbox control. I want users to be able to enter U.S. Currency values ($12,115.85 or 1500.22 etc.). I found a regular expression off of regexlib website that does the trick. The validation control seems to be working except for one crucial thing. If invalid data is entered, the validation text dispalys (a red "*" next to the textbox), but the page will still submit and the error message won't pop up... I thought that the error message is supposed to display and the page won't submit if the validation control detects invalid data. Isn't this automatic with ASP .NET? I have searched extensively on how to create validation controls, but haven't found anything different than what I am already doing. Can anyone tell me what I am doing wrong here? <asp:TextBox ID="txtActualCost" runat="server" Width="120px" CausesValidation="true"></asp:TextBox> <asp:RegularExpressionValidator ID="regExValActualCost" ControlToValidate="txtActualCost" Text="*" ValidationExpression="^\$?(\d{1,3}(\,\d{3})*|(\d+))(\.\d{2})?$" ErrorMessage="Please enter a valid currency value for 'Actual Cost'" Display="Dynamic" EnableClientScript="true" runat="server" />

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  • How to sort output of "s3cmd ls"

    - by dba.in.ua
    Amazon "s3cmd ls" takes like this output: 2010-02-20 21:01 1458414588 s3://file.tgz.00 2010-02-20 21:10 1458414527 s3://file.tgz.01 2010-02-20 22:01 1458414588 s3://file.tgz.00 2010-02-20 23:10 1458414527 s3://file.tgz.01 2010-02-20 23:20 1458414588 s3://file.tgz.02 How to select all files of archive, ending at 0 ... X, with the latest date of fileset ? Bash, regexp ? Thanx!

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  • Parse string with bash and extract number

    - by cleg
    Hello I've got supervisor's status output, looking like this. frontend RUNNING pid 16652, uptime 2:11:17 nginx RUNNING pid 16651, uptime 2:11:17 redis RUNNING pid 16607, uptime 2:11:32 I need to extract nginx's PID. I've done it via grep -P command, but on remote machine grep is build without perl regular expression support. Looks like sed or awk is exactly what I need, but I don't familiar with them. Please help me to find a way how to do it, thanks in advance.

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  • python search replace using wildcards

    - by tom smith
    hi somewhat confused.. but trying to do a search/repace using wildcards if i have something like: <blah.... ssf ff> <bl.... ssf dfggg ff> <b.... ssf ghhjj fhf> and i want to replace all of the above strings with say, <hh >t any thoughts/comments on how this can be accomplished? thanks update (thanks for the comments!) i'm missing something... my initial sample text are: Soo Choi</span>LONGEDITBOX">Apryl Berney Soo Choi</span>LONGEDITBOX">Joel Franks Joel Franks</span>GEDITBOX">Alexander Yamato and i'm trying to get Soo Choi foo Apryl Berney Soo Choi foo Joel Franks Joel Franks foo Alexander Yamato i've tried derivations of name=re.sub("</s[^>]*\">"," foo ",name) but i'm missing something... thoughts... thanks

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  • rename files with the same name

    - by snorpey
    Hi. I use the following function to rename thumbnails. For example, if I upload a file called "image.png" to an upload folder, and this folder already has a file named "image.png" in it, the new file automatically gets renamed to "image-copy-1.png". If there also is a file called "image-copy-1.png" it gets renamed to "image-copy-2.png" and so on. The following function returns the new filename. At least that's what it is supposed to do... The renaming doesn't seeem to work correctly, though. Sometimes it produces strange results, like: 1.png 1-copy-1.png 1-copy-2.png 1-copy-2-copy-1.png 1-copy-2-copy-3.png I hope you understand my problem, despite my description being somewhat complex... Can you tell me what went wrong here? (bonus question: Is regular expressions the right tool for doing this kind of stuff?) <?php function renameDuplicates($path, $file) { $fileName = pathinfo($path . $file, PATHINFO_FILENAME); $fileExtension = "." . pathinfo($path . $file, PATHINFO_EXTENSION); if(file_exists($path . $file)) { $fileCopy = $fileName . "-copy-1"; if(file_exists($path . $fileCopy . $fileExtension)) { if ($contains = preg_match_all ("/.*?(copy)(-)(\\d+)/is", $fileCopy, $matches)) { $copyIndex = $matches[3][0]; $fileName = substr($fileCopy, 0, -(strlen("-copy-" . $copyIndex))) . "-copy-" . ($copyIndex + 1); } } else { $fileName .= "-copy-1"; } } $returnValue = $fileName . $fileExtension; return $returnValue; }?>

