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  • Wanted: a very simple java RegExp API

    - by itsadok
    I'm tired of writing Pattern p = Pattern.compile(... Matcher m = p.matcher(str); if (m.find()) { ... Over and over again in my code. I was going to write a helper class to make it neater, but I then I wondered: is there a library that tries to provide a simpler facade for Regular Expressions in Java? I'm thinking something in the style of commons-lang and Guava.

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  • rename files with the same name

    - by snorpey
    Hi. I use the following function to rename thumbnails. For example, if I upload a file called "image.png" to an upload folder, and this folder already has a file named "image.png" in it, the new file automatically gets renamed to "image-copy-1.png". If there also is a file called "image-copy-1.png" it gets renamed to "image-copy-2.png" and so on. The following function returns the new filename. At least that's what it is supposed to do... The renaming doesn't seeem to work correctly, though. Sometimes it produces strange results, like: 1.png 1-copy-1.png 1-copy-2.png 1-copy-2-copy-1.png 1-copy-2-copy-3.png I hope you understand my problem, despite my description being somewhat complex... Can you tell me what went wrong here? (bonus question: Is regular expressions the right tool for doing this kind of stuff?) <?php function renameDuplicates($path, $file) { $fileName = pathinfo($path . $file, PATHINFO_FILENAME); $fileExtension = "." . pathinfo($path . $file, PATHINFO_EXTENSION); if(file_exists($path . $file)) { $fileCopy = $fileName . "-copy-1"; if(file_exists($path . $fileCopy . $fileExtension)) { if ($contains = preg_match_all ("/.*?(copy)(-)(\\d+)/is", $fileCopy, $matches)) { $copyIndex = $matches[3][0]; $fileName = substr($fileCopy, 0, -(strlen("-copy-" . $copyIndex))) . "-copy-" . ($copyIndex + 1); } } else { $fileName .= "-copy-1"; } } $returnValue = $fileName . $fileExtension; return $returnValue; }?>

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  • Parse string with bash and extract number

    - by cleg
    Hello I've got supervisor's status output, looking like this. frontend RUNNING pid 16652, uptime 2:11:17 nginx RUNNING pid 16651, uptime 2:11:17 redis RUNNING pid 16607, uptime 2:11:32 I need to extract nginx's PID. I've done it via grep -P command, but on remote machine grep is build without perl regular expression support. Looks like sed or awk is exactly what I need, but I don't familiar with them. Please help me to find a way how to do it, thanks in advance.

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  • SoundManager / Jquery / Regular expression : Parse class name before certain character To Get SoundI

    - by j-man86
    So I am trying to access a jquery soundmanager variable from one script (wpaudio.js – from the wp-audio plugin) inside of another (init.js – my own javascript). I am creating an alternate pause/play button higher up on the page and need to resume the current soundID, which is contained as part of a class name in the DOM. Here is the code that creates that class name in wpaudio.js: function wpaButtonCheck() { if (!this.playState || this.paused) jQuery('#' + this.sID + '_play').attr('src', wpa_url + '/wpa_play.png'); else jQuery('#' + this.sID + '_play').attr('src', wpa_url + '/wpa_pause.png'); } Here is the output: where wpa0 would be the sID of the sound I need. My current script in init.js is: $('.mixesSidebar #currentSong .playBtn').toggle(function() { soundManager.pauseAll(); $(this).addClass('paused'); }, function() { soundManager.resumeAll(); $(this).removeClass('paused'); }); I need to change resumeAll to "resume(this.sID)", but I need to somehow store the sID onclick and call it in the above function. Alternately, I think a regular expression that could get the class name of the current play button and either parse the string up to the "_play" or use a trim function to get rid of "_play"– but I'm not sure how to do this. Thanks for your help!

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  • RegularExpression Validator doesn't display error message.

    - by Rudi Ramey
    I have a regular expression validation control initialized to validate a textbox control. I want users to be able to enter U.S. Currency values ($12,115.85 or 1500.22 etc.). I found a regular expression off of regexlib website that does the trick. The validation control seems to be working except for one crucial thing. If invalid data is entered, the validation text dispalys (a red "*" next to the textbox), but the page will still submit and the error message won't pop up... I thought that the error message is supposed to display and the page won't submit if the validation control detects invalid data. Isn't this automatic with ASP .NET? I have searched extensively on how to create validation controls, but haven't found anything different than what I am already doing. Can anyone tell me what I am doing wrong here? <asp:TextBox ID="txtActualCost" runat="server" Width="120px" CausesValidation="true"></asp:TextBox> <asp:RegularExpressionValidator ID="regExValActualCost" ControlToValidate="txtActualCost" Text="*" ValidationExpression="^\$?(\d{1,3}(\,\d{3})*|(\d+))(\.\d{2})?$" ErrorMessage="Please enter a valid currency value for 'Actual Cost'" Display="Dynamic" EnableClientScript="true" runat="server" />

