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  • Ruby number_to_currency displays a totally wrong number!

    - by SueP
    Greetings! I’m an old Delphi programmer making the leap to the Mac, Ruby, Rails, and web programming in general. I’m signed up for the Advanced Rails workshop at the end of the month. In the meantime, I’ve been working on porting a mission-critical (of course) app from Delphi to RAILS. It feels like I’ve spent most of the past year with my head buried in a book or podcast. Right now, I’ve hit a major issue and I’m tearing my hair out. I literally don’t know where to go with this, I desperately don’t want to deploy with this bug, and I’m feeling a bit frantic. (The company database is currently running on an ancient XP box that’s looking rustier by the day.) So, I set up a test database that shows the problem. I’m running: OS/X 10.6.3 Rails 2.3.5 ruby 1.8.7 (2009-06-08 patchlevel 173) [universal-darwin10.0] MySQL 5.1.38-log via socket MySQL Client Version 5.1.8 ActiveRecord::Schema.define(:version => 20100406222528) do create_table “money”, :force => true do |t| t.decimal “amount_due”, :precision => 10, :scale => 2, :default => 0.0 t.decimal “balance”, :precision => 10, :scale => 2, :default => 0.0 t.text “memofield” t.datetime “created_at” t.datetime “updated_at” end The index view is right out of the generator, slightly modified to add the formatting that's breaking on me. Listing money <table> <tr> <th>Amount</th> <th>Amount to_s </th> <th>Balance to $</th> <th>Balance with_precision </th> <th>Memofield</th> </tr> <% @money.each do |money| %> <tr> <td><%=h money.amount_due %></td> <td><%=h money.amount_due.to_s(‘F’) %></td> <td><%=h number_to_currency(money.balance) %></td> <td><%=h number_with_precision(money.balance, :precision => 2) %></td> <td><%=h money.memofield %></td> <td><%= link_to ‘Show’, money %></td> <td><%= link_to ‘Edit’, edit_money_path(money) %></td> <td><%= link_to ‘Destroy’, money, :confirm => ‘Are you sure?’, :method => :delete %></td> </tr> *<% end %> *</table> <%= link_to ‘New money’, new_money_path %> This seemed to work pretty well. Then I started testing with production data and hit a major problem with number_to_currency. The number in the database is: 10542.28, I verified it with the MySQL Query Browser. RAILS will display this as 10542.28 unless I call number_to_currency, then that number is displayed as: $15422.80 The error seems to happen with any number between 10,000.00 and 10,999.99 So far, I haven’t seen it outside of that range, but I obviously haven’t tested everything. I guess my workaround is to remove number_to_currency, but that leaves the views looking really sloppy and unprofessional. The formatting is messed up, things don’t line up properly and I can’t force the display to 2 decimal places. I’m seriously hoping there is an easy fix for this. I can’t imagine this being a widespread problem. It would affect so many people that someone would have fixed it! But I don’t know where to go from here. I’d desperately like some help. (Later – number_with_precision fails the same way number_to_currency does.) Sue Petersen

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  • Performance considerations for common SQL queries

