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  • FileOpenPicker/FileSavePicker doesn't allow *.* wildcard file associations

    - by mbrit
    On Twitter, Matthias Jauernig commented that the FileOpenPicker and FileSavePicker doesn't allow *.* wildcard file associations. I was relaxed about this and wrote back that it was related to sandboxing implying it was a "good thing", however as Matthias commented back, perhaps it's not.In Metro-style the sandboxing works that if something gives you a file (e.g. the picker, or a share operation), you can access it regardless of where on the system. If you find the file yourself, you have to declare the type.The reason why I think it's related to sandboxing is because if you work with files programmatically you have to be explicit about the file types. This is to stop malware that you think is only interested in - say .PDF files, scanning and uploading any .EML files that it can find on the machine. It follows then on the pickers that restriction would continue. It allow's the retail store team to validate that an app is likely to behave itself. If it's an app that works with images, locking down the picker so that it can only access image file types makes sense.However Matthias mentioned that he has an app that should allow files of any arbitrary file. That fits more into the "if the user selects it, it must be OK" camp than the "programmatic scanning" camp. So now I'm left wondering why the picker doesn't allow any type to be selected.I think then maybe the decision comes down to simplicity. A lot of the decisions in Metro-style design relate to ideas about "zero intimidation". Allow the user to select any file is too much like Old Windows, and not enough like Reimagined Windows. What happens in Matthias's app if the user selects Explorer.exe as the file he or she wants to work with? I guess it's fine if you expect your user to know what they're doing (Old Windows), but not so fine if you're expecting a three year old to work with it (Reimagined Windows).

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  • BizTalk 2009 - Error when Testing Map with Flat File Source Schema

    - by StuartBrierley
    I have recently been creating some flat file schemas using the BizTalk Server 2009 Flat File Schema Wizard.  I have then been mapping these flat file schemas to a "normal" xml schema format. I have not previsouly had any cause to map flat files and ran into some trouble when testing the first of these flat file maps; with an instance of the flat file as the source it threw an XSL transform error: Test Map.btm: error btm1050: XSL transform error: Unable to write output instance to the following <file:///C:\Documents and Settings\sbrierley\Local Settings\Temp\_MapData\Test Mapping\Test Map_output.xml>. Data at the root level is invalid. Line 1, position 1. Due to the complexity of the map in question I decided to created a small test map using the same source and destination schemas to see if I could pinpoint the problem.  Although the source message instance vaildated correctly against the flat file schema, when I then tested this simplified map I got the same error. After a time of fruitless head scratching and some serious google time I figured out what the problem was. Looking at the map properties I noticed that I had the test map input set to "XML" - for a flat file instance this should be set to "native".

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  • How to obtain position in file (byte-position) from java scanner?

    - by september2010
    How to obtain a position in file (byte-position) from the java scanner? Scanner scanner = new Scanner(new File("file")); scanner.useDelimiter("abc"); scanner.hasNext(); String result = scanner.next(); and now: how to get the position of result in file (in bytes)? Using scanner.match().start() is not the answer, because it gives the position within internal buffer.

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  • Python: shutil.rmtree fails on Windows with 'Access is denied'

    - by Sridhar Ratnakumar
    In Python, when running shutil.rmtree over a folder that contains a read-only file, the following exception is printed: File "C:\Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\Python26\lib\shutil.py", line 221, in rmtree onerror(os.remove, fullname, sys.exc_info()) File "C:\Python26\lib\shutil.py", line 219, in rmtree os.remove(fullname) WindowsError: [Error 5] Access is denied: 'build\\tcl\\tcl8.5\\msgs\\af.msg' Looking in File Properties dialog I noticed that af.msg file is set to be read-only. So the question is: what is the simplest workaround/fix to get around this problem - given that my intention is to do an equivalent of rm -rf build/ but on Windows? (without having to use third-party tools like unxutils or cygwin - as this code is targeted to be run on a bare Windows install with Python 2.6 w/ PyWin32 installed)

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  • Extract wav file from video file

    - by Nikos Steiakakis
    I am developing an application in which I need to extract the audio from a video. The audio needs to be extracted in .wav format but I do not have a problem with the video format. Any format will do, as long as I can extract the audio in a wav file. Currently I am using Windows Media Player COM control in a windows form to play the videos, but any other embedded player will do as well. Any suggestions on how to do this? Thanks

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  • Locking behaviour is different via network shares