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  • Regular expressions and the question mark

    - by James P.
    I'm having trouble finding a regular expression that matches the following String. Korben;http://feeds.feedburner.com/KorbensBlog-UpgradeYourMind?format=xml;1 One problem is escaping the question mark. Java's pattern matcher doesn't seem to accept \? as a valid escape sequence but it also fails to work with the tester at myregexp.com. Here's what I have so far: ([a-zA-Z0-9])+;http://([a-zA-Z0-9./-]+);[0-9]+ Any suggestions?

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  • python search replace using wildcards

    - by tom smith
    hi somewhat confused.. but trying to do a search/repace using wildcards if i have something like: <blah.... ssf ff> <bl.... ssf dfggg ff> <b.... ssf ghhjj fhf> and i want to replace all of the above strings with say, <hh >t any thoughts/comments on how this can be accomplished? thanks update (thanks for the comments!) i'm missing something... my initial sample text are: Soo Choi</span>LONGEDITBOX">Apryl Berney Soo Choi</span>LONGEDITBOX">Joel Franks Joel Franks</span>GEDITBOX">Alexander Yamato and i'm trying to get Soo Choi foo Apryl Berney Soo Choi foo Joel Franks Joel Franks foo Alexander Yamato i've tried derivations of name=re.sub("</s[^>]*\">"," foo ",name) but i'm missing something... thoughts... thanks

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  • What's a regular language?

    - by Javier Badia
    I've read that you can't parse HTML with regular expressions because HTML is not a regular language. I tried searching Wikipedia, but I didn't understand a word of what the various related articles said. Can someone explain, in simpler terms, what's a regular (or non-regular) language, and why non-regular languages can't be parsed with regexes?

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  • Regular expression to match maximium of five words.

    - by KhanS
    I have a regular expression ^[a-zA-Z+#-.0-9]{1,5}$ which validates that the word contains alpha-numeric characters and few special characters and length should not be more than 5 characters. How do I make this regular expression to accept a maximum of five words matching the above regular expression.

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  • perl escaping \n or \t

    - by Michael
    I need to escape \n so on output I really get newline or tab $ perl -p -e 's/e/a/ge' now I want each e to be substituted with \n $ perl -p -e 's/e/\n/ge' but even \n gives me an error. this was a simplified example. In real script(makefile) I have substitute := perl -p -e 's/@([^@]+)@/defined $$ENV{$$1} ? $$ENV{$$1} : $$1/ge' and in target I have such a nice command $(substitute) $< > $@ and if the input file for perl contains \n at output I will see it literally... I want to have real newline.

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  • Use regular expressions to match an ? but not a \?

    - by J.Milly
    I have a PHP regular expression that has been functioning fairly well to parse some odd legacy client templates until recently when we found an escaped question mark (\?) included in a template expression. I'm not strong enough with my regular expression-fu to wrap my feeble noodle around a negative look ahead or some techno-mumbo-jumbo so, tips or points in the right direction would be greatly appreciated. My PHP: preg_match_all("/\{\{IF (.*)\?(.*):(.*)\}\}/U", $template, $m, PREG_SET_ORDER);

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  • SoundManager / Jquery : Get SoundID sID

    - by j-man86
    So I am trying to access a jquery soundmanager variable from one script (wpaudio.js – from the wp-audio plugin) inside of another (init.js – my own javascript). I am creating an alternate pause/play button higher up on the page and need to resume the current soundID, which is contained as part of a class name in the DOM. Here is the code that creates that class name in wpaudio.js: function wpaButtonCheck() { if (!this.playState || this.paused) jQuery('#' + this.sID + '_play').attr('src', wpa_url + '/wpa_play.png'); else jQuery('#' + this.sID + '_play').attr('src', wpa_url + '/wpa_pause.png'); } Here is the output: <img src="http://24.232.185.173/wordpress/wp-content/plugins/wpaudio-mp3-player/wpa_play.png" class="wpa_play" id="wpa0_play"> where wpa0 would be the sID of the sound I need. My current script in init.js is: $('.mixesSidebar #currentSong .playBtn').toggle(function() { soundManager.pauseAll(); $(this).addClass('paused'); }, function() { soundManager.resumeAll(); $(this).removeClass('paused'); }); I need to change resumeAll to "resume(this.sID)", but I need to somehow store the sID onclick and call it in the above function. Alternately, I think a regular expression that could get the class name of the current play button and either parse the string up to the "_play" or use a trim function to get rid of "_play"– but I'm not sure how to do this. Thanks for your help!