    - by Jim Giercyk
    Originally posted on: http://geekswithblogs.net/NibblesAndBits/archive/2013/10/16/performance-considerations-for-common-sql-queries.aspxSQL offers many different methods to produce the same results.  There is a never-ending debate between SQL developers as to the “best way” or the “most efficient way” to render a result set.  Sometimes these disputes even come to blows….well, I am a lover, not a fighter, so I decided to collect some data that will prove which way is the best and most efficient.  For the queries below, I downloaded the test database from SQLSkills:  http://www.sqlskills.com/sql-server-resources/sql-server-demos/.  There isn’t a lot of data, but enough to prove my point: dbo.member has 10,000 records, and dbo.payment has 15,554.  Our result set contains 6,706 records. The following queries produce an identical result set; the result set contains aggregate payment information for each member who has made more than 1 payment from the dbo.payment table and the first and last name of the member from the dbo.member table.   /*************/ /* Sub Query  */ /*************/ SELECT  a.[Member Number] ,         m.lastname ,         m.firstname ,         a.[Number Of Payments] ,         a.[Average Payment] ,         a.[Total Paid] FROM    ( SELECT    member_no 'Member Number' ,                     AVG(payment_amt) 'Average Payment' ,                     SUM(payment_amt) 'Total Paid' ,                     COUNT(Payment_No) 'Number Of Payments'           FROM      dbo.payment           GROUP BY  member_no           HAVING    COUNT(Payment_No) > 1         ) a         JOIN dbo.member m ON a.[Member Number] = m.member_no         /***************/ /* Cross Apply  */ /***************/ SELECT  ca.[Member Number] ,         m.lastname ,         m.firstname ,         ca.[Number Of Payments] ,         ca.[Average Payment] ,         ca.[Total Paid] FROM    dbo.member m         CROSS APPLY ( SELECT    member_no 'Member Number' ,                                 AVG(payment_amt) 'Average Payment' ,                                 SUM(payment_amt) 'Total Paid' ,                                 COUNT(Payment_No) 'Number Of Payments'                       FROM      dbo.payment                       WHERE     member_no = m.member_no                       GROUP BY  member_no                       HAVING    COUNT(Payment_No) > 1                     ) ca /********/                    /* CTEs  */ /********/ ; WITH    Payments           AS ( SELECT   member_no 'Member Number' ,                         AVG(payment_amt) 'Average Payment' ,                         SUM(payment_amt) 'Total Paid' ,                         COUNT(Payment_No) 'Number Of Payments'                FROM     dbo.payment                GROUP BY member_no                HAVING   COUNT(Payment_No) > 1              ),         MemberInfo           AS ( SELECT   p.[Member Number] ,                         m.lastname ,                         m.firstname ,                         p.[Number Of Payments] ,                         p.[Average Payment] ,                         p.[Total Paid]                FROM     dbo.member m                         JOIN Payments p ON m.member_no = p.[Member Number]              )     SELECT  *     FROM    MemberInfo /************************/ /* SELECT with Grouping   */ /************************/ SELECT  p.member_no 'Member Number' ,         m.lastname ,         m.firstname ,         COUNT(Payment_No) 'Number Of Payments' ,         AVG(payment_amt) 'Average Payment' ,         SUM(payment_amt) 'Total Paid' FROM    dbo.payment p         JOIN dbo.member m ON m.member_no = p.member_no GROUP BY p.member_no ,         m.lastname ,         m.firstname HAVING  COUNT(Payment_No) > 1   We can see what is going on in SQL’s brain by looking at the execution plan.  The Execution Plan will demonstrate which steps and in what order SQL executes those steps, and what percentage of batch time each query takes.  SO….if I execute all 4 of these queries in a single batch, I will get an idea of the relative time SQL takes to execute them, and how it renders the Execution Plan.  We can settle this once and for all.  Here is what SQL did with these queries:   Not only did the queries take the same amount of time to execute, SQL generated the same Execution Plan for each of them.  Everybody is right…..I guess we can all finally go to lunch together!  But wait a second, I may not be a fighter, but I AM an instigator.     Let’s see how a table variable stacks up.  Here is the code I executed: /********************/ /*  Table Variable  */ /********************/ DECLARE @AggregateTable TABLE     (       member_no INT ,       AveragePayment MONEY ,       TotalPaid MONEY ,       NumberOfPayments MONEY     ) INSERT  @AggregateTable         SELECT  member_no 'Member Number' ,                 AVG(payment_amt) 'Average Payment' ,                 SUM(payment_amt) 'Total Paid' ,                 COUNT(Payment_No) 'Number Of Payments'         FROM    dbo.payment         GROUP BY member_no         HAVING  COUNT(Payment_No) > 1   SELECT  at.member_no 'Member Number' ,         m.lastname ,         m.firstname ,         at.NumberOfPayments 'Number Of Payments' ,         at.AveragePayment 'Average Payment' ,         at.TotalPaid 'Total Paid' FROM    @AggregateTable at         JOIN dbo.member m ON m.member_no = at.member_no In the interest of keeping things in groupings of 4, I removed the last query from the previous batch and added the table variable query.  Here’s what I got:     Since we first insert into the table variable, then we read from it, the Execution Plan renders 2 steps.  BUT, the combination of the 2 steps is only 22% of the batch.  It is actually faster than the other methods even though it is treated as 2 separate queries in the Execution Plan.  The argument I often hear against Table Variables is that SQL only estimates 1 row for the table size in the Execution Plan.  While this is true, the estimate does not come in to play until you read from the table variable.  In this case, the table variable had 6,706 rows, but it still outperformed the other queries.  People argue that table variables should only be used for hash or lookup tables.  The fact is, you have control of what you put IN to the variable, so as long as you keep it within reason, these results suggest that a table variable is a viable alternative to sub-queries. If anyone does volume testing on this theory, I would be interested in the results.  My suspicion is that there is a breaking point where efficiency goes down the tubes immediately, and it would be interesting to see where the threshold is. Coding SQL is a matter of style.  If you’ve been around since they introduced DB2, you were probably taught a little differently than a recent computer science graduate.  If you have a company standard, I strongly recommend you follow it.    If you do not have a standard, generally speaking, there is no right or wrong answer when talking about the efficiency of these types of queries, and certainly no hard-and-fast rule.  Volume and infrastructure will dictate a lot when it comes to performance, so your results may vary in your environment.  Download the database and try it!