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  • django urls.py regex isn't working

    - by Phil
    This is for Django 1.2.5 and Python 2.7 on Wamp Server running apache version 2.2.17. My problem is that the my URLConf in urls.py isn't redirecting, it's just throwing a 404 error. urls.py: from django.conf.urls.defaults import * # Uncomment the next two lines to enable the admin: #from django.contrib import admin #admin.autodiscover() urlpatterns = patterns('', (r'^app/$', include('app.views.index')), # Uncomment the admin/doc line below to enable admin documentation: #(r'^admin/doc/', include('django.contrib.admindocs.urls')), # Uncomment the next line to enable the admin: #(r'^admin/', include(admin.site.urls)), ) views.py from django.http import HttpResponse def index(request): return HttpResponse("Hello World") I'm getting the following error: ImportError at /app/ No module named index I'm stumped as I'm only learning Django, can anybody see something wrong with my code? Here's my PythonPath: ['C:\Windows\system32\python27.zip', 'C:\Python27\Lib', 'C:\Python27\DLLs', 'C:\Python27\Lib\lib-tk', 'C:\wamp\bin\apache\Apache2.2.17', 'C:\wamp\bin\apache\apache2.2.17\bin', 'C:\Python27', 'C:\Python27\lib\site-packages', 'c:\wamp\www\seetwo']

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  • Regular expression for checking website url

    - by Linto davis
    I need to check the web address, using regular expression. if user type url as www.test.com http://www.test.com https://www.test.com i have a regular expression like /^(http\:\/\/[a-zA-Z0-9_-]+(?:.[a-zA-Z0-9_-]+)*.[a-zA-Z]{2,4}(?:\/[a-zA-Z0-9_]+)*(?:\/[a-zA-Z0-9_]+.[a-zA-Z]{2,4}(?:\?[a-zA-Z0-9_]+\=[a-zA-Z0-9_]+)?)?(?:\&[a-zA-Z0-9_]+\=[a-zA-Z0-9_]+)*)$/ but it will only allow the second option only. how can i modify the regular expression so that , it should accept 1st and 3rd option too

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  • Splitting a string according to a delimiter when elements in the string can contain the delimiter

    - by Vivin Paliath
    I have a string that looks like this: "#Text() #SomeMoreText() #TextThatContainsDelimiter(#blah) #SomethingElse()" I'd like to get back [#Text(), #SomeMoreText(), #TextThatContainsDelimiter(#blah), #SomethingElse()] One way I thought about doing this was to require that the # to be escaped into \#, which makes the input string: "#Text() #SomeMoreText() #TextThatContainsDelimiter(\#blah) #SomethingElse()" I can then split it using /[^\\]#/ which gives me: [#Text(), SomeMoreText, TextThatContainsDelimiter(\#blah), SomethingElse()] The first element will contain # but I can strip it out. However, is there a cleaner way to do this without having to escape the #, and which ensures that the first element will not contain a #? Basically I'd like it to split by # only if the # is not enclosed by parentheses. My hunch is that since the # is context-sensitive and and regular expressions are only suited for context-free strings, this may not be the right tool. If so, would I have to write a grammar for this and roll my own parser/lexer?