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  • how to match all group and subgroup in pcre

    - by mono
    a ip or other string, like "11.22.33.44" or "aa.bb.cc.dd". basically, I think it is very easy, (([\d\w]+)+\.)+[\d\w]+ but the problem is which group these submatches are in. not like ip, some string is consist of lots of words+separate in pcre, I don't know how to extract it all words -- "aa bb cc dd ..."

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  • Warning: preg_match() [function.preg-match]: Unknown modifier '/' problem

    - by SonOfOmer
    I am building custom implementation of php MVC routing engine, and I have custom routes like one in $routes array below. Each time when I send asynchronous GET request like xmlhttp.open("GET","someurl"); I get following message Warning: preg_match() [function.preg-match]: Unknown modifier '/' problem but with synchronous (normal) request it all works fine <?php $routes = array( array('url' => '/^someurl$/', 'controller' => 'somecontroller', 'view' => 'someview') ); $url = $_SERVER['REQUEST_URI']; $url = substr( $url, 1 ); $params = array(); $route_match = false; foreach($routes as $urls => $route) { if(preg_match($route['url'], $url, $matches)) { $params = array_merge($params, $matches); $route_match = true; break; } } require_once(CONTROLLER_PATH.$route['controller'].'.php'); ?> string(11) "/^someurl$/" is the result of var_dump($route['url']); Thanks.

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  • How to sort output of "s3cmd ls"

    - by dba.in.ua
    Amazon "s3cmd ls" takes like this output: 2010-02-20 21:01 1458414588 s3://file.tgz.00 2010-02-20 21:10 1458414527 s3://file.tgz.01 2010-02-20 22:01 1458414588 s3://file.tgz.00 2010-02-20 23:10 1458414527 s3://file.tgz.01 2010-02-20 23:20 1458414588 s3://file.tgz.02 How to select all files of archive, ending at 0 ... X, with the latest date of fileset ? Bash, regexp ? Thanx!

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  • How to create Shared VB Array Initialisors for NerdDinner

    - by David A Gibson
    Hello, I am trying to work my way through the NerdDinner tutorial - and as an exercise I'm converting it to VB as I go. I'm not very far in and after having gotten past the C# Yield statement I'm stuck on Shared VB Array Initialisors. static IDictionary<string, Regex> countryRegex = new Dictionary<string, Regex>() { { "USA", new Regex("^[2-9]\\d{2}-\\d{3}-\\d{4}$")}, { "UK", new Regex("(^1300\\d{6}$)|(^1800|1900|1902\\d{6}$)|(^0[2|3|7|8]{1}[0- 9]{8}$)|(^13\\d{4}$)|(^04\\d{2,3}\\d{6}$)")}, { "Netherlands", new Regex("(^\\+[0-9]{2}|^\\+[0- 9]{2}\\(0\\)|^\\(\\+[0-9]{2}\\)\\(0\\)|^00[0-9]{2}|^0)([0-9]{9}$|[0-9\\- \\s]{10}$)")}, Can anyone please help me write this in VB? Public Shared countryRegex As IDictionary(Of String, Regex) = New Dictionary(Of String, Regex)() {("USA", New Regex("^[2-9]\\d{2}-\\d{3}-\\d{4}$"))} This code has an error as it does not accept the String and the Regex as an item for the array. Thanks

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  • preg_replace, exact opposite of a preg_match

    - by SoLoGHoST
    I need to do a preg_replace for the exact opposite of this preg_match regular expression: preg_match('#^(\w+/){0,2}\w+\.\w+$#', $string); So I need to replace all strings that are not valid with an empty string - '' So it needs to remove the first / and last / if found, and all non-valid characters, that is the only valid characters are A-Z, a-z, 0-9, _, ., and / (if it's not the first or last characters of the string). How can I accomplish this with the preg_replace? Thanks :)

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  • How to remove lowercase sentence fragments from text?