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  • Transpose matrix-style table to 3 columns in Excel

    - by polarbear2k
    I have a matrix-style table in excel where B1:Z1 are column headings and A2:A99 are row headings. I would like to convert this table to a 3 column table (column heading, row heading, cell value). It does not matter in what order the new table is. A B C D A B C A B C 1 H1 H2 H3 1 H1 R1 V1 1 H1 R1 V1 2 R1 V1 V2 V3 => 2 H1 R2 V4 or 2 H2 R1 V2 3 R2 V4 V5 V6 3 H1 R3 V7 3 H3 R1 V3 4 R3 V7 V8 V9 4 H2 R1 V2 4 H1 R2 V4 5 H2 R2 V5 5 H2 R2 V5 6 H2 R3 V8 6 H3 R2 V6 7 H3 R1 V3 7 H1 R3 V7 8 H3 R2 V6 8 H2 R3 V8 9 H3 R3 V9 9 H3 R3 V8 I've been playing around with the OFFSET function to create the whole table but I feel like a combination of TRANSPOSE and V/HLOOKUP is required. Thanks EDIT I have managed to come up with the correct formulas. If the data is in Sheet1 like in my example above, the formulas go in Sheet2: [A1] =IF(ROW() <= COUNTA(Sheet1!$B$1:$Z$1)*COUNTA(Sheet1!$A$2:$A$99), OFFSET(Sheet1!$A$1,0,IF(MOD(ROW(),COUNTA(Sheet1!$B$1:$Z$1))=0,COUNTA(Sheet1!$B$1:$Z$1),MOD(ROW(),COUNTA(Sheet1!$B$1:$Z$1)))),"") [B1] =IF(ROW() <= COUNTA(Sheet1!$B$1:$Z$1)*COUNTA(Sheet1!$A$2:$A$99),OFFSET(Sheet1!$A$1,IF(MOD(ROW(),COUNTA(Sheet1!$A$2:$A$99))=0,COUNTA(Sheet1!$A$2:$A$99),MOD(ROW(),COUNTA(Sheet1!$A$2:$A$99))),0),"") [C1] =IF(ROW() <= COUNTA(Sheet1!$B$1:$Z$1)*COUNTA(Sheet1!$A$2:$A$99),OFFSET(Sheet1!$A$1,IF(MOD(ROW(),COUNTA(Sheet1!$A$2:$A$99))=0,COUNTA(Sheet1!$A$2:$A$99),MOD(ROW(),COUNTA(Sheet1!$A$2:$A$99))),IF(MOD(ROW(),COUNTA(Sheet1!$B$1:$Z$1))=0,COUNTA(Sheet1!$B$1:$Z$1),MOD(ROW(),COUNTA(Sheet1!$B$1:$Z$1)))),"") The formulas are limited to B1:Z1 for the headings and A2:A99 for the rows (these can be increased to their maximums if required). The COUNTA() formula returns the number of cells that actually have values, which limits the number of rows returned to headings*rows. Otherwise the formulas would could go on for infinity because of the MOD function.

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  • Regular Expressions

    - by Rocky
    Hello Everyone, I am new to Stackoverflow and I have a quick question. Let's assume we are given a large number of HTML files (large as in theoretically infinite). How can I use Regular Expressions to extract the list of Phone Numbers from all those files? Explanation/expression will be really appreciated. The Phone numbers can be any of the following formats: (123) 456 7899 (123).456.7899 (123)-456-7899 123-456-7899 123 456 7899 1234567899 Thanks a lot for all your help and have a good one!

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  • Simple hardware RNG

    - by roygbiv
    I made a tongue-in-cheek comment to this question about making a hardware RNG. Does anyone know of any simple plans or can anyone descibe a simple hardware based RNG and the software to drive it? Go to Radio Shack. Buy a diode, an NTR resistor, a capacitor and serial cable. Cut off the end of the serial cable that does not fit on your computer. Solder the diode and resistor in series between pins DTR and DSR of the cable. Solder the capacitor between DSR and TXD pins. Write a small C program to do the following: Set DTR to 1. Start Timer. Monitor DSR until it goes to 1. Stop Timer. Calculate resistance from elapsed time. Retreive serveral bits from that value to use as part of random number. Repeat until enough bits have accumulated.