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  • Regular expressions and the question mark

    - by James P.
    I'm having trouble finding a regular expression that matches the following String. Korben;http://feeds.feedburner.com/KorbensBlog-UpgradeYourMind?format=xml;1 One problem is escaping the question mark. Java's pattern matcher doesn't seem to accept \? as a valid escape sequence but it also fails to work with the tester at myregexp.com. Here's what I have so far: ([a-zA-Z0-9])+;http://([a-zA-Z0-9./-]+);[0-9]+ Any suggestions?

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  • Wanted: a very simple java RegExp API

    - by itsadok
    I'm tired of writing Pattern p = Pattern.compile(... Matcher m = p.matcher(str); if (m.find()) { ... Over and over again in my code. I was going to write a helper class to make it neater, but I then I wondered: is there a library that tries to provide a simpler facade for Regular Expressions in Java? I'm thinking something in the style of commons-lang and Guava.

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  • Determining whether values can potentially match a regular expression, given more input

    - by Andreas Grech
    I am currently writing an application in JavaScript where I'm matching input to regular expressions, but I also need to find a way how to match strings to parts of the regular expressions. For example: var invalid = "x", potentially = "g", valid = "ggg", gReg = /^ggg$/; gReg.test(invalid); //returns false (correct) gReg.test(valid); //returns true (correct) Now I need to find a way to somehow determine that the value of the potentially variable doesn't exactly match the /^ggg$/ expression, BUT with more input, it potentially can! So for example in this case, the potentially variable is g, but if two more g's are appended to it, it will match the regular expression /^ggg$/ But in the case of invalid, it can never match the /^ggg$/ expression, no matter how many characters you append to it. So how can I determine if a string has or doesn't have potential to match a particular regular expression?

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  • Track results of a regular expression extractor in JMeter

    - by Glenn Slaven
    Our server returns a custom 'X-Execution-Time' HTTP response header that returns in miliseconds the time between the server getting a request and our code returning a page, ie how long our code takes to run. I'm using JMeter to do some testing & I'd like to be able to report on this number of over time. I've setup this regular expression extractor: X-Execution-Time:\s(\d+) but I don't know how to get JMeter to report on this number per request so i can get a trend over time

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  • format string (postcode) in ruby

    - by noddy
    I need to re-format a list of UK postcodes and have started with the following to strip whitespace and capitalize: postcode.upcase.gsub(/\s/,'') I now need to change the postcode so the new postcode will be in a format that will match the following regexp: ^([A-PR-UWYZ0-9][A-HK-Y0-9][AEHMNPRTVXY0-9]?[ABEHMNPRVWXY0-9]? {1,2}[0-9][ABD-HJLN-UW-Z]{2}|GIR 0AA)$ I would be grateful of any assistance.

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  • How to remove lowercase sentence fragments from text?

    - by Aaron
    Hello: I'm tyring to remove lowercase sentence fragments from standard text files using regular expresions or a simple Perl oneliner. These are commonly referred to as speech or attribution tags, for example - he said, she said, etc. This example shows before and after using manual deletion: Original: "Ah, that's perfectly true!" exclaimed Alyosha. "Oh, do leave off playing the fool! Some idiot comes in, and you put us to shame!" cried the girl by the window, suddenly turning to her father with a disdainful and contemptuous air. "Wait a little, Varvara!" cried her father, speaking peremptorily but looking at them quite approvingly. "That's her character," he said, addressing Alyosha again. "Where have you been?" he asked him. "I think," he said, "I've forgotten something... my handkerchief, I think.... Well, even if I've not forgotten anything, let me stay a little." He sat down. Father stood over him. "You sit down, too," said he. All lower case sentence fragments manually removed: "Ah, that's perfectly true!" "Oh, do leave off playing the fool! Some idiot comes in, and you put us to shame!" "Wait a little, Varvara!" "That's her character," "Where have you been?" "I think," "I've forgotten something... my handkerchief, I think.... Well, even if I've not forgotten anything, let me stay a little." He sat down. Father stood over him. "You sit down, too," I've changed straight quotes " to balanced and tried: ” (...)+[.] Of course, this removes some fragments but deletes some text in balanced quotes and text starting with uppercase letters. [^A-Z] didn't work in the above expression. I realize that it may be impossible to achieve 100% accuracy but any useful expression, perl, or python script would be deeply appreciated. Cheers, Aaron