    - by Aaron
    Hello: I'm tyring to remove lowercase sentence fragments from standard text files using regular expresions or a simple Perl oneliner. These are commonly referred to as speech or attribution tags, for example - he said, she said, etc. This example shows before and after using manual deletion: Original: "Ah, that's perfectly true!" exclaimed Alyosha. "Oh, do leave off playing the fool! Some idiot comes in, and you put us to shame!" cried the girl by the window, suddenly turning to her father with a disdainful and contemptuous air. "Wait a little, Varvara!" cried her father, speaking peremptorily but looking at them quite approvingly. "That's her character," he said, addressing Alyosha again. "Where have you been?" he asked him. "I think," he said, "I've forgotten something... my handkerchief, I think.... Well, even if I've not forgotten anything, let me stay a little." He sat down. Father stood over him. "You sit down, too," said he. All lower case sentence fragments manually removed: "Ah, that's perfectly true!" "Oh, do leave off playing the fool! Some idiot comes in, and you put us to shame!" "Wait a little, Varvara!" "That's her character," "Where have you been?" "I think," "I've forgotten something... my handkerchief, I think.... Well, even if I've not forgotten anything, let me stay a little." He sat down. Father stood over him. "You sit down, too," I've changed straight quotes " to balanced and tried: ” (...)+[.] Of course, this removes some fragments but deletes some text in balanced quotes and text starting with uppercase letters. [^A-Z] didn't work in the above expression. I realize that it may be impossible to achieve 100% accuracy but any useful expression, perl, or python script would be deeply appreciated. Cheers, Aaron

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  • Python re.sub MULTILINE caret match

    - by cdleary
    The Python docs say: re.MULTILINE: When specified, the pattern character '^' matches at the beginning of the string and at the beginning of each line (immediately following each newline)... By default, '^' matches only at the beginning of the string... So what's going on when I get the following unexpected result? >>> import re >>> s = """// The quick brown fox. ... // Jumped over the lazy dog.""" >>> re.sub('^//', '', s, re.MULTILINE) ' The quick brown fox.\n// Jumped over the lazy dog.'

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  • best way to parse plain text file with a nested information structure

    - by Beffa
    The text file has hundreds of these entries (format is MT940 bank statement) {1:F01AHHBCH110XXX0000000000}{2:I940X N2}{3:{108:XBS/091502}}{4: :20:XBS/091202/0001 :25:5887/507004-50 :28C:140/1 :60F:C0914CHF7789, :61:0912021202D36,80NTRFNONREF//0887-1202-29-941 04392579-0 LUTHY + xxx, ZUR :86:6034?60LUTHY + xxxx, ZUR vom 01.12.09 um 16:28 Karten-Nr. 2232 2579-0 :62F:C091202CHF52,2 :64:C091302CHF52,2 -} This should go into an Array of Hashes like [{"1"=>"F01AHHBCH110XXX0000000000"}, "2"=>"I940X N2", 3 => {108=>"XBS/091502"} etc. } ] I tried it with tree top, but it seemed not to be the right way, because it's more for something you want to do calculations on, and I just want the information. grammar Mt940 rule document part1:string spaces [:|/] spaces part2:document { def eval(env={}) return part1.eval, part2.eval end } / string / '{' spaces document spaces '}' spaces { def eval(env={}) return [document.eval] end } end end I also tried with a regular expression matches = str.scan(/\A[{]?([0-9]+)[:]?([^}]*)[}]?\Z/i) but it's difficult with recursion ... How can I solve this problem?

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  • Determining whether values can potentially match a regular expression, given more input

    - by Andreas Grech
    I am currently writing an application in JavaScript where I'm matching input to regular expressions, but I also need to find a way how to match strings to parts of the regular expressions. For example: var invalid = "x", potentially = "g", valid = "ggg", gReg = /^ggg$/; gReg.test(invalid); //returns false (correct) gReg.test(valid); //returns true (correct) Now I need to find a way to somehow determine that the value of the potentially variable doesn't exactly match the /^ggg$/ expression, BUT with more input, it potentially can! So for example in this case, the potentially variable is g, but if two more g's are appended to it, it will match the regular expression /^ggg$/ But in the case of invalid, it can never match the /^ggg$/ expression, no matter how many characters you append to it. So how can I determine if a string has or doesn't have potential to match a particular regular expression?

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  • format string (postcode) in ruby

    - by noddy
    I need to re-format a list of UK postcodes and have started with the following to strip whitespace and capitalize: postcode.upcase.gsub(/\s/,'') I now need to change the postcode so the new postcode will be in a format that will match the following regexp: ^([A-PR-UWYZ0-9][A-HK-Y0-9][AEHMNPRTVXY0-9]?[ABEHMNPRVWXY0-9]? {1,2}[0-9][ABD-HJLN-UW-Z]{2}|GIR 0AA)$ I would be grateful of any assistance.

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  • JavaScript String Replace with a tricky regular expression

    - by Juri
    Hi. I'm trying to work out what regular expression I would need to change this string html = '<img style="width: 311px; height: 376px;" alt="test" src="/img/1268749322.jpg" />'; to this html = '<img width="311" height="376" alt="test" src="/img/1268749322.jpg" />'; with the help of Javascript.replace. This is my start: html = html.replace(/ style="width:\?([0-9])px*"/g, "width=\"$1\""); Can anyone help me? THANKS

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