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  • Regular Expression for finding phone numbers

    - by Rocky
    Hello Everyone, I am new to Stackoverflow and I have a quick question. Let's assume we are given a large number of HTML files (large as in theoretically infinite). How can I use Regular Expressions to extract the list of Phone Numbers from all those files? Explanation/expression will be really appreciated. The Phone numbers can be any of the following formats: (123) 456 7899 (123).456.7899 (123)-456-7899 123-456-7899 123 456 7899 1234567899 Thanks a lot for all your help and have a good one!

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  • Generating random numbers in C

    - by moonstruckhorrors
    While searching for Tutorials on generating random numbers in C I found This Topic When I try to use the rand() function with parameters, I always get the random number generated 0. When I try to use the rand() function with parameters, I always get the value 41. And whenever I try to use arc4random() and random() functions, I get a LNK2019 error. Here's what I'm doing: #include <stdlib.h> int main() { int x; x = rand(6); printf("%d", x); } This code always generate 41. Where am I going wrong?? P.S. : I'm running Windows XP SP3 and using VS2010 Command Prompt as compiler. P.P.S. : Took me 15 minutes to learn how to format properly.

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  • Using the mpz_powm functions from the GMP/MPIR libraries with negative exponents

    - by Mihai Todor
    Please consider the following code: mpz_t x, n, out; mpz_init_set_ui(x, 2UL); mpz_init_set_ui(n, 7UL); mpz_init(out); mpz_invert(out, x, n); gmp_printf ("%Zd\n", out);//prints 4. 2 * 4 (mod 7) = 1. OK mpz_powm_ui(out, x, -1UL, n);//prints 1. 2 * 1 (mod 7) = 2. How come? gmp_printf ("%Zd\n", out); mpz_clear(x); mpz_clear(n); mpz_clear(out); I am unable to understand how the mpz_powm functions handle negative exponents, although, according to the documentation, it is supposed to support them. I would expect that raising a number to -1 modulo n is equivalent to inverting it modulo n. What am I missing here?

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  • Actionscript NetStream.play drops port in relative URLs

    - by Steve Middleton
    Hi, the current page my flash application is running from is http://localhost:3000/. I'm trying to play a video using NetStream.play(relativeURL) by using a relative URL (e.g. "myVideo.flv"), but when I look at the actual request made by actionscript, it's dropping the port number. (e.g. http://localhost/myVideo.flv). Is there something I can do on the flash side to make this work? Is anyone else having this problem?

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  • Simple, Custom Parsing with c++

    - by bradkovach
    Hi! I have been reading SO for some time now, but I truly cannot find any help for my problem. I have a c++ assignment to create an IAS simulator. Here is some sample code... 0 1 a 1 2 b 2 c 3 1 10 begin 11 . load a, subtract b and offset by -1 for jump+ 11 load M(0) 12 sub M(1) 13 sub M(3) 14 halt Using c++, I need to be able to read these lines and store them in a "memory register" class that I already have constructed... For example, the first line would need to store "1 a" in register zero. How can I parse out the number at the line beginning and then store the rest as a string? I have setup storage using a class that is called using mem.set(int, string);. int is the memory location at the beginning of the line and string is the stored instruction.

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  • How to specify VNC port number with Mac OS X built-in VNC client?

    - by Eonil
    Is it possible to specify VNC port number in built-in VNC client of Mac OS X? I'm trying to connect to Xen VPS machine with Finder's built-in VNC client. I used address like this. vnc://server:port But it fails because it uses another port, and Finder's built-in VNC cannot handle port number. As I know it handles the number after colon as display-number, not a port number. Is there a way to specify port number on the VNC client? Or any workaround for this? (port forwarding??? I have no idea about it...)

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  • How to specify VNC port number with Mac OS X built-in VNC client?

    - by Eonil
    Is it possible to specify VNC port number in built-in VNC client of Mac OS X? I'm trying to connect to Xen VPS machine with Finder's built-in VNC client. I used address like this. vnc://server:port But it fails because it uses another port, and Finder's built-in VNC cannot handle port number. As I know it handles the number after colon as display-number, not a port number. Is there a way to specify port number on the VNC client? Or any workaround for this? (port forwarding??? I have no idea about it...)