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  • SoundManager / Jquery / Regular expression : Parse class name before certain character To Get SoundI

    - by j-man86
    So I am trying to access a jquery soundmanager variable from one script (wpaudio.js – from the wp-audio plugin) inside of another (init.js – my own javascript). I am creating an alternate pause/play button higher up on the page and need to resume the current soundID, which is contained as part of a class name in the DOM. Here is the code that creates that class name in wpaudio.js: function wpaButtonCheck() { if (!this.playState || this.paused) jQuery('#' + this.sID + '_play').attr('src', wpa_url + '/wpa_play.png'); else jQuery('#' + this.sID + '_play').attr('src', wpa_url + '/wpa_pause.png'); } Here is the output: where wpa0 would be the sID of the sound I need. My current script in init.js is: $('.mixesSidebar #currentSong .playBtn').toggle(function() { soundManager.pauseAll(); $(this).addClass('paused'); }, function() { soundManager.resumeAll(); $(this).removeClass('paused'); }); I need to change resumeAll to "resume(this.sID)", but I need to somehow store the sID onclick and call it in the above function. Alternately, I think a regular expression that could get the class name of the current play button and either parse the string up to the "_play" or use a trim function to get rid of "_play"– but I'm not sure how to do this. Thanks for your help!

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  • How to create Shared VB Array Initialisors for NerdDinner

    - by David A Gibson
    Hello, I am trying to work my way through the NerdDinner tutorial - and as an exercise I'm converting it to VB as I go. I'm not very far in and after having gotten past the C# Yield statement I'm stuck on Shared VB Array Initialisors. static IDictionary<string, Regex> countryRegex = new Dictionary<string, Regex>() { { "USA", new Regex("^[2-9]\\d{2}-\\d{3}-\\d{4}$")}, { "UK", new Regex("(^1300\\d{6}$)|(^1800|1900|1902\\d{6}$)|(^0[2|3|7|8]{1}[0- 9]{8}$)|(^13\\d{4}$)|(^04\\d{2,3}\\d{6}$)")}, { "Netherlands", new Regex("(^\\+[0-9]{2}|^\\+[0- 9]{2}\\(0\\)|^\\(\\+[0-9]{2}\\)\\(0\\)|^00[0-9]{2}|^0)([0-9]{9}$|[0-9\\- \\s]{10}$)")}, Can anyone please help me write this in VB? Public Shared countryRegex As IDictionary(Of String, Regex) = New Dictionary(Of String, Regex)() {("USA", New Regex("^[2-9]\\d{2}-\\d{3}-\\d{4}$"))} This code has an error as it does not accept the String and the Regex as an item for the array. Thanks

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  • What's a regular language?

    - by Javier Badia
    I've read that you can't parse HTML with regular expressions because HTML is not a regular language. I tried searching Wikipedia, but I didn't understand a word of what the various related articles said. Can someone explain, in simpler terms, what's a regular (or non-regular) language, and why non-regular languages can't be parsed with regexes?

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  • Regular expression replace in PL/pgSQL

    - by dreamlax
    If I have the following input (excluding quotes): "The ancestral territorial imperatives of the trumpeter swan" How can I collapse all multiple spaces to a single space so that the input is transformed to: "The ancestral territorial imperatives of the trumpeter swan" This is going to be used in a trigger function on insert/update (which already trims leading/trailing spaces). Currently, it raises an exception if the input contains multiple adjacent spaces, but I would rather it simply transforms it into something valid before inserting. What is the best approach? I can't seem to find a regular-expression replace function for PL/pgSQL. There is a text_replace function, but this will only collapse at most two spaces down to one (meaning three consecutive spaces will collapse to two). Calling this function over and over is not ideal.