    - by MattH
    I have been trying to lock a file so that other cloned services cannot access the file. I then read the file, and then move the file when finished. The Move is allowed by using FileShare.Delete. However in later testing, we found that this approach does not work if we are looking at a network share. I appreciate my approach may not have been the best, but my specific question is: Why does the below demo work against the local file, but not against the network file? The more specific you can be the better, as I've found very little information in my searches that indicates network shares behave differently to local disks. string sourceFile = @"C:\TestFile.txt"; string localPath = @"C:\MyLocalFolder\TestFile.txt"; string networkPath = @"\\MyMachine\MyNetworkFolder\TestFile.txt"; File.WriteAllText(sourceFile, "Test data"); if (!File.Exists(localPath)) File.Copy(sourceFile, localPath); foreach (string path in new string[] { localPath, networkPath }) { using (FileStream fsLock = File.Open(path, FileMode.Open, FileAccess.ReadWrite, (FileShare.Read | FileShare.Delete))) { string target = path + ".out"; File.Move(path, target); //This is the point of failure, when working with networkPath if (File.Exists(target)) File.Delete(target); } if (!File.Exists(path)) File.Copy(sourceFile, path); }

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  • shutil.rmtree fails on Windows with 'Access is denied'

    - by Sridhar Ratnakumar
    In Python, when running shutil.rmtree over a folder that contains a read-only file, the following exception is printed: File "C:\ActivePython32Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\ActivePython32Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\ActivePython32Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\ActivePython32Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\ActivePython32Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\ActivePython32Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\ActivePython32Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\ActivePython32Python26\lib\shutil.py", line 221, in rmtree onerror(os.remove, fullname, sys.exc_info()) File "C:\ActivePython32Python26\lib\shutil.py", line 219, in rmtree os.remove(fullname) WindowsError: [Error 5] Access is denied: 'build\\pyhg_trunk-win32-x86-hgtip27\\image\\feature-core\\INSTALLDIR\\tcl\\tcl8.5\\msgs\\af.msg' Looking in File Properties dialog I noticed that af.msg file is set to be read-only. So the question is: what is the simplest workaround/fix to get around this problem - given that my intention is to do an equivalent of rm -rf build/ but on Windows? (without having to use unxutils or cygwin)

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  • Can't read excel file after creating it using File.WriteAllText() function

    - by Srikanth Mattihalli
    public void ExportDataSetToExcel(DataTable dt) { HttpResponse response = HttpContext.Current.Response; response.Clear(); response.Charset = "utf-8"; response.ContentEncoding = Encoding.GetEncoding("utf-8"); response.ContentType = "application/vnd.ms-excel"; Random Rand = new Random(); int iNum = Rand.Next(10000, 99999); string extension = ".xls"; string filenamepath = AppDomain.CurrentDomain.BaseDirectory + "graphs\\" + iNum + ".xls"; string file_path = "graphs/" + iNum + extension; response.AddHeader("Content-Disposition", "attachment;filename=\"" + iNum + "\""); string query = "insert into graphtable(graphtitle,graphpath,creategraph,year) VALUES('" + iNum.ToString() + "','" + file_path + "','" + true + "','" + DateTime.Now.Year.ToString() + "')"; try { int n = connect.UpdateDb(query); if (n > 0) { resultLabel.Text = "Merge Successfull"; } else { resultLabel.Text = " Merge Failed"; } resultLabel.Visible = true; } catch { } using (StringWriter sw = new StringWriter()) { using (HtmlTextWriter htw = new HtmlTextWriter(sw)) { // instantiate a datagrid DataGrid dg = new DataGrid(); dg.DataSource = dt; //ds.Tables[0]; dg.DataBind(); dg.RenderControl(htw); File.WriteAllText(filenamepath, sw.ToString()); // File.WriteAllText(filenamepath, sw.ToString(), Encoding.UTF8); response.Write(sw.ToString()); response.End(); } } } Hi all, I have created an excel sheet from datatable using above function. I want to read the excel sheet programatically using the below connectionstring. This string works fine for all other excel sheets but not for the one i created using the above function. I guess it is because of excel version problem. OleDbConnection conn= new OleDbConnection("Data Source='" + path +"';provider=Microsoft.Jet.OLEDB.4.0;Extended Properties=Excel 8.0;";); Can anyone suggest a way by which i can create an excel sheet such that it is readable again using above query. I cannot use Microsoft InterOp library as it is not supported by my host.

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  • Code to update HyperV Export file

    - by Andy Schneider
    I am using the HyperV Module from Codeplex to do a "config only" export from a 2008R2 Hyper-V server. In order to import the configuration on another HyperV server, I need to edit the value of CopyVMStorage in the EXP file. This file is an XML file. I wrote the following code in PowerShell to do the update for me. The variable $existing is the existing exp file. $xml = [xml](get-content $existing) $xpath = '//PROPERTY[@NAME ="CopyVmStorage"]' foreach ($node in $xml.SelectNodes($xpath)) {$node.Value = 'TRUE'} $xml.Save($existing) This code makes the correct changes to the XML. However, when I go to import the file on the Hyper-V server, I get an error that says the file format is incorrect. I am wondering if the encoding of the file is incorrect or if there is something else going on. If I edit the file manually in wordpad, it imports without an issue. The filename is a GUID with a .exp extension, and it appears that the file name is too long for notepad to open. Notepad throws an error trying to open the file, which is why I went with WordPad. I have noticed that the file that is updated with PowerShell comes out formatted whereas the raw file is xml all bunched together with no whitespace. Any ideas on what "file format" means in this HyperV error message and how I might be able to use my code to automate this change in the XML without changing the file format?