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  • Enhancing an 'ORDER BY' clause to judge condition by more than 1 integer

    - by Yvonne
    Hi folks, I have some PHP code which allows me to sort a column into ascending and descending order (upon click of a table row title), which is good. It works perfectly for my D.O.B colum (with date/time field type), but not for a quantity column. For example, I have quantites of 10, 50, 100, 30 and another 100. The order seems to be only appreciating the 1st integer, so my sorting of the column ends up in this order: 10, 100, 100, 30, 50... and 50, 30, 100, 100, 10. This is obviously incorrect as 100 is bigger than 50, therefore both 100 values should appear at the end surely? It seems to me that 100 is only being taken into account as having the '1' value, then it appears before 10 because the system recognises it has another 0. Is this normal to happen? Is there any way I can solve this problem? Thanks for any help. P.S. I can show code if necessary, but would like to know if this is a common issue by default.

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  • "Malformed version number string mingw32" when starting rails

    - by Freewind
    My os: windows xp, ruby: 1.8.7, rails: 2.3.5 Everything was fine, but I just installed a "gcc-4.4.0-mingw32-bin", and run gem install rdiscount, then my rails can't start. Now when I run ruby script/server, or rake gems:install, the following error will occur: rake aborted! Malformed version number string mingw32 (See full trace by running task with --trace) E:\WORKSPACE_TOPCODER\wenda_ror>ruby script/server => Booting Mongrel => Rails 2.3.5 application starting on http://0.0.0.0:3000 E:/Ruby/ruby-187/lib/ruby/site_ruby/1.8/rubygems/version.rb:182:in `initialize': Malformed version number string mingw32 (ArgumentError) from E:/Ruby/ruby-187/lib/ruby/gems/1.8/gems/rails-2.3.5/lib/rails/vendor_gem_source_index.rb:105:in `new' from E:/Ruby/ruby-187/lib/ruby/gems/1.8/gems/rails-2.3.5/lib/rails/vendor_gem_source_index.rb:105:in `version_for_dir' from E:/Ruby/ruby-187/lib/ruby/gems/1.8/gems/rails-2.3.5/lib/rails/vendor_gem_source_index.rb:47:in `refresh!' from E:/Ruby/ruby-187/lib/ruby/gems/1.8/gems/rails-2.3.5/lib/rails/vendor_gem_source_index.rb:45:in `each' from E:/Ruby/ruby-187/lib/ruby/gems/1.8/gems/rails-2.3.5/lib/rails/vendor_gem_source_index.rb:45:in `refresh!' from E:/Ruby/ruby-187/lib/ruby/gems/1.8/gems/rails-2.3.5/lib/rails/vendor_gem_source_index.rb:29:in `initialize' from E:/Ruby/ruby-187/lib/ruby/gems/1.8/gems/rails-2.3.5/lib/rails/gem_dependency.rb:21:in `new' from E:/Ruby/ruby-187/lib/ruby/gems/1.8/gems/rails-2.3.5/lib/rails/gem_dependency.rb:21:in `add_frozen_gem_path' from E:/Ruby/ruby-187/lib/ruby/gems/1.8/gems/rails-2.3.5/lib/initializer.rb:298:in `add_gem_load_paths' from E:/Ruby/ruby-187/lib/ruby/gems/1.8/gems/rails-2.3.5/lib/initializer.rb:132:in `process' from E:/Ruby/ruby-187/lib/ruby/gems/1.8/gems/rails-2.3.5/lib/initializer.rb:113:in `send' from E:/Ruby/ruby-187/lib/ruby/gems/1.8/gems/rails-2.3.5/lib/initializer.rb:113:in `run' from E:/WORKSPACE_TOPCODER/wenda_ror/config/environment.rb:9 from E:/Ruby/ruby-187/lib/ruby/site_ruby/1.8/rubygems/custom_require.rb:31:in `gem_original_require' from E:/Ruby/ruby-187/lib/ruby/site_ruby/1.8/rubygems/custom_require.rb:31:in `require' from E:/Ruby/ruby-187/lib/ruby/gems/1.8/gems/activesupport-2.3.5/lib/active_support/dependencies.rb:156:in `require' Now I have re-installed my ruby and rails, but the same error still occurs. And I have searched in google, found no solution. It seems I have to re-install my windows xp. Somebody knows the reason? Help...

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  • Django QuerySet ordering by number of reverse ForeignKey matches

    - by msanders
    I have the following Django models: class Foo(models.Model): title = models.CharField(_(u'Title'), max_length=600) class Bar(models.Model): foo = models.ForeignKey(Foo) eg_id = models.PositiveIntegerField(_(u'Example ID'), default=0) I wish to return a list of Foo objects which have a reverse relationship with Bar objects that have a eg_id value contained in a list of values. So I have: id_list = [7, 8, 9, 10] qs = Foo.objects.filter(bar__eg_id__in=id_list) How do I order the matching Foo objects according to the number of related Bar objects which have an eg_id value in the id_list?

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