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  • Python re.sub MULTILINE caret match

    - by cdleary
    The Python docs say: re.MULTILINE: When specified, the pattern character '^' matches at the beginning of the string and at the beginning of each line (immediately following each newline)... By default, '^' matches only at the beginning of the string... So what's going on when I get the following unexpected result? >>> import re >>> s = """// The quick brown fox. ... // Jumped over the lazy dog.""" >>> re.sub('^//', '', s, re.MULTILINE) ' The quick brown fox.\n// Jumped over the lazy dog.'

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  • Matching unmatched strings based on a unknown pattern

    - by Polity
    Alright guys, i really hurt my brain over this one and i'm curious if you guys can give me any pointers towards the right direction i should be taking. The situation is this: Lets say, i have a collection of strings (let it be clear that the pattern of this strings is unknown. For a fact, i can say that the string contain only signs from the ASCII table and therefore, i dont have to worry about weird Chinese signs). For this example, i take the following collection of strings (note that the strings dont have to make any human sence so dont try figguring them out :)): "[001].[FOO].[TEST] - 'foofoo.test'", "[002].[FOO].[TEST] - 'foofoo.test'", "[003].[FOO].[TEST] - 'foofoo.test'", "[001].[FOO].[TEST] - 'foofoo.test.sample'", "[002].[FOO].[TEST] - 'foofoo.test.sample'", "-001- BAR.[TEST] - 'bartest.xx1", "-002- BAR.[TEST] - 'bartest.xx1" Now, what i need to have is a way of finding logical groups (and subgroups) of these set of strings, so in the above example, just by rational thinking, you can combine the first 3, the 2 after that and the last 2. Also the resulting groups from the first 5 can be combined in one main group with 2 subgroups, this should give you something like this: { { "[001].[FOO].[TEST] - 'foofoo.test'", "[002].[FOO].[TEST] - 'foofoo.test'", "[003].[FOO].[TEST] - 'foofoo.test'", } { "[001].[FOO].[TEST] - 'foofoo.test.sample'", "[002].[FOO].[TEST] - 'foofoo.test.sample'", } { "-001- BAR.[TEST] - 'bartest.xx1", "-002- BAR.[TEST] - 'bartest.xx1" } } Sorry for the layout above but indenting with 4 spaces doesnt seem to work correctly (or im frakk'n it up). Anyways, I'm not sure how to approach this problem (how to get the result desired as indicated above). First of, i thought of creating a huge set of regexes which would parse most known patterns but the amount of different patterns is just to huge that this isn't realistic. Another think i thought of was parsing each indidual word within a string (so strip all non alphabetic or numeric characters and split by those), and if X% matches, i can assume the strings belong to the same group. (where X wil probably be around 80/90). However, i find the area of speculation kinda big. For example, when matching strings with each 20 words, the change of hitting above 80% is kinda big (that means that 4 words can differ), however when matching only 8 words, 2 words at most can differ. My question to you is, what would be a logical approach in the above situation? Thanks in advance!

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  • Matching a date in perl

    - by Zerobu
    Hello, I want to match a date in the format day/month/year. where day is two digits month is two digits and year is four digits. Also, I want to check see if it is a valid date, for example knows when is leap year, and know which month has 30days, 31days and 28, or 29 days for Februrary.

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  • how to match all group and subgroup in pcre

    - by mono
    a ip or other string, like "11.22.33.44" or "aa.bb.cc.dd". basically, I think it is very easy, (([\d\w]+)+\.)+[\d\w]+ but the problem is which group these submatches are in. not like ip, some string is consist of lots of words+separate in pcre, I don't know how to extract it all words -- "aa bb cc dd ..."

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