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  • How to read from database and write into text file with C#?

    - by user147685
    How to read from database and write into text file? I want to write/copy (not sure what to call) the record inside my database into a text file. One row record in database is equal to one line in the text file. I'm having no problem in database. For creating text file, it mentions FileStream and StreamWriter. Which one should I use?

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  • Getting a file pointer from file descriptor

    - by Naga Kiran
    In PHP 5.2.3, "fdopen" was used to read/write to a file descriptor that's opened by another application. fdopen(<fileDescriptorId>,"rw"); //It worked fine with PHP 5.2.3 After upgrading PHP to 5.3.2, it's throwing "undefined reference to 'fdopen' function". Please suggest whats the replacement for this in PHP 5.3.2 or any workaround.

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  • How to compare filename of uploaded file and string

    - by user225269
    I use this code to upload image files in xammp server: <?php if ((($_FILES["file"]["type"] == "image/gif") || ($_FILES["file"]["type"] == "image/jpeg") || ($_FILES["file"]["type"] == "image/pjpeg")) && ($_FILES["file"]["size"] < 100000)) { if ($_FILES["file"]["error"] > 0) { echo "Return Code: " . $_FILES["file"]["error"] . "<br />"; } else { echo "Upload: " . $_FILES["file"]["name"] . "<br />"; echo "Type: " . $_FILES["file"]["type"] . "<br />"; echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />"; echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br />"; if (file_exists("upload/" . $_FILES["file"]["name"])) { echo $_FILES["file"]["name"] . " already exists. "; } else { move_uploaded_file($_FILES["file"]["tmp_name"], "upload/" . $_FILES["file"]["name"]); echo "Stored in: " . "upload/" . $_FILES["file"]["name"]; } } } else { echo "Invalid file, File must be less than 100Kb in size with .jpg, .jpeg, or .gif file extension"; } ?> What do I do to compare the file name of the uploaded files with the text inputted by the user? My goal is to be able to compare the user input(ID number) and the file name of the image file which should also be an ID number. So that I will be able to display the image that corresponds with the ID Number provided. What do I need to do?Please give me an idea on how can I achieve this. Thanks

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  • Program crashes after trying to use a recently created file. C#

    - by Jason T.
    So here is my code if (!File.Exists(pathName)) { File.Create(pathName); } StreamWriter outputFile = new StreamWriter(pathName,true); But whenever I run the program the first time the path with file gets created. However once I get to the StreamWriter line my program crashes because it says my fie is in use by another process. Is there something I'm missing between the File.Create and the StreamWriter statements?

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  • Develop a custom file sync provider over file transfer WCF service

    - by user336622
    Hi All I'm trying to develop a custom sync provider to sync files over the internet using WCF service. We already have a file transfer service and it's working in production but I need to implement a custom sync provider on top of it. I've checked the solution in Braynt Likes blog here but this doesn't fulfill my needs. Any advices, guidance, or sample code to help is really appreciated?

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  • Extract a portion of a Qt .ui file into its own .ui file

    - by Grant Limberg
    We have a designer creating a user interface for an application. The main window has several QStackedWidgets used for in place panel switching. What I'd like to be able to do is extract each individual panel that makes up each page of the QStackedWidget into it its own .ui file. Is there an easy way to accomplish this from within Qt Designer, or are there any other tools to help accomplish this task short of redesigning all of the panels in their own .ui files?

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  • Writing Strings to files in python

    - by Leif Andersen
    I'm getting the following error when trying to write a string to a file in pythion: Traceback (most recent call last): File "export_off.py", line 264, in execute save_off(self.properties.path, context) File "export_off.py", line 244, in save_off primary.write(file) File "export_off.py", line 181, in write variable.write(file) File "export_off.py", line 118, in write file.write(self.value) TypeError: must be bytes or buffer, not str I basically have a string class, which contains a string: class _off_str(object): __slots__ = 'value' def __init__(self, val=""): self.value=val def get_size(self): return SZ_SHORT def write(self,file): file.write(self.value) def __str__(self): return str(self.value) Furthermore, I'm calling that class like this: def write(self, file): for variable in self.variables: variable.write(file) I have no idea what is going on. I've seen other python programs writing strings to files, so why can't this one? Thank you very much for your help.

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