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• Java Double Array

  - by user1062058

  I'm having trouble setting up and placing values into an array using a text file containing the floating point numbers 2.1 and 4.3 each number is separated by a space - below is the error I'm getting: Exception in thread "main" java.util.NoSuchElementException import java.util.*; import java.io.*; public class DoubleArray { public static void main(String[] args) throws FileNotFoundException { Scanner in = new Scanner(new FileReader("mytestnumbers.txt")); double [] nums = new double[2]; for (int counter=0; counter < 2; counter++) { int index = 0; index++; nums[index] = in.nextDouble(); } } } Thanks, I'm sure this isn't a hard question to answer... I appreciate your time.

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• Fractional Calculator in Java

  - by user2888881

  I am trying to create a fractional calculator in Java with inputs of mixed fractions, proper fractions, improper fractions or integers. It should include the four basic operators as well. The program should be set up as a loop where it is continuous until the user types "quit". I have coded the beginning loop but have no idea where to go from there. Please help, I am a beginner and would really appreciate it. Thank you again. This is what I have so far: import java.util.*; public class FractionCalculator { private static Scanner input; public static void main(String[] args) { input = new Scanner(System.in); String x = "quit"; System.out.println("Enter a fraction"); while (true) { String y = input.next(); if (y.equals(x)) { break; } } } }

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• scala coalesces multiple function call parameters into a Tuple -- can this be disabled?

  - by landon9720

  This is a troublesome violation of type safety in my project, so I'm looking for a way to disable it. It seems that if a function takes an AnyRef (or a java.lang.Object), you can call the function with any combination of parameters, and Scala will coalesce the parameters into a Tuple object and invoke the function. In my case the function isn't expecting a Tuple, and fails at runtime. I would expect this situation to be caught at compile time. object WhyTuple { def main(args: Array[String]): Unit = { fooIt("foo", "bar") } def fooIt(o: AnyRef) { println(o.toString) } } Output: (foo,bar)

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• Bash redirection: save stderr/stdout to different files and still print them out on a console

  - by Alby

  Here is a simple program. class Redirection { public static void main (String args[]){ System.out.println("Hello World_Stdout"); System.err.println("Hello World_Stderr"); } } I want to see the all the outputs on a console, but at the same time I want to store stdout and stderr in different files. I tried the following command, to no avail. $java Redirection 3>&1 2>stderr 1>stdout 1>&3 2>&3 stderr& stdout files have the file size of 0. So basically I want to do what "tee" command does but I also want to capture stderr as well.

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• Why Timer does not work if we do not generate a window?

  - by Roman

  Here is the code: import java.awt.event.ActionEvent; import java.awt.event.ActionListener; import javax.swing.JFrame; import javax.swing.Timer; public class TimerSample { public static void main(String args[]) { new JFrame().setVisible(true); ActionListener actionListener = new ActionListener() { public void actionPerformed(ActionEvent actionEvent) { System.out.println("Hello World Timer"); } }; Timer timer = new Timer(500, actionListener); timer.start(); } } It generates a window and then periodically prints "Hello World Timer" in the terminal (Command Prompt). If I comment this line new JFrame().setVisible(true); the application do not print anything to the command line. Why?

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• gtk-sharp-2.0 hide/show external applications(processes)

  - by ziuciek

  Hi, maybe the topic isn't quite precise.. i want to write in c# (gtk#-2.0) an app which opens another app hidden and later shows that app. For now i know only how to open hidden app... in windows...: using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Diagnostics; namespace do_kasacji { class Program { static void Main(string[] args) { ProcessStartInfo info = new ProcessStartInfo(); info.WindowStyle = ProcessWindowStyle.Minimized; info.FileName = "notepad"; using (Process pr = Process.Start(info)) { pr.WaitForExit(); } } } } Anyone knows how to change it so hat it would run in linux?

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• How do i get (is it possible to) a reference to the class that creates an instance of another class.

  - by Cadde

  Odd situation... I need to create a new instance of a class that needs a member of the calling class. But i can't pass a reference to the calling class through the constructor. The solution i am looking for is something like this: Public Class ChildClass Public Sub New(args) _MyMember = GetMemberFromCallingClass() ... ... End Sub End Class I want this to work without having to manually pass any references or variables from the calling class to the new instance of ChildClass. Is this possible and if so, what should i look at to make this part of my code.

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• jquery animate() problem

  - by meo

  $('#somediv').stop(false, true).animate({marginLeft: '-=' + e.width() + 'px'}, options.speed, function(){ options.onNewSlide() }) e.with() returns 640 opctions.speed contains 800 options.onNewSlide() contains a a custom callback function It works fine in firefox. But i debugged it with jquery.lint because it was throwing some random error in IE. lint tells me: When I called animate(...) with your args, an error was thrown! TypeError: c.speed is not a function { message="c.speed is not a function", more...} You passed: [Object { marginLeft="-=640px"}, 800, function()] and it indicates me the line i have posted. I have checked the jquery doc, but my syntax seams ok. Do you know what i am doing wrong?

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• question about random select

  - by davit-datuashvili

  here is code print number in decreasing order import java.util.*; public class select { public static void Select(int m,int n){ Random r=new Random(); if (m>0) if (r.nextInt(0x3fff8001) % n <m ){ System.out.println(n-1); Select(m-1,n-1); } else{ Select(m,n-1); } } public static void main(String[]args){ int m=35; int n=200; Select(m,n); } } and question is how to changes code such that print number in increasing order? please help

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• Set intersection of two strings

  - by user1785712

  import java.util.*; class set { public static void main(String args[]) { TreeSet<Character> t1 = new TreeSet<Character>(); TreeSet<Character> t2 = new TreeSet<Character>(); String s1 = "Ambitab bachan"; String s2 = "Ranjikanth"; for(char c1:s1.toCharArray()) t1.add(c1); for(char c2:s2.toCharArray()) t2.add(c2); t2.retainAll(t1); System.out.println(t2); } } this program find the common character in two different string. in this program Treeset is used to store the value and retainAll() method is used to find the common characters. can anybody help me reduce the line of coding.thanks in advance

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• complexity of algorithms

  - by davit-datuashvili

  i have question what is complexity of this algorithm public class smax{ public static void main(String[]args){ int b[]=new int[11]; int a[]=new int[]{4,9,2,6,8,7,5}; for (int i=0;i int m=0; while (m int k=a[0]; for (int i=0;i k && b[a[i]]!=1){ b[a[i]]=1; } } m++; } for (int i=0;i for (int j=0;j //result=2 4 5 6 7 8 9 } } ?

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• What does this java output mean?!

  - by Phil

  public class Arrys { private int[] nums; //Step 3 public Arrys (int arrySize) { nums = new int[arrySize]; } public int [] getNums (){ return nums; } } Test class: public class TestArrys { public static void main(String args[]) { //Step 4 Arrys arry = new Arrys(10); System.out.println("\nStep4 "); for(int index = 0; index < arry.getNums().length; index++) { System.out.print(arry.getNums()); } } } It's incredibly simple, that is why I think I'm doing something fundamentally wrong. All I want is to display the value of the array. This is what I get back. I am totally lost, there is nothing in my book that explains this nor does googling it help. Step4 [I@1ac88440[I@1ac88440[I@1ac88440[I@1ac88440[I@1ac88440[I@1ac88440[I@1ac88440[I@1ac88440[I@1ac88440[I@1ac88440[I@1ac88440

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• How to validate phone number(US format) in Java?

  - by Maxood

  I just want to know where am i wrong here: import java.io.*; class Tokens{ public static void main(String[] args) { //String[] result = "this is a test".split(""); String[] result = "4543 6546 6556".split(""); boolean flag= true; String num[] = {"0","1","2","3","4","5","6","7","8","9"}; String specialChars[] = {"-","@","#","*"," "}; for (int x=1; x<result.length; x++) { for (int y=0; y<num.length; y++) { if ((result[x].equals(num[y]))) { flag = false; continue; } else { flag = true; } if (flag == true) break; } if (flag == false) break; } System.out.println(flag); } }

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• How do I setup Eclipse to stop on the line an exception occured?

  - by Chris Persichetti

  Hi, How can I setup Eclipse to stop at the point an exception occurred. I have an Eclipse breakpoint setup to break on an exception. In the code example below, the problem I'm having is Eclipse tries to open the Integer source code. Is there any way to just have debugger break at the point shown in my code example? If I move down the stack trace, I will get to this line, it'd be nice if there's a way to do this without the "Source not found" window coming up. This can be done in Visual Studio, so it's driving me crazy not being able to find a way to do this in Eclipse. package com.test; public class QuickTest { public static void main(String[] args) { try { test(); } catch(NumberFormatException e) { System.out.println(e.getMessage()); } } private static void test() { String str = "notAnumber"; Integer.parseInt(str);//<----I want debugger to stop here } }

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• question on reverse array

  - by davit-datuashvili

  we know algorithm how reverse array of n integers for (int i=0;i<n/2;i++){ swap(a[i],a[n-1-i]): } is this method better according the speed of algorithm or not because swap using xor is more fast then in other method here is code public class swap { public static void main(String[]args){ int a[]=new int[]{2,4,5,7,8,11,13,12,14,24}; System.out.println(" array at the begining:"); for (int i=0;i<a.length;i++){ System.out.println(a[i]); } for (int j=0;j<a.length/2;j++){ a[j]^=a[a.length-1-j]; a[a.length-1-j]^=a[j]; a[j]^=a[a.length-1-j]; } System.out.println("reversed array:"); for (int j=0;j<a.length;j++){ System.out.println(a[j]); } } } Result: array at the begining: 2 4 5 7 8 11 13 12 14 24 reversed array: 24 14 12 13 11 8 7 5 4 2

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• How to remove strings of certain lengths

  - by Macosx Iam

  So I have this array, and I want to delete strings that are 2 or 4 characters in length (strings that contain 2 or 4 characters). I am doing this method, and it doesn't work, even though logically, it SHOULD work. public static void main(String[] args) { ArrayList<String> list = new ArrayList<String>(); list.add("This"); list.add("is"); list.add("a"); list.add("test"); for (int i=0; i<list.size(); i++) { if(list.get(i).length()==2 || list.get(i).length()==4) { list.remove(i); } } } I'd like to stick to this method of doing it. Can you please give me some suggestions as to how to correct this code? The output of this code when I run it is: [is, a] Even though I want the output to be [a] because "is" is 2 characters long.

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• Is read-only auto-imlemented property possible?

  - by abatishchev

  Hello. I found a topic on MSDN that talks that yes, this is possible. I did a test that seems to break this statement: using System; namespace Test { class Program { static void Main(string[] args) { Foo f = new Foo("1"); Console.WriteLine(f.Bar); // prints 1 f.Test("2"); Console.WriteLine(f.Bar);// successfully prints 2 } } class Foo { public Foo(string b) { this.Bar = b; } public string Bar { get; private set; } public void Test(string b) { // this would be impossible for readonly field! // next error would be occur: CS0191 or CS0191 // A readonly field cannot be assigned to (except in a constructor or a variable initializer) this.Bar = b; } } } Where am I wrong?

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• Does Java have "properties" that work the same way properties work in C# (see the body of my text)?

  - by tyrone302

  In C#, you can use properties to make a data field publicly accessible (allowing the user to directly access it), and yet retain the ability to perform data validation on those directly-accessed fields. Doese Java have something similar? For Instance, suppose there exists a C# class with the following implementation(see below): public class newInt{ public newInt(){...} public int x{ get{ return this.x } set{ this.x = isValid(value) } } } private static int isValid(int value){...} This definition in the class allows the user to "naturally" use the data field 'x' when retrieving values from it and assigning values to it. Below is how it would be used in main. public class Test{ public static void main(String[] args){ newInt a = new newInt(); a.x = 50; int b = a.x; } } The question is... can java do this as well? if so, what is it called?

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• Why javabeans framework create the IndexedPropertyDescriptor for the NON index method

  - by George Macus

  I'm not familiar with java beans framework, in the below scenario, I got the IndexedPropertyDescriptor for the method getFooWithX, could someone explain why? public class IntrospectorTest { public static void main(String[] args) throws IntrospectionException { BeanInfo info = Introspector.getBeanInfo(SubClass.class); PropertyDescriptor[] descriptors = info.getPropertyDescriptors(); for (int i = 0; i < descriptors.length; i++) { System.out.println(descriptors[i].getClass().getName() + ":" + descriptors[i].getName()); } } } abstract class BaseClass { public abstract Object getFoo(); } abstract class SubClass extends BaseClass { public Object getFooWithX(int x) { return null; } } and the result will be: java.beans.PropertyDescriptor:class java.beans.PropertyDescriptor:foo java.beans.IndexedPropertyDescriptor:fooWithX Why?

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• the difference of String.valueOf(char) and +

  - by Will Yu

  to show the default value of char ,I wrote code like this: public class TestChar { static char a; public static void main(String[] args) { System.out.println("."+String.valueOf(a)+"."); System.out.println("the default char is "+a); } } but the console output is confused.the first is ". ." ,however the second is "the default char is [](like this ,I don't know how to describe it.)" why?thanks for help

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• Java : Using parent class method to access child class variable

  - by Jayant

  I have the following scenario : public class A { private int x = 5; public void print() { System.out.println(x); } } public class B extends A { private int x = 10; /*public void print() { System.out.println(x); }*/ public static void main(String[] args) { B b = new B(); b.print(); } } On executing the code, the output is : 5. How to access the child class(B's) variable(x) via the parent class method? Could this be done without overriding the print() method (i.e. uncommenting it in B)? [This is important because on overriding we will have to rewrite the whole code for the print() method again]

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• Solution to compiler warning for generic varargs

  - by TJR

  A puzzle from this blog. Similar to SO1445233. Given the following source listing, explain why the compiler is producing a warning at invocation to the list method and give a solution for removing the warning without resorting to @SuppressWarnings annotation. public class JavaLanguagePuzzle3 { public static void main(String[] args) { list("1", 2, new BigDecimal("3.5")); } private static <T> List<T> list(T... items) { return Arrays.asList(items); } } Warning: Type safety: A generic array of Object&Serializable&Comparable<?> is created for a varargs parameter

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• How does ruby allow a method and a Class with the same name?

  - by Daniel Beardsley

  I happened to be working on a Singleton class in ruby and just remembered the way it works in factory_girl. They worked it out so you can use both the long way Factory.create(...) and the short way Factory(...) I thought about it and was curious to see how they made the class Factory also behave like a method. They simply used Factory twice like so: def Factory (args) ... end class Factory ... end My Question is: How does ruby accomplish this? and Is there danger in using this seemingly quirky pattern?

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• scope of variables java

  - by qxc

  Is a variable inside the main, a public variable? public static void main(String[] args) { ......... for(int i=0;i<threads.length;i++) try { threads[i].join(); } catch (InterruptedException e) { e.printStackTrace(); } long time=0; .... } i and time are they both public variables? Of course if my reasoning is correct, also any variable belonging to a public method should be considered public.. am i right? Thanks

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• Reference and Value confusion

  - by rgamber

  Hi I read this question on Stack overflow, and tried to do an example. I had the below code: public static void main(String[] args){ int i = 5; Integer I = new Integer(5); increasePrimitive(i); increaseObject(I); System.out.println(i); //Prints 5 - correct System.out.println(I); //Still prints 5 System.out.println(increaseObject2(I)); //Still prints 5 } public static void increasePrimitive(int n){ n++; } public static void increaseObject(Integer n){ n++; } public static int increaseObject2(Integer n){ return n++; } Does the increaseObject print 5 because the value of reference is changing inside that function? Am I right? I am confused why the increasedObject2 prints 5 and not 6. Can anyone please explain